Search Results

Search found 5493 results on 220 pages for 'boost regex'.

Page 118/220 | < Previous Page | 114 115 116 117 118 119 120 121 122 123 124 125  | Next Page >

  • Match groups in Python

    - by Curd
    Is there a way in Python to access match groups without explicitely creating a match object (or another way to beautify the example below)? Here is an example to clarify my motivation for the question: Following perl code if ($statement =~ /I love (\w+)/) { print "He loves $1\n"; } elsif ($statement =~ /Ich liebe (\w+)/) { print "Er liebt $1\n"; } elsif ($statement =~ /Je t\'aime (\w+)/) { print "Il aime $1\n"; } translated into Python m = re.match("I love (\w+)", statement) if m: print "He loves",m.group(1) else: m = re.match("Ich liebe (\w+)", statement) if m: print "Er liebt",m.group(1) else: m = re.match("Je t'aime (\w+)", statement) if m: print "Il aime",m.group(1) looks very awkward (if-else-cascade, match object creation).

    Read the article

  • sorting in python

    - by tipu
    I have a hashmap like so: results[tweet_id] = {"score" : float(dot(query,doc) / (norm(query) * norm(doc))), "tweet" : tweet} What I'd like to do is to sort results by the innser "score" key. I don't know how possible this is, I saw many sorting tutorials but they were for simple (not nested) data structures.

    Read the article

  • Remove unmatched HTML tags in a string

    - by Freeman
    Folks does anyone knows of a PHP function to remove unmatched HTML tags from a string. for example<div> This is a string <b> with an unmatched bold tag </div>. If there isnt one then help me buld one, maybe I can have a function that counts the number of opening tags and matching closing tags. If they are not even then remove the first opening tag or if closing tags are more, it removes the last tag?

    Read the article

  • Regular Expression for CSV with numbers

    - by Bernie Perez
    I'm looking for some regular expression to help parse my CSV file. The file has lines of number,number number,number Comment I want to skip number,number number,number Ex: 319,5446 564425,87 Text to skip 27,765564 I read each line into a string and I wanted to use some regular express to make sure the line matches the pattern of (number,number). If not then don't use the line.

    Read the article

  • How to with extract url from tweet using Regular Expressions

    - by neutreno
    Ok so i'm executing the following line of code in javascript RegExp('(http:\/\/t.co\/)[a-zA-Z0-9\-\.]{8}').exec(tcont); where tcont is equal to some string like 'Test tweet to http://t.co/GXmaUyNL' (the content of a tweet obtained by jquery). However it is returning, in the case above for example, 'http://t.co/GXmaUyNL,http://t.co/'. This is frustracting because I want the url without the bit on the end - after and including the comma. Any ideas why this is appearing? Thanks

    Read the article

  • Regular Expression - capturing contents of <select>

    - by joey mueller
    I'm trying to use a regular expression to capture the contents of all option values inside an HTML select element For example, in: <select name="test"> <option value="blah">one</option> <option value="mehh">two</option> <option value="rawr">three</option> </select> I'd like to capture one two and three into an array. My current code is var pages = responseDetails.responseText.match(/<select name="page" .+?>(?:\s*<option .+?>([^<]+)<\/option>)+\s*<\/select>/); for (var c = 0; c<pages.length; c++) { alert(pages[c]); } But it only captures the last value, in this case, "three". How can I modify this to capture all of them? Thanks!

    Read the article

  • regular expression for indian vehicle number in javascript and php

    - by I Like PHP
    i need regular expression in java script as well as in PHP for Indian vehicle NUMBER here are conditions list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

    Read the article

  • Regular expression to remove all text except...

    - by Barryman9000
    There may be an easier way, and if there is I'm all for it. However - my ASP.NET page has a TON of controls on it, and I've given them all ID's that start with underscore. I copied all the markup into Notepad++ and I'm trying to find a regular expression that will find everything but the controls and replace it with whitespace. that way I'll have a text file that has all my control names which I'll probably throw into Excel and do some string manipulation to add ".Text = " etc. Any suggestions?

    Read the article

  • Multiple calls to preg_replace alters result

    - by Hurpe
    I have a bunch of files that were named in a somewhat standard format. The standard form is basically this: [integer]_word1_word2_word3_ ... _wordn where a word could really be anything, but all words are separated by an underscore. There is really only 3 things I want to do to the text: 1.) I want to modify the integer, which is always at the beginning, so that something like "200" would become $ 200.00. 2.) replace any "words" of the form "with", "With", "w/", or "W/" with "with". 3.) Replace all underscores with a space. I wrote three different preg_replace calls to do the trick. They are as follows: 1.) $filename = preg_replace("/(^[0-9]+)/","$ $1.00",$filename) 2.) $filename = preg_replace("/_([wW]|[wW]ith)_/"," with ",$filename) 3.) $filename = preg_replace("/_/"," ",$filename); Each replacement works as expected when run individually, but when all three are run, the 2nd replacement is ignored. Why would something like that occur? Thanks for the help!

    Read the article

  • What's the fastest way to check if a word from one string is in another string?

    - by Mike Trpcic
    I have a string of words; let's call them bad: bad = "foo bar baz" I can keep this string as a whitespace separated string, or as a list: bad = bad.split(" "); If I have another string, like so: str = "This is my first foo string" What's the fasted way to check if any word from the bad string is within my comparison string, and what's the fastest way to remove said word if it's found? #Find if a word is there bad.split(" ").each do |word| found = str.include?(word) end #Remove the word bad.split(" ").each do |word| str.gsub!(/#{word}/, "") end

    Read the article

  • Python regular expressions assigning to named groups

    - by None
    When you use variables (is that the correct word?) in python regular expressions like this: "blah (?P\w+)" ("value" would be the variable), how could you make the variable's value be the text after "blah " to the end of the line or to a certain character not paying any attention to the actual content of the variable. For example, this is pseudo-code for what I want: >>> import re >>> p = re.compile("say (?P<value>continue_until_text_after_assignment_is_recognized) endsay") >>> m = p.match("say Hello hi yo endsay") >>> m.group('value') 'Hello hi yo' Note: The title is probably not understandable. That is because I didn't know how to say it. Sorry if I caused any confusion.

    Read the article

  • Regular Expressions in PHP

    - by kelly
    Sorry for unclear description, my English is not good. My problem is that I want to decode a string, and this string has nested content delimited by {}. For example: The string: {any string0{any string 00{any string 000....}}}{any string1}any string. The result I want to get: array[0] = {any string0{any string 00{any string 000....}}} array[1] = {any string1} I hope it's clear enough.

    Read the article

  • Regular expression only for website

    - by Katie
    HI, I'm new to Regular Expression. I need to find just website in some text and I'm looking for a regular expression able to find out strings like: www.my.home, http://my.site.it But this regular expression should not find strings like: [email protected] or if the website is already inside html tag <a href="http://www.my.site.com/"><span style="font-style: normal;">www.mambo-test.org</span></a> I tried with this one: \b((https?://[^ ])|(www.[^ ])) but it also finds the website in the href and between the tag: <a href="http://www.my.site.com/"><span style="font-style: normal;">www.mambo-test.org</span></a> and I don't know how except this case.

    Read the article

  • How to Practically Split Values from CSV File into MySQL Database

    - by Ryan
    Let's suppose I have the following line in a CSV file (I removed the header row in this example): "500,000",2,50,2,90000 I have a PHP script read the CSV file, break the file into individual lines, and store each line in an array called $linearray. Then, I use a foreach loop to look at each line individually. Within the foreach loop, I break the line into separate variables using the following function: $line = str_replace("'","\'",$line); From here, I insert the values into separate columns within a MySQL database. The script works. The values are inserted into a database, but I run into a problem. I want: "500,000" | 2 | 50 | 2 | 90000 But I get this: "500 | 000" | 2 | 50 | 2 | 90000 The script isn't smart enough to understand it should skip commas within quotation marks. Do you know how I can alter my script to make sure I get the output I'm looking for? Thanks.

    Read the article

  • how to search some character inside string

    - by klox
    i have been type some string inside textfield that is "KD-G435MUN2D"... i already use this code for search "UD" character from that string: <script> var str="KD-R435MUN2D"; var patt1=/UD/gi; document.write(str.match(patt1)); </script> but this code doesn't work..where is my fault?

    Read the article

  • Strange JavaScript Regular Expression Behavior

    - by Kiwi
    I'm getting different behavior from a regular expression in JavaScript depending on whether or not I declare it using literal syntax. Using a extremely simple test HTML file: <html> <head> <script type="text/javascript"> var s = '3'; var regex1 = /\d/; var regex2 = new RegExp('\d'); alert(s.search(regex1)); // 0 (matches) alert(s.search(regex2)); // -1 (does not match) </script> </head> <body></body> </html> The regular expression declared with literal syntax (/\d/) works correctly, while the other (new RegExp('\d')) does not. Why on earth is this happening? I'm using Google Chrome 5.0.375.70 on Windows Vista Home Premium, if that's at all helpful.

    Read the article

  • How to get a Clean String in Javascript?

    - by streetparade
    i have a long String. With some German characters and lots of new lines tabs ect.. In a Selectbox user can select a text, on change i do document.getElementById('text').value=this.value; But this fails. I just get a "unterminated string literal" as error in JavaScript. I think i should clean the string. How can i do it in JavaScript?

    Read the article

  • Is the JavaScript RegExp implicit method deprecated?

    - by Eric
    So everyone knows what I mean by "implicit methods"? They're like those default properties from the Windows COM days of yore, where you could type something like val = obj(arguments) and it would be interpreted as val = obj.defaultMethod(arguments) I just found out JavaScript has the same thing: the default method of a RegExp object appears to be 'exec', as in /(\w{4})/('yip jump man')[1] ==> jump This even works when the RegExp object is assigned to a variable, and even when it's created with the RegExp constructor, instead of /.../, which is good news to us fans of referential transparency. Where is this documented, and/or is it deprecated?

    Read the article

  • How to get everything in the string, but a particular pattern

    - by José Leal
    Yet another regexp question: I have a string as the following, "This is a string, and I have a priority !1" So I want to build a regexp that extracts my priority, which is this number 1 preceded by the "!". To extract it is very easy, "!([1-4])". But now I want to extract the text, leaving it out! How can I do that? DETAIL: The !1 can be anywhere in the string, so this is also perfectly fine: "This is a string, !1 and I have a priority" Thanks! UPDATE: I'm using scala

    Read the article

< Previous Page | 114 115 116 117 118 119 120 121 122 123 124 125  | Next Page >