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  • Rollback doesn't work in MySQLdb

    - by Anton Barycheuski
    I have next code ... db = MySQLdb.connect(host=host, user=user, passwd=passwd, db=db, charset='utf8', use_unicode=True) db.autocommit(False) cursor = db.cursor() ... for col in ws.columns[1:]: data = (col[NUM_ROW_GENERATION].value, 1, type_topliv_dict[col[NUM_ROW_FUEL].value]) fullgeneration_id = data[0] type_topliv = data[2] if data in completions_set: compl_id = completions_dict[data] else: ... sql = u"INSERT INTO completions (type, mark, model, car_id, type_topliv, fullgeneration_id, mark_id, model_id, production_period, year_from, year_to, production_period_url) VALUES (1, '%s', '%s', 0, %s, %s, %s, %s, '%s', '%s', '%s', '%s')" % (marks_dict[mark_id], models_dict[model_id], type_topliv, fullgeneration_id, mark_id, model_id, production_period, year_from, year_to, production_period.replace(' ', '_').replace(u'?.?.', 'nv') ) inserted_completion += cursor.execute(sql) cursor.execute("SELECT fullgeneration_id, type, type_topliv, id FROM completions where fullgeneration_id = %s AND type_topliv = %s" % (fullgeneration_id, type_topliv)) row = cursor.fetchone() compl_id = row[3] if is_first_car: deleted_compl_rus = cursor.execute("delete from compl_rus where compl_id = %s" % compl_id) for param, row_id in params: sql = u"INSERT INTO compl_rus (compl_id, modification, groupparam, param, paramvalue) VALUES (%s, '%s', '%s', '%s', %s)" % (compl_id, col[NUM_ROW_MODIFICATION].value, param[0], param[1], col[row_id].value) inserted_compl_rus += cursor.execute(sql) is_first_car = False db.rollback() print '\nSTATISTICS:' print 'Inserted completion:', inserted_completion print 'Inserted compl_rus:', inserted_compl_rus print 'Deleted compl_rus:', deleted_compl_rus ans = raw_input('Commit changes? (y/n)') db.close() I has manually deleted records from table and than run script two times. See https://dpaste.de/MwMa . I think, that rollback in my code doesn't work. Why?

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  • Is there anyway to get pdb and Mac Terminal to play nicely?

    - by Ross
    When debugging my django apps I use pdb for interactive debugging with pdb.set_trace(). However, when I amend a file the local django webserver restarts and then I cant see what I type in the terminal, until I type reset. Is there anyway for this to happen automatically? It can be real annoying, having to cancel the runserver and reset and restart it all the time. I'm told it doesn't happen on other OS's (ubuntu) so is there anyway to make it not happen on the Mac? (I'm using Snow Leopard).

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  • Extracting a number from a 1-word string

    - by Kyle
    In this program I am trying to make, I have an expression (such as "I=23mm", or "H=4V") and I am trying to extract the 23 (or the 4) out of it, so that I can turn it into an integer. The problem I keep running into is that since the expression I am trying to take the numbers out of is 1 word, I cannot use split() or anything. One example I saw but wouldnt work was - I="I=2.7A" [int(s) for s in I.split() if s.isdigit()] This wouldnt work because it only takes the numbers are are delimited by spaces. If there was a number in the word int078vert, it wouldnt extract it. Also, mine doesnt have spaces to delimit. I tried one that looked like this, re.findall("\d+.\d+", "Amps= 1.4 I") but it didnt work either, because the number that is being passed is not always 2 digits. It could be something like 5, or something like 13.6. What code do I need to write so that if I pass a string, such as I="I=2.4A" or I="A=3V" So that I can extract only the number out of this string? (and do operations on it)? There are no spaces or other constant chars that I can delimit by.

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  • how to interleaving lists

    - by user2829177
    I have two lists that could be not equal in lengths and I want to be able to interleave them. I want to be able to append the extra values in the longer list at the end of my interleaved list.I have this: a=xs b=ys minlength=[len(a),len(b)] extralist= list() interleave= list() for i in range((minval(minlength))): pair=a[i],b[i] interleave.append(pair) flat=flatten(interleave) c=a+b if len(b)>len(a): remainder=len(c)-len(a) for j in range(-remainder): extra=remainder[j] extralist.append(extra) if len(a)>len(b): remainder=len(c)-len(b) for j in range(-remainder): extra=remainder[j] final=flat+extralist return final but if I test it: >>> interleave([1,2,3], ["hi", "bye",True, False, 33]) [1, 'hi', 2, 'bye', 3, True] >>> The False and 33 don't appear. What is it that Im doing wrong?

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  • different behavior when using re.finditer and re.match.

    - by Shahzad
    Hi, I'm working on a regex to to collect some values from a page through some script. I'm using re.match in condition but it returns false but if i use finditer it returns true and body of condition is executed. i tested that regex in my own built tester and it's working there but not in script. here is sample script. result = [] RE_Add0 = re.compile("\d{5}(?:(?:-| |)\d{4})?", re.IGNORECASE) each = ''Expiration Date:\n05/31/1996\nBusiness Address: 23901 CALABASAS ROAD #2000 CALABASAS, CA 91302\n' if RE_Add0.match(each): result0 = RE_Add0.match(each).group(0) print result0 if len(result0) < 100: result.append(result0) else: print 'Address ignore' else: None

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  • Resetting Globals With Importing

    - by what
    I have this code (Reset.py) that works how I want it to unless I import it. class Res(object): defaults={} class NoKey: pass def __init__(self): for key, values in defaults.items(): globals()[key]=values def add_defaults(key, values): Res.defaults[key]=value def remove_defaults(key=NoKey, remove_all=False): if remove_all: defaults={} else: del defaults[key] Without importing: >>> a=54 >>> Res.add_default('a', 3) >>> Res() <__main__.Res object at 0x> >>> a 3 >>> #great! :D With importing: >>> a=54 >>> Res.add_default('a', 3) >>> Res() <Reset.Res object at 0x> >>> a 54 This must mean when it is imported it changes the globals() under Reset and not __main__. How can I fix this?

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  • How do I print the Images?

    - by user1477539
    I want to print the images of the 30 nba teams drafting in the first round. However when I tell it to print it prints out the link instead of the image. How do I get it to print out the image instead of giving me the image link. Here's my code: import urllib2 from BeautifulSoup import BeautifulSoup # or if your're using BeautifulSoup4: # from bs4 import BeautifulSoup soup = BeautifulSoup(urllib2.urlopen('http://www.cbssports.com/nba/draft/mock-draft').read()) rows = soup.findAll("table", attrs = {'class': 'data borderTop'})[0].tbody.findAll("tr")[2:] for row in rows: fields = row.findAll("td") if len(fields) >= 3: anchor = row.findAll("td")[1].find("a") if anchor: print anchor

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  • Sharing base object with inheritance

    - by max
    I have class Base. I'd like to extend its functionality in a class Derived. I was planning to write: class Derived(Base): def __init__(self, base_arg1, base_arg2, derived_arg1, derived_arg2): super().__init__(base_arg1, base_arg2) # ... def derived_method1(self): # ... Sometimes I already have a Base instance, and I want to create a Derived instance based on it, i.e., a Derived instance that shares the Base object (doesn't re-create it from scratch). I thought I could write a static method to do that: b = Base(arg1, arg2) # very large object, expensive to create or copy d = Derived.from_base(b, derived_arg1, derived_arg2) # reuses existing b object but it seems impossible. Either I'm missing a way to make this work, or (more likely) I'm missing a very big reason why it can't be allowed to work. Can someone explain which one it is? [Of course, if I used composition rather than inheritance, this would all be easy to do. But I was hoping to avoid the delegation of all the Base methods to Derived through __getattr__.]

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  • Are there any other ways to iterate through the attributes of a custom class, excluding the in-built ones?

    - by Ricardo Altamirano
    Is there another way to iterate through only the attributes of a custom class that are not in-built (e.g. __dict__, __module__, etc.)? For example, in this code: class Terrain: WATER = -1 GRASS = 0 HILL = 1 MOUNTAIN = 2 I can iterate through all of these attributes like this: for key, value in Terrain.__dict__.items(): print("{: <11}".format(key), " --> ", value) which outputs: MOUNTAIN --> 2 __module__ --> __main__ WATER --> -1 HILL --> 1 __dict__ --> <attribute '__dict__' of 'Terrain' objects> GRASS --> 0 __weakref__ --> <attribute '__weakref__' of 'Terrain' objects> __doc__ --> None If I just want the integer arguments (a rudimentary version of an enumerated type), I can use this: for key, value in Terrain.__dict__.items(): if type(value) is int: # type(value) == int print("{: <11}".format(key), " --> ", value) this gives the expected result: MOUNTAIN --> 2 WATER --> -1 HILL --> 1 GRASS --> 0 Is it possible to iterate through only the non-in-built attributes of a custom class independent of type, e.g. if the attributes are not all integral. Presumably I could expand the conditional to include more types, but I want to know if there are other ways I'm missing.

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  • printing out dictionnaires

    - by kyril
    I have a rather specific question: I want to print out characters at a specific place using the \033[ syntax. This is what the code below should do: (the dict cells has the same keys as coords but with either '*' or '-' as value.) coords = {'x'+str(x)+'y'+str(y) : (x,y) for x,y, in itertools.product(range(60), range(20))} for key, value in coords.items(): char = cells[key] x,y = value HORIZ=str(x) VERT=str(y) char = str(char) print('\033['+VERT+';'+HORIZ+'f'+char) However, I noticed that if I put this into a infinite while loop, it does not always prints the same characters at the same position. There are only slight changes, but it deletes some and puts them back in after some loops. I already tried it with lists, and there it seems to behave just fine, so I tend to think it has something todo with the dict, but I can not figure out what it could be. You can see the Problem in a console here: SharedConsole.I am happy for every tip on this matter. On a related topic: After the printing, some changes should be made at the values of the cells dict, but for reason unknown to me, the only the first two rules are executed and the rest is ignored. The rules should test how many neighbours (which is in population) are around the cell and apply the according rule. In my implemention of this I have some kind of weird tumor growth (which should not happen, as if there more than three around they should the cell should die) (see FreakingTumor): if cells_copy [coord] == '-': if population == 3: cells [coord] = '*' if cells_copy [coord] == '*': if population > 3: cells [coord] = '-' elif population <= 1: cells [coord] = '-' elif population == 2 or 3: cells [coord] = '*' I checked the population variable several times, so I am quite sure that is not the matter. I am sorry for the slow consoles. Thanks in advance! Kyril

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  • How do I require a login for a user in Django?

    - by Di Zou
    In my urls.py I have this: (r'^myapp/$', 'myapp.views.views.index'), (r'^myapp/login/$', 'myapp.views.views.login_user'), In my settings.py I have this: LOGIN_URL = '/myapp/login' In my views.py I have this: @login_required((login_url='/myapp/login/') def index(request): return render_to_response('index.html') def login_user(request): #login stuff return render(request, 'registration/login.html', {'state':state, 'username': username}) I can go to mysite.com/myapp/login and the login page works. However, when I go to mysite.com/myapp/index I do not get redirected to the login page even though I am logged out. Why is that and how do I fix it?

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  • Can I do a reduce on a list comprehension into two lists, based on two values?

    - by pdknsk
    I've got the following code. sum_review = reduce(add,[book['rw'] for book in books]) sum_rating = reduce(add,[book['rg'] for book in books]) items = len(books) avg_review = sum_review/items avg_rating = sum_rating/items What I'd like is this. sum_review,sum_rating = reduce(add,([book['rw'],[book['rg']) for book in books]) items = len(books) avg_review = sum_review/items avg_rating = sum_rating/items Obviously this doesn't work. How can I solve this redundancy, without a regular loop?

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  • How do I override file.write() under Python 3?

    - by Sorin Sbarnea
    Below works on Python 2.6 but on Python 3.x it doesn't: old_file_write = file.write class file(): def write(self, d): if isinstance(d, types.bytes): self.buffer.write(d) else: old_file_write(d) # ... do something like f = open("x") f.write("...") The problems is that with Python 3.x the first like will generate an error: NameError: name 'file' is not defined How can I make this work on Python 3.x? PS. In fact I'm looking for a solution that will work on both versions.

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  • Accessing parent class attribute from sub-class body

    - by warwaruk
    I have a class Klass with a class attribute my_list. I have a subclass of it SubKlass, in which i want to have a class attribute my_list which is a modified version of the same attribute from parent class: class Klass(): my_list = [1, 2, 3] class SubKlass(Klass): my_list = Klass.my_list + [4, 5] # this works, but i must specify parent class explicitly #my_list = super().my_list + [4, 5] # SystemError: super(): __class__ cell not found #my_list = my_list + [4, 5] # NameError: name 'my_list' is not defined print(Klass.my_list) print(SubKlass.my_list) So, is there a way to access parent class attribute without specifying its name?

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  • How to write a list to a text file in the correct format

    - by lia1000
    I've got this piece of code that I want to write the output to a text file but with the correct format i.e. no brackets, single quotes so it appears as a formatted list. This is the code: file = open("env5.txt", "w"); for key in os.environ.keys(): env = os.environ[key]; key1 = key; list = str([key, env]).replace("'","").replace('[]', ''); list2 = list[1:-1]; print(list2); file.writelines(list2); file.close(); This is the original code: for key in os.environ.keys(): print(key, os.environ[key]); Many thanks

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  • Set the right two characters (if there are any) to capitals?

    - by Hyflex
    Below is my data: Data Here 94/452O Data more 94/4522i Data bla 94/111 Data bla 94/459es Data bla 94/444 items is automatically generated by some previous code but it could come out like: items = ["Data Here 94/452O", "Data more 94/4522i", "Data bla 94/111", "Data bla 94/459es", "Data bla 94/444"] Now currently I'm appending the following: "\n".join(items).replace("4ke", "9") with a few other .replaces however I want it to replace/change the characters on the end of the numbers with a capital letter instead of lowercase... Output: Data Here 94/452O Data more 94/4522I Data bla 94/111 Data bla 94/459ES Data bla 94/444

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  • wrap all lines that are longer than line length

    - by user1919840
    I am writing a program that limits each line to a certain length. this is what i got so far, i am almost done but i still need to cut each line, but i cant figure it out. def main(): filename = input("Please enter the name of the file to be used: ") openFile = open(filename, 'r+') file = openFile.read() lLength = int(input("enter a number between 10 & 20: ")) while (lLength < 10) or (lLength > 20) : print("Invalid input, please try again...") lLength = int(input("enter a number between 10 & 20: ")) wr = textwrap.TextWrapper() wraped = wr.wrap(file) print("Here is your output formated to a max of", lLength, "characters per line: ") wr.width = lLength wr.expand_tabs = True for lines in wraped: print(lines) an example of what the output SHOULD be is this. If the file specified contains this text: hgytuinghdt #here the length is 11 ughtnjuiknshfyth #here the length is 16 nmjhkaiolgytuhngjuin #here the length is 20 and the lLength is specified to 15 then this should print out: hgytuinghdt ughtnjuiknshfyt h nmjhkaiolgytuhng juin Thanks.

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  • list within a list

    - by atm atm
    I'm working on this problem, but I cannot figure out the second part. I tried using reverse list but it did not work out how I planned it. Given a list L (e.g. [1,2,3,4]), write a program that generates the following nested lists: L1 = [[1],[1,2],[1,2,3],[1,2,3,4]], L2 = [[4],[3,4],[2,3,4],[1,2,3,4]]. My code that I have so far: mylist=[,1,2,3,4] print("Orginal list L=",mylist) n=len(mylist) l1=[] l2=[] for x in range(1,n+1,1): l1.append(mylist[0:x]) print("L1=",l1) #prints final product of l1 mylist.reverse() #this is where i get messed up for x in range(1,n+1,1): l2.append(mylist[0:x]) print("L2=",l2)

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  • Removing words from a file

    - by user1765792
    I'm trying to take a regular text file and remove words identified in a separate file (stopwords) containing the words to be removed separated by carriage returns ("\n"). Right now I'm converting both files into lists so that the elements of each list can be compared. I got this function to work, but it doesn't remove all of the words I have specified in the stopwords file. Any help is greatly appreciated. def elimstops(file_str): #takes as input a string for the stopwords file location stop_f = open(file_str, 'r') stopw = stop_f.read() stopw = stopw.split('\n') text_file = open('sample.txt') #Opens the file whose stop words will be eliminated prime = text_file.read() prime = prime.split(' ') #Splits the string into a list separated by a space tot_str = "" #total string i = 0 while i < (len(stopw)): if stopw[i] in prime: prime.remove(stopw[i]) #removes the stopword from the text else: pass i += 1 # Creates a new string from the compilation of list elements # with the stop words removed for v in prime: tot_str = tot_str + str(v) + " " return tot_str

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  • Jython 'unknown enocoding ms932' on japanese system

    - by Houtman
    i've written a program in Jython 2.5.1 which works fine on my Windows 7 machine, but on a japanese machine it throws an Exception saying "unknown encoding 'ms932'" i found that codecs.java is the only module printing the unknown encoding 'xyz' message this file loads aliases.py which does contain # cp932 codec '932' : 'cp932', 'ms932' : 'cp932', 'mskanji' : 'cp932', 'ms_kanji' : 'cp932', The file cp932.py contains import _codecs_jp, codecs But.. _codecs_jp does not exist as is also discussed in this page Does anyone have a clue where to go from here ? http://web.archiveorange.com/archive/v/8tc1Zc2rV3qiUcy9zPlA

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  • Empty value when iterating a dictionary with .iteritems() method

    - by ptpatil
    I am having some weird trouble with dictionaries, I am trying to iterate pairs from a dictionary to pass to another function. The loop for the iterator though for some reason always returns empty values. Here is the code: def LinktoCentral(self, linkmethod): if linkmethod == 'sim': linkworker = Linker.SimilarityLinker() matchlist = [] for k,v in self.ToBeMatchedTable.iteritems(): matchlist.append(k, linkworker.GetBestMatch(v, self.CentralDataTable.items())) Now if I insert a print line above the for loop: matchlist = [] print self.ToBeMatchedTable.items() for k,v in self.ToBeMatchedTable.iteritems(): matchlist.append(k, linkworker.GetBestMatch(v, self.CentralDataTable.items())) I get the data that is supposed to be in the dictionary printed out. The values of the dictionary are list objects. An example tuple I get from the dictionary when printing just above the for loop: >>> (1, ['AARP/United Health Care', '8002277789', 'PO Box 740819', 'Atlanta', 'GA', '30374-0819', 'Paper', '3676']) However, the for loop gives empty lists to the linkworker.GetBestMatch method. If I put a print line just below the for loop, here is what I get: Code: matchlist = [] for k,v in self.ToBeMatchedTable.iteritems(): print self.ToBeMatchedTable.items() matchlist.append(k, linkworker.GetBestMatch(v, self.CentralDataTable.items())) ## Place holder for line to send match list to display window return matchlist Result of first iteration: >>> (0, ['', '', '', '', '', '', '', '']) I literally have no idea whats going on, there is nothing else going on while this loop is executed. Any stupid mistakes I made?

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  • process the data after using str.split

    - by juju
    I parse a .txt like this: def parse_file(src): for line in src.readlines(): if re.search('SecId', line): continue else: cols = line.split(',') Time = cols[4] output_file.write('{}\n'.format( Time)) I think cols are lists that I could use index. Although it succeeds in printing out correct result as I want, there exists an out of range error. What's the matter? File "./tdseq.py", line 37, in parse_file Time = cols[4] IndexError: list index out of range make: *** [all] Error 1 Data I use: I10.FE,--,2008-04-16,15:15:00,13450,13488,13450,13470,490,359,16APR2008:09:15:00 I10.FE,--,2008-04-16,15:16:00,13468,13473.8,13467,13467,306,521,16APR2008:09:16:00 ....

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  • How to install port versions of perl modules for perl5.14 in freebsd 9.0

    - by jm666
    Trying to use perl5.14 on Freebsd with port based p5-modules. uname -impr 9.0-RELEASE amd64 amd64 ALTQ delete all installed ports, start with a clean system # pkg_delete -a # rm -rf /var/db/pkg /var/db/ports /usr/local installing portmaster, checking /etc/make.conf (here is only WITHOUT_X11=YES). Now installing perl. # portmaster -g --force-config lang/perl5.14 # perl -v This is perl 5, version 14, subversion 2 (v5.14.2) built for amd64-freebsd-multi Now perl modules from the ports, # portmaster -g devel/p5-Moose #install Moose and its deps check with pkg_info and got zilion errors like: # pkg_info pkg_info: corrupted record (pkgdep line without argument), ignoring dpendecy check with portmaster - showing dependecies on perl5.12 #portmaster --check-depends Checking p5-Class-C3-0.24 ===>>> lang/perl5.12 is listed as a dependency ===>>> but there is no installed version ===>>> Delete this dependency data? y/n [n] when tried # perl-after-upgrade -f got: Fixed 0 packages (0 files moved, 0 files modified) In short: i got installed Moose into /usr/local/lib/perl5/site_perl/5.14.2/ but all its dependencies into /usr/local/lib/perl5/site_perl/5.12.4/ Yes, it is possible fix this with: # portmaster p5- what reinstall all installed p5-packages once again, now correctly for the 5.14 but it is terrible installing them twice... Questions: What is the correct way install p5-MODULES from ports with installed perl5.14 in an clean system? How to fix wrong dependency data on perl5.12 without the need install and reinstall them again What i'm doing wrong? Ps: know perlbrew and/or Local::lib - but for this case - want port versions.

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