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  • PHP: Return string between two characters

    - by Nic Hubbard
    I am wanting to use "keywords" within a large string. These keywords start and end using *my_keyword* and are user defined. How, within a large string, can I search and find what is between the two * characters and return each instance? The reason it might change it, that parts of the keywords can be user defined, such as *page_date_Y* which might show the year in which the page was created. So, again, I just need to do a search and return what is between those * characters. Is this possible, or is there a better way of doing this if I don't know the "keyword" length or what i might be?

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  • not autolinking all-numeric twitter hashtags in perl?

    - by all_numeric_no_hash
    I'm producing HTML from twitter search results. Happily using the Net::Twitter module :-) One of the rules in Twitter is that all-numeric hashtags are not links. This allows to unambiguously tweet things like "ur not my #1 anymore", as in here: http://twitter.com/natarias2007/status/11246320622 The solution I came up with looks like: $tweet =~ s{#([0-9]*[A-Za-z_]+[0-9]*)}{<a href="http://twitter.com/search?q=%23$1">#$1</a>}g; It seems to work (let's hope), but I'm still curious... how would you do it?

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  • javascript regular expressions

    - by Zhasulan Berdybekov
    Help me with regular expressions. I need to check the text on the hour and minute. That is the first case, the text can be from 0 to 12. In the second case, the text can be from 1 to 60. this is my code: var hourRegEx = /^([0-9]{2})$/; //You can fix this line of code? $(document).ready( function(){ $('form.form').submit(function(){ if( $('input.hour').val().match(hourRegEx) ){ return true; } return false; }); }); In my case, the code says that, for example 52, too, the correct answer

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  • Splitting Nucleotide Sequences in JS with Regexp

    - by TEmerson
    I'm trying to split up a nucleotide sequence into amino acid strings using a regular expression. I have to start a new string at each occurrence of the string "ATG", but I don't want to actually stop the first match at the "ATG". Valid input is any ordering of a string of As, Cs, Gs, and Ts. For example, given the input string: ATGAACATAGGACATGAGGAGTCA I should get two strings: ATGAACATAGGACATGAGGAGTCA (the whole thing) and ATGAGGAGTCA (the first match of "ATG" onward). A string that contains "ATG" n times should result in n results. I thought the expression /(?:[ACGT]*)(ATG)[ACGT]*/g would work, but it doesn't. If this can't be done with a regexp it's easy enough to just write out the code for, but I always prefer an elegant solution if one is available.

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  • Need some help setting up subdomains for my site

    - by KarimSaNet
    I'm setting up my website and want to have it so all subdomain requests are rewritten to the appropriate subdirectory. For example http://projects.karimsa.net/ -> http://karimsa.net/projects/ But I want to use the Apache rewrite mod to do this so that the URL in the browser stays the same. Here is what my config looks like at the moment: ## rewrite subdomains RewriteEngine On RewriteCond %{HTTP_HOST} ^(.*).karimsa.net RewriteCond %{HTTP_HOST} !^www.karimsa.net [NC] RewriteRule ^(.*)$ http://karimsa.net/%1/$1 [R=301,L] And my CNAME records on 'projects.karimsa.net': Domain TTL Data Type projects.karimsa.net 14400 karimsa.net CNAME Theoretically, I feel this should work. But when I go to the URL, it gives me a server misconfiguration error, my provider's default webpage. What I should see is the index.php under /projects/. What am I doing wrong? Any help would be appreciated, thanks for reading. Addition: I realized I forgot to mention some of the problem. The domain 'karimsa.net' is parked at 'karimsa.x10.mx'. If I set up the same configuration on 'projects.karimsa.x10.mx', the rewrite and CNAME work. But on the parked domain I still get the default webpage.

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  • Notepad++ regular expression find and replace $_REQUEST with $_GET but a more secure

    - by David
    What I am doing is replacing, in a large program, all $_REQUEST['var'] and mysql_escape_string($_REQUEST['var']) with either the 1st or 2nd line below the dotted line. Now, I have figured out this much of the regular expression but I would like to make it simpler. Instead of having to run the top one first then the 2nd one I would like to just run one all together. I tried this but it did not work. (mysql_escape_string\()*$_REQUEST\[\'([^']*)\'\]\)(\)*) So below is what works but again have to do it twice. $_REQUEST\[\'([^']*)\'\] mysql_escape_string\($_REQUEST\[\'([^']*)\'\]\) (isset($_GET['\1'])?mysql_real_escape_string($_GET['\1']):false) (isset($_POST['\1'])?mysql_real_escape_string($_POST['\1']):false) ============================ Update: Yeah, after some research I figured out that Notepad++ does not support most regular expressions. I guess one additional step can not hurt a person. It's just laziness. *NOTE: BUT if anyone wants to try feel free to comment. At least it is just 2 steps and not 20.

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  • How can I improve this regular expression?

    - by Michael Haren
    I want a regular expression to match valid input into a Tags input field with the following properties: 1-5 tags Each tag is 1-30 characters long Valid tag characters are [a-zA-Z0-9-] input and tags can be separated by any amount of whitespace Here's what I have so far--it seems to work but I'm interested how it could be simplified or if it has any major flaws: \s*[a-zA-Z0-9-]{1,30}(\s+[a-zA-Z0-9-]{1,30}){0,4}\s* // that is: \s* // match all beginning whitespace [a-zA-Z0-9-]{1,30} // match the first tag (\s+[a-zA-Z0-9-]{1,30}){0,4} // match all subsequent tags \s* // match all ending whitespace Preprocessing the input to make the whitespace issue easier isn't an option (e.g. trimming or adding a space). If it matters, this will be used in javascript. Any suggestions would be appreciated, thanks!

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  • mine phrases (up to 3 words) from a given text

    - by DS_web_developer
    I asked before for a simple solution to my problem (using sphinx search service) but I got nowhere... someone has kindly provided me with this code <?php /** * $Project: GeoGraph $ * $Id$ * * GeoGraph geographic photo archive project * This file copyright (C) 2005 Barry Hunter ([email protected]) * * This program is free software; you can redistribute it and/or * modify it under the terms of the GNU General Public License * as published by the Free Software Foundation; either version 2 * of the License, or (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program; if not, write to the Free Software * Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. */ /** * Provides the methods for updating the worknet tables * * @package Geograph * @author Barry Hunter <[email protected]> * @version $Revision$ */ function addTwoLetterPhrase($phrase) { global $w2; $w2[$phrase] = (isset($w2[$phrase]))?($w2[$phrase]+1):1; } function addThreeLetterPhrase($phrase) { global $w3; $w3[$phrase] = (isset($w3[$phrase]))?($w3[$phrase]+1):1; } function updateWordnet(&$db,$text,$field,$id) { global $w1,$w2,$w3; $alltext = strtolower(preg_replace('/\W+/',' ',str_replace("'",'',$text))); if (strlen($text)< 1) return; $words = preg_split('/ /',$alltext); $w1 = array(); $w2 = array(); $w3 = array(); //build a list of one word phrases foreach ($words as $word) { $w1[$word] = (isset($w1[$word]))?($w1[$word]+1):1; } //build a list of two word phrases $text = $alltext; $text = preg_replace('/(\w+) (\w+)/e','addTwoLetterPhrase("$1 $2")',$text); $text = $alltext; $text = preg_replace('/(\w+)/','',$text,1); $text = preg_replace('/(\w+) (\w+)/e','addTwoLetterPhrase("$1 $2")',$text); //build a list of three word phrases $text = $alltext; $text = preg_replace('/(\w+) (\w+) (\w+)/e','addThreeLetterPhrase("$1 $2 $3")',$text); $text = $alltext; $text = preg_replace('/(\w+)/','',$text,1); $text = preg_replace('/(\w+) (\w+) (\w+)/e','addThreeLetterPhrase("$1 $2 $3")',$text); $text = $alltext; $text = preg_replace('/(\w+) (\w+)/','',$text,1); $text = preg_replace('/(\w+) (\w+) (\w+)/e','addThreeLetterPhrase("$1 $2 $3")',$text); foreach ($w1 as $word=>$count) { $db->Execute("insert into wordnet1 set gid = $id,words = '$word',$field = $count");// ON DUPLICATE KEY UPDATE $field=$field+$count"); } foreach ($w2 as $word=>$count) { $db->Execute("insert into wordnet2 set gid = $id,words = '$word',$field = $count"); } foreach ($w3 as $word=>$count) { $db->Execute("insert into wordnet3 set gid = $id,words = '$word',$field = $count"); } } ?> It works fine and does almost exactly what I need....... except.... it is not utf8 friendly... I mean... it splits whole words into parts (on special chars) where it shouldn't! so my guess is I should use multibyte functions instead of regular preg_replace... I tried to replace preg_replace with mb_ereg_replace but it is not working as it should... at least not for 2 and 3 words phrases any ideas?

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  • How can I match everything in a string until the second occurrence of a delimiter with a regular expression?

    - by Steve
    I am trying to refine a preg_match_all by finding the second occurrence of a period then a space: <?php $str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop. Slight chance of showers."; preg_match_all ('/(^)((.|\n)+?)(\.\s{2})/',$str, $matches); $dataarray=$matches[2]; foreach ($dataarray as $value) { echo $value; } ?> But it does not work: the {2} occurrence is incorrect. I have to use preg_match_all because I am scraping dynamic HTML. I want to capture this from the string: East Winds 20 knots. Gusts to 25 knots.

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  • extract word with regular expression

    - by farka
    I have a string 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and I would like to extract the words temperatoA and CelcieusB. I have this regular expression (\d+/(\w+),?)*! but I only get the match 1/temperatoA,2/CelcieusB! Why?

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  • Regular Expression Fails

    - by Meander365
    Anyone help? When I run this I get " invalid quantifier ?<=href= " var aHrefMatch = new RegExp("(?<=href\=")[^]+?(?=")"); var matchedLink = mystring.match(aHrefMatch); But I know the regular expression is valid. Any ideas?

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  • Normalizing Strings using Regexes

    - by RasputinJones
    How do I match this string "1 & 2" from this string "Foo Bar 1 & 2"? How do I match this string "1, 2 & 3" from this string "Foo Baz 1, 2 & 3"? Trying to split out "Foo Bar" from the string using regexes while using the presence of "1 & 2" or "1, 2 & 3" as conditionals to normalize these strings into "Foo Bar 1" and "Foo Bar 2" or "Foo Baz 1", "Foo Baz 2" and "Foo Baz 3" respectively.

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  • Is it possible to exclude some elements from parsing when using regular expression and .replace()?

    - by Fletus Mefitis
    <script language="javascript"> $("div.post-content , .parsedsig").each(function(){ if($(this).html().indexOf("[/tabulaScriptum]") != -1) { pattern = /\[tabulaScriptum=(.*?)\]([^\[]*)\[\/tabulaScriptum\]/gi $(this).html($(this).html().replace(pattern, "<div class='tabulaScriptum'><div class='tabulaNomen'>$1</div><div class='tabulaImpleo'>$2</div></div>")) } }); </script> This script is working perfectly, except for one thing... I need not to replace [tabulaScriptum=][/tabulaScriptum] in certain elements. For example, I don't want to replace those "tags" in element that has class .code-box. Is it possible? Clarification: element .code-box is located within .post-content. Clarification #2: this script creates simple division spoiler. .tabulaScriptum is spoier's body, .tabulaNomen is spoiler's name and button which, in turn, reveals(or hides) .tabulaImpleo on click. Reveal\hide script is located in some other place, and I didn't post it here since it doesn't really matter. Clarification #3: http://jsfiddle.net/PRtsw/1/ fiddle.

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  • Highlight curret page in jquery

    - by 3gwebtrain
    Hi, I have the 12 html pages. and all this pages are loads when the left navigation bar link clicked. in this, i need to add a class to the current link, which is clicked and loaded the page. i tried with this: $(function(){ $('#container li a').click(function(){ $('#container li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); if(currentPage==pathname){ $(this).addClass('current'); } else{ alert('wrong'); } // alert(pathname+' currentPage: '+currentPage); }) }) it works, but on page load, the class is removed, i don't know why it's happening.. any help?

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  • Regular Expression

    - by Blanca
    Hi! i would like to avoid texts like this one: height="49" with a regular expresion. I tought in .replaceAll("\s*="*"",""); (replaceAll is used as a method in a java class), but eclipse don't allowed me to do that. Any other suggestion?? tx!

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  • parse unformatted string into dictionary with python

    - by user553131
    I have following string. DATE: 12242010Key Type: Nod32 Anti-Vir (30d trial) Key: a5B2s-sH12B-hgtY3-io87N-srg98-KLMNO I need to create dictionary so it would be like { "DATE": "12242010", "Key Type": "Nod32 Anti-Vir (30d trial)", "Key": "a5B2s-sH12B-hgtY3-io87N-srg98-KLMNO" } The problem is that string is unformatted DATE: 12242010Key Type: Nod32 Anti-Vir (30d trial) there is no space after Date before Key Type also it would be nice to have some validation for Key, eg if there are 5 chars in each box of key and number of boxes I am a beginner in python and moreover in regular expressions. Thanks a lot.

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  • dropping characters from regular expression groups

    - by tcurdt
    The goal: I want to convert a number from the format "10.234,56" to "10234.56" Using this simple approach almost gets us there /([\d\.]+),(\d\d)/ => '\1.\2' The problem is that the first group of the match (of course) still contains the '.' character. So questions are: Is it possible to exclude a character from the group somehow? How would you solve this with a single regexp (I know this is a trivial problem when not using a single regexp)

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  • python and regular expression with unicode

    - by bsn
    I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

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  • Does '[ab]+' equal '(a|b)+' in python re module?

    - by user1477871
    I think pat1 = '[ab]' and pat2 = 'a|b' have the same function in Python(python2.7, windows) 're' module as a regular expression pattern. But I am confused with '[ab]+' and '(a|b)+', do they have the same function, if not plz explain details. ''' Created on 2012-9-4 @author: melo ''' import re pat1 = '(a|b)+' pat2 = '[ab]+' text = '22ababbbaa33aaa44b55bb66abaa77babab88' m1 = re.search(pat1, text) m2 = re.search(pat2, text) print 'search with pat1:', m1.group() print 'search with pat2:', m2.group() m11 = re.split(pat1, text) m22 = re.split(pat2, text) print 'split with pat1:', m11 print 'split with pat2:', m22 m111 = re.findall(pat1, text) m222 = re.findall(pat2, text) print 'findall with pat1:', m111 print 'findall with pat2:', m222 output as below: search with pat1: ababbbaa search with pat2: ababbbaa split with pat1: ['22', 'a', '33', 'a', '44', 'b', '55', 'b', '66', 'a', '77', 'b', '88'] split with pat2: ['22', '33', '44', '55', '66', '77', '88'] findall with pat1: ['a', 'a', 'b', 'b', 'a', 'b'] findall with pat2: ['ababbbaa', 'aaa', 'b', 'bb', 'abaa', 'babab'] why are 'pat1' and 'pat2' different and what's their difference? what kind of strings can 'pat1' actually match?

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  • Getting all matches for a regexp on clojure

    - by Deleteman
    I'm trying to parse an HTML file and get all href's inside it. So far, the code I'm using is: (map #(println (str "Match: " %)) (re-find #"(?sm)href=\"([a-zA-Z.:/]+)\"" str_response)) str_response being the string with the HTML code inside it. According to my basic understanding of Clojure, that code should print a list of matches, but so far, no luck. It doens't crash, but it doens't match anything either. I've tried using re-seq instead of re-find, but with no luck. Any help? Thanks!

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