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  • Normals per index?

    - by WarrenFaith
    I have a pyramid which has 5 vertex and 18 indices. As I want to add normals to each face I just found solution for normals for each vertex. That means I can't use indices to define my pyramid I need to have 18 vertex (and 3 times the same vertex for the same point in space). There must be a solution to use normals not on vertex base but on index base. Some code (javascript): var vertices = [ -half, -half, half, // 0 front left half, -half, half, // 1 front right half, -half, -half, // 2 back right -half, -half, -half, // 3 back left 0.0, Math.sqrt((size * size) - (2 * (half * half))) - half, 0.0 // 4 top ]; var vertexNormals = [ // front face normaleFront[0], normaleFront[1], normaleFront[2], normaleFront[0], normaleFront[1], normaleFront[2], normaleFront[0], normaleFront[1], normaleFront[2], // back face normaleBack[0], normaleBack[1], normaleBack[2], normaleBack[0], normaleBack[1], normaleBack[2], normaleBack[0], normaleBack[1], normaleBack[2], // left face normaleLeft[0], normaleLeft[1], normaleLeft[2], normaleLeft[0], normaleLeft[1], normaleLeft[2], normaleLeft[0], normaleLeft[1], normaleLeft[2], // right face normaleRight[0], normaleRight[1], normaleRight[2], normaleRight[0], normaleRight[1], normaleRight[2], normaleRight[0], normaleRight[1], normaleRight[2], // bottom face 0.0, -1.0, 0.0, 0.0, -1.0, 0.0, 0.0, -1.0, 0.0, 0.0, -1.0, 0.0, 0.0, -1.0, 0.0, 0.0, -1.0, 0.0, ]; var pyramidVertexIndices = [ 0, 1, 4, // Front face 2, 3, 4, // Back face 3, 0, 4, // Left face 1, 2, 4, // Right face 0, 1, 2, 2, 3, 0, // Bottom face ];

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  • Where to give feedback on a new Feature is SO ?

    - by justjoe
    After using SO, for sometimes, i realize i got some problems. zen masters fighting each other on one of my question. Every side have their own arguments and Everybody seem right. Frankly, this make me confuse : How can i choose somebody's answer where personally i don't know the right answer. So, i would like to propose a feature 'i choose this because' for a user who asked. So at least he/she explain why he choose the particular answer. Maybe it's silly, but as somebody who getting helps from other's answer, i would like to know everybody get what they deserve. Usually in this kind of situation, i just upvote every good answer and check the one i think the right one. Second feature : every hot question always got plenty answer and comment. And if among person who answer it, start to debate then it will become a little bit hectic. Right now a page only have ability to sort answer based on oldest, newest votest. So, is it possible to make a new sort based on timeline what make comment and answer collide. I believe it will be more easy to read. this feature can only see by the person who create the question, or also for public.

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  • Reading JSON with Javascript/jQuery

    - by Josephine
    I'm building a game in javascript/html5 and I'm trying to build a database of locked doors in a maze that can be loaded from and overwritten to throughout gameplay. I've found a large number of tutorials online, but nothing is working. I was wondering if someone could look at what I'm trying and let me know what I'm doing wrong. My JSON file looks like this: { "doors": [ {"left":true, "right":false, "bottom":false}, {"left":false, "right":false, "bottom":false}, {"right":false, "bottom":false, "top":false}, {"left":false, "right":false, "top":false} ] } I want to build the HTML page so that when a player collides with a door it checks if its locked or not like: if (player.x < leftDoor.x + leftDoor.width && player.x + player.width > leftDoor.x && player.y < leftDoor.y + leftDoor.height && player.y + player.height > leftDoor.y) { if(doors[0].left == true) alert("door is locked"); else window.location = ( "2.html?p1="); } However I'm having trouble reading from the JSON file itself. I've tried things like: function loadJson() { $(document).ready(function() { $.getJSON('info.json', function(doors) { alert(doors[0].left); }); }); } But nothing happens, and I need to be able to access the information in the HTML as well. I'd rather use jQuery, but I'm not opposed to straight JS if it works. I've been trying to do this for ages and I'm getting absolutely no where. If someone could help that would be amazing. Thanks!

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  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

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  • android opengl es texture mapping into polygons

    - by kamil
    I wrote opengl es code for android to map textures on a square but i want to draw texture on polygons. When user moved the image, texture will be mapped on polygons have more vertexes. I tried the arrays combination below for pentagon but i could not find the correct triangle combination in indices array. public float vertices[] = { // -1.0f, 1.0f, 0.0f, //Top Left // -1.0f, -1.0f, 0.0f, //Bottom Left // 1.0f, -1.0f, 0.0f, //Bottom Right // 1.0f, 1.0f, 0.0f //Top Right -1.0f, 1.0f, 0.0f, //Top Left -1.0f, -1.0f, 0.0f, //Bottom Left 1.0f, -1.0f, 0.0f, //Bottom Right 1.0f, 1.0f, 0.0f, //Top Right 0.4f, 1.4f, 0.0f }; /** Our texture pointer */ private int[] textures = new int[1]; /** The initial texture coordinates (u, v) */ private float texture[] = { //Mapping coordinates for the vertices // 1.0f, 0.0f, // 1.0f, 1.0f, // 0.0f, 1.0f, // 0.0f, 0.0f, // 0.0f, 1.0f, // 0.0f, 0.0f, // 1.0f, 0.0f, // 1.0f, 1.0f, 0.0f, 0.0f, 0.0f, 1.0f, 1.0f, 1.0f, 1.0f, 0.0f, 1.0f, 0.7f, }; /** The initial indices definition */ private byte indices[] = { //2 triangles // 0,1,2, 2,3,0, 0,1,2, 2,3,4, 3,4,0, //triangles for five vertexes }; i draw with the code below gl.glDrawElements(GL10.GL_TRIANGLES, indices.length, GL10.GL_UNSIGNED_BYTE, indexBuffer);

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  • How to Alphabetize a CSS file in Vim

    - by Kev
    I get a CSS file: div#header h1 { z-index: 101; color: #000; position: relative; line-height: 24px; margin-right: 48px; border-bottom: 1px solid #dedede; font-size: 18px; } div#header h2 { z-index: 101; color: #000; position: relative; line-height: 24px; margin-right: 48px; border-bottom: 1px solid #dedede; font-size: 18px; } I want to Alphabetize lines between the {...} div#header h1 { border-bottom: 1px solid #dedede; color: #000; font-size: 18px; line-height: 24px; margin-right: 48px; position: relative; z-index: 101; } div#header h2 { border-bottom: 1px solid #dedede; color: #000; font-size: 18px; line-height: 24px; margin-right: 48px; position: relative; z-index: 101; } I map F7 to do it nmap <F7> /{/+1<CR>vi{:sort<CR> But I need to press F7 over and over again to get the work done. If the CSS file is big, It's time-consuming & easily get bored. I want to get the cmds piped. So that, I only press F7 once! Any idea? thanks!

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  • OpenMP: Get total number of running threads

    - by Konrad Rudolph
    I need to know the total number of threads that my application has spawned via OpenMP. Unfortunately, the omp_get_num_threads() function does not work here since it only yields the number of threads in the current team. However, my code runs recursively (divide and conquer, basically) and I want to spawn new threads as long as there are still idle processors, but no more. Is there a way to get around the limitations of omp_get_num_threads and get the total number of running threads? If more detail is required, consider the following pseudo-code that models my workflow quite closely: function divide_and_conquer(Job job, int total_num_threads): if job.is_leaf(): # Recurrence base case. job.process() return left, right = job.divide() current_num_threads = omp_get_num_threads() if current_num_threads < total_num_threads: # (1) #pragma omp parallel num_threads(2) #pragma omp section divide_and_conquer(left, total_num_threads) #pragma omp section divide_and_conquer(right, total_num_threads) else: divide_and_conquer(left, total_num_threads) divide_and_conquer(right, total_num_threads) job = merge(left, right) If I call this code with a total_num_threads value of 4, the conditional annotated with (1) will always evaluate to true (because each thread team will contain at most two threads) and thus the code will always spawn two new threads, no matter how many threads are already running at a higher level. I am searching for a platform-independent way of determining the total number of threads that are currently running in my application.

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  • Center big image in smaller div

    - by larin555
    I'm trying to align images in the center of a slider div. I'm adjusting FlexSlider css by the way. Here's my CSS code : .flexslider {margin: 0; padding: 0; width: 600px; height:480px; overflow:hidden;margin-left:auto;margin-right:auto;} .flexslider .slides > li {display: none; -webkit-backface-visibility: hidden;} /* Hide the slides before the JS is loaded. Avoids image jumping */ .flexslider .slides img {width:auto;height:100%; display: inline-block; text-align:center;} Everything is working like I want, except that I want wider image to be centered in the div. Right now it is left-aligned. I cannot use background-image by the way. Any ideas? I also tried applying to the .flexslider .slides img : margin-left:-50%...not working margin-left:auto and margin-right:auto...not working left:50% and right:50%...not working either

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  • jQuery slideDown + CSS Floats

    - by danilo
    I'm using a HTML Table with several rows. Every second row - containing details about the preceding row - is hidden using CSS. When clicking the first row, the second row gets showed using jQuery show(). This is quite nice, but I would prefer the slideDown-Effect. The problem is, inside the details row, there are two floating DIVs, one floating on the left, and one on the right. Now if i slideDown the previously hidden row, the contained DIVs behave strange and "jump around". See this animated gif to understand what I mean: http://ich-wars-nicht.ch/tmp/lunapic_127365879362365_.gif The markup: <tr class="row-vm"> <td>...</td> ... </tr> <tr class="row-details"> <td colspan="8"> <div class="vmdetail-left"> ... </div> <div class="vmdetail-right"> ... </div> </td> </tr> The CSS: .table-vmlist tr.row-details { display: none; } div.vmdetail-left { float: left; width: 50%; } div.vmdetail-right { float: right; width: 50%; } And the jQuery code: if ($(this).next().css('display') == 'none') { // Show details //$(this).next().show(); $(this).next().slideDown(); } else { // Hide details //$(this).next().hide(); $(this).next().slideUp(); } Is there a way to fix this behavior, and to implement a nice slideDown-effect?

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  • call back function set by JS settimeout doesn't work in IE8....

    - by NAG
    <html <head <script function addEvent( obj, type, fn ) { if ( obj.attachEvent ) { obj['e'+type+fn] = fn; obj[type+fn] = function(){obj['e'+type+fn]( window.event );} obj.attachEvent( 'on'+type, obj[type+fn] ); } else obj.addEventListener( type, fn, false ); } </script </head <body <!-- HTML for example event goes here -- <div id="mydiv" style="border: 1px solid black; width: 100px; height: 100px; margin-top: 10px;"</div <script // Script for example event goes here addEvent(document.getElementById('mydiv'), 'contextmenu', function(event) { display_short('right-clicked (contextmenu)'); }); function display_short(str) { clearTimeout(); document.getElementById('mydiv').innerHTML = str; if (str != '') alert("hello"); setTimeout("display_short('abcd')", 1000); } </script </body </html Behaves diffrently in IE and FF when you right click on the div area. In ff display_short will be called for evry 1 sec eventhough you dont release right click but in IE it will not call display_short if you dont release right click. But i expect in IE it should call display_short for every 1 sec if you dont release also. Is there any solution for this?

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  • Passing Extras and screen rotation

    - by Luis A. Florit
    This kind of questions appear periodically. Sorry if this has been covered before, but I'm a newbie and couldn't find the appropriate answer. It deals with the correct implementation of communication between classes and activities. I made a gallery app. It has 3 main activities: the Main one, to search for filenames using a pattern; a Thumb one, that shows all the images that matched the pattern as thumbnails in a gridview, and a Photo activity, that opens a full sized image when you click a thumb in Thumbs. I pass to the Photo activity via an Intent the filenames (an array), and the position (an int) of the clicked thumb in the gridview. This third Photo activity has only one view on it: a TouchImageView, that I adapted for previous/next switching and zooming according to where you shortclick on the image (left, right or middle). Moreover, I added a longclick listener to Photo to show EXIF info. The thing is working, but I am not happy with the implementation... Some things are not right. One of the problems I am experiencing is that, if I click on the right of the image to see the next in the Photo activity, it switches fine (position++), but when rotating the device the original one at position appears. What is happening is that Photo is destroyed when rotating the image, and for some reason it restarts again, without obeying super.onCreate(savedInstanceState), loading again the Extras (the position only changed in Photo, not on the parent activities). I tried with startActivityForResult instead of startActivity, but failed... Of course I can do something contrived to save the position data, but there should be something "conceptual" that I am not understanding about how activities work, and I want to do this right. Can someone please explain me what I am doing wrong, which is the best method to implement what I want, and why? Thanks a lot!!!

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  • JSF myfaces dataTable , how to avoid NBSP; tags in the TDs

    - by Peter
    Hi, I have style applied to the TD elements of the dataTable of my myfaces application. td.financialReportTd { font-family: Arial; font-size: 12px; line-height: 12px; color:black; background-color: white; padding-right: 5px; text-align: right; border:0px black solid; height: 30px; padding-top:4px; padding-left:4px; vertical-align: top; direction: rtl; } Output: <td class="financialReportTd"> &nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;MY TEXT </td> No matter what I try, those NBSP tags fill up the TD and position of the text changes to the worse. I tried style text-align:right; (I need RTL text), I tried direction: rtl; Nothing helps. How can I align my text to the very right of the TD and avoid those space tags?

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  • The proper way to script periodically pulling a page from an https site

    - by DarthShader
    I want to create a command-line script for Cygwin/Bash that logs into a site, navigates to a specific page and compares it with the results of the last run. So far, I have it working with Lynx like so: ----snpipped, just setting variables---- echo "# Command logfile created by Lynx 2.8.5rel.5 (29 Oct 2005) ----snipped the recorded keystrokes------- key Right Arrow key p key Right Arrow key ^U" >> $tmp1 #p, right arrow initiate the page saving #"type" the filename inside the "where to save" dialog for i in $(seq 0 $((${#tmp2} - 1))) do echo "key ${tmp2:$i:1}" >> $tmp1 done #hit enter and quit echo "key ^J key y key q key y " >> $tmp1 lynx -accept_all_cookies -cmd_script=$tmp1 https://thewebpage.com/login diff $tmp2 $oldComp mv $tmp2 $oldComp It definitely does not feel "right": the cmd_script consists of relative user actions instead of specifying the exact link names and actions. So, if anything on the site ever changes, switches places, or a new link is added - I will have to re-create the actions. Also, I can't check for any errors so I can't abort the script if something goes wrong (login failed, etc) Another alternative I have been looking at is Mechanize with Ruby (as a note - I have 0 experience with Ruby). What would be the best way to improve or rewrite this?

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  • jQuery class selector oddness

    - by x3sphere
    I'm using jQuery to change the background image of a button depending on the class associated with it on hover. It only works if I put the hover statements in separate functions, however. Why is this? Here's the NON working code, always evaluates to the .submit hover statement, even when that class is removed via the keyup event. $(function() { { $('.submit-getinfo').hover(function () { $(this).css( {backgroundPosition: "right bottom"} ); }, function() { $(this).css( {backgroundPosition: "right top"} ); //$(this).removeClass('submithover'); }); $('.submit').hover(function () { $(this).css( {backgroundPosition: "left bottom"} ); }, function() { $(this).css( {backgroundPosition: "left top"} ); //$(this).removeClass('submithover'); }); }}); Working code: $(function() { { $('.submit').hover(function () { $(this).css( {backgroundPosition: "left bottom"} ); }, function() { $(this).css( {backgroundPosition: "left top"} ); //$(this).removeClass('submithover'); }); }}); $('#test').bind('keyup', function() { if (url == 'devel') { $("#submit").addClass("submit-getinfo").removeClass("submit"); $('.submit-getinfo').hover(function () { $(this).css( {backgroundPosition: "right bottom"} ); }, function() { $(this).css( {backgroundPosition: "right top"} ); //$(this).removeClass('submithover'); }); } } ); I just fail to see why I have to put the hover statements in separate functions, instead of sticking both in the main DOM.

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  • IE7 Debug Issue - Word Breaks in <li>

    - by JCHASE11
    Hello, I am having a very basic problem in IE7 that I cannot seem to fix. If you look at this page: http://vitaminjdesign.com/IAM/company/ you will notice that the vertical nav (ul id="leftcol") is displaying incorrectly in IE7. Each word appears on its own line. Here is my HTML /. CSS: <ul id="leftcol"> <li><a class="active" href="#">Company Overview</a></li> <li><a href="#">Why Choose Parker?</a></li> <li><a href="#">Testimonials</a></li> <li><a href="#">Financing Promotions</a></li> <li><a href="#">Licensing & Credentials</a></li> </ul> ul#leftcol{float:left; width:185px; position:relative; z-index:10;} ul#leftcol li{float:right; clear:right; margin-bottom:14px; list-style:none; list-style-image:none; text-align:right; line-height:1.3; } ul#leftcol li a{color:#505050; text-decoration:none; font-size:15px; float:right;} ul#leftcol li a.active,ul#leftcol li a:hover{color:#89b060;} Any ideas?

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  • C++: recursively computer all permutaions of digits 0 - 9

    - by Nate
    I have a homework assignment where part of the requirement is to recursively compute all the permutations of integers 0 - 9. The professor actually gave us the algorithm for this part of the question. I've finished the rest of the assignment, but I can't get the permute function working...I'm implementing it exactly like it was shown on the assignment information. However, when I run it each permutation is repeated multiple times (and I'm not sure if I'm even getting all the correct permutations.) I think he must've made a mistake on the assignment instructions. I've been working on this for a couple of hours and can't seem to figure out where I'm going wrong. Can anybody help point me in the right direction? Here's the current code: void permute(int v[], int curr) { for (int i = curr; i < MAX; i++) { swap(v[i], v[curr]); permute(v, curr + 1); swap(v[curr], v[i]); } } EDIT: Actually, right after posting this I realized it has to do with the swap, right? Because right now i and curr are the same, so I'm swapping identical numbers. Hm, should it be swap(v[i], v[curr+1])?

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  • Operator+ for a subtype of a template class.

    - by baol
    I have a template class that defines a subtype. I'm trying to define the binary operator+ as a template function, but the compiler cannot resolve the template version of the operator+. #include <iostream> template<typename other_type> struct c { c(other_type v) : cs(v) {} struct subtype { subtype(other_type v) : val(v) {} other_type val; } cs; }; template<typename other_type> typename c<other_type>::subtype operator+(const typename c<other_type>::subtype& left, const typename c<other_type>::subtype& right) { return typename c<other_type>::subtype(left.val + right.val); } // This one works // c<int>::subtype operator+(const c<int>::subtype& left, // const c<int>::subtype& right) // { return c<int>::subtype(left.val + right.val); } int main() { c<int> c1 = 1; c<int> c2 = 2; c<int>::subtype cs3 = c1.cs + c2.cs; std::cerr << cs3.val << std::endl; } I think the reason is because the compiler (g++4.3) cannot guess the template type so it's searching for operator+<int> instead of operator+. What's the reason for that? What elegant solution can you suggest?

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  • Trouble deciding how to add popup menu to eclipse plugin using either action ObjectContributions or command handlers

    - by user1808408
    The issue is this: Most things I read on the web says that we should avoid actions when creating popup menus because the command framework allows for more decoupling. Example: http://wiki.eclipse.org/FAQ_What_is_the_difference_between_a_command_and_an_action%3F Fair enough. But I am having a heck of a time getting the command framework to add my menu when I right click on a .java file inside the editor, and only when I click inside the editor. I can get the menu to show (using 'with' and the activeEditor variable), but it also shows when I right click on the java file inside the package explorer, which I don't want. I suspect it's because the file is already open inside the editor. I also have a menu that gets added when I right click on the java file inside the package explorer, using IComplilationUnit. That works fine. So my problem is solved using a popup menu action for when I click inside the file. I also get access to to all the ISelection stuff there. But the coupling is to high and I lose the flexability of using handlers. I'm looking for either: Tell me I'm doing it the only way possible; or Tell me how to have my popup appear only when I right click on the java file editor. Regards

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  • Python: Behavior of object in set operations

    - by Josh Arenberg
    I'm trying to create a custom object that behaves properly in set operations. I've generally got it working, but I want to make sure I fully understand the implications. In particular, I'm interested in the behavior when there is additional data in the object that is not included in the equal / hash methods. It seems that in the 'intersection' operation, it returns the set of objects that are being compared to, where the 'union' operations returns the set of objects that are being compared. To illustrate: class MyObject: def __init__(self,value,meta): self.value = value self.meta = meta def __eq__(self,other): if self.value == other.value: return True else: return False def __hash__(self): return hash(self.value) a = MyObject('1','left') b = MyObject('1','right') c = MyObject('2','left') d = MyObject('2','right') e = MyObject('3','left') print a == b # True print a == c # False for i in set([a,c,e]).intersection(set([b,d])): print "%s %s" % (i.value,i.meta) #returns: #1 right #2 right for i in set([a,c,e]).union(set([b,d])): print "%s %s" % (i.value,i.meta) #returns: #1 left #3 left #2 left Is this behavior documented somewhere and deterministic? If so, what is the governing principle?

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  • How to use a divider in a navigation with list elements?

    - by Kris
    I want to create a navigation which got divider between each list element. Here is a simple HTML/CSS Code/Template : <nav> <ul> <li><a href="#">A</a></li> <li><a href="#">B</a></li> <li><a href="#">C</a></li> <li><a href="#">D</a></li> <li><a href="#">E</a></li> </ul> </nav> nav ul { list-style:none; float:right; } nav ul li { float:left; padding-left:10px; } nav ul li a { color:#111; font-family:Verdana; font-size:15px; text-decoration:none; } nav ul li a:hover { color:#9F3039; } so just a simple looking navigation which floats from the right side on a logo which is not displayed in the code here. Now I want to at devider between each link - I know I could do it with border-right and just use another class on my last listelement which set the border-right off, BUT I want to use a special kind of divider - an image. How can I do it best ?

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  • Operator+ for a subtype of a template classe.

    - by baol
    I have a template class that defines a subtype. I'm trying to define the binary operator+ as a template function, but the compiler cannot resolve the template version of the operator+. #include <iostream> template<typename other_type> struct c { c(other_type v) : cs(v) {} struct subtype { subtype(other_type v) : val(v) {} other_type val; } cs; }; template<typename other_type> typename c<other_type>::subtype operator+(const typename c<other_type>::subtype& left, const typename c<other_type>::subtype& right) { return typename c<other_type>::subtype(left.val + right.val); } // This one works // c<a>::subtype operator+(const c<a>::subtype& left, // const c<a>::subtype& right) // { return c<a>::subtype(left.val + right.val); } int main() { c<int> c1 = 1; c<int> c2 = 2; c<int>::subtype cs3 = c1.cs + c2.cs; std::cerr << cs3.val << std::endl; } I think the reason is because the compiler (g++4.3) cannot guess the template type so it's searching for operator+<int> instead of operator+. What's the reason for that? What elegant solution can you suggest?

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  • Binary Search Tree, cannot do traversal

    - by ihm
    Please see BST codes below. It only outputs "5". what did I do wrong? #include <iostream> class bst { public: bst(const int& numb) : root(new node(numb)) {} void insert(const int& numb) { root->insert(new node(numb), root); } void inorder() { root->inorder(root); } private: class node { public: node(const int& numb) : left(NULL), right(NULL) { value = numb; } void insert(node* insertion, node* position) { if (position == NULL) position = insertion; else if (insertion->value > position->value) insert(insertion, position->right); else if (insertion->value < position->value) insert(insertion, position->left); } void inorder(node* tree) { if (tree == NULL) return; inorder(tree->left); std::cout << tree->value << std::endl; inorder(tree->right); } private: node* left; node* right; int value; }; node* root; }; int main() { bst tree(5); tree.insert(4); tree.insert(2); tree.insert(10); tree.insert(14); tree.inorder(); return 0; }

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  • Internet Explorer 6 and 7: floated elements expand to 100% width when they contain a child element f

    - by Paul D. Waite
    I've got a parent div floated left, with two child divs that I need to float right. The parent div should (if I understand the spec correctly) be as wide as needed to contain the child divs, and this is how it behaves in Firefox et al. In IE, the parent div expands to 100% width. This seems to be an issue with floated elements that have children floated right. Test page: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>Float test</title> </head> <body> <div style="border-top:solid 10px #0c0;float:left;"> <div style="border-top:solid 10px #00c;float:right;">Tester 1</div> <div style="border-top:solid 10px #c0c;float:right;">Tester 2</div> </div> </body> </html> Unfortunately I can't fix the width of the child divs, so I can't set a fixed width on the parent. Is there a CSS-only workaround to make the parent div as wide as the child divs?

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  • How To Start Your Own Professional Blog with WordPress

    - by Matthew Guay
    Would you like to start your own blog or website?  With a free WordPress  account, it’s free and easy to get started creating your own professional quality blog site. This is the first part in a series on how to create your own professional quality blog site. No, we’re not talking about some cheapo looking blog from Blogger or something on Facebook, but creating a quality blog you can be proud of and present to millions of readers online. WordPress is one of the most popular blogging platforms, powering hundreds of high-profile websites and blogs around the world.  It’s both powerful and easy to use, which makes it great whether you’re just starting out or are a blogging pro.  To start out with your blogging project WordPress is completely free, and you can use the online interface or install the WordPress software on your own server and blog from there. Getting Started You can start a blog in just a few minutes.  Head over to WordPress.com and click Sign up now on the right-hand side of the main page. Enter a username and password, check that you agree with the legal terms, select the “Gimme a blog” bullet, and click Next. WordPress may inform you that your username is already taken, simply choose a new one and try again. Next, choose a domain for your blog.  This will be the address for your site, and cannot be changed, so be sure to choose exactly what you want.  If you’d prefer your address to be yourname.com instead of yourname.wordpress.com, you can add your own domain for a fee after your blog is setup…but we’ll cover that later. Once you click signup, you will be sent a confirmation email.  While you wait for the email to arrive you can go ahead and enter in your name and a short bio about yourself. When you receive your confirmation email, click the link.  Congratulations; you now have your own blog! You can view your new blog immediately, though the default theme isn’t very interesting without your content and pictures. Back on the page you opened from the email, click Login to access your blog’s administration page and to start adding stuff to your blog.  You can also access your blog’s admin page anytime by from yourname.wordpress.com/admin, substituting your own blog name for yourname. Enter your username and password, then click Log in to get started. Adding Content to your WordPress.com Blog When you sign in to your WordPress blog, you’ll first see the WordPress Admin page.  Here you can see recent posts and comments, and you can see stats of how many people have visited your site.  You can also access all of your blog tools and settings right from this page. To add a new post to your blog, click the Posts link on the left, then click “Add New” either on the left menu or on the top of the Edit Posts page.  Or, if you want to edit the default first post, hover over it and select Edit. Or click the New Posts button on the top of the page.  This menu bar is always visible whenever you’re logged in, so it’s an easy way to add a post. The editor lets you easily write anything you want in a Microsoft Word-style editor.  You can format your text, add lists, links, quotes, and more.  When you’re ready to share your content with the world, click Publish on the right side. To add pictures or other files, click the picture icon beside “Upload/Insert”.  Your free blog account can store up to 3Gb of pictures and documents which will definitely give you a good start. Click Select Files, and then choose the pictures or documents you want to add to your post. When the pictures have uploaded, you can add a caption and choose how to position the picture.  When you’re finished, select “Insert into Post”.   Or, if you want to add a video, click the video button.  You have to add a paid upgrade to upload videos directly, but you can add YouTube and other online videos for free. Click the “From URL” tab, and then paste the link to the YouTube video and click Insert into post. If you’re a code geek, click the HTML tab in the editor and edit the HTML of your blog post the geeky way. Once you’ve added all your content and edited it the way you want, click the Publish button on the right of the editor.  Or, you can click Preview to make sure it looks right, and then click Publish. Here’s our blog with the new blog post containing a picture and video.  While you’re getting to know you’re way around the controls in WordPress, the Preview feature will be your best friend while you try to organize the content to your liking.   Conclusion It only takes a couple minutes to get started blogging at WordPress.com. Whether you want to write about your daily life, share pictures of your children, or review the latest books and gadgets, WordPress.com is a great place to get started for free.  But we’ve only covered a small portion of the WordPress features…but this should get you started. Check back for more WordPress and blogging coverage coming up soon! Links Signup for a free WordPress.com account Similar Articles Productive Geek Tips Add Social Bookmarking (Digg This!) Links to your Wordpress BlogHow-To Geek SoftwareProtecting Your WordPress Admin Panel From Hackers With .htaccessMake a Backup Copy of your Production Wordpress Blog on UbuntuLinux QuickTip: Downloading and Un-tarring in One Step TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Awe inspiring, inter-galactic theme (Win 7) Case Study – How to Optimize Popular Wordpress Sites Restore Hidden Updates in Windows 7 & Vista Iceland an Insurance Job? Find Downloads and Add-ins for Outlook Recycle !

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  • How to configure VPN in Windows XP

    - by SAMIR BHOGAYTA
    VPN Overview A VPN is a private network created over a public one. It’s done with encryption, this way, your data is encapsulated and secure in transit – this creates the ‘virtual’ tunnel. A VPN is a method of connecting to a private network by a public network like the Internet. An internet connection in a company is common. An Internet connection in a Home is common too. With both of these, you could create an encrypted tunnel between them and pass traffic, safely - securely. If you want to create a VPN connection you will have to use encryption to make sure that others cannot intercept the data in transit while traversing the Internet. Windows XP provides a certain level of security by using Point-to-Point Tunneling Protocol (PPTP) or Layer Two Tunneling Protocol (L2TP). They are both considered tunneling protocols – simply because they create that virtual tunnel just discussed, by applying encryption. Configure a VPN with XP If you want to configure a VPN connection from a Windows XP client computer you only need what comes with the Operating System itself, it's all built right in. To set up a connection to a VPN, do the following: 1. On the computer that is running Windows XP, confirm that the connection to the Internet is correctly configured. • You can try to browse the internet • Ping a known host on the Internet, like yahoo.com, something that isn’t blocking ICMP 2. Click Start, and then click Control Panel. 3. In Control Panel, double click Network Connections 4. Click Create a new connection in the Network Tasks task pad 5. In the Network Connection Wizard, click Next. 6. Click Connect to the network at my workplace, and then click Next. 7. Click Virtual Private Network connection, and then click Next. 8. If you are prompted, you need to select whether you will use a dialup connection or if you have a dedicated connection to the Internet either via Cable, DSL, T1, Satellite, etc. Click Next. 9. Type a host name, IP or any other description you would like to appear in the Network Connections area. You can change this later if you want. Click Next. 10. Type the host name or the Internet Protocol (IP) address of the computer that you want to connect to, and then click Next. 11. You may be asked if you want to use a Smart Card or not. 12. You are just about done, the rest of the screens just verify your connection, click Next. 13. Click to select the Add a shortcut to this connection to my desktop check box if you want one, if not, then leave it unchecked and click finish. 14. You are now done making your connection, but by default, it may try to connect. You can either try the connection now if you know its valid, if not, then just close it down for now. 15. In the Network Connections window, right-click the new connection and select properties. Let’s take a look at how you can customize this connection before it’s used. 16. The first tab you will see if the General Tab. This only covers the name of the connection, which you can also rename from the Network Connection dialog box by right clicking the connection and selecting to rename it. You can also configure a First connect, which means that Windows can connect the public network (like the Internet) before starting to attempt the ‘VPN’ connection. This is a perfect example as to when you would have configured the dialup connection; this would have been the first thing that you would have to do. It's simple, you have to be connected to the Internet first before you can encrypt and send data over it. This setting makes sure that this is a reality for you. 17. The next tab is the Options Tab. It is The Options tab has a lot you can configure in it. For one, you have the option to connect to a Windows Domain, if you select this check box (unchecked by default), then your VPN client will request Windows logon domain information while starting to work up the VPN connection. Also, you have options here for redialing. Redial attempts are configured here if you are using a dial up connection to get to the Internet. It is very handy to redial if the line is dropped as dropped lines are very common. 18. The next tab is the Security Tab. This is where you would configure basic security for the VPN client. This is where you would set any advanced IPSec configurations other security protocols as well as requiring encryption and credentials. 19. The next tab is the Networking Tab. This is where you can select what networking items are used by this VPN connection. 20. The Last tab is the Advanced Tab. This is where you can configure options for configuring a firewall, and/or sharing. Connecting to Corporate Now that you have your XP VPN client all set up and ready, the next step is to attempt a connection to the Remote Access or VPN server set up at the corporate office. To use the connection follow these simple steps. To open the client again, go back to the Network Connections dialog box. 1. One you are in the Network Connection dialog box, double-click, or right click and select ‘Connect’ from the menu – this will initiate the connection to the corporate office. 2. Type your user name and password, and then click Connect. Properties bring you back to what we just discussed in this article, all the global settings for the VPN client you are using. 3. To disconnect from a VPN connection, right-click the icon for the connection, and then click “Disconnect” Summary In this article we covered the basics of building a VPN connection using Windows XP. This is very handy when you have a VPN device but don’t have the ‘client’ that may come with it. If the VPN Server doesn’t use highly proprietary protocols, then you can use the XP client to connect with. In a future article I will get into the nuts and bolts of both IPSec and more detail on how to configure the advanced options in the Security tab of this client. 678: The remote computer did not respond. 930: The authentication server did not respond to authentication requests in a timely fashion. 800: Unable to establish the VPN connection. 623: The system could not find the phone book entry for this connection. 720: A connection to the remote computer could not be established. More on : http://www.windowsecurity.com/articles/Configure-VPN-Connection-Windows-XP.html

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