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  • Implementing Linked Lists in C#

    - by nijhawan.saurabh
    Why? The question is why you need Linked Lists and why it is the foundation of any Abstract Data Structure. Take any of the Data Structures - Stacks, Queues, Heaps, Trees; there are two ways to go about implementing them - Using Arrays Using Linked Lists Now you use Arrays when you know about the size of the Nodes in the list at Compile time and Linked Lists are helpful where you are free to add as many Nodes to the List as required at Runtime.   How? Now, let's see how we go about implementing a Simple Linked List in C#. Note: We'd be dealing with singly linked list for time being, there's also another version of linked lists - the Doubly Linked List which maintains two pointers (NEXT and BEFORE).   Class Diagram Let's see the Class Diagram first:     Code     1 // -----------------------------------------------------------------------     2 // <copyright file="Node.cs" company="">     3 // TODO: Update copyright text.     4 // </copyright>     5 // -----------------------------------------------------------------------     6      7 namespace CSharpAlgorithmsAndDS     8 {     9     using System;    10     using System.Collections.Generic;    11     using System.Linq;    12     using System.Text;    13     14     /// <summary>    15     /// TODO: Update summary.    16     /// </summary>    17     public class Node    18     {    19         public Object data { get; set; }    20     21         public Node Next { get; set; }    22     }    23 }    24         1 // -----------------------------------------------------------------------     2 // <copyright file="LinkedList.cs" company="">     3 // TODO: Update copyright text.     4 // </copyright>     5 // -----------------------------------------------------------------------     6      7 namespace CSharpAlgorithmsAndDS     8 {     9     using System;    10     using System.Collections.Generic;    11     using System.Linq;    12     using System.Text;    13     14     /// <summary>    15     /// TODO: Update summary.    16     /// </summary>    17     public class LinkedList    18     {    19         private Node Head;    20     21         public void AddNode(Node n)    22         {    23             n.Next = this.Head;    24             this.Head = n;    25     26         }    27     28         public void printNodes()    29         {    30     31             while (Head!=null)    32             {    33                 Console.WriteLine(Head.data);    34                 Head = Head.Next;    35     36             }    37     38         }    39     }    40 }    41          1 using System;     2 using System.Collections.Generic;     3 using System.Linq;     4 using System.Text;     5      6 namespace CSharpAlgorithmsAndDS     7 {     8     class Program     9     {    10         static void Main(string[] args)    11         {    12             LinkedList ll = new LinkedList();    13             Node A = new Node();    14             A.data = "A";    15     16             Node B = new Node();    17             B.data = "B";    18     19             Node C = new Node();    20             C.data = "C";    21             ll.AddNode(A);    22             ll.AddNode(B);    23             ll.AddNode(C);    24     25             ll.printNodes();    26         }    27     }    28 }    29        Final Words This is just a start, I will add more posts on Linked List covering more operations like Delete etc. and will also explore Doubly Linked List / Implementing Stacks/ Heaps/ Trees / Queues and what not using Linked Lists.   Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Global Address List, Multiple All Address Lists in CN=Address Lists Container

    - by Jonathan
    When my colleges (that was way before my time here) updated Exchange 2000 to 2003 a English All Address Lists appeared in addition to the German variant. The English All Address Lists have German titled GAL below it. This has just been a cosmetic problem for the last few years. Now as we are in the process of rolling out Exchange 2010 this causes some issues. Exchange 2010 picked the wrong i.e. English Address Lists Container to use. In ADSI Editor we see CN=All Address Lists,CN=Address Lists Container,CN=exchange org,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain and CN=Alle Adresslisten,CN=Address Lists Container,CN=exchange org,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain. In the addressBookRoots attribute of CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain both address lists were stored as values. We removed the English variant from addressBookRoots and restarted all (old and new) Exchange servers. User with mailboxes on the Exchange 2003 now only sees the German variant. Exchange 2010 is still stuck with the English/Mixed variant as are Users on Exchange 2010. Our goal would be to have Outlook display the German title of All Address Lists and get rid of the wrong Address Lists Container.

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  • not able to remove nested lists in a jQuery variable

    - by Pradyut Bhattacharya
    Hi I have a nested oredered list which i m animating using this code... var $li = $("ol#update li"); function animate_li(){ $li.filter(':first') .animate({ height: 'show', opacity: 'show' }, 500, function(){ animate_li(); }); $li = $li.not(':first'); } animate_li(); now i want not to show or animate the nested lists(ol s) or the li s in the ols take a look at the example here The structure of my ols are <ol> <li class="bar248"> <div class="nli"> <div class="pic"> <img src="dir/anonymous-thumb.png"alt="image" /> </div> <div align="left" class="text"> <span> <span class="delete_button"><a href="#" id="test" class="delete_update">R</a></span> test shouted <span class="timestamp"> 2010/02/24 18:34:26 </span> <br /> this </span> </div> <div class="clear"></div> </div> <div class="padd"> </div> <ol class="comment"> <li> <div>Testing </div> </li> <li> <div>Another Test </div> </li> </ol> </li> </ol> I m able to hide the nested ols using this code... $("ol#update li ol").hide(); But still time is being consumed in animating them although they are hidden I m not able to remove the nested li s using this code var $li = $("ol#update li").not("ol#update li ol"); $li = $li.not("ol#update li ol"); Take a look at this here Any help thanks < br Pradyut

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  • Number nested ordered lists in HTML

    - by John
    Hi I have a nested ordered list. <ol> <li>first</li> <li>second <ol> <li>second nested first element</li> <li>second nested secondelement</li> <li>second nested thirdelement</li> </ol> </li> <li>third</li> <li>fourth</li> </ol> Currently the nested elements start back from 1 again, e.g. first second second nested first element second nested second element second nested third element third fourth What I want is for the second element to be numbered like this: first second 2.1. second nested first element 2.2. second nested second element 2.3. second nested third element third fourth Is there a way of doing this? Thanks

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  • Why are listener lists Lists?

    - by Joonas Pulakka
    Why are listener lists (e.g. in Java those that use addXxxListener() and removeXxxListener() to register and unregister listeners) called lists, and usually implemented as Lists? Wouldn't a Set be a better fit, since in the case of listeners there's No matter in which order they get called (although there may well be such needs, but they're special cases; ordinary listener mechanisms make no such guarantees), and No need to register the same listener more than once (whether doing that should result in calling the same listener 1 times or N times, or be an error, is another question) Is it just a matter of tradition? Sets are some kind of lists under the hood anyway. Are there performance differences? Is iterating through a List faster or slower than iterating through a Set? Does either take more or less memory? The differences are certainly almost negligible.

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  • How to sort a list alphabetically and have additional lists sorted in the same order

    - by Carl
    I have 3 lists, each with equal elements: email addresses, salaries and IDs I'd like to sort the email addresses alphabetically and in some way sort the other 2 lists (salaries and IDs). E.g., Emails: [email protected] [email protected] Salaries: 50000 60000 IDs: 2 1 The puzzle: I'd like to sort Emails such that [email protected] is first and [email protected] is last and Salaries is 60000 then 50000 and IDs is 1 then 2. Additional detail: 1. Length of lists are the same and can be longer than two elements. 2. I will subsequently pass IDs to functions to retrieve further lists. Those lists won't need sorting as they will adopt the order of the IDs list.

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  • HTML/CSS - How can I position these nested unordered lists correctly?

    - by Samuroid
    I am looking for some help resolving an issue im having with positioning the following unordered list elements that are contained in a div which has relative positioning: The html structure of the UL: <div id="accountBox" class="account_settings_box"> <ul> <ul> <li class="profileImage"><img src="images/profileimage.jpg" alt="Profile Image" /></li> <li class="profileName">Your name</li> <li class="profileEmail">Your email</li> </ul> <li><a href="">Messages</a></li> <li><a href="">Settings</a></li> <li><a href="">Password</a></li> <li><a href="">Sign out</a></li> </ul> </div> and the CSS for this list: .account_settings_box ul ul { display: inline-block; margin: 0; padding: 0; width: 100%; height: 150px; outline: 1px solid blue; } .account_settings_box ul ul li { display: inline-block; border: none; /* Reset the border */ } .profileImage { float: right; display: block; width: 150px; height: 150px; outline: 1px solid purple; } .profileName, .profileEmail { width: auto; height: auto; width: 150px; height: 150px; } .account_settings_box ul ul li:hover { outline: 1px solid red; } .profileImage img { width: 150px; height: 150px; } I am having difficultly with the embedded ul, i.e, .account_settings_box ul ul element. The image below shows what it currently looks like. I am trying to achieve the follow: Have the image floating to the right, and have the "your name" and "your email" positioned to the left of the image (basically where they are currently). Thanks for your help in advance. Sam :)

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  • Combining lists but getting unique members

    - by MC
    I have a bit of a special requirement when combining lists. I will try to illustrate with an example. Lets say I'm working with 2 lists of GamePlayer objects. GamePlayer has a property called LastGamePlayed. A unique GamePlayer is identified through the GamePlayer.ID property. Now I'd like to combine listA and listB into one list, and if a given player is present in both lists I'd like to keep the value from listA. I can't just combine the lists and use a comparer because my uniqueness is based on ID, and if my comparer checks ID I will not have control over whether it picks the element of listA or listB. I need something like: for each player in listB { if not listA.Contains(player) { listFinal.Add(player) } } However, is there a more optimal way to do this instead of searching listA for each element in listB?

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  • Merging k sorted linked lists - analysis

    - by Kotti
    Hi! I am thinking about different solutions for one problem. Assume we have K sorted linked lists and we are merging them into one. All these lists together have N elements. The well known solution is to use priority queue and pop / push first elements from every lists and I can understand why it takes O(N log K) time. But let's take a look at another approach. Suppose we have some MERGE_LISTS(LIST1, LIST2) procedure, that merges two sorted lists and it would take O(T1 + T2) time, where T1 and T2 stand for LIST1 and LIST2 sizes. What we do now generally means pairing these lists and merging them pair-by-pair (if the number is odd, last list, for example, could be ignored at first steps). This generally means we have to make the following "tree" of merge operations: N1, N2, N3... stand for LIST1, LIST2, LIST3 sizes O(N1 + N2) + O(N3 + N4) + O(N5 + N6) + ... O(N1 + N2 + N3 + N4) + O(N5 + N6 + N7 + N8) + ... O(N1 + N2 + N3 + N4 + .... + NK) It looks obvious that there will be log(K) of these rows, each of them implementing O(N) operations, so time for MERGE(LIST1, LIST2, ... , LISTK) operation would actually equal O(N log K). My friend told me (two days ago) it would take O(K N) time. So, the question is - did I f%ck up somewhere or is he actually wrong about this? And if I am right, why doesn't this 'divide&conquer' approach can't be used instead of priority queue approach?

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  • Is the a pattern for iterating over lists held by a class (dynamicly typed OO languages)

    - by Roman A. Taycher
    If I have a class that holds one or several lists is it better to allow other classes to fetch those lists(with a getter) or to implement a doXList/eachXList type method for that list that take a function and call that function on each element of the list contained by that object. I wrote a program that did a ton of this and I hated passing around all these lists sometimes with method in class a calling method in class B to return lists contained in class C, B contains a C or multiple C's (note question is about dynamically typed OO languages languages like ruby or smalltalk) ex. (that came up in my program) on a Person class containing scheduling preferences and a scheduler class needing to access them.

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  • Lists inside lists don't validate with w3c?

    - by cosmicbdog
    Hi everybody, I've got some lists inside lists to make some fancy drop-down menus. e.g <ul> <li>something <ul> <li>sub menu</li> </ul> </li> </ul> Problem is, w3c doesn't like it. Is there a way to make this validate or this just one of these hacks that browsers can render, but w3c dislikes?

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  • Exchange mail users cannot send to certain lists

    - by blsub6
    First of all, everyone's on Exchange 2010 using OWA I have a dynamic distribution list that contains all users in my domain called 'staff'. I can send to this list, other people can send to this list, but I have one user that cannot send to this list. Sending to this list gives the user an email back with the error: Delivery has failed to these recipients or groups: Staff The e-mail address you entered couldn't be found. Please check the recipient's e-mail address and try to resend the message. If the problem continues, please contact your helpdesk. and then a bunch of diagnostic information that I don't want to paste here because I don't want to have to censor all of the sensitive information contained (lazy) Can you guys throw me some possible reasons why this would happen? If there are an innumerable number of reasons, where should I start to troubleshoot this? EDIT One Exchange server inside the network that acts as a transport server, client access server and mailbox server and one Edge Transport server in the DMZ.

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  • Regex for recursive "wiki-style" lists

    - by Syd Miller
    I'm trying to create a Regular Expression to match "wiki style" lists as in (using preg_replace_callback() ): * List Item 1 * List Item 2 *# List Item 2.1 *# List Item 2.2 * List Item 3 Asterisks denote Unordered Lists while Number-Signs denote Ordered Lists. I'm trying to get this so it can match infinite depth and so that * and # can be mixed. I tried the following expression (and variations of it): /\s([*#]{1,}) ([\S ]+)\s/si But it doesn't seem to want to work. What am I doing wrong? Or is there a better way of accomplishing this?

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  • taking intersection of N-many lists in python

    - by user248237
    what's the easiest way to take the intersection of N-many lists in python? if I have two lists a and b, I know I can do: a = set(a) b = set(b) intersect = a.intersection(b) but I want to do something like a & b & c & d & ... for an arbitrary set of lists (ideally without converting to a set first, but if that's the easiest / most efficient way, I can deal with that.) I.e. I want to write a function intersect(*args) that will do it for arbitrarily many sets efficiently. What's the easiest way to do that? EDIT: My own solution is reduce(set.intersection, [a,b,c]) -- is that good? thanks.

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  • python union of 2 nested lists with index

    - by sbas
    I want to get the union of 2 nested lists plus an index to the common values. I have two lists like A = [[1,2,3],[4,5,6],[7,8,9]] and B = [[1,2,3,4],[3,3,5,7]] but the length of each list is about 100 000. To A belongs an index vector with len(A): I = [2,3,4] What I want is to find all sublists in B where the first 3 elements are equal to a sublist in A. In this example I want to get B[0] returned ([1,2,3,4]) because its first three elements are equal to A[0]. In addition, I also want the index to A[0] in this example, that is I[0]. I tried different things, but nothing worked so far :( First I tried this: Common = [] for i in range(len(B)): if B[i][:3] in A: id = [I[x] for x,y in enumerate(A) if y == B[i][:3]][0] ctdCommon.append([int(id)] + B[i]) But that takes ages, or never finishes Then I transformed A and B into sets and took the union from both, which was very quick, but then I don't know how to get the corresponding indices Does anyone have an idea?

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  • How to hide Lists from specific group?

    - by DanSogaard
    How to hide Lists from specific group, but at the same time allow them to add items in it?. I edited permission levels for the site and created a permission that has these privileges: List Permissions: Add Items, View Items. Site Permissions: View Pages, Open. And then assign this permission to the group along with View Only. However this would still show Lists and the users are able to access them. How can I hide it from this specific group only?.

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  • Feature activate via UI but does not show in the Libraries and Lists

    - by Justin Cullen
    I am really hating SharePoint as there are hardly any good/concrete documentation. I developed custom List "MainCatalog" with few columns (not site columns). Create features and elements with MOSS feature builder at Site collection level so scope="site" installed via stsadm activated via UI "went to site collection website", Site Setting Site collection Feature (and saw my custom list "MainCatalog") and was able to activate. then went to "mySiteCollection Site Settings Site Libraries and Lists " My list is showing But it shows in the "mySiteCollection Create Custom Lists "MainCatalog" I guess it's showing there as a template... But my intention is to deploy this list from development to test environment. EXTREMELY STRESSED. I AM ON THIS FOR LAST 8 DAYS.....

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  • filtering elements from list of lists in Python?

    - by user248237
    I want to filter elements from a list of lists, and iterate over the elements of each element using a lambda. For example, given the list: a = [[1,2,3],[4,5,6]] suppose that I want to keep only elements where the sum of the list is greater than N. I tried writing: filter(lambda x, y, z: x + y + z >= N, a) but I get the error: <lambda>() takes exactly 3 arguments (1 given) How can I iterate while assigning values of each element to x, y, and z? Something like zip, but for arbitrarily long lists. thanks, p.s. I know I can write this using: filter(lambda x: sum(x)..., a) but that's not the point, imagine that these were not numbers but arbitrary elements and I wanted to assign their values to variable names.

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  • Updating Lists of Lists in Tapestry4 using textfields and a single submit button

    - by Nicolas Scarrci
    In Tapestry 4 I am trying it iterate over a list of lists (technically a list of objects who have a list of strings as a data field). I am currently doing this by using 'nested' for components. (This is pseudo code) <span jwcid="Form"> <span jwcid="@For" source="ognl:Javaclass.TopLevelList" value="ognl:SecondLevelList" index="ognl:index"> <span jwcid="@For" source="ognl:SecondLevelList.List" value="ognl:ListItem" index="ListItemIndex"> <span jwcid="@TextField" value="ognl:ListItem"/> <span jwcid="@Submit" listener="ognl:listeners.onSubmit"/> </span></span></span> The onSubmit listener then accesses the index and ListItem index page properties, as well as the ListItem page property in order to correctly update the list in Javaclass.TopLevelList. This works fine, but it looks terrible, and is cumbersome to the end user. I would prefer to somehow simulate this functionality using only one submit button at the bottom of the page. I have looked into somehow using the overlying form component to obtain a list of the 'form control components' within it, and then (with great care) parsing through tapestry's naming conventions to recover the functionality of the indexes. If anyone knows how to do this, or could explain the form component (how/when it submits, etc.) it would be greatly appreciated.

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  • Combining lists of objects containing lists of objects in c#

    - by Dan H
    The title is a little prosaic, I know. I have 3 classes (Users, Cases, Offices). Users and Cases contain a list of Offices inside of them. I need to compare the Office lists from Users and Cases and if the ID's of Offices match, I need to add those IDs from Cases to the Users. So the end goal is to have the Users class have any Offices that match the Offices in the Cases class. Any ideas? My code (which isnt working) foreach (Users users in userList) foreach (Cases cases in caseList) foreach (Offices userOffice in users.officeList) foreach (Offices caseOffice in cases.officeList) { if (userOffice.ID == caseOffice.ID) users.caseAdminIDList.Add(cases.adminID); }//end foreach //start my data classes class Users { public Users() { List<Offices> officeList = new List<Offices>(); List<int> caseAdminIDList = new List<int>(); ID = 0; }//end constructor public int ID { get; set; } public string name { get; set; } public int adminID { get; set; } public string ADuserName { get; set; } public bool alreadyInDB { get; set; } public bool alreadyInAdminDB { get; set; } public bool deleted { get; set; } public List<int> caseAdminIDList { get; set; } public List<Offices> officeList { get; set; } } class Offices { public int ID { get; set; } public string name { get; set; } } class Users { public Users() { List<Offices> officeList = new List<Offices>(); List<int> caseAdminIDList = new List<int>(); ID = 0; }//end constructor public int ID { get; set; } public string name { get; set; } public int adminID { get; set; } public string ADuserName { get; set; } public bool alreadyInDB { get; set; } public bool alreadyInAdminDB { get; set; } public bool deleted { get; set; } public List<int> caseAdminIDList { get; set; } public List<Offices> officeList { get; set; } }

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  • The difference between lists and sequences

    - by Peanut
    I'm trying to understand the difference between sequences and lists. In F# there is a clear distinction between the two. However in C# I have seen programmers refer to IEnumerable collections as a sequence. Is what makes IEnumerable a sequence the fact that it returns an object to iterate through the collection? Perhaps the real distinction is purely found in functional languages?

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  • Is there a simple way to make lists behave as files (with ftplib)

    - by Brent.Longborough
    I'd like to use ftplib to upload program-generated data as lists. The nearest method I can see for doing this is ftp.storlines, but this requires a file object with a readlines() method. Obviously I could create a file, but this seems like overkill as the data isn't persistent. Is there anything that could do this?: session = ftp.new(...) upload = convertListToFileObject(mylist) session.storlines("STOR SOMETHING",upload) session.quit

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  • All possible permutations of a set of lists in Python

    - by Ian Davis
    In Python I have a list of n lists, each with a variable number of elements. How can I create a single list containing all the possible permutations: For example [ [ a, b, c], [d], [e, f] ] I want [ [a, d, e] , [a, d, f], [b, d, e], [b, d, f], [c, d, e], [c, d, f] ] Note I don't know n in advance. I thought itertools.product would be the right approach but it requires me to know the number of arguments in advance

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  • .net databound lists

    - by d daly
    Hi, Is there any way around this? I have a few dropdown lists bound to lookup tables in sql server. some old records imported from a previos version of the system wont open due to data in these fields not matching the current dropdown data. Other than adding the old data to the lookup table (which I dont want to do) is there a way around this? Thanks DD

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  • What's the best way to read mailing lists in 2011?

    - by Avdi
    I used to use Emacs/GNUS for reading mailing lists, but that feels very 1990. Plus, it doesn't sync my scoring across PCs. GMail is wonderful, but it kind of sucks for mailing lists. The essential "mute" feature doesn't even work unless the mail is in the Inbox. I'd read my mailing lists on the Google Groups site, but not all of them are Google Groups. Basically, I'm looking for the "Google Reader" of mailing lists. Any suggestions?

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