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  • How to connect two query results?

    - by nijansen
    I want to retrieve all ids within a certain timespan. The timestamps however, are stored in a different table: Table A has column my_id Table B has columns my_id, timestamp I would want something like SELECT id, time FROM (SELECT my_id AS id FROM A) q1, (SELECT timestamp AS time FROM B WHERE my_id = id) q2 ; But how can I get the value of id within a different subquery? Is there an elegant solution for this problem?

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  • jQuery: Sustain a hover over two elements

    - by wkdown
    I have an <img> that, once hovered over, animates and fades in the <div> of a larger version of the picture, along with text and a hyperlink. When mousing out, the <div> animates and fades away. This works fine, only my hover function only pertains to the <img> itself. As soon as either a) the <div> appears over the <img>, or b) one mouses off the <img> to get to the <div>, jQuery reads a mouseout and animates the <div> away. How do I re-write my jQuery to allow me to fix this? Thanks in advance ... Here is a portion of the HTML: <img runat="server" src="~/images/pc_blocks_navigation_spec1.gif" class="navigation_spec1" alt="" /> <div class="navigation_spec1_panel"> <p>filler <a href="#">test</a></p> </div> ... and the jQuery ... $('.navigation_spec1_panel').hide().css('opacity','0.0'); $('.navigation_spec1').hover(function() { $('.navigation_spec1_panel').animate({ width: '337px', height: '234px', opacity: 1.0 }, 1250 ); }, function() { $('.navigation_spec1_panel').animate({ width: '1px', height: '1px', opacity: 0.0 }, 1250); }); }); (Side comment: My animated <div> does not appear over / on top of other <div>s coded after this one in IE 6 or 7. The <div> appears behind them instead, regardless of z-index. Suggestions?)

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  • R: optimal way of computing the "product" of two vectors

    - by Musa
    Hi, Let's assume that I have a vector r <- rnorm(4) and a matrix W of dimension 20000*200 for example: W <- matrix(rnorm(20000*200),20000,200) I want to compute a new matrix M of dimension 5000*200 such that m11 <- r%*%W[1:4,1], m21 <- r%*%W[5:8,1], m12 <- r%*%W[1:4,2] etc. (i.e. grouping rows 4-by-4 and computing the product). What's the optimal (speed,memory) way of doing this? Thanks in advance.

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  • Selecting two specific mysql table rows in a single query

    - by Scotta
    Lets say I have a table with 20 entries. They are sorted by date (date is a column name _) in descending order. How would I go about selecting ONLY the newest entry and the 15th oldest entry? I am getting all 15 results by doing the following query SELECT * FROM mytable m WHERE col1 = "zzz" ORDER BY date DESC LIMIT 15;

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  • I wanna make a UDP comunication between two or more computers using c++ on linux

    - by HMojtaba
    Hi every one! I really need to make this connection throw wireless (or lan ethernet). I have done this on windows (VS2008 C#, sockets), but here on linux (ubuntu 10.04) I have installed mono, and i can handle many things there, but it's speed is unacceptable for my 600MHz processor. so i decided to move on c++, but i'm new to c++ and i'm not familiar to many of it's headers. Is there any header or any library which can do that for me? thanks

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  • Create rails record from two ids

    - by Michael Luby
    The functionality I'm trying to build allows Users to Visit a Restaurant. I have Users, Locations, and Restaurants models. Locations have many Restaurants. I've created a Visits model with user_id and restaurant_id attributes, and a visits_controller with create and destroy methods. Thing is, I can't create an actual Visit record. Any thoughts on how I can accomplish this? Or am I going about it the wrong way. Here's the code: Model: class Visit < ActiveRecord::Base attr_accessible :restaurant_id, :user_id belongs_to :user belongs_to :restaurant end View: <% @restaurants.each do |restaurant| %> <%= link_to 'Visit', location_restaurant_visits_path(current_user.id, restaurant.id), method: :create %> <% @visit = Visit.find_by_user_id_and_restaurant_id(current_user.id, restaurant.id) %> <%= @visit != nil ? "true" : "false" %> <% end %> Controller: class VisitsController < ApplicationController before_filter :find_restaurant before_filter :find_user def create @visit = Visit.create(params[:user_id => @user.id, :restaurant_id => @restaurant.id]) respond_to do |format| if @visit.save format.html { redirect_to location_restaurants_path(@location), notice: 'Visit created.' } format.json { render json: @visit, status: :created, location: @visit } else format.html { render action: "new" } format.json { render json: @visit.errors, status: :unprocessable_entity } end end end def destroy @visit = Visit.find(params[:user_id => @user.id, :restaurant_id => @restaurant.id]) @restaurant.destroy respond_to do |format| format.html { redirect_to location_restaurants_path(@restaurant.location_id), notice: 'Unvisited.' } format.json { head :no_content } end end private def find_restaurant @restaurant = Restaurant.find(params[:restaurant_id]) end def find_user @user = current_user end end

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  • Two quick Mathematica questions

    - by sciguy
    How do I remove the numbers on the x-axis only not the y-axis? Is it possible to shift the y-axis without shifting the functions? What I mean is, instead of having the y-axis at x = 0, could I have it at x = -5?

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  • Matching two sections same number of times

    - by Leszczu
    Hello, i need a HTML to parse: <span>some text<span><span><span>text</span></span></span></span> I need to remove unnecessary <span> occurrences, so that output is: <span>some text<span>text</span></span> I wrote a regex, which does this once: /<SPAN>[^<]*<\/SPAN>/i How to make this work same number of times on both <span> and </span>?

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  • Parsing in groovy between two tags ?

    - by fabien-barbier
    I would like to parse this Gstring with groovy : Format type : CodeClass, Name, Accession, Count. def txt = """ <Lane_Attributes> ID,1 FovCount,600 FovCounted,598 ... </Lane_Attributes> """ And get a map like : Map = [ID:1, FovCount:600, FovCounted:598] How can I : - extract text between tag and ?, - and convert to a map ?

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  • Normalization two types of customers into one table

    - by JDewzy
    I am trying to model a sales situation where you can sell to a person or to a business with a contact person. I cannot figure out the proper way to do this. It seems like 2 tables would be incorrect. But how do I model a Customer table that can be a business or a person? Would I just have a boolean for "business" and an additional "business_name" field that would default to Null. But then I have to do an if/then on the columns and that seems like poor design. Any advice, direction, or links is appreciated.

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  • How to compare two vectors, in C++

    - by Vincenzo
    This is my code: #include <algorithm> void f() { int[] a = {1, 2, 3, 4}; int[] b = {1, 2, 100, 101}; // I want to do something like this: // int* found = compare(a[0], a[3], b[0]); // in order to get a pointer to a[2] } Maybe I missed this algorithm in the manual… Please help :)

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  • Unable to change two things about a single row in mysql with php

    - by user1624005
    Here's the code: $id = intval($_POST['id']); $score = "'" . $_POST['score'] . "'"; $shares = "'" . $_POST['shares'] . "'"; $conn = new PDO('mysql:host=localhost;dbname=news', 'root', ''); $stmt = $conn->prepare("UPDATE news SET 'shares' = :shares, 'score' = :score WHERE id = :id"); $stmt -> execute(array( 'shares' => $shares, 'score' => $score, 'id' => $id )); And it doesn't work. I am unsure as to how I would see the error that I assume mysql is giving somewhere, and I've tried everything I could think of. Using double quotes and adding the variables into the statement right away. Adding single quotes to shares and score. How am I supposed to be doing this?

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  • C: Comparing two long integers (very strange)

    - by Kyle
    Hi, I have following situation (unix) : x is a long and has value 300 y is a long and has value 50000 if (x <= y) printf("Correct."); if (x > y) printf("Ouch."); Now I always get "Ouch". That means the program keeps telling me that 300 is greater than 50000! It only works again when I do if ((int)x <=(int) y) printf("Correct."); if ((int)x > (int)y) printf("Ouch."); So what is wrong with the comparison operators?

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