Search Results

Search found 10657 results on 427 pages for 'group'.

Page 153/427 | < Previous Page | 149 150 151 152 153 154 155 156 157 158 159 160  | Next Page >

  • best way to add route under resource in Laravel 4

    - by passingby
    I would like know if there is a better way to add additional route aside from the default of resource in Laravel 4. I have this code below which is no problem with regard to the functionality, it's just that it seems to be long: <?php Route::group(array('before' => 'auth'), function() { # API Route::group(array('prefix' => 'api'), function() { Route::resource('projects', 'ProjectsController'); Route::resource('projects.groups', 'GroupsController'); Route::post('/projects/{projects}/groups/{groups}/reorder', 'GroupsController@reorder'); }); }); If in Rails Rails.application.routes.draw do # API namespace :api, defaults: { format: 'json' } do scope module: :v1 do resources :projects do resources :groups do member do post :reorder end end end end end end

    Read the article

  • PHP is_file returns false (incorrectly) for Windows share on Ubuntu

    - by M3Mania
    Ubuntu server, PHP 5.3, connected via Samba to Windows server share. I am using file_exists() to check for availability of file on Windows machine. It returns false, although the filepath does exist. Meanwhile, file_get_contents() on the exact same filepath works fine. I'm wondering if it's a permission issue, since I'm having trouble configuring permissions of the files on the Windows share (it says I don't have permission to change permissions on them). When I look at the permissions through Nautilus, it says the user and group are both root, with 755 rights. I'd like to change the group to www-data, but can't seem to do it.

    Read the article

  • Nested attributes form for model which belongs_to few models

    - by ExiRe
    I have few models - User, Teacher and TeacherLeader. class User < ActiveRecord::Base attr_accessible ..., :teacher_attributes has_one :teacher has_one :teacher_leader accepts_nested_attributes_for :teacher_leader end class Teacher < ActiveRecord::Base belongs_to :user has_one :teacher_leader end class TeacherLeader < ActiveRecord::Base belongs_to :user belongs_to :teacher end I would like to fill TeacherLeader via nested attributes. So, i do such things in controller: class TeacherLeadersController < ApplicationController ... def new @user = User.new @teacher_leader = @user.build_teacher_leader @teachers_collection = Teacher.all.collect do |t| [ "#{t.teacher_last_name} #{t.teacher_first_name} #{t.teacher_middle_name}", t.id ] end @choosen_teacher = @teachers_collection.first.last unless @teachers_collection.empty? end end And also have such view (new.html.erb): <%= form_for @user, :url => teacher_leaders_url, :html => {:class => "form-horizontal"} do |f| %> <%= field_set_tag do %> <% f.fields_for :teacher_leader do |tl| %> <div class="control-group"> <%= tl.label :teacher_id, "Teacher names", :class => "control-label" %> <div class="controls"> <%= select_tag( :teacher_id, options_for_select( @teachers_collection, @choosen_teacher )) %> </div> </div> <% end %> <div class="control-group"> <%= f.label :user_login, "Login", :class => "control-label" %> <div class="controls"> <%= f.text_field :user_login, :placeholder => @everpresent_field_placeholder %> </div> </div> <div class="control-group"> <%= f.label :password, "Pass", :class => "control-label" %> <div class="controls"> <%= f.text_field :password, :placeholder => @everpresent_field_placeholder %> </div> </div> <% end %> <%= f.submit "Create", :class => "btn btn-large btn-success" %> <% end %> Problem is that select form here does NOT appear. Why? Do i do something wrong?

    Read the article

  • SVN: authz directory identifiers not support

    - by ledy
    Without using the authz, all the svn users can login and use the repos without issues. However, I would like to limit the access to some directories - not to be readable or writeable for all users. svnserve --version = 1.6.6 I tried both, granting access to users and groups. I also tried it separate, only group or only user access. [groups] admingroup=i_can_access_anything limitedgroup=i_am_limited [/] #*= @admingroup=rw i_can_access_anything=rw [projectX] #i also tried [repository:/projectX] #*= @limitedgroup=rw i_am_limited=rw Trying to access the / or /projectX at the svn fails. = access denied Without the authz, it works properly, but also grants access to other projects that do not belong to the "limited" user group :-/ Do you see what's wrong there? Thx

    Read the article

  • How should I join these 3 SQL queries in Oracle?

    - by Nazgulled
    I have these 3 queries: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url FROM movies m WHERE m.mid = 1; SELECT AVG(rating) FROM movie_ratings WHERE mid = 1; SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1; And I need to join them into a single query. I was able to do it like this: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url, AVG(rating) average, COUNT(rating) count FROM movies m INNER JOIN movie_ratings mr ON m.mid = mr.mid WHERE m.mid = 1 GROUP BY title, year, MovieGenres(m.mid), MovieDirectors(m.mid), MovieWriters(m.mid), synopsis, poster_url; But I don't really like that "huge" GROUP BY, is there a simpler way to do it?

    Read the article

  • Achieving AES-256 Channel Encryption with the .NET Compact Framework

    - by Ev
    Hi There, I am working on a business application where the clients are Windows Mobile 6.1 Professional devices. The server is a Java enterprise application. The industry working group recommends AES-256 encryption for client/server communications. This is necessary to gain certification. The encryption doesn't necessarily need to be channel encryption, it could be payload encryption. Channel encryption is preferable. The client and server communicate using SOAP/HTTP, which we are yet to implement. We plan to use WCF on the compact framework. In order to alleviate some of the work required to implement manual encryption/decryption, it would be nice if we could achieve the required encryption either at the TLS level, or somehow using the WS-* standards (I'm not particularly familiar with that group of technologies but I am learning right now). The server supports https with 256-bit AES. Does anybody have an idea on the best way to implement this? Thanks in advance.

    Read the article

  • I have a SID of a user account, and I want the SIDs of the groups it belongs to. (C#)

    - by JCCyC
    This has to be obtained from a remote machine. The following query works not for SIDs, but for group and account names. "SELECT GroupComponent FROM Win32_GroupUser WHERE PartComponent = \"Win32_UserAccount.Domain='" + accountDomain + "',Name='" + accountName + "'\"" The Win32_Group objects it returns come in the forms of strings, and they only have domain and name (even though Win32_Group has a SID property). I have this sinking feeling I'll have to: Turn the SID into an account name by querying Win32_SID; Perform the query above; Turn each of the resulting group names into SIDs by querying Win32_Group. PLEASE tell me there's a better way.

    Read the article

  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

    Read the article

  • A linq join combined with a regex

    - by Geert Beckx
    Is it possible to combine these 2 queries or would this make my code too complex? Also I think there should be a performance gain by combining these queries since I think in the near future my source table could be over 11000 records. This is what i came up with so far : Dim lit As LiteralControl ' check characters not in alphabet Dim r As New Regex("^[^a-zA-Z]+") Dim query = From o In source.ToTable _ Where r.IsMatch(o.Field(Of String)("nam")) lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", "0-9", query.Count)) plhAlpabetLinks.Controls.Add(lit) Dim q = From l In "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToLower.ToCharArray _ Group Join o In source.ToTable _ On l Equals o.Field(Of String)("nam").ToLowerInvariant(0) Into g = Group _ Select l, g.Count ' iterate the alphabet to generate all the links. For Each letter In q.AsEnumerable lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", letter.l, letter.Count)) plhAlpabetLinks.Controls.Add(lit) Next Kind regards, G.

    Read the article

  • how to add column in SQL Query that incl. LEFT OUTER JOIN

    - by radbyx
    I have this Query: SELECT p.ProductName, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID = dt.ProductID ORDER BY p.ProductName; It works like it should, but now I need to SELECT "State" out too. The tricky part is, that I only want the lastest "TimeStamp" where "State" was false. But now I also need the "State" for the lastest "TimeStamp". I tried this: SELECT p.ProductName, dt.State, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp, State FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID =dt.ProductID ORDER BY p.ProductName; But it didn't work, because it gave me the "State" for the lastest "TimeStamp". So I hope there is some clever heads out there that can help me. I'm guessing that this is either very simple or very hard to solve.

    Read the article

  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

    Read the article

  • Alternative to 'where col in (list)' for MySQL

    - by user210481
    Hi I have the following table T: id 1 2 3 4 col a b a c I want to do a select that returns the id,col when group by(col) having count(col)1 One way of doing it is SELECT id,col FROM T WHERE col IN (SELECT col FROM T GROUP BY(col) HAVING COUNT(col)>1); The intern select (from the right) returns 'a' and main one (left) will return 1,a and 3,a The problem is that the where in statement seems to be extremely slow. In my real case, the results from the internal select has many 'col's, something about 70000 and it's taking hours. Right now it's much faster to do the internal select and the main select getting all ids and upcs and do the intersection locally. MySQL should be able to handle this kind of query efficiently. Can I substitute the where in for a join or something faster? Thanks

    Read the article

  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

    Read the article

  • XML and .NET: How to replace specific node with many other ones loaded from raw xml data

    - by Entrase
    Let's suppose we have an element like this one in the main xml file: <group name="gr1" filename="groups/gr1.xml"/>. The second file gr1.xml contains something like this: <item name="i1">Item one</item> <item name="i2">Item two</item> <item name="i3">Item three</item> Note that there is no XML declaration in gr1.xml, just plain items without single parent node. So… Which is the best way to replace <group/> with its <item/>s? I have already tried some things like manual enclosing of gr1.xml content into a single node with XML declaration and loading it into XmlDocument, but it doesn't look like a good solution.

    Read the article

  • Rails 3 render :partials

    - by user297221
    Hi guys. I am migrating my 1.8.7 rails app to rails 3. But I have a problem with a partial: I have the following partial: in my cms controller : @clients = Client.all group = render_to_string :layout = 'layouts/window', :partial = 'clients/index' in my "clients/index" partial: <%= render :partial = 'clients/item', :collection = @clients % This worked great with rails 1.7.8 but with rails 3 only the partial in the index get's rendered!. So, to clarify this, the group variable in the controller doesn't get the html from the layout. Also the weird thing is that the window layout is _window.erb (if I do window.html.erb or just window.erb rails can't find it which is strange). Does anybody know if this behavior is normal for rails 3? thanxs!

    Read the article

  • what is a fast way to output h5py dataset to text?

    - by user362761
    I am using the h5py python package to read files in HDF5 format. (e.g. somefile.h5) I would like to write the contents of a dataset to a text file. For example, I would like to create a text file with the following contents: 1,20,31,75,142,324,78,12,3,90,8,21,1 I am able to access the dataset in python using this code: import h5py f = h5py.File('/Users/Me/Desktop/thefile.h5', 'r') group = f['/level1/level2/level3'] dset = group['dsetname'] My naive approach is too slow, because my dataset has over 20000 entries: # write all values to file for index in range(len(dset)): # do not add comma after last value if index == len(dset)-1: txtfile.write(repr(dset[index])) else: txtfile.write(repr(dset[index])+',') txtfile.close() return None Is there a faster way to write this to a file? Perhaps I could convert the dataset into a NumPy array or even a Python list, and then use some file-writing tool? (I could experiment with concatenating the values into a larger string before writing to file, but I'm hoping there's something entirely more elegant)

    Read the article

  • How do I create a point system in a Rails app that assigns points to users and non-authenticated-use

    - by codyvbrown
    I'm building a question and answer application on top of twitter and I'm hitting some snags because I'm inevitably dealing with two classes of users: authenticated and non-authenticated. The site enable users to give points to other users, who may or may not be authenticated, and I want to create a site-wide point system where the application stores and displays this information on their profile. I want to save this point data to the user because that would be faster and more efficient but non-authenticated users aren't in our system, we only have the twitter handle. So instead we display the points in our system like this: @points = point.all( :select => "tag, count(*) AS count", # Return tag and count :group => 'tag', # Group by the tag :order => "2 desc", :conditions => {:twitter_handle => params[:username]}) Is there a better way to do this? Is there a better way to associate data with non-authenticated users?

    Read the article

  • MySQL different versions other results.

    - by kuba
    hey, i have 2 version of mysql on windows 5.1.39-community and on linux 5.1.39-log i execute a query: SELECT `o`.`idOffer`, `o`.`offer_date`, `p`.`factory`, `c`.`short` AS `company`, `s`.`name` AS `subcategory`, `ct`.`name` AS `category`, count( (select count(1) from product where idProduct=idOffer group by idOffer) ) as b FROM `Offer` AS `o` LEFT JOIN `Product` AS `p` ON o.idOffer = p.idOffer LEFT JOIN `company` AS `c` ON o.company = c.id LEFT JOIN `Subcategory` AS `s` ON s.idSubcategory = o.idSubcategory LEFT JOIN `Category` AS `ct` ON ct.idCategory = s.idCategory WHERE (o.idOffer = p.idOffer) GROUP BY `o`.`idOffer` on windows it works as it suppose, but on linux it says: ERROR 1242 (21000): Subquery returns more than 1 row is it any way to get it worked on linux without any mysql updates/downgrades ?

    Read the article

  • I'm searching for a messaging platform (like XMPP) that allows tight integration with a web applicat

    - by loxs
    Hi, At the company I work for, we are building a cluster of web applications for collaboration. Things like accounting, billing, CRM etc. We are using a RESTfull technique: For database we use CouchDB Different applications communicate with one another and with the database via http. Besides, we have a single sign on solution, so that when you login in one application, you are automatically logged to the other. For all apps we use Python (Pylons). Now we need to add instant messaging to the stack. We need to support both web and desktop clients. But just being able to chat is not enough. We need to be able to achieve all of the following (and more similar things). When somebody gets assigned to a task, they must receive a message. I guess this is possible with some system daemon. There must be an option to automatically group people in groups by lots of different properties. For example, there must be groups divided both by geographical location, by company division, by job type (all the programers from different cities and different company divisions must form a group), so that one can send mass messages to a group of choice. Rooms should be automatically created and destroyed. For example when several people visit the same invoice, a room for them must be automatically created (and they must auto-join). And when all leave the invoice, the room must be destroyed. Authentication and authorization from our applications. I can implement this using custom solutions like hookbox http://hookbox.org/docs/intro.html but then I'll have lots of problems in supporting desktop clients. I have no former experience with instant messaging. I've been reading about this lately. I've been looking mostly at things like ejabberd. But it has been a hard time and I can't find whether what I want is possible at all. So I'd be happy if people with experience in this field could help me with some advice, articles, tales of what is possible etc.

    Read the article

  • How to read ident and it's value from registry?

    - by user367856
    i have store a list of items from gridView into registry as below: * frmPOSConfigSet.tblCatItems.First; while not frmPOSConfigSet.tblCatItems.Eof do begin RegItemSetting.WriteString('stk Group\Candy', frmPOSConfigSet.tblCatItemsCODE.Text, frmPOSConfigSet.tblCatItemsSPHOTO.Text); frmPOSConfigSet.tblCatItems.Next; end; * [In Registry Editor] stk Group - Candy - YUPI_GUM_HB , c:\Users\chai\Pictures\POS Item Images\image1.jpg - YUPI_GUM_SBKISS , c:\Users\chai\Pictures\POS Item Images\image2.jpg After i close the form and open again, all values in gridView is gone, how to retrieve the ident (eg. YUPI_GUM_HB) and it's value (eg.c:\Users\chai\Pictures\POS Item Images\image1.jpg) from registry to the gridView when load the form?

    Read the article

  • Find groups with both validated, unvalidated users

    - by Matchu
    (Not my real MySQL schema, but illustrates what needs done.) Users can belong to many groups, and groups have many users. users: id INT validated TINYINT(1) groups: id INT name VARCHAR(20) groups_users: group_id INT user_id INT I need to find groups that contain both validated and unvalidated users (validated being 1 or 0, respectively), in order to perform a specific manual maintenance task. There are thousands of users, all belong to at least one group, but a group usually only has 2-5 users. This is a live production server, so I could probably craft a query myself, but the last one I tried took a matter of minutes before I killed it. (I'm not one of those brilliant SQL wizards.) I suppose I could take the server down for maintenance, but, if possible, a query that gets this job done in a matter of seconds would be fantastic. Thanks!

    Read the article

  • Asp.Net MVC Handle Drop Down Boxes that are not part of the Model

    - by Pino
    I have a small form which the user must fill in and consists of the following fields. Name (Text) Value (Text) Group (Group - Is a list of option pulled from a database table) Now the Model for this View looks like so, public string Name { get; set; } public string Value { get; set; } public int GroupID { get; set; } Now the view is Strongly Typed to the above model. What method would one use to populate the drop down list? Since the data is not contained within the Model (It could be contained in the Model) should we be using Temp/View data? A HTML Helper? What would be the ideal way to achieve this.

    Read the article

  • Union All Won't work in stored procedure

    - by MyHeadHurts
    ALTER PROCEDURE [dbo].[MyStoredProcedure1] @YearToGet int AS Select Division, SDESCR, DYYYY, Sum(APRICE) ASofSales, Sum(PARTY) AS ASofPAX, Sum(NetAmount) ASofNetSales, Sum(InsAmount) ASofInsSales, Sum(CancelRevenue) ASofCXSales, Sum(OtherAmount) ASofOtherSales, Sum(CXVALUE) ASofCXValue From dbo.B101BookingsDetails Where Booked <= CONVERT(int,DateAdd(year, @YearToGet - Year(getdate()), DateAdd(day, DateDiff(day, 1, getdate()), 0) ) ) and (DYYYY = @YearToGet) Group By SDESCR, DYYYY, Division Having (DYYYY = @YearToGet) Order By Division, SDESCR, DYYYY union all SELECT DIVISION, SDESCR, DYYYY, SUM(APRICE) AS YESales, SUM(PARTY) AS YEPAX, SUM(NetAmount) AS YENetSales, SUM(InsAmount) AS YEInsSales, SUM(CancelRevenue) AS YECXSales, SUM(OtherAmount) AS YEOtherSales, SUM(CXVALUE) AS YECXValue FROM dbo.B101BookingsDetails Where (DYYYY=@YearToGet) GROUP BY SDESCR, DYYYY, DIVISION ORDER BY DIVISION, SDESCR, DYYYY The error I am getting is Msg 156, Level 15, State 1, Procedure MyStoredProcedure1, Line 36 Incorrect syntax near the keyword 'union'. But my goal here is the user inputs a year for example 2009, my first query will get all the sales made in 2009 to the same date it is was yesterday 12/23/2009, while the second query is getting 2009 totals up to dec 31 2009. I want the columns to be side by side not in one column

    Read the article

  • iPhone: Grouping records in multiple UITableView views

    - by Nic Hubbard
    Let me first say, I know how to create sections and group records within a UITableView. What I am wanting to do is something similar to creating a photo album. So, I have all my data objects coming from core data, and, I want to be able to create a custom group, such as "My Trip to Mexico" and "First Birthday". Then, the user should be able to add objects/records into new sections/albums. So, basically the user is creating custom sections with their own custom names, and then choosing what records should go into that section/album. So, I am just wondering what is the best way to do this? I am thinking that I would just create some extra attributes for my core data model. Or, would I create a whole new "Album Section" object, and somehow use that? Point me in the right direction. :)

    Read the article

  • some examples for using specific searchalgorithm

    - by Robert
    I could understand the following search algorithms: Constraint Satisfaction with Arc Consistency, Uninformed search A* Search MinMax I would understand the definition and working principles of the above algorithm,but could you please give me some real world examples that the above algorithms will be suitable?My idea would be: For CSP with Arc Consistency,assign students to groups that each group must contain both technical and management students,and no 2 technical students in a same group. Uniformed Search: search for a file under UNIX directoy. A* Search: search a way (staring from home) to go to mulitple stores to buy things then get back home with minimum total travelling time. MinMax:Go or other Chess. Please correct me if I am wrong.

    Read the article

< Previous Page | 149 150 151 152 153 154 155 156 157 158 159 160  | Next Page >