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  • assign operator to variable in python?

    - by abhilashm86
    Usual method of applying mathematics to variables is a * b Is it able to calculate and manipulate two operands like this? a = input('enter a value') b = input('enter a value') op = raw_input('enter a operand') then how do i connect op and two variables a and b?? i know i can compare op to +, -, %, $ and then assign and compute.... but can i do something like a op b , how to tell compiler that op is an operator?? any tweaks possible?

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  • Fast iterating over first n items of an iterable (not a list) in python

    - by martinthenext
    Hello! I'm looking for a pythonic way of iterating over first n items of an iterable (upd: not a list in a common case, as for lists things are trivial), and it's quite important to do this as fast as possible. This is how I do it now: count = 0 for item in iterable: do_something(item) count += 1 if count >= n: break Doesn't seem neat to me. Another way of doing this is: for item in itertools.islice(iterable, n): do_something(item) This looks good, the question is it fast enough to use with some generator(s)? For example: pair_generator = lambda iterable: itertools.izip(*[iter(iterable)]*2) for item in itertools.islice(pair_generator(iterable), n): so_something(item) Will it run fast enough as compared to the first method? Is there some easier way to do it?

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  • Python nested function scopes

    - by Thomas O
    I have code like this: def write_postcodes(self): """Write postcodes database. Write data to file pointer. Data is ordered. Initially index pages are written, grouping postcodes by the first three characters, allowing for faster searching.""" status("POSTCODE", "Preparing to sort...", 0, 1) # This function returns the key of x whilst updating the displayed # status of the sort. ctr = 0 def keyfunc(x): ctr += 1 status("POSTCODE", "Sorting postcodes", ctr, len(self.postcodes)) return x sort_res = self.postcodes[:] sort_res.sort(key=keyfunc) But ctr responds with a NameError: Traceback (most recent call last): File "PostcodeWriter.py", line 53, in <module> w.write_postcodes() File "PostcodeWriter.py", line 47, in write_postcodes sort_res.sort(key=keyfunc) File "PostcodeWriter.py", line 43, in keyfunc ctr += 1 UnboundLocalError: local variable 'ctr' referenced before assignment How can I fix this? I thought nester scopes would have allowed me to do this. I've tried with 'global', but it still doesn't work.

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  • Python halts while iteratively processing my 1GB csv file

    - by Dan
    I have two files: metadata.csv: contains an ID, followed by vendor name, a filename, etc hashes.csv: contains an ID, followed by a hash The ID is essentially a foreign key of sorts, relating file metadata to its hash. I wrote this script to quickly extract out all hashes associated with a particular vendor. It craps out before it finishes processing hashes.csv stored_ids = [] # this file is about 1 MB entries = csv.reader(open(options.entries, "rb")) for row in entries: # row[2] is the vendor if row[2] == options.vendor: # row[0] is the ID stored_ids.append(row[0]) # this file is 1 GB hashes = open(options.hashes, "rb") # I iteratively read the file here, # just in case the csv module doesn't do this. for line in hashes: # not sure if stored_ids contains strings or ints here... # this probably isn't the problem though if line.split(",")[0] in stored_ids: # if its one of the IDs we're looking for, print the file and hash to STDOUT print "%s,%s" % (line.split(",")[2], line.split(",")[4]) hashes.close() This script gets about 2000 entries through hashes.csv before it halts. What am I doing wrong? I thought I was processing it line by line. ps. the csv files are the popular HashKeeper format and the files I am parsing are the NSRL hash sets. http://www.nsrl.nist.gov/Downloads.htm#converter UPDATE: working solution below. Thanks everyone who commented! entries = csv.reader(open(options.entries, "rb")) stored_ids = dict((row[0],1) for row in entries if row[2] == options.vendor) hashes = csv.reader(open(options.hashes, "rb")) matches = dict((row[2], row[4]) for row in hashes if row[0] in stored_ids) for k, v in matches.iteritems(): print "%s,%s" % (k, v)

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  • In Python, urllib2 giving error

    - by pythBegin
    I tried running this, >>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') But it is giving error like this, can anyone tell me a solution ? Traceback (most recent call last): File "<pyshell#11>", line 1, in <module> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') File "C:\Python26\lib\urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "C:\Python26\lib\urllib2.py", line 391, in open response = self._open(req, data) File "C:\Python26\lib\urllib2.py", line 409, in _open '_open', req) File "C:\Python26\lib\urllib2.py", line 369, in _call_chain result = func(*args) File "C:\Python26\lib\urllib2.py", line 1161, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python26\lib\urllib2.py", line 1136, in do_open raise URLError(err) URLError: <urlopen error [Errno 11001] getaddrinfo failed>

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  • fit a ellipse in Python given a set of points xi=(xi,yi)

    - by Gianni
    I am computing a series of index from a 2D points (x,y). One index is the ratio between minor and major axis. To fit the ellipse i am using the following post when i run these function the final results looks strange because the center and the axis length are not in scale with the 2D points center = [ 560415.53298363+0.j 6368878.84576771+0.j] angle of rotation = (-0.0528033467597-5.55111512313e-17j) axes = [0.00000000-557.21553487j 6817.76933256 +0.j] thanks in advance for help import numpy as np from numpy.linalg import eig, inv def fitEllipse(x,y): x = x[:,np.newaxis] y = y[:,np.newaxis] D = np.hstack((x*x, x*y, y*y, x, y, np.ones_like(x))) S = np.dot(D.T,D) C = np.zeros([6,6]) C[0,2] = C[2,0] = 2; C[1,1] = -1 E, V = eig(np.dot(inv(S), C)) n = np.argmax(np.abs(E)) a = V[:,n] return a def ellipse_center(a): b,c,d,f,g,a = a[1]/2, a[2], a[3]/2, a[4]/2, a[5], a[0] num = b*b-a*c x0=(c*d-b*f)/num y0=(a*f-b*d)/num return np.array([x0,y0]) def ellipse_angle_of_rotation( a ): b,c,d,f,g,a = a[1]/2, a[2], a[3]/2, a[4]/2, a[5], a[0] return 0.5*np.arctan(2*b/(a-c)) def ellipse_axis_length( a ): b,c,d,f,g,a = a[1]/2, a[2], a[3]/2, a[4]/2, a[5], a[0] up = 2*(a*f*f+c*d*d+g*b*b-2*b*d*f-a*c*g) down1=(b*b-a*c)*( (c-a)*np.sqrt(1+4*b*b/((a-c)*(a-c)))-(c+a)) down2=(b*b-a*c)*( (a-c)*np.sqrt(1+4*b*b/((a-c)*(a-c)))-(c+a)) res1=np.sqrt(up/down1) res2=np.sqrt(up/down2) return np.array([res1, res2]) if __name__ == '__main__': points = [(560036.4495758876, 6362071.890493258), (560036.4495758876, 6362070.890493258), (560036.9495758876, 6362070.890493258), (560036.9495758876, 6362070.390493258), (560037.4495758876, 6362070.390493258), (560037.4495758876, 6362064.890493258), (560036.4495758876, 6362064.890493258), (560036.4495758876, 6362063.390493258), (560035.4495758876, 6362063.390493258), (560035.4495758876, 6362062.390493258), (560034.9495758876, 6362062.390493258), (560034.9495758876, 6362061.390493258), (560032.9495758876, 6362061.390493258), (560032.9495758876, 6362061.890493258), (560030.4495758876, 6362061.890493258), (560030.4495758876, 6362061.390493258), (560029.9495758876, 6362061.390493258), (560029.9495758876, 6362060.390493258), (560029.4495758876, 6362060.390493258), (560029.4495758876, 6362059.890493258), (560028.9495758876, 6362059.890493258), (560028.9495758876, 6362059.390493258), (560028.4495758876, 6362059.390493258), (560028.4495758876, 6362058.890493258), (560027.4495758876, 6362058.890493258), (560027.4495758876, 6362058.390493258), (560026.9495758876, 6362058.390493258), (560026.9495758876, 6362057.890493258), (560025.4495758876, 6362057.890493258), (560025.4495758876, 6362057.390493258), (560023.4495758876, 6362057.390493258), (560023.4495758876, 6362060.390493258), (560023.9495758876, 6362060.390493258), (560023.9495758876, 6362061.890493258), (560024.4495758876, 6362061.890493258), (560024.4495758876, 6362063.390493258), (560024.9495758876, 6362063.390493258), (560024.9495758876, 6362064.390493258), (560025.4495758876, 6362064.390493258), (560025.4495758876, 6362065.390493258), (560025.9495758876, 6362065.390493258), (560025.9495758876, 6362065.890493258), (560026.4495758876, 6362065.890493258), (560026.4495758876, 6362066.890493258), (560026.9495758876, 6362066.890493258), (560026.9495758876, 6362068.390493258), (560027.4495758876, 6362068.390493258), (560027.4495758876, 6362068.890493258), (560027.9495758876, 6362068.890493258), (560027.9495758876, 6362069.390493258), (560028.4495758876, 6362069.390493258), (560028.4495758876, 6362069.890493258), (560033.4495758876, 6362069.890493258), (560033.4495758876, 6362070.390493258), (560033.9495758876, 6362070.390493258), (560033.9495758876, 6362070.890493258), (560034.4495758876, 6362070.890493258), (560034.4495758876, 6362071.390493258), (560034.9495758876, 6362071.390493258), (560034.9495758876, 6362071.890493258), (560036.4495758876, 6362071.890493258)] a_points = np.array(points) x = a_points[:, 0] y = a_points[:, 1] from pylab import * plot(x,y) show() a = fitEllipse(x,y) center = ellipse_center(a) phi = ellipse_angle_of_rotation(a) axes = ellipse_axis_length(a) print "center = ", center print "angle of rotation = ", phi print "axes = ", axes from pylab import * plot(x,y) plot(center[0:1],center[1:], color = 'red') show() each vertex is a xi,y,i point plot of 2D point and center of fit ellipse

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  • Most efficient way to search the last x lines of a file in python

    - by Harley
    I have a file and I don't know how big it's going to be (it could be quite large, but the size will vary greatly). I want to search the last 10 lines or so to see if any of them match a string. I need to do this as quickly and efficiently as possible and was wondering if there's anything better than: s = "foo" last_bit = fileObj.readlines()[-10:] for line in last_bit: if line == s: print "FOUND"

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  • Reading Python Documentation for 3rd party modules

    - by Shadyabhi
    I recently downloaded IMDbpy moduele.. When I do, import imdb help(imdb) i dont get the full documentation.. I have to do im = imdb.IMDb() help(im) to see the available methods. I dont like this console interface. Is there any better way of reading the doc. I mean all the doc related to module imdb in one page..

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  • Importing files in Python from __init__.py

    - by Federico Builes
    Suppose I have the following structure: app/ __init__.py foo/ a.py b.py c.py __init__.py a.py, b.py and c.py share some common imports (logging, os, re, etc). Is it possible to import these three or four common modules from the __init__.py file so I don't have to import them in every one of the files? Edit: My goal is to avoid having to import 5-6 modules in each file and it's not related to performance reasons.

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  • Write xml file using lxml library in Python

    - by systempuntoout
    I'm using lxml to create an XML file from scratch; having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • Python lambda returning None instead of empty string

    - by yoshi
    I have the following lambda function: f = lambda x: x == None and '' or x It should return an empty string if it receives None as the argument, or the argument if it's not None. For example: >>> f(4) 4 >>> f(None) >>> If I call f(None) instead of getting an empty string I get None. I printed the type of what the function returned and I got NoneType. I was expecting string. type('') returns string, so I'd like to know why the lambda doesn't return an empty string when I pass None as an argument. I'm fairly new to lambdas so I might have misunderstood some things about how they work.

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  • Proper way to assert type of variable in Python

    - by Morlock
    In using a function, I wish to ensure that the type of the variables are as expected. How to do it right? Here is an example fake function trying to do just this before going on with its role: def my_print(text, begin, end): """Print text in UPPER between 'begin' and 'end' in lower """ for i in (text, begin, end): assert type(i) == type("") out = begin.lower() + text.upper() + end.lower() print out Is this approach valid? Should I use something else than type(i) == type("") ? Should I use try/except instead? Thanks pythoneers

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  • strange behavior in python

    - by fsm
    The tags might not be accurate since I am not sure where the problem is. I have a module where I am trying to read some data from a socket, and write the results into a file (append) It looks something like this, (only relevant parts included) if __name__ == "__main__": <some init code> for line in file: t = Thread(target=foo, args=(line,)) t.start() while nThreads > 0: time.sleep(1) Here are the other modules, def foo(text): global countLock, nThreads countLock.acquire() nThreads += 1 countLock.release() """connect to socket, send data, read response""" writeResults(text, result) countLock.acquire() nThreads -= 1 countLock.release() def writeResults(text, result): """acquire file lock""" """append to file""" """release file lock""" Now here's the problem. Initially, I had a typo in the function 'foo', where I was passing the variable 'line' to writeResults instead of 'text'. 'line' is not defined in the function foo, it's defined in the main block, so I should have seen an error, but instead, it worked fine, except that the data was appended to the file multiple times, instead of being written just once, which is the required behavior, which I got when I fixed the typo. My question is, 1) Why didn't I get an error? 2) Why was the writeResults function being called multiple times?

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  • Multiple levels of 'collection.defaultdict' in Python

    - by Morlock
    Thanks to some great folks on SO, I discovered the possibilities offered by collections.defaultdict, notably in readability and speed. I have put them to use with success. Now I would like to implement three levels of dictionaries, the two top ones being defaultdict and the lowest one being int. I don't find the appropriate way to do this. Here is my attempt: from collections import defaultdict d = defaultdict(defaultdict) a = [("key1", {"a1":22, "a2":33}), ("key2", {"a1":32, "a2":55}), ("key3", {"a1":43, "a2":44})] for i in a: d[i[0]] = i[1] Now this works, but the following, which is the desired behavior, doesn't: d["key4"]["a1"] + 1 I suspect that I should have declared somewhere that the second level defaultdict is of type int, but I didn't find where or how to do so. The reason I am using defaultdict in the first place is to avoid having to initialize the dictionary for each new key. Any more elegant suggestion? Thanks pythoneers!

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  • Reading HTTP server push streams with Python

    - by Sam
    I'm playing around trying to write a client for a site which provides data as an HTTP stream (aka HTTP server push). However, urllib2.urlopen() grabs the stream in its current state and then closes the connection. I tried skipping urllib2 and using httplib directly, but this seems to have the same behaviour. Is there a way to get the stream to stay open, so it can be checked each program loop for new contents, rather than waiting for the whole thing to be redownloaded every few seconds, introducing lag?

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  • Python - Strange Behavior in re.sub

    - by Greg
    Here's the code I'm running: import re FIND_TERM = r'C:\\Program Files\\Microsoft SQL Server\\90\\DTS\\Binn\\DTExec\.exe' rfind_term = re.compile(FIND_TERM,re.I) REPLACE_TERM = 'C:\\Program Files\\Microsoft SQL Server\\100\\DTS\\Binn\\DTExec.exe' test = r'something C:\Program Files\Microsoft SQL Server\90\DTS\Binn\DTExec.exe something' print rfind_term.sub(REPLACE_TERM,test) And the result I get is: something C:\Program Files\Microsoft SQL Server@\DTS\Binn\DTExec.exe something Why is there an @ sign?

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  • Flickr API automated login using Python library flickrapi

    - by Dave Aaron Smith
    I have a web application that I want to sync with Flickr. I don't want the users to have to log into Flickr so I plan to use a single login. I believe I'll need to do something like this: import flickrapi flickr = flickrapi.FlickrAPI(myKey, mySecret) (token, frob) = flickr.get_token_part_one(perms='write', my_auth_callback) flickr.get_token_part_two((token, frob,)) flickr.what_have_you(... I don't know what my_auth_callback should look like though. I suspect it will have to post my login information to flickr. Could I do the get_token_part_one step just once manually perhaps and then re-use it in get_token_part_two?

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