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  • .NET regular expression

    - by vert
    How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following: a-z A-Z Æ æ Å å Ø ø - '

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  • using sed to replace whole word containing '='?

    - by rashid
    EDIT i have something like this in a file: imagecolor=0 arrayimagecolorcopy=0 arrayimagecolorcopy3d=0 when i use sed -i -e 's/imagecolor=0/imagecolor=1/' it will change 1 and 2 line. But i only want it to replace first line. i also tried sed with \< \ and \b \b, but no luck. Could it be the '=' sign? Do we have something like -w as in grep command? Thank you.

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  • which regular expressions do you use the most?

    - by markcial
    I'm starting to learn reg exp and i'm just curious to reg exp used by the rest of the people so i can have a thread to look at and learn from. I had started with the eight listed here, i tried to play a little big with firebug and some tutorials and used some in my websites, but i'd like to know some from more experienced people. Thanks!

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  • Get all text between tags with preg_match_all() or better function?

    - by kylex
    2010-June-11 <remove>2010-June-2</remove> <remove>2010-June-3</remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-3 2010-June-2 2010-June-1 I'm trying to find all instances that are between the <remove> tags This is what I have: $pattern = "/<remove>(.*?)<\/remove>/"; preg_match_all($pattern, $_POST['exclude'], $matches); foreach($matches as $deselect){ foreach ($deselect as $display){ echo $display."<br />"; } } This is what it returns: 2010-June-2 2010-June-3 2010-June-2 2010-June-3 Why is it doubling up, and how do I prevent that?

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  • Does '[ab]+' equal '(a|b)+' in python re module?

    - by user1477871
    I think pat1 = '[ab]' and pat2 = 'a|b' have the same function in Python(python2.7, windows) 're' module as a regular expression pattern. But I am confused with '[ab]+' and '(a|b)+', do they have the same function, if not plz explain details. ''' Created on 2012-9-4 @author: melo ''' import re pat1 = '(a|b)+' pat2 = '[ab]+' text = '22ababbbaa33aaa44b55bb66abaa77babab88' m1 = re.search(pat1, text) m2 = re.search(pat2, text) print 'search with pat1:', m1.group() print 'search with pat2:', m2.group() m11 = re.split(pat1, text) m22 = re.split(pat2, text) print 'split with pat1:', m11 print 'split with pat2:', m22 m111 = re.findall(pat1, text) m222 = re.findall(pat2, text) print 'findall with pat1:', m111 print 'findall with pat2:', m222 output as below: search with pat1: ababbbaa search with pat2: ababbbaa split with pat1: ['22', 'a', '33', 'a', '44', 'b', '55', 'b', '66', 'a', '77', 'b', '88'] split with pat2: ['22', '33', '44', '55', '66', '77', '88'] findall with pat1: ['a', 'a', 'b', 'b', 'a', 'b'] findall with pat2: ['ababbbaa', 'aaa', 'b', 'bb', 'abaa', 'babab'] why are 'pat1' and 'pat2' different and what's their difference? what kind of strings can 'pat1' actually match?

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  • Words doesn't starts with numbers

    - by pocoa
    I have a string "one two 9three 52eight four", so I only want to get "one two four", because "three" starts with "9" and "eight" starts with "52". I tried: "(?!\d)\w+" but it's still taking the "three" and "eight". I don't want it.

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  • MySQL: searh by host name in field containing urls

    - by Silver Light
    Hello! I have this database table: id | url ----------------------------------------- 1 | http://stackoverflow.com/ 2 | http://www.google.com 3 | http://example.com/somepage 4 | https://another.net?id=88 5 | http://hello.org/index.php?hello=2 6 | http://google.com?q=hello+world I need to search all fields, where URL belongs to a certain host. For example, if I give the query 'google.com', it will return rows 2 and 6 (www is ignored). I get the host using PHP parse_url() function. How this SQL query would look like?

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  • Replacing multiple `-` with one `-` without regexp

    - by Adam Kiss
    I've seen so many misuses of RegExp, I don't really like it :) I have string (as a result of two str_replaces) that might look something like this: .?This iš my ".stRiNg."! | V --this-is-my---string--- Is there any way better than $string = trim(preg_replace('/[-]+/u','-', $string),'-'); to get: this-is-my-string ?

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  • Getting all matches for a regexp on clojure

    - by Deleteman
    I'm trying to parse an HTML file and get all href's inside it. So far, the code I'm using is: (map #(println (str "Match: " %)) (re-find #"(?sm)href=\"([a-zA-Z.:/]+)\"" str_response)) str_response being the string with the HTML code inside it. According to my basic understanding of Clojure, that code should print a list of matches, but so far, no luck. It doens't crash, but it doens't match anything either. I've tried using re-seq instead of re-find, but with no luck. Any help? Thanks!

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  • Can anyone decipher this for me? PHP (I think)

    - by Josh
    This code is being used to parse email, it's stored as a table in a mySQL database. I believe it's PHP code. What does the (.+) do? /A new order has been successfully placed through(.+)Name:(.+)Company:(.+)Email:(.+)Address 1(.+)Order ID:(.+)Date:(.+)Payment Type:(.+)Order Status:(\s*)Accepted(.*)\n(.+)\$([\d\.]+)\s+X/si Thanks, super-brainiacs!

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  • Parsing in groovy between two tags ?

    - by fabien-barbier
    I would like to parse this Gstring with groovy : Format type : CodeClass, Name, Accession, Count. def txt = """ <Lane_Attributes> ID,1 FovCount,600 FovCounted,598 ... </Lane_Attributes> """ And get a map like : Map = [ID:1, FovCount:600, FovCounted:598] How can I : - extract text between tag and ?, - and convert to a map ?

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  • partial string matching - R

    - by DonDyck
    I need to write a query in R to match partial string in column names. I am looking for something similar to LIKE operator in SQL. For e.g, if I know beginning, middle or end part of the string I would write the query in format: LIKE 'beginning%middle%' in SQL and it would return matching strings. In pmatch or grep it seems I can only specify 'beginning' , 'end' and not the order. Is there any similar function in R that I am looking for? For example, say I am looking in the vector: y<- c("I am looking for a dog", "looking for a new dog", "a dog", "I am just looking") Lets say I want to write a query which picks "looking for a new dog" and I know start of the string is "looking" and end of string is "dog". If I do a grep("dog",y) it will return 1,2,3. Is there any way I can specify beginning and end in grep?

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  • sed: group capturing

    - by Michael
    Is there any way to tell sed to output only captured groups? for example given by input: This is a sample 123 text and some 987 numbers and pattern /([\d]+)/ I could get only 123 and 987 output in the way formatted by back references perhaps?

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  • How can I get the file extensions from relative links in HTML text using Perl?

    - by Structure
    For example, scanning the contents of an HTML page with a Perl regular expression, I want to match all file extensions but not TLD's in domain names. To do this I am making the assumption that all file extensions must be within double quotes. I came up with the following, and it is working, however, I am failing to figure out a way to exclude the TLDs in the domains. This will return "com", "net", etc. m/"[^<>]+\.([0-9A-Za-z]*)"/g Is it possible to negate the match if there is more than one period between the quotes that are separated by text? (ie: match foo.bar.com but not ./ or ../) Edit I am using $1 to return the value within parentheses.

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  • What does the $1$2$4 mean in this preg_replace?

    - by Taylor
    Got this function for ammending the query string and was wondering what the replacement part of the pre_replace meant (ie- $1$2$4). function add_querystring_var($url, $key, $value) { $url = preg_replace('/(.*)(\?|&)' . $key . '=[^&]+?(&)(.*)/i', '$1$2$4', $url . '&'); $url = substr($url, 0, -1); if (strpos($url, '?') === false) { return ($url . '?' . $key . '=' . $value); } else { return ($url . '&' . $key . '=' . $value); } } Not too familiar with regular expression stuff. I get the various parts to preg_replace but not 100% about the use of '$1$2$4' in the replacement part.

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  • Regular expression - stop at first match

    - by publicRavi
    My pattern looks something like <xxxx location="file path/level1/level2" xxxx some="xxx"> I am only interested in the part in quotes assigned to location. Shouldn't it be as easy as below without the greedy switch? Does not seem to work :( /.*location="(.*)".*/

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