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  • Is it possible for a parent to use a child's constant or static variables from inside a static metho

    - by ryeguy
    Below is an example of what I'm trying to do. The parent can't access any of the child's variables. It doesn't matter what technique I use (static or constants), I just need some kind of functionality like this. class ParentClass { public static function staticFunc() { //both of these will throw a (static|const) not defined error echo self::$myStatic; echo self::MY_CONSTANT; } } class ChildClass extends ParentClass { const MY_CONSTANT = 1; public static $myStatic = 2; } ChildClass::staticFunc();

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  • What is the difference between "render a view" and send the response using the Response's method "sendResponse()"?

    - by Green
    I've asked a question about what is "rendering a view". Got some answers: Rendering a view means showing up a View eg html part to user or browser. and So by rendering a view, the MVC framework has handled the data in the controller and done the backend work in the model, and then sends that data to the View to be output to the user. and render just means to emit. To print. To echo. To write to some source (probably stdout). but don't understand then the difference between rendering a view and using the Response class to send the output to the user using its sendResponse() method. If render a view means to echo the output to the user then why sendResponse() exists and vise versa? sendResponse() exactly sends headers and after headers outputs the body. They solve the same tasks but differently? What is the difference?

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  • PHP: Display comma after each element except the last. Using 'for' statement and no 'implode/explode

    - by Jonathan
    hi, so I have this simple for loop to echo an array: for ($i = 0; $i < count($director); $i++) { echo '<a href="person.php?id='.$director[$i]["id"].'">'.$director[$i]["name"].'</a>'; } The problem here is that when more than one element is in the array then I get everything echoed without any space between. I want to separate each element with a comma except the last one. I cant use 'implode' so I'm looking for another solution... Anyone?

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  • Prolem with if function

    - by Ryan
    Hi, something seems to be wrong with the first line of this if function, seems alright to me though. if ($count1 == sizeof($map) && $count2 == sizeof($map[0])){ echo ";"; }else{ echo ","; } This is the error I get (line 36 is the first line of the above line.) Parse error: parse error in C:\wamp\www\game\mapArrayConvertor.php on line 36 EDIT: The OP notes in an answer below that the error was a missing semi-colon on line 35 and not the code included in the question.

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  • What's wrong with my If-statement to check uploaded file? (PHP)

    - by ggfan
    I am trying to test if the uploaded file is the image type I want. If it isn't a gif,jpeg, png, it should echo "Problem". But when I execute this code, it always says there's a problem. What's wrong with my if statement? $uploadfile_type=$_FILES['userfile']['type']; if ( ($uploadfile_type !='image/gif') || ($uploadfile_type !='image/jpeg') || ($uploadfile_type !='image/png')) { echo 'Problem: file is not a gif or jpeg or png!'; exit; } This code works when I am only checking one type of image. Ex: if($uploadfile_type !='image/gif') -- this statement would work but when I add a OR it doesn't.

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  • how to make PHP lists all Linux Users?

    - by Data-Base
    Hello I want to build a php based site that (automate) some commands on my Ubuntu Server first thing I did was going to the file (sudoers) and add the user www-data so I can execute php commands with root privileges! # running the web apps with root power!!! www-data ALL=(ALL) NOPASSWD: ALL then my PHP code was <?php $command = "cat /etc/passwd | cut -d\":\" -f1"; echo 'running the command: <b>'.$command."</b><br />"; echo exec($command); ?> it returns only one user (the last user) !!! how to make it return all users? thank you

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  • How to setup a mail server on Mac OS X 10.7.4?

    - by 0x90
    I am working in PHP and I have mamp on my machine. I would like to send emails from my PHP code, like this: <?php $to = "[email protected]"; $subject = "Hi!"; $body = "Hi,\n\nHow are you?"; if (mail($to, $subject, $body)) { echo("<p>Message successfully sent!</p>"); } else { echo("<p>Message delivery failed...</p>"); } ?> How can I configure a mail server for free on my machine?

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • need to loop through a PHP array in JavaScript

    - by user296516
    Hi guys, For example I have a PHP array, such as this one <?php $s= array('a','b','c','d','e','f') ; ?> And I need to loop through it in JavaScript, any ideas how do I do that? for ( i=0 ; i < <?php echo sizeof($s) ?> ; i++) { document.write('<?php echo $s [somehow need to get the 'i' value into here] ?>'); } Any suggestions? Thanks!

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  • Deprecated: Function eregi() is deprecated, how to solve this error ?

    - by Jitendra Vyas
    I'm using this php code. but it's giving error Deprecated: Function eregi() is deprecated in C:\xampp\htdocs\fuel\emailcheck.php on line 7 <? include_once("mastersecure.php"); $emailcheck=$_POST["member_name"]; function isValidEmail($email){ $pattern = "^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$"; if (eregi($pattern, $email)){ return true; } else { return false; } } if (!isValidEmail($_POST['member_name'])){ echo "The email is invalid!"; } else { $query="select email from fuel where email='$_POST[member_name]'"; $res=mysql_query($query); $rowcount=mysql_num_rows($res); if($rowcount!=0) { echo "This mail is already exits"; } } ?> Any solution for this?

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  • php/mySQL error: mysql_num_rows(): supplied argument is not a valid MySQL result

    - by Michael Robinson
    I'm trying to INSERT INTO a mySQL database and I'm getting this error on: if (mysql_num_rows($login) == 1){ Here is the php, The php does add the user to the database. I can't figure it out. <? session_start(); require("config.php"); $u = $_GET['username']; $pw = $_GET['password']; $pwh = $_GET['passwordhint']; $em = $_GET['email']; $zc = $_GET['zipcode']; $check = "INSERT INTO family (loginName, email, password, passwordhint, location) VALUES ('$u', '$pw', '$pwh', '$em', '$zc')"; $login = mysql_query($check, $link) or die(mysql_error()); if (mysql_num_rows($login) == 1) { $row = mysql_fetch_assoc($login); echo 'Yes';exit; } else { echo 'No';exit; } mysql_close($link); ?> Thanks,

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  • How to send mail using PHP?

    - by phpaddict
    I'm using Windows Vista OS. PHP, MySQL as the database and Apache web server. I want to send notification to those who want to join in my site. But the problem is when I click submit. It doesn't send anything to the email address of the user. What to do you think is the best solution for this? <?php $to = "[email protected]"; $subject = "Hi!"; $body = "Hi,\n\nHow are you?"; if (mail($to, $subject, $body)) { echo("<p>Message successfully sent!</p>"); } else { echo("<p>Message delivery failed...</p>"); } ?>

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  • How place a link below a picture that is displayed using fancybox (jquery)?

    - by janoChen
    In the first picture of my website (the two persons), shows an URL address when you click on it. I used the "title" thing. Is there a simple way of doing the same but placing a link instead? code: <div class="pusher"> <h3><?php echo l('showcase1_h3'); ?></h3> <p><?php echo l('showcase1_p'); ?></p> <div class="pic"> <a id="showcase1" title="studyatbest.com" href="images/showcase1.png"><img src="images/showcase1t.png"/></a> </div> </div> http://alexchen.co.nr/

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  • list of all commits SHA1_HASH

    - by dorelal
    git init echo 'I am foo' > foo.txt git add foo.txt # this woould create a git commit object echo ' I am foo2' > foo.txt git add foo.txt # this would create another git commit object git commit -m 'doe' # this would create two git # objects: one commit object and one tree object How do I get a list of all 4 commits SHA1_HASH ? cd .git/objects ls (master)$ ls -al total 0 drwxr-xr-x 8 nsingh staff 272 Mar 27 16:44 . drwxr-xr-x 13 nsingh staff 442 Mar 27 16:44 .. drwxr-xr-x 3 nsingh staff 102 Mar 27 16:44 37 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:43 a2 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:44 e1 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:42 e6 drwxr-xr-x 2 nsingh staff 68 Mar 27 16:42 info drwxr-xr-x 2 nsingh staff 68 Mar 27 16:42 pack I can find the list of all 4 commits by looking at file here but there must be a better way.

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  • Weird "?>" being displayed

    - by Jaxkr
    I have the following navigation bar script: <?php session_start(); require('includepath.inc.php'); require($include_path.'loginsysfunc.inc.php'); $current_page = $_SERVER['REQUEST_URI']; ?> <div class="navbar"> <img class="navlogo" src="logo.png"> <div class="navbutton"><a href="index.php">Home</a></div> <div class="navbutton"><a href="about.php">About</a></div> <div class="navbutton"><a href="donate.php">Donate</a></div> <?php if (loggedIn()){ ?> <div class="navusername"><a href="profile.php?user=<?php echo $_SESSION['username'];?>"><?php echo $_SESSION['username']; ?></a></div> <div class="navtoolsettings"><a href="settings.php">Settings</a></div> <div class="navtoollogout"><a href="logout.php">Log out</a> <?php } elseif ($current_page == '/login.php') { ?> <div class="navregister"><a href="register.php">Register</a></div> <?php } else { ?> <div class="navusername"><a href="login.php">Log in</a></div> <?php } ?> </div> For some reason, a strange "?" is being displayed. I am super confused, so please help. Here is includepath.inc.php (the only I reason it's there is because I am on a shared host, and I don't want to type '/home/bigdumbhash/public_html/include' everytime. But, here it is: <?php $include_path = '/home/a6595899/public_html/include/'; ?> Here is loginsysfunc.inc.php. These are functions that go with my login system to save time: <?php function valUser() { session_regenerate_id(); $_SESSION['valid'] = true; $_SESSION['username'] = $userid; echo '<meta http-equiv="refresh" content="0;URL=\'index.php\'">'; } function loggedIn() { if($_SESSION['valid'] == true) { return true; } else { return false; } } function createSalt() { $string = $string = md5(uniqid(rand(), true)); return substr($string, 0, 3); } function logout() { $_SESSION = array(); session_destroy(); echo '<meta http-equiv="refresh" content="0;URL=\'index.php\'">'; } ?> Here is the actual HTML of the page: <!DOCTYPE html> <html> <head> <link href="style.css" rel="stylesheet" type="text/css"> <title> Log in </title> </head> <body> <div class="navbar"> <img class="navlogo" src="logo.png"> <div class="navbutton"><a href="index.php">Home</a></div> <div class="navbutton"><a href="about.php">About</a></div> <div class="navbutton"><a href="donate.php">Donate</a></div> <div class="navregister"><a href="register.php">Register</a></div> </div> ?> <div class="loginbox"> <h1>Log in</h1> <form action="logingo.php" method="POST"> <input class="userpass" type="text" name="username" value="Username" onFocus="this.value='';"> <br> <input class="userpass" type="password" name="password" value="Password" onFocus="this.value='';"> <br> <input class="loginbutton" type="submit" value="Log in!"> </form> </div> </body> </html>

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  • Access a static variable by $var::$reference

    - by chuckg
    I am trying to access a static variable within a class by using a variable class name. I'm aware that in order to access a function within the class, you use call_user_func(): class foo { function bar() { echo 'hi'; } } $class = "foo"; all_user_func(array($class, 'bar')); // prints hi However, this does not work when trying to access a static variable within the class: class foo { public static $bar = 'hi'; } $class = "foo"; call_user_func(array($class, 'bar')); // nothing echo $foo::$bar; // invalid How do I get at this variable? Is it even possible? I have a bad feeling this is only available in PHP 5.3 going forward and I'm running PHP 5.2.6. Thanks.

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  • need the right way to setcookie in wordpress

    - by jq beginner
    i've been looking the whole day how to setcookies in wordpress. in my way i found out (using the developer toolbar) that the cookie is set but still not working. i have 2 files the first contains the login form redirecting to another page to set the cookie and return to another page to check if it's working. domain which is tested on is like this : blog.mydomain.com. here's the setcookie file : <?php setcookie("user_name","test",time()+3600); ?> and chcking the cookie like this : if(isset($_COOKIE["user_name"])){ echo "cookie exists"; } else{ echo "cookie doesn't exist"; } i've read many topics about this issue but there was no clear answer. Thanks in advance

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  • Why does this PHP program not work?

    - by oncode
    I'm new to PHP and was learning about PHP functions from w3schools. It said PHP allows a function call to be made when the function name is in a variable: This program worked <?php $v = "var_dump"; $v('foo'); ?> But this program did not work: <?php $v = "echo"; $v('foo'); ?> But if I do echo('foo'); it works. What am I doing wrong?

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  • In PHP: How to call a $variable inside one function that was defined previously inside another funct

    - by Sam
    I'm just starting with Object Oriented PHP and I have the following issue: I have a class that contains a function that contains a certain script. I need to call a variable located in that script within another function further down the same class. For example: class helloWorld { function sayHello() { echo "Hello"; $var = "World"; } function sayWorld() { echo $var; } } in the above example I want to call $var which is a variable that was defined inside a previous function. This doesn't work though, so how can I do this?

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  • php time 2 hours wrong for only 50% some users

    - by user1797802
    I am having huge issues with php time. For some reason it shows a different time (by 2 hours) to some users and the correct time to other users. The code is H:i:s d-M-y T when I view the page in a browser from my PC it tells me its 11am when infact its 9am, when I check via a browser using one my RDP's I get the correct time. Both PC's are in the country (uk) both PC's have the same system time etc. Tried setting the timezone default, but no matter what I do the server still shows some users the correct time, and other users the time 2 hour forward, any ideas? the code is echo gmdate("H:i:s d-M-y T"); <?php echo gmdate("H:i:s d-M-y T"); ?>

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  • PHP_AUTH_USER only known in certain frames

    - by Rob
    Getting very confused by PHP_AUTH_USER. Within my web pages I have .htaccess files in every directory, controlling who can (and cant) see certain folders. In order to further customise the pages I was hoping to use PHP_AUTH_USER within the PHP code, i.e. tailor page contents based on the user. This only seems to work partially. The code snippets below hopefully demonstrate my problems. The main index.php creates a framed page with a menu structure in the top left hand corners, some irrelvant stuff in top right and then the tailor made contents in bottom frame. In top left the user is correctly shown, but in the bottom frame PHP_AUTH_USER doesnt seem to be set anymore (it returns empty and when printing all $HTTP_SERVER_VARS its not listed). Script.php is in a different path, but they all have .htaccess files in them and all other contents is displayed correctly. Why does it not know about PHP_AUTH_USER there? Running version php version 5.2.12 on chrome. index.php <FRAMESET ROWS="35%, *"> <FRAMESET COLS="25%, *"> <FRAME SRC="Menu.php"> <FRAME SRC="Something.php"> </FRAMESET> <FRAME SRC="../OtherPath/Script.php?large=1" name="outputlisting"> </FRAMESET> </FRAMESET> Menu.php <ul> <li>Reporting <ul> <li>Link1 <a href="../OtherPath/Script.php" target="outputlisting">All</a>, <a href="../OtherPath/Script.php?large=1" target="outputlisting">Big</a> </ul> <?php echo 'IP Address: ' . $_SERVER['REMOTE_ADDR'] . '<br />'; echo 'User: ' . $_SERVER['PHP_AUTH_USER']; ?> Script.php <?php echo 'User: ' . $_SERVER['PHP_AUTH_USER']; ?>

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  • PHP strange issue with memcache

    - by Industrial
    Hi everyone, I am testing out some memcache code here in PHP: 1: $testInstance = new Memcache; $var = @$testInstance->connect('localhost', 11211); echo $var; // Outputs true no matter if the memcached is running or not. 2: $testInstance = new Memcache; $var = @$testInstance->connect('blablabla', 11211); echo $var; // Outputs false Why on earth is this occuring? I am running WinXP in my development environment and I cant see how the localhost version always returns true no matter if the memcached is running or not. Thanks!

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