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  • Checking if a string's characters are ascending alphabetically and its ascent is evenly spaced python

    - by FRU5TR8EDD
    So need to check if a string's characters are ascending alphabetically and if that ascent is evenly spaced. a = "abc" b = "ceg" So a is alphabetically ascending and it's spacing is 1 (if you convert to the ordinal values they are 97,98,99). And b is also alphabetically ascending and it's spacing is 2 (99,101,103). And I am sticking with the following code: a = 'jubjub' words1 = [] ords = [ord(letter) for letter in a] diff = ords[1] - ords[0] for ord_val in range(1, len(ords)-1): if diff > 0: if ords[ord_val + 1] - ords[ord_val] == diff: if a not in words1: words1.append((a, diff)) print words1 How come 'jubjub' works, 'ace' works, but 'catcat' doesn't?

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  • Python List length as a string

    - by mvid
    Is there a preferred (not ugly) way of outputting a list length as a string? Currently I am nesting function calls like so: print "Length: %s" % str(len(self.listOfThings)) This seems like a hack solution, is there a more graceful way of achieving the same result?

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  • Network Communication program in python

    - by lamnep
    Hi all, Basically what I'm trying to achieve is a program which allow users to connect to a each other over a network in, essentially, a chat room. What I'm currently struggling with is writing the code so that the users can connect to each other without knowing the IP-address of the computer that the other users are using or knowing the IP-address of a server. Does anyone know of a way in which I could simply have all of the users scan the IP range of my network in order to find any active 'room' and then give the user a chance to connect to it? Also, the hope is that there will be no need for a central server to run this from, rather every user will simply be connected to all other user, essentially being the server and client at the same time.

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  • Python regular expression

    - by user3692739
    I have this HTTP Request and I want to display only the Authorization section (base64 Value) : any help ? This Request is stored on a variable called hreq I have tried this : reg = re.search(r"Authorization:\sBasic\s(.*)\r", hreq) print reg.group() but doesn't work Here is the request : HTTP Request: Path: /dynaform/custom.js Http-Version: HTTP/1.1 Host: 192.168.1.254 Accept-Language: en-US,en;q=0.5 Accept-Encoding: gzip, deflate Referer: http://domain.com/userRpm/StatusRpm.htm Authorization: Basic YWhtEWa6MDfGcmVlc3R6bGH I want to display the value YWhtEWa6MDfGcmVlc3R6bGH Please I need your help thanks in advance experts

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  • Perfom python unit tests via a web interface

    - by 47
    Is it possible to perform unittest tests via a web interface...and if so how? EDIT: For now I want the results...for the tests I want them to be automated...possibly every time I make a change to the code. Sorry I forgot to make this more clear

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  • Assistance with regular expressions in Python

    - by da5id
    I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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  • escaping query string with special characters with python

    - by that_guy
    I got some pretty messy urls that i got via scraping here, problem is that they contain spaces or other special characters in the path and query string, here is some example http://www.example.com/some path/to the/file.html http://www.example.com/some path/?file=path to/file name.png&name=name.me so, is there an easy and robust way to escape the urls so that i can pass them to urlopen? i tried urlib.quote, but it seems to escape the '?', '&', and '=' in the query string as well, and it seems to escape the protocol as well, currently, what i am trying to do is use regex to separate the protocol, path name, and query string and escape them separately, but there are cases where they arent separated properly any advice is appreciated

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  • Python Threading, loading one thread after another

    - by Michael
    Hi, I'm working on a media player and am able to load in a single .wav and play it. As seen in the code below. foo = wx.FileDialog(self, message="Open a .wav file...", defaultDir=os.getcwd(), defaultFile="", style=wx.FD_MULTIPLE) foo.ShowModal() queue = foo.GetPaths() self.playing_thread = threading.Thread(target=self.playFile, args=(queue[0], 'msg')) self.playing_thread.start() But the problem is, when I try to make the above code into a loop for multiple .wav files. Such that while playing_thread.isActive == True, create and .start() the thread. Then if .isActive == False, pop queue[0] and load the next .wav file. Problem is, my UI will lock up and I'll have to terminate the program. Any ideas would be appreciated.

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  • Normalising book titles - Python

    - by RadiantHex
    Hi folks, I have a list of books titles: "The Hobbit: 70th Anniversary Edition" "The Hobbit" "The Hobbit (Illustrated/Collector Edition)[There and Back Again]" "The Hobbit: or, There and Back Again" "The Hobbit: Gift Pack" and so on... I thought that if I normalised the titles somehow, it would be easier to implement an automated way to know what book each edition is referring to. normalised = ''.join([char for char in title if char in (string.ascii_letters + string.digits)]) or normalised = '' for char in title: if char in ':/()|': break normalised += char return normalised But obviously they are not working as intended, as titles can contain special characters and editions can basically have very different title layouts. Help would be very much appreciated! Thanks :)

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  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

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  • python intercepting communication

    - by nabizan
    lets say you run third party program on your computer whitch create a process named example.exe how do i determinate if this process is running and how many windows does he open? How do i intercept network communication between this windows and server? my goal is to create an app whitch will be monitoring network trafic between example.exe and its home server in order to analyze data and save to database, and finally simulate user interaction to get more relevant data

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  • Http.Request and cookies Python

    - by Kyle
    I am trying to retrieve source code from a webpage with an already issued cookie and write the source code to a txt file. If I remove the cookies=cookie portion I can retrieve the source code but I need to somehow send the cookie with the http.request. output = open('Filler.txt', 'w+') http = urllib3.PoolManager() cookie =('users' , '1597413515') r = http.request('http://google.com' , 'GET' , cookies=cookie) output.write(r.data) output.close() I get a KeyError: None

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  • Python frequency detection

    - by Tsuki
    Ok what im trying to do is a kind of audio processing software that can detect a prevalent frequency an if the frequency is played for long enough (few ms) i know i got a positive match. i know i would need to use FFT or something simiral but in this field of math i suck, i did search the internet but didn not find a code that could do only this. the goal im trying to accieve is to make myself a custom protocol to send data trough sound, need very low bitrate per sec but im also very limited on the transmiting end so the recieving software will need to be able custom (cant use an actual hardware/software modem) also i want this to be software only (no additional hardware except soundcard) thanks alot for the help.

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  • Python Frequently Asked Questions

    - by Casebash
    After seeing this suggestion for creating tag homepages/FAQs, I thought it'd be best to go on ahead and start collecting links to frequently asked questions to demonstrate how this would work. Object Oriented Metaclasses Missing features Enums Tools Available IDEs?

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  • Adding items to dictionary if condition is true, else dont - python

    - by CodeTalk
    I'm trying to take an existing process: if self.path_object is not None: dictpath = {} for path in self.path_object: self.params = path.pathval.split("?")[0] self.params = path.pathval.split("&", 2) if path.pathval.contains(self.params): out = list(map(lambda v: v.split("=")[0] +"=" + str(self.fuzz_vectors), self.params)) else: pass dictpath[path] = out print dictpath I added the sub-if/else block in, but it is failing, stating: AttributeError: 'unicode' object has no attribute 'contains' on the if block . How can I fix it? I'm simply trying to do: if the path.pathval has either ? or & in it: add to dictionary else: pass #forget about it. Thanks!

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  • Sending Data as Instances using Python Sockets

    - by Alice
    I'm working on the networking part of a 2 player game (similar to tetris), and I'm trying to pass the game grid from client to server and vice versa. However, when I tried using send(grid) I get a TypeError: send() argument 1 must be string or read-only buffer, not instance. Is there anyway to circumvent this, or do I have to convert my grid instance into a string and then interpret it from the other side? Thanks in advance!

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  • python mock side_effect or return_value dependent on call_count

    - by user18380
    To test a polling function I want to mock the calling of a sub function so that the first time it is called it will fail, and the second time it is called it will succeed. Here's a very simplified version of it: poll_function(var1): value = sub_function(var1) # First call will return None while not value: time.sleep(POLLING_INTERVAL) value = sub_function(var1) # A subsequent call will return a string, e.g "data" return value Is this possible to do with a Mock object from the mock framework? I know Mock objects have a call_count attribute I should be able to use somehow. Right now I've solved it by creating a custom mock object that I use to monkey patch sub_function(), but I feel there should be a better less verbose way of doing it: def test_poll(): class MyMock(object): def __init__(self, *args): self.call_count = 0 def sub_function(self, *args, **kwargs): if self.call_count > 1: return "data" else: self.call_count += 1 return None my_mock = MyMock() with patch('sub_function', my_mock.sub_function): ok_(poll_function())

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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