Consider the following example:
#include <iostream>
#include <sstream>
#include <vector>
#include <wchar.h>
#include <stdlib.h>
using namespace std;
struct odp {
int f;
wchar_t* pstr;
};
int main()
{
vector<odp> vec;
ostringstream ss;
wchar_t base[5];
wcscpy_s(base, L"1234");
for (int i = 0; i < 4; i++)
{
odp foo;
foo.f = i;
wchar_t loopStr[1];
foo.pstr = loopStr; // wchar_t* = wchar_t ? Why does this work?
foo.pstr[0] = base[i];
vec.push_back(foo);
}
for (vector<odp>::iterator iter = vec.begin(); iter != vec.end(); iter++)
{
cout << "Vec contains: " << iter->f << ", " << *(iter->pstr) << endl;
}
}
This produces:
Vec contains: 0, 52
Vec contains: 1, 52
Vec contains: 2, 52
Vec contains: 3, 52
I would hope that each time, iter->f and iter->pstr would yield a different result. Unfortunately, iter->pstr is always the same.
My suspicion is that each time through the loop, a new loopStr is created. Instead of copying it into the struct, I'm only copying a pointer. The location that the pointer writes to is getting overwritten.
How can I avoid this? Is it possible to solve this problem without allocating memory on the heap?
