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  • How to check if a string has earlier been set using iabbr (full match)

    - by Sumit
    I am trying to check if a lhs is already abbreviated in vim. mapcheck, however, seems to have a problem. For example, iabbr swt switch echo mapcheck('sw','i',1) returns "switch" even when "switch" defined for "swt". mapargs seem to return a string even if there is a partial match with the lhs. Is there a way to find if an abbreviation has been defined for the "exact" match, i.e., the above mapcheck returning a "" instead.

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  • error in script

    - by lego69
    can somebody please help, I'm working with C-Shell, I'm trying to run this script set callsTo = "`cut -d" " -f2 ${1}`" echo $callsTo cut receives data from the file which is the first parameter > ./myscript data I need only second field from every row -f2 after that I want to check if the data was stored, but I receive or an error unmatched `. or empty row, what is wrong with my script, thanks in advance for any help

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  • Why PHP Error: Call to a member function set_prefix() on a non-object

    - by Rebol Tutorial
    I got this error Fatal error: Call to a member function set_prefix() on a non-object in /home/reboltutorial/reboltutorial.com/wp-settings.php on line 254 line 254 contains: $prefix = $wpdb->set_prefix($table_prefix); // set up global tables This occurs if I try to call index_wordpress() instead of calling these two lines define('WP_USE_THEMES', true); require('./wp-blog-header.php'); so this doesn't work: <?php function index_wordpress() { define('WP_USE_THEMES', true); require('./wp-blog-header.php'); } ?> <?php if(!function_exists('apache_request_headers')) { function apache_request_headers() { $headers = array(); foreach($_SERVER as $key => $value) { if(substr($key, 0, 5) == 'HTTP_') { $headers[str_replace(' ', '-', ucwords(str_replace('_', ' ', strtolower(substr($key, 5)))))] = $value; } } return $headers; } } function getCurrentPageUrl() { $pageURL = 'http'; if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} $pageURL .= "://"; if ($_SERVER["SERVER_PORT"] != "80") { $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"]; } else { $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]; } return $pageURL; } $a = apache_request_headers(); $pos = strrpos($a["User-Agent"], "REBOL"); if ($pos === false) { index_wordpress(); } else { if ($_SERVER['REMOTE_ADDR'] != "69.163.203.14") { $command= './cgi-bin/index.cgi '. '"' . getCurrentPageUrl() . '"'; echo system($command); } else { index_wordpress(); } } ?> while this works: <?php if(!function_exists('apache_request_headers')) { function apache_request_headers() { $headers = array(); foreach($_SERVER as $key => $value) { if(substr($key, 0, 5) == 'HTTP_') { $headers[str_replace(' ', '-', ucwords(str_replace('_', ' ', strtolower(substr($key, 5)))))] = $value; } } return $headers; } } function getCurrentPageUrl() { $pageURL = 'http'; if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} $pageURL .= "://"; if ($_SERVER["SERVER_PORT"] != "80") { $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"]; } else { $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]; } return $pageURL; } $a = apache_request_headers(); $pos = strrpos($a["User-Agent"], "REBOL"); if ($pos === false) { define('WP_USE_THEMES', true); require('./wp-blog-header.php'); } else { if ($_SERVER['REMOTE_ADDR'] != "69.163.203.14") { $command= './cgi-bin/index.cgi '. '"' . getCurrentPageUrl() . '"'; echo system($command); } else { define('WP_USE_THEMES', true); require('./wp-blog-header.php'); } } ?>

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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  • sending full form data to back end using jquery

    - by pradeep
    i have a form that is dynamically built. so the number of form elements arr not fixed. I wnat to send whole of $_POSt data from the form using jquery to back end for processing .i cant use jquery form plugin as the jquery version i am using is old. any other way ? i tied to do like this $.post('all_include_files/update_save.php',{variable:"<?php echo json_encode($_POST) ?>"},function(data) { alert(data); }) but did not work

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  • How to grep curl -I header information

    - by Mint
    Im trying to get the redirect link from a site by using curl -I then grep to "location" and then sed out the location text so that I am left with the URL. But this doesn't work, it will outputs the URL to screen and doesn't put it test=$(curl -I "http://www.redirectURL.com/" 2> /dev/null | grep "location" | sed -E 's/location:[ ]+//g') echo "1..$test..2" Which then outputs: ..2http://www.newURLfromRedirect.com/bla Whats going on?

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  • Why is this simple hello world PHP code not working?

    - by Silva
    class saySomething { var $helloWorld = 'hello world'; function sayHelloWorld($helloWorld) { echo $helloWorld; } } $saySomething = new saySomething(); $saySomething->sayHelloWorld(); the above gives this error: Warning: Missing argument 1 for saySomething::sayHelloWorld(), called in C:\xampp\htdocs\test.php on line 15 and defined in C:\xampp\htdocs\test.php on line 7

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  • Disable Dojo validation on certain fields

    - by Eric LaForce
    I would like to disable client side validation on certain fields in my user form. Currently I have two sets of fields that are displayed depending on the value of a previous drop down list. i.e. if the drop down list is set to value "A" 1 new field appears in the form. If the drop down list is set to value "B" 3 new fields appear in the form (mutually exclusive from the new form field when "A" is selected). Currently my Dojo client side validation fails because the fields that are not shown to the user (and thus no data can be inserted into those fields) fails to validate. Currently I determined that I can set the "validate" attribute to return true like so: <input type="text" id="companycity" name="companycity" class="textinput" value="<?php echo set_value('companycity'); ?>" style="<?php if(isset($errorData['companycity'])){echo $errorData['companycity'];} ?>" dojotype="dijit.form.ValidationTextBox" required="true" trim="true" validate='return true'" regexp="([a-zA-Z]{1,25})" invalidMessage="Invalid value. Must be between 1 and 25 alphabetic characters long."> This fixes my issue for hidden fields. However this now means that no validation is performed when this field becomes visible to the user (i.e. the validate attribute is still set to return true). I have tried removing the validate property when a field is displayed to the user like so: dijit.byId('companycode').attr('validate',''); This just set the attribute to nothing. This however gives errors in firebug saying validate method not found, so I take that to mean I did not remove this attribute correctly or removing this attribute is not the appropriate way to do this. I have also looked at overriding the validator method here but this doesnt seem like what I want either. I do not want to have to rewrite all the validation methods in place of dojo's. I just want dojo not to validate if the field is not visible to the user. Thanks for any advice or help.

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  • array with sessions, only prints one letter

    - by jolabero
    On login: $result = mysql_query("SELECT `id`, `username`, `email` FROM `users` WHERE `username` = '$username' AND `password` = '$passwd'"); $userdata = array('id','username','email'); $_SESSION['user'] = mysql_result($result, 0, $userdata); And when i want to print the users username echo $_SESSION['user']['username'] it only prints the first letter :/ whats wrong`?

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  • Add a + sign to a +ve number in PHP

    - by user318466
    I need to design a function to return -ve numbers unchanged but should add a + sign at the start of the number if its alreay no present. Example: Input Output ---------------- +1 +1 1 +1 -1 -1 It will get only numeric input. function formatNum($num) { # something here..perhaps a regex? } This function is going to be called several times in echo/print so the quicker the better.

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  • Maybe This is dead-simple stupid question, but how PHP translate our code ?

    - by justjoe
    i got this code ` // // prints out "Hello World!" // hello_world(); //First call function hello_world() { echo "Hello World!<br/>\n"; } hello_world(); //second call ?>` Both of 'hello_world' call will print out the same result. It's easily to understand why the second call will be output 'Hello world', but how the first call output the same where it's been call before the initiation of the function hello_world itself ?enter code here

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  • Pass variables between separate instances of ruby (without writing to a text file or database)

    - by boulder_ruby
    Lets say I'm running a long worker-script in one of several open interactive rails consoles. The script is updating columns in a very, very, very large table of records. I've muted the ActiveRecord logger to speed up the process, and instruct the script to output some record of progress so I know how roughly how long the process is going to take. That is what I am currently doing and it would look something like this: ModelName.all.each_with_index do |r, i| puts i if i % 250 ...runs some process... r.save end Sometimes its two nested arrays running, such that there would be multiple iterators and other things running all at once. Is there a way that I could do something like this and access that variable from a separate rails console? (such that the variable would be overwritten every time the process is run without much slowdown) records = ModelName.all $total = records.count records.each_with_index do |r, i| $i = i ...runs some process... r.save end meanwhile mid-process in other console puts "#{($i/$total * 100).round(2)}% complete" #=> 67.43% complete I know passing global variables from one separate instance of ruby to the next doesn't work. I also just tried this to no effect as well unix console 1 $X=5 echo {$X} #=> 5 unix console 2 echo {$X} #=> "" Lastly, I also know using global variables like this is a major software design pattern no-no. I think that's reasonable, but I'd still like to know how to break that rule if I'd like. Writing to a text file obviously would work. So would writing to a separate database table or something. That's not a bad idea. But the really cool trick would be sharing a variable between two instances without writing to a text file or database column. What would this be called anyway? Tunneling? I don't quite know how to tag this question. Maybe bad-idea is one of them. But honestly design-patterns isn't what this question is about.

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  • trying to show a variable in my layout

    - by user1400
    hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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  • Manipulating values from database table with php

    - by charliecodex23
    I currently have 5 tables in MySQL database. Some of them share foreign keys and are interdependent of each other. I am displaying classes accordingly to their majors. Each class is taught during the fall, spring or all_year. In my database I have a table named semester which has an id, year, and semester fields. The semester field in particular is a tinyint that has three values 0, 1, 2. This signifies the fall, spring or all_year. When I display the query instead of having it show 0 or 1 or 2 can I have it show fall, spring etc? Extra: How can I add space to the end of each loop so the data doesn't look clustered? Key 0 Fall 1 Spring 2 All-year PHP <? try { $pdo = new PDO ("mysql:host=$hostname;dbname=$dbname","$username","$pw"); } catch (PDOException $e) { echo "Failed to get DB handle: " . $e->getMessage() . "\n"; exit; } $query = $pdo->prepare("SELECT course.name, course.code, course.description, course.hours, semester.semester, semester.year FROM course LEFT JOIN major_course_xref ON course.id = major_course_xref.course_id LEFT JOIN major ON major.id = major_course_xref.major_id LEFT JOIN course_semester_xref ON course.id = course_semester_xref.course_id LEFT JOIN semester ON course_semester_xref.semester_id = semester.id"); $query->execute(); if ($query->execute()){ while ($row = $query->fetch(PDO::FETCH_ASSOC)){ print $row['name'] . "<br>"; print $row['code'] . "<br>"; print $row['description'] . "<br>"; print $row['hours'] . " hrs.<br>"; print $row['semester'] . "<br>"; print $row['year'] . "<br>"; } } else echo 'Could not fetch results.'; unset($pdo); unset($query); ?> Current Display Computer Programming I CPSC1400 Introduction to disciplined, object-oriented program development. 4 hrs. 0 2013 Desire Display Computer Programming I CPSC1400 Introduction to disciplined, object-oriented program development. 4 hrs. Fall 2013

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  • Require_once to variable

    - by swamprunner7
    I want to call require_once("test.php") but not display result and save it into variable like this: //pseudocode $test = require_once('test.php'); //some operations like $test = preg_replace(…); echo $test; Is it possible?

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  • Distributing an executable zip file with __main__.py, how to access extra data?

    - by pygabriel
    I'm doing a little program and I want to distribute using this recipe: single directory with _main_.py in it zip this directory and echo #!/usr/bin/env python\n file.zip making it executable The problem is that in this package I have also extra files (I'm using pygtk toolkit and I need images and ui xml files). When I try to access these files I have the error that the resource is unavailable (the path that I'm trying to open is something like file.zip/gui/gui.ui ). How can I handle this situation?

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  • PHP-OOP extending two classes?

    - by user1292810
    I am very beginner to OOP and now I am trying to write some PHP class to connect with FTP server. class ftpConnect { private $server; private $user; private $password; private $connection_id; private $connection_correct = false; public function __construct($server, $user = "anonymous", $password = "[email protected]") { $this->server = $server; $this->user = $user; $this->password = $password; $this->connection_id = ftp_connect($this->server); $this->connection_correct = ftp_login($this->connection_id, $this->user, $this->password); if ( (!$this->connection_id) || (!$this->connection_correct) ){ echo "Error! Couldn't connect to $this->server"; var_dump($this->connection_id); var_dump($this->connection_correct); return false; } else { echo "Successfully connected to $this->server, user: $this->user"; $this->connection_correct = true; return true; } } } I reckon that body of the class is insignificant at the moment. Main issue is that I have some problems with understanding OOP idea. I wanted to add sending emails every time, when the code is run. I have downloaded PHPMailer Class and extended my class with it: class ftpConnect extends PHPMailer {...} I have added some variables and methods and everything works as expected to that point. I thought: why not to add storing everything in database. Everytime user runs above code, proper information should be stored in database. I could edit my ftpConnect class and add database connecting to the constructor, and some other methods to updating tables. But database connecting and all that stuff could be used by other classes in the future, so it definitely should be implemented in seperate class. But my "main" ftpConnect class already extends one class and could not extend not a single one more. I have no idea how can I resolve this problem. Maybe my ftpConnect class is to complex and I should somehow divide it into couple smaller classes? Any help is much appreciated.

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  • Error during data UPDATE in php

    - by Piyush
    $sql = "UPDATE tblprofile SET name = '$membername' , f_h_name = '$fathername', maritalS = '$mstatus' , dob = '$dob' , occupation = '$occupation' , nominee = '$nominee' , address1 = '$address1' , address2 = '$address2', city = '$city', district = '$district', state = '$state', pin = '$areapin', mobile = '$mobileno', email = '$email', PANno = '$panno', bankname = '$bankname', branch = '$branch', accountno = '$accountno' WHERE userId = '$_SESSION['UserId']' "; //line 212 if(mysql_query($sql)) { echo "Updation Done."; } Error comes in browser : Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\xampp\htdocs\303\saveEditProfile.php on line 212

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  • Convert numbers to enumeration of strings in bash

    - by User1
    Using bash, I have a list of strings that I want to use to replace an int. Here's an example: day1=Monday day2=Tuesday day3=Wednesday day4=Thursday day5=Friday day6=Saturday day7=Sunday If I have an int, $dow, to represent the day of the week, how do I print the actual string? I tried this: echo ${day`echo $dow`} but get error of "bad substitution". How do I make this work? Note: I can change the $day variables to a list or something.

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  • Why save output until the end?

    - by user509006
    Very quick question about programming practices here: I've always used echo() to output HTML code to the user as soon as it was generated, and used ob_start() at the same time to be able to output headers later in the code. Recently, I was made aware that this is bad programming practice and I should be saving HTML output until the end. Is there a reason for this? What is it, and why isn't output buffering a good alternative? Thanks!

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  • How do I generate an Array string from an array in memory (php).

    - by Itay Moav
    I need to create a big array in my code, I have the values in several tables (for easy management). I select it and now I have all the values in an array, in memory in the way I want. My problem, I need to write this array down, into the code. Is there a way to take an array which sits in the memory and translate it into a string "array('g'='h','b'='d'....)" which I can then echo and just copy-paste into my code?

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  • how to disable on click event

    - by user1819709
    function insertQuestion(form) { var x = "<img src='Images/plussigndisabled.jpg' width='30' height='30' alt='Look Up Previous Question' class='plusimage' name='plusbuttonrow'/><span id='plussignmsg'>(Click Plus Sign to look <br/> up Previous Questions)</span>" ; if (qnum == <?php echo (int)$_SESSION['textQuestion']; ?>) { $('#mainPlusbutton').replaceWith(x); } //append rows into a table code, not needed for this question } .... $('.plusimage').live('click', function() { plusbutton($(this)); }); function plusbutton(plus_id) { // Set global info plusbutton_clicked = plus_id; // Display an external page using an iframe var src = "previousquestions.php"; $.modal('<iframe src="' + src + '" style="border:0;width:100%;height:100%;">'); return false; } <form id="QandA" action="<?php echo htmlentities($action); ?>" method="post"> <table id="question"> <tr> <td colspan="2"> <a onclick="return plusbutton();"> <img src="Images/plussign.jpg" width="30" height="30" alt="Look Up Previous Question" class="plusimage" id="mainPlusbutton" name="plusbuttonrow"/> </a> <span id="plussignmsg">(Click Plus Sign to look up Previous Questions)</span> </td> </tr> </table> <table id="questionBtn" align="center"> <tr> <th> <input id="addQuestionBtn" name="addQuestion" type="button" value="Add Question" onClick="insertQuestion(this.form)" /> </th> </tr> </table> </form> In the code above I am able to replace an image with another image when the if statement is met. But my problem is that when the image is replaced, it does not disable the on click event. My question is that when the image is replaced, how do I disable the onclick event onclick="return plusbutton();? Could unbind click work in this situation. I don't want to use href=# because I don't want to include # at the end of the url

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