Search Results

Search found 5493 results on 220 pages for 'boost regex'.

Page 120/220 | < Previous Page | 116 117 118 119 120 121 122 123 124 125 126 127  | Next Page >

  • Simplest way to convert all html links in a string using PHP

    - by Gaz
    I am trying to convert a block of text that contains html text - i'd like to find all http links and convert them for link tracking purposes. So eg anything like this in a string would be converted to the latter <a href="http://www.google.com">Some Link</a> <a href="http://www.mysite.com/tracking.php?url=www.google.com">Some Link</a> Can anyone how to do this taking into account the original string will consists of all sorts of html, images etc..

    Read the article

  • What is the MM/DD/YYYY regular expression and how do I use it in php?

    - by zeckdude
    I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

    Read the article

  • Filter string in C

    - by Paul Tarjan
    How can I filter a string in c? I want to remove anything that isn't [a-z0-9_]. int main(int argc, char ** argv) { char* name = argv[1]; // remove anything that isn't [a-z0-9_] printf("%s", name); }

    Read the article

  • Limiting input to specified regexp with uppercase chars in IE

    - by pixelboy
    I'm trying to limit what our users will be able to type in inputs, using javascript/jquery. Problem is, I have to limit this to Uppercase chars only, and numbers. Here's what I coded previously : $(input).keydown(function(e){ if ($(input).attr("class")=="populationReference"){ var ValidPattern = /^[A-Z_0-9]*$/; var char = String.fromCharCode(e.charCode); if (!ValidPattern.test(char) && e.charCode!=0){ return false; e.preventDefault(); } } }); If Firefox supports charCode, IE doesn't. How then, could I test if the user is typing uppercase or lowercase characters ? Thanks for any help !

    Read the article

  • Is it possible to use re2 from Python?

    - by flow
    i just discovered http://code.google.com/p/re2, a promising library that uses a long-neglected way (Thompson NFA) to implement a regular expression engine that can be orders of magnitudes faster than the available engines of awk, Perl, or Python. so i downloaded the code and did the usual sudo make install thing. however, that action had seemingly done little more than adding /usr/local/include/re2/re2.h to my system. there seemed to be some `*.a file in addition, but then what is it with this *.a extension? i would like to use re2 from Python (preferrably Python 3.1) and was excited to see files like make_unicode_groups.py in the distro (maybe just used during the build process?). those however were not deployed on my machine. how can i use re2 from Python?

    Read the article

  • Ruby: backslash all non-alphanumeric characters in a string

    - by HBlend
    I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

    Read the article

  • get city, state or zip from a string in python

    - by Joe
    I'd like to be able to parse out the city, state or zip from a string in python. So, if I entered Boulder, Co 80303 Boulder, Colorado Boulder, Co 80303 ... any variation of these it would return the city, state or zip. This is all going to be user inputted data and inputted in one text field.

    Read the article

  • Regular expressions and matching URLs with metacharacters

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions? Edit: The original intent was to match all URLs that could be found after the first semi colon.

    Read the article

  • Match subpatterns in any order

    - by Yaroslav
    I have long regexp with two complicated subpatters inside. How i can match that subpatterns in any order? Simplified example: /(apple)?\s?(banana)?\s?(orange)?\s?(kiwi)?/ and i want to match both of apple banana orange kiwi apple orange banana kiwi It is very simplified example. In my case banana and orange is long complicated subpatterns and i don't want to do something like /(apple)?\s?((banana)?\s?(orange)?|(orange)?\s?(banana)?)\s?(kiwi)?/ Is it possible to group subpatterns like chars in character class? UPD Real data as requested: 14:24 26,37 Mb 108.53 01:19:02 06.07 24.39 19:39 46:00 my strings much longer, but it is significant part. Here you can see two lines what i need to match. First has two values: length (14 min 24 sec) and size 26.37 Mb. Second one has three values but in different order: size 108.53 Mb, length 01 h 19 m 02 s and date June, 07 Third one has two size and length Fourth has only length There are couple more variations and i need to parse all values. I have a regexp that pretty close except i can't figure out how to match patterns in different order without writing it twice. (?<size>\d{1,3}\[.,]\d{1,2}\s+(?:Mb)?)?\s? (?<length>(?:(?:01:)?\d{1,2}:\d{2}))?\s* (?<date>\d{2}\.\d{2}))? NOTE: that is only part of big regexp that forks fine already.

    Read the article

  • questions on nfa and dfa..

    - by Loop
    Hi Guys... Hope you help me with this one.... I have a main question which is ''how to judge whether a regular expression will be accepted by NFA and/or DFA? For eg. My question says that which of the regular expressions are equivalent? explain... 1.(a+b)*b(a+b)*b(a+b)* 2.a*ba*ba* 3.a*ba*b(a+b)* do we have to draw the NFA and DFA and then find through minimisation algorithm? if we do then how do we come to know that which regular expression is accepted by NFA/DFA so that we can begin with the answer? its so confusing.... Second is a very similar one, the question asks me to show that the language (a^nb^n|n1} is not accepted by DFA...grrrrr...how do i know this? (BTW this is a set of all strings of where a number of a's is followed by the same number of b's).... I hope I explained clearly well....

    Read the article

  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

    Read the article

  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

    Read the article

  • Replacing multiple patterns in a block of data

    - by VikrantY
    Hi All, I need to find the most efficient way of matching multiple regular expressions on a single block of text. To give an example of what I need, consider a block of text: "Hello World what a beautiful day" I want to replace Hello with "Bye" and "World" with Universe. I can always do this in a loop ofcourse, using something like String.replace functions availiable in various languages. However, I could have a huge block of text with multiple string patterns, that I need to match and replace. I was wondering if I can use Regular Expressions to do this efficiently or do I have to use a Parser like LALR. I need to do this in JavaScript, so if anyone knows tools that can get it done, it would be appreciated.

    Read the article

  • How to parse phpDoc style comment block with php?

    - by Reveller
    Please consider the following code with which I'm trying to parse only the first phpDoc style comment (noy using any other libraries) in a file (file contents put in $data variable for testing purposes): $data = " /** * @file A lot of info about this file * Could even continue on the next line * @author [email protected] * @version 2010-05-01 * @todo do stuff... */ /** * Comment bij functie bar() * @param Array met dingen */ function bar($baz) { echo $baz; } "; $data = trim(preg_replace('/\r?\n *\* */', ' ', $data)); preg_match_all('/@([a-z]+)\s+(.*?)\s*(?=$|@[a-z]+\s)/s', $data, $matches); $info = array_combine($matches[1], $matches[2]); print_r($info) This almose works, except for the fact that everything after @todo (including the bar() comment block and code) is considered the value of @todo: Array ( [file] => A lot of info about this file Could even continue on the next line [author] => [email protected] [version] => 2010-05-01 [todo] => do stuff... / /** Comment bij functie bar() [param] => Array met dingen / function bar() { echo ; } ) How does my code need to be altered so that only the first comment block is being parsed (in other words: parsing should stop after the first "*/" encountered?

    Read the article

  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

    Read the article

  • Python comparing string against several regular expressions

    - by maerics
    I'm pretty experienced with Perl and Ruby but new to Python so I'm hoping someone can show me the Pythonic way to accomplish the following task. I want to compare several lines against multiple regular expressions and retrieve the matching group. In Ruby it would be something like this: STDIN.each_line do |line| case line when /^A:(.*?)$/ then puts "FOO: #{$1}" when /^B:(.*?)$/ then puts "BAR: #{$1}" # when ... else puts "NO MATCH: #{line}" end end My attempts in Python are turning out pretty ugly because the matching group is returned from a call to match/search on a regular expression and Python has no assignment in conditionals or switch statements. What's the Pythonic way to do (or think!) about this problem?

    Read the article

  • Regular expression for dividing country calling codes

    - by RickiG
    Hi I have a list of calling codes for all countries(the phone number prefixes), I would like to split them up in the country name and the actual code so I can put then into an xml. I have tried back and forth but can not get a regexp going that takes all cases into account. I think it is fairly simple for someone with a bit of experience. The codes have these formats: Afghanistan 93 Anguilla 1 264 Antarctica 6721 Antigua and Barbuda 1 268 Bosnia and Herzegovina 387 Canada 1 Congo, Republic of the 242 Cote d'Ivoire 225 Ireland (Eire) 353 United States of America 1 There are around 235 of them in total, but these are the regulars and the exceptions. ^[a-zA-Z]\s,'()] for between 1 and X words and then it is [0-9\s]{1,5}$ for the numbers: X XX XXX XXXX X XXX So if I should express it as a sentence it would be: "from beginning of a line, take all characters (1) including space,'() until you encounter digits, then take all of these including space(2) until you encounter a line break." I am using TextMate, and the docs says: TextMate uses the Oniguruma regular expression library by K. Kosako. I would appreciate any help given:) Thank you.

    Read the article

  • Extracting a string between specified characters in python

    - by Seth
    I'm a newbie to regular expressions and I have the following string: sequence = ["{\"First\":\"Belyuen,NT,0801\",\"Second\":\"Belyuen,NT,0801\"}","{\"First\":\"Larrakeyah,NT,0801\",\"Second\":\"Larrakeyah,NT,0801\"}"] I am trying to extract the text Belyuen,NT,0801 and Larrakeyah,NT,0801 in python. I have the following code which is not working: re.search('\:\\"...\\', ''.join(sequence)) I.e. I want to get the string between characters :\ and \.

    Read the article

  • How to validate hostname in perl?

    - by embedded
    Hi, I need to come up with a regular expression to validate hostname against RFC-1123 and RFC-952. Right now I'm using this: ^(?=.{1,255}$)[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?(?:\.[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?)*\.?$/ but this does not do the trick since it does not catch a. as invalid hostname. How do I enhance the reg expression to comply with those RFCs? Thanks

    Read the article

< Previous Page | 116 117 118 119 120 121 122 123 124 125 126 127  | Next Page >