Search Results

Search found 71056 results on 2843 pages for 'django class based views'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 124/2843 | < Previous Page | 120 121 122 123 124 125 126 127 128 129 130 131  | Next Page >

  • Trying to Nullify Django model fields with method where model and fields are parameters

    - by Johnny4000
    I'm trying to write a method like the below where a list of fields (a subset of all the fields) is passed in as a parameter and has their column values set to null. I would be happy of I could get a method with just the fields as a parameter like below, but having the model as a parameter would be even better. from my_project.my_app.models import MyModel def nullify_columns (self, null_fields): field_names = MyModel._meta.get_all_field_names() for field in field_names: if field in null_fields: # The below line does not work because I'm not sure how to # dynamically assign the field name. MyModel.objects.all().update( (MyModel.get_field(field).column) = None) Right now I have something like if 'column1' in list_of_fields: MyModel.objects.all().update(column1 = None) if 'column2' in list_of_fields: MyModel.objects.all().update(column2 = None) etc. which is horrible, but works.

    Read the article

  • Modify Django settings variables in a middleware

    - by jack
    I set a variable MAX_REQUEST = 100 in settings.py I write a middleware which may lower this value for request origining from a proxy ip address by the following code: settings.MAX_REQUEST = 10 However, looks like the above modification affects all legitimate users. Is it normal?

    Read the article

  • Django select max id

    - by pistacchio
    Hi, given a standard model (called Image) with an autoset 'id', how do I get the max id? So far I've tried: max_id = Image.objects.all().aggregate(Max('id')) but I get a 'id__max' Key error. Trying max_id = Image.objects.order_by('id')[0].id gives a 'argument 2 to map() must support iteration' exception Any help?

    Read the article

  • django manual login and redirect

    - by Zayatzz
    Hello I have such view that handles user registration. After creating new user i want to manually authenticate it and log it in.: def register(request): ... ... if form.is_valid(): username = form.cleaned_data['username'] password = form.cleaned_data['password1'] email = '' newuser = User.objects.create_user(username, email, password) user = authenticate(username=username, password=password) login (request, user) I have set LOGIN_REDIRECT_URL to '/profile/', but after authenticating and logging user in, it redirects me back to the same view not to /profile/, why? And how can i specify where to redirect after logging in? If i add HttpResponseRedirect('/profile/') After login line - nothing happens. The script never ends up there. Alan.

    Read the article

  • django media url is not resolved in 500 internal server error template

    - by Tom Tom
    Hi, I'm using a 500.html template for my app, which is an identical copy of the 404.html with some minor text changes. Interestingly the {{ media_url }} context variable will not be resolved by the server if the 500.html is presented (e.g. when I force an internal server error), resulting in a page without any css loaded. An easy way to circumvent this would be to hardcode the links to the css, but I m just curious why the media_url is not resolved. Probably it is because the server encounters a internal server error and that leads to context variables not any more available!?

    Read the article

  • Django: test failing on a view with @login_required

    - by Esteban Feldman
    Hi all, I'm trying to build a test for a view that's decorated with @login_required, since I failed to make it work, I did a simple test and still can't make it pass. Here is the code for the simple test and the view: def test_login(self): user = self._create_new_user() self.assertTrue(user.is_active) login = self.client.login(username=user.username, password=self.data['password1']) self.failUnless(login, 'Could not log in') response = self.client.get('/accounts/testlogin/') self.assertEqual(response.status_code, 200) @login_required def testlogin(request): print 'testlogin !! ' return HttpResponse('OK') _create_new_user() is saving the user and there is a test inside that method to see that is working. The test fails in the response.status_code, returning 302 and the response instance is of a HttpResponseRedirect, is redirecting it as if not logged in. Any clue? I'm missing something? Regards Esteban

    Read the article

  • Django/Python best practice template_dict

    - by fredrik
    Hi, After just been coding for about 6-9 months. I probably changed my coding style a number of times after reading some code or read best practices. But one thing I haven't yet come a cross is a good why to populate the template_dict. As of now I pass the template_dict across a number of methods (that changes/modifies it) and returns is. The result is that every methods takes template_dict as first argument and the returns it and this in my eyes doesn't seems to be the best solution. An idea is to have a method that handles all the changes. But I'm curios if there's a best practice for this? Or is it "do what you feel like"-type of thing? The 2 things I think is pretty ugly is to send as an argument and return it in all methods. And the just the var name is written xxx number of times in the code :) ..fredrik

    Read the article

  • Django openid authentication with google

    - by Zayatzz
    Hello I am looking into authenticating via google. I dont understand how it works:http://code.google.com/apis/accounts/docs/OpenID.html#Samples If i do that 2nd request by entering the data as one url with params into browser i get back XML file. Should i not get back sample response nr3? Can somebody explain this to me? The problem is, that im trying to sort through some third party app that uses google openid authentication and its not recieving authenticated users e-mail back, like in sample response 3. Alan PS i have read through similar questions and their responses and gone through pages like: http://stackoverflow.com/questions/353880/how-does-openid-authentication-works http://www.windley.com/archives/2006/04/how_does_openid.shtml http://tinisles.blogspot.com/2008/02/how-does-openid-work.html http://openid.net/pres/protocolflow-1.1.png etc..

    Read the article

  • add text to the choice_label of ChoiceField in Django

    - by pablo
    The ChoiceField creates a select html element and the options show the choice_label which is the _unicode_ of each model object. How can I change the text of the choice_label without modifying _unicode_ ? I have a Product model and I want to show in the options text the product name + price + link to edit. I've searched in fields.py and widgets.py but couldn't find what needed to be changed. Thanks

    Read the article

  • django link to any user profile in social comunity

    - by dana
    i am trying to build a virtual comunity, and i have a profile page, and a personal page. In the profile page, one can see only the posts of one user(the user whos profile is checked), in the personal page one can see his posts, plus all the posts he has subscribed to (just like in Facebook) it's a little confusing for me how i can link to the profile of one user, i mean when anybody clicks on a username, it should link to his personal profile page. for example, if someone searches name "abc", the rsult would be "abc",and link to his profile. How can i pass to one function the username or id of a linked user? i mean, showing the profile of the logged in user who is checking his profile is quite easy.But how about another user profile, if one wants to access it? thanks a lot!

    Read the article

  • Django stupid mark_safe?

    - by Mark
    I wrote this little function for writing out HTML tags: def html_tag(tag, content=None, close=True, attrs={}): lst = ['<',tag] for key, val in attrs.iteritems(): lst.append(' %s="%s"' % (key, escape_html(val))) if close: if content is None: lst.append(' />') else: lst.extend(['>', content, '</', tag, '>']) else: lst.append('>') return mark_safe(''.join(lst)) Which worked great, but then I read this article on efficient string concatenation (I know it doesn't really matter for this, but I wanted consistency) and decided to update my script: def html_tag(tag, body=None, close=True, attrs={}): s = StringIO() s.write('<%s'%tag) for key, val in attrs.iteritems(): s.write(' %s="%s"' % (key, escape_html(val))) if close: if body is None: s.write(' />') else: s.write('>%s</%s>' % (body, tag)) else: s.write('>') return mark_safe(s.getvalue()) But now my HTML get escaped when I try to render it from my template. Everything else is exactly the same. It works properly if I replace the last line with return mark_safe(unicode(s.getvalue())). I checked the return type of s.getvalue(). It should be a str, just like the first function, so why is this failing?? Also fails with SafeString(s.getvalue()) but succeeds with SafeUnicode(s.getvalue()). I'd also like to point out that I used return mark_safe(s.getvalue()) in a different function with no odd behavior.

    Read the article

  • arbitrary typed data in django model

    - by Dmitry Shevchenko
    I have a model, say, Item. I want to store arbitrary amount of attributes on it, like title, description, release_date. And i want them to be not just strings but have python type, so string, boolean, datetime etc. What are my options here? EAV pattern with separate name-value table won't work because of the same DB type across all values. JSONField can probably help, but it doesn't know about datetime, for example. Also i was looking at PickeField, it fits perfectly, but i'm a bit concerned about performance.

    Read the article

  • django file upload in 2 steps

    - by alexarsh
    Hi, I want to upload a file in 2 steps. First I want to upload it and show the errors and on the second step I want actually to save the file data in the database. So I made a simple form and my problem is how to pass the same file to the form on the second step? I mean how to insert request.FILES data in the same form again. Or maybe there is a better way? Thanks, Arshavski Alexander.

    Read the article

  • Django dislaying upload file content

    - by dana
    hello, i have an application that loads different documents to the server, and allows users to read documents' content. i am uploading the documents to the server, and then i try to read the courses by id, like: def view_course(request,id): u = Courses.objects.get(pk=id) etc But i don't find anywhere : how can i actually read the content of a /.doc/.pdf/.txt and display it on a web page? thanks in advance!

    Read the article

  • Django Distinct on queryset in forms.py

    - by Thomas
    Hi all, I try to get a list with distinct into the forms.py like this: forms.ModelMultipleChoiceField(queryset=Events.objects.values('hostname'), required=False).distinct() In the python shell this command works perfect, but when trying it in forms.py leaves me a blank form, so nothing appears. When i just do Events.objects.all() the form appears, but distinct doesn't work with Events.objects.all()... i also tried values_list etc but doesn't seem to fit into the forms neither... anyone got an idea how to get a SELECT DISTINCT into a ModelMultipleChoiceField? I read some other questions about this at stackoverflow but nothing seems to work out with me, so hopefully someone knows how to do this in forms.py. Thxs in advance

    Read the article

  • Django: tinyMCE and cross site javascript

    - by pistacchio
    Hi, follow this question, I was able to set some textareas in my admin page as richtext inputs. The most voted answer suggests to follow an example and is what i did. Also, it talks about a problem concerning "blank pages". I'm having the same problem and I'm not able to solve it. I have my media files served by a different server, so MEDIA_URL points to a different host with a different port. To simulate this in my dev environment, I also serve media files from a different port. Debugging the failing javascript, Chrome yelds: Unsafe JavaScript attempt to access frame with URL http://localhost:8000/admin/blog/post/add/ from frame with URL http://localhost:88/s3mangerie/js/tiny_mce/themes/advanced/image.htm. Domains, protocols and ports must match. How to solve this problem? Thanks

    Read the article

  • Bypass django form validation on new form instance

    - by Thomas Schultz
    Hello! I have a situation where we are trying to autofill some form data on the second page of a signup and I was wondering if there's a way to bypass the entire form validation when we pass in only a couple of fields? so we have something like form = NewForm(request.POST) Where request.POST only contains some of the fields in NewForm(). So the page loads and there is feedback about how some fields are not filled in yet. This all happens from the GET request of the second page. Is there a way to do something like... form = NewForm(request.POST, validate=False)

    Read the article

  • Django: Group by?

    - by Mark
    I'm looking for something like the following: previous_invoices = Invoice.objects.filter(is_open=False).order_by('-created').group_by('user') (group_by() doesn't exist) This would find the most recently closed invoice for each user. This aggregation API seems to let you do stuff like this for counts and sums, but I don't need a count or sum or anything, I actually want the invoice objects!

    Read the article

  • django username in url, instead of id

    - by dana
    Hello, in a mini virtual community, i have a profile_view function, so that i can view the profile of any registered user. The profile view function has as a parameter the id of the user wich the profile belongs to, so that when i want to access the profile of user 2 for example, i call it like that: http://127.0.0.1:8000/accounts/profile_view/2/ My problem is that i would like to have the username in the url, and NOT the id. I try to modify my code as follows, but it doesn't work still. Here is my code: view: def profile_view(request, user): u = User.objects.get(pk=user) up = UserProfile.objects.get(created_by = u) cv = UserProfile.objects.filter(created_by = User.objects.get(pk=user)) blog = New.objects.filter(created_by = u) replies = Reply.objects.filter(reply_to = blog) vote = Vote.objects.filter(voted=blog) following = Relations.objects.filter(initiated_by = u) follower = Relations.objects.filter(follow = u) return render_to_response('profile/publicProfile.html', { 'vote': vote, 'u':u, 'up':up, 'cv': cv, 'ing': following.order_by('-date_initiated'), 'er': follower.order_by('-date_follow'), 'list':blog.order_by('-date'), 'replies':replies }, context_instance=RequestContext(request)) and my url: urlpatterns = patterns('', url(r'^profile_view/(?P<user>\d+)/$', profile_view, name='profile_view'), thanks in advance!

    Read the article

  • django - variable declared in base project does not appear in app

    - by unsorted
    I have a variable called STATIC_URL, declared in settings.py in my base project: STATIC_URL = '/site_media/static/' This is used, for example, in my site_base.html, which links to CSS files as follows: <link rel="stylesheet" href="{{ STATIC_URL }}css/site_tabs.css" /> I have a bunch of templates related to different apps which extend site_base.html, and when I look at them in my browser the CSS is linked correctly as <link rel="stylesheet" href="/site_media/static/css/site_tabs.css" /> (These came with a default pinax distribution.) I created a new app called 'courses' which lives in the ...../apps/courses folder. I have a view for one of the pages in courses called courseinstance.html which extends site_base.html just like the other ones. However, when this one renders in my browser it comes out as <link rel="stylesheet" href="css/site_tabs.css" /> as if STATIC_URL were equal to "" for this app. Do I have to make some sort of declaration to get my app to take on the same variable values as the project? I don't have a settings.py file for the app. by the way, the app is listed in my list of INSTALLED_APPS and it gets served up fine, just without the link to the CSS file (so the page looks funny). Thanks in advance for your help.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 120 121 122 123 124 125 126 127 128 129 130 131  | Next Page >