Search Results

Search found 8646 results on 346 pages for 'echo flow'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 188/346 | < Previous Page | 184 185 186 187 188 189 190 191 192 193 194 195  | Next Page >

  • Multi-line code in PHP interactive shell

    - by Andrei
    I'm learning to use the PHP interactive shell, but I'm having trouble with multi-line code. Using backslashes like in the UNIX shells doesn't seem to work. What am I doing wrong ? php > function test(){\ php { echo "test";\ php { }\ php > test(); PHP Parse error: syntax error, unexpected T_ECHO, expecting T_STRING in php shell code on line 2

    Read the article

  • pagination - 10 pages per page

    - by arthur
    I have a pagination script that displays a list of all pages like so: prev [1][2][3][4][5][6][7][8][9][10][11][12][13][14] next But I would like to only show ten of the numbers at a time: prev [3][4][5][6][7][8][9][10][11][12] next How can I accomplish this? Here is my code so far: <?php /* Set current, prev and next page */ $page = (!isset($_GET['page']))? 1 : $_GET['page']; $prev = ($page - 1); $next = ($page + 1); /* Max results per page */ $max_results = 2; /* Calculate the offset */ $from = (($page * $max_results) - $max_results); /* Query the db for total results. You need to edit the sql to fit your needs */ $result = mysql_query("select title from topics"); $total_results = mysql_num_rows($result); $total_pages = ceil($total_results / $max_results); $pagination = ''; /* Create a PREV link if there is one */ if($page > 1) { $pagination .= '< a hr_ef="?page='.$prev.'">Previous</a> '; } /* Loop through the total pages */ for($i = 1; $i <= $total_pages; $i++) { if(($page) == $i) { $pagination .= $i; } else { $pagination .= '< a hr_ef="index.php?page='.$i.'">'.$i.'</a>'; } } /* Print NEXT link if there is one */ if($page < $total_pages) { $pagination .= '< a hr_ef="?page='.$next.'"> Next</a>'; } /* Now we have our pagination links in a variable($pagination) ready to print to the page. I pu it in a variable because you may want to show them at the top and bottom of the page */ /* Below is how you query the db for ONLY the results for the current page */ $result=mysql_query("select * from topics LIMIT $from, $max_results "); while ($i = mysql_fetch_array($result)) { echo $i['title'].'<br />'; } echo $pagination; ?>

    Read the article

  • how to use alert in php and js combined

    - by user295189
    have a need to alert through php, I have the code below. Problem is that it works as long as I dont use header redirect. But as soon as I use it..I loose alert. echo "I will do some functions here in php"; if($value == 1){ alert('ok working'); } header(location: 'someOtherpagethanthis.php');

    Read the article

  • Hyperlink for each record

    - by shantanuo
    I need a link for each depotname that will bring up a child window with the details of the last 10 backup status. while($data=mysql_fetch_array($res)) { if(is_null($depot_array) || !in_array($data['depotname'],$depot_array )) { $depot_array[$r]=$data['depotname']; if($data['SCP_status'] <> 'success') { echo "<tr id='fail'>"; The results of the following query should be displayed in a child window. select * from backup_log where depotname = $data['depotname']

    Read the article

  • mysql_fetch_array() expects parameter 1 to be resource problem

    - by user225269
    I don't get it, I see no mistakes in this code but there is this error, please help: mysql_fetch_array() expects parameter 1 to be resource problem <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO=".$_GET['id']); ?> <?php while ($row = mysql_fetch_array($result)) { ?> <table class="a" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="get" action="updateact.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Update Students</td> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $_GET['id']; ?>"></td> </tr> <tr> <td width="30" height="35"><font size="2">*Year:</td> <td width="30"><input name="yr" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $row["YEAR"]; ?>"></td> <?php } ?> I'm just trying to load the data in the forms but I don't know why that error appears. What could possibly be the mistake in here?

    Read the article

  • I am having trouble using jquery to submit a form. It was working before

    - by noah
    When a user clicks a link it uses jquery ajax to submit a form to go to paypal. Not working for some reason. Really appreciate any help... LINK TO CLICK I put this in an href for onClick: javascript:go_paypal(); CODE TO EXECUTE ON CLICK function go_paypal() { data = 'req_paypal=1'; $.blockUI({ message: '<h1> Going to Paypal...</h1>',css:{background:'#000'} }); $.ajax({ type: "POST", url: "index.php", data: data, success: function(data) { $("#paypal_form").html(data); $("#payPalForm").submit(); } , error: function() {$.unblockUI(); alert('Unable to communicate to server.'); } }); return false; } CODE TO GO ON SUBMIT if(isset($_POST['req_paypal']) && $_POST['req_paypal'] == 1 ) { $sql = 'INSERT INTO `transactions` (id,type,ip,time,ammount,status) VALUES (NULL,1,\''.$_SERVER['REMOTE_ADDR'].'\',\''.time().'\',\''.$global['paypal_prod_amount'].'\',0) '; echo $sql; mysql_query($sql); $id = mysql_insert_id(); $html = ' <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post" id="payPalForm"> <input type="hidden" name="item_number" value="One Year of Imgur Pro"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="no_note" value="1"> <input type="hidden" name="business" value="'.$global['paypal_email'].'"> <input type="hidden" name="custom" value="'.base64_encode($id).'"> <input type="hidden" name="currency_code" value="USD"> <input type="hidden" name="return" value="'.$global['paypal_return'].'"> <input name="item_name" type="hidden" id="item_name" value="One Year of Imgur Pro" > <input name="amount" type="hidden" id="amount" value="'.$global['paypal_prod_amount'].'" > </form> '; echo $html;exit; }

    Read the article

  • Ant variable does not exists in Ubuntu 10.10

    - by Nishat Baig
    I am trying to set up ANT build. However when I invoke build command helloworld_15/${NAME} does not exist. BUILD FAILED (total time: 0 seconds) Also the configure variables does not seems to be assigned. However i have set them into /etc/envitonment I tried echo $<varaiable_name> and value get displayed. Tried to google but not solutions seems am the first one having this issue. PS: OS Ubuntu 10.10

    Read the article

  • PHP something faster than explode to get filename from URL

    - by FFish
    My URL's can be absolute or relative: $rel = "date/album/001.jpg"; $abs = "http://www.site.com/date/album/image.jpg"; function getFilename($url) { $imgName = explode("/", $url); $imgName = $imgName[count($imgName) - 1]; echo $imgName; } There must be a faster way to do this right? Maybe a reg expression? But that's Chinese to me..

    Read the article

  • PHP looping through an array to fetch a value for each key from database (third normal form)

    - by zomboble
    I am building a system, mostly for consolidating learning but will be used in practice. I will try and verbally explain the part of the E-R diagram I am focusing on: Each cadet can have many uniformID's Each Uniform ID is a new entry in table uniform, so cadets (table) may look like: id | name | ... | uniformID 1 | Example | ... | 1,2,3 uniform table: id | notes | cadet 1 | Need new blahh | 1 2 | Some stuff needed | 1 3 | Whatever you like | 1 On second thought, looks like I wont need that third column in the db. I am trying to iterate through each id in uniformID, code: <?php $cadet = $_GET['id']; // set from URL $query = mysql_query("SELECT `uniformID` FROM `cadets` WHERE id = '$cadet' LIMIT 1") or die(mysql_error()); // get uniform needed as string // store it while ($row = mysql_fetch_array($query)) { $uniformArray = $row['uniformID']; } echo $uniformArray . " "; $exploded = explode(",", $uniformArray); // convert into an array // for each key in the array perform a new query foreach ($exploded as $key => $value) { $query(count($exploded)); $query[$key] = mysql_query("SELECT * FROM `uniform` WHERE `id` = '$value'"); } ? As I say, this is mainly for consolidation purposes but I have come up with a error, sql is saying: Fatal error: Function name must be a string in C:\wamp\www\intranet\uniform.php on line 82 line 82 is: $query[$key] = mysql_query("SELECT * FROM `uniform` WHERE `id` = '$value'"); I wasn't sure it would work so I tried it and now i'm stuck! EDIT: Thanks to everyone who has contributed to this! This is now the working code: foreach ($exploded as $key => $value) { //$query(count($exploded)); $query = mysql_query("SELECT * FROM `uniform` WHERE `id` = '$value'"); while ($row = mysql_fetch_array($query)) { echo "<tr> <td>" . $row['id'] . "</td> <td>" . $row['note'] . "</td> </tr>"; } } Added the while and did the iteration by nesting it in the foreach

    Read the article

  • Zend Framework: View variable in layout script is always null

    - by understack
    I set a view variable in someAction function like this: $this->view->type = "some type"; When I access this variable inside layout script like this: <?php echo $this->type ?> it prints nothing. What's wrong? My application.ini settings related to layout resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts/" resources.layout.layout = "layout" ; changed 'default' to 'layout'

    Read the article

  • php function output ina table row... how?

    - by user352868
    I want to run this function but show the result in a table row strlen($cat_row['sms'] This is what i came up with but it is not working: echo "<tr><td bgcolor=#626E7A>".**strlen($cat_row['cars']**."</td></tr>"; How do you show result of a php function in a table row? i am trying to format the output some how. please help

    Read the article

  • PHP using Declare ? What is a tick?

    - by ArneRie
    Iam a little bit confused by php function declare. What exactly is an single tick, i thought 1 tick = one line of code? But if i use: function myfunc() { print "Tick"; } register_tick_function("myfunc"); declare(ticks=1) { echo 'foo!bar'; } The script prints : "Tick" 2 Times??

    Read the article

  • PHP syntax question: global $argv, $argc;

    - by Andrew
    So I have a PHPUnit test, and found this code within a function. global $argv, $argc; echo $argc; print_r($argv); I understand what these variables represent (arguments passed from the command line), but I've never seen this syntax before:global $argv, $argc; What specifically is going on here?

    Read the article

  • Python | How to send a JSON response with name assign to it

    - by MMRUser
    How can I return an response (lets say an array) to the client with a name assign to it form a python script. echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; in this scenario it returns an array with the name(jsonValidateReturn) assign to it also this can be accessed by jsonValidateReturn[1],so I want to do the same using a python script. I tried it once but it didn't go well array_to_js = [vld_id, vld_error, False] array_to_js[2] = False jsonValidateReturn = simplejson.dumps(array_to_js) return HttpResponse(jsonValidateReturn, mimetype='application/json') Thanks.

    Read the article

  • MySQL Queries using Doctrine & CodeIgniter

    - by 01010011
    Hi, How do I write plane SQL queries using Doctrine connection object and display the results? For example, how do I perform: SELECT * FROM table_name WHERE column_name LIKE '%anything_similar_to_this%'; using Doctrine something like this (this example does not work) $search_key = 'search_for_this'; $conn = Doctrine_Manager::connection(); $conn->execute('SELECT * FROM table_name WHERE column_name LIKE ?)', $search_key); echo $conn;

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 184 185 186 187 188 189 190 191 192 193 194 195  | Next Page >