Search Results

Search found 52038 results on 2082 pages for 'php form processing'.

Page 141/2082 | < Previous Page | 137 138 139 140 141 142 143 144 145 146 147 148  | Next Page >

  • jQuery: modify hidden form field value before submit

    - by Jason Miesionczek
    I have the following code in a partial view (using Spark): <span id="selectCount">0</span> video(s) selected. <for each="var video in Model"> <div style="padding: 3px; margin:2px" class="video_choice" id="${video.YouTubeID}"> <span id="video_name">${video.Name}</span><br/> <for each="var thumb in video.Thumbnails"> <img src="${thumb}" /> </for> </div> </for> # using(Html.BeginForm("YouTubeVideos","Profile", FormMethod.Post, new { id = "youTubeForm" })) # { <input type="hidden" id="video_names" name="video_names" /> <input type="submit" value="add selected"/> # } <ScriptBlock> $(".video_choice").click(function() { $(this).toggleClass('selected'); var count = $(".selected").length; $("#selectCount").html(count); }); var options = { target: '#videos', beforeSubmit: function(arr, form, opts) { var names = []; $(".selected").each(function() { names[names.length] = $(this).attr('id'); }); var namestring = names.join(","); $("#video_names").attr('value',namestring); //alert(namestring); //arr["video_names"] = namestring; //alert($.param(arr)); //alert($("#video_names").attr('value')); return true; } }; $("#youTubeForm").ajaxForm(options); </ScriptBlock> Essentially i display a series of divs that contain information pulled from the YouTube API. I use jQuery to allow the the user to select which videos they would like to add to their profile. When i submit the form i would like to populate the hidden field with a comma separated list of video ids. Everything works except that when i try to set the value of the field, in the controller on post, the field comes back empty. I am using the jQuery ajax form plugin. What am i doing wrong that is not allowing the value i set in the field to be sent to the server?

    Read the article

  • jQuery: form input values turns up undefined

    - by Seerumi
    Having problem with this bit of code qith jQuery. it should pick the values from current form and then submit them, but when I try to get them with jQuery they always turn up undefined. I know the SQL results are fine since they show correctly in HTML table, so it must be my inferior javascript skills. New with jQuery and I'm at loss :( PHP/HTML: echo "<table>\n" while ($row = odbc_fetch_array($query)) { echo "<form class='catForm'>\n"; echo "<input type=hidden class='catID' name='catID' value='".$row['running_id']."'/>\n"; echo "<tr>\n"; echo "<td>".$row['running_id']."</td>\n"; echo "<td>".$row['site_id']."</td>\n"; echo "<td>".$row['main_category']."</td>\n"; echo "<td>".$row['map_name']."</td>\n"; echo "<td><input type=textfield class='bCatID' value='".$row['mapping_id']."' size=6/></td>\n"; echo "<td><input type=submit class='saveCat' value='Save'/></td>\n"; echo "<td><input type=submit class='killCat' value='Delete' /></td>\n"; echo "</tr>\n"; echo "</form>\n"; } echo "</table>"; jQuery: $(".catForm").submit(function () { var id = $(this).find('.catID').val(); var bCatID = $(this).find('.bCatID').val(); var dataString = 'id='+id+'&bCatID='+bCatID; $.ajax({ type: "POST", url: 'adminUI/bin/updateSCategories.php', dataType : 'json', data: dataString, success: function(data) { if (data.error == true) $('.failure').html("Error, save failed.").show().fadeOut(2000); if (data.error == false) $('.success').html("Saved succesfully").show().fadeOut(2000); }, error: function(XMLHttpRequest, textStatus, errorThrown) { $('.failure').html("Error, save failed.").show().fadeOut(2000); } }); return false; }); RESULT: id: undefined bCatID: undefined

    Read the article

  • PHP & MySQL form question.

    - by peakUC
    How do I allow all users to have there username field empty without having them to enter a username when they submit the form using PHP and MySQL? Here is part my PHP and MySQL code. $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if(isset($_POST['username'])) { // Make sure the username address is available: $u = "SELECT * FROM users WHERE username = '$username' AND user_id <> '$user_id'"; $r = mysqli_query ($mysqli, $u) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); if (mysqli_num_rows($r) == TRUE) { // Unavailable. echo '<p class="error">Your username is unavailable!</p>'; $username = NULL; } else if(mysqli_num_rows($r) == 0) { // Available. $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); } }

    Read the article

  • Saving a remote image with cURL?

    - by thebluefox
    Morning all, Theres a few questions around this but none that really answer my question, as far as I ca understand. Basically I have a GD script that deals with resizing and caching images on our server, but I need to do the same with images stored on a remote server. So, I'm wanting to save the image locally, then resize and display it as normal. I've got this far... $file_name_array = explode('/', $filename); $file_name_array_r = array_reverse($file_name_array); $save_to = 'system/cache/remote/'.$file_name_array_r[1].'-'.$file_name_array_r[0]; $ch = curl_init($filename); $fp = fopen($save_to, "wb"); // set URL and other appropriate options $options = array(CURLOPT_FILE => $fp, CURLOPT_HEADER => 0, CURLOPT_FOLLOWLOCATION => 1, CURLOPT_TIMEOUT => 60); // 1 minute timeout (should be enough) curl_setopt_array($ch, $options); curl_exec($ch); curl_close($ch); fclose($fp); This creates the image file, but does not copy it accross? Am I missing the point? Cheers guys.

    Read the article

  • get renamed file names of multiple upload form [js array] in codeigniter

    - by artmania
    Hi friends, I use codeigniter. I have a multiple image upload form. The code below is working well for uploading, but I also need to save file names to database. How can I get the names in here? I spent hours & hours :/ but could not sort it :/ Appreciate helps!!! uploadform.php echo form_open_multipart('gallery/upload'); <input type="file" name="photo" size="50" /> <input type="file" name="thumb" size="50" /> <input type="submit" value="Upload" /> </form> I have a controller between form view and model load model (of course : )) but didnt post here because of no need. gallery_model.php function multiple_upload($upload_dir = 'uploads/', $config = array()) { /* Upload */ $CI =& get_instance(); $files = array(); if(empty($config)) { $config['upload_path'] = realpath($upload_dir); $config['allowed_types'] = 'gif|jpg|jpeg|jpe|png'; $config['max_size'] = '2048'; } $CI->load->library('upload', $config); $errors = FALSE; foreach($_FILES as $key => $value) { if( ! empty($value['name'])) { if( ! $CI->upload->do_upload($key)) { $data['upload_message'] = $CI->upload->display_errors(ERR_OPEN, ERR_CLOSE); // ERR_OPEN and ERR_CLOSE are error delimiters defined in a config file $CI->load->vars($data); $errors = TRUE; } else { // Build a file array from all uploaded files $files[] = $CI->upload->data(); } } } // There was errors, we have to delete the uploaded files if($errors) { foreach($files as $key => $file) { @unlink($file['full_path']); } } elseif(empty($files) AND empty($data['upload_message'])) { $CI->lang->load('upload'); $data['upload_message'] = ERR_OPEN.$CI->lang->line('upload_no_file_selected').ERR_CLOSE; $CI->load->vars($data); } else { return $files; } /* ------------------------------- Insert to database */ // problem is here, i need file names to add db. // if there is already same names file at the folder, it rename file itself. so in such case, I need renamed file name :/ } }

    Read the article

  • How should images be stored when multiple sizes are needed?

    - by Josh Curren
    What is the best way to store images? Currently when an image is uploaded I resize it to 3 different sizes (a thumbnail, a normal size, and a large size). I save in a database a description of the image, the format, and use the id number from the database as the image name. Each size image has its own directory. Should I be storing the images in the database? Should I only be storing the larger size and generate the thumbnail as needed? Or any other ideas you have?

    Read the article

  • Php mail pulling form data from previous page

    - by Mark
    So I have a form being filled out on one php like so: <p> <label for="first_name">First Name: </label> <input type="text" size="30" name="first_name" id="first_name"/> </p> <p> <label for="last_name"> Last Name:</label> <input type="text" size="30" name="last_name" id="last_name"/> </p> <p> <label for="address_street">Street:</label> <input type="text" size="30" name="address_street" id="address_street"/> </p> <p> <label for="address_city">City:</label> <input type="text" size="30" name="address_city" id="address_city"/> </p> <p> <label for="address_state">State/Province:</label> <input type="text" size="30" name="address_state" id="address_state"/> </p> <p> <label for="email">Your e-mail: </label> <input type="text" size="30" name="email" id="email"/> </p> <p> <label for="phone">Your phone number: </label> <input type="text" size="30" name="phone" id="phone"/> </p> This is on one php page. From here, it goes to another php which part of it contains script to send a html email to recipient. Problem is, I cannot seem to get it to pull the variables even though I thought I declared them correctly and mixed them into the html correctly. <?php $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; $to = "[email protected], [email protected]"; $subject = "HTML email for ALPS"; $message .= ' <html> <body> <div style="display: inline-block; width: 28%; float: left;"> <img src="http://englishintheusa.com/images/alps-logo.jpg" alt="ALPS Language School" /> </div> <div style="display: inline-block; width: 68%; float: right;"> <p style="color: #4F81BD; font-size: 20px; text-decoration: underline;">Thanks You For Your Inquiry!</p> </div> <div style="padding-left: 20px; color: #666666; font-size: 16.8px; clear: both;"> <p>Dear $first_name $last_name ,</p> </br > <p>Thank you for the following inquiry:</p> </br > </br > </br > </br > <p>****Comment goes here****</p> </br > </br > <p>We will contact you within 2 business days. Our office is open Monday-Friday, 8:30 AM - 5:00 PM Pacific Standard Time.</p> </br > <p>Thank you for your interest!</p> </br > </br > <p>Best Regards,</p> </br > </br > <p>ALPS Language School</p> </br > </br > <p>430 Broadway East</p> <p>Seattle WA 98102</p> <p>Phone: 206.720.6363</p> <p>Fax: 206. 720.1806</p> <p>Email: [email protected]</p> </div> </body> </html>'; // Always set content-type when sending HTML email $headers .= "MIME-Version: 1.0" . "\r\n"; $headers .= "Content-type:text/html;charset=UTF-8" . "\r\n"; // More headers mail($to,$subject,$message,$headers); ?> So you see where I am trying to get first_name and last_name. Well it doesn't come out correctly. Can someone help here?

    Read the article

  • Codeigniter Image Library Cropping an Image with 2 sets of coordinates to make square anywhere?

    - by chris
    Spending time reading through the docs, and searching for examples. I understand cropping an image from top 0, and left 0 is pretty straight forward. However. I would like to pass 2 sets of coordinates, a starting point and an ending point. Four Points, a Square that is defined anywhere. However from the examples I am finding, and from what I gather the rendition is not going to let me do this. codeigniter so I am seeking confirmation on this thought, is it true that I can only provide end points from 0, and it crops a square based on said end points or can I actually specify an x start, an x end, and similar for y? Or is there some other technique I can use within codeigniter that will allow me to pass for coordinates for starting and ending points?

    Read the article

  • PHP form validation submit problem

    - by TaG
    Every time I try to submit the form and I have not entered nothing in the year field I get Incorrect year! how can I still submit the form without having to enter a year. In other words leaving the year field blank and not getting a warning? Here is the PHP code. if(preg_match('/^\d{4,}$/', $_POST['year'])) { $year = mysqli_real_escape_string($mysqli, $_POST['year']); } else { $year = NULL; } if($year == NULL) { echo '<p class="error">Incorrect year!</p>'; } else { //do something }

    Read the article

  • Sync offline JQuery Mobile form

    - by Dimas
    My name is Dimas and I work as a developer in a hospital. I've developed a web form with JQuery Mobile which is accessed from an Android tablet. It sends data (text and FILES) to the server (PHP) and it's saved in a MySQL database. This tablets are used by doctors that are visiting the patients in their homes. Some of these patients live in remote areas with very bad Internet connection, so I'm thinking on use HTML5 Offline feature to solve these situations. I started reading about it but I'm newbie with this technology. I've some questions: Do you think this is the best/easiest solution? If I could save the form data in a local sqlite storage when the tablet is offline, how I could synchronize it with the data in MySQL server when the tablet become online? Thanks

    Read the article

  • Will data order in post form be the same to it in web form?

    - by Relax
    Assuming there are 5 inputs in web form <input name='the_same' value='different' /> <input name='the_same' value='different' /> <input name='the_same' value='different' /> <input name='the_same' value='different' /> <input name='the_same' value='different' /> When server side receive the post data, i use a foreach to accept data, say $the_same = new array(); foreach($_REQUEST as $data) $the_same[] = $data; Will the order of data saved in server side be the same to it in web form?

    Read the article

  • form Validation white page not showing errors

    - by Jess McKenzie
    In the example below I am wanting to do all of the 'safety' checks on the $_POST variables but it seems when I click submit I get a white page why? I am wanting it to show the errors etc Form Process: /* check if the form is submitted */ if (isset($_POST['submitButton'])) { $fullName = $_POST['fullname']; if($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($fullName)) { if (!ctype_alpha(str_replace(array("'", "-"), "",$fullName))) { $errorfullName .= '<span class="errorfullName">*First name should be alpha characters only.</span>'; } if (strlen($fullName) < 3 OR strlen($fullName) > 40) { $errorfullName .= '<span class="errorfullName">*First name should be within 3-40 characters long.</span>'; } } }

    Read the article

  • how to validate the form using jquery

    - by kumar
    I have this Fieldset values.. <fieldset class="clearfix" id="fieldset-exception"> <legend>Mass Edit Exception Information</legend> <div id="#error-msg-ID" class="ui-widget hide"> <div class="ui-state-highlight ui-corner-all"> <p><span style="float: left; margin-right: 0.3em;" class="ui-icon ui-icon-info"></span> <span></span></p> </div> </div> <div class="fiveper"> <label for="ExceptionStatus"> Status: <span> </span> </label> <label for="ResolutionCode"> Resolution: <span> <%=Html.DropDownListFor(model => model.Exception.ResolutionCode, new SelectList(Model.LookupCodes["C_EXCPT_RESL"], "Key", "Value"))%> </span> </label> <label for="ReasonCode"> Reason: <span><%=Html.DropDownListFor(model => model.Exception.ReasonCode, new SelectList(Model.LookupCodes["C_EXCPT_RSN"], "Key", "Value"))%></span> </label> <label for="ExceptionStatus"> Action Taken: <span><%=Html.DropDownListFor(model => model.Exception.ActionCode, new SelectList(Model.LookupCodes["C_EXCPT_ACT"], "Key", "Value"))%></span> </label> </div> <div class="fiveper"> <label for="FollowupDate"> Follow-up: <span><input type="text" id="exc-flwup" name="fdate" /></span> <%--<%=Html.EditorFor(model=>model.Exception.FollowupDate) %>--%> </label> <label for="IOL"> Inquiry #: <%=Html.TextBox("Inquiry", ViewData["inq"] ?? "")%> </label> <label>Comment</label> <span> <%=Html.TextArea("value", ViewData["Comnt"] ?? "")%> <%=Html.ValidationMessage("value")%> </span> </div> <br /> <br /> <div> <input type="submit" class="button" value="Save" /> </div> </fieldset> before submiting I need to do some time of validation..below validation not working for me is that right what I am doing here? These all fieds user is entering from UI.. thanks <script type="text/javascript"> $(document).ready(function() { $('#btnSelectAll').click(function() { $('#EditExceptions input[name=chk]').attr('checked', true); }); $('#btnCancel').click(function() { $('#EditExceptions input[name=chk]').attr('checked',false); }); function validate_excpt(formData, jqForm, options) { var form = jqForm[0]; **if (form.e_Exception_ResolutionCode.value && !form.e_Exception_ReasonCode.value) { alert('All Resolution Codes need a Reason Code.'); return false; }** } // post-submit callback function showResponse(responseText, statusText, xhr, $form) { if (responseText[0].substring(0, 16) != "System.Exception") { $('#error-msg-ID span:last').html('<strong>Update successful.</strong>'); $().ShowDialog('Success', 'Update successful'); } else { $('#error-msg-ID span:last').html('<strong>Update failed.</strong> ' + responseText[0].substring(0, 48)); $().ShowDialog('Failed', 'Update failed'); } $('#error-msg-ID').removeClass('hide'); $('#gui-stat-').html(responseText[1]); } $('#exc-').ajaxForm({ beforeSubmit: validate_excpt, success: showResponse, dataType: 'json' }); $('.button').button(); $("input[id^='exc-flwup']").datepicker({ duration: '', showTime: true, constrainInput: true, stepMinutes: 30, stepHours: 1, altTimeField: '', time24h: true, minDate: 0 }); $('#ui-timepicker-div').bgiframe(); }); </script>

    Read the article

  • Passing javascript form variables into jQuery function not working

    - by Chase
    I am trying to pass some JavaScript variables that I have assigned to form variables into a query string used by a jQuery plug in called fancybox. If I hard code in the string that I want lightbox works great, however I need it to pass some form values in there to make it work as desire. <script type="text/javascript"> $(document).ready(function(){ var item = document.itemFinder.item; var zip = document.itemFinder.zip; var radius = document.itemFinder.radius; var dataString = "item=" + item + "&zip=" + zip + "&radius=" + radius; $("#various3").fancybox({ ajax : { type : "POST", data : dataString}, 'scrolling' : 'auto', 'overlayOpacity' : '0' } ); }); </script> What am I doing wrong?

    Read the article

  • Javascript form validation events

    - by user307922
    Hi All, I am making a small form for a php app and had a question regarding javascript validation. What is the best event to run the javascript validation on the input value? Is it the "focusout" event? I used "focusout" to originally but it creates problems when the user hits enter while they are still focused on any particular field in the form. Should I run the js validation when the user clicks submit? Just looking for some advice. Thanks! Chuck

    Read the article

  • Handling errors on php contact form

    - by topSearchDesign
    The below code is working great for handling errors for text fields in my contact form, but how do I get this same method to work for dropdown select option boxes and textareas? <input type="text" name="name" value="<?php if($errors){echo $name;} ?>" id="name" size="30" /> For example: <textarea name="message" value="<?php if($errors){echo $message;} ?>" id="message" rows="10" cols="40"></textarea> does not work.

    Read the article

  • Upload image using CURL + PHP via remote form

    - by user253530
    I have a few images that i need to upload using an online form. So far here's my code $info = array('test title','1234','virginia','@'.realpath('e:\wamp\www\1.jpg'),'@'.realpath('e:\wamp\www\2.jpg'),'@'.realpath('e:\wamp\www\3.jpg'),'@'.realpath('e:\wamp\www\4.jpg'),'test description'); $post->postAd($url, $info); The $info array is processed in the postAd method and it's being sent as an associative array using a method from a Curl class i have (it has been tested and worked nicely with everything i needed to do so far with curl). The problem is that the data is completed correctly on the form but the images are not uploaded. Can anyone help with advices/code/guidance?

    Read the article

  • Posting form using javascript and json with nested objects

    - by Tim
    I have an html form that has the following structure: <input type="text" name="title" /> <input type="text" name="persons[0].name" /> <input type="text" name="persons[0].color" /> <input type="text" name="persons[1].name" /> <input type="text" name="persons[1].color" /> I would like to serialize this into the following json: { "title":"titlecontent", "persons":[ { "name":"person0name", "color":"red" }, { "name":"person1name", "color":"blue" } ] } Notice that the number of persons can vary from case to case. The structure of the html form can change, but the structure of the submitted json can't. How is this done the easiest?

    Read the article

  • Javascript clone form?

    - by user202987
    I need to copy a form information with all types of elements and send it with AJAX. Tried these: 1. cloneNode on the form. - Doesn't work with IE, only copies text stuff properly. cloneNode on each element. Doesn't work with IE, only copies text stuff properly. Making new textareas for each element, and copying the value in. Doesn't work for textareas in IE, formatting is lost. I imagine a combination of those 3 would work for IE and FF but is there any decent solution to this? Shortness of code is a priority.

    Read the article

  • Pass form object value to static method

    - by jrubengb
    Hi, I need to take a form object value and pass it into a static method: public void SetCalendarStartSafe(DateTime startDateSafe) { startDateSafe = calendarStart.Value; } private static DataTable GetData() { frmMain frm = new frmMain(); DateTime startDate = new frmMain(); frm.SetCalendarStartSafe(startDate); } However I keep getting today's current date whenever I try this approach, even if the specified calendar date on the form is different. How can I can the user-specified calendar date from the original frmMain object? Thanks in advance for any guidance.

    Read the article

  • Display error when entire form is blank in CodeIgniter

    - by Joe
    I'm trying to create a fairly simple form that has a few checkboxes and input fields and a textarea. Nothing is required by itself; however, if 'A' checkbox is checked, then 'A' input field is required (and so on for the couple other checkboxes I have). I have the above functionality in place, but I'm having a tough time figuring out how to have an error returned if the form is submitted blank (since nothing is required by default). Does anyone know of an easy-ish solution for this? It seems like it should be so simple... Thanks

    Read the article

< Previous Page | 137 138 139 140 141 142 143 144 145 146 147 148  | Next Page >