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  • Work at Oracle as a Fresh Student by Ang Sun

    - by Nadiya
    The past months have flown by since I started working at Oracle; but at the same time it feels like I’ve been here forever. I came to Beijing to find a job after I graduated from The University of Southampton with a MSc in Software Engineering. I got an offer the next day after I had an interview with my manager. This new style of working life hasn’t been a problem with me. The atmosphere here is fantastic and everyone is so friendly and easy to talk to. I am the first member in our AIE China Team. We do appreciate those colleagues from Core I/O team who helped us a lot to familiarize ourselves with the new environment. After hire orientation training I got to know many new people from various teams including Middleware, People Soft and Solaris. Also Oracle provides weekly system online training as additional training for those people who need it. The best thing about working at Oracle is that there is a balance between work and rest. It’s good to have a really nice park and green space near the Oracle buildings. Most of us like to walk around the riverside after lunch before we get back to work. I like to grab a cup of latte before discussing issues and the schedule of our projects in a weekly conference call with my US colleagues. It has been great experience; I am working alongside talented colleagues from different countries and nationalities. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Make two page navigations on top ang bottom of a list

    - by sees
    I'm creating a simple PHP page that reads CSV file content and display some selected columns to users in pages Currently, I'm reading each line and display it immediately. Because of this method, I only know total of lines after finishing reading entire file( searching in file also). What I want is displaying two page navigations on the top and bottom of the list. Like this: Page 1|2|3|4 Field 1|Field 2|Field 3|Field 4|Field 5....|Field n Row1 Row2 .... Rown Page 1|2|3|4 After displaying all rows, bottom page nav, I used jquery function: insertBefore to insert another page navi to the top. Problems are: 1) Top page nav not displayed in IE8 but displayed ater pressing F5(worked in FF, Chrome). 2) Using insertBefore function, the top page nav is suddenly poppep up afer displaying the bottom one. It doesn't look naturally Any suggestion?

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  • High level macro not recognized - Beginner MASM

    - by Francisco P.
    main proc finit .while ang < 91 invoke func, ang fstp res print real8$(ang), 13, 10 print real8$(res), 13, 10 fld ang fld1 fadd fstp ang .endw ret main endp What's wrong with this piece of MASM code? I get an error on .endw. I have ran some tests to ensure myself of that. Assembler tells me invalid instruction operands. Thank you for your time!

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  • How to find vector for the quaternion from X Y Z rotations

    - by can poyrazoglu
    I am creating a very simple project on OpenGL and I'm stuck with rotations. I am trying to rotate an object indepentdently in all 3 axes: X, Y, and Z. I've had sleepless nights due to the "gimbal lock" problem after rotating about one axis. I've then learned that quaternions would solve my problem. I've researched about quaternions and implementd it, but I havent't been able to convert my rotations to quaternions. For example, if I want to rotate around Z axis 90 degrees, I just create the {0,0,1} vector for my quaternion and rotate it around that axis 90 degrees using the code here: http://iphonedevelopment.blogspot.com/2009/06/opengl-es-from-ground-up-part-7_04.html (the most complicated matrix towards the bottom) That's ok for one vector, but, say, I first want to rotate 90 degrees around Z, then 90 degrees around X (just as an example). What vector do I need to pass in? How do I calculate that vector. I am not good with matrices and trigonometry (I know the basics and the general rules, but I'm just not a whiz) but I need to get this done. There are LOTS of tutorials about quaternions, but I seem to understand none (or they don't answer my question). I just need to learn to construct the vector for rotations around more than one axis combined. UPDATE: I've found this nice page about quaternions and decided to implement them this way: http://www.cprogramming.com/tutorial/3d/quaternions.html Here is my code for quaternion multiplication: void cube::quatmul(float* q1, float* q2, float* resultRef){ float w = q1[0]*q2[0] - q1[1]*q2[1] - q1[2]*q2[2] - q1[3]*q2[3]; float x = q1[0]*q2[1] + q1[1]*q2[0] + q1[2]*q2[3] - q1[3]*q2[2]; float y = q1[0]*q2[2] - q1[1]*q2[3] + q1[2]*q2[0] + q1[3]*q2[1]; float z = q1[0]*q2[3] + q1[1]*q2[2] - q1[2]*q2[1] + q1[3]*q2[0]; resultRef[0] = w; resultRef[1] = x; resultRef[2] = y; resultRef[3] = z; } Here is my code for applying a quaternion to my modelview matrix (I have a tmodelview variable that is my target modelview matrix): void cube::applyquat(){ float& x = quaternion[1]; float& y = quaternion[2]; float& z = quaternion[3]; float& w = quaternion[0]; float magnitude = sqrtf(w * w + x * x + y * y + z * z); if(magnitude == 0){ x = 1; w = y = z = 0; }else if(magnitude != 1){ x /= magnitude; y /= magnitude; z /= magnitude; w /= magnitude; } tmodelview[0] = 1 - (2 * y * y) - (2 * z * z); tmodelview[1] = 2 * x * y + 2 * w * z; tmodelview[2] = 2 * x * z - 2 * w * y; tmodelview[3] = 0; tmodelview[4] = 2 * x * y - 2 * w * z; tmodelview[5] = 1 - (2 * x * x) - (2 * z * z); tmodelview[6] = 2 * y * z - 2 * w * x; tmodelview[7] = 0; tmodelview[8] = 2 * x * z + 2 * w * y; tmodelview[9] = 2 * y * z + 2 * w * x; tmodelview[10] = 1 - (2 * x * x) - (2 * y * y); tmodelview[11] = 0; glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadMatrixf(tmodelview); glMultMatrixf(modelview); glGetFloatv(GL_MODELVIEW_MATRIX, tmodelview); glPopMatrix(); } And my code for rotation (that I call externally), where quaternion is a class variable of the cube: void cube::rotatex(int angle){ float quat[4]; float ang = angle * PI / 180.0; quat[0] = cosf(ang / 2); quat[1] = sinf(ang/2); quat[2] = 0; quat[3] = 0; quatmul(quat, quaternion, quaternion); applyquat(); } void cube::rotatey(int angle){ float quat[4]; float ang = angle * PI / 180.0; quat[0] = cosf(ang / 2); quat[1] = 0; quat[2] = sinf(ang/2); quat[3] = 0; quatmul(quat, quaternion, quaternion); applyquat(); } void cube::rotatez(int angle){ float quat[4]; float ang = angle * PI / 180.0; quat[0] = cosf(ang / 2); quat[1] = 0; quat[2] = 0; quat[3] = sinf(ang/2); quatmul(quat, quaternion, quaternion); applyquat(); } I call, say rotatex, for 10-11 times for rotating only 1 degree, but my cube gets rotated almost 90 degrees after 10-11 times of 1 degree, which doesn't make sense. Also, after calling rotation functions in different axes, My cube gets skewed, gets 2 dimensional, and disappears (a column in modelview matrix becomes all zeros) irreversibly, which obviously shouldn't be happening with a correct implementation of the quaternions.

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  • determine collision angle on a rotating body

    - by jorb
    update: new diagram and updated description I have a contact listener set up to try and determine the side that a collision happened at relative to the a bodies rotation. One way to solve this is to find the value of the yellow angle between the red and blue vectors drawn above. The angle can be found by taking the arc cosine of the dot product of the two vectors (Evan pointed this out). One of my points of confusion is the difference in domain of the atan2 function html canvas coordinates and the Box2d rotation information. I know I have to account for this somehow... SS below questions: Does Box2D provide these angles more directly in the collision information? Am I even on the right track? If so, any hints? I have the following javascript so far: Ship.prototype.onCollide = function (other_ent,cx,cy) { var pos = this.body.GetPosition(); //collision position relative to body var d_cx = pos.x - cx; var d_cy = pos.y - cy; //length of initial vector var len = Math.sqrt(Math.pow(pos.x -cx,2) + Math.pow(pos.y-cy,2)); //body angle - can over rotate hence mod 2*Pi var ang = this.body.GetAngle() % (Math.PI * 2); //vector representing body's angle - same magnitude as the first var b_vx = len * Math.cos(ang); var b_vy = len * Math.sin(ang); //dot product of the two vectors var dot_prod = d_cx * b_vx + d_cy * b_vy; //new calculation of difference in angle - NOT WORKING! var d_ang = Math.acos(dot_prod); var side; if (Math.abs(d_ang) < Math.PI/2 ) side = "front"; else side = "back"; console.log("length",len); console.log("pos:",pos.x,pos.y); console.log("offs:",d_cx,d_cy); console.log("body vec",b_vx,b_vy); console.log("body angle:",ang); console.log("dot product",dot_prod); console.log("result:",d_ang); console.log("side",side); console.log("------------------------"); }

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  • Email php isn't working, please help?

    - by laurence-benson
    Hey Guys, My email code isn't working, can anyone help? Thanks. <?php if(isset($_POST['send'])){ $to = "[email protected]" ; // change all the following to $_POST $from = $_REQUEST['Email'] ; $name = $_REQUEST['Name'] ; $headers = "From: $from"; $subject = "Web Contact Data"; $fields = array(); $fields{"Name"} = "Name"; $fields{"Email"} = "Email"; $body = "We have received the following information:\n\n"; foreach($fields as $a => $b){ $body .= sprintf("%20s: %s\n",$b,$_REQUEST[$a]); } $subject2 = "Thank you for contacting us."; $autoreply = "<html><body><p>Dear " . $name . ",</p><p>Thank you for registering with ERB Images.</p> <p>To make sure that you continue to receive our email communications, we suggest that you add [email protected] to your address book or Safe Senders list. </p> <p>In Microsoft Outlook, for example, you can add us to your address book by right clicking our address in the 'From' area above and selecting 'Add to Outlook Contacts' in the list that appears.</p> <p>We look forward to you visiting the site, and can assure you that your privacy will continue to be respected at all times.</p><p>Yours sincerely.</p><p>Edward R Benson</p><p>Edward Benson Esq.<br />Founder<br />ERB Images</p><p>www.erbimages.com</p></body></html>"; $headers2 = 'MIME-Version: 1.0' . "\r\n"; $headers2 .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n"; $headers2 .= 'From: [email protected]' . "\r\n"; mail($from, $subject2, $autoreply, $headers2); $send=false; if($name == '') {$error= "You did not enter your name, please try again.";} else { if(!preg_match("/^[[:alnum:]][a-z0-9_.'+-]*@[a-z0-9-]+(\.[a-z0-9-]{2,})+$/",$from)) {$error= "You did not enter a valid email address, please try again.";} else { $send = mail($to, $subject, $body, $headers); $send2 = mail($from, $subject2, $autoreply, $headers2); } if(!isset($error) && !$send) $error= "We have encountered an error sending your mail, please notify [email protected]"; } }// end of if(isset($_POST['send'])) ?> <?php include("http://erbimages.com/php/doctype/index.php"); ?> <?php include("http://erbimages.com/php/head/index.php"); ?> <div class="newsletter"> <ul> <form method="post" action="http://lilyandbenson.com/newletter/index.php"> <li> <input size="20" maxlength="50" name="Name" value="Name" onfocus="if(this.value==this.defaultValue) this.value='';" onblur="if(this.value=='') this.value=this.defaultValue;"> </li> <li> <input size="20" maxlength="50" name="Email" value="Email" onfocus="if(this.value==this.defaultValue) this.value='';" onblur="if(this.value=='') this.value=this.defaultValue;"> </li> <li> <input type="submit" name="send" value="Send" id="register_send"> </li> </form> <?php ?> </ul> <div class="clear"></div> </div> <div class="section_error"> <?php if(isset($error)) echo '<span id="section_error">'.$error.'</span>'; if(isset($send) && $send== true){ echo 'Thank you, your message has been sent.'; } if(!isset($_POST['send']) || isset($error)) ?> <div class="clear"></div> </div> </body> </html>

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  • keyboard shortcut to switch focus between separate X screens?

    - by ang mo
    I'm using XFCE on a dual monitor setup, with Xorg configured to separate X screens (neither twinview nor cinerama is working on GF470 with latest nvidia drivers). I'm not using xrandr. Suppose I have firefox running on one screen (:0.0) and thunderbird on the other (:0.1). When I want to switch focus from thunderbird to firefox, I need to move my mouse pointer to the firefox window and click (alt-tab switches between windows on a single screen only). Is there any keyboard shortcut for switching focus between screens?

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  • get rotation direction of UIView on touchesMoved

    - by mlecho
    this may sound funny, but i spent hours trying to recreate a knob with a realistic rotation using UIView and some trig. I achieved the goal, but now i can not figure out how to know if the knob is rotating left or right. The most pertinent part of the math is here: - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [touches anyObject]; CGPoint pt = [touch locationInView:self]; float dx = pt.x - iv.center.x; float dy = pt.y - iv.center.y; float ang = atan2(dy,dx); //do the rotation if (deltaAngle == 0.0) { deltaAngle = ang; initialTransform = iv.transform; }else { float angleDif = deltaAngle - ang; CGAffineTransform newTrans = CGAffineTransformRotate(initialTransform, -angleDif); iv.transform = newTrans; currentValue = [self goodDegrees:radiansToDegrees(angleDif)]; } } ideally, i could leverage a numeric value to tell me if the rotation is positive or negative.

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  • How can I solve, error:unknown filesytem grub rescue>

    - by Benson
    I was previously using Win7 and had two partitions on my hard disk. After learning about Ubuntu I decide to remove Windows and install Ubuntu 11.10 instead. All my important files and documents are stored in my second partition. After successful installation, during restart I get the error : error: unknown filesystem grub rescue> Please help me to resolve the problem, and note that I don't want dual boot my machine.

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  • CW/CCW Rotation of a Vector

    - by user23132
    Considering that I have a vector A, and after an arbitrary rotation I get vector B. I want to use this rotation operation in others vectors as well, but I'm having problems in doing that. My idea do that is to calculate the perpendicular vector C of the plane AB (by calculating AxB). This vector C is the axis that I'll need to rotate. To discover the angle I used the dot product between A and B, the acos of the dot product will return the lowest angle between A and B, the angle ang. The rotation I need to do is then: -rotate *ang*º around the C axis. The problem is that I dont know if this rotation is a CW or CCW rotation, since the cos of the dot product does not give me information of the sign of the angle. There's a tip discover that in 2D ( A.x * B.y - A.y * B.x) that you can use to discover if the vector A is at left/right of vector B. But I dont know how to do this in 3D space. Can anyone help me?

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  • Issue with angular gradient algorithm

    - by user146780
    I have an angular gradient algorithm: GLuint OGLENGINEFUNCTIONS::CreateAngularGradient( std::vector<ARGBCOLORF> &input,POINTFLOAT start, POINTFLOAT end, int width, int height ) { std::vector<GLubyte> pdata(width * height * 4); float pi = 3.1415; float cx; float cy; float r1; float r2; float ang; float px; float py; float t; cx = start.x; cy = start.y; r1 = 0; r2 = 500; ang = end.x / 100; ARGBCOLORF color; for (unsigned int i = 0; i < height; i++) { for (unsigned int j = 0; j < width; j++) { px = j; py = i; if( px * px + py * py <= r2 * r2 && px * px + py * py >= r1 * r1 ) { t= atan2(py-cy,px-cx) + ang; t= t+ pi; if (t > 2* pi) { t=t-2*pi; t=t/(2*pi); } } //end + start color.r = (0 * t) + (120 * (1 - t)); color.g = (50 * t) + (255 * (1 - t)); color.b = (0 * t) + (50 * (1 - t)); color.a = (255 * t) + (200 * (1 - t)); pdata[i * 4 * width + j * 4 + 0] = (GLubyte) color.r; pdata[i * 4 * width + j * 4 + 1] = (GLubyte) color.g; pdata[i * 4 * width + j * 4 + 2] = (GLubyte) 12; pdata[i * 4 * width + j * 4 + 3] = (GLubyte) 255; } } It works fine except the ang variable only controls the end sweep, not the start sweep. The start sweep is always facing the middle left as seen here: http://img810.imageshack.us/img810/9623/uhoh.png Basically I have no control over the end one going this <- way. How could I control this one? Thanks

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  • macbook pro for developer

    - by Michael Ellick Ang
    Which of the following choices would be more beneficial to developers ? 13 inch Macbook Pro, Core 2 Duo, 4 GB Memory, 128 GB SSD - $1550 - Faster Storage 13 inch Macbook Pro, Core 2 Duo, 8 GB Memory, 250 GB HD - $1600 - More Memory 15 inch Macbook Pro, Core i5, 4 GB Memory, 320 GB HD - $1800 - Better CPU Thanks.

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  • Setting up Windows 2008 with VPN and NAT

    - by Benson
    I have a Windows 2008 box set up with VPN, and that works quite well. NPS is used to validate the VPN clients, who are able to access the private address of the server, once connected. I can't for the life of me get NAT working for the VPN clients, though. I've added NAT as a routing protocol, and set the one on in the VPN address pool as private, and the other as public - but it still won't NAT connections when I add a route through the VPN server's IP on the client side (route add SomeInternetIp IpOfPrivateInterfaceOnServer). I know I can reach the server's private interface (which happens to be 10.2.2.1) with remote desktop client, so I can't think of any issues with the VPN.

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  • Folder/File permission transfer between alike file structure

    - by Tyler Benson
    So my company has recently upgraded to a new SAN but the person who copied all the data over must have done a drag n' drop or basic copy to move everything. Apparently Xcopy is not something he cared to use. So now I am left with the task of duplicating all the permissions over. The structure has changed a bit ( as in more files/folders have been added) but for the most part has been stayed unchanged. I'm looking for suggestions to help automate this process. Can I use XCopy to transfer ONLY permissions to one tree from another? Would i just ignore any folders/permissions that don't line up correctly? Thanks a ton in advance, Tyler

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  • cannot get apache2 redirect working for a site

    - by benson
    what i want to do is to redirect all visitors going to example.com to www.example.com.it seems a very common task but for some reason it is not working for this specific site .it always points to the default one. And strangely, if i replace the domain with another one(yyyyy.com and www.yyyyy.com), it works all right.i check my DNS,and it's resolved to the right IP. here's my virtual host configure: <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /var/www/html/example.com Servername www.example.com <Directory /> Options FollowSymLinks AllowOverride All </Directory> <Directory /var/www/html/example.com> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> </VirtualHost > <VirtualHost *:80> ServerAdmin webmaster@localhost Servername example.com Redirect 301 / http://www.example.com </VirtualHost>

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  • Setting up Windows 2008 with VPN and NAT

    - by Benson
    I have a Windows 2008 box set up with VPN, and that works quite well. NPS is used to validate the VPN clients, who are able to access the private address of the server, once connected. I can't for the life of me get NAT working for the VPN clients, though. I've added NAT as a routing protocol, and set the one on in the VPN address pool as private, and the other as public - but it still won't NAT connections when I add a route through the VPN server's IP on the client side (route add SomeInternetIp IpOfPrivateInterfaceOnServer). I know I can reach the server's private interface (which happens to be 10.2.2.1) with remote desktop client, so I can't think of any issues with the VPN.

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  • How to I get a rotated sprite to move left or right?

    - by rphello101
    Using Java/Slick 2D, I'm using the mouse to rotate a sprite on the screen and the directional keys (in this case, WASD) to move the spite. Forwards and backwards is easy, just position += cos(ang)*speed or position -= cos(ang)*speed. But how do I get the sprite to move left or right? I'm thinking it has something to do with adding 90 degrees to the angle or something. Any ideas? Rotation code: int mX = Mouse.getX(); int mY = HEIGHT - Mouse.getY(); int pX = sprite.x+sprite.image.getWidth()/2; int pY = sprite.y+sprite.image.getHeight()/2; double mAng; if(mX!=pX){ mAng = Math.toDegrees(Math.atan2(mY - pY, mX - pX)); if(mAng==0 && mX<=pX) mAng=180; } else{ if(mY>pY) mAng=90; else mAng=270; } sprite.angle = mAng; sprite.image.setRotation((float) mAng); And the movement code (delta is change in time): Input input = gc.getInput(); Vector2f direction = new Vector2f(); Vector2f velocity = new Vector2f(); direction.x = (float) Math.cos(Math.toRadians(sprite.angle)); direction.y = (float) Math.sin(Math.toRadians(sprite.angle)); if(direction.length()>0) direction = direction.normalise(); //On a separate note, what does this line of code do? velocity.x = (float) (direction.x * sprite.moveSpeed); velocity.y = (float) (direction.y * sprite.moveSpeed); if(input.isKeyDown(sprite.up)){ sprite.x += velocity.x*delta; sprite.y += velocity.y*delta; }if (input.isKeyDown(sprite.down)){ sprite.x -= velocity.x*delta; sprite.y -= velocity.y*delta; }if (input.isKeyDown(sprite.left)){ //??? }if (input.isKeyDown(sprite.right)){ //??? }

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  • Ways to recover data from external hard drive

    - by Howard Benson
    I use an external hard disk for backup of my mac with time machine (OS 10.5.8). I have made something wrong and I have found important folders in the recycler bin. These folders come from external hd. They are backup folders (backups.backupdb) and others. I have tried to restore them draggin and dropping. Some of them came back in the external hd in a while. For the others it takes hours to "preparing to copy" and then it has said "there's no space to copy" on ext hd. It's strange. Files are now in the recycle bin (180gb), and the ext had should have lot of free space. But it isn't really so. Ext hd is not free of space even if these files are in the bin. I ask for advices. I'm not also able to use time machine now (and i have "lost" old backups) for the same reason. Ext hd says that it has not free space.. Thanks

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