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• Whats the regular expression for finding string between " "

  - by chitresh

  Hi all, I have a string as below: "http:172.1." = (10, 1,3); "http:192.168." = (15, 2,6); "http:192.168.1.100" = (1, 2,8); The string inside " " is a Tag and inside () is the value for preceding tag. What is the regular expression that will return me: Tag: http:172.1. Value: 10, 1,3

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• Apply a class to a <h1> based on the site url

  - by user1870639

  I'm new to PHP and want to apply a specific class to the title of my page depending on what part of the site the viewer is browsing. For instance, I want to apply the class "blog" to the if the viewer is at domain.com/blog OR domain.com/blog/post-1 so on and so forth BUT apply the class "pics" if they're viewing domain.com/pics or domain.com/pics/gallery-1 etc etc. I found something that could be modified to serve my needs using javascript here but I figured seeing as I'm using PHP already, it'd make more sense to keep this sort of thing server side. As I say, I'm new to PHP. I've experimented with some regular expressions, but to no avail.

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• How can I handle validation of non-latin script input in PHP?

  - by Matt

  I am trying to adapt a php application to handle non-latin scripts (specifically: Japanese, simplified Chinese and Arabic). The app's data validation routines make frequent use of regular expressions to check input, but I am not sure how to adapt the \w character type to other languages without installing additional locales on the system (which I cannot rely on). Previous developers to have worked on the app have simply added needed characters to the regexes as the number of languages we supported grew (you frequently see "[\wÀÁÂÃÄÅÆÇÈÉ... etc" in the code), but I can't really do this for all the alphabets I need to support now. Does anybody out there have some advice on how to tackle this?

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• Regular expression using + problem in js

  - by Karthik

  I am using regular expression. In phone validation, i have to use the "+" sign in that. How to provide the + sign in regular expression. Because + sign indicates one or more of preceding character(s). Whether i will provide like this + ?

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• A regular expression question

  - by Hellnar

  Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

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• How to strip everything between a key phrase and an ending tag?

  - by user3620142

  I am trying to strip everything between a key phrase and ending tag but for some reason it is not working. I always get blank data. I've tried many different ways but no luck. Basically I have a script that connect to IMAP and store emails into MySQL as service tickets. It works great but I am trying to strip off everything except for user reply because currently if a user reply to an email it re-inserts the entire email into MySQL. I added a key phrase at the top of all outgoing emails . Structure is as below: --Reply below this line to respond-- ------------------------------------------------------------------------------------ Email body message... When replying to the message, it becomes: New Message reply...... --Reply below this line to respond-- old message body. I would only like to insert the new reply message only. This is what I've got so far: $message = strip_tags($message, "<br><div><p><u><hr></section>"); $message=preg_replace("</p>", "br /", $message); $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); $message=clean("<br/><hr><u>Received On $rep_date / $from_email</u><br><br/>$message"); It inserts the Received On date and From but $message is blank. If I remove $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); it inserts the entire email. Any suggestion on what i am doing wrong?

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• Is it possible to use a back reference to specify the number of replications in a regular expression

  - by user307894

  Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

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• extracting multiple fields from a text file using php

  - by Dave

  Hi, what is the best way of extracting multiple (~40 values) from a text file using php? the data is more or less like: NAMEA valuea NAMEB valueb I'm looking for a proper* approach to extracting this data into a data-structure, because i will need to specify regexs for all of them (all 40). did i make myself clear? *meaning, the default/painful method would be for me to do: $namea = extractfunction("regexa", $textfilevalue); $nameb = extractfunction("regeb", $textfilevalue); ... 40 times!

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• How do I .MatchCase and .WholeWord?

  - by Tanner

  Hello, Ive been making a find, find next function for my richtextbox, so I have these check boxes to let the user search by whole word or case sensitive or both, and I got the first two, to work but I can't get it to work with both case a whole word checked, here's my code: if (isWhole == true && isCase == true) { string searchText = Form2.text; this.Focus(); richTextBox1.Focus(); findPos = richTextBox1.Find(searchText,findPos,richTextBox1.Text.Length, RichTextBoxFinds.WhatGoesHere?); richTextBox1.Select(findPos, searchText.Length); findPos += searchText.Length; } But there's no option for wholeword and matchcase so is there any way to do this with .Find()?

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• Notepad++ regular expression find and replace $_REQUEST with $_GET but a more secure

  - by David

  What I am doing is replacing, in a large program, all $_REQUEST['var'] and mysql_escape_string($_REQUEST['var']) with either the 1st or 2nd line below the dotted line. Now, I have figured out this much of the regular expression but I would like to make it simpler. Instead of having to run the top one first then the 2nd one I would like to just run one all together. I tried this but it did not work. (mysql_escape_string\()*$_REQUEST\[\'([^']*)\'\]\)(\)*) So below is what works but again have to do it twice. $_REQUEST\[\'([^']*)\'\] mysql_escape_string\($_REQUEST\[\'([^']*)\'\]\) (isset($_GET['\1'])?mysql_real_escape_string($_GET['\1']):false) (isset($_POST['\1'])?mysql_real_escape_string($_POST['\1']):false) ============================ Update: Yeah, after some research I figured out that Notepad++ does not support most regular expressions. I guess one additional step can not hurt a person. It's just laziness. *NOTE: BUT if anyone wants to try feel free to comment. At least it is just 2 steps and not 20.

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• Regular Expression

  - by equilibrium

  Ohh! this regular expression thing is eating my brain up. I have been reading it from Introduction to Automata Theory, Languages and Computer by Hopcroft, Motwani and Ullman. I have solved a few exercises too but could not solve the following even after trying for almost one hr. The problem is to write a regular expression that defines a language consisting of all strings of 0s and 1s except the substring 011. Is the answer (0+1)* - 011 correct ? If not what should be the correct answer for this?

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• Censoring selected words (replacing them with ****) using a single replaceAll?

  - by aioobe

  I'd like to censor some words in a string by replacing each character in the word with a "*". Basically I would want to do String s = "lorem ipsum dolor sit"; s = s.replaceAll("ipsum|sit", $0.length() number of *)); so that the resulting s equals "lorem ***** dolor ***". I know how to do this with repeated replaceAll invokations, but I'm wondering, is this possible to do with a single replaceAll?

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• Regular Expression to capture the first <p> of HTML

  - by Program.X

  I have the following regular expression: (?:<(?<tag>\w*)>(?<text>.*)</\k<tag>>) I want it t grab the text within the first HTML element. eg. <p>This should capture</p>This shouldn't Works, but ... <p>This should capture</p><p>This shouldn't</p> Doesn't work. As you'd expect, it returns: This should capture</p><p>This shouldn't I'm racking my brains here. How can I just have it select the FIRST inner text? (I'm trying to be tag-agnostic, so <strong>This should match</strong> is equally appropriate, etc.)

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• RegExp that matches any String containing "0-9" and "." and "-" and " "

  - by tzippy

  I need t check every line of a file for the following pattern: - 14 Values seperated by an irregular number of spaces. - Values may be negative (-), decimal seperator is a dot followed by maximum one digit - The line ends with several spaces here is an example line: 10015 20100501 1 4.6 6.4 8.4 10.5 86.6 4.0 13.0 0.9 6.4 0.0 1007.2 Thanks!

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• Elegant way to distinct Path or Entry key

  - by sum1stolemyname

  I have an application loading CAD data (Custom format), either from the local filesystem specifing an absolute path to a drawing or from a database. Database access is realized through a library function taking the drawings identifier as a parameter. the identifiers have a format like ABC 01234T56-T, while my paths a typical windows Paths (eg x:\Data\cadfiles\cadfile001.bin). I would like to write a wrapper function Taking a String as an argument which can be either a path or an identifier which calls the appropriate functions to load my data. Like this: Function CadLoader(nameOrPath : String):TCadData; My Question: How can I elegantly decide wether my string is an idnetifier or a Path to a file? Use A regexp? Or just search for '\' and ':', which are not appearing in the Identifiers?

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• How can I match everything in a string until the second occurrence of a delimiter with a regular expression?

  - by Steve

  I am trying to refine a preg_match_all by finding the second occurrence of a period then a space: <?php $str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop. Slight chance of showers."; preg_match_all ('/(^)((.|\n)+?)(\.\s{2})/',$str, $matches); $dataarray=$matches[2]; foreach ($dataarray as $value) { echo $value; } ?> But it does not work: the {2} occurrence is incorrect. I have to use preg_match_all because I am scraping dynamic HTML. I want to capture this from the string: East Winds 20 knots. Gusts to 25 knots.

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• How can I test if an input field contains foreign characters?

  - by zeckdude

  I have an input field in a form. Upon pushing submit, I want to validate to make sure the user entered non-latin characters only, so any foreign language characters, like Chinese among many others. Or at the very least test to make sure it does not contain any latin characters. Could I use a regular expression for this? What would be the best approach for this? I am validating in both javaScript and in PHP. What solutions can I use to check for foreign characters in the input field in both programming languages?

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• Regular expression to match text that doesn't start with substring?

  - by Steven

  I have text with file names scattered throughout. The filenames appear in the text like this: |test.txt| |usr01.txt| |usr02.txt| |foo.txt| I want to match the filenames that don't start with usr. I came up with (?<=\|).*\.txt(?=\|) to match the filenames, but it doesn't exclude the ones starting with usr. Is this possible with regular expressions?

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• Regular expression - starting and ending with a letter, accepting only letters, numbers and _

  - by jreid9001

  I'm trying to write a regular expression which specifies that text should start with a letter, every character should be a letter, number or underscore, there should not be 2 underscores in a row and it should end with a letter or number. At the moment, the only thing I have is ^[a-zA-Z]\w[a-zA-Z1-9_] but this doesn't seem to work properly since it only ever matches 3 characters, and allows repeated underscores. I also don't know how to specify requirements for the last character.

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• what is the regular expression for this

  - by bn

  I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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• javascript split string on space or on quotes to array

  - by Boriz

  var str = 'single words "fixed string of words"'; var astr = str.split(" "); // need fix i want the array to be like: single, words, fixed string of words.

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• How to determine that there is date in the string or not with different date format ?

  - by Harikrishna

  I have a need of checking whether there is the date in the string or not. FUTIDX 26FEB2009 NIFTY 0 -- There is date in the string. FUTIDX MINIFTY 30 Jul 2009 -- There is date in the string. FUTSTK ONGC 27 Mar 2008 -- There is date in the string. How can I do that ?

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• extract word with regular expression

  - by farka

  I have a string 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and I would like to extract the words temperatoA and CelcieusB. I have this regular expression (\d+/(\w+),?)*! but I only get the match 1/temperatoA,2/CelcieusB! Why?

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• How do you use grep to find terms that are n characters long?

  - by Brian

  I'm using grep to filter the Mac OS X dictionary words file (by default located at /usr/share/dict/words). I want to use grep to retrieve all words four characters long. How do I do this? My best guess for how to do this was: grep [:alpha:]{4} words But that returns zero results.

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• JavaScript: add or subtract from number in string

  - by yoavf

  I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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