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  • how do I call create a name of a button variable in a code, with a number in it? (hard to explain)

    - by Sam Jarman
    Ive got a int, that is changed in a previous method, that now has to be part of the name of a button variable eg int numberFromLastOne; numberFromLastOne = 4; I then want to get 'button4' to do something. Could i use something like this? [[button@"%d", numberFromLastOne] doSomethign:withSomethignElse]; Ive never had to do something this before.... Any ideas would be appreciated :) Sam

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  • How do I determine the revision number of an Android build?

    - by hermo
    I know how to get the API level, android.os.Build.VERSION.SDK_INT, but there are also several revisions of each level release, e.g. for 2.1 there's rev 1 and 2. How do I determine the revision of a build? The reason i'd like to know this is that I have a workaround for a bug in Android 2.1 (and 2.2), and this workaround will break the moment the corresponding bug is fixed. So right now i'm in the odd position of hoping that the bug won't be fixed (at least not until I can find an answer to above question).

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  • Performance degrades for more than 2 threads on Xeon X5355

    - by zoolii
    Hi All, I am writing an application using boost threads and using boost barriers to synchronize the threads. I have two machines to test the application. Machine 1 is a core2 duo (T8300) cpu machine (windows XP professional - 4GB RAM) where I am getting following performance figures : Number of threads :1 , TPS :21 Number of threads :2 , TPS :35 (66 % improvement) further increase in number of threads decreases the TPS but that is understandable as the machine has only two cores. Machine 2 is a 2 quad core ( Xeon X5355) cpu machine (windows 2003 server with 4GB RAM) and has 8 effective cores. Number of threads :1 , TPS :21 Number of threads :2 , TPS :27 (28 % improvement) Number of threads :4 , TPS :25 Number of threads :8 , TPS :24 As you can see, performance is degrading after 2 threads (though it has 8 cores). If the program has some bottle neck , then for 2 thread also it should have degraded. Any idea? , Explanations ? , Does the OS has some role in performance ? - It seems like the Core2duo (2.4GHz) scales better than Xeon X5355 (2.66GHz) though it has better clock speed. Thank you -Zoolii

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  • PHP - not returning a count number for filled array...

    - by Phil Jackson
    Morning, this is eating me alive so Im hoping it's not something stupid, lol. $arrg = array(); if( str_word_count( $str ) > 1 ) { $input_arr = explode(' ', $str); die(print_r($input_arr)); $count = count($input_arr); die($count); above is part of a function. when i run i get; > Array ( > [0] => luke > [1] => snowden > [2] => create > [3] => develop > [4] => web > [5] => applications > [6] => sites > [7] => alse > [8] => dab > [9] => hand > [10] => design > [11] => love > [12] => helping > [13] => business > [14] => thrive > [15] => latest > [16] => industry > [17] => developer > [18] => act > [19] => designs > [20] => php > [21] => mysql > [22] => jquery > [23] => ajax > [24] => xhtml > [25] => css > [26] => de > [27] => montfont > [28] => award > [29] => advanced > [30] => programming > [31] => taught > [32] => development > [33] => years > [34] => experience > [35] => topic > [36] => fully > [37] => qualified > [38] => electrician > [39] => city > [40] => amp > [41] => guilds > [42] => level ) Which im expecting; run this however and nothing is returned!?!?! $arrg = array(); if( str_word_count( $str ) > 1 ) { $input_arr = explode(' ', $str); //die(print_r($input_arr)); $count = count($input_arr); die($count); can anyone see anything that my eyes cant?? regards, Phil

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  • The dictionary need to add every word in SpellingMistakes and the line number but it only adds the l

    - by Will Boomsight
    modules import sys import string Importing and reading the files form the Command Prompt Document = open(sys.argv[1],"r") Document = open('Wc.txt', 'r') Document = Document.read().lower() Dictionary = open(sys.argv[2],"r") Dictionary = open('Dict.txt', 'r') Dictionary = Dictionary.read() def Format(Infile): for ch in string.punctuation: Infile = Infile.replace(ch, "") for no in string.digits: Infile = Infile.replace(no, " ") Infile = Infile.lower() return(Infile) def Corrections(Infile, DictWords): Misspelled = set([]) Infile = Infile.split() DictWords = DictWords.splitlines() for word in Infile: if word not in DictWords: Misspelled.add(word) Misspelled = sorted(Misspelled) return (Misspelled) def Linecheck(Infile,ErrorWords): Infile = Infile.split() lineno = 0 Noset = list() for line in Infile: lineno += 1 line = line.split() for word in line: if word == ErrorWords: Noset.append(lineno) sorted(Noset) return(Noset) def addkey(error,linenum): Nodict = {} for line in linenum: Nodict.setdefault(error,[]).append(linenum) return Nodict FormatDoc = Format(Document) SpellingMistakes = Corrections(FormatDoc,Dictionary) alp = str(SpellingMistakes) for word in SpellingMistakes: nSet = str(Linecheck(FormatDoc,word)) nSet = nSet.split() linelist = addkey(word, nSet) print(linelist) # # for word in Nodict.keys(): # Nodict[word].append(line) Prints each incorrect word on a new line

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  • Is there any sence in performing binary AND with a number where all bits are set to 1

    - by n535
    Greetings everybody. I have seen examples of such operations for so many times that i began to think that i am getting something wrong with binary arithmetics. Is there any sense to perform the following: byte value = someAnotherByteValue & 0xFF; I don't really understand this, because it does not change anything anyway. Thanks for help. P.S. I was trying to search for information both elsewhere and here, but unsuccessfully.

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  • How to know which process hold a semnum with a specific number?

    - by Daniel
    For the following truss output, we can see the process post to 11 processes whose semnum is 49,32, ..etc, is there anyway to find out which process hold semnum 49, and which process holds setnum32, etc? /1: semop(67108928, 0xFFFFFFFF7FFF9F4C, 11) = 0 /1: semnum=49 semop=1 semflg=0 /1: semnum=32 semop=1 semflg=0 /1: semnum=52 semop=1 semflg=0 /1: semnum=41 semop=1 semflg=0 /1: semnum=40 semop=1 semflg=0 /1: semnum=55 semop=1 semflg=0 /1: semnum=46 semop=1 semflg=0 /1: semnum=35 semop=1 semflg=0 /1: semnum=37 semop=1 semflg=0 /1: semnum=48 semop=1 semflg=0 /1: semnum=39 semop=1 semflg=0

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  • Is there any sense in performing binary AND with a number where all bits are set to 1

    - by n535
    Greetings everybody. I have seen examples of such operations for so many times that I begin to think that I am getting something wrong with binary arithmetic. Is there any sense to perform the following: byte value = someAnotherByteValue & 0xFF; I don't really understand this, because it does not change anything anyway. Thanks for help. P.S. I was trying to search for information both elsewhere and here, but unsuccessfully. EDIT: Well, off course i assume that someAnotherByteValue is 8 bits long, the problem is that i don't get why so many people ( i mean professionals ) use such things in their code. For example in Jon Skeet's MiscUtil there is: uint s1 = (uint)(initial & 0xffff); where initial is int.

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  • How can you tell MYSQL to TRIM the X number of characters, beginning from the Back?

    - by Tim
    How do I write the following in MYSQL? SELECT SUBSTRING(value - (1 TRAILING CHARACTER)) FROM table; Basically substring(value, 2) trims the first letters. But I need to trim the last letters. I can't use substring(value, -4, 3) because I don't know the length of the value. Here's another example: SELECT * FROM table WHERE SUBSTRING(value - (4 TRAILING CHARACTER)) in (SELECT SUBSTRING(value - (1 TRAILING CHARACTER)) FROM table);

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  • usort - more parameters

    - by pgfonline
    Hallo, how can I pass more parameters to usort? I have different functions, which are very similar in structure, I want to have just one function: <?php $arr = array( array('number' => 100, 'string'=>'aaa'), array('number'=>50, 'string'=>'bdef'), array('number'=>150, 'string'=>'cbba') ); usort($arr, 'sortNumberDesc'); //How can I use just a single function? //How can I pass further parameters to usort? function sortNumberDesc($a, $b){ $a = $a['number']; $b = $b['number']; if ($a == $b) return 0; return ($a > $b) ? -1 : +1; } function sortNumberAsc($a, $b){ $a = $a['number']; $b = $b['number']; if ($a == $b) return 0; return ($a < $b) ? -1 : +1; } //I want to do the same with just one function: //Sort ID is the search index, reverse DESC or ASC function sort($a, $b, $sortId='number', $reverse = 0){ $a = $a[$sortId]; $b = $b[$sortId]; if ($a == $b) return 0; if($reverse == false) return ($a > $b) ? -1 : +1; else return ($a < $b) ? -1 : +1; } print_r($arr); ?>

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  • How to deploy a number of disparate project types?

    - by niteice
    This question is similar to http://stackoverflow.com/questions/1900269/whats-the-best-way-to-deploy-an-executable-process-on-a-web-server. The situation is this: I'm developing a product that needs to be deployed to a web server. It consists of 4 website projects, a background service, a couple of command-line tools, and two assemblies shared by all of these components. Now, I also happen to administer the server that this product will be deployed on. So I'm familiar with everything that may need to be done to perform an update: Copy website files Replace the service binary Install updated components in the GAC Configure IIS Update database schema After some research it seems that, to reduce deployment time and to be able to let the other sysadmins handle deployment, I want to deploy all of these as an MSI, except that I don't know a thing about installers. I know VS can generate web deployment projects, but where do I go from there? Being able to simply click Next a few times on an installer is my goal for deploying updates. It would also be nice to modularize it, so for example, I could distribute the four websites among multiple servers and have everything appear as individual components in the installer, and as one entity in Add/Remove Programs. Is all of this too much to ask in a single package?

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  • How do you print a limited number of characters?

    - by Mike Pateras
    Sorry to put a post up about something so simple, but I don't see what I'm doing wrong here. char data[1024]; DWORD numRead; ReadFile(handle, data, 1024, &numRead, NULL); if (numRead > 0) printf(data, "%.5s"); My intention with the above is to read data from a file, and then only print out 5 characters. However, it prints out all 1024 characters, which is contrary to what I'm reading here. The goal, of course, is to do something like: printf(data, "%.*s", numRead); What am I doing wrong here?

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  • WPF MVVM View with varying number of objects. How to?

    - by 0xDEAD BEEF
    HI! I want to design view which will contain multiple objects in different locations. For example - it would be great if viewmodel could have field like list of objects (rectangles) and when i change/add members to list, new rectangles appear on view in specified positions. How do i create such view/viewmodel?

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  • How do I select distinct rows where a column may have a number of the same values but all their 2nd

    - by Martin Rose
    I have a table in the form: test_name| test_result | test1 | pass | test2 | fail | test1 | pass | test1 | pass | test2 | pass | test1 | pass | test3 | pass | test3 | fail | test3 | pass | As you can see all test1's pass while test2's and test3's have both passes and fails. Is there a SQL statement that I can use to return the distinct names of the tests that only pass? E.g. test1

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  • Java threads, wait time always 00:00:00-Producer/Consumer

    - by user3742254
    I am currently doing a producer consumer problem with a number of threads and have had to set priorities and waits to them to ensure that one thread, the security thread, runs last. I have managed to do this and I have managed to get the buffer working. The last thing that I am required to do is to show the wait time of threads that are too large for the buffer and to calculate the average wait time. I have included code to do so, but everything I run the program, the wait time is always returned as 00:00:00, and by extension, the average is returned as the same. I was speaking to one of my colleagues who said that it is not a matter of the code but rather a matter of the computer needing to work off of one processor, which can be adjusted in the task manager settings. He has an HP like myself but his program prints the wait time 180 times, whereas mine prints usually about 3-7 times and is only 00:00:01 on one instance before finishing when I have made the processor adjustments. My other colleague has an iMac and hers puts out an average of 42:00:34(42 minutes??) I am very confused about this because I can see no difference between our codes and like my colleague said, I was wondering is it a computer issue. I am obviously concerned as I wanted to make sure that my code correctly calculated an average wait time, but that is impossible to tell when the wait times always show as 00:00:00. To calculate the thread duration, including the time it entered and exited the buffer was done by using a timestamp import, and then subtracting start time from end time. Is my code correct for this issue or is there something which is missing? I would be very grateful for any solutions. Below is my code: My buffer class package com.Com813cw; import java.text.DateFormat; import java.text.SimpleDateFormat; /** * Created by Rory on 10/08/2014. */ class Buffer { private int contents, count = 0, process = 200; private int totalRam = 1000; private boolean available = false; private long start, end, wait, request = 0; private DateFormat time = new SimpleDateFormat("ss:SSS"); public int avWaitTime =0; public void average(){ System.out.println("Average Application Request wait time: "+ time.format(request/count)); } public synchronized int get() { while (process <= 500) { try { wait(); } catch (InterruptedException e) { } } process -= 200; System.out.println("CPU After Process " + process); notifyAll(); return contents; } public synchronized void put(int value) { if (process <= 500) { process += value; } else { start = System.currentTimeMillis(); try { wait(); } catch (InterruptedException e) { } end = System.currentTimeMillis(); wait = end - start; count++; request += wait; System.out.println("Application Request Wait Time: " + time.format(wait)); process += value; contents = value; calcWait(wait, count); } notifyAll(); } public void calcWait(long wait, int count){ this.avWaitTime = (int) (wait/count); } public void printWait(){ System.out.println("Wait time is " + time.format(this.avWaitTime)); } } My spotify class package com.Com813cw; import java.sql.Timestamp; /** * Created by Rory on 11/08/2014. */ class Spotify extends Thread { private Buffer buffer; private int number; private int bytes = 250; public Spotify(Buffer c, int number) { buffer = c; this.number = number; } long startTime = System.currentTimeMillis(); public void run() { for (int i = 0; i < 20; i++) { buffer.put(bytes); System.out.println(getName() + this.number + " put: " + bytes + " bytes "); try { sleep(1000); } catch (InterruptedException e) { } } long endTime = System.currentTimeMillis(); long timeTaken = endTime - startTime; java.util.Date date = new java.util.Date(); System.out.println("-----------------------------"); System.out.println("Spotify has finished executing."); System.out.println("Time taken to execute was " + timeTaken + " milliseconds"); System.out.println("Time that Spotify thread exited Buffer was " + new Timestamp(date.getTime())); System.out.println("-----------------------------"); } } My BubbleWitch class package com.Com813cw; import java.lang.*; import java.lang.System; import java.sql.Timestamp; /** * Created by Rory on 10/08/2014. */ class BubbleWitch2 extends Thread { private Buffer buffer; private int number; private int bytes = 100; public BubbleWitch2(Buffer c, int number) { buffer = c; this.number=number ; } long startTime = System.currentTimeMillis(); public void run() { for (int i = 0; i < 10; i++) { buffer.put(bytes); System.out.println(getName() + this.number + " put: " + bytes + " bytes "); try { sleep(1000); } catch (InterruptedException e) { } } long endTime = System.currentTimeMillis(); long timeTaken = endTime - startTime; java.util.Date date = new java.util.Date(); System.out.println("-----------------------------"); System.out.println("BubbleWitch2 has finished executing."); System.out.println("Time taken to execute was " +timeTaken+ " milliseconds"); System.out.println("Time Bubblewitch2 thread exited Buffer was " + new Timestamp(date.getTime())); System.out.println("-----------------------------"); } } My Test class package com.Com813cw; /** * Created by Rory on 10/08/2014. */ public class ProducerConsumerTest { public static void main(String[] args) throws InterruptedException { Buffer c = new Buffer(); BubbleWitch2 p1 = new BubbleWitch2(c,1); Processor c1 = new Processor(c, 1); Spotify p2 = new Spotify(c, 2); SystemManagement p3 = new SystemManagement(c, 3); SecurityUpdate p4 = new SecurityUpdate(c, 4, p1, p2, p3); p1.setName("BubbleWitch2 "); p2.setName("Spotify "); p3.setName("System Management "); p4.setName("Security Update "); p1.setPriority(10); p2.setPriority(10); p3.setPriority(10); p4.setPriority(5); c1.start(); p1.start(); p2.start(); p3.start(); p4.start(); p2.join(); p3.join(); p4.join(); c.average(); System.exit(0); } } My security update package com.Com813cw; import java.lang.*; import java.lang.System; import java.sql.Timestamp; /** * Created by Rory on 11/08/2014. */ class SecurityUpdate extends Thread { private Buffer buffer; private int number; private int bytes = 150; private int process = 0; public SecurityUpdate(Buffer c, int number, BubbleWitch2 bubbleWitch2, Spotify spotify, SystemManagement systemManagement) throws InterruptedException { buffer = c; this.number = number; bubbleWitch2.join(); spotify.join(); systemManagement.join(); } long startTime = System.currentTimeMillis(); public void run() { for (int i = 0; i < 15; i++) { buffer.put(bytes); System.out.println(getName() + this.number + " put: " + bytes + " bytes"); try { sleep(1500); } catch (InterruptedException e) { } } long endTime = System.currentTimeMillis(); long timeTaken = endTime - startTime; java.util.Date date = new java.util.Date(); System.out.println("-----------------------------"); System.out.println("Security Update has finished executing."); System.out.println("Time taken to execute was " + timeTaken + " milliseconds"); System.out.println("Time that SecurityUpdate thread exited Buffer was " + new Timestamp(date.getTime())); System.out.println("------------------------------"); } } I'd be grateful as I said for any help as this is the last and most frustrating obstacle.

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