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  • 2d int array Drawing Canvas

    - by Andy
    How do you print out the contents of a 2d int array Ive code written in java for a sudoku game and im trying to create a game on the android using the same code My code in java reads in a text file(sudoku grid) i see canvas.drawText will read in a string, but how do you do it for a 2d int array, so it prints out in a grid?

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  • Having dynamic javascript on the same page as response.BinaryWrite

    - by nilesh
    Hi All, I am display a pdf document on page using response.binarywrite i.e Response.ClearHeaders() Response.ClearContent() Response.ContentType = "application/pdf" Response.BinaryWrite(result) need to call some javascript function to open up the print dialog after the pdf is loaded. is it possible Please let me know if someone knows how to achieve this ? regards Nilesh

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  • how to import a.py not a folder

    - by zjm1126
    zjm_code |-----a.py |-----a |----- __init__.py |-----b.py in a.py is : c='ccc' in b.py is : import a print dir(a) when i execute b.py ,it show (it import 'a' folder): ['__builtins__', '__doc__', '__file__', '__name__', '__path__'] and when i delete a folder, it show ,(it import a.py): ['__builtins__', '__doc__', '__file__', '__name__', 'c'] so my question is : how to import a.py via not delete a folder thanks

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  • Can't modify constant item in scalar assignment

    - by joe
    sub new { my $class = shift; my $ldap_obj = Net::LDAP->new( 'test.company.com' ) or die "$@"; my $self = { _ldap = $ldap_obj, _dn ='dc=users,dc=ldap,dc=company,dc=com', _dn_login = 'dc=login,dc=ldap,dc=company,dc=com', _description ='company', }; # Print all the values just for clarification. bless $self, $class; return $self; } what is wrong on this code : i got this error Can't modify constant item in scalar assignment at Core.pm line 12, near "$ldap_obj,"

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  • change session property in zend

    - by Behrang
    I made session using zend authentication it works good but my problem is I want to change some property of it from another action in other controller my code is: $auth = Zend_Auth::getInstance(); if($auth-hasIdentity()) { $blogId = new model_blog request; $auth-getIdentity()-user_current_blog = $blogId; print "Current Blog"; print_r($auth-getIdentity()-user_current_blog); } in this action user_current_blog change but in other action it not works!!! where I made a mistake???

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  • Break the nested(double) loop in python

    - by prosseek
    I use the following method to break the double loop in Python. for word1 in buf1: find = False for word2 in buf2: ... if res == res1: print "BINGO " + word1 + ":" + word2 find = True if find: break Is there better way to break the double loop?

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  • redefine __and__ operator

    - by wiso
    Why I can't redefine the __and__ operator? class Cut(object): def __init__(self, cut): self.cut = cut def __and__(self, other): return Cut("(" + self.cut + ") && (" + other.cut + ")") a = Cut("a>0") b = cut("b>0") c = a and b print c.cut() I want (a>0) && (b>0), but I got b, that the usual behaviour of and

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  • C program help......

    - by scott
    void main () { int c; signal (SIGINT, Handle); while (( c = getchar()) != '\n' ); return(); } void Handle(signum) { signal {SIGINT, Handle); printf ("beep \n"); } I thought it would print 'beep' until any key has been pressed but the method call is outside the loop? :S

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  • C++ random number from a set

    - by user69514
    Is it possible to print a random number in C++ from a set of numbers with ONE SINGLE statement? let's say the set is 2, 5, 22, 55, 332 i looked up rand, but I double it's possible to do in a single statement

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  • Perl pattern matching with zero width assertion

    - by Simone
    Hi everyone, I can't get why this code work: $seq = 'GAGAGAGA'; my $regexp = '(?=((G[UCGA][GA]A)|(U[GA]CG)|(CUUG)))'; # zero width match while ($seq =~ /$regexp/g){ # globally my $pos = pos($seq) + 1; # position of a zero width matching print "$1 position $pos\n"; } I know this is a zero width match and it dosn't put the matched string in $&, but why does it put it in $1? thank you!

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  • CreateObject "Access.Application.10"

    - by Daniel
    I have two Access versions installed: Microsoft Access XP (aka 2002, aka version 10.0) Microsoft Access 2007 (aka version 12.0) Wenn I let an Application run in Microsoft Access XP and call Dim o As Object Set o = CreateObject("Access.Application.10") Debug.print o.version This returns 12.0 instead of 10.0! Solutions anybody? I don't get this.

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  • PHP email form multiple select

    - by Justin Goodman
    I'm trying to set up a simple PHP contact form for a website and I need some help modifying the PHP to list multiple items from a select menu and would appreciate the help. I'm a graphic designer, not a developer, so a lot of this is way over my head. This is the problem area here: <label for="Events[]">Which Event(s) Will You Be Attending?</label> <div class="input-bg"> <select name="Events[]" size="6" multiple="MULTIPLE" class="required" id="Events[]"> <option value="Wednesday">Portfolio Show June 16</option> <option value="Thursday">Portfolio Show June 17</option> <option value="Saturday">Graduation Ceremony</option> <option value="Saturday Eve">Graduation Party</option> <option value="Not Sure">Not Sure</option> <option value="Not Coming">Not Coming</option> </select> </div> And here's the PHP: <?php // CHANGE THE VARIABLES BELOW $EmailFrom = "[email protected]"; $EmailTo = "[email protected]"; $Subject = "Graduation RSVP"; $Name = Trim(stripslashes($_POST['Name'])); $Email = Trim(stripslashes($_POST['Email'])); $Guests = Trim(stripslashes($_POST['Guests'])); $Events = Trim(stripslashes($_POST['Events'])); // prepare email body text $Body = ""; $Body .= "Name: "; $Body .= $Name; $Body .= "\n"; $Body .= "Email: "; $Body .= $Email; $Body .= "\n"; $Body .= "Guests: "; $Body .= $Guests; $Body .= "\n"; $Body .= "Events: "; $Body .= $Events; $Body .= "\n"; // send email $success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>"); // redirect to success page // CHANGE THE URL BELOW TO YOUR "THANK YOU" PAGE if ($success){ print "<meta http-equiv=\"refresh\" content=\"0;URL=http://justgooddesign.net/graduation\">"; } else{ print "<meta http-equiv=\"refresh\" content=\"0;URL=http://justgooddesign.net/graduation/error.html\">"; } ?> Any help really is appreciated!

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  • Splitting a person's name into forename and surname

    - by Nick
    ok so basically I am asking the question of their name I want this to be one input rather than Forename and Surname. Now is there any way of splitting this name? and taking just the last word from the "Sentence" e.g. name = "Thomas Winter" print name.split() and what would be output is just "Winter"

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  • What is the best way, if possible, to send information from a Java PrintStream to a JTextPane?

    - by Daniel Reeves
    In Java, I have a package that translates XML metadata from one standard to another. This package is ultimately accessed through a single function and sends all of its output through a PrintStream object. The output sent is just a status of each file and whether or not it was translated. This is pretty fine and dandy if I'm just printing to System.out, but I'm actually wanting to print this to a JTextPane while it translates (kind of like a progress text box). It wouldn't be a big deal to just print the status after it was done translating the XML, but since there may be thousands of XML files, that's just not feasible. One thing that I've tried is to use a thread that takes all of the information from the PrintStream (which is attached to a ByteArrayOutputStream) and let it send any new information to the text pane. Unfortunately, this still sends the information all at once at the end of the translation. This does work correctly for System.out. Here's the code that does the translation and tries to show the output: public class ConverterGUI extends javax.swing.JFrame { boolean printToResultsBox = false; PrintStream printStream = null; ByteArrayOutputStream baos = null; private class ResultsPrinter implements Runnable { public ResultsPrinter() { baos = new ByteArrayOutputStream(); printStream = new PrintStream(baos); } public void run() { String tempString = ""; while (printToResultsBox) { try { if (!baos.toString().equals(tempString)) { tempString = baos.toString(); resultsBox.setText(tempString); } } catch (Exception ex) { } } } } ... ResultsPrinter rp = new ResultsPrinter(); Thread thread = new Thread(rp); thread.start(); // Do the translation. try { printToResultsBox = true; boolean success = false; TranslationEngine te = new TranslationEngine(); // fileOrFolderToConvert is a text box in the GUI. // linkNeeded and destinationFile are just parameters for the translation process. success = te.translate(fileOrFolderToConvert.getText(), linkNeeded, destinationFile, printStream); if (success) { printStream.println("File/folder translation was a success."); } resultsBox.setText(baos.toString()); } catch (Exception ex) { printStream.println("File translation failed."); } finally { printToResultsBox = false; } ... } Ultimately, this code prints out to the JTextPane just fine after all the translation is done but not during. Any suggestions? Do I need to change the PrintStream to something else?

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  • f# types' properties in inconsistent order and of slightly differing types

    - by philbrowndotcom
    I'm trying to iterate through an array of objects and recursively print out each objects properties. Here is my object model: type firmIdentifier = { firmId: int ; firmName: string ; } type authorIdentifier = { authorId: int ; authorName: string ; firm: firmIdentifier ; } type denormalizedSuggestedTradeRecommendations = { id: int ; ticker: string ; direction: string ; author: authorIdentifier ; } Here is how I am instantiating my objects: let getMyIdeasIdeas = [| {id=1; ticker="msfqt"; direction="buy"; author={authorId=0; authorName="john Smith"; firm={firmId=12; firmName="Firm1"}};}; {id=2; ticker="goog"; direction="sell"; author={authorId=1; authorName="Bill Jones"; firm={firmId=13; firmName="ABC Financial"}};}; {id=3; ticker="DFHF"; direction="buy"; author={authorId=2; authorName="Ron James"; firm={firmId=2; firmName="DEFFirm"}};}|] And here is my algorithm to iterate, recurse and print: let rec recurseObj (sb : StringBuilder) o= let props : PropertyInfo [] = o.GetType().GetProperties() sb.Append( o.GetType().ToString()) |> ignore for x in props do let getMethod = x.GetGetMethod() let value = getMethod.Invoke(o, Array.empty) ignore <| match value with | :? float | :? int | :? string | :? bool as f -> sb.Append(x.Name + ": " + f.ToString() + "," ) |> ignore | _ -> recurseObj sb value for x in getMyIdeas do recurseObj sb x sb.Append("\r\n") |> ignore If you couldnt tell, I'm trying to create a csv file and am printing out the types for debugging purposes. The problem is, the first element comes through in the order you'd expect, but all subsequent elements come through with a slightly different (and confusing) ordering of the "child" properties like so: RpcMethods+denormalizedSuggestedTradeRecommendationsid: 1,ticker: msfqt,direction: buy,RpcMethods+authorIdentifierauthorId: 0,authorName: john Smith,RpcMethods+firmIdentifierfirmId: 12,firmName: Firm1, RpcMethods+denormalizedSuggestedTradeRecommendationsid: 2,ticker: goog,direction: sell,RpcMethods+authorIdentifierauthorName: Bill Jones,RpcMethods+firmIdentifierfirmName: ABC Financial,firmId: 13,authorId: 1, RpcMethods+denormalizedSuggestedTradeRecommendationsid: 3,ticker: DFHF,direction: buy,RpcMethods+authorIdentifierauthorName: Ron James,RpcMethods+firmIdentifierfirmName: DEFFirm,firmId: 2,authorId: 2, Any idea what is going on here?

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  • Python float copy question

    - by SJA
    Hi, I'm puzzled by some behaviour I'm seeing when copying a float array member into another variable - please help! For example data_entry[1] = 9.6850069951 new_value = data_entry[1] <comment> #print both 9.6850069951 9.6850663300 I'm aware of the problem of binary storage of floats but I thought with a direct copy of memory we would end up with the same value. Any ideas? I need better precision than this! thanks in advance Stuart

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  • Url conversion in PHP

    - by ayush
    i have the following url in a html page- /delete/Release 1 But when i am trying to print it it comes in following manner- /delete/Release%201 Can anyone suggest how to convert this hex value of %20 into a white space in PHP.

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  • How to redirect within a monad in Yesod?

    - by Squazic
    I'm currently using the fb package to write a Yesod app that takes data from Facebook. In my Handler, I've managed to get the first step of the authentication to work, but I need to redirect to the url that getUserAccessTokenStep1 returns, which I've defined as fbRedirUrl. I'm having trouble with all the monad wrapping and type checking to make sure I can redirect to this url. getAccessTokenR :: Handler RepHtml getAccessTokenR = do withManager $ \manager -> do FB.runFacebookT creds manager $ do fbRedirUrl <- FB.getUserAccessTokenStep1 redirUrl [] liftIO $ print fbRedirUrl

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  • Haskell Type error

    - by Jon
    I am getting a Couldn't match expected type error on this code and am not sure why. Would appreciate it if someone could point me in the right direction as to fixing it. import qualified Data.ByteString.Lazy as S import Data.Binary.Get import Data.Word getBinary :: Get Word16 getBinary = do a <- getWord16be "Test.class" return (a) main :: IO () main = do contents <- S.getContents print getBinary contents Specifically it cannot match expected type 'S.ByteString - IO ()' to inferred type 'IO ()'

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