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  • pattern for the following condition in java

    - by zahir hussain
    hi i want to know how to write pattern.. for example : the word is "AboutGoogle AdWords Drive traffic and customers to your site. Pay through Cheque, Net Banking or Credit Card. Google Toolbar Add a search box to your browser. Google SMS To find out local information simply SMS to 54664. Gmail Free email with 7.2GB storage and less spam. Try Gmail today. Our ProductsHelp Help with Google Search, Services and ProductsGoogle Web Search Features Translation, I'm Feeling Lucky, CachedGoogle Services & Tools Toolbar, Google Web APIs, ButtonsGoogle Labs Ideas, Demos, ExperimentsFor Site OwnersAdvertising AdWords, AdSenseBusiness Solutions Google Search Appliance, Google Mini, WebSearchWebmaster Central One-stop shop for comprehensive info about how Google crawls and indexes websitesSubmit your content to Google Add your site, Google SitemapsOur CompanyPress Center News, Images, ZeitgeistJobs at Google Openings, Perks, CultureCorporate Info Company overview, Philosophy, Diversity, AddressesInvestor Relations Financial info, Corporate governanceMore GoogleContact Us FAQs, Feedback, NewsletterGoogle Logos Official Logos, Holiday Logos, Fan LogosGoogle Blog Insights to Google products and cultureGoogle Store Pens, Shirts, Lava lamps©2010 Google - Privacy Policy - Terms of Service" I have to search some word... for example "google insights" so how to write the code in java... i just write small code... check my code and answer my question... that code only use for find the search word, where is that. but i need to display some words front of search word and display some words rear of search workd... similar to google search... my code is Pattern p = Pattern.compile("(?i)(.*?)"+search+""); Matcher m = p.matcher(full); String title=""; while (m.find() == true) { title=m.group(1); System.out.println(title); } the full is orignal content, search s search word... thanks and advance

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  • Rails validates_format_of

    - by squids
    Hi, I want to use validates_format_of to validate a comma separated string with only letters (small and caps), and numbers. So. example1, example2, 22example44, ex24 not: ^&*, < , asfasfsdafas<#%$# Basically I want to have users enter comma separated words(incl numbers) without special characters. I'll use it to validate tags from acts_as_taggable_on. (i don't want to be a valid tag for example. Thanks in advance.

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  • dual map structure implementation?

    - by Danra
    Hey, I'm looking for a standard dual-map structure - is there one implemented in std/boost/another standard C++ library? When I say "dual-map" I mean a map which can be indexed efficiently both by the key and the "value" (it actually has two key types instead of one key type and one value type). for example: dualmap<int,string> m; m[1] = "foo"; m["bar"] = 2 int a = m["bar"]; // a = 2 Thanks, Dan

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  • regexp exclusion

    - by Vlad
    Hello everyone! I have regexp to change smileys to images. Here it is (?:(?![0]:\)|:\)\)|:-\)\)))(:\)|:-\)) The point is not to change 0:) and :)) and :-)) while changing :) and :-) It works pretty well with :)) and :-)) but somehow still grabs :) in 0:) Where's my mistake?

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  • Validating javascript decimal numbers

    - by Click Upvote
    I'm using the following regexp to validate numbers in my javascript file: var valid = (val.match(/^\d+$/)); It works fine for whole numbers like 100, 200, etc, however for things like 1.44, 4.11, etc, it returns false. How can I change it so numbers with a decimal are also accepted?

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  • multi-line pattern matching in pyhon

    - by Horace Ho
    A periodic computer generated message (simplified): Hello user123, - (604)7080900 - 152 - minutes Regards Using python, how can I extract "(604)7080900", "152", "minutes" (i.e. any text following a leading "- " pattern) between the two empty lines (empty line is the \n\n after "Hello user123" and the \n\n before "Regards"). Even better if the result string list are stored in an array. Thanks!

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  • Asterisk in eregi

    - by Mihai
    //URL START $urlregex = "^(https?|ftp)\:\/\/"; // USER AND PASS $urlregex .= "([a-z0-9+!*(),;?&=\$_.-]+(\:[a-z0-9+!*(),;?&=\$.-]+)?@)?"; // HOSTNAME OR IP $urlregex .= "[a-z0-9+\$-]+(.[a-z0-9+\$_-]+)*"; // PORT $urlregex .= "(\:[0-9]{2,5})?"; // PATH $urlregex .= "(\/([a-z0-9+\$_-].?)+)*\/?"; // GET Query $urlregex .= "(\?[a-z+&\$.-][a-z0-9;:@/&%=+\$.-]*)?"; // ANCHOR $urlregex .= "(#[a-z_.-][a-z0-9+\$_.-]*)?\$"; // check if (eregi($urlregex, $url)) {echo "good";} else {echo "bad";} but what if I have http://www.example.com/about-me/my-4*-hotel/ That eregi check isn't valid because of the asterisk. What should I do?

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  • Lighttpd rewriting files and directories

    - by Ronald
    I'm trying to do url rewriting with Lighttpd. I have what I need partially working. Right now I have this: http://domain.com/name/a/123 which rewrites to http://domain.com/name/a.php?pid=123 I do this with this rewrite-once rule: "^/name/a/([^/]+)"= "/name/a.php?pid=$1" That php page has external resources that are not getting rewritten such as the JavaScript and CSS files. Is there a way I can also have the rewrite do the following? http://domain.com/name/a/js/file.js = http://domain.com/name/js/file.js

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  • How can I remove HTML span tags with a Perl one liner?

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with Perl. I would prefer to allow for any occurences of whitespace or newlines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> EDIT: It's just the <span>'s and </span>'s that are inbetween <p> and <a> from the "blockDontForget" class </div> that I want to remove (there are lots or these blockDontForget divs with spans inside anchors that I want to keep).

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  • match at the beginning of any line, including the first

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)?

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  • How can I replace only the last occurence of an number in a string with php?

    - by Shawn
    How would you change this: a-10-b-19-c into something like this: a-10-b-20-c using regular expressions in PHP? The only solution I've found so far is: reverse the original string - "c-91-b-01-a" find the first number - "91" reverse it - "19" turn in into a number (parseInt) - 19 add 1 to it (+1) - 20 turn it into a string again (toString) - "20" reverse it again - "02" replace the original match with this new number - "c-02-b-01-a" reverse the string - "a-10-b-20-c" I was hoping someone on SO would have a simpler way to do this... Anyone?

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  • Regexp for selecting spaces between digits and decimal char

    - by Tirithen
    I want to remove spaces from strings where the space is preceeded by a digit or a "." and acceded by a digit or ".". I have strings like: "50 .10", "50 . 10", "50. 10" and I want them all to become "50.10" but with an unknown number of digits on either side. I'm trying with lookahead/lookbehind assertions like this: $row = str_replace("/(?<=[0-9]+$)\s*[.]\s*(?=[0-9]+$)/", "", $row); But it does not work...

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  • Basic Profanity Filter in Objective C for iPhone

    - by David van Dugteren
    How have you like minded individuals tackled the basic challenge of filtering profanity, obviously one can't possibly tackle every scenario but it would be nice to have one at the most basic level as a first line of defense. In Obj-c I've got NSString *tokens = [text componentsSeparatedByString:@" "]; And then I loop through each token to see if any of the keywords (I've got about 400 in a list) are found within each token. Realising False positives are also a problem, if the word is a perfect match, its flagged as profanity otherwise if more than 3 words with profanity are found without being perfect matches it is also flagged as profanity. Later on I will use a webservice that tackles the problem more precisely, but I really just need something basic. So if you wrote the word penis it would go yup naughty naughty, bad word written.

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  • PostgreSQL String search for partial patterns removing exrtaneous characters

    - by tbrandao
    Looking for a simple SQL (PostgreSQL) regular expression or similar solution (maybe soundex) that will allow a flexible search. So that dashes, spaces and such are omitted during the search. As part of the search and only the raw characters are searched in the table.: Currently using: SELECT * FROM Productions WHERE part_no ~* '%search_term%' If user types UTR-1 it fails to bring up UTR1 or UTR 1 stored in the database. But the matches do not happen when a part_no has a dash and the user omits this character (or vice versa) EXAMPLE search for part UTR-1 should find all matches below. UTR1 UTR --1 UTR 1 any suggestions...

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  • which regular expression will capture this sequence?

    - by John Smith
    The text follows this pattern <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) so basically the above line might repeat itself multiple times, and the idea is to retrieve the first 3 characters immediately after ABC. I have tried regular expressions along the lines of \<tr class="text" [.]+ABC(?<capture>[.]{3}) but they all fail. Can someone give me a hint?

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  • Javascript substrings multiline replace by RegExp

    - by Radek Šimko
    Hi, I'm having some troubles with matching a regular expression in multi-line string. <script> var str="Welcome to Google!\n"; str = str + "We are proud to announce that Microsoft has \n"; str = str + "one of the worst Web Developers sites in the world."; document.write(str.replace(/.*(microsoft).*/gmi, "$1")); </script> http://jsbin.com/osoli3/3/edit As you may see on the link above, the output of the code looks like this: Welcome to Google! Microsoft one of the worst Web Developers sites in the world. Which means, that the replace() method goes line by line and if there's no match in that line, it returns just the whole line... Even if it has the "m" (multiline) modifier...

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  • Remove unmatched HTML tags in a string

    - by Freeman
    Folks does anyone knows of a PHP function to remove unmatched HTML tags from a string. for example<div> This is a string <b> with an unmatched bold tag </div>. If there isnt one then help me buld one, maybe I can have a function that counts the number of opening tags and matching closing tags. If they are not even then remove the first opening tag or if closing tags are more, it removes the last tag?

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  • Multiple calls to preg_replace alters result

    - by Hurpe
    I have a bunch of files that were named in a somewhat standard format. The standard form is basically this: [integer]_word1_word2_word3_ ... _wordn where a word could really be anything, but all words are separated by an underscore. There is really only 3 things I want to do to the text: 1.) I want to modify the integer, which is always at the beginning, so that something like "200" would become $ 200.00. 2.) replace any "words" of the form "with", "With", "w/", or "W/" with "with". 3.) Replace all underscores with a space. I wrote three different preg_replace calls to do the trick. They are as follows: 1.) $filename = preg_replace("/(^[0-9]+)/","$ $1.00",$filename) 2.) $filename = preg_replace("/_([wW]|[wW]ith)_/"," with ",$filename) 3.) $filename = preg_replace("/_/"," ",$filename); Each replacement works as expected when run individually, but when all three are run, the 2nd replacement is ignored. Why would something like that occur? Thanks for the help!

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  • Jetty RewriteHandler and RewriteRegexRule

    - by Justin
    I'm trying to rewrite a URL for a servlet. The URL gets rewritten correctly, but the context doesn't match after that. Any idea how to get this to work? RewriteHandler rewriteHandler = new RewriteHandler(); rewriteHandler.setRewriteRequestURI(true); rewriteHandler.setRewritePathInfo(true); rewriteHandler.setOriginalPathAttribute("requestedPath"); RewriteRegexRule rewriteRegexRule = new RewriteRegexRule(); rewriteRegexRule.setRegex("/r/([^/]*).*"); rewriteRegexRule.setReplacement("/r?z=$1"); rewriteHandler.addRule(rewriteRegexRule); ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection(); Context servletContext = new Context(contextHandlerCollection, "/"); servletContext.addServlet(new ServletHolder(new RedirectServlet()), "/r"); So basically /r/asdf gets rewritten to /r?z=asdf. However, the rewritten /r?z=asdf is now not processed by the servlet. Also, /r?z=asdf does work if called directly.

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