Perl passing argument into eval

Posted by ehretf on Stack Overflow See other posts from Stack Overflow or by ehretf
Published on 2012-10-03T21:29:21Z Indexed on 2012/10/03 21:37 UTC
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Filed under:

perl

|

arguments

|

eval

I'm facing an issue using eval function.

Indeed I have some function name inside a SQL database, my goal is to execute those functions within perl (after retrieve in SQL).

Here is what I'm doing, considering that $RssSource->{$k}{Proceed} contains "&test" as a string retrieved from SQL:

my $str2 = "ABCD";
eval "$RssSource->{$k}{Proceed}";warn if $@;

sub test
{
   my $arg = shift;

   print "fct TEST -> ", $row, "\n";
}

This is working correctly and display:

fct TEST ->

However I would like to be able to pass $str2 as an argument to $RssSource->{$k}{Proceed} but I don't know how, every syntax I tried return an error:

eval "$RssSource->{$k}{Proceed}$str2"
eval "$RssSource->{$k}{Proceed}($str2)"
eval "$RssSource->{$k}{Proceed}"$str2
eval "$RssSource->{$k}{Proceed}"($str2)

May someone tell me how to properly pass an argument to the evaluated function?

Thanks a lot for your help

Regards.

Florent

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