XSLT: How to get XML

Posted by Jyotsna Sonawane on Stack Overflow See other posts from Stack Overflow or by Jyotsna Sonawane
Published on 2012-10-15T03:13:05Z Indexed on 2012/10/15 3:37 UTC
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I have a XSL that transforms one format of XML into another. In input XML I have a node with following value - which is actually a XML string if we replace &lt; with < (less than) for e.g.

&lt;Paragraph&gt;&lt;Title&gt;&lt;!CDATA[Pour les nuits du 2012-10-01 - 2012-10-30]]&gt;&lt;/Title&gt;&lt;Text&gt;&lt;![CDATA[TAXES INCLUSES.]]&gt;&lt;/Text&gt;&lt;/Paragraph&gt;

I want to have the content of otherInfo as a XML node in output XML.

if I do , I do not get it as a XML node - it is output just as text. How can I make XSL output the content of otherInfo as XML node ?

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