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  • GenericIdentity not FormsIdentity

    - by Tony
    H Regarding this URL http://www.codeproject.com/KB/aspnet/FlashUpload.aspx User.Identity as System.Web.Security.FormsIdentity is always null, because the Identity is GenericIdentity, I assumed it will be as in the tutorial FormsIdentity, what is chances. Thanks

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  • How to create an "endless" scrolling slideshow?

    - by Andrew
    I know a good bit of JS and I'm familiar with jQuery, and I'm trying to create an "endless" slideshow (like the one on http://thisismedium.com/), where the images scroll -- one right behind the other -- and when it reaches the end it loops. I don't really know how to start, so I was hoping someone could point me in the right direction. I created a slideshow before that automatically switched images and let you click Next and Previous, but I'm stuck here. =/.

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  • @ContextConfiguration in Spring 3.0 give me No default constructor found

    - by atomsfat
    I have already do the test using AbstractDependencyInjectionSpringContextTests and it works but in spring 3 it is deprecated, so I decided to try @ContextConfiguration but spring say that default constructor is not found, I check and the class doesn't have any constructor. If I use this test spring give the object. package atoms.portales.servicios.impl; import atoms.portales.model.Cliente; import atoms.portales.servicios.ClienteService; import java.util.List; import javax.persistence.EntityManager; import org.springframework.test.AbstractDependencyInjectionSpringContextTests; /** * * @author tsalazar */ public class ClienteServiceImplDeTest extends AbstractDependencyInjectionSpringContextTests{ private ClienteService clienteService; public ClienteService getClienteService() { return clienteService; } public void setClienteService(ClienteService clienteService) { this.clienteService = clienteService; } public ClienteServiceImplDeTest(String testName) { super(testName); } @Override protected String[] getConfigLocations() { return new String[]{"PersistenceAppCtx.xml", "ServicesAppCtx.xml"}; } /** * Test of buscaCliente method, of class ClienteServiceImplDeTest. */ public void testBuscaCliente() { System.out.println("======================================="); System.out.println("buscaCliente"); String nombre = ""; System.out.println(clienteService); System.out.println("======================================="); } } But if I use this, spring say that default constructor is not found. package atoms.config.portales.servicios.impl; import atoms.portales.model.Cliente; import atoms.portales.servicios.ClienteService; import org.junit.runner.RunWith; import org.junit.Test; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.test.context.ContextConfiguration; import org.springframework.test.context.junit4.SpringJUnit4ClassRunner; import org.springframework.test.context.transaction.TransactionConfiguration; import org.springframework.transaction.annotation.Transactional; /** * * @author tsalazar */ @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = {"/PersistenceAppCtx.xml", "/ServicesAppCtx.xml"}) @TransactionConfiguration(transactionManager = "transactionManager") @Transactional public class ClienteServiceImplTest { @Autowired private ClienteService clienteService; /** * Test of buscaCliente method, of class ClienteServiceImpl. */ @Test public void testBuscaCliente() { System.out.println("======================================="); System.out.println("buscaCliente"); System.out.println(clienteService); System.out.println("======================================="); } } This how I do the implementacion: package atoms.portales.servicios; import atoms.portales.model; /** * Una interface para obtener clientes, con sus surcursales, servicios, layouts * y contratos. Tambien soporta operaciones CRUD. * @author tsalazar */ public interface ClienteService { /** * Busca clientes a partir del nombre * @param nombre */ public Cliente buscaCliente(String nombre); } the implemetacion package atoms.portales..servicios.impl; import atoms.portales.model.Cliente; import atoms.portales.servicios.ClienteService; import javax.persistence.EntityManager; import javax.persistence.PersistenceContext; import org.springframework.stereotype.Repository; import org.springframework.stereotype.Service; import org.springframework.transaction.annotation.Transactional; /** * A JPA-based implementation.Delegates to a JPA entity manager to issue data access calls * against the backing repository. The EntityManager reference is provided by the managing container (Spring) * automatically. */ @Service("clienteSerivice") @Repository public class ClienteServiceImpl implements ClienteService { public ClienteServiceImpl() { } private EntityManager em; @PersistenceContext public void setEntityManager(EntityManager em) { this.em = em; } @Transactional(readOnly = true) public Cliente buscaCliente(String nombre) { Cliente cliente = em.getReference(Cliente.class, 1l); return cliente; } } spring configuration: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <!-- Instructs Spring to perfrom declarative transaction management on annotated classes --> <tx:annotation-driven /> <!-- Drives transactions using local JPA APIs --> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <!-- Creates a EntityManagerFactory for use with the Hibernate JPA provider and a simple in-memory data source populated with test data --> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" /> </property> </bean> <!-- Deploys a in-memory "booking" datasource populated --> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver" /> <property name="url" value="jdbc:hsqldb:hsql://localhost/test" /> <property name="username" value="sa" /> <property name="password" value="" /> </bean> <context:component-scan base-package="atoms.portales.servicios" /> </beans> This is the persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="configuradorPortales" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <class>atoms.portales.model.Cliente</class> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/> <property name="hibernate.hbm2ddl.auto" value="create-drop"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.cache.provider_class" value="org.hibernate.cache.HashtableCacheProvider"/> </properties> </persistence-unit> </persistence> This is the error that give me:

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  • Why does ANT tell me that JAVA_HOME is wrong when it is not?

    - by Ankur
    I get the error: C:\dev\ws\springapp\build.xml:81: Unable to find a javac compiler; com.sun.tools.javac.Main is not on the classpath. Perhaps JAVA_HOME does not point to the JDK. It is currently set to "C:\Program Files\Java\jre6" But I have clearly set my JAVA_HOME to be C:\Program Files\Java\jdk1.6.0_14 Where is ANT getting this value?

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  • How to disable automatic loading in NHibernate?

    - by Drevak
    This question might be a duplicate of this one: http://stackoverflow.com/questions/217761/nhibernate-disable-automatic-lazy-loading-of-child-records-for-one-to-many-rela I'd like to know if there is any way to tell nhibernate to do not load a child collections (best if it's with fluent Nhibernate) unless i do it manually with a query (keeping all the mappings!). The problem is that even turning off lazy loading the collections get eager-loaded automatically. I'd like that no collections are loaded unless I specify a fetchmode in my query.

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  • jQuery ajax post dynamic url insertion

    - by Kirill
    $.ajax({ type: "POST", url: "OMFG.php", data: info, success: function(){ }}); is what I'm using atm as a test and it works fine. I need to get the url from the link I'm clicking, so I do: var url = $(this).attr("href"); which works fine if I alert it out(the link includes http://samedomain.com/etc.php), but the ajax function doesn't post if I insert it into the ajax code: $.ajax({ type: "POST", url: url, data: info, success: function(){ }}); Please help, as I'm screwed without this working.

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  • finding distance between two UK addresses

    - by effkay
    Hello; I need to write an application which is to calculate the estimated driving distance between two UK addresses; I think I can use Google as following: http://maps.google.com/maps/nav?q=from:London%20to:Dover However, anyone knows what is the daily/monthly limit of querying the database from a single IP address? I need to implement in a commercial application (freight services), is there any reliable alternative? Development language/platform: C#, .NET Regards,

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  • Build hierarchical chart using flex and action script

    - by jk
    i want to develop an application using flex 4 sdk with eclipse and action script. i need to draw the hierarchy chart dynamically and save it. should be able to label all the nodes at runtime, should able to view all charts created previously saved chart. i need source code for this sample application http://live.yworks.com/graphity/ thanks in advance

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  • Problems with Joomla menus

    - by aarontb
    I added a new link (like I usually do) but now all but the HOME menu button DO NOT WORK...they send me to a page that says No input file specified. Can someone help me please...it's a bit of an EMERGENCY. Check it out at http://www.fishchummer.com Thanks guys, Aaron

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  • Is There Something Wrong With My Computer Or The Website Server?

    - by thewarspk
    Recently I've been playing one new game which is called THE WARS, it's so fucking interesting that has become the routine work of my life. Yesterday i carelessly downloaded some files with virus, now my computer can't work properly, i just found i couldn't open the game page! Im so mad now, im wondering is there something wrong with my computer or website server, if it's mine, i will find someone to fix my PC, please check out for me...thank you very much, here is the address http://wars.swagblack.com/webgamethewars.aspx

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  • Retrive JSON data from JSON Object in C#

    - by user1638260
    JsonObject friendlist = facebookClient.Get("/me/friends") as JsonObject; //Retrive Data from friendlist { "data": [ { "name": "Mehta", "id": "1000032633029611" }, { "name": "Patu Mehta", "id": "1000042433527270" } ], "paging": { "next": "https://graph.facebook.com/100004241944047/friends?access_token=AAAEXJfmh18QBALKtilFYJz5PU6XvxKIaZAc65NYtyZCLbOqFKyZC8hdyjaU7C7w1CaLKG8tFdRtLYqtAX3vqrPwYNNe5G0aTGhB5x1mwgZDZD&limit=5000&offset=5000&__after_id=100004244527270" } } Count: 2 IsReadOnly: false Keys: Count = 2 Values: Count = 2 But i required only data not whole value like

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  • how to display user name in login name control

    - by user569285
    I have a master page that holds the loginview content that appears on all subsequent pages based on the master page. i have a username control also nested in the loginview to display the name of the user when they are logged in. the code for the loginview from the master page is displayed as follows: <div class="loginView"> <asp:LoginView ID="MasterLoginView" runat="server"> <LoggedInTemplate> Welcome <span class="bold"><asp:LoginName ID="HeadLoginName" runat="server" /> <asp:Label ID="userNameLabel" runat="server" Text="Label"></asp:Label></span>! [ <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Logout.aspx"/> ] <%--Welcome: <span class="bold"><asp:LoginName ID="MasterLoginName" runat="server" /> </span>!--%> </LoggedInTemplate> <AnonymousTemplate> Welcome: Guest [ <a href="~/Account/Login.aspx" ID="HeadLoginStatus" runat="server">Log In</a> ] </AnonymousTemplate> </asp:LoginView> <%--&nbsp;&nbsp; [&nbsp;<asp:LoginStatus ID="MasterLoginStatus" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" />&nbsp;]&nbsp;&nbsp;--%> </div> Since VS2010 launches with a default login page in the accounts folder, i didnt think it necessary to create a separate log in page, so i just used the same log in page. please find the code for the login control below: <asp:Login ID="LoginUser" runat="server" EnableViewState="false" RenderOuterTable="false"> <LayoutTemplate> <span class="failureNotification"> <asp:Literal ID="FailureText" runat="server"></asp:Literal> </span> <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="failureNotification" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend style="text-align:left; font-size:1.2em; color:White;">Account Information</legend> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User ID:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="failureNotification" ErrorMessage="User ID is required." ToolTip="User ID field is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="failureNotification" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="submitButton"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="LoginUserValidationGroup" onclick="LoginButton_Click"/> </p> </div> </LayoutTemplate> </asp:Login> I then wrote my own code for authentication since i had my own database. the following displays the code in the login buttons click event.: public partial class Login : System.Web.UI.Page { //create string objects string userIDStr, pwrdStr; protected void LoginButton_Click(object sender, EventArgs e) { //assign textbox items to string objects userIDStr = LoginUser.UserName.ToString(); pwrdStr = LoginUser.Password.ToString(); //SQL connection string string strConn; strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ConnectionString; SqlConnection Conn = new SqlConnection(strConn); //SqlDataSource CSMDataSource = new SqlDataSource(); // CSMDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ToString(); //SQL select statement for comparison string sqlUserData; sqlUserData = "SELECT StaffID, StaffPassword, StaffFName, StaffLName, StaffType FROM Staffs"; sqlUserData += " WHERE (StaffID ='" + userIDStr + "')"; sqlUserData += " AND (StaffPassword ='" + pwrdStr + "')"; SqlCommand com = new SqlCommand(sqlUserData, Conn); SqlDataReader rdr; string usrdesc; string lname; string fname; string staffname; try { //string CurrentData; //CurrentData = (string)com.ExecuteScalar(); Conn.Open(); rdr = com.ExecuteReader(); rdr.Read(); usrdesc = (string)rdr["StaffType"]; fname = (string)rdr["StaffFName"]; lname = (string)rdr["StaffLName"]; staffname = lname.ToString() + " " + fname.ToString(); LoginUser.UserName = staffname.ToString(); rdr.Close(); if (usrdesc.ToLower() == "administrator") { Response.Redirect("~/CaseAdmin.aspx", false); } else if (usrdesc.ToLower() == "manager") { Response.Redirect("~/CaseManager.aspx", false); } else if (usrdesc.ToLower() == "investigator") { Response.Redirect("~/Investigator.aspx", false); } else { Response.Redirect("~/Default.aspx", false); } } catch(Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } finally { Conn.Close(); } } My authentication works perfectly and the page gets redirected to the designated destination. However, the login view does not display the users name. i actually cant figure out how to pass the users name that i had picked from the database to the login name control to be displayed. taking a close look i also noticed the logout text that should be displayed after successful log in does not show. that leaves me wondering if the loggedin template control on the masterpage even fires at all or its still the anonymous template control that keeps displaying.? How do i get this to work as expected? Please help....

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  • Google Products listing help

    - by joesalvator
    I am so fed up with this Google products I am Ready to give someone my UN and PS and pay them to do it. I keep getting a error message when i upload my data feed. I get the error saying Text, I followed the instructions , they said to do it in excel and save as a text then upload the data feed thank you microcomputerctr.com

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  • Finding key Solr performance metrics

    - by Mike Malloy
    To improve performance of Solr find your slowest searches, monitor query results, cache hit rate and cache size, document cache and filter cache; find problems with Solr update handlers by tracking index operations and document operations. There is a tool from New Relic which may help. http://www.newrelic.com/solr.html

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  • css sprite button is jumping around

    - by Richard
    Hello everyone, Does anyone know what is causing the sprite rollover to jump around It is I think more likely a photoshop question, but I am not completely sure. I hope to get an answer here anyway, since I think most webdesigners/programmers problably worked with photoshop also. This is what I want the rollover to do example 1 and this is my testpage (see the play button) I made the sprite with spriteme.com thanks, Richard

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  • Drupal html user id

    - by msindle
    I'm using Drupal 6.16: I think I have a pretty simple question. How can I get the current user id and put it in a menu tab. What I would like to happen is when the user logs in and wants to change their their name, email etc to click a menu tab. I image it would look something like this: http://domain.com/user/{userid}/edit Thanks in advance! msindle

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  • Creating a line chart

    - by Mahendra
    Can I create a line chart that looks like the one(which I have provided as a link. Please click the link to see the chart image) using SSRS 2008? If so, please help me how to do that? Please see the below link for sample http://i48.tinypic.com/20ib1v8.png

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  • PHP Form Security With Referer

    - by Jascha
    I'm putting together a site that will make itself available for user input. I was wondering if writing a function like: if(getenv("HTTP_REFERER") != 'http://www.myURL.com/submitArea'){ die('don\'t be an jerk, ruin your own site'); }else{ // continue with form processing } is enough to prevent cross site form submissions.

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  • Only allow access of FIle From embed.

    - by KyleT
    Hey All, So I am embedding a PDF file on my page: <embed src="http://www.mywebsite.com/files/ebook.pdf" width="500" height="375"> Is there anyway to prevent any and all access to that file except for when it is being accessed via this embed? Thanks!

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  • Way to get logged in user in Expression Engine?

    - by Andrew G. Johnson
    Hi all, I am using Expression Engine in part of a site I am developing and other parts are just using my own PHP. My question is how can I tell who the user is logged in as on a non-EE page? I have access to the EE cookies and the EE database but couldn't find a way to use these values to figure out who the user is. I have a list of all the cookie keys/values at: http://andrewgjohnson.com/cookies.html

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