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  • JQuery post to php

    - by RussP
    Why is it that I can never get JQuery serialize to work properly. I guess I must be missing something. I can serialize a form data and it shows in an alert: var forminfo = $j('#frmuserinfo').serialize(); alert(forminfo); I then post to my PHP page thus: $j.ajax({ type: "POST", url: "cv-user-process.php", data: "forminfo="+forminfo, cache: false, complete: function(data) { } }); But WHENEVER (not the first time) I try to insert/update the data in the DB I only ever get 1 varaible passed: Here is my PHP script: $testit = mysql_query("UPDATE cv_usersmeta SET inputtest='".$_POST['forminfo']."' WHERE user='X'"); the data passed only ever gets the first variable. why? I think it is more the way I deal with the php but it drives me nuts and always takes me far too long to find where I am going wrong.

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  • Change HTML DropDown Default Value with a MySQL value

    - by fzr11017
    I'm working on a profile page, where a registered user can update their information. Because the user has already submitted their information, I would like their information from the database to populate my HTML form. Within PHP, I'm creating the HTML form with the values filled in. However, I've tried creating an IF statement to determine whether an option is selected as the default value. Right now, my website is giving me a default value of the last option, Undeclared. Therefore, I'm not sure if all IF statements are evaluation as true, or if it is simply skipping to selected=selected. Here is my HTML, which is currently embedded with PHP(): <select name="Major"> <option if($row[Major] == Accounting){ selected="selected"}>Accounting</option> <option if($row[Major] == Business Honors Program){ selected="selected"}>Business Honors Program</option> <option if($row[Major] == Engineering Route to Business){ selected="selected"}>Engineering Route to Business</option> <option if($row[Major] == Finance){ selected="selected"}>Finance</option> <option if($row[Major] == International Business){ selected="selected"}>International Business</option> <option if($row[Major] == Management){ selected="selected"}>Management</option> <option if($row[Major] == Management Information Systems){ selected="selected"}>Management Information Systems</option> <option if($row[Major] == Marketing){ selected="selected"}>Marketing</option> <option if($row[Major] == MPA){ selected="selected"}>MPA</option> <option if($row[Major] == Supply Chain Management){ selected="selected"}>Supply Chain Management</option> <option if($row[Major] == Undeclared){ selected="selected"}>Undeclared</option> </select>

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  • MP3 and OGG tags in PHP

    - by Quamis
    Except http://us3.php.net/manual/en/book.ktaglib.php and http://getid3.sourceforge.net/ does anyone know of any other way to work from PHP with tags on audio files? I need to read and write them, and KTagLib seems a little too much for the job, and also don't really get the documentation, and getID3 seems to only write ID3v1 tags.

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  • Php + mysql transactions examples

    - by Donator
    I really haven't found normal example of php file where mysql transactions are being used. Can you show me simple example of that? And one more question. I've already created a lot of programming and didn't use transaction, maybe I can put any php function or smth to header.php that if one mysql_query fails, then others too? Thank you.

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  • htaccess to not show index.php in sub directory

    - by Jamesaa
    I have a simple page structure like below /directory/subdir_1/index.php /directory/subdir_2/index.php .... (there are no other files in these directories) is it possible to have 'fake/pretty' urls for the above files as below? /directory/subdir_1 /directory/subdir_2 ... so this path would show whether the visitor typed that,/directory/subdir_2/ or /directory/subdir_2/index.php. Many thanks

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  • Rails-like console for PHP?

    - by Chad Johnson
    Every so often, things work in my local PHP development environment, while in my test environment on my server, things do not. It's a nightmare to debug this. If I had a console like Rails provides, debugging would be much much simpler. Is there anything like the Rails console but for PHP? I should mention that I am using a home-brewn PHP application.

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  • HttpWebRequest POST and retrieve data from php script after login

    - by KenaGT
    Hello guys i am newbie to this stuff so i'll try to explain my problem.I am building application that retrieve data after login to php script that looks like this: https://zamger.etf.unsa.ba/getrssid.php (see the page source for php scirpt definition) and definition(source) here: Korisnicko ime (UID): Šifra: After i login it shows me data that i must collect like this: RSSID: 1321B312 (this is only data that it shows and nothing else) I must do this with httpwebrequest but don't know how i tried to do it with POST(data) but it always give me the defnition of php script as response.But i need response to be like "RSSID: 1321B312" not as script definition mentioned above...please heeelp ASAP....

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  • Gmail,Yahoo, Facebook, Twitter contacts importer in PHP

    - by Arjun
    Which is the greatest, cheapest application in PHP that I can buy to import Gmail, Yahoo, MSN, Facebook, Twitter contacts from my user's accounts if they wish to invite their friends? I have gone through: http://www.improsys.com/importer.htm http://www.octazen.com/demo.php and http://www.iplussoft.com/product/iplusinvite_pricing Octazen looks awesome but wants excess of $320 for an all in solution. I don't want to spend that much. All you PHP programmers out there you may have needed to build of integrate a similar app, I need to know which is the best PHP readymade app for this? Any help would be appreciated and I'll smile with each answer - this should be your biggest incentive to find me something amazing :)

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  • undefined offset error in php

    - by user225269
    I don't know why but the code below is working when I have a different query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <?php list($year,$month,$day)=explode("-", $row['BIRTHDAY']); ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mm" type="text" id="mm" onkeypress="return handleEnter(this, event)" value="<?php echo $month;?>"> <td width="30" height="35"><font size="2">Day:</td> <td width="30"><input name="dd" type="text" id="dd" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $day;?>"> <td width="30" height="35"><font size="2">Year:</td> <td width="30"><input name="yyyy" type="text" id="yyyy" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $year;?>"> And it works when this is my query: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); Please help, why do I get the undefined offset error when I use this query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") I assume that the query is the problem because its the only thing that's different between the two.

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  • where is wrong in my php code ????

    - by user318068
    hi all, <td align="center" bgcolor="#FFFFFF"><?php echo '<label onclick="window.open('profilephp.php?member=$row['MemberID']','mywindow')">'.{$row['MemberName']}.'</label>';?><br /> <?php echo "<p align='center'><img width='100' height='100' src={$row['MemberImg']} alt='' /></p>";?></td></tr> Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\home - Copy\membercopy.php on line 141 I really don't know where it went wrong. Please help,

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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  • How to insert form data into MySQL database table

    - by Richard
    So I have this registration script: The HTML: <form action="register.php" method="POST"> <label>Username:</label> <input type="text" name="username" /><br /> <label>Password:</label> <input type="text" name="password" /><br /> <label>Gender:</label> <select name="gender"> <optgroup label="genderset"> <option value="Male">Male</option> <option value="Female">Female</option> <option value="Hermaphrodite">Hermaphrodite</option> <option value="Not Sure!!!">Not Sure!!!</option> </optgroup> </select><br /> <input type="submit" value="Register" /> </form> The PHP/SQL: <?php $username = $_POST['username']; $password = $_POST['password']; $gender = $_POST['gender']; mysql_query("INSERT INTO registration_info (username, password, gender) VALUES ('$username', '$password', '$gender') ") ?> The problem is, the username and password gets inserted into the "registration_info" table just fine. But the Gender input from the select drop down menu doesn't. Can some one tell me how to fix this, thanks.

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  • iPhone: Try to send html code to a php script (but fail)

    - by Marc-André Weibezahn
    Hello all, I am trying this for an iPhone app in Xcode: create html code for a website on the fly sending it to a php-script and getting the response with this code: NSError * error = [[[NSError alloc]init]autorelease]; NSURL * phpURL = [NSURL URLWithString: @"http://www.mydomain.com/myscript.php?mywebsite= (...websitestring...) ];NSString * myResponse = [NSString stringWithContentsOfURL:phpURL encoding:NSUTF8StringEncoding error:&error]; It does not work. It should not be a problem of the php code because when I replace the websitestring which contains the html code with "hello" or something, this is accepted. (the script then creates a file "test.html" with the content I sent.) But when I put html code in it, I always get the error: Error Domain=NSCocoaErrorDomain Code=256 "The operation couldn’t be completed. (Cocoa error 256.)" UserInfo=0x322ec10 {} It seems that there are some things to consider when sending code to php? Thanks in advance!

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  • Fake Template Engine php

    - by user1464822
    i got an idea for making php template engine fast and user friendly but i'm not sure if it's good or bad. the idea is to create a fake template engine: creating a template editor in control panel that let user see something like this: <html> <head> <title>{title}</title> </head> <body> {content} </body> </html> what the editor actually does is to replace all php code like <?php echo $this->title; ?> to user friendly {title} but it's not really replacing it just in the view when the user save the template the template actually saved as fast pure php template. the question is this a good idea or bad ? your answers is highly appreciated.

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  • Passing $_GET or $_POST data to PHP script that is run with wget

    - by Matt
    Hello, I have the following line of PHP code which works great: exec( 'wget http://www.mydomain.com/u1.php /dev/null &' ); u1.php acts to do various types of maintenance on my server and the above command makes it happen in the background. No problems there. But I need to pass variable data to u1.php before it's executed. I'd like to pass POST data preferably, but could accommodate GET or SESSION data if POST isn't an option. Basically the type of data being passed is user-specific and will vary depending on who is logged in to the site and triggering the above code. I've tried adding the GET data to the end of the URL and that didn't work. So how else might I be able to send the data to u1.php? POST data preferred, SESSION data would work as well (but I tried this and it didn't pick up the logged in user's session data). GET would be a last resort. Thanks!

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  • What is wrong with this php loop?

    - by Mark R
    I made a loop but it doesn't work. here's what I did: <?php if(is_tree('4')) { ?> <?php $show_after_p = 2; $content = apply_filters('the_content', $post->post_content); if(substr_count($content, '<p>') > $show_after_p) { $contents = explode("</p>", $content); $p_count = 1; foreach($contents as $content) { echo $content; if($p_count == $show_after_p) { ?> YOUR AD CODE GOES HERE < ? } echo "</p>"; $p_count++; } } ?> <?php else : ?> <?php the_content('<p class="serif">Read the rest of this page &raquo;</p>'); ?> <?php endif; } ?> I need to make it work but don't know how. I'm guessing it's a simple syntax error I'm not seeing?

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  • header problem in php refresh

    - by basma
    hello i have this code : <?php session_start(); echo "".$_SESSION['eventnum'].""; $urlRefresh = "testremot.php"; header("Refresh: 5; URL=\"" . $urlRefresh . "\""); ?> but the header doesnt work and this warning appear when i try to run this code : Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\remot\testremot.php:3) in C:\xampp\htdocs\remot\testremot.php on line 5 can you please help me ?

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  • Absolute URL Path for PHP Website

    - by kakaajee
    Hi friends, I am working on a website in a CMS site. I have provided a link in my footer file e.g blogs.php. This page is at the root like "http://www.example.com/new_cms/blogs.php" When I moves to other files link like "http://www.example.com/new_cms/forums" the footer link is changed to "http://www.example.com/new_cms/forums/blogs.php" but the blogs.php page resides at path "http://www.example.com/new_cms/" . I tried different $_SERVER[] variables but got no luck to get the above path "http://www.example.com/new_cms/" means the server name with the directory where the project is currently running from. Any one have idea how to get it done will be a great help. Thanks

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  • php regular expression assistance bold a filename

    - by jason
    I am not very good, with regular expression in php I am trying to get a reg_expression to find all file names such as /file-name-here.php and make it bold. This expression works in Flash but not in php it also doesn't accept the '-' i'm not sure why i can't get it to work with preg_replace /(https?://)?(www\.)?([a-zA-Z0-9_%]*)\b\.[a-z]{2,4}(\.[a-z]{2})?((/[a-zA-Z0-9_%]*)+)?(\.[a-z]*)?/g

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