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  • PHP Form (post) Repeating input in a tabel

    - by Sef
    Hello, I have a form (with post method) that takes the following input: - a certain name - a number - 3 checkboxes All this input gets generated and calculated in a table.(html code within the php) Everything gets properly calculated and displayed in a table. So my question: How do i make it possible after giving all those input to give in more input? Meaning i have made a hyperlink that goes back to the form itself (where i can give the input). So i can give in new data, and after submiting that again the table now contains 2 rows of values insteed of just 1. Not really sure what exactly i need for this. Regards.

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  • How to get the duration of the video uploaded ?

    - by Holicreature
    i'm using ffmpeg to convert videos to desired formats and to generate the thumbnails.. I want to find the total duration of the video to display in the main page along with the thumbnails.. Can i use ffmpeg to find the duration when its being uploaded and store them on the database.? Is storing the duration in db is necessary or else is there any other method?

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  • How to remove background of a image and copy into another?

    - by Gustavo Pinent
    I'm researching about captchas. In this idea, the task is: create a image from a JPEG and remove the white background, than create another image from another JPEG, than create the final image by adding the second as a background, and copying the first one over this background preserving the transparent area created, of course. Here is the code: header("Content-Type: image/jpeg"); $nFundo = rand(0,4); $Dirs = array(rand(0,7), rand(0,7), rand(0,7), rand(0,7)); // Will be four times all $_SESSION["form_captcha"] = $Dirs; $image = ImageCreatetruecolor(320, 80); ImageAlphaBlending($image, FALSE); ImageSaveAlpha($image, TRUE); $image_seta = ImageCreateFromJPEG("_captcha-seta.jpg"); // Image do copy over $image_fundo = ImageCreateFromJPEG("_captcha-fundo-".$nFundo.".jpg"); // Image to make the background for($i=0; $i<4; $i++){ ImageCopy($image, $image_fundo, $i*80, 0, 0, 0, 80, 80); } // So far so good, a background with a pattern repeated four times $color_white = ImageColorAllocate($image_seta, 255, 255, 255); ImageColorTransparent($image_seta, $color_white); ImageSaveAlpha($image_seta, TRUE); for($i=0; $i<4; $i++){ $image_seta_rot = imageRotate($image_seta, $Dirs[$i]*45, $color_white); ImageCopyResampled($image, $image_seta_rot, $i*80, 0, 0, 0, 80, 80, 80, 80); // Try } echo(imagejpeg($image)); imagedestroy($image); I tried to replace $image_seta_rot by $image_seta ("Try" line) to see if the rotation is the problem, but even without rotation, the white wasn't removed and the image just "erase" the background created before. So the copy is failing or the white were never removed... I may create a PNG with transparent background, but will be interesting to learn how to make it dynamically, don't you think? Any ideas?

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  • AJAX - how to make autocomplete/autosuggestion and show results outside form, in table

    - by michael85
    hello im trying to make a simple page with search engine. i read, that if i want to implement autocomplete/autosuggest with form, i have to use ajax. thats ok for me. there are a lot solutions on the intenret, but unfortunetly all of them is the same script :/ and thats fine for me :) but i want to go further. i want to show autosuggest results in table for example below search form. the data is stored in a simple array (eventualy, source mysql) i know that kind of script isnt easy to write, so i ask you to give me a hint or something. trivial solution is use php, but this needs submit button. help, im stuck :)

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  • file_get_contents to image and change quality

    - by Chris
    Hey I have some code that downloads an image from a remote server $data = file_get_contents("$rURL"); I want to then change the quality of this image, but do not want to save it out to a file first, how do I convert $data into an image that I can then use in imagecopyresampled? Thanks

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  • How to resubmit PHP form with javascript

    - by user866339
    I am wondering if it is possible to to resubmit a form with a button click that calls up a javascript command. So this is basically what I'm trying to do - page 1: form; action = page2.php page 2: generate a randomized list according to parameters set by page 1 I would like to place a button on page 2 so that on click, it would be as if the user has hit F5, and a new list would be generated with the same parameters. I found a lot of help on Google with people trying NOT to get this to happen, but I'm not sure how to actually get it to happen..... Thank you!

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  • PHP Templated site w/ file_get_content links

    - by s32ialx
    Ok so i have a template script my friend built for me. I'll include all file names OK so what is not working is file_get_contents is not grabing the content (1 I don't know where the content should be placed and 2 i want it placed in a directory so that IF i change the template the area where content stays is the same. I'm trying to get file_get_contents to load the links ?=about ?=services etc to load in to body.tpl in the contents div please any help is apperciated. /* file.class.php */ <?php $file = new file(); class file{ var $path = "templates/clean"; var $ext = "tpl"; function loadfile($filename){ return file_get_contents($this->path . "/" . $filename . "." . $this->ext); } function css($val,$content='',$contentvar='#CSS#') { if(is_array($val)) { $css = 'style="'; foreach($val as $p) { $css .= $p . ";"; } $css .= '"'; } else { $css = 'style="' . $val . '"'; } if($content!='') { return str_replace($contentvar,' ' . $css,$content); } else { return $css; } } function setsize($content,$width='-1',$height='-1',$border='-1'){ $css = ''; if($width!='-1') { $css = $css . "width=\"".$width."\""; } if($height!='-1') { $css = $css . "height=\"".$height."\""; } if($border!='-1') { $css = $css . "border=\"" . $border . "\""; } return str_replace('#SIZE#',' ' . $css,$content); } function setcontent($content,$newcontent,$vartoreplace='#CONTENT#'){ $val = str_replace($vartoreplace,$newcontent,$content); return $val; } function p($content) { $v = $content; $v = str_replace('#CONTENT#','',$v); $v = str_replace('#SIZE#','',$v); print $v; } } if (isset($_GET['page'])) { $content = $_GET['page'].'.php'; } else { $content = 'main.php'; } ?> if some one could trim that down so it JUST is the template required code and file get contents. /* index.php */ <?php include('classes/file.class.php'); //load template content $header = $file->loadfile('header'); $body = $file->loadfile('body'); $footer = $file->loadfile('footer'); //assign content to multiple variables $file->p($header . $body . $footer); ?> /* header.tpl */ <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/> <meta name="robots" content="index,follow"/> <meta name="distribution" content="global"/> <meta name="description" content=""/> <meta name="keywords" content=""/> <link href="templates/clean/style.css" rel="stylesheet" type="text/css" media="screen" /> <link rel="stylesheet" href="templates/clean/menu_style.css" type="text/css" /> <script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.2.min.js"></script> </head> <body> <div id="header"> <div id="logo"><a href="index.php" style="height:30px;width:150px;"><img src="images/logo.png" border="0" alt=""/></a></div> <div id="menuo"> <div class="menu"> <ul id="menu"> <li><a href="?page=home">Home</a></li> <li><a href="?page=about">About Us</a></li> <li><a href="?page=services">Services</a> <ul> <li><a href="?page=instore">InStore Repairs</a></li> <li><a href="?page=inhome">InHome Repairs</a></li> <li><a href="?page=website">Website Design</a></li> <li><a href="?page=soon">Comming Soon.</a></li> </ul> </li> <li><a href="?page=products">Products</a> <ul> <li><a href="?page=pchard">Computer Hardware</a></li> <li><a href="?page=monitor">Monitor's</a></li> <li><a href="?page=laptop">Laptop + Netbooks</a></li> <li><a href="?page=soon">Comming Soon.</a></li> </ul> </li> <li><a href="?page=contact">Contact</a></li> </ul> </div> </div> </div> <div id="headerf"> </div> /* body.tpl */ <div id="bodys"> <div id="bodt"></div> <div id="bodm"> <div id="contents"> #CONTENT# </div> /* footer.tpl */ <div id="footer"> <div style="position:absolute; top:4px; left:4px;"><img src="images/ff.png" alt="ok"></div> <div style="position:absolute; top:4px; right:5px; color:#FFFFFF;">&copy;2010 <a href="mailto:">Company Name</a></div> </div> </body> </html>

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  • php syntax error

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • PHP syntax error “unexpected $end”

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • extra configuration needed after installing SSL certificate?

    - by ptriek
    We recently developed two rather simple PHP applications for AXA (European bank). URL's are axa.tfo.be/incentives/cipres and axa.tfo.be/incentives/zrkk (access to both sites is restricted to visitors with cookies with encrypted passwords) On a previous security audit by an external company several security issues have been found. All these issues have been solved by a collleague PHP developer. However, one last requirement has been added - all data should be transfered over https. My php collegue is on holiday, however - and unavailable at the moment. So I contacted my host, and asked for installing SSL certificate. I myself have no knowledge/experience with SSL, so I'm a bit at loss for the following problems. Comodo SSL certificate + unique IP address has been installed today by my webhost for subdomain axa.tfo.be (by www.combell.be). However, it doesn't seem to be working. I posted a question about this earlier today, and was told not to worry, see link: http://serverfault.com/questions/339320/what-happens-if-you-install-an-ssl-certificate Current problems: the web applications aren't accessible over https, http works though (if a valid cookie is available) there's a static html page at http://axa.tfo.be/incentives/cipres/static.html, even that page is only accessible over http My webhost is telling me that 'my application probably doesn't support SSL', and has asked me to set an SSL variable to true in my php code. So my questions: I have basic knowledge of php, but don't know where to start regarding the 'php ssl variable'. The sites have been online for some time, and have been developed for regular php access. (Google didn't bring me any help, either.) Can anyone point me in the right direction, or give me some clues about whether/what I should ask my webhost for further assistance? (I'm a bit on a tight schedule, the sites will be audited again on monday, and it's a customer i wouldn't want to loose...) Thanks for looking into this, and sorry if my questions sound a bit nooby - I'm a webdesigner, not a server specialist...

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  • Web developing- Strange happenings

    - by Jason
    As I'm teaching myself PHP and MySQL during break, I'm experimenting coding in a Ubuntu virtual machine where Apache, MySQL and PHP have been installed and configured to a shared folder. I'm not a big fan of Kompozer because the source code layout is a PIA, so I've started checking out gPHPEdit. However, since using it, I've come across two issues: when I edit the .html and .php files, sometimes the file extension will change to .html~ and .php~, becoming invisible to the browser. The only solution is to switch to Windows, right click and rename the file extension. In Ubuntu Firefox, when I click on my prpject's Submit button for in a practice form, a dialog box pops up asking what Firefox should do with the .php file, rather than simply displaying it in the browser. When I do this in Windows Chrome & Firefox, it goes right to the response page. I'm not sure if this behavior is limited to gPHPEdit/Kompozer, but I've never noticed this happening in Dreamweaver. Any solutions? EDIT The behavior in Point 1 occurs both when Dreamweaver is open in Windows accessing the same files and when it is not. I changed the extension filename of welcome.php, added a comment in gPHPEdit, and the file changed to welcome.php~ upon saving.

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  • Which open source PHP project has the 'perfect' OOP design I can learn from?

    - by aditya menon
    I am a newbie to OOP, and I learn best by example. You could say this question is similar to Which Scala open source projects should I study to learn best coding practices - but in PHP. I have heard-tell that Symfony has the best 'architecture' (I will not pretend I know what that exactly means), as well as Doctrine ORM. Is it worth it to spend many months reading the source code of these projects, trying to deduce the patterns used and learning new tricks? I have seen equal number of web pages dissing and liking Zend's codebase (will provide links if deemed necessary). Do you know of any other project that would make any veteran OOP developer shed tears of joy? Please let me add that practicality and scope of use is not a concern at all here - I just want to do: Pick a project that has a codebase deemed awesome by devs way better and greater than me. Write code that achieves what the project does. Compare results and try to learn what I don't know. Basically, an academic interest codebase. Any recommendations please?

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  • Xdebug 2.0.5 with Zend Server CE PHP5.2.12 possible?

    - by notbrain
    I'm using Zend Server CE with PHP 5.2.12 on OSX Snow Leopard and want to use Xdebug. I've turned off Zend Data Cache, Zend Optimizer+, and Zend Debugger in the console. When I run $ cd ~/Downloads/xdebug-2.0.5 $ /usr/local/zend/bin/phpize I get Configuring for: PHP Api Version: 20041225 Zend Module Api No: 20060613 Zend Extension Api No: 220060519 The PHP API Version, 20041225, seems to be off from the documentation (aka wrong). When I continue installation with $ ./configure ---with-php-config=/usr/local/zend/bin/php-config $ make $ sudo make install The installed xdebug.so seems to be the wrong one. Which version of xdebug do I need for this PHP API version? The Zend API numbers are ok. I'm just confused at why the PHP API Version doesn't match. PHP Warning: PHP Startup: Unable to load dynamic library '/usr/local/zend/lib/php_extensions/xdebug.so' - (null) in Unknown on line 0 PHP 5.2.12 (cli) (built: Feb 17 2010 13:39:36)

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  • Using default parameters for 404 error (PHP with mvc design)?

    - by user1175327
    I have a custom made Framework (written in PHP). It all works very good, but i have some doubts about a certain thing. Right now when a user call this url for example: http://host.com/user/edit/12 Which would resolve to: user = userController edit = editAction() in userController 12 = treated as a param But suppose the controller 'userController' doesn't exist. Then i could throw a 404. But on the other hand, the url could also be used as params for the indexController (which is the default controller). So in that case: controller = indexController user = could be an action in indexController, otherwise treated as a param edit = treated as a param 12 = treated as a param That is actually how it works right now in my framework. So basically, i never throw a 404. I could ofcourse say that only params can be given if the controller name is explicitly named in the URL. So if i want the above url: http://host.com/user/edit/12 To be invoked by the indexController, in the indexAction. Then i specifically have to tell what controller and action it uses in the URL. So the URL should become: http://host.com/index/index/user/edit/12 index = indexController index (2nd one) = the action method user = treated as a param edit = treated as a param 12 = treated as a param That way, when a controller doesn't exist, i don't reroute everything as a param to the index controller and simply throw a 404 error. Now my question is, which one is more preffered? Should i allow both options to be configurable in a config file? Or should i always use one of them. Simply because that's the only and best way to do it?

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  • How to integrate a PHP CMS with paypal so that only users who completed a payment can register and authenticate?

    - by ibiza
    I am currently using a PHP CMS - cmsmadesimple - in order to create a website where services will be sold. I intend to use Paypal 'Buy Now' buttons in order to offer a few packages that will be renewable every 1-month or every 3-months and that grant access to the secure content of the website for a given period of time. Everything is going well so far but I am somewhat at loss for the user registration process as I have a few constraints I would like to use and it would be nice to automate the process if possible. Here are the constraints : User should be able to register to my website and choose a password himself Only users that paid should be able to register Access permissions should be disabled automatically after the service period if the package is not renewed And here is the process which I am thinking of : User clicks 'buy' on my website User is redirected on Paypal and completes the payment The paypal email used to pay should be returned to my server and somehow stored If it is a new email, user needs to register to my website (else if it is a returning customer, the deactivation flag for payment stopped should be removed to give back access) If a user does not renew his subscription, there should be a deactivation flag automatically set to the email used in order to lock access until next payment. Ideally, no human intervention is needed. What is the best way to implement all this? I am a bit at loss. I found this article that explained a few things and even has a nice code snippet, except that I'm not sure where to plug it. Thanks all

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  • How (and when) to move users to mysqli and PDO_MYSQL?

    - by cj
    An important discussion on the PHP "internals" development mailing list is taking place. It's one that you should take some note of. It concerns the next step in transitioning PHP applications away from the very old mysql extension and towards adopting the much better mysqli extension or PDO_MYSQL driver for PDO. This would allow the mysql extension to, at some as-yet undetermined time in the future, be removed. Both mysqli and PDO_MYSQL have been around for many years, and have various advantages: http://php.net/manual/en/mysqlinfo.api.choosing.php The initial RFC for this next step is at https://wiki.php.net/rfc/mysql_deprecation I would expect the RFC to change substantially based on current discussion. The crux of that discussion is the timing of the next step of deprecation. There is also discussion of the carrot approach (showing users the benfits of moving), and stick approach (displaying warnings when the mysql extension is used). As always, there is a lot of guesswork going on as to what MySQL APIs are in current use by PHP applications, how those applications are deployed, and what their upgrade cycle is. This is where you can add your weight to the discussion - and also help by spreading the word to move to mysqli or PDO_MYSQL. An example of such a 'carrot' is the excellent summary at Ulf Wendel's blog: http://blog.ulf-wendel.de/2012/php-mysql-why-to-upgrade-extmysql/ I want to repeat that no time frame for the eventual removal of the mysql extension is set. I expect it to be some years away.

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  • php.ini modifications has no effect on joomla

    - by user488736
    I have a netbook with a recently installed ubuntu server 12.04 64-bit. I have (only) installed Joomla on it (version 2.5) and now I am trying to tweak the php.ini settings so I can install jomsocial onto joomla. I have changed these settings: upload_max_filesize = 2M post_max_size = 8M to this: upload_max_filesize = 20M post_max_size = 20M in all php.ini-files in my system. Thats six files, found using 'locate': /etc/php5/apache2/php.ini /etc/php5/cli/php.ini /usr/share/doc/php5-common/examples/php.ini-development /usr/share/php5/php.ini-production /usr/share/php5/php.ini-production-dist /usr/share/php5/php.ini-production.cli I have double-checked that these files actually contain the new settings. Still, joomla does not recognize the new settings, stating that upload_max_filesize is still only 2M and post_max_size is still only 8M The same is true after a complete restart of the server. What am I doing wrong here?

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  • Do objects maintain identity under all non-cloning conditions in PHP?

    - by Buttle Butkus
    PHP 5.5 I'm doing a bunch of passing around of objects with the assumption that they will all maintain their identities - that any changes made to their states from inside other objects' methods will continue to hold true afterwards. Am I assuming correctly? I will give my basic structure here. class builder { protected $foo_ids = array(); // set in construct protected $foo_collection; protected $bar_ids = array(); // set in construct protected $bar_collection; protected function initFoos() { $this->foo_collection = new FooCollection(); foreach($this->food_ids as $id) { $this->foo_collection->addFoo(new foo($id)); } } protected function initBars() { // same idea as initFoos } protected function wireFoosAndBars(fooCollection $foos, barCollection $bars) { // arguments are passed in using $this->foo_collection and $this->bar_collection foreach($foos as $foo_obj) { // (foo_collection implements IteratorAggregate) $bar_ids = $foo_obj->getAssociatedBarIds(); if(!empty($bar_ids) ) { $bar_collection = new barCollection(); // sub-collection to be a component of each foo foreach($bar_ids as $bar_id) { $bar_collection->addBar(new bar($bar_id)); } $foo_obj->addBarCollection($bar_collection); // now each foo_obj has a collection of bar objects, each of which is also in the main collection. Are they the same objects? } } } } What has me worried is that foreach supposedly works on a copy of its arrays. I want all the $foo and $bar objects to maintain their identities no matter which $collection object they become of a part of. Does that make sense?

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  • Init script & the green [ OK ]

    - by Lord Loh.
    I am trying to install fast-cgi for nginx on an EC2 instance. I followed the steps explained here, but that is meant for Debian and does not work out of the box for a red-hat based system. I modified the script a bit to look like - #!/bin/bash ### BEGIN INIT INFO # Provides: php-fcgi # Required-Start: $nginx # Required-Stop: $nginx # Default-Start: 2 3 4 5 # Default-Stop: 0 1 6 # Short-Description: starts php over fcgi # Description: starts php over fcgi ### END INIT INFO . /etc/rc.d/init.d/functions (( EUID )) && echo .You need to have root priviliges.. && exit 1 BIND=/tmp/php.socket USER=nginx PHP_FCGI_CHILDREN=15 PHP_FCGI_MAX_REQUESTS=1000 PHP_CGI=/usr/bin/php-cgi PHP_CGI_NAME=`basename $PHP_CGI` PHP_CGI_ARGS="- USER=$USER PATH=/usr/bin PHP_FCGI_CHILDREN=$PHP_FCGI_CHILDREN PHP_FCGI_MAX_REQUESTS=$PHP_FCGI_MAX_REQUESTS $PHP_CGI -b $BIND" RETVAL=0 start() { echo -n "Starting PHP FastCGI: " #ORIGINAL LINE #daemon $PHP_CGI --quiet --start --background --chuid "$USER" --exec /usr/bin/env -- $PHP_CGI_ARGS #MODIFIED LINE daemon --user=$USER $PHP_CGI -b $BIND& RETVAL=$? echo [ $RETVAL -eq 0 ] && touch /var/lock/subsys/php-fcgi #echo "$PHP_CGI_NAME." } stop() { echo -n "Stopping PHP FastCGI: " killall -q -w -u $USER $PHP_CGI RETVAL=$? echo "$PHP_CGI_NAME." rm /var/lock/subsys/php-fcgi } case "$1" in start) start ;; stop) stop ;; restart) stop start ;; *) echo "Usage: php-fastcgi {start|stop|restart}" exit 1 ;; esac exit $RETVAL The problem I have now is - service php-fcgi start keeps the shell blocked. If I run service php-fcgi start & and then ps aux, I see the php-cgi process running bound to the socket. I see the start command stop only when I execute service php-fcgi stop. How do I solve this blocking issue? I have tried adding an & at the end of the line spawning the daemon. But other scripts do not seem to be doing this. This is the most complicated script I am attempting to modify yet :-( How do I get the script to display the green [ OK ]? I checked scripts like httpd and saw that all they were doing was something as shown below. But I never see a green [ OK ] when I execute php-fcgi. I also discovered that putting echo_success with functions sourced displays the green [ OK ] but I do not see any other scripts in the /etc/rc.d/init.d/ executing echo_success or echo_failure. What have I got wrong? Also, How do i specify PHP_FCGI_CHILDREN with daemon? echo [ $RETVAL -eq 0 ] && touch /var/lock/subsys/

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  • If Variable = True show this, else show this [on hold]

    - by Tim Marshall
    If my variable of $userLoggedIn is true, the <?php if ($userLoggedIn == 'true') : ?> works perfect, however if the variable is false, the <?php if ($userLoggedIn == 'false') : ?> does not work at all. How do I resolve this problem? <?php $EditingWagesPage = false; $userLoggedIn = false; ?> <!DOCTYPE html> <!--[if IE 8]> <html lang="en" class="ie8 no-js"> <![endif]--> <!--[if IE 9]> <html lang="en" class="ie9 no-js"> <![endif]--> <!--[if !IE]><!--> <html lang="en" class="no-js"> <!--<![endif]--> <!-- BEGIN HEAD --> <?php if ($userLoggedIn == 'true') : ?> <head> ** HEADER STUFF ** </head> <body> ** BODY STUFF ** </body> <?php endif;?> <?php if ($userLoggedIn == 'false') : ?> <head> </head> <body> hiya </body> <?php endif;?> </html>

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  • Tracking form abandonment

    - by Alec Sanger
    I'm looking for a decent way to track form abandonment. Ideally, I would like to see how many people start filling out a form but do not complete it, as well as the last field that was filled out. The website is a fairly large Wordpress site with quite a few forms. Some of these forms are to register for events, some are for donations, some are for information requests. My first attempt at this was adding a generic jquery that bound functions to all forms on the site. When a form element was blurred, I would trigger a Google Analytics event with the name of the form, the name of the field, and whether or not it was filled. I expected to be able to go to the Event Flow section in Google Analytics and see the flow of these form events, however since there are so many forms and other events occurring on the website, Google wouldn't let me break them out very well. The other issue was the Quform doesn't name their fields anything relevant, and it doesn't look like we can name them ourselves. This results in a lot of ugly form names that don't mean anything without cross-referencing the actual form. Does anybody have any suggestions on how I can achieve more usable form abandonment metrics in a scenario like this?

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  • Work @ Java shop. Tasked to redo intranet. I only know PHP - CTO says use that; Ops Says no - we have JSP, use that - Thoughts?

    - by Mackysback
    So I work as a project manager and was given the opportunity to redo the intranet and Internet site... I'd love to , great addition to my resume. However.... I am not familiar with java nor JSP... I am fairly proficient with PHP and MySQL ... Also my intention was to use a CMS that I have experience with, wordpress, drupal or joomla... The site would be very simple so I was thinking wordpress would be fine for this. I told management that I would need it to run on PHP and they gave me their blessing... Now the disconnect bw it and management ... I spoke with ops and they told me that we have java and JSP for that purpose although the IT guy did say "oh but I do know that php and mysql are gaining popularity" That said ... I do not understand much as far as systems architecture... We do self host and run websphere with IIS and jboss with tomcat. Any advice or suggestions? Thanks ! Is my request that unfeasible?

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  • what is standard approach to create a responsive website using javascript,php ajax and perhaps zend framework [closed]

    - by shawndreck
    I am working on a web system currently and plans to heavily use javascript with ajax to make the user interface more friendlier, not fancy as such. The javascript will be used for client side form validation, data loading from server and creating proper content with the result, also to for floating windows during add/edit or external references. Here is a scenerio that could clearify my question. A user wants to update card but instead of jumping to another page to verify the available colors,size and prizes of product, those information are shown in a floating window and changes in the floating window can affect the underlying one. My question is : 1. What are some of the approaches to encounter this situation? 2. Are there any helpful tips, tricks and links on this subject? I am comfortable with js,php and zend. I would appreciate any advice,tip and tricks, problem solving approach to handle a situation like this! Thanks in advance. Hope this make sense.

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