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  • php add hours to date output wrong result

    - by i need help
    Basically what I want to do is to send an email to follow up on order placed in 3 hours later. What I try to do is to get the current date (up to hours level), then compare with the orderdate+ 3 hours, to see whether it match. Example orderdate: 2010-06-12 18, after add 3 hours should become 2010-06-12 21 However, after add hour, the final result sometimes become bigger, sometimes become smaller... something wrong. $now= date('Y-m-d H'); echo $now . "<br>"; ... ... while ($data = mysql_fetch_array ($result)) { $orderid = $data['orderid']; $orddate = $data['orddate']; $corddate= date('Y-m-d H:i:s', $orddate); $year = substr ($corddate, 0, 4); $month = substr ($corddate, 5, 2); $day = substr ($corddate, 8, 2); $hour = substr ($corddate, 11, 2); $actualorderdate= $year . "-" . $month . "-" . $day . " " . $hour; $new_time = mktime ($hour+3, 0, 0, $month, $day, $year); $year = date ('Y', $new_time); $month = date ('m', $new_time); $day= date ('d', $new_time); $hour= date ('h', $new_time); $xhourslater= $year . "-" . $month . "-" . $day . " " . $hour; echo "actualorderdate: ". $actualorderdate. " xhourslater: " . $xhourslater. "<br>"; if($now==$xhourslater) { echo "now is 3 hours later" . "<br>"; //send email follow up, then update status as sent, in order not to resend anytime in the 3rd hour. } }

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  • returning values from function or method multiple times by only calling the class once

    - by Sokhrat Sikar
    I have a members.php file that shows my websites members. I echo members name by using foreach method. A method of Members class returns an array, then I use foreach loop in the members.php file to echo the members. I am trying to aovid writing php code in my members.php file. Is there a way to avoid using foreach inside members.php file? For example, is it possible to return value from a method couple of times? (by only calling the object once). Just like how we normally call the functions? This question doesn't make sense, but I am just trying to see if there is a away around this issue?

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  • Proper mechanism for sending PHP errors to the client

    - by Chris
    Greetings, I was trying to discover a proper way to send captured errors or business logic exceptions to the client in an Ajax-PHP system. In my case, the browser needs to react differently depending on whether a request was successful or not. However in all the examples I've found, only a simple string is reported back to the browser in both cases. Eg: if (something worked) echo "Success!"; else echo "ERROR: that failed"; So when the browser gets back the Ajax response, the only way to know if an error occurred would be to parse the string (looking for 'error' perhaps). This seems clunky. Is there a better/proper way to send back the Ajax response & notify the browser of an error? Thank you.

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  • PHP and Javascript: Getting file contents with Javascript variable

    - by celliott1997
    Could someone help me to understand why this isn't working? var uname = "<?php echo strtolower($_GET['un']) ?>"; var source = "<?php echo file_get_contents('accounts/"+uname+"') ?>"; console.log(source); I've been trying for a while to get this working and it just doesn't seem to. Before I added in the source variable, it was working fine and displayed the un variable on the page. Thanks.

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  • php multidimensional array if loop

    - by user1091558
    I have a multidimensional array like this array[value][1][1] Now i would like to implement if loop like this if ($value = array[value][1][1]) { echo "It works"; } Now it works if i assign the values like [1][1],[2][1]. Is it possible to compare the whole array. I mean if the array looks like array[value][1][1],array[value][2][1],..........,array[value][n][1] It works should be echoed. I tried like this. if ($value = array[value][][]) { echo "It works"; } But its not working. Can anyone give me the correct syntax?

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  • Why is this mail going straight to SPAM box?

    - by ththat
    I am using the following script to send mail <? extract($_POST); $subject = "Feedback from ".$name." (".$email.", Ph: ".$phone.")"; $mail = @mail($send,$subject,$content); if($mail) { echo "Your feedback has been sent"; } else { echo "We are sorry for the inconvienience, but we could not send your feedback now."; } ?> But this is always ending up in the spam Folder. Why?

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  • showing content in profile box from another file

    - by fusion
    i'm stuck at this facebook application, not knowing how do i go ahead. for the canvas, the app works quite perfectly. i've two pages, quote.html and quote.php. in quote.html, quote.php [which gets the quotes from the database] is called through ajax which displays a quote randomly for 10 secs. however, for the wall tab/profile box, i can't seem to know where i'm going wrong. i created a page called 'profile_box.php', call quote.php for the quotes, setFBML. while this works on canvas [sans the timing], it doesn't display anything on the wall tab. <?php include 'quote.php'; $row = mysql_fetch_array($result, MYSQL_ASSOC); if ( !$row ) { echo "Empty"; } else{ $fb_box = "<p>" . h($row['cArabic']) . "</p>"; $fb_box .= "<p>" . h($row['cQuotes']) . "</p>"; $fb_box .= "<p>" . h($row['vAuthor']) . "</p>"; $fb_box .= "<p>" . h($row['vReference']) . "</p>"; } try{ $url="http://website/name/quote.html"; $facebook->api_client->fbml_refreshRefUrl($url); $fbml = "<fb:ref url='$url'/>"; if(isset($_REQUEST['fb_sig_page_id'])){ $page_id = $_REQUEST['fb_sig_page_id']; $profile_type = $_REQUEST['fb_sig_type']; $facebook->api_client->profile_setFBML($appapikey, $page_id, "$fbml", NULL, NULL, "$fb_box"); } else { $is_tab = isset($_REQUEST['fb_sig_in_profile_tab']); if( !$is_tab ) $user_id = $facebook->require_login(); $result = $facebook->api_client->profile_setFBML($appapikey, $user_id, "$fbml", NULL, NULL, "$fb_box"); } } catch(Exception $ex){ echo 'Caught exception: ', $ex->getMessage(), "\n"; } echo "<fb:add-section-button section=\"profile\" /><br />"; ?> can anyone please give any pointers?

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  • PHP loop position

    - by Jordan Pagaduan
    Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: $dbc = mysql_connect("localhost" , "root" , "") or die (mysql_error()); mysql_select_db('blog_data') or die (mysql_error()); $sql = "SELECT * FROM img_uploaded"; $result = mysql_query($sql); while($rows=mysql_fetch_array($result)) { if ($rows) { echo "<tr><td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td></tr>"; } else { echo "<td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td>"; } }

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  • A beginner's question...How do I use $_POST instead of $_GET? (PHP)

    - by ggfan
    Okay, for all my coding so far I been using GETs and only $_POST on the same script. Ex: profile.php would show all the posts an user made and under each of their post, they can edit their post. The way I been using it is through $_GETs. So.. //this is the link users click to edit their post echo '<td><a href="editad.php?posting_id='.$row3['posting_id'].' ">Edit</a>'; //on the editad.php $posting_id=$_GET['posting_id']; if (isset($posting_id)){ //show all the forms, sqls to do the editing } else{ //if the $_GET hasn't been set echo "You have not specified which ad to edit. Please go back"; } How do I do this via POST? Thanks :)

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  • best way of printing data

    - by Syom
    for example i want to generate html code, using some data from database. here is two ways of printing data <? echo '<li><img src="'.$row['image'].'" /></li>';?> or <? echo "<li><img src='$row[image]' /></li>";?> both of them are working. and if so, why people use the first method, if without spliting the row by . it works fine too. thanks

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  • PHP Datediff days involved

    - by user3549835
    I need to know how many days are involved in a date diff. \For example: <? $start = new DateTime('2014-06-29 14:00:00'); $ende = new DateTime('2014-07-02 05:45:00'); $diff = $start->diff($ende); echo $diff->format('%R'); echo $diff->days; ?> The above code echos +2 My desired result would be 4, because the 29th, 30th, 1st and 2nd of July are "touched". I have no idea to achieve that with the given functions. Coding a day-subtraction seems to bean open door for errors.

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  • Duplicate array but maintain pointer links

    - by St. John Johnson
    Suppose I have an array of nodes (objects). I need to create a duplicate of this array that I can modify without affecting the source array. But changing the nodes will affect the source nodes. Basically maintaining pointers to the objects instead of duplicating their values. // node(x, y) $array[0] = new node(15, 10); $array[1] = new node(30, -10); $array[2] = new node(-2, 49); // Some sort of copy system $array2 = $array; // Just to show modification to the array doesn't affect the source array array_pop($array2); if (count($array) == count($array2)) echo "Fail"; // Changing the node value should affect the source array $array2[0]->x = 30; if ($array2[0]->x == $array[0]->x) echo "Goal"; What would be the best way to do this?

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  • Syntax problem when checking for a file

    - by Luke
    This piece of code has previously worked but I have C&P it to a new place and for some reason, it now won't work! <? $user_image = '/images/users/' . $_SESSION['id'] . 'a.jpg'; if (file_exists(realpath(dirname(__FILE__) . $user_image))) { echo '<img src="'.$user_image.'" alt="" />'; } else { echo '<img src="/images/users/small.jpg" alt="" />'; } ?> As you can see, I am checking for a file, if exists, showing it, if not, showing a placeholder. The $_SESSION['id'] variable does exist and is being used elsewhere within the script. Any ideas what the problem is? Thanks

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  • How do I Parse the response I get back from CURL?

    - by Daelan
    I'm sending some data to an external URL using Curl. The server sends me back a response in a string like this: trnApproved=0&trnId=10000002&messageId=7&messageText=DECLINE I can assign this string to a variable like this: $txResult = curl_exec( $ch ); echo "Result:<BR>"; echo $txResult; But how do I use the data that is sent back? I need a way to get the value of each variable sent back so that I can use it in my PHP script. Any help would be much appreciated. Thanks.

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  • Accessing object's method within string

    - by Wild One
    Recently I was reading php documentation and found interesting note in string section: Functions, method calls, static class variables, and class constants inside {$} work since PHP 5. However, the value accessed will be interpreted as the name of a variable in the scope in which the string is defined. Using single curly braces ({}) will not work for accessing the return values of functions or methods or the values of class constants or static class variables. See www.php.net/manual/en/language.types.string.php It says, that I can't use curly syntax to get value returned by object's method call. Is it a mistake in manual or I misunderstood it, because I tried the following code and it works just fine: <?php class HelloWorld { public static function hello() { echo 'hello'; } } $a = new HelloWorld(); echo "{$a->hello()} world";

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  • Prolem with if function

    - by Ryan
    Hi, something seems to be wrong with the first line of this if function, seems alright to me though. if ($count1 == sizeof($map) && $count2 == sizeof($map[0])){ echo ";"; }else{ echo ","; } This is the error I get (line 36 is the first line of the above line.) Parse error: parse error in C:\wamp\www\game\mapArrayConvertor.php on line 36 EDIT: The OP notes in an answer below that the error was a missing semi-colon on line 35 and not the code included in the question.

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  • Windows 7 PATH not expanding

    - by trinithis
    I am using the following to create and edit environment variables for Windows 7. Control Panel\All Control Panel Items\System -> Advanced system settings -> Environment Variables Under System variables I have the following pertinant variables: PROG32=C:\Program Files (x86) REALDWG_SDK_DIR=%PROG32%\Autodesk\RealDWG 2011 Path=%REALDWG_SDK_DIR%;%PROG32%\Haskell\bin However, the following happens: C:\>echo %PROG32% C:\Program Files (x86) C:\>echo %Path% %REALDWG_SDK_DIR%;C:\Program Files (x86)\Haskell\bin Is it possible to have a chain of variables expand? If I rename Path to something else, I sometimes get the problem, and sometimes I don't.

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  • PHP: Display comma after each element except the last. Using 'for' statement and no 'implode/explode

    - by Jonathan
    hi, so I have this simple for loop to echo an array: for ($i = 0; $i < count($director); $i++) { echo '<a href="person.php?id='.$director[$i]["id"].'">'.$director[$i]["name"].'</a>'; } The problem here is that when more than one element is in the array then I get everything echoed without any space between. I want to separate each element with a comma except the last one. I cant use 'implode' so I'm looking for another solution... Anyone?

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  • checking the return code using python (MAC)

    - by cyberbemon
    I have written a script that checks if an SVN Repo is up and running, the result is based on the return value. import subprocess url = " validurl" def check_svn_status(): subprocess.call(['svn info'+url],shell=True) def get_status(): subprocess.call('echo $?',shell=True) def main(): check_svn_status() get_status() if __name__ == '__main__': main() The problem I'm facing is that if I change the url to something that does't exist I still get the return value as 0, but if I were to run this outside the script, i.e go to the terminal type svn info wrong url and then do a echo $? I get a return value of 1. But I can't re-create this in the python. Any guidelines ?

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  • Which code snipplets in PHP can create a input form, which creates a new set of data in my mysql dat

    - by smiyazaki
    I am using the Google Maps API with parts in javascript and others in PHP. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> Google Maps AJAX + mySQL/PHP Example // var iconBlue = new GIcon(); iconBlue.image = 'icon.png'; iconBlue.shadow = ''; iconBlue.iconSize = new GSize(19, 19); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'icon.png'; iconRed.shadow = ''; iconRed.iconSize = new GSize(19, 19); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.setMapType(G_SATELLITE_MAP); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); // Change this depending on the name of your PHP file GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> (I suppose the php will be called by "GDownloadUrl("phpsqlajax_genxml.php", function(data) { ..." in the javascript part of the sourcecode of phpsqlajax_map.htm) Now I need another php file and the code snipplets for it, which creates an input form where I can add some new locations to the google map. Following code is used to create the xml file here: http://detektors.de/maptest/phpsqlajax_genxml.php The next step would be, trying to make an plugin for wordpress that I could easily post a blog entry with a new location on the same map, which displays already some other locations stored in the mysql database. thanks! <?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers WHERE 1"; $result = mysql_query($query); if (!$result) { die('Invalid query: ' . mysql_error()); } header("Content-type: text/xml"); // Start XML file, echo parent node echo ''; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo ''; } // End XML file echo ''; ?

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  • CakePHP two forms next to eachother instead of below eachother

    - by Jarno wildenaar
    Im developing an form in cakePHP where i want to set two forms next to eachother. Im creating it using this code. echo $form-input('timeback', array('options' = array('week',1,2,3,))); This creates a dropdown. Followed by this code: echo $form-end('submit'); This all works well, accept that these two forms should be next to eachother instead of below eachother. Is there a way to make this happen? Thanx in advance!

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  • Error - Trying to get property of non-object

    - by Patrick Lanfranco
    I am currently getting this error on one of my files: /var/www/vhosts/httpdocs/generator/index.php on line 6 Line 6 would be resulting in: echo $results->GetBookCodesResult->BookCodes->BookInfo->ServiceCode; My code: <?php $config['soap_url'] = "http://myservice.com?WSDL"; if(isset($_REQUEST['codes'])) { $results = request_Data(explode("\n",$_REQUEST['codes'])); echo $results->GetBookCodesResult->BookCodes->BookInfo->ServiceCode; } .... What is the best method to have this fixed? Some advice would be appreciated.

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  • Javascript function not working with an array

    - by Ryan Harvie
    Hi, i have this function which loops through an array of check boxes checking if the boxes value is equal to something in a text box, i dont know whats wrong. function checkValue(contain) { var boxes = document.getElementsByTagName("input"); for (var i = 0; i < boxes.length; i++) { if (boxes[i].name == "vote[]") { if (boxes[i].value.indexOf(contain.value) != -1) { boxes[i].checked = true; } } } } and this is how i call it OnClick="uncheckAll(); checkValue(document.getElementsByName("countrylist"));" this code is in side a echo in php which is like this echo ' ';

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  • What's wrong with my If-statement to check uploaded file? (PHP)

    - by ggfan
    I am trying to test if the uploaded file is the image type I want. If it isn't a gif,jpeg, png, it should echo "Problem". But when I execute this code, it always says there's a problem. What's wrong with my if statement? $uploadfile_type=$_FILES['userfile']['type']; if ( ($uploadfile_type !='image/gif') || ($uploadfile_type !='image/jpeg') || ($uploadfile_type !='image/png')) { echo 'Problem: file is not a gif or jpeg or png!'; exit; } This code works when I am only checking one type of image. Ex: if($uploadfile_type !='image/gif') -- this statement would work but when I add a OR it doesn't.

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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