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  • MySQL Queries using Doctrine & CodeIgniter

    - by 01010011
    Hi, How do I write plane SQL queries using Doctrine connection object and display the results? For example, how do I perform: SELECT * FROM table_name WHERE column_name LIKE '%anything_similar_to_this%'; using Doctrine something like this (this example does not work) $search_key = 'search_for_this'; $conn = Doctrine_Manager::connection(); $conn->execute('SELECT * FROM table_name WHERE column_name LIKE ?)', $search_key); echo $conn;

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  • mysql_fetch_array() expects parameter 1 to be resource problem

    - by user225269
    I don't get it, I see no mistakes in this code but there is this error, please help: mysql_fetch_array() expects parameter 1 to be resource problem <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO=".$_GET['id']); ?> <?php while ($row = mysql_fetch_array($result)) { ?> <table class="a" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="get" action="updateact.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Update Students</td> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $_GET['id']; ?>"></td> </tr> <tr> <td width="30" height="35"><font size="2">*Year:</td> <td width="30"><input name="yr" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $row["YEAR"]; ?>"></td> <?php } ?> I'm just trying to load the data in the forms but I don't know why that error appears. What could possibly be the mistake in here?

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  • display image and run script for fifteen seconds

    - by Ryan Max
    This is very similar to a question I asked the other day but my page code has become significantly more complicated and I need to revisit it. I've been using the following code: $('#myLink').click(function() { $('#myImg').attr('src', 'newImg.jpg'); setTimeout(function() { $('#myImg').attr('src', 'oldImg.jpg'); }, 15000); }); To replace an image for a set period of time (15 seconds) when the link is clicked, then after 15 seconds, revert to the original image. However now, I'd like to run a snippet of javascript as well when the link is clicked (in addition to replacing the image), and only when the link is clicked (it's related to the 15 second image) and then have the js code disappear as well after the 15 seconds...however I'm not sure how to have jquery send js code into the page...Basically I just want jQuery to "echo" this code onto the page underneath the 15 second while I am there, but I don't know how jquery formats this "echo". Does this question make sense? interval = 500; imgsrc = "webcam/image.jpg"; function Refresh() { tmp = new Date(); tmp = "?" + tmp.getTime(); document.images["image1"].src = imgsrc + tmp; setTimeout("Refresh()", interval); } Refresh(); It's script for a webcam. Basically it takes a new picture every half a second and replaces it on the page. You must forgive me, I'm new to jquery, I don't know how to make this script work in a jquery context. i'm sorry, I'm explaining badly. This is what I need to happen, step by step: 1) User comes to the page and there is a static image that says "Click here to view webcam" 2) User clicks image 3) Image is replaced by live webcam image, which is refreshed every .5 seconds by the second script in my question. 4) After 15 seconds the live webcam reverts back to the static image saying "click here to view webcam" It is ONLY during that 15 second interval that I wan the webcam refresh script running, otherwise it's wasting bandwidth on an element that isn't even shown. Sorry for the confusion.

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  • PHP using Declare ? What is a tick?

    - by ArneRie
    Iam a little bit confused by php function declare. What exactly is an single tick, i thought 1 tick = one line of code? But if i use: function myfunc() { print "Tick"; } register_tick_function("myfunc"); declare(ticks=1) { echo 'foo!bar'; } The script prints : "Tick" 2 Times??

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  • JavaScript: A BackSlash as part of the string

    - by Abs
    Hello all, I have a JavaScript variable that I echo out using PHP which is shown like this in the page source: var db_1 = 'C:\this\path'; When I set the value of a text field with that variable like so: $('#myinput').val(db_1); The slashes have disappeared and only the other characters are left! Why is this and how can I put the slashes back in?? Thanks all

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  • how to disable on click event

    - by user1819709
    function insertQuestion(form) { var x = "<img src='Images/plussigndisabled.jpg' width='30' height='30' alt='Look Up Previous Question' class='plusimage' name='plusbuttonrow'/><span id='plussignmsg'>(Click Plus Sign to look <br/> up Previous Questions)</span>" ; if (qnum == <?php echo (int)$_SESSION['textQuestion']; ?>) { $('#mainPlusbutton').replaceWith(x); } //append rows into a table code, not needed for this question } .... $('.plusimage').live('click', function() { plusbutton($(this)); }); function plusbutton(plus_id) { // Set global info plusbutton_clicked = plus_id; // Display an external page using an iframe var src = "previousquestions.php"; $.modal('<iframe src="' + src + '" style="border:0;width:100%;height:100%;">'); return false; } <form id="QandA" action="<?php echo htmlentities($action); ?>" method="post"> <table id="question"> <tr> <td colspan="2"> <a onclick="return plusbutton();"> <img src="Images/plussign.jpg" width="30" height="30" alt="Look Up Previous Question" class="plusimage" id="mainPlusbutton" name="plusbuttonrow"/> </a> <span id="plussignmsg">(Click Plus Sign to look up Previous Questions)</span> </td> </tr> </table> <table id="questionBtn" align="center"> <tr> <th> <input id="addQuestionBtn" name="addQuestion" type="button" value="Add Question" onClick="insertQuestion(this.form)" /> </th> </tr> </table> </form> In the code above I am able to replace an image with another image when the if statement is met. But my problem is that when the image is replaced, it does not disable the on click event. My question is that when the image is replaced, how do I disable the onclick event onclick="return plusbutton();? Could unbind click work in this situation. I don't want to use href=# because I don't want to include # at the end of the url

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  • PHP 5 functioning returning an array- interaction without assignment?

    - by Lee
    I'm wondering if this kind of thing will ever be possible in PHP (and whether it already is and I'm just missing something...) <?php function test() { return array( 'id'=>10, 'name'=>'John' ); } echo 'Your name is: '.test()['name']; ?> I'd really like to be able to use returned arrays directly instead of first assigning them to a var... possible?

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  • git repository sync between computers, when moving around?

    - by Johan
    Hi Let's say that I have a desktop pc and a laptop, and sometimes I work on the desktop and sometimes I work on the laptop. What is the easiest way to move a git repository back and forth? I want the git repositories to be identical, so that I can continue where I left of at the other computer. I would like to make sure that I have the same branches and tags on both of the computers. Thanks Johan Note: I know how to do this with SubVersion, but I'm curious on how this would work with git. If it is easier, I can use a third pc as classical server that the two pc:s can sync against. Note: Both computers are running Linux. Update: So let's try XANI:s idea with a bare git repo on a server, and the push command syntax from KingCrunch. In this example there is two clients and one server. So let's create the server part first. ssh user@server mkdir -p ~/git_test/workspace cd ~/git_test/workspace git --bare init So then from one of the other computers I try to get a copy of the repo with clone: git clone user@server:~/git_test/workspace/ Initialized empty Git repository in /home/user/git_test/repo1/workspace/.git/ warning: You appear to have cloned an empty repository. Then go into that repo and add a file: cd workspace/ echo "test1" > testfile1.txt git add testfile1.txt git commit testfile1.txt -m "Added file testfile1.txt" git push origin master Now the server is updated with testfile1.txt. Anyway, let's see if we can get this file from the other computer. mkdir -p ~/git_test/repo2 cd ~/git_test/repo2 git clone user@server:~/git_test/workspace/ cd workspace/ git pull And now we can see the testfile. At this point we can edit it with some more content and update the server again. echo "test2" >> testfile1.txt git add testfile1.txt git commit -m "Test2" git push origin master Then we go back to the first client and do a git pull to see the updated file. And now I can move back and forth between the two computers, and add a third if I like to.

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  • How to build array of 'bad' values

    - by JM4
    I am processing a form and in turn, receiving a response code based on the information submitted. I have a list of approximately 40 response codes (and their meaning) in my hands and am trying to build an 'if' statement that checks against a predefined array and returns a specific value. Just not sure how to do this First pass conceptually: $bads = array (1,2,3,4,5,6) if ($output['responsecode'] == (any value in $bads) { echo "you suck"; }

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  • Why Netbeans stop completing my php code?

    - by T1000
    It seems that Netbeans don't know about functions like mysql_query and complete only globals like $_SESSION or $_POST and stuff like echo and print (don't know about print_r)... Screenshot: http://img163.imageshack.us/img163/4290/clipboard03vr.png

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  • Zend Framework in a subfolder, but images taken from site root

    - by Pentium10
    I have a dev project setup in a subfolder on my testing machine and it must stay there. However all the Zend frameworks views are linked to server root. CSS are linked like: <link type="text/css" href="<?php echo $this->baseUrl('/css/frontend.css') ?>" rel="Stylesheet" /> Which must be stayed this way, but it should link to localhost/a/b/c/prj1/css/frontend.css How can I setup a global subdirectory for this?

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  • file content into unix variable with newlines

    - by Hugo
    I have a text file test.txt with the following content: text1 text2 And I want to assign the content of the file to a UNIX variable but when I do this: testvar=$(cat test.txt) echo $testvar the reult is: text1 text2 instead of text1 text2 Can someone suggest me a solution for this?

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  • What is the difference?

    - by Eragonio
    I try out CakePHP. I follow this Tutorial and can't find out why this code doesn't work. The code from the tutorial works fine. echo $html -> link('Löschen', array('action' => 'delete', 'id' => $post['Post']['id']), null, 'Sind Sie sicher?' );

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  • find: What's up with basename and dirname?

    - by temp2290
    I'm using find for a task and I noticed that when I do something like this: find `pwd` -name "file.ext" -exec echo $(dirname {}) \; it will give you dots only for each match. When you s/dirname/basename in that command you get the full pathnames. Am I screwing something up here or is this expected behavior? I'm used to basename giving you the name of the file (in this case "file.ext") and dirname giving you the rest of the path.

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  • Zend Framework: View variable in layout script is always null

    - by understack
    I set a view variable in someAction function like this: $this->view->type = "some type"; When I access this variable inside layout script like this: <?php echo $this->type ?> it prints nothing. What's wrong? My application.ini settings related to layout resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts/" resources.layout.layout = "layout" ; changed 'default' to 'layout'

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  • Using PHP5s SOAP Client to send data to an ASP/.NET based SOAP server.

    - by user325143
    I am trying to write a snippet of PHP to connect to a third party's API via SOAP to enter some data into their database. The API requires me to pass several mandatory fields for every call (username, password, companyid, entitytype) in addition to the mandatory data fields. It also requires me to call the "ValidateEntity" funciton before calling the "CreateEntity" function. Documentation can be found here: http://wiki.agemni.com/Getting_Started/APIs/Database_API I have never worked with SOAP before, so I am very new to this. Here is what I have so far: error_reporting(E_ALL); ini_set('display_errors', '1'); $client = new SoapClient("http://agemni.com/AgemniWebservices/service1.asmx?WSDL", array('trace'=> true)); $options = array( 'username' => "myuser", 'password' => "mypassword", 'companyid' => myID, 'entitytype' => 2 ); $params = array( 'fname' => "John", 'lname' => "Doe", 'phone' => "859-333-3333", 'zip' => "40332", 'area id' => "12345", 'lead id' => "28222", 'contactdate' => "4/10/2010" ); $validate = $client->__soapCall("ValidateEntity", array($params), array($options)); $client->__soapCall("CreateEntity", array($params), array($options)); echo "<pre>"; var_dump($client-> __getLastRequestHeaders()); var_dump($client-> __getLastRequest()); var_dump($client-> __getLastResponseHeaders()); var_dump($client-> __getLastResponse()); var_dump($result); echo "</pre>"; Upon executing this code, I get the following error: Fatal error: Uncaught SoapFault exception: [Client] SOAP-ERROR: Encoding: object hasn't 'objecttype' property in /www/tmp/index-soap.php:24 Stack trace: #0 /www/tmp/index-soap.php(24): SoapClient->__soapCall('ValidateEntity', Array) #1 {main} thrown in /www/stealth/tmp/index-soap.php on line 24 I guess my question is.. am I even going about doing this the right way? I know this is a very broad question, but I appreciate any advice you can give me about making this work. Please let me know if you require more detail. Thanks!

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  • How to transfer json data to html with php?

    - by cj333
    How to transfer json data to html with php? $url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey" when I type the url in browser, it return {"offset" : "0" , "results" : [{"body" : "A guide to cultural and recreational goings-on in and around the Hudson Valley. ...}]} how to put the json body data into html? I mean like this echo '<div class="body"></div>';

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  • What is wrong with this PHP function.

    - by [email protected]
    I am new to PHP and regular expression. I was going thorugh some online examples and came with this example: <?php echo preg_replace_callback('~-([a-z])~', function ($match) { return strtoupper($match[1]); }, 'hello-world'); // outputs helloWorld ?> in php.net but to my surprise it does not work and keep getting error: PHP Parse error: parse error, unexpected T_FUNCTION Why get error ?

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