Search Results

Search found 8646 results on 346 pages for 'echo flow'.

Page 126/346 | < Previous Page | 122 123 124 125 126 127 128 129 130 131 132 133  | Next Page >

  • Why use of session name and session id in the get variables does not work?

    - by Roman
    I have the following code: $location .= 'red=no&'.session_name() . "=". session_id(); $content = file_get_contents($location); echo $content; If I run it, noting is displayed in my browser. However, if I modify it in the following way: $location .= 'red=no'; $content = file_get_contents($location); echo $content; everything works fine (I see the content in my browser). What is also strange, if I display the value of the $location variable from the first example (url) and manually paste it in the address line of my browser, I do see the content. So, my browser is able to use this URL and file_get_contents not. Does anybody know how it can be explained?

    Read the article

  • How to use PHP to POST to a web page then get the results back, locally

    - by Patrick Gates
    I have a page on my web server that is PHP that is set to do this if ($_POST['post'] == true) { echo: 'hello, world'; } I want to create a page that calls to that page, posts "post" equal to "true" and then returns the value "hello, world". I have a script that works, but only if the pages are on different servers. Unfortunately, both of these pages are on the same server, so, heres my code, and I'm hoping you guys can help me, Thank you :) function post($site, $post) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$site); curl_setopt($ch, CURLOPT_FAILONERROR,1); curl_setopt ($ch, CURLOPT_POST, 1); curl_setopt ($ch, CURLOPT_POSTFIELDS, $post); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_TIMEOUT, 15); $retValue = curl_exec($ch); curl_close($ch); return $retValue; } echo post('data.php', 'post=true');

    Read the article

  • If-statement: how to pull 2nd GET variable

    - by arsoneffect
    How do I get this to pull my 2nd variable? (I already have a switch setup) <body id="<?php if (! isset($_GET['page'])) { echo "home"; } else { $_GET['page']; echo $page; } ?>"> I have a switch statement that pulls the pages from index.php?page=##### and I have just added this part to my switch: index.php?page=####&section=##### Right now, if I am on page=photos, my code ends up being: <body id="photos"> I need to make it so that if any link has the "sections" variable on it like this page=photos&section=cars it uses the same ID: <body id="photos">

    Read the article

  • Access PHP var from external javascript file

    - by FFish
    I can access a PHP var with Javascript like this: <?php $fruit = "apple"; $color = "red"; ?> <script type="text/javascript"> alert("fruit: " + "<?php echo $fruit; ?>"); // or shortcut "<?= $fruit ?>" </script> But what if I want to use an external JS file: <script type="text/javascript" src="externaljs.js"></script> externaljs.js: alert("color: " + "<?php echo $color; ?>");

    Read the article

  • Internet Explorer and Google Chrome different showup of content

    - by NDLombardi
    I'm setting up an online form where to choose boxes and stuff. I almost finished the whole thing when I said to my self "Let's try it in IE". This is the result I want and what comes up in Google Chrome: And this is what happens in IE: And this is the CSS and HTML for that part: <!--- HTML ---> <div id="choosen"><img src="img.jpg" class="center-img" /></div> /* --- CSS --- */ img.center-img{ margin-top:15px; position:relative; width: <?php echo $width; ?>px; left:50%; margin-left:-<?php echo $width/2; ?>px; } Basically the image is centered into the div as this page I'm writing will be included into another one which I never saw and someone else will do it.

    Read the article

  • Class works without declaring variables?

    - by Maxim Droy
    I'm learned php as functional and procedure language. Right now try to start learn objective-oriented and got an important question. I have code: class car { function set_car($model) { $this->model = $model; } function check_model() { if($this->model == "Mercedes") echo "Good car"; } } $mycar = new car; $mycar->set_car("Mercedes"); echo $mycar->check_model(); Why it does work without declaration of $model? var $model; in the begin? Because in php works "auto-declaration" for any variables? I'm stuck

    Read the article

  • VBScript Writing to Server Text File

    - by Keyfer Mathewson
    I have created a VBScript which pulls the service tag, username, and computer name from a computer. What I need to do now is compile this information in a text document. How it's set up is as follows: We have an Active Directory Server, with a folder for login scripts. I have created a batch file to run this .vbs script, and the script works well so far. What I now need is for a file on the AD server, called "logging.txt", to be populated with the information that is created with the .vbs script. This is the script I have so far: 'Get Dell Service Tag Info set ProSet = GetObject("winmgmts:").InstancesOf("Win32_BIOS") Set ProSet1 = GetObject("winmgmts:").InstancesOf("Win32_SystemEnclosure") For each Pro in ProSet For each Pro1 in ProSet1 ServiceTag=Pro.SerialNumber wscript.echo ServiceTag exit for Next exit for Next 'get username and computername, could also be asked in a batch Set oShell = WScript.CreateObject("WScript.Shell") Set oShellEnv = oShell.Environment("Process") sComputerName = oShellEnv("ComputerName") sUsername = oShellEnv("username") wscript.echo sComputerName & " " & sUsername Thank you very much in advance!

    Read the article

  • Commands implicitly threaded in Makefiles ?

    - by apple92
    Hi, I have a "super" makefile which launches two "sub" make file: libwebcam: @echo -e "\nInvoking libwebcam make." $(MAKE) -C $(TOPDIR)/libwebcam uvcdynctrl: @echo -e "\nInvoking uvcdynctrl make." $(MAKE) -C $(TOPDIR)/uvcdynctrl uvcdynctrl uses libwebcam... I noticed that those two builds are launched as separate threads by make ! Thus sometimes the lib is not available when uvcdynctrl starts being built, and I get errors. By default, make should not launch commands as threads since this is available only through -j (number of jobs) and, according to the make manual, there is no thread by default. I run this on an Ubuntu. Did someone face the same issue ? Apple92

    Read the article

  • Explaining makefile

    - by Michael
    xpi_built := $(build_dir)/$(install_rdf) \ $(build_dir)/$(chrome_manifest) \ $(chrome_jar_file) \ $(default_prefs) xpi_built_no_dir := $(subst $(build_dir)/,,$(xpi_built)) $(xpi_file): $(build_dir) $(xpi_built) @echo "Creating XPI file." cd $(build_dir); $(ZIP) ../$(xpi_file) $(xpi_built_no_dir) @echo "Creating XPI file. Done!" $(build_dir)/%: % cp -f $< $@ $(build_dir): @if [ ! -x $(build_dir) ]; \ then \ mkdir $(build_dir); \ fi can anyone explain me this makefile part? particularly interested in $(build_dir)/%: % as well as $< and $@ directives two labels $(build_dir) exists, I guess both are executed, but in which order?

    Read the article

  • A beginner's question...How do I use $_POST instead of $_GET? (PHP)

    - by ggfan
    Okay, for all my coding so far I been using GETs and only $_POST on the same script. Ex: profile.php would show all the posts an user made and under each of their post, they can edit their post. The way I been using it is through $_GETs. So.. //this is the link users click to edit their post echo '<td><a href="editad.php?posting_id='.$row3['posting_id'].' ">Edit</a>'; //on the editad.php $posting_id=$_GET['posting_id']; if (isset($posting_id)){ //show all the forms, sqls to do the editing } else{ //if the $_GET hasn't been set echo "You have not specified which ad to edit. Please go back"; } How do I do this via POST? Thanks :)

    Read the article

  • How do I specify the regular expression to disable the use of underscores after the '@' sign in php for email validation?

    - by Qlidnaque
    Currently the following email in the script validates even though there are no underscores indicated in the second part of the regular expression validation after the '@' sign. How do I make underscores invalid in the second part of the email? <?php $email = 'firstname.lastname@a_aa.bbb.co_m'; $regexp = "/^[^0-9][A-z0-9_]+([.][A-z0-9_]+)*[@][A-z0-9]+([.][A-z0-9]+)*[.][A-z]{2,4}$/"; if (preg_match($regexp, $email)) { echo "Email address is valid."; } else { echo "Email address is <u>not</u> valid."; } ?>

    Read the article

  • php add hours to date output wrong result

    - by i need help
    Basically what I want to do is to send an email to follow up on order placed in 3 hours later. What I try to do is to get the current date (up to hours level), then compare with the orderdate+ 3 hours, to see whether it match. Example orderdate: 2010-06-12 18, after add 3 hours should become 2010-06-12 21 However, after add hour, the final result sometimes become bigger, sometimes become smaller... something wrong. $now= date('Y-m-d H'); echo $now . "<br>"; ... ... while ($data = mysql_fetch_array ($result)) { $orderid = $data['orderid']; $orddate = $data['orddate']; $corddate= date('Y-m-d H:i:s', $orddate); $year = substr ($corddate, 0, 4); $month = substr ($corddate, 5, 2); $day = substr ($corddate, 8, 2); $hour = substr ($corddate, 11, 2); $actualorderdate= $year . "-" . $month . "-" . $day . " " . $hour; $new_time = mktime ($hour+3, 0, 0, $month, $day, $year); $year = date ('Y', $new_time); $month = date ('m', $new_time); $day= date ('d', $new_time); $hour= date ('h', $new_time); $xhourslater= $year . "-" . $month . "-" . $day . " " . $hour; echo "actualorderdate: ". $actualorderdate. " xhourslater: " . $xhourslater. "<br>"; if($now==$xhourslater) { echo "now is 3 hours later" . "<br>"; //send email follow up, then update status as sent, in order not to resend anytime in the 3rd hour. } }

    Read the article

  • PHP PDO Username Availability Checker

    - by John Bernal
    I'm building a registration page that uses JQuery's validator plugin to validate the form. For the username, i used the remote method. So here's my jquery+html code: fiddle And here's Available.php: <?php $usr = $_POST["username"]; $link = new PDO('mysql:***;dbname=***;charset=UTF-8','***','***'); $usr_check = $link->prepare("SELECT * FROM Conference WHERE Username = :usr"); $link->bindParam(':usr', $usr); $usr_check->execute(); if($usr_check->rowCount()>0) echo "false"; else echo "true"; ?> So I have a test account in my database with the username: user. When I tried to submit my form with the same username, it didn't display the error saying "username taken" which means the php isn't correct. Any ideas where I went wrong? Thanks

    Read the article

  • Strip H1 tag and its contents

    - by Andy
    How can i remove <h1>and its contents</h1> from the following line strip_tags(substr($article->content(),0,255) from this complete code <?php $last_articles = $this->children(array('limit'=>5, 'order'=>'page.created_on DESC')); ?> <?php foreach ($last_articles as $article): ?> <div class="entry"> <h3><?php echo $article->link($article->title); ?></h3> <?php echo strip_tags(substr($article->content(),0,255).'...', '<p><a>'); ?> </div> <?php endforeach; ?> Any help would be appreciated.

    Read the article

  • OOP PHP simple question

    - by Tristan
    Hello, I'm new to OOP in PHP, is that to seems correct ? class whatever { Function Maths() { $this->sql->query($requete); $i = 0; while($val = mysql_fetch_array($this)) { $tab[i][average] = $val['average']; $tab[i][randomData] = $val['sum']; $i=$i+1; } return $tab; } I want to access the data contained in the array $foo = new whatever(); $foo->Maths(); for ($i, $i <= endOfTheArray; i++) { echo Maths->tab[i][average]; echo Maths->tab[i][randomData]; } Thank you ;)

    Read the article

  • Zend and Jquery (Ajax Post)

    - by Zend_Newbie_Dev
    I'm using zend framework, i would like to get POST data using Jquery ajax post on a to save without refreshing the page. //submit.js $(function() { $('#buttonSaveDetails').click(function (){ var details = $('textarea#details').val(); var id = $('#task_id').val(); $.ajax({ type: 'POST', url: 'http://localhost/myproject/public/module/save', async: false, data: 'id=' + id + '&details=' + details, success: function(responseText) { //alert(responseText) console.log(responseText); } }); }); }); On my controller, I just don't know how to retrieve the POST data from ajax. public function saveAction() { $data = $this->_request->getPost(); echo $id = $data['id']; echo $details = $data['details']; //this wont work; } Thanks in advance.

    Read the article

  • Codeigniter: Retrieving data on button click with Ajax

    - by OllyTenerife
    I have a simple webpage which generates a random quote from my database upon refreshing the page. I wish to implement some AJAX and JQuery in order to generate quotes via the button rather than having to refresh the page. I have done some research but I am not sure how to implement this in Codeigniter. My current code is below... Page controller: public function index() { $this->load->model('quote_model', '', TRUE); $data['quotes'] = $this->quote_model->getRandom(); $this->load->view('home', $data); } The view: <?php include ('layout/header.php'); ?> <div class="container-fluid"> <div class="row"> <div class="col-md-4 quote-holder"> <img src="application/assets/alan1.jpg" alt="..." class="img-circle img-responsive"> <br> <blockquote class="text-center"> <p><?php echo $quotes[0]['quote']; ?></p> <footer class="text-center"><?php echo $quotes[0]['character_name']; ?> in <cite title="Source Title"><?php echo $quotes[0]['series_name']; ?></cite></footer> </blockquote> <button type="button" class="btn btn-default center-block">Generate quote</button> </div> </div> <?php include ('layout/footer.php'); ?> Here is the function in the model I am retrieving the data from: function getRandom() { $query = $this->db->query(" SELECT * FROM quotes, characters, series WHERE quotes.series_id = series.series_id AND quotes.character_id = characters.character_id ORDER BY rand() LIMIT 1 "); return $query->result_array(); } Should I simply be using something like this? $("button").click(function(){ $.get( "Page/index", function( data ) { //output data to page element... } });

    Read the article

  • preg_match_all confusing failing

    - by James
    $string = (string) file_get_contents($_FILES['file']['tmp_name']); echo $string; preg_match_all("/[\._a-zA-Z0-9-]+@[\._a-zA-Z0-9-]+/i", $string, $matches); print_r($matches); I am parsing text/csv files and grabbing email addresses from uploaded files. When parsing a Google Contact file I exported it weirdly fails. But when I simply copy the string that is echo'd and paste that instead of the file_get_contents result, it parses and works. Any idea why it is refusing to take the file_get_contents string, but if I paste in the raw data myself, it works?

    Read the article

  • Bash intercepting wildcard in script

    - by MrRoth
    I am using Bash script to read line by line from a text file, which has special characters in it (regular expression). When I use echo "${SOME_VAR}" it does not display the text as is. I am familiar with Prevent * to be expanded in the bash script. How can I display and use the text as is? UPDATE The text (TSV) file holds tuples similar to (the last entry is a psql query) bathroom bathroom select name from photos where name ~* '\mbathroom((s)?|(''s)?)\M'; I am reading the CSV as follows: tail -n+2 text.file | while IFS=$'\t' read x y z do echo "${z}" done which gives the output select name from photos where name ~* 'mbathroom((s)?|(''s)?)M'); note that the '\' is missing

    Read the article

  • Array iteration issue

    - by Tao
    i have this array which i echo and get this results: $hostess_ids[]=$row['hostess_id']; $j=0; foreach($hostess_ids as $hostess_selected){ $hostess_array= explode("-",$hostess_selected); echo var_dump($hostess_array); This is the output array(1) { [0]=> string(2) "16" } array(1) { [0]=> string(2) "16" } array(1) { [0]=> string(0) "" } array(1) { [0]=> string(0) "" } array(2) { [0]=> string(2) "17" [1]=> string(1) "1" } array(1) { [0]=> string(0) "" } array(2) { [0]=> string(2) "17" [1]=> string(1) "1" } array(2) { [0]=> string(2) "17" [1]=> string(2) "16" } How can i iterate in this array to get the first ceel values, then the second one, etc etc... Thanks..

    Read the article

  • Shell script syntax error: unexpected end of line

    - by user1557674
    I wrote a simple shell script to check for the existence of a xml file and if it exists, then rename an old xml file to be backup and then move the new xml file to where the old xml file was stored. #!/bin/sh oldFile="/Documents/sampleFolder/sampleFile.xml" newFile="/Documents/sampleFile.xml" backupFileName="/Documents/sampleFolder/sampleFile2.backup" oldFileLocation="/Documents/sampleFolder" if [ -f "$newFile" ] ; then echo "File found" #Rename old file mv $oldFile $backupFileName #move new file to old file's location mv $newFile $oldFileLocation else echo "File not found, do nothing" fi However, every time I try to run the script, I get 4 command not found messages and a syntax error: unexpected end of file. Any suggestions on why I get these command not found errors or the unexpected end of file? I double checked that I closed all my double quotes, I have code highlight :) EDIT: output from running script: : command not found: : command not found: : command not found1: : command not found6: replaceXML.sh: line 26: syntax error: unexpected end of file

    Read the article

  • Duplicate array but maintain pointer links

    - by St. John Johnson
    Suppose I have an array of nodes (objects). I need to create a duplicate of this array that I can modify without affecting the source array. But changing the nodes will affect the source nodes. Basically maintaining pointers to the objects instead of duplicating their values. // node(x, y) $array[0] = new node(15, 10); $array[1] = new node(30, -10); $array[2] = new node(-2, 49); // Some sort of copy system $array2 = $array; // Just to show modification to the array doesn't affect the source array array_pop($array2); if (count($array) == count($array2)) echo "Fail"; // Changing the node value should affect the source array $array2[0]->x = 30; if ($array2[0]->x == $array[0]->x) echo "Goal"; What would be the best way to do this?

    Read the article

  • CakePHP two forms next to eachother instead of below eachother

    - by Jarno wildenaar
    Im developing an form in cakePHP where i want to set two forms next to eachother. Im creating it using this code. echo $form-input('timeback', array('options' = array('week',1,2,3,))); This creates a dropdown. Followed by this code: echo $form-end('submit'); This all works well, accept that these two forms should be next to eachother instead of below eachother. Is there a way to make this happen? Thanx in advance!

    Read the article

  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

    Read the article

  • Why is this mail going straight to SPAM box?

    - by ththat
    I am using the following script to send mail <? extract($_POST); $subject = "Feedback from ".$name." (".$email.", Ph: ".$phone.")"; $mail = @mail($send,$subject,$content); if($mail) { echo "Your feedback has been sent"; } else { echo "We are sorry for the inconvienience, but we could not send your feedback now."; } ?> But this is always ending up in the spam Folder. Why?

    Read the article

< Previous Page | 122 123 124 125 126 127 128 129 130 131 132 133  | Next Page >