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  • intersection of three sets in python?

    - by Phil Brown
    Currently I am stuck trying to find the intersection of three sets. Now these sets are really lists that I am converting into sets, and then trying to find the intersection of. Here's what I have so far: for list1 in masterlist: list1=thingList1 for list2 in masterlist: list2=thingList2 for list3 in masterlist: list3=thingList3 d3=[set(thingList1), set(thingList2), set(thingList3)] setmatches c= set.intersection(*map(set,d3)) print setmatches and I'm getting set([]) Script terminated. I know there's a much simpler and better way to do this, but I can't find one...

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  • Free vector icons

    - by rwallace
    Are there any free vector icons (as in, suitable for use in an open source project using WPF) for basic desktop program toolbar buttons like Back, Forward, Print, Save etc.?

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  • how to get ip address of my computer

    - by asthagoyal
    hello i want to get ipaddress of my computer in variable ip thru this code but it assign nothing in ip char comm[100]; int s=0; char ip[100]; sprintf(comm,"export ip=`/sbin/ifconfig eth0 | grep 'inet addr:' | cut -d: -f2 | awk '{ print $1}'`"); s=system(comm); printf("\n ip is %s",ip);

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  • python to display the special characters

    - by Suhail
    Hi, I am facing issues with the special characters like ° and ® which represent the degreee Farenheit sign and the ® represent the registered sign, when i print the string the contains the special characters, it gives output like this: Preheat oven to 350&deg F Welcome to Lorem Ipsum Inc&reg is there a way i can output the exact characters and not their codes ? please let me know.

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  • Why does Git.pm on cygwin complain about 'Out of memory during "large" request?

    - by Charles Ma
    Hi, I'm getting this error while doing a git svn rebase in cygwin Out of memory during "large" request for 268439552 bytes, total sbrk() is 140652544 bytes at /usr/lib/perl5/site_perl/Git.pm line 898, <GEN1> line 3. 268439552 is 256MB. Cygwin's maxium memory size is set to 1024MB so I'm guessing that it has a different maximum memory size for perl? How can I increase the maximum memory size that perl programs can use? update: This is where the error occurs (in Git.pm): while (1) { my $bytesLeft = $size - $bytesRead; last unless $bytesLeft; my $bytesToRead = $bytesLeft < 1024 ? $bytesLeft : 1024; my $read = read($in, $blob, $bytesToRead, $bytesRead); //line 898 unless (defined($read)) { $self->_close_cat_blob(); throw Error::Simple("in pipe went bad"); } $bytesRead += $read; } I've added a print before line 898 to print out $bytesToRead and $bytesRead and the result was 1024 for $bytesToRead, and 134220800 for $bytesRead, so it's reading 1024 bytes at a time and it has already read 128MB. Perl's 'read' function must be out of memory and is trying to request for double it's memory size...is there a way to specify how much memory to request? or is that implementation dependent? UPDATE2: While testing memory allocation in cygwin: This C program's output was 1536MB int main() { unsigned int bit=0x40000000, sum=0; char *x; while (bit > 4096) { x = malloc(bit); if (x) sum += bit; bit >>= 1; } printf("%08x bytes (%.1fMb)\n", sum, sum/1024.0/1024.0); return 0; } While this perl program crashed if the file size is greater than 384MB (but succeeded if the file size was less). open(F, "<400") or die("can't read\n"); $size = -s "400"; $read = read(F, $s, $size); The error is similar Out of memory during "large" request for 536875008 bytes, total sbrk() is 217088 bytes at mem.pl line 6.

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  • Git command to display HEAD commit id?

    - by Andrew Arnott
    What command can I use to print out the commit id of HEAD? This is what I'm doing by hand: $ cat .git/HEAD ref: refs/heads/v3.3 $ cat .git/refs/heads/v3.3 6050732e725c68b83c35c873ff8808dff1c406e1 But I need a script that can reliably pipe the output of some command to a text file such that the text file contains exactly the commit id of HEAD (nothing more or less, and not just a ref). Can anyone help?

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  • Twitter json output

    - by Bunny Rabbit
    $(function(){ $.ajax({ url:'http://api.twitter.com/1/statuses/user_timeline.json?screen_name=user_name&callback=?', //dataType:'json', success:function(data){$('body').append('the data is' +data);} }); }); the above code with dataType line prints out [objects] while with the dataType line commented it prints out nothing ...how can i get it to print the json output from the server rather then the javascript object?

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  • Python: list and string matching

    - by pete
    Hi All, I have following: temp = "aaaab123xyz@+" lists = ["abc", "123.35", "xyz", "AND+"] for list in lists if re.match(list, temp, re.I): print "The %s is within %s." % (list,temp) The re.match is only match the beginning of the string, How to I match substring in between too.

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  • Python. How to iterate through a list of lists looking for a partial match

    - by Becca Millard
    I'm completely stuck on this, without even an idea about how to wrap my head around the logic of this. In the first half of the code, I have successfully generation a list of (thousands of) lists of players names and efficiency scores: eg name_order_list = [["Bob", "Farley", 12.345], ["Jack", "Donalds", 14.567], ["Jack", "Donalds", 13.421], ["Jack", "Donalds", 15.232],["Mike", "Patricks", 10.543]] What I'm trying to do, is come up with a way to make a list of lists of the average efficiency of each player. So in that example, Jack Donalds appears multiple times, so I'd want to recognize his name somehow and average out the efficiency scores. Then sort that new list by efficiency, rather than name. So then the outcome would be like: average_eff_list = [[12.345, "Bob", "Farley"], [14.407, "Jack", "Donalds"], [10.543, "Mike", "Patricks"]] Here's what I tried (it's kind of a mess, but should be readable): total_list = [] odd_lines = [name_order_list[i] for i in range(len(name_order_list)) if i % 2 == 0] even_lines = [name_order_list[i] for i in range(len(name_order_list)) if i % 2 == 1] i = 0 j = i-1 while i <= 10650: iteration = 2 total_eff = 0 while odd_lines[i][0:2] == even_lines[i][0:2]: if odd_lines[i][0:2] == even_lines[j][0:2]: if odd_lines[j][0:2] != even_lines[j][0:2]: total_eff = even_lines[j][2]/(iteration-1) iteration -= 1 #account fr the single (rather than dual) additional entry else: total_eff = total_eff if iteration == 2: total_eff = (odd_lines[i][2] + even_lines[i][2]) / iteration else: total_eff = ((total_eff * (iteration - 2)) + (odd_lines[i][2] + even_lines[i][2])) / iteration iteration += 2 i += 1 j += 1 if i > 10650: break else: if odd_lines[i][0:2] == even_lines[j][0:2]: if odd_lines[j][0:2] != even_lines[j][0:2]: total_eff = (odd_lines[i][2] + even_lines[j][2]) / iteration else: total_eff = ((total_eff * (iteration -2)) + odd_lines[i][2]) / (iteration - 1) if total_eff == 0: #there's no match at all total_odd = [odd_lines[i][2], odd_lines[i][0], odd_lines[i][1]] total_list.append(total_odd) if even_lines[i][0:2] != odd_lines[i+1][0:2]: total_even = [even_lines[i][2], even_lines[i][0], even_lines[i][1]] else: total = [total_eff, odd_lines[i][0], odd_lines[i][1]] total_list.append(total) i += 1 if i > 10650: break else: print(total_list) Now, this runs well enough (doesn't get stuck or print someone's name multiple times) but the efficiency values are off by a large amount, so I know that scores are getting missed somewhere. This is a problem with my logic, I think, so any help would be greatly appreciated. As would any advice about how to loop through that massive list in a smarter way, since I'm sure there is one... EIDT: for this exercise, I need to keep it all in a list format. I can make new lists, but no using dictionaries, classes, etc.

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  • Strange Syntax Parsing Error in Python?

    - by user213060
    Am I missing something here? Why shouldn't the code under the "Broken" section work? I'm using Python 2.6. #!/usr/bin/env python def func(a,b,c): print a,b,c #Working: p={'c':3} func(1, b=2, c=3, ) #Working: func(1, b=2, **p,) #Broken: func(1, b=2, **p, )

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  • how to import a.py not a folder

    - by zjm1126
    zjm_code |-----a.py |-----a |----- __init__.py |-----b.py in a.py is : c='ccc' in b.py is : import a print dir(a) when i execute b.py ,it show (it import 'a' folder): ['__builtins__', '__doc__', '__file__', '__name__', '__path__'] and when i delete a folder, it show ,(it import a.py): ['__builtins__', '__doc__', '__file__', '__name__', 'c'] so my question is : how to import a.py via not delete a folder thanks

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  • How to get the list of price offers on an item from Amazon with python-amazon-product-api item_looku

    - by miernik
    I am trying to write a function to get a list of offers (their prices) for an item based on the ASIN: def price_offers(asin): from amazonproduct import API, ResultPaginator, AWSError from config import AWS_KEY, SECRET_KEY api = API(AWS_KEY, SECRET_KEY, 'de') str_asin = str(asin) node = api.item_lookup(id=str_asin, ResponseGroup='Offers', Condition='All', MerchantId='All') for a in node: print a.Offer.OfferListing.Price.FormattedPrice I am reading http://docs.amazonwebservices.com/AWSECommerceService/latest/DG/index.html?ItemLookup.html and trying to make this work, but all the time it just says: Failure instance: Traceback: <type 'exceptions.AttributeError'>: no such child: {http://webservices.amazon.com/AWSECommerceService/2009-10-01}Offer

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  • What is the best way, if possible, to send information from a Java PrintStream to a JTextPane?

    - by Daniel Reeves
    In Java, I have a package that translates XML metadata from one standard to another. This package is ultimately accessed through a single function and sends all of its output through a PrintStream object. The output sent is just a status of each file and whether or not it was translated. This is pretty fine and dandy if I'm just printing to System.out, but I'm actually wanting to print this to a JTextPane while it translates (kind of like a progress text box). It wouldn't be a big deal to just print the status after it was done translating the XML, but since there may be thousands of XML files, that's just not feasible. One thing that I've tried is to use a thread that takes all of the information from the PrintStream (which is attached to a ByteArrayOutputStream) and let it send any new information to the text pane. Unfortunately, this still sends the information all at once at the end of the translation. This does work correctly for System.out. Here's the code that does the translation and tries to show the output: public class ConverterGUI extends javax.swing.JFrame { boolean printToResultsBox = false; PrintStream printStream = null; ByteArrayOutputStream baos = null; private class ResultsPrinter implements Runnable { public ResultsPrinter() { baos = new ByteArrayOutputStream(); printStream = new PrintStream(baos); } public void run() { String tempString = ""; while (printToResultsBox) { try { if (!baos.toString().equals(tempString)) { tempString = baos.toString(); resultsBox.setText(tempString); } } catch (Exception ex) { } } } } ... ResultsPrinter rp = new ResultsPrinter(); Thread thread = new Thread(rp); thread.start(); // Do the translation. try { printToResultsBox = true; boolean success = false; TranslationEngine te = new TranslationEngine(); // fileOrFolderToConvert is a text box in the GUI. // linkNeeded and destinationFile are just parameters for the translation process. success = te.translate(fileOrFolderToConvert.getText(), linkNeeded, destinationFile, printStream); if (success) { printStream.println("File/folder translation was a success."); } resultsBox.setText(baos.toString()); } catch (Exception ex) { printStream.println("File translation failed."); } finally { printToResultsBox = false; } ... } Ultimately, this code prints out to the JTextPane just fine after all the translation is done but not during. Any suggestions? Do I need to change the PrintStream to something else?

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  • Python 2D list has weird behavor when trying to modify a single value...

    - by Brian
    Hi guys, So I am relatively new to Python and I am having trouble working with 2D Lists. Here's my code: data = [[None]*5]*5 data[0][0] = 'Cell A1' print data and here is the output (formatted for readability): [['Cell A1', None, None, None, None], ['Cell A1', None, None, None, None], ['Cell A1', None, None, None, None], ['Cell A1', None, None, None, None], ['Cell A1', None, None, None, None]] Why does every row get assigned the value?

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  • QString::number() - zero padding?

    - by elcuco
    I want to "stringify" a number and keep leading zeros. Unlike this question: http://stackoverflow.com/questions/885401/print-trailing-zeros-in-a-qstring I also need this in hex. By code now uses this, which is not enough: QString::number(myNumber,16).toUpper()

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  • How to prefix a positive number with plus sign in PHP

    - by user318466
    I need to design a function to return negative numbers unchanged but should add a + sign at the start of the number if its already no present. Example: Input Output ---------------- +1 +1 1 +1 -1 -1 It will get only numeric input. function formatNum($num) { # something here..perhaps a regex? } This function is going to be called several times in echo/print so the quicker the better.

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  • IF Statement has strange behavior

    - by BSchlinker
    I've developed a 'custom' cout, so that I can display text to console and also print it to a log file. This cout class is passed a different integer on initialization, with the integer representing the verbosity level of the message. If the current verbosity level is greater then or equal to the verbosity level of the message, the message should print. The problem is, I have messages printing even when the current verbosity level is too low. I went ahead and debugged it, expecting to find the problem. Instead, I found multiple scenarios where my if statements are not working as expected. The statement if(ilralevel_passed <= ilralevel_set) will sometimes proceed even if ilralevel_set is LESS then ilralevel_passed. You can see this behavior in the following picture (my apologizes for using Twitpic) http://twitpic.com/1xtx4g/full. Notice how ilralevel_set is equal to zero, and ilralevel_passed is equal to one. Yet, the if statement has returned true and is now moving forward to pass the line to cout. I've never seen this type of behavior before and I'm not exactly sure how to proceed debugging it. I'm not able to isolate the behavior either -- it only occurs in certain parts of my program. Any suggestions are appreciated as always. // Here is an example use of the function: // ilra_status << setfill('0') << setw(2) << dispatchtime.tm_sec << endl; // ilra_warning << "Dispatch time (seconds): " << mktime(&dispatchtime) << endl; // Here is the 'custom' cout function: #ifndef ILRA_H_ #define ILRA_H_ // System libraries #include <iostream> #include <ostream> #include <sstream> #include <iomanip> // Definitions #define ilra_talk ilra(__FUNCTION__,0) #define ilra_update ilra(__FUNCTION__,0) #define ilra_error ilra(__FUNCTION__,1) #define ilra_warning ilra(__FUNCTION__,2) #define ilra_status ilra(__FUNCTION__,3) // Statics static int ilralevel_set = 0; static int ilralevel_passed; // Classes class ilra { public: // constructor / destructor ilra(const std::string &funcName, int toset) { ilralevel_passed = toset; } ~ilra(){}; // enable / disable irla functions static void ilra_verbose_level(int toset){ ilralevel_set = toset; } // output template <class T> ilra &operator<<(const T &v) { if(ilralevel_passed <= ilralevel_set) std::cout << v; return *this; } ilra &operator<<(std::ostream&(*f)(std::ostream&)) { if(ilralevel_passed <= ilralevel_set) std::cout << *f; return *this; } }; // end of the class #endif /* ILRA_H_ */

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  • Static method not called

    - by Smile
    I'm trying to call a static method (printABC()) in this class but it's not working. If I uncomment both of the lines marked T_T (1 and 2), it works! Why does it fail with only one of the lines? import java.util.Scanner; class pro0009 { static Scanner in = new Scanner(System.in); static int A,B,C; static void printABC(){ String ABC = in.nextLine(); ABC=ABC.replace("A"," "+A+" "); ABC=ABC.replace("B"," "+B+" "); ABC=ABC.replace("C"," "+C+" "); //System.out.print(ABC.substring(1)); System.out.print(ABC); } public static void main(String[] args){ int x = in.nextInt(); //1 int y = in.nextInt(); //2 int z = in.nextInt(); //3 if(x<y){//1<2 if(x<z){ //1<3 if(y<z){//x<y<z 2<3 //1<2<3 A=x; B=y; C=z; printABC();//T_T 1 System.out.println("Here"); //pro0009.printABC();//T_T 2 //System.out.println("Here2"); }else{ //x<z<y A=x; B=z; C=y; } }else{//z<x<y A=z; B=x; C=y; } }else{//y<x if(y<z){ if(x<z){//y<x<z A=y; B=x; C=z; }else{//y<z<x A=y; B=z; C=x; } }else{//z<y<x A=z; B=y; C=x; } } } }

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