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  • Deprecated: Function eregi() is deprecated, how to solve this error ?

    - by Jitendra Vyas
    I'm using this php code. but it's giving error Deprecated: Function eregi() is deprecated in C:\xampp\htdocs\fuel\emailcheck.php on line 7 <? include_once("mastersecure.php"); $emailcheck=$_POST["member_name"]; function isValidEmail($email){ $pattern = "^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$"; if (eregi($pattern, $email)){ return true; } else { return false; } } if (!isValidEmail($_POST['member_name'])){ echo "The email is invalid!"; } else { $query="select email from fuel where email='$_POST[member_name]'"; $res=mysql_query($query); $rowcount=mysql_num_rows($res); if($rowcount!=0) { echo "This mail is already exits"; } } ?> Any solution for this?

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  • What's wrong with my If-statement to check uploaded file? (PHP)

    - by ggfan
    I am trying to test if the uploaded file is the image type I want. If it isn't a gif,jpeg, png, it should echo "Problem". But when I execute this code, it always says there's a problem. What's wrong with my if statement? $uploadfile_type=$_FILES['userfile']['type']; if ( ($uploadfile_type !='image/gif') || ($uploadfile_type !='image/jpeg') || ($uploadfile_type !='image/png')) { echo 'Problem: file is not a gif or jpeg or png!'; exit; } This code works when I am only checking one type of image. Ex: if($uploadfile_type !='image/gif') -- this statement would work but when I add a OR it doesn't.

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  • PHP Magento get customers last order total

    - by simian
    I am working outside of magento store root folder (1.4) and I would like to get customers order totals, and date of last order. I have started with this: $customer = Mage::getModel('customer/customer')->load($entity_id); $customerTotals =Mage::getResourceModel('sales/sale_collection') ->setCustomerFilter($customer) ->load() ->getTotals(); echo $customerTotals->getNumOrders(); echo money_format('$%i',$customerTotals->getLifetime()); This seems to be giving me totals from the wrong customer... Also, can't quite figure out how to get customers last order day. any help would be appreciated.

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  • how to make PHP lists all Linux Users?

    - by Data-Base
    Hello I want to build a php based site that (automate) some commands on my Ubuntu Server first thing I did was going to the file (sudoers) and add the user www-data so I can execute php commands with root privileges! # running the web apps with root power!!! www-data ALL=(ALL) NOPASSWD: ALL then my PHP code was <?php $command = "cat /etc/passwd | cut -d\":\" -f1"; echo 'running the command: <b>'.$command."</b><br />"; echo exec($command); ?> it returns only one user (the last user) !!! how to make it return all users? thank you

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  • php/mySQL error: mysql_num_rows(): supplied argument is not a valid MySQL result

    - by Michael Robinson
    I'm trying to INSERT INTO a mySQL database and I'm getting this error on: if (mysql_num_rows($login) == 1){ Here is the php, The php does add the user to the database. I can't figure it out. <? session_start(); require("config.php"); $u = $_GET['username']; $pw = $_GET['password']; $pwh = $_GET['passwordhint']; $em = $_GET['email']; $zc = $_GET['zipcode']; $check = "INSERT INTO family (loginName, email, password, passwordhint, location) VALUES ('$u', '$pw', '$pwh', '$em', '$zc')"; $login = mysql_query($check, $link) or die(mysql_error()); if (mysql_num_rows($login) == 1) { $row = mysql_fetch_assoc($login); echo 'Yes';exit; } else { echo 'No';exit; } mysql_close($link); ?> Thanks,

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  • need to loop through a PHP array in JavaScript

    - by user296516
    Hi guys, For example I have a PHP array, such as this one <?php $s= array('a','b','c','d','e','f') ; ?> And I need to loop through it in JavaScript, any ideas how do I do that? for ( i=0 ; i < <?php echo sizeof($s) ?> ; i++) { document.write('<?php echo $s [somehow need to get the 'i' value into here] ?>'); } Any suggestions? Thanks!

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  • How to avoid my script to freeze

    - by jemz
    I have socket server script that continuously running listening for the GPS device that runs in PHP CLI,my problem is that my socket will freeze if it executes long time,how do I prevent this so that my script will not freeze.I have no idea on this socket.this is the first time that I use socket connection. I appreciate someone can help my problem. <?php error_reporting(-1); ini_set('display_errors', 1); set_time_limit (0); $address_server = 'xxx.xxx.xx.xx'; $port_server = xxxx; $isTrue = true; socketfunction($address_server,$port_server,$isTrue); function socketfunction($address,$port,$done){ $sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP); socket_set_option($sock, SOL_SOCKET, SO_REUSEADDR, 1); socket_bind($sock, $address, $port); socket_listen($sock); $clients = array($sock); while ($done ) { $file = fopen('txt.log','a'); $read = $clients; $write = NULL; $except = NULL; $tv_sec = 0; if (socket_select($read, $write , $except, $tv_sec) < 1){ continue; } // checking client if (in_array($sock, $read)) { $clients[] = $newsock = socket_accept($sock); $key = array_search($sock, $read); unset($read[$key]); } //handle client for reading foreach ($read as $read_sock) { $data = @socket_read($read_sock, 1024, PHP_NORMAL_READ); if ($data === false) { $key = array_search($read_sock, $clients); unset($clients[$key]); echo "client disconnected.\n"; echo "Remaining ".(count($clients) - 1)."client(s) connected\r\n"; continue; } $data = trim($data); if (!empty($data)) { echo("Returning stripped input\n"); fwrite($file,$data."\n"); } } // end of reading foreach fclose($file); }//end while socket_close($sock); } ?> Thank you in advance.

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  • list of all commits SHA1_HASH

    - by dorelal
    git init echo 'I am foo' > foo.txt git add foo.txt # this woould create a git commit object echo ' I am foo2' > foo.txt git add foo.txt # this would create another git commit object git commit -m 'doe' # this would create two git # objects: one commit object and one tree object How do I get a list of all 4 commits SHA1_HASH ? cd .git/objects ls (master)$ ls -al total 0 drwxr-xr-x 8 nsingh staff 272 Mar 27 16:44 . drwxr-xr-x 13 nsingh staff 442 Mar 27 16:44 .. drwxr-xr-x 3 nsingh staff 102 Mar 27 16:44 37 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:43 a2 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:44 e1 drwxr-xr-x 3 nsingh staff 102 Mar 27 16:42 e6 drwxr-xr-x 2 nsingh staff 68 Mar 27 16:42 info drwxr-xr-x 2 nsingh staff 68 Mar 27 16:42 pack I can find the list of all 4 commits by looking at file here but there must be a better way.

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  • How to send mail using PHP?

    - by phpaddict
    I'm using Windows Vista OS. PHP, MySQL as the database and Apache web server. I want to send notification to those who want to join in my site. But the problem is when I click submit. It doesn't send anything to the email address of the user. What to do you think is the best solution for this? <?php $to = "[email protected]"; $subject = "Hi!"; $body = "Hi,\n\nHow are you?"; if (mail($to, $subject, $body)) { echo("<p>Message successfully sent!</p>"); } else { echo("<p>Message delivery failed...</p>"); } ?>

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  • How to setup a mail server on Mac OS X 10.7.4?

    - by 0x90
    I am working in PHP and I have mamp on my machine. I would like to send emails from my PHP code, like this: <?php $to = "[email protected]"; $subject = "Hi!"; $body = "Hi,\n\nHow are you?"; if (mail($to, $subject, $body)) { echo("<p>Message successfully sent!</p>"); } else { echo("<p>Message delivery failed...</p>"); } ?> How can I configure a mail server for free on my machine?

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  • What is the difference between "render a view" and send the response using the Response's method "sendResponse()"?

    - by Green
    I've asked a question about what is "rendering a view". Got some answers: Rendering a view means showing up a View eg html part to user or browser. and So by rendering a view, the MVC framework has handled the data in the controller and done the backend work in the model, and then sends that data to the View to be output to the user. and render just means to emit. To print. To echo. To write to some source (probably stdout). but don't understand then the difference between rendering a view and using the Response class to send the output to the user using its sendResponse() method. If render a view means to echo the output to the user then why sendResponse() exists and vise versa? sendResponse() exactly sends headers and after headers outputs the body. They solve the same tasks but differently? What is the difference?

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  • Getting an Ajax response from Zend Framework Controller

    - by JavaLava
    I'm doing an Ajax request on one of my views to a Controller but I am unable to send back a response to the Ajax method. In the snippet below, I am trying to send the word 'hellopanda' back but in the alert message, I'll get data as an object. View : $.ajax({ type: "POST", url: "localhost/some-activity", data: dataString, success: function(data) { alert( "Data is: " + data); //do something with data }, error: function(data){ alert( "Data is: " + data); //do something with data }, onComplete: function(){ } }); Controller: public function someActivityAction(){ //do stuff echo "hellopanda"; } I'm pretty sure the echo is the problem. Any insights on to how to do a proper response to the view would be greatly appreciated.

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  • How place a link below a picture that is displayed using fancybox (jquery)?

    - by janoChen
    In the first picture of my website (the two persons), shows an URL address when you click on it. I used the "title" thing. Is there a simple way of doing the same but placing a link instead? code: <div class="pusher"> <h3><?php echo l('showcase1_h3'); ?></h3> <p><?php echo l('showcase1_p'); ?></p> <div class="pic"> <a id="showcase1" title="studyatbest.com" href="images/showcase1.png"><img src="images/showcase1t.png"/></a> </div> </div> http://alexchen.co.nr/

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  • PHP Variable Passing in Foreach on same page

    - by tooly228
    I've been struggling this for a while and I simply can't figure this out. Here is my code: <?php foreach($list as $id =>$name) { echo("<td style=\"vertical-align:middle;\"> <a href=\"item=$id#confirm\" role=\"button\" data-toggle=\"modal\"> Buy</a></td></tr>"); }?> <html> <div class="modal small hide fade" id="confirm" tabindex="-1" role="dialog" aria- labelledby="myModalLabel" aria-hidden="true"> <a href="redeem.php?item=<?php echo $id; ?>"><button class="btn btn-danger"> Buy</button></a></div> The main issue here is that the $id from the foreeach is not the same as the $id in the div class link. Instead the link is the end value of the foreach list.

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  • Access a static variable by $var::$reference

    - by chuckg
    I am trying to access a static variable within a class by using a variable class name. I'm aware that in order to access a function within the class, you use call_user_func(): class foo { function bar() { echo 'hi'; } } $class = "foo"; all_user_func(array($class, 'bar')); // prints hi However, this does not work when trying to access a static variable within the class: class foo { public static $bar = 'hi'; } $class = "foo"; call_user_func(array($class, 'bar')); // nothing echo $foo::$bar; // invalid How do I get at this variable? Is it even possible? I have a bad feeling this is only available in PHP 5.3 going forward and I'm running PHP 5.2.6. Thanks.

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  • PHP_AUTH_USER only known in certain frames

    - by Rob
    Getting very confused by PHP_AUTH_USER. Within my web pages I have .htaccess files in every directory, controlling who can (and cant) see certain folders. In order to further customise the pages I was hoping to use PHP_AUTH_USER within the PHP code, i.e. tailor page contents based on the user. This only seems to work partially. The code snippets below hopefully demonstrate my problems. The main index.php creates a framed page with a menu structure in the top left hand corners, some irrelvant stuff in top right and then the tailor made contents in bottom frame. In top left the user is correctly shown, but in the bottom frame PHP_AUTH_USER doesnt seem to be set anymore (it returns empty and when printing all $HTTP_SERVER_VARS its not listed). Script.php is in a different path, but they all have .htaccess files in them and all other contents is displayed correctly. Why does it not know about PHP_AUTH_USER there? Running version php version 5.2.12 on chrome. index.php <FRAMESET ROWS="35%, *"> <FRAMESET COLS="25%, *"> <FRAME SRC="Menu.php"> <FRAME SRC="Something.php"> </FRAMESET> <FRAME SRC="../OtherPath/Script.php?large=1" name="outputlisting"> </FRAMESET> </FRAMESET> Menu.php <ul> <li>Reporting <ul> <li>Link1 <a href="../OtherPath/Script.php" target="outputlisting">All</a>, <a href="../OtherPath/Script.php?large=1" target="outputlisting">Big</a> </ul> <?php echo 'IP Address: ' . $_SERVER['REMOTE_ADDR'] . '<br />'; echo 'User: ' . $_SERVER['PHP_AUTH_USER']; ?> Script.php <?php echo 'User: ' . $_SERVER['PHP_AUTH_USER']; ?>

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  • Elegant way to search for UTF-8 files with BOM?

    - by vog
    For debugging purposes, I need to recursively search a directory for all files which start with a UTF-8 byte order mark (BOM). My current solution is a simple shell script: find -type f | while read file do if [ "`head -c 3 -- "$file"`" == $'\xef\xbb\xbf' ] then echo "found BOM in: $file" fi done Or, if you prefer short, unreadable one-liners: find -type f|while read file;do [ "`head -c3 -- "$file"`" == $'\xef\xbb\xbf' ] && echo "found BOM in: $file";done It doesn't work with filenames that contain a line break, but such files are not to be expected anyway. Is there any shorter or more elegant solution? Are there any interesting text editors or macros for text editors?

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  • Creating an array from a MySQL table

    - by Rob
    I'm trying to create an array to use for a curl_multi_exec, but I can't seem to create the array properly. Here is my code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the shell table while($resultSet = mysql_fetch_array($SQL)){ $urls[]=$resultSet; } echo $urls; //Test that the array works But when I run this script, all it does is echo "Array" I have no idea what I'm doing wrong, I've checked around google a bit, but can't figure it out. Any insight would be appreciated.

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  • In PHP: How to call a $variable inside one function that was defined previously inside another funct

    - by Sam
    I'm just starting with Object Oriented PHP and I have the following issue: I have a class that contains a function that contains a certain script. I need to call a variable located in that script within another function further down the same class. For example: class helloWorld { function sayHello() { echo "Hello"; $var = "World"; } function sayWorld() { echo $var; } } in the above example I want to call $var which is a variable that was defined inside a previous function. This doesn't work though, so how can I do this?

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  • Why does this PHP program not work?

    - by oncode
    I'm new to PHP and was learning about PHP functions from w3schools. It said PHP allows a function call to be made when the function name is in a variable: This program worked <?php $v = "var_dump"; $v('foo'); ?> But this program did not work: <?php $v = "echo"; $v('foo'); ?> But if I do echo('foo'); it works. What am I doing wrong?

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  • Does certain tags we write in PHP affects the performance of the live server???

    - by Sachindra
    I have written some tags in PHP as <a href="<?php bloginfo('url'); ?>/?cat=<?php $cate_id ?>"><?php echo $resid->post_content ?></a> or even this one echo "<li><a href = '?cat=$cate_id'>".$resid->post_content."</a></li>";?> Does this in any case affect the performance on the live server. I am no getting the image to appear on the live server after upload but on my local system(on my side) , things are fine..

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  • Weird "?>" being displayed

    - by Jaxkr
    I have the following navigation bar script: <?php session_start(); require('includepath.inc.php'); require($include_path.'loginsysfunc.inc.php'); $current_page = $_SERVER['REQUEST_URI']; ?> <div class="navbar"> <img class="navlogo" src="logo.png"> <div class="navbutton"><a href="index.php">Home</a></div> <div class="navbutton"><a href="about.php">About</a></div> <div class="navbutton"><a href="donate.php">Donate</a></div> <?php if (loggedIn()){ ?> <div class="navusername"><a href="profile.php?user=<?php echo $_SESSION['username'];?>"><?php echo $_SESSION['username']; ?></a></div> <div class="navtoolsettings"><a href="settings.php">Settings</a></div> <div class="navtoollogout"><a href="logout.php">Log out</a> <?php } elseif ($current_page == '/login.php') { ?> <div class="navregister"><a href="register.php">Register</a></div> <?php } else { ?> <div class="navusername"><a href="login.php">Log in</a></div> <?php } ?> </div> For some reason, a strange "?" is being displayed. I am super confused, so please help. Here is includepath.inc.php (the only I reason it's there is because I am on a shared host, and I don't want to type '/home/bigdumbhash/public_html/include' everytime. But, here it is: <?php $include_path = '/home/a6595899/public_html/include/'; ?> Here is loginsysfunc.inc.php. These are functions that go with my login system to save time: <?php function valUser() { session_regenerate_id(); $_SESSION['valid'] = true; $_SESSION['username'] = $userid; echo '<meta http-equiv="refresh" content="0;URL=\'index.php\'">'; } function loggedIn() { if($_SESSION['valid'] == true) { return true; } else { return false; } } function createSalt() { $string = $string = md5(uniqid(rand(), true)); return substr($string, 0, 3); } function logout() { $_SESSION = array(); session_destroy(); echo '<meta http-equiv="refresh" content="0;URL=\'index.php\'">'; } ?> Here is the actual HTML of the page: <!DOCTYPE html> <html> <head> <link href="style.css" rel="stylesheet" type="text/css"> <title> Log in </title> </head> <body> <div class="navbar"> <img class="navlogo" src="logo.png"> <div class="navbutton"><a href="index.php">Home</a></div> <div class="navbutton"><a href="about.php">About</a></div> <div class="navbutton"><a href="donate.php">Donate</a></div> <div class="navregister"><a href="register.php">Register</a></div> </div> ?> <div class="loginbox"> <h1>Log in</h1> <form action="logingo.php" method="POST"> <input class="userpass" type="text" name="username" value="Username" onFocus="this.value='';"> <br> <input class="userpass" type="password" name="password" value="Password" onFocus="this.value='';"> <br> <input class="loginbutton" type="submit" value="Log in!"> </form> </div> </body> </html>

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