Counting vowels in a string using recursion
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                Daniel Love Jr
            
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        Published on 2012-10-13T22:40:31Z
        Indexed on 
            2012/10/14
            3:37 UTC
        
        
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In my python class we are learning about recursion. I understand that it's when a function calls itself, however for this particular assignment I can't figure out how exactly to get my function to call it self to get the desired results. I need to simply count the vowels in the string given to the function.
def recVowelCount(s):
    'return the number of vowels in s using a recursive computation'
    vowelcount = 0
    vowels = "aEiou".lower()
    if s[0] in vowels:
        vowelcount += 1
    else:
        ???
I'm really not sure where to go with this, it's quite frustrating.
I came up with this in the end, thanks to some insight from here.
def recVowelCount(s):
'return the number of vowels in s using a recursive computation'
vowels = "aeiouAEIOU"
if s == "":
    return 0
elif s[0] in vowels:
    return 1 + recVowelCount(s[1:])
else:
    return 0 + recVowelCount(s[1:])
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