Search Results

Search found 40281 results on 1612 pages for 'mysql query browser'.

Page 162/1612 | < Previous Page | 158 159 160 161 162 163 164 165 166 167 168 169  | Next Page >

  • Drupal - db_fetch_array returns NULL for every row

    - by darudude
    I'm using Drupal's db_fetch_array to fetch rows from my db_query. However, every row returned is equal to NULL. Typing the query into PHP myadmin works, so I have no idea whats going on. db_num_rows returns the number of rows as well. Here is the code: if(count($rebuild_ids)) { $ids=implode(",",$rebuild_ids); $type_stmt = "SELECT * from {" . ItemType::$type_table_name . "} where id IN ($ids)"; $new_items=db_query($type_stmt); if(!$new_items || db_num_rows($new_items) == 0) { return; } while($row = db_fetch_array($new_items)); { if ($row!=NULL) { echo "I work!" $game_items[] = $row['id']; ItemInstance::$nid_to_item_type_code[$row['nid']] = $row['id']; } } } However, it never gets into the third if statement (i.e. never echos "I work!") Any ideas?

    Read the article

  • Get the names of IDs from different table

    - by user896692
    I have an array with a lot of data from a database. In the array, there are two fields called teameinsid and teamzweiid. The query is a very simple one : $spiel = mysql_query("select teameinsid, teamzweiid from begegnung", $connection) or die("Keine passende Begegnung"); What I need is to search in the database for the names of these IDs. The names are in a different table. What I have now is the following: while($tmp = mysql_fetch_array($spiel)){ $teins = $tmp['teameinsid']; $tzwei = $tmp['teamzweiid']; } So I know the two IDs, but I don't know where to save the names. If I try: $name = mysql_query("select name from team where teameinsid = $teins", $con) it gets overwritten every time. How can I manage this?

    Read the article

  • Trouble with a query

    - by Mark Allison
    Hi there, I'm having trouble with a query in SQL Server 2008 on some forex trading data. I have a trades table and an orders table. A trade needs to comprise of 2 or more orders. DDL schema and sample data below. What I want to do is write a query that shows the profit/loss in pips for each trade. A pip is 1/1000th of a currency. So the difference between USD 1.3441 and 1.3442 is 1 pip in forex-speak. A trade usually has one entry order and multiple exit orders. So for example if I buy 3 lots of the currency pair GBP/USD at the exchange rate of 1.6100 and then sell 1 lot at 1.6150, 1 lot at 1.6200 and 1 lot at 1.6250 then the profit is (1.6150 - 1.6100) + (1.6200 - 1.6100) + (1.6250 - 1.6100), or 50 + 100 + 150 = 300 pips profit. The trade could also go the other way (Shorting). For example the currency pair can be sold first before it's bought back later at a cheaper price. I would like a query that returns the following: tradeId, currencyPair, profitInPips It seems like a pretty straightforward query, but it's eluding me right now. Here's my DDL and sample data: CREATE TABLE [dbo].[trades]( [tradeId] [int] IDENTITY(1,1) NOT NULL, [currencyPair] [char](6) NOT NULL, CONSTRAINT [PK_trades] PRIMARY KEY CLUSTERED ( [tradeId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO SET ANSI_PADDING OFF GO SET IDENTITY_INSERT [dbo].[trades] ON INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (1, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (2, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (3, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (4, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (5, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (6, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (7, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (8, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (9, N'GBPUSD') INSERT [dbo].[trades] ([tradeId], [currencyPair]) VALUES (10, N'GBPUSD') SET IDENTITY_INSERT [dbo].[trades] OFF GO CREATE TABLE [dbo].[orders]( [orderId] [int] IDENTITY(1,1) NOT NULL, [tradeId] [int] NOT NULL, [amount] [decimal](18, 1) NOT NULL, [buySell] [char](1) NOT NULL, [rate] [decimal](18, 6) NOT NULL, [orderDateTime] [datetime] NOT NULL, CONSTRAINT [PK_orders] PRIMARY KEY CLUSTERED ( [orderId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO SET ANSI_PADDING OFF GO SET IDENTITY_INSERT [dbo].[orders] ON INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (1, 1, CAST(3.0 AS Decimal(18, 1)), N'S', CAST(1.606500 AS Decimal(18, 6)), CAST(0x00009CF40083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (2, 1, CAST(3.0 AS Decimal(18, 1)), N'B', CAST(1.615500 AS Decimal(18, 6)), CAST(0x00009CF400A4CB80 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (3, 2, CAST(3.0 AS Decimal(18, 1)), N'S', CAST(1.608000 AS Decimal(18, 6)), CAST(0x00009CF500000000 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (4, 2, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.603000 AS Decimal(18, 6)), CAST(0x00009CF50083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (5, 2, CAST(2.0 AS Decimal(18, 1)), N'B', CAST(1.605500 AS Decimal(18, 6)), CAST(0x00009CF50107AC00 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (6, 3, CAST(3.0 AS Decimal(18, 1)), N'S', CAST(1.595500 AS Decimal(18, 6)), CAST(0x00009CF70083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (7, 3, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.590500 AS Decimal(18, 6)), CAST(0x00009CF700C5C100 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (8, 3, CAST(2.0 AS Decimal(18, 1)), N'B', CAST(1.594500 AS Decimal(18, 6)), CAST(0x00009CF701499700 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (9, 4, CAST(3.0 AS Decimal(18, 1)), N'B', CAST(1.611000 AS Decimal(18, 6)), CAST(0x00009CFB0083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (10, 4, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.616000 AS Decimal(18, 6)), CAST(0x00009CFB00A4CB80 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (11, 4, CAST(2.0 AS Decimal(18, 1)), N'S', CAST(1.611500 AS Decimal(18, 6)), CAST(0x00009CFB0107AC00 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (12, 5, CAST(3.0 AS Decimal(18, 1)), N'B', CAST(1.613000 AS Decimal(18, 6)), CAST(0x00009CFC0083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (13, 5, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.618000 AS Decimal(18, 6)), CAST(0x00009CFC0107AC00 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (14, 5, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.623000 AS Decimal(18, 6)), CAST(0x00009CFC0083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (15, 5, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.628000 AS Decimal(18, 6)), CAST(0x00009CFD00C5C100 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (16, 6, CAST(3.0 AS Decimal(18, 1)), N'B', CAST(1.632000 AS Decimal(18, 6)), CAST(0x00009D020083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (17, 6, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.637000 AS Decimal(18, 6)), CAST(0x00009D0200A4CB80 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (18, 6, CAST(2.0 AS Decimal(18, 1)), N'S', CAST(1.630000 AS Decimal(18, 6)), CAST(0x00009D0200C5C100 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (19, 7, CAST(3.0 AS Decimal(18, 1)), N'B', CAST(1.634500 AS Decimal(18, 6)), CAST(0x00009D0201499700 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (20, 7, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.639500 AS Decimal(18, 6)), CAST(0x00009D0300000000 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (21, 7, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.644500 AS Decimal(18, 6)), CAST(0x00009D030083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (22, 7, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.637500 AS Decimal(18, 6)), CAST(0x00009D0300C5C100 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (23, 8, CAST(3.0 AS Decimal(18, 1)), N'S', CAST(1.625000 AS Decimal(18, 6)), CAST(0x00009D0400C5C100 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (24, 8, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.620000 AS Decimal(18, 6)), CAST(0x00009D050083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (25, 8, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.615000 AS Decimal(18, 6)), CAST(0x00009D0500A4CB80 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (26, 8, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.623000 AS Decimal(18, 6)), CAST(0x00009D050107AC00 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (27, 9, CAST(3.0 AS Decimal(18, 1)), N'S', CAST(1.618000 AS Decimal(18, 6)), CAST(0x00009D0600C5C100 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (28, 9, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.613000 AS Decimal(18, 6)), CAST(0x00009D0600D63BC0 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (29, 9, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.608000 AS Decimal(18, 6)), CAST(0x00009D0600E6B680 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (30, 9, CAST(1.0 AS Decimal(18, 1)), N'B', CAST(1.613300 AS Decimal(18, 6)), CAST(0x00009D0601391C40 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (31, 10, CAST(3.0 AS Decimal(18, 1)), N'B', CAST(1.614500 AS Decimal(18, 6)), CAST(0x00009D090083D600 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (32, 10, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.619500 AS Decimal(18, 6)), CAST(0x00009D090107AC00 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (33, 10, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.624500 AS Decimal(18, 6)), CAST(0x00009D0901499700 AS DateTime)) INSERT [dbo].[orders] ([orderId], [tradeId], [amount], [buySell], [rate], [orderDateTime]) VALUES (34, 10, CAST(1.0 AS Decimal(18, 1)), N'S', CAST(1.619000 AS Decimal(18, 6)), CAST(0x00009D0A0083D600 AS DateTime)) SET IDENTITY_INSERT [dbo].[orders] OFF /****** Object: ForeignKey [FK_orders_trades] Script Date: 04/02/2010 15:05:31 ******/ ALTER TABLE [dbo].[orders] WITH CHECK ADD CONSTRAINT [FK_orders_trades] FOREIGN KEY([tradeId]) REFERENCES [dbo].[trades] ([tradeId]) GO ALTER TABLE [dbo].[orders] CHECK CONSTRAINT [FK_orders_trades] GO Thanks in advance for any help!

    Read the article

  • SQL Joining Two or More from Table B with Common Data in Table A

    - by Matthew Frederick
    The real-world situation is a series of events that each have two or more participants (like sports teams, though there can be more than two in an event), only one of which is the host of the event. There is an Event db table for each unique event and a Participant db table with unique participants. They are joined together using a Matchup table. They look like this: Event EventID (PK) (other event data like the date, etc.) Participant ParticipantID (PK) Name Matchup EventID (FK to Event table) ParicipantID (FK to Participant) Host (1 or 0, only 1 host = 1 per EventID) What I'd like to get as a result is something like this: EventID ParticipantID where host = 1 Participant.Name where host = 1 ParticipantID where host = 0 Participant.Name where host = 0 ParticipantID where host = 0 Participant.Name where host = 0 ... Where one event has 2 participants and another has 3 participants, for example, the third participant column data would be null or otherwise noticeable, something like (PID = ParticipantID): EventID PID-1(host) Name-1 (host) PID-2 Name-2 PID-3 Name-3 ------- ----------- ------------- ----- ------ ----- ------ 1 7 Lions 8 Tigers 12 Bears 2 11 Dogs 9 Cats NULL NULL I suspect the answer is reasonably straightforward but for some reason I'm not wrapping my head around it. Alternately it's very difficult. :) I'm using MYSQL 5 if that affects the available SQL.

    Read the article

  • How can I use SQL to select duplicate records, along with counts of related items?

    - by mipadi
    I know the title of this question is a bit confusing, so bear with me. :) I have a (MySQL) database with a Person record. A Person also has a slug field. Unfortunately, slug fields are not unique. There are a number of duplicate records, i.e., the records have different IDs but the same first name, last name, and slug. A Person may also have 0 or more associated articles, blog entries, and podcast episodes. If that's confusing, here's a diagram of the structure: I would like to produce a list of records that match this criteria: duplicate records (i.e., same slug field) for people who also have at least 1 article, blog entry, or podcast episode. I have a SQL query that will list all records with the same slug fields: SELECT id, first_name, last_name, slug, COUNT(slug) AS person_records FROM people_person GROUP BY slug HAVING (COUNT(slug) > 1) ORDER BY last_name, first_name, id; But this includes records for people that may not have at least 1 article, blog entry, or podcast. Can I tweak this to fit the second criteria?

    Read the article

  • SQL Latest photos from contacts (grouped by contact)

    - by kitsched
    Hello, To short version of this question is that I want to accomplish something along the lines of what's visible on Flickr's homepage once you're logged in. It shows the three latest photos of each of your friends sorted by date but grouped by friend. Here's a longer explanation: For example I have 3 friends: John, George and Andrea. The list I want to extract should look like this: George Photo - 2010-05-18 Photo - 2010-05-18 Photo - 2010-05-12 John Photo - 2010-05-17 Photo - 2010-05-14 Photo - 2010-05-12 Andrea Photo - 2010-05-15 Photo - 2010-05-15 Photo - 2010-05-15 Friend with most recent photo uploaded is on top but his or her 2 next files follow. I'd like to do this from MySQL, and for the time being I got here: SELECT photos.user_id, photos.id, photos.date_uploaded FROM photos WHERE photos.user_id IN (SELECT user2_id FROM user_relations WHERE user1_id = 8) ORDER BY date_uploaded DESC Where user1_id = 8 is the currently logged in user and user2_id are the ids of friends. This query indeed returns the latest files uploaded by the contacts of the user with id = 8 sorted by date. However I'd like to accomplish the grouping and limiting mentioned above. Hopefully this makes sense. Thank you in advance.

    Read the article

  • I have created a PHP script and I am lacking to extract the primary key, I have given flow below, pl

    - by Parth
    I am using MySQL DB, working for Joomla, My requirement is tracking the activity like insert/update/delete on any table and store it in another audit table using triggers, i.e. I am doing Auditing. DB's table structure: Few tables dont have any PK nor auto increment key Flow of my script is : I fetch out all table from DB. I check whether the table have any trigger or not. If yes then it moves to check nfor next table and so on. If it does'nt find any trigger then it creates the triggers for the table, such that, -it first checks if the table has any primary key or not(for inserting in Tracking audit table for every change made) if it has the primary key then it uses it further in creation of trigger. if it doesnt find any PK then it proceeds further in creating the trigger without inserting any id in audit table Now here, My problem is I need the PK every time so that I can record the id of any particular table in which the insert/update/delete is performed, so that further i can use this audit track table to replicate in production DB.. Now as I haave mentioned earlier that I am not available with PK/auto-incremented in some table, then what should I do get the particular id in which change is done? please guide me...GEEKS!!!

    Read the article

  • 2 iframes with the same display even if the src are different

    - by JulienH
    Hi, I am using this code: <div class="infobox-pair"> <div class="ibp-left"> <iframe width="105" height="350" frameborder="0" scrolling="no" style="width: 311px; height: 105px;" marginwidth="0" marginheight="0" name="infobox_flight" id="ibp-left-iframe" src="http://mywebpage.com/paris"></iframe> </div> <div class="ibp-right"> <iframe width="105" height="350" frameborder="0" scrolling="no" style="width: 311px; height: 105px;" marginwidth="0" marginheight="0" name="infobox_package" id="ibp-right-iframe" src="http://mywebpage.com/lisbonne"></iframe> </div> That is displaying into the same div two different iframes. When I display the page whatever the browser it happens that I can get the same content for both the iframes even if looking at the source code the iframe are still different (based on their src and id). It doesn't happen 100% of the time, I have to refresh sometimes several times to see it. Do you have any clue ? Thanks in advance

    Read the article

  • Querying calender events even if they do not have any for the day

    - by StealthRT
    Hey everyone, i am trying to figure out a way of query my mysql server so that even if a company does not have anything posted for the day the user clicks on their logo, it still adds them to the list. That sounds a little confusing so let me try to explain it another way. Say i have 3 company's in my database: Comp1 Comp2 Comp3 And Comp1 & Comp3 have something for today on the calender but Comp2 does not. I still need it to populate and place that company on the page but have something along the lines of "nothing on the calender for today". The other 2 companys (Comp1 & Comp3) would show the calender posting for that day. This is the code i have right now: SELECT clientinfo.id, clientinfo.theCompName, clientinfo.theURL, clientinfo.picURL, clientinfo.idNumber, clientoffers.idNumber, clientoffers.theDateStart, clientoffers.theDateEnd FROM clientinfo, clientoffers WHERE clientinfo.accountStats = 'OPEN' AND clientinfo.idNumber = clientinfo.idNumber AND '2010-05-08' BETWEEN clientoffers.theDateStart AND clientoffers.theDateEnd GROUP BY clientinfo.idNumber ORDER BY clientinfo.theCompName ASC That executes just fine but for Comp2, it just places the calender info from Comp1 into it when it really doesn't have anything. The output looks like this: Comp1 | 2010-05-08 | this is the calender event 1 | etc etc Comp2 | 2010-05-08 | this is the calender event 1 | etc etc comp3 | 2010-05-09 | this is the calender event 2 | etc etc Any help would be great :o) David

    Read the article

  • Trying to build a dynamic PHP mysql_query string to update a row and getting back the updated row

    - by adardesign
    I have a form that jQuery tracks the onChage .change() event so when something is changed it runs a ajax request and i pass in the column, id, and the values in the url. Here i have the PHP code that should update the data. My question is now how do i build the mySQl string dynamically. and how do i echo back the changes/updates that where just changed on the db. Here is the PHP code i am trying to work with. <?php require_once('Connections/connect.php'); ?> <?php $id = $_GET['id']; $collumn = $_GET['collumn']; $val = $_GET['val']; ?> <?php mysql_select_db($myDB, $connection); // here i try to build the query string and pass in the passed in values $sqlUpdate = 'UPDATE `plProducts`.`allPens` SET `$collumn` = '$val' WHERE `allPens`.`prodId` = '$id' LIMIT 1;'; // here i want to echo back the updated row (or the updated data) $seeResults = mysql_query($sqlUpdate, $connection); echo $seeResults ?>

    Read the article

  • Joining tables, if percentage is above certain value

    - by CluelessGerman
    My question is similar to this one: Compare rows and get percentage However, little different. I adapted my question to the other post. I got 2 tables. First table: user_id | post_id 1 1 1 2 1 3 2 12 2 15 And second table: post_id | rating 1 1 1 2 1 3 2 1 2 5 3 null 3 1 3 4 12 4 15 1 So now I would like to count the rating for each post, in the second table. If the rating has more than, lets say, 50% positive ratings than I want to get the post_id and going it to the post_id from table one and add 1 to the user_id. At the end it would return the user_id with the number of positive posts. The result for above table would be: user_id | helpfulPosts 1 2 2 1 The post with post_id 1 and 3 have positive rating, because more than 50% have ratings of 1-3. The post with id = 2 is not positive, because the rating is exactly 50%. How would I achieve this? For clarification: It's a mysql rdbm and a positive post, is one where the number of rating_ids with 1, 2 and 3 are more than half of the overall rating. Basically the same thing, from the other thread I posted above.

    Read the article

  • Duplicate information from sql result

    - by puddleJumper
    I looked in about 18 other posts on here an most people are asking how to delete the records not just hide them. So my problem: I have a database with staff members who are associated with locations. Many of the staff members are associated with more than one location. What I want to do is to only display the first location listed in the mysql result and skip over the others. I have the sql query linking the tables together and it works aside from it showing the same information for those staff members that are in those other locations multiple times so example would be like this: This is the sql statement I have currently SELECT staff_tbl.staffID, staff_tbl.firstName, staff_tbl.middleInitial, staff_tbl.lastName, location_tbl.locationID, location_tbl.staffID, officelocations_tbl.locationID, officelocations_tbl.officeName, staff_title_tbl.title_ID, staff_title_tbl.staff_ID, titles_tbl.titleID, titles_tbl.titleName FROM staff_tbl INNER JOIN location_tbl ON location_tbl.staffID = staff_tbl.staffID INNER JOIN officelocations_tbl ON location_tbl.locationID = officelocations_tbl.locationID INNER JOIN staff_title_tbl ON staff_title_tbl.staff_ID = staff_tbl.staffID INNER JOIN titles_tbl ON staff_title_tbl.title_ID = titles_tbl.titleID and my php is <?php do { ?> <tr> <td><?php echo $row_rs_Staff_Info['firstName']; ?>&nbsp; <?php echo $row_rs_Staff_Info['lastName']; ?></td> <td><?php echo $row_rs_Staff_Info['titleName']; ?>&nbsp; </td> <td><?php echo $row_rs_Staff_Info['officeName']; ?>&nbsp; </td> </tr> <?php } while ($row_mysqlResult = mysql_fetch_assoc($rs_mysqlResult)); ?> What I would like to know is there a way using php to select only the first entry listed for each person and display that and just skip over the other two. I was thinking it could be done by possibly adding the staffID's to an array and if they are in there to skip over the next one listed in the staff_title_tbl but wasn't quite sure how to write it that way. Any help would be great thank you in advance.

    Read the article

  • get me the latest Change from Select Query in below given condition

    - by OM The Eternity
    I have a Table structure as id, trackid, table_name, operation, oldvalue, newvalue, field, changedonetime Now if I have 3 rows for the same "trackid" same "field", then how can i select the latest out of the three? i.e. for e.g.: id = 100 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPL newvalue = IPLcccc field = name live = 0 changedonetime = 2010-04-30 17:54:39 and id = 101 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPLcccc newvalue = IPL2222 field = name live = 0 changedonetime = 2010-04-30 18:54:39 As u can see above the secind entry is the latest change, Now what query I should use to get the only one and Latest row out of many such rows... $distupdqry = "select DISTINCT trackid,table_name from jos_audittrail where live = 0 AND operation = 'UPDATE'"; $disupdsel = mysql_query($distupdqry); $t_ids = array(); $t_table = array(); while($row3 = mysql_fetch_array($disupdsel)) { $t_ids[] = $row3['trackid']; $t_table[] = $row3['table_name']; //$t_table[] = $row3['table_name']; } //echo "<pre>";print_r($t_table);echo "<pre>"; //exit; for($n=0;$n<count($t_ids);$n++) { $qupd = "SELECT * FROM jos_audittrail WHERE operation = 'UPDATE' AND trackid=$t_ids[$n] order by changedone DESC "; $seletupdaudit = mysql_query($qupd); $row4 = array(); $audit3 = array(); while($row4 = mysql_fetch_array($seletupdaudit)) { $audit3[] = $row4; } $updatefield = ''; for($j=0;$j<count($audit3);$j++) { if($j == 0) { if($audit3[$j]['operation'] == "UPDATE") { //$insqry .= $audit2[$i]['operation']." "; //echo "<br>"; $updatefield .= "UPDATE `".$audit3[$j]['table_name']."` SET "; } } if($audit3[$j]['operation'] == "UPDATE") { $updatefield .= $audit3[$j]['field']." = '".$audit3[$j]['newvalue']."', "; } } /*echo "<pre>"; print_r($audit3); exit;*/ $primarykey = "SHOW INDEXES FROM `".$t_table[$n]."` WHERE Key_name = 'PRIMARY'"; $prime = mysql_query($primarykey); $pkey = mysql_fetch_array($prime); $updatefield .= "]"; echo $updatefield = str_replace(", ]"," WHERE ".$pkey['Column_name']." = '".$t_ids[$n]."'",$updatefield); } In the above code I am fetching ou the distinct IDs in which update operation has been done, and then accordingly query is fired to get all the changes done on different fields of the selected distinct ids... Here I am creating the Update query by fetching the records from the initially described table which is here mentioned as audittrail table... Therefore I need the last made change in the field so that only latest change can be selected in the select queries i have used... please go through the code.. and see how can i make the required change i need finally..

    Read the article

  • Training on Demand Certification Packages for DBAs

    - by Antoinette O'Sullivan
    The demand for Database Administrators continues to grow.*Almost two-thirds of IT hiring managers indicate that they highly value certifications in validatingIT skills and expertise.** * Job satisfaction and DBA work growth rate: CNN Money's 2011 Best Jobs in America survey.** Survey among nearly 1,700 respondents by CompTIA, the nonprofit trade association for the IT industry, cited in Certification Magazine, Feb. 14 th., 2012. Get Certified with Training on DemandAre you an experienced Database professional eager to achieve certification?Is time your most precious resource?Then try our new Training On Demand Certification Value Package with 20% discount. These all-in-one packages give you everything you need to get certified with success: Why Training On Demand:  Expert training from Oracle’s top instructors Sophisticated streaming video recording Available for 90 days, 24 hours a day, 7 days a week White boarding and training labs for hands-on experience Start, stop, pause, jump or rewind sections of the course as needed  Oracle University instructor Q&A  A full-text search leads to the right video fragment in a matter of seconds. Watch this demo to see how it works. Additional Certification resources: Benefits of Oracle Certification Database Certification Paths Available Database Certification Exams Getting certified has never been easier!For assistance contact your local Oracle University Service Desk. Many organizations deploy both Oracle Database and MySQL side by side to serve different needs, and as a database professional you can find training courses on both topics at Oracle University! Check out the upcoming Oracle Database 11g training courses and MySQL training courses. Even if you're only managing Oracle Databases at this point of time, getting familiar with MySQL Database will broaden your career path with growing job demand. These Value Packages are also available with the following training formats: In-Class, Live Virtual Class and Self Study: MySQL Database Administration Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand MySQL Database Administrator Certification Value Package View Package View Package View Package View Package MySQL Developer Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand       MySQL Developer Certification Value Package View Package View Package     Oracle Database 10g Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database 10g Administrator Certified Associate Certification Value Package View Package View Package View Package   Oracle Database 10g Administrator Certified Professional Certification Value Package View Package View Package View Package   Oracle Database 11g Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database 11g Administrator Certified Associate Certification Value Package View Package View Package View Package View Package Oracle Database 11g Administrator Certified Professional Certification Value Package View Package View Package View Package View Package Exam Prep Seminar Value Package: Oracle Database Admin 1       View Package Oracle Database 11g Administrator Certified Professional UPGRADE Certification Value Package       View Package Oracle Real Application Clusters 11g and Grid Infrastructure Administraton Certified Expert Certification Value Package       View Package Exam Prep Seminar Value Package: Oracle Database Admin 2        View Package Exam Prep Seminar Value Package: Oracle RAC 11g and Grid Infrastructure Administration       View Package Exam Prep Seminar Value Package: Upgrade Oracle Certified Professional (OCP) to Oracle Database 11g       View Package SQL and PL/SQL Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database Sql Expert Certification Value Package View Package View Package View Package View Package Exam Prep Seminar Value Package: Oracle Database SQL       View Package View our Certification Value Packages Mention this code at the time of booking: E1245 Connect For a full list of MySQL Training courses and events, go to http://oracle.com/education/mysql.

    Read the article

  • Export from EndNote into MySQL database

    - by Tomba
    I would like to export some records from an EndNote (reference management software) library and import into a MySQL database. Does anyone have any experience with this? I've tried creating custom EndNote "output styles" containing either comma-delimited values or even SQL code, but have had mixed results, either because EndNote filters out some characters (like `) or because EndNote doesn't (or I can't work out how to make it) escape text, which might include characters like ' and ". I realize this might be a bit off-topic but any help would be appreciated.

    Read the article

  • Entity Framework with MySQL - Timeout Expired while Generating Model

    - by Nathan Taylor
    I've constructed a database in MySQL and I am attempting to map it out with Entity Framework, but I start running into "GenerateSSDLException"s whenever I try to add more than about 20 tables to the EF context. An exception of type 'Microsoft.Data.Entity.Design.VisualStudio.ModelWizard.Engine.ModelBuilderEngine+GenerateSSDLException' occurred while attempting to update from the database. The exception message is: 'An error occurred while executing the command definition. See the inner exception for details.' Fatal error encountered during command execution. Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding. There's nothing special about the affected tables, and it's never the same table(s), it's just that after a certain (unspecific) number of tables have been added, the context can no longer be updated without the "Timeout expired" error. Sometimes it's only one table left over, and sometimes it's three; results are pretty unpredictable. Furthermore, the variance in the number of tables which can be added before the error indicates to me that perhaps the problem lies in the size of the query being generated to update the context which includes both the existing table definitions, and also the new tables that are being added to it. Essentially, the SQL query is getting too large and it's failing to execute for some reason. If I generate the model with EdmGen2 it works without any errors, but the generated EDMX file cannot be updated within Visual Studio without producing the aforementioned exception. In all likelihood the source of this problem lies in the tool within Visual Studio given that EdmGen2 works fine, but I'm hoping that perhaps others could offer some advice on how to approach this very unique issue, because it seems like I'm not the only person experiencing it. One suggestion a colleague offered was maintaining two separate EBMX files with some table crossover, but that seems like a pretty ugly fix in my opinion. I suppose this is what I get for trying to use "new technology". :(

    Read the article

  • Storing Twitter OAuth in MySQL

    - by nute
    I'm about to add a feature on my website that will post stuff to the users' twitter accounts. I read that storing an "OAuth" token is better than storing their usernames and passwords (which makes sense). What should I store in my MySQL database? The token, secret and username? Or just the token? What data type(s) would you use? How big are they? Thanks!

    Read the article

  • mysql server upgrade problem from 5.0 to 5.1

    - by Avinash
    Hi I have upgraded my mysql server from 5.0 to 5.1. But i am having a problem related to tables for InnoDB storage Engine. My default engine is InnoDB, So it is enabled in my server. But tables with InneDB engine are not displaying in phpmyadmin. Tables with MyISAM are displaying properly. and also i can't fire a query on the table with InnoDB Engine. Thanks Avinash

    Read the article

  • php connection pooling mysql

    - by coool
    Hi, I am planning to use MYSQL. Is there a connection pooling extension available. or what is the normal practice for connection. is this the one used in every where... mysqli_connect("localhost", "xxx", "xxx", "test"); Do people use just normal msql_connect or pconnect..? how better is pconnect and what setting should I do for PConnect.... THnks

    Read the article

  • mysql UDF : fopen = permission denied

    - by Pierre
    Hi All, I'm trying to create a mysql UDF function , this function calls "fopen/fclose" to read a flat file stored in /data. But using errno (yes, I know it is bad in a MT program...) I can see that the function cannot open my file: "Permission denied" I tried to do a chmod -R 755 /data but it didn't change anything. Any idea ?

    Read the article

  • NHibernate query with Projections.Cast to DateTime

    - by stiank81
    I'm experimenting with using a string for storing different kind of data types in a database. When I do queries I need to cast the strings to the right type in the query itself. I'm using .Net with NHibernate, and was glad to learn that there exists functionality for this. Consider the simple class: public class Foo { public string Text { get; set; } } I successfully use Projections.Cast to cast to numeric values, e.g. the following query correctly returns all Foos with an interger stored as int - between 1-10. var result = Session.CreateCriteria<Foo>() .Add(Restrictions.Between(Projections.Cast(NHibernateUtil.Int32, Projections.Property("Text")), 1, 10)) .List<Foo>(); Now if I try using this for DateTime I'm not able to make it work no matter what I try. Why?! var date = new DateTime(2010, 5, 21, 11, 30, 00); AddFooToDb(new Foo { Text = date.ToString() } ); // Will add it to the database... var result = Session .CreateCriteria<Foo>() .Add(Restrictions.Eq(Projections.Cast(NHibernateUtil.DateTime, Projections.Property("Text")), date)) .List<Foo>();

    Read the article

  • Selecting info from multiple tables for one unique ID with PHP and MySQL

    - by Mark
    I'm using PHP and MySQL. Is this the best method to select information about "user_1" from four different tables? I know it works, because I have tried it. But is this the preferred method of selecting information from multiple tables for "user_1"? $query = "SELECT table_1.username, table_2.city, table_3.state, table_4.country FROM table_1 JOIN table_2 ON table_1.username=table_2.city JOIN table_3 ON table_1.username=table_3.state JOIN table_4 ON table_1.username=table_4.country WHERE table_1.username = 'user_1'";

    Read the article

  • MySQL "filegroup"??

    - by Xaitec
    Coming for using Sql Server where there are file-groups, i was wondering if there is (i'm sure there is) something similar in MySQL. After all the database cant be limited to just one hard drive( if using windows that is). I've tried to search but its hard to find the something that you don't know the name of!.

    Read the article

< Previous Page | 158 159 160 161 162 163 164 165 166 167 168 169  | Next Page >