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  • Improving first person camera and implementing third person camera

    - by brainydexter
    I want to improve upon my first person camera implementation and extend it to, so the user can toggle between third person/first person view. My current setup: draw():: glPushMatrix(); m_pCamera->ApplyCameraTransform(); // Render gameObjects glPopMatrix(); Camera is strongly coupled to the player, so much so, that it is a friend of player. This is what the Camera::ApplyCameraTransform looks like: glm::mat4 l_TransformationMatrix; m_pPlayer->m_pTransformation->GetTransformation(l_TransformationMatrix, false); l_TransformationMatrix = glm::core::function::matrix::inverse(l_TransformationMatrix); glMultMatrixf(glm::value_ptr(l_TransformationMatrix)); So, I take the player's transformation matrix and invert it to yield First person camera view. Since, Third person camera view is just a 'translated' first person view behind the player; what would be a good way to improve upon this (keeping in mind that I will be extending it to Third person camera as well. Thanks

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  • The Best Free Online First Person Shooter (FPS) Games

    - by Lori Kaufman
    First Person Shooter (FPS) games are action games centered around gun and projectile weapon-based combat. As the player, you experience the action directly through the eyes of the protagonist. FPS games have become a very popular type of game online. A lot of FPS games are paid, but there are many you can play for free. Most FPS games have online versions where you play in a supported browser or download a program for your PC that allows you to connect to the game online. We have collected links and information about some of the more popular free FPS games available. All the games listed here are free to play, but there may be some limitations, and you have to register for many of them and download game clients to your computer to be able to connect to the game online. Secure Yourself by Using Two-Step Verification on These 16 Web Services How to Fix a Stuck Pixel on an LCD Monitor How to Factory Reset Your Android Phone or Tablet When It Won’t Boot

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  • Starcraft 2 - Third Person Custom Map

    - by Norla
    I would like to try my hand at creating a custom map in Starcraft 2 that has a third-person camera follow an individual unit. There are a few custom maps that exist with this feature already, so I do know this is possible. What I'm having trouble wrapping my head around are the features that are new to the SC2 map editor that didn't exist in the Warcraft 3 editor. For instance, to do a third-person map, do I need a custom mods file, or can everything be done in the map file? Regardless, is it worth using a mod file? What map settings do I NEED to edit/implement? Which are not necessary, but recommended?

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  • Who owns code if its written by one person with another person directing [on hold]

    - by user136226
    I have an Issue that I need some info on. Basically what Im looking to find out is if I create software,and someone else gives me direction on what they want the software to look like,e.g. an image here,this font of text and it must behave in a certain way. Also some of the code was not developed on my computer and there is no official agreement in place. Not looking to screw anyone over here but need to protect myself if things go sour. Do I own the software or is it jointly owned? Thanks

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  • Improve mouse movement in First person game

    - by brainydexter
    In my current FPS game, I have the mouse setup in a way, that it always forces the position of the mouse to be centered at the screen. This gets the job done, but also gets very annoying, since the mouse is "fixed" at the center of the screen. Here is what I am doing: get mouse current position find offset from center of the screen set mouse current position to center of the screen apply difference to m_pTransformation (transformation matrix of the player) Is there a better way to deal with this ?

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  • Adidas by Jeremy Scott is the famous ‘wings’

    - by WoolrichParka
    The higher on this design activities the United states banner layover all over the shoes with red lines on one remaining feet and Adidas by Jeremy Scott the famous 5 celebrity agreement in white-colored and red on the other feet.Out of the many couples of JS Pizza 2.0 silhouettes we’ve gotten a look at, one of the more latest and awesome couples features a glow-in-the-dark higher.One of those Adidas Wing Shoes comes with opera create and bone fragments along the shoelaces place.Expect these to fall this fall, along with more from this years’ selection.wufengfengmaple36

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  • Unity - Mecanim & Rigidbody on Third Person Controller - Gravity bug?

    - by Celtc
    I'm working on a third person controller which uses physX to interact with the other objects (using the Rigidbody component) and Mecanim to animate the character. All the animations used are baked to Y, and the movement on this axis is controlled by the gravity applied by the rigidbody component. The configuration of the falling animation: And the character components configuration: Since the falling animation doesn't have root motion on XZ, I move the character on XZ by code. Like this: // On the Ground if (IsGrounded()) { GroundedMovementMgm(); // Stores the velocity velocityPreFalling = rigidbody.velocity; } // Mid-Air else { // Continue the pre falling velocity rigidbody.velocity = new Vector3(velocityPreFalling.x, rigidbody.velocity.y, velocityPreFalling.z); } The problem is that when the chracter starts falling and hit against a wall in mid air, it gets stuck to the wall. Here are some pics which explains the problems: Hope someone can help me. Thanks and sory for my bad english! PD.: I was asked for the IsGrounded() function, so I'm adding it: void OnCollisionEnter(Collision collision) { if (!grounded) TrackGrounded(collision); } void OnCollisionStay(Collision collision) { TrackGrounded(collision); } void OnCollisionExit() { grounded = false; } public bool IsGrounded() { return grounded; } private void TrackGrounded(Collision collision) { var maxHeight = capCollider.bounds.min.y + capCollider.radius * .9f; foreach (var contact in collision.contacts) { if (contact.point.y < maxHeight && Vector3.Angle(contact.normal, Vector3.up) < maxSlopeAngle) { grounded = true; break; } } } I'll also add a LINK to download the project if someone wants it.

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  • How do I have to take into account the direction in which the camera is facing when creating a first person strafe (left/right) movement

    - by Chris
    This is the code I am currently using, and it works great, except for the strafe always causes the camera to move along the X axis which is not relative to the direction in which the camera is actually facing. As you can see currently only the x location is updated: [delta * -1, 0, 0] How should I take into account the direction in which the camera is facing (I have the camera's target x,y,z) when creating a first person strafe (left/right) movement? case 'a': var eyeOriginal = g_eye; var targetOriginal = g_target; var viewEye = g_math.subVector(g_eye, g_target); var viewTarget = g_math.subVector(g_target, g_eye); viewEye = g_math.addVector([delta * -1, 0, 0], viewEye); viewTarget = g_math.addVector([delta * -1, 0, 0], viewTarget); g_eye = g_math.addVector(viewEye, targetOriginal); g_target = g_math.addVector(viewTarget, eyeOriginal); break; case 'd': var eyeOriginal = g_eye; var targetOriginal = g_target; var viewEye = g_math.subVector(g_eye, g_target); var viewTarget = g_math.subVector(g_target, g_eye); viewEye = g_math.addVector([delta, 0, 0], viewEye); viewTarget = g_math.addVector([delta, 0, 0], viewTarget); g_eye = g_math.addVector(viewEye, targetOriginal); g_target = g_math.addVector(viewTarget, eyeOriginal); break;

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  • Passing a comparator syntax help in Java

    - by Crystal
    I've tried this a couple ways, the first is have a class that implements comparator at the bottom of the following code. When I try to pass the comparat in sortListByLastName, I get a constructor not found error and I am not sure why import java.util.*; public class OrganizeThis implements WhoDoneIt { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { PersonLastNameComparator comp = new PersonLastNameComparator(); Map<String, Person> sorted = new TreeMap<String, Person>(comp); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } System.out.println(testObj.getAuthor()); } } class PersonLastNameComparator implements Comparator<Person> { public int compare(Person a, Person b) { return a.getLastName().compareTo(b.getLastName()); } } And then when I tried doing it by creating an anonymous inner class, I also get a constructor TreeMap cannot find symbol error. Any thoughts? inner class method: public Person[] getSortedListByLastName() { //PersonLastNameComparator comp = new PersonLastNameComparator(); Map<String, Person> sorted = new TreeMap<String, Person>(new Comparator<Person>() { public int compare(Person a, Person b) { return a.getLastName().compareTo(b.getLastName()); } }); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; }

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  • convert the output into an list

    - by prince23
    using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Linq.Expressions; using System.Xml.XPath; using System.Xml.Linq; namespace SampleProgram1 { class Program { static void Main(string[] args) { string xml = @"<people> <person><name>kumar</name><school>fes</school><parent>All</parent></person> <person><name>manju</name><school>fes</school><parent>kumar</parent></person> <person><name>anu</name><school>frank</school><parent>kumar</parent></person> <person><name>anitha</name><school>jss</school><parent>All</parent></person> <person><name>rohit</name><school>frank</school><parent>manju</parent></person> <person><name>anill</name><school>vijaya</school><parent>manju</parent></person> <person><name>vani</name><school>jss</school><parent>kumar</parent></person> <person><name>soumya</name><school>jss</school><parent>kumar</parent></person> <person><name>madhu</name><school>jss</school><parent>rohit</parent></person> <person><name>shiva</name><school>jss</school><parent>rohit</parent></person> <person><name>vanitha</name><school>jss</school><parent>anitha</parent></person> <person><name>anu</name><school>jss</school><parent>anitha</parent></person> </people>"; XDocument document = XDocument.Parse(xml); var people = (from person in document.Descendants("person") select new Person { Name = (string)person.Element("name"), School = (string)person.Element("school"), Parent = (string)person.Element("parent") }).ToList(); var parents = people.Where(p => p.Parent == "All"); Action<Person> findChildren = null; findChildren = person => { List<Person> children = people.Where(p => p.Parent == person.Name).ToList(); person.Children = children; foreach (Person p in children) findChildren(p); }; foreach (Person parent in parents) { findChildren(parent); } Action<Person, int> showChildren = null; showChildren = (person, tabs) => { //Console.WriteLine(new string('\t', tabs) + person.Name); if (person.Children != null) { foreach (Person p in person.Children) showChildren(p, tabs + 1); } }; foreach (Person parent in parents) { showChildren(parent, 0); } // Console.Read(); } } class Person { public string Name { get; set; } public string School { get; set; } public string Parent { get; set; } public List<Person> Children { get; set; } } } this my program where i need to put the output into a list an dthen bind the lsit into gridview can any one help me out in syntax achiveing this one. i am using c# 3.5

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  • Pair programming business logic with a non-IT person

    - by user1598390
    Have you have any experience in which a non-IT person works with a programmer during the coding process? It's like pair programming, but one person is a non-IT person that knows a lot about the business, maybe a process engineer with math background who knows how things are calculated and can understand non-idiomatic, procedural code. I've found that some procedural, domain-specific languages like PL/SQL are quite understandable by non-IT engineers. These person end up being co-authors of the code and guarantee the correctness of formulas, factors etc. I've found this kind of pair programming quite productive, this kind of engineer user feel they are also "owners" and "authors" of the code and help minimize misunderstanding in the communication process. They even help design the test cases. Is this practice common ? Does it have a name ? Have you had similar experiences ?

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  • Sorting in Hash Maps in Java

    - by Crystal
    I'm trying to get familiar with Collections. I have a String which is my key, email address, and a Person object (firstName, lastName, telephone, email). I read in the Java collections chapter on Sun's webpages that if you had a HashMap and wanted it sorted, you could use a TreeMap. How does this sort work? Is it based on the compareTo() method you have in your Person class? I overrode the compareTo() method in my Person class to sort by lastName. But it isn't working properly and was wondering if I have the right idea or not. getSortedListByLastName at the bottom of this code is where I try to convert to a TreeMap. Also, if this is the correct way to do it, or one of the correct ways to do it, how do I then sort by firstName since my compareTo() is comparing by lastName. import java.util.*; public class OrganizeThis { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { Map<String, Person> sorted = new TreeMap<String, Person>(staff); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } } } Person class: public class Person implements Comparable { String firstName; String lastName; String telephone; String email; public Person() { firstName = ""; lastName = ""; telephone = ""; email = ""; } public Person(String firstName) { this.firstName = firstName; } public Person(String firstName, String lastName, String telephone, String email) { this.firstName = firstName; this.lastName = lastName; this.telephone = telephone; this.email = email; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getTelephone() { return telephone; } public void setTelephone(String telephone) { this.telephone = telephone; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public int compareTo(Object o) { String s1 = this.lastName + this.firstName; String s2 = ((Person) o).lastName + ((Person) o).firstName; return s1.compareTo(s2); } public boolean equals(Object otherObject) { // a quick test to see if the objects are identical if (this == otherObject) { return true; } // must return false if the explicit parameter is null if (otherObject == null) { return false; } if (!(otherObject instanceof Person)) { return false; } Person other = (Person) otherObject; return firstName.equals(other.firstName) && lastName.equals(other.lastName) && telephone.equals(other.telephone) && email.equals(other.email); } public int hashCode() { return this.email.toLowerCase().hashCode(); } public String toString() { return getClass().getName() + "[firstName = " + firstName + '\n' + "lastName = " + lastName + '\n' + "telephone = " + telephone + '\n' + "email = " + email + "]"; } }

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  • Given a project and working with 1 other person - never worked with someone before

    - by Celeritas
    I'm taking a class where I work with a partner to implement the link layer of the OSI model. I've worked programmed with a partner once before and it went bad. Is the goal to divide the work up and decides who does what or should one person code and the other person reviews and switch roles after a while? Any tips are much appreciated. Literally I know nothing about working with a partner to program so even if it's basic please tell me.

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  • Frustum culling with third person camera

    - by Christian Frantz
    I have a third person camera that contains two matrices: view and projection, and two Vector3's: camPosition and camTarget. I've read up on frustum culling and it makes it seem easy enough for a first person camera, but how would I implement this for a third person camera? I need to take into effect the objects I can see behind me too. How would I implement this into my camera class so it runs at the same time as my update method? public void CameraUpdate(Matrix objectToFollow) { camPosition = objectToFollow.Translation + (objectToFollow.Backward *backward) + (objectToFollow.Up * up); camTarget = objectToFollow.Translation; view = Matrix.CreateLookAt(camPosition, camTarget, Vector3.Up); } Can I just create another method within the class which creates a bounding sphere with a value from my camera and then uses the culling based on that? And if so, which value am I using to create the bounding sphere from? After this is implemented, I'm planning on using occlusion culling for the faces of my objects adjacent to other objects. Will using just one or the other make a difference? Or will both of them be better? I'm trying to keep my framerate as high as possible

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  • Circular dependency and object creation when attempting DDD

    - by Matthew
    I have a domain where an Organization has People. Organization Entity public class Organization { private readonly List<Person> _people = new List<Person>(); public Person CreatePerson(string name) { var person = new Person(organization, name); _people.Add(person); return person; } public IEnumerable<Person> People { get { return _people; } } } Person Entity public class Person { public Person(Organization organization, string name) { if (organization == null) { throw new ArgumentNullException("organization"); } Organization = organization; Name = name; } public Organization { get; private set; } public Name { get; private set; } } The rule for this relationship is that a Person must belong to exactly one Organization. The invariants I want to guarantee are: A person must have an organization this is enforced via the Person's constuctor An organization must know of its people this is why the Organization has a CreatePerson method A person must belong to only one organization this is why the organization's people list is not publicly mutable (ignoring the casting to List, maybe ToEnumerable can enforce that, not too concerned about it though) What I want out of this is that if a person is created, that the organization knows about its creation. However, the problem with the model currently is that you are able to create a person without ever adding it to the organizations collection. Here's a failing unit-test to describe my problem [Test] public void AnOrganizationMustKnowOfItsPeople() { var organization = new Organization(); var person = new Person(organization, "Steve McQueen"); CollectionAssert.Contains(organization.People, person); } What is the most idiomatic way to enforce the invariants and the circular relationship?

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  • Java Dynamic Binding

    - by Chris Okyen
    I am having trouble understanding the OOP Polymorphic principl of Dynamic Binding ( Late Binding ) in Java. I looked for question pertaining to java, and wasn't sure if a overall answer to how dynamic binding works would pertain to Java Dynamic Binding, I wrote this question. Given: class Person { private String name; Person(intitialName) { name = initialName; } // irrelevant methods is here. // Overides Objects method public void writeOutput() { println(name); } } class Student extends Person { private int studentNumber; Student(String intitialName, int initialStudentNumber) { super(intitialName); studentNumber = initialStudentNumber; } // irrellevant methods here... // overides Person, Student and Objects method public void writeOutput() { super.writeOutput(); println(studentNumber); } } class Undergaraduate extends Student { private int level; Undergraduate(String intitialName, int initialStudentNumber,int initialLevel) { super(intitialName,initialStudentNumber); level = initialLevel; } // irrelevant methods is here. // overides Person, Student and Objects method public void writeOutput() { super.writeOutput(); println(level); } } I am wondering. if I had an array called person declared to contain objects of type Person: Person[] people = new Person[2]; person[0] = new Undergraduate("Cotty, Manny",4910,1); person[1] = new Student("DeBanque, Robin", 8812); Given that person[] is declared to be of type Person, you would expect, for example, in the third line where person[0] is initialized to a new Undergraduate object,to only gain the instance variable from Person and Persons Methods since doesn't the assignment to a new Undergraduate to it's ancestor denote the Undergraduate object to access Person - it's Ancestors, methods and isntance variables... Thus ...with the following code I would expect person[0].writeOutput(); // calls Undergraduate::writeOutput() person[1].writeOutput(); // calls Student::writeOutput() person[0] to not have Undergraduate's writeOutput() overidden method, nor have person[1] to have Student's overidden method - writeOutput(). If I had Person mikeJones = new Student("Who?,MikeJones",44,4); mikeJones.writeOutput(); The Person::writeOutput() method would be called. Why is this not so? Does it have to do with something I don't understand about relating to arrays? Does the declaration Person[] people = new Person[2] not bind the method like the previous code would?

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  • Finding a person in the forest

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved finding a person in the forest or Limiting the AD result in SharePoint People Picker There are times when we need to limit the SharePoint audience of certain farms or servers or site collections to a particular audience. One of my experiences involved limiting access to US citizens, another to a particular location. Now, most of us – your humble servant included – are not Active Directory experts – but we must be able to handle the “audience restrictions” as required. So here is how it’s done in a nutshell. Important note. Not all could be done in PowerShell (at least not yet)! There are no Windows PowerShell commands to configure People Picker. The stsadm command is: stsadm -o setproperty -pn peoplepicker-searchadcustomquery -pv ADQuery –url http://somethingOrOther Note the long-hyphenated property name. Now to filling the ADQuery.   LDAP Query in a nutshell Syntax LDAP is no older than SQL and an LDAP query is actually a query against the LDAP Database. LDAP attributes are the equivalent of Database columns, so why do we have to learn a new query language? Beats me! But we must, so here it is. The syntax of an LDAP query string is made of individual statements with relational operators including: = Equal <= Lower than or equal >= Greater than or equal… and memberOf – a group membership. ! Not * Wildcard Equal and memberOf are the most commonly used. Checking for absence uses the ! – not and the * - wildcard Example: (SN=Grant) All whose last name – SurName – is Grant Example: (!(SN=Grant)) All except Grant Example: (!(SN=*)) all where there is no SurName i.e SurName is absent (probably Rappers). Example: (CN=MyGroup) Common Name is MyGroup.  Example: (GN=J*) all the Given Names that start with J (JJ, Jane, Jon, John, etc.) The cryptic SN, CN, GN, etc. are attributes and more about them later All the queries are enclosed in parentheses (Query). Complex queries are comprised of sets that are in AND or OR conditions. AND is denoted by the ampersand (&) and the OR is denoted by the vertical pipe (|). The general syntax is that of the Prefix polish notation where the operand precedes the variables. E.g +ab is the sum of a and b. In an LDAP query (&(A)(B)) will garner the objects for which both A and B are true. In an LDAP query (&(A)(B)(C)) will garner the objects for which A, B and C are true. There’s no limit to the number of conditions. In an LDAP query (|(A)(B)) will garner the objects for which either A or B are true. In an LDAP query (|(A)(B)(C)) will garner the objects for which at least one of A, B and C is true. There’s no limit to the number of conditions. More complex queries have both types of conditions and the parentheses determine the order of operations. Attributes Now let’s get into the SN, CN, GN, and other attributes of the query SN – is the SurName (last name) GN – is the Given Name (first name) CN – is the Common Name, usually GN followed by SN OU – is an Organization Unit such as division, department etc. DC – is a Domain Content in the AD forest l – lower case ‘L’ stands for location. Jerusalem anybody? Or Katmandu. UPN – User Principal Name, is usually the first part of an email address. By nature it is unique in the forest. Most systems set the UPN to be the first initial followed by the SN of the person involved. Some limit the total to 8 characters. If we have many ‘jsmith’ we have to somehow distinguish them from each other. DN – is the distinguished name – a name unique to AD forest in which it lives. Usually it’s a CN with some domain or group distinguishers. DN is important in conjunction with the memberOf relation. Groups have stricter requirement. Each group has to have a unique name - its CN and it has to be unique regardless of its place. See more below. All of the attributes are case insensitive. CN, cn, Cn, and cN are identical. objectCategory is an element that requires special consideration. AD contains many different object like computers, printers, and of course people and groups. In the queries below, we’re limiting our search to people (person). Putting it altogether Let’s get a list of all the Johns in the SPAdmin group of the Jerusalem that local domain. (&(objectCategory=person)(memberOf=cn=SPAdmin,ou=Jerusalem,dc=local)) The memberOf=cn=SPAdmin uses the cn (Common Name) of the SPAdmin group. This is how the memberOf relation is used. ‘SPAdmin’ is actually the DN of the group. Also the memberOf relation does not allow wild cards (*) in the group name. Also, you are limited to at most one ‘OU’ entry. Let’s add Marvin Minsky to the search above. |(&(objectCategory=person)(memberOf=cn=SPAdmin,ou=Jerusalem,dc=local))(CN=Marvin Minsky) Here I added the or pipeline at the beginning of the query and put the CN requirement for Minsky at the end. Note that if Marvin was already in the prior result, he’s not going to be listed twice. One last note: You may see a dryer but more complete list of attributes rules and examples in: http://www.tek-tips.com/faqs.cfm?fid=5667 And finally (thus negating the claim that my previous note was last), to the best of my knowledge there are 3 more ways to limit the audience. One is to use the peoplepicker-searchadcustomfilter property using the same ADQuery. This works only in SP1 and above. The second is to limit the search to users within this particular site collection – the property name is peoplepicker-onlysearchwithinsitecollection and the value is yes (-pv yes) And the third is –pn peoplepicker-serviceaccountdirectorypaths –pv “OU=ou1,DC=dc1…..” Again you are limited to at most one ‘OU’ phrase – no OU=ou1,OU=ou2… And now the real end. The main property discussed in this sprawling and seemingly endless monogram – peoplepicker-searchadcustomquery - is the most general way of getting the job done. Here are a few examples of command lines that worked and some that didn’t. Can you see why? C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (Title=David) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (!Title=David) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (OU=OURealName,OU=OUMid,OU=OUTop,DC=TopDC,DC=MidDC,DC=BottomDC) Command line error. Too many OUs C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (OU=OURealName) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (DC=TopDC,DC=MidDC,DC=BottomDC) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (OU=OURealName,DC=TopDC,DC=MidDC,DC=BottomDC) Operation completed successfully.   That’s all folks!

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  • How do I sort an array of Person Objects by using compareto()?

    - by Adam
    Here is my code: > import java.util.Scanner; import java.util.Arrays; /** This class tests the Person class. */ public class PersonDemo { public static void main(String[] args) { int count = 0; Scanner in = new Scanner(System.in); boolean more = false; Person first = null; Person last = null; while (more) { System.out.println( "Please enter the person's name or a blank line to quit"); String name = in.nextLine(); if (name.equals("")) more = false; else { Person p = new Person(name); //new person object created with inputted name Person[] people = new Person[10]; //new array of 10 person objects people[count] = p; //declare person object with index of variable count as the new person object first = people[count]; // I have no idea what to do here. This is where I'm stuck. last = people[count]; // I can't figure out what to do with this either. first.compareTo(p); //call compareTo method on first and new person object last.compareTo(p); //call compareTo method on last and new person object count++; // increase count variable } } System.out.println("First: " + first.toString()); System.out.println("Last: " + last.toString()); } } And the Person class: /** A person with a name. */ public class Person implements Comparable { /** * Constructs a Person with a name. * @param aName the person's name */ public Person(String aName) { name = aName; } public String getName() { return name; } @Override public int compareTo(Object otherObject) { Person other = (Person)otherObject; if (name.compareTo(other.name) < 0) return -1; if (name.compareTo(other.name) > 0) return 1; return 0; } /** Returns a string representation of the object. @return name of Person */ public String toString() { return "[name=" + name + "]"; } private String name; }

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  • Camera rotation - First Person Camera using GLM

    - by tempvar
    I've just switched from deprecated opengl functions to using shaders and GLM math library and i'm having a few problems setting up my camera rotations (first person camera). I'll show what i've got setup so far. I'm setting up my ViewMatrix using the glm::lookAt function which takes an eye position, target and up vector // arbitrary pos and target values pos = glm::vec3(0.0f, 0.0f, 10.0f); target = glm::vec3(0.0f, 0.0f, 0.0f); up = glm::vec3(0.0f, 1.0f, 0.0f); m_view = glm::lookAt(pos, target, up); i'm using glm::perspective for my projection and the model matrix is just identity m_projection = glm::perspective(m_fov, m_aspectRatio, m_near, m_far); model = glm::mat4(1.0); I send the MVP matrix to my shader to multiply the vertex position glm::mat4 MVP = camera->getProjection() * camera->getView() * model; // in shader gl_Position = MVP * vec4(vertexPos, 1.0); My camera class has standard rotate and translate functions which call glm::rotate and glm::translate respectively void camera::rotate(float amount, glm::vec3 axis) { m_view = glm::rotate(m_view, amount, axis); } void camera::translate(glm::vec3 dir) { m_view = glm::translate(m_view, dir); } and i usually just use the mouse delta position as the amount for rotation Now normally in my previous opengl applications i'd just setup the yaw and pitch angles and have a sin and cos to change the direction vector using (gluLookAt) but i'd like to be able to do this using GLM and matrices. So at the moment i have my camera set 10 units away from the origin facing that direction. I can see my geometry fine, it renders perfectly. When i use my rotation function... camera->rotate(mouseDeltaX, glm::vec3(0, 1, 0)); What i want is for me to look to the right and left (like i would with manipulating the lookAt vector with gluLookAt) but what's happening is It just rotates the model i'm looking at around the origin, like im just doing a full circle around it. Because i've translated my view matrix, shouldn't i need to translate it to the centre, do the rotation then translate back away for it to be rotating around the origin? Also, i've tried using the rotate function around the x axis to get pitch working, but as soon as i rotate the model about 90 degrees, it starts to roll instead of pitch (gimbal lock?). Thanks for your help guys, and if i've not explained it well, basically i'm trying to get a first person camera working with matrix multiplication and rotating my view matrix is just rotating the model around the origin.

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  • Title of person reporting to CEO responsible for strategy and projects [closed]

    - by user64134
    Case in point: What is the title of the person reporting directly to the CEO and/or CTO, responsible for the overall technical strategy and the overall responsibility for all projects and programs among multiple teams (being led by team leads) in a tech company I'm thinking that it is a mix of a staff and line position - making chief architect being too advisory and not matching the project/program part and VP of engineering a bit too high level?

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  • Rendering skybox in first person shooter

    - by brainydexter
    I am trying to get a skybox rendered correctly in my first person shooter game. I have the skybox cube rendering using GL_TEXTURE_CUBE_MAP. I author the cube with extents of -1 and 1 along X,Y and Z. However, I can't wrap my head around the camera transformations that I need to apply to get it right. My render loop looks something like this: mp_Camera-ApplyTransform() :: Takes the current player transformation and inverts it and pushes that on the modelview stack. Draw GameObjects Draw Skybox DrawSkybox does the following: glEnable(GL_TEXTURE_CUBE_MAP); glDepthMask(GL_FALSE); // draw the cube here with extents glDisable(GL_TEXTURE_CUBE_MAP); glDepthMask(GL_TRUE); Do I need to translate the skybox by the translation of the camera ? (btw, that didn't help either) EDIT: I forgot to mention: It looks like a small cube with unit extents. Also, I can strafe in/out of the cube. Screenshot:

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  • First Person Shooter game agent development

    - by LangerHansIslands
    I would like to apply (program) the Artificial intelligence methods to create a intelligent game bots for a first person shooter game. Do you have any knowledge from where can I start to develop as a Linux user? Do you have a suggestion for an easy-to-start game for which I can develop bots easily, caring more about the result of my algorithms rather than spending a lot of time dealing with the game code? I've read some publications about the applied methods to Quake 3 (c) and Open Arena. But I couldn't find the source codes and manuals describing how to start coding( for compiling, developing ai and etc.). I appreciate your help.

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  • Referring to hardware/software in first-person? [closed]

    - by JYelton
    At my company, there is a habit for the engineers to refer to their respective hardware/firmware/software in the first-person as if the device they are responsible for is a manifestation of themselves. I'll give you an example: Hardware Engineer: "I don't receive the first byte, so I stay off." Software Engineer: "I'm sending you the first byte after the ack flag, so I thought you were getting it." Hardware Engineer: "No, you're not turning me on." It was this very example I overheard today that nearly had me giggling in fits. "You're not turning me on." Well, I should hope not! So, is it common practice for engineers to do this, or simply unprofessional? Any suggestions for changing this apparently bad habit?

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  • 2010 SQLPeople Person of the Year

    - by andyleonard
    Introduction Back in 2010, I started recognizing the SQLPeople Person of the Year. It's been a tradition ever since. "But Andy, you're writing this in 2010." Yep. Good eye, Pep. The Award Goes To: Steve Jones ( Blog | @way0utwest ). I am not a DBA - I'm a database developer. I joke and say I look like the world's greatest DBA when there's no contention, the jobs are finishing successfully, queries return data quickly and accurately, and the backups succeed. But anyone looks like the world's greatest...(read more)

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  • Tableview not updating correctly after adding person

    - by tazboy
    I have to be missing something simple here but it escapes me. After the user enters a new person to a mutable array I want to update the table. The mutable array is the datasource. I believe my issue lies within cellForRowAtIndexPath. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { TextFieldCell *customCell = (TextFieldCell *)[tableView dequeueReusableCellWithIdentifier:@"TextCellID"]; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"cell"]; if (indexPath.row == 0) { if (customCell == nil) { NSArray *nibObjects = [[NSBundle mainBundle] loadNibNamed:@"TextFieldCell" owner:nil options:nil]; for (id currentObject in nibObjects) { if ([currentObject isKindOfClass:[TextFieldCell class]]) customCell = (TextFieldCell *)currentObject; } } customCell.nameTextField.delegate = self; cell = customCell; } else { if (cell == nil) { cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"cell"]; cell.textLabel.text = [[self.peopleArray objectAtIndex:indexPath.row-1] name]; NSLog(@"PERSON AT ROW %d = %@", indexPath.row-1, [[self.peopleArray objectAtIndex:indexPath.row-1] name]); NSLog(@"peopleArray's Size = %d", [self.peopleArray count]); } } return cell; } When I first load the view everything is great. This is what prints: PERSON AT ROW 0 = Melissa peopleArray's Size = 2 PERSON AT ROW 1 = Dave peopleArray's Size = 2 After I add someone to that array I get this: PERSON AT ROW 1 = Dave peopleArray's Size = 3 PERSON AT ROW 2 = Tom peopleArray's Size = 3 When I add a second person I get: PERSON AT ROW 2 = Tom peopleArray's Size = 4 PERSON AT ROW 3 = Ralph peopleArray's Size = 4 Why is not printing everyone in the array? This pattern continues and it only ever prints two people, and it's always the last two people. What the heck am I missing?

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