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  • mysql query optimization

    - by vamsivanka
    I would need some help on how to optimize the query. select * from transaction where id < 7500001 order by id desc limit 16 when i do an explain plan on this - the type is "range" and rows is "7500000" According to the some online reference's this is explained as, it took the query 7,500,000 rows to scan and get the data. Is there any way i can optimize so it uses less rows to scan and get the data. Also, id is the primary key column.

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  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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  • Need some sort of "conditional grouping" in MySQL.

    - by serg555
    I have Article table: id | type | date ----------------------- 1 | A | 2010-01-01 2 | A | 2010-01-01 3 | B | 2010-01-01 Field type can be A, B or C. I need to run a report that would return how many articles of each type there is per every day, like this: date | count(type="A") | count(type="B") | count(type="C") ----------------------------------------------------- 2010-01-01 | 2 | 1 | 0 2010-01-02 | 5 | 6 | 7 Currently I am running 3 queries for every type and then manually merging the results select date, count(id) from article where type="A" group by date Is it possible to do this in one query? (in pure sql, no stored procedures or anything like that). Thanks

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  • What is wrong with this trigger in mysql?

    - by Jimit
    Hi all, Below is trigger that I need to create but It is not getting created.Please any buddy can explain me what is wrong with this trigger ? Help me please. DELIMITER $$ CREATE TRIGGER property_history_update AFTER UPDATE ON `properties` FOR EACH ROW BEGIN IF OLD.ListPrice != NEW.ListPrice THEN INSERT INTO `property_history` SET ListingKey=OLD.ListingKey,ListPrice = NEW.ListPrice, ListingStatus = OLD.ListingStatus,LastUpdatedTime = NEW.LocalLastModifiedOn; END IF; END$$ DELIMITER ;

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  • Strange behavior of MySQL UPDATE query in PHP?

    - by Prashant
    When I am executing following query then its not updating views column by 1 instead sometimes its updating it by 2 or 3. Say currently views count is 24 then after executing this query it becomes 26 or sometimes its 27. $views = $views + 1; $_SQL = ''; $_SQL = 'UPDATE videos SET views = '.$views.' WHERE VideoId= "'.$videoid.'";'; @mysql_query($_SQL); I am not getting why this is happening, am I missing something or the query is executing 2 times automatically? Please help me to figure out the issue. Thanks

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  • Generating Unordered List with PHP + CodeIgniter from a MySQL Database

    - by Tim
    Hello Everyone, I am trying to build a dynamically generated unordered list in the following format using PHP. I am using CodeIgniter but it can just be normal php. This is the end output I need to achieve. <ul id="categories" class="menu"> <li rel="1"> Arts &amp; Humanities <ul> <li rel="2"> Photography <ul> <li rel="3"> 3D </li> <li rel="4"> Digital </li> </ul> </li> <li rel="5"> History </li> <li rel="6"> Literature </li> </ul> </li> <li rel="7"> Business &amp; Economy </li> <li rel="8"> Computers &amp; Internet </li> <li rel="9"> Education </li> <li rel="11"> Entertainment <ul> <li rel="12"> Movies </li> <li rel="13"> TV Shows </li> <li rel="14"> Music </li> <li rel="15"> Humor </li> </ul> </li> <li rel="10"> Health </li> And here is my SQL that I have to work with. -- -- Table structure for table `categories` -- CREATE TABLE IF NOT EXISTS `categories` ( `id` mediumint(8) NOT NULL auto_increment, `dd_id` mediumint(8) NOT NULL, `parent_id` mediumint(8) NOT NULL, `cat_name` varchar(256) NOT NULL, `cat_order` smallint(4) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; So I know that I am going to need at least 1 foreach loop to generate the first level of categories. What I don't know is how to iterate inside each loop and check for parents and do that in a dynamic way so that there could be an endless tree of children. Thanks for any help you can offer. Tim

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  • Testing + production server and syncing MySQL data

    - by Matthew
    I have a web application running on LAMP with a testing server and a production server. Is there a standard practice for keeping the data on the testing server in sync with the production server? The data on the testing server gets out of date pretty quick and I feel like there must be an easier way than just dumping the production server and copying it onto the testing server every so often. It's not important that the data is in total sync, just that the testing server represents the production enviornment as accurately as possible.

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  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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  • php + MySQL editing table data.

    - by Jacksta
    This question is relating to 2 php scripts. The first script is called pick_modcontact.php where I choose a contact (from a contact book like phone book), then posts to the script show_modcontact.php When I click the submit button on the form on pick.modcontact.php. As a result of submitting the form I am then taken to show_modcontact.php. As the variables are not present the user is directed back to pick_modcontact.php I can not work out how to correct the code so that it will show the results of the script show_modcontact.php This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION['valid'] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST['id']) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION['valid'] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '" . $_POST['id'] . "'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="text" name="id" value="<? echo $_POST['id']; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1"; ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2"; ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3"; ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode"; ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country"; ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email;" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday"; ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html> note for site admin, I am re posting this question with the hope of someone else reading over it. older questions seem to go dead after a while.

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  • Mysql SQL join question

    - by David
    I am trying to find all deals information along with how many comments they have received. My query select deals.*, count(comments.comments_id) as counts from deals left join comments on comments.deal_id=deals.deal_id where cancelled='N' But now it only shows the deals that have at least one comment. What is the problem?

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  • Problems with MYSQL database

    - by shinjuo
    I have a database that worked fine until I decided to add a log onto the page. here is what I have now: <body> <?php if($_SERVER['REQUEST_METHOD'] == 'POST') { require("serverInfo.php"); mysql_query("UPDATE `cardLists` SET `AmountLeft` = `AmountLeft` + ".mysql_real_escape_string($_POST['Add'])." WHERE `cardID` = '".mysql_real_escape_string($_POST['Cards'])."'"); echo "\"" .$_POST['Add'] ."\" has been added to the inventory amount for the card \"". $_POST['Cards']. "\""; mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <?php require("serverInfo.php"); ?> <?php $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = 'Cards'>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=\"$row[cardID]\">$row[cardID]</option>"; } echo "</select>"; ?> Amount to Add: <input type="text" name="Add" maxlength="8" /> Changes Made By: <select name="Person"> <option value="justin">Justin</option> <option value="chris">Chris</option> <option value="matt">Matt</option> <option value="dan">Dan</option> <option value="tim">Tim</option> <option value="amanda">Amanda</option> </select> <input type="submit" name ="submit" onClick= "return confirm( 'Are you sure you want to add this amount?');"> </form> <br /> <input type="button" name="main" value="Return To Main" onclick="window.location.href='index.php';" /> </body> </html> it works fine until I added the: mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); Can anyone see what is going on?

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  • MYSQL JOIN WHERE ISSUES - need some kind of if condition

    - by Breezer
    Hi Well this will be hard to explain but ill do my best The thing is i have 4 tables all with a specific column to relate to eachother. 1 table with users(agent_users) , 1 with working hours(agent_pers), 1 with sold items(agent_stat),1 with project(agent_pro) the user and the project table is irrelevant in the issue at hand but to give you a better understanding why certain tables is included in my query i decided to still mention them =) The thing is that I use 2 pages to insert data to the working hour and the sold items during that time tables, then i have a third page to summarize everything for current month, the query for that is as following: SELECT *, SUM(sv_p_kom),SUM(sv_p_gick),SUM(sv_p_lunch) FROM (( agent_users LEFT JOIN agent_pers ON agent_users.sv_aid = agent_pers.sv_p_uid) LEFT JOIN agent_stat ON agent_pers.sv_p_uid = agent_stat.sv_s_uid) LEFT JOIN agent_pro ON agent_pers.sv_p_pid=agent_pro.p_id WHERE MONTH(agent_pers.sv_p_datum) =7 GROUP BY sv_aname so the problem is now that i dont want sold items from previous months to get included in the data received, i know i could solve that by simple adding in the WHERE part MONTH(agent_stat.sv_s_datum) =7 but then if no items been sold that month no data at all will show up not the time or anything. Any aid on how i could solve this is greatly appreciated. if there's something that's not so clear dont hesitate to ask and ill try my best to answer. after all my english isn't the best out there :P regards breezer

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  • Multiple OR Clauses in MySQL

    - by Grant
    I'm trying to grab content where id = 3 OR id = 9 OR id = 100... Keep in mind, I can have a few hundred of these ids. What is the most efficient way to write my query? $sql = "SELECT name FROM artists WHERE (id=3 OR id=9 OR .... id-100)"

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  • MySQL Delete from 1 table, using multiple tables

    - by nute
    I would like to delete all the rows found by that query: SELECT cart_abandon.* FROM cart_abandon, cart_product, txn_product, users WHERE cart_abandon.cartid = cart_product.cartid AND cart_product.productid = txn_product.productid AND txn_product.username = users.username AND users.id = cart_abandon.userid AND txn_product.txndate >= cart_abandon.abandondate The thing to keep in mind is that the query here uses 4 different tables, however I only want to delete rows from 1 table (cart_abandon). Is there an easy way to do that? Maybe this: ? DELETE cart_abandon FROM cart_abandon, cart_product, txn_product, users WHERE cart_abandon.cartid = cart_product.cartid AND cart_product.productid = txn_product.productid AND txn_product.username = users.username AND users.id = cart_abandon.userid AND txn_product.txndate >= cart_abandon.abandondate Is that valid? Correct?

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  • generic Mysql stored procedure

    - by psu
    Hi, I have the fallowing stored procedure: CREATE PROCEDURE `get`(IN tb VARCHAR(50), IN id INTEGER) BEGIN SELECT * FROM tb WHERE Indx = id; END// When I call get(user,1) I get the following: ERROR 1054 (42S22): Unknown column 'user' in 'field list'

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  • MySQL float values jumping around on insert?

    - by dubayou
    So i have a SQL table setup as such CREATE TABLE IF NOT EXISTS `points` ( `id` int(11) NOT NULL auto_increment, `lat` float(10,6) NOT NULL, `lng` float(10,6) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM; And im inserting stuff like INSERT INTO `points` (`lat`, `lng`) VALUES ('89.123456','-12.123456'); Gives me a row with lat and lng being 89.123459 and -12.123455 Whats up?

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  • MySQL Select Statement - Two Tables, Sort One Table by Count of Other Table

    - by Robert Boka
    So I have built a voting system for a custom post system i wrote. I want to be able to sort by "most voted", "Most liked", etc. I have two tables. Entry: ID, Title, Post Vote: ID, EntryID, Result I want to be able to query the vote table for each entry and see how many vote's there are, and then sort the entry's by how many vote's each table had. I have messed around with joins, etc. and cannot seem to figure it out. Any suggestions?

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  • Mysql - Grouping the result based on a mathematical operation and SUM() function

    - by SpikETidE
    Hi all... I'm having the following two tables... Table : room_type type_id type_name no_of_rooms max_guests rate 1 Type 1 15 2 1254 2 Type 2 10 1 3025 Table : reservation reservation_id start_date end_date room_type booked_rooms 1 2010-04-12 2010-04-15 1 8 2 2010-04-12 2010-04-15 1 2 Now... I have this query SELECT type_id, type_name FROM room_type WHERE id NOT IN (SELECT room_type FROM reservation WHERE start_date >= '$start_date' AND end_date <= '$end_date') What the query does is it selects the rooms that are not booked between the start date and end date. Also, as you can see from the reservation table, we also have 'number of rooms booked between the two dates' factor also... I need to add this 'no.of booked rooms between the two dates' factor also in to the query... The query should return the type of rooms for which at least one room is free between the two dates. I worked out the logic but just can't represent it as a query....! How will you do this...? Thanks for your suggestions..!

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  • PHP MYSQL Add up number of entries in single table and display in HTML

    - by Derek
    I have a table called activities which contains a number of activities for projects (for example 6 activities are related to one project). On a manage projects page, you can see the projects, and I have one column which needs to display the number of tasks associated with the project (in that particular row). So basically, I need a query or PHP calculation that can add up the number of tasks for the project and then display this number dynamically! I know exactly what I need, just do not know how to implement it. Any help is much appreciated! Thanks.

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  • How to get unique values when using a UNION mysql query

    - by Roland
    I have 2 sql queries that return results, both contain a contract number, now I want to get the unique values of contract numbers HEre's the query (SELECT contractno, dsignoff FROM campaigns WHERE clientid = 20010490 AND contractno != '' GROUP BY contractno,dsignoff) UNION (SELECT id AS contractno,signoffdate AS dsignoff FROM contract_details WHERE clientid = 20010490) So for example, if the first query before the union returns two results with contract no 10, and the sql query after the union also returns 10, then we have 3 rows in total, however because contractno of all three rows is 10, I need to have only one row returned, Is this possible?

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