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  • not able to Deserialize object

    - by Ravisha
    I am having following peice of code ,where in i am trying to serialize and deserailize object of StringResource class. Please note Resource1.stringXml = its coming from resource file.If i pass strelemet.outerXMl i get the object from Deserialize object ,but if i pass Resource1.stringXml i am getting following exception {"< STRING xmlns='' was not expected."} System.Exception {System.InvalidOperationException} class Program { static void Main(string[] args) { StringResource str = new StringResource(); str.DELETE = "CanDelete"; str.ID= "23342"; XmlElement strelemet = SerializeObjectToXmlNode (str); StringResource strResourceObject = DeSerializeXmlNodeToObject<StringResource>(Resource1.stringXml); Console.ReadLine(); } public static T DeSerializeXmlNodeToObject<T>(string objectNodeOuterXml) { try { TextReader objStringsTextReader = new StringReader(objectNodeOuterXml); XmlSerializer stringResourceSerializer = new XmlSerializer(typeof(T),string.Empty); return (T)stringResourceSerializer.Deserialize(objStringsTextReader); } catch (Exception excep) { return default(T); } } public static XmlElement SerializeObjectToXmlNode(object obj) { using (MemoryStream memoryStream = new MemoryStream()) { try { XmlSerializerNamespaces xmlNameSpace = new XmlSerializerNamespaces(); xmlNameSpace.Add(string.Empty, string.Empty); XmlWriterSettings writerSettings = new XmlWriterSettings(); writerSettings.CloseOutput = false; writerSettings.Encoding = System.Text.Encoding.UTF8; writerSettings.Indent = false; writerSettings.OmitXmlDeclaration = true; XmlWriter writer = XmlWriter.Create(memoryStream, writerSettings); XmlSerializer xmlserializer = new XmlSerializer(obj.GetType()); xmlserializer.Serialize(writer, obj, xmlNameSpace); writer.Close(); memoryStream.Position = 0; XmlDocument serializeObjectDoc = new XmlDocument(); serializeObjectDoc.Load(memoryStream); return serializeObjectDoc.DocumentElement; } catch (Exception excep) { return null; } } } } public class StringResource { [XmlAttribute] public string DELETE; [XmlAttribute] public string ID; }

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  • Is there a clean way to determine RSS version?

    - by Fenick
    Is it possible to determine the feed type and version in a way so that you can make sure that you have the correct version. At the lowest level so to speak. Namespaces is an obvious approach, but its not present for a lot of feeds. Any thoughts? (I'm trying to mashup varioius RSS Feeds). Thanks in advance for any help!

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  • How to add line breaks in RSS feeds?

    - by Candidasa
    I'm building my own custom RSS feed in PHP. I want the tag to contain line breaks to make the text more readable. However, I can't seem to figure out how to do it correctly. No matter what I try some RSS reader interprets it incorrectly. Is there some standard best way to add a line-break in and RSS 2.0 feed? I have tried "\n", which works in NetNewsWire on the Mac, but gets ignored by the built-in Safari browser's RSS reader. I have tried <br />, which works in the Safari RSS reader, but results in all the text after the being cut off in NetNewsWire.

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  • How to get a html elements with python lxml

    - by Damiano
    Hello! I have this html code: <table> <tr> <td class="test"><b><a href="">aaa</a></b></td> <td class="test">bbb</td> <td class="test">ccc</td> <td class="test"><small>ddd</small></td> </tr> <tr> <td class="test"><b><a href="">eee</a></b></td> <td class="test">fff</td> <td class="test">ggg</td> <td class="test"><small>hhh</small></td> </tr> </table> I use this Python code to extract all <td class="test"> with lxml module. import urllib2 import lxml.html code = urllib.urlopen("http://www.example.com/page.html").read() html = lxml.html.fromstring(code) result = html.xpath('//td[@class="test"][position() = 1 or position() = 4]') It works good! The result is: <td class="test"><b><a href="">aaa</a></b></td> <td class="test"><small>ddd</small></td> <td class="test"><b><a href="">eee</a></b></td> <td class="test"><small>hhh</small></td> (so the first and the fourth column of each <tr>) Now, I have to extract: aaa (the title of the link) ddd (text between <small> tag) eee (the title of the link) hhh (text between <small> tag) How could I extract these values? (the problem is that I have to remove <b> tag and get the title of the anchor on the first column and remove <small> tag on the forth column) Thank you!

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  • Why doesn't XmlSerializer support Dictionary?

    - by theburningmonk
    Just curious as to why Dictionary is not supported by XmlSerializer? You can get around it easily enough by using DataContractSerializer and writing the object to a XmlTextWriter, but what are the characteristics of a Dictionary that makes it difficult for a XmlSerializer to deal with considering it's really an array of KeyValuePairs. In fact, you can pass an IDictionary<TKey, TItem> to a method expecting an IEnumerable<KeyValuePairs<TKey, ITem>>.

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  • How to register XHTML namespaces??

    - by John Tyler
    My page use to validate for XHTML but I added the addthis buttons to page and it gives a new namespace: E.G.: <a addthis:url="http://domain.tld/path/to/stuff" addthis:title="Teh Title here"> I tried: <html xmlns="http://www.w3.org/1999/xhtml" xmlns:addthis="http://addthis.com/" lang="en"> Doesn't work. Can we register namespaces for the validator??? I AM EMOTIONALLY ATTACHED TO VALID XHTML. I like addthis, I think its the best button of its kind (yes, I need to use the namespace properties, I know you dont have to but I do for what im doing PHP project) :(

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  • Implicitly including optional dependencies in Maven

    - by Jon Todd
    I have a project A which has a dependency X. Dependency X has an optional dependency Y which doens't get included in A by default. Is there a way to include Y in my POM without explicitly including it? In Ivy they have a way to essentailly say include all optional dependencies of X, does Maven have a way to do this?

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  • c# - How do you get a variable's name as it was physically typed in its declaration?

    - by Petras
    The class below contains the field city. I need to dynamically determine the field's name as it is typed in the class declaration i.e. I need to get the string "city" from an instance of the object city. I have tried to do this by examining its Type in DoSomething() but can't find it when examining the contents of the Type in the debugger. Is it possible? public class Person { public string city = "New York"; public Person() { } public void DoSomething() { Type t = city.GetType(); string field_name = t.SomeUnkownFunction(); //would return the string "city" if it existed! } } Some people in their answers below have asked me why I want to do this. Here's why. In my real world situation, there is a custom attribute above city. [MyCustomAttribute("param1", "param2", etc)] public string city = "New York"; I need this attribute in other code. To get the attribute, I use reflection. And in the reflection code I need to type the string "city" MyCustomAttribute attr; Type t = typeof(Person); foreach (FieldInfo field in t.GetFields()) { if (field.Name == "city") { //do stuff when we find the field that has the attribute we need } } Now this isn't type safe. If I changed the variable "city" to "workCity" in my field declaration in Person this line would fail unless I knew to update the string if (field.Name == "workCity") //I have to make this change in another file for this to still work, yuk! { } So I am trying to find some way to pass the string to this code without physically typing it. Yes, I could declare it as a string constant in Person (or something like that) but that would still be typing it twice. Phew! That was tough to explain!! Thanks Thanks to all who answered this * a lot*. It sent me on a new path to better understand lambda expressions. And it created a new question.

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  • Processing RSS/RDF via xml.dom.minidom

    - by Bill
    I'm trying to process a delicious rss feed via python. Here's a sample: ... <item rdf:about="http://weblist.me/"> <title>WebList - The Place To Find The Best List On The Web</title> <dc:date>2009-12-24T17:46:14Z</dc:date> <link>http://weblist.me/</link> ... </item> <item rdf:about="http://thumboo.com/"> <title>Thumboo! Free Website Thumbnails and PHP Script to Generate Web Screenshots</title> <dc:date>2006-10-24T18:11:32Z</dc:date> <link>http://thumboo.com/</link> ... The relevant code is: def getText(nodelist): rc = "" for node in nodelist: if node.nodeType == node.TEXT_NODE: rc = rc + node.data return rc dom = xml.dom.minidom.parse(file) items = dom.getElementsByTagName("item") for i in items: title = i.getElementsByTagName("title") print getText(title) I would think this would print out each title, but instead I get basically get blank output. I'm sure I'm doing something stupid wrong, but no idea what?

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  • How to get parameter values from an XmlNode in C#

    - by Brian
    How do I get the values for parameters in a XmlNode tag. For example: <weather time-layout="k-p24h-n7-1"> <name>Weather Type, Coverage, and Intensity</name> <weather-conditions weather-summary="Mostly Sunny"/> </weather> I want to get the value for the parameter 'weather-summary' in the node 'weather-conditions'.

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  • button in XSL for AJAX usage

    - by phingko
    Hi guys, I wonder if its is possible to do AJAX when I put a button inside the xsl file; <input type = "button" id="laptop" value = "Add to Cart" onclick="sendCartRequest('Add');" /> That's what I do in my xsl file then in my js file I pass the id to the DOM and try to alert it make sure it is passed. And the alert appear to be empty. Is it a mistake to put the button in the xsl? or that's something else that cause it's empty? May be my DOMpath? Please point me a right direction. Thanks in advanced.

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  • Null Exception RelativeLayout

    - by theblixguy
    I am trying to remove objects from my relative layout and replace the background with another image but I get a java.lang.NullPointerException on this line: RelativeLayout ths = (RelativeLayout)findViewById(R.layout.activity_main); Below is my code: package com.ssrij.qrmag; import android.app.Activity; import android.content.Intent; import android.net.Uri; import android.os.Bundle; import android.view.View; import android.view.animation.Animation; import android.view.animation.TranslateAnimation; import android.view.animation.Animation.AnimationListener; import android.widget.Button; import android.widget.RelativeLayout; import android.widget.TextView; public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); // Initialize animations Animation a = new TranslateAnimation(1000,0,0,0); Animation a1 = new TranslateAnimation(1000,0,0,0); Animation a2 = new TranslateAnimation(1000,0,0,0); Animation a3 = new TranslateAnimation(1000,0,0,0); // Set animation durations (ms) a.setDuration(1200); a1.setDuration(1400); a2.setDuration(1600); a3.setDuration(1800); // Get a reference to the objects we want to apply the animation to final TextView v = (TextView)findViewById(R.id.textView1); final TextView v1 = (TextView)findViewById(R.id.textView2); final TextView v2 = (TextView)findViewById(R.id.TextView3); final Button v3 = (Button)findViewById(R.id.tap_scan); // Clear existing animations, just in case... v.clearAnimation(); v1.clearAnimation(); v2.clearAnimation(); v3.clearAnimation(); // Start animating v.startAnimation(a); v1.startAnimation(a1); v2.startAnimation(a2); v3.startAnimation(a3); a1.setAnimationListener(new AnimationListener() { @Override public void onAnimationStart(Animation animation) { // TODO Auto-generated method stub } @Override public void onAnimationRepeat(Animation animation) { // TODO Auto-generated method stub } @Override public void onAnimationEnd(Animation animation) { v.setVisibility(View.INVISIBLE); v1.setVisibility(View.INVISIBLE); v2.setVisibility(View.INVISIBLE); v3.setVisibility(View.INVISIBLE); RelativeLayout ths = (RelativeLayout)findViewById(R.layout.activity_main); ths.setBackgroundResource(R.drawable.blurbg); } }); } public void ScanQr(View v) { // Open the QR Scan page Intent a = new Intent(MainActivity.this, ScanActivity.class); startActivity(a); } } Is there anything that I am doing wrong?

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  • How to draw some lines in a view element defined in the xml layout

    - by Nils
    Hello, I have problems drawing some simple lines in a view object (Android programming). First I created the layout with the view element(kind of painting area) in it (XML file). [...] < View android:id="@+id/viewmap" android:layout_width="572px" android:layout_height="359px" android:layout_x="26px" android:layout_y="27px" [...] ... and tried then to access it to draw some lines. Unfortunately the program is running and other UI elements like buttons are displayed, but I can't see the drawings. What's wrong ? [...] viewmap = (View) findViewById(R.id.viewmap); Canvas canvas = new Canvas(); viewmap.draw(canvas); Paint p = new Paint(); p.setColor(Color.BLUE); p.setStyle(Paint.Style.STROKE); canvas.drawColor(Color.WHITE); p.setColor(Color.BLUE); canvas.drawLine(4, 4, 29, 5, p); p.setColor(Color.RED); viewmap.draw(canvas); [...] Thanks for help :) !

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  • Xpath how to select an element based on an order and dependent of its existence

    - by hokkos
    Hi, how to select an element based on an order and dependent of its existence in XPath ? For example how to select the best quality video if it exist. <VIDEOS> <LOW_RES>video_L.flv</LOW_RES> <HI_RES>video_H.flv</HI_RES> <HD/> </VIDEOS> this should return video_H.flv because the hd version doesn't exist this case can exist (the videos names can be random): <VIDEOS> <LOW_RES>video_L.flv</LOW_RES> <HI_RES>video_H.flv</HI_RES> <HD>video_hd.mp4</HD> </VIDEOS> this should return video_hd.mp4 because the hd version exist. Many thanks.

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  • Confused as to use a class or a function: Writing XML files using lxml and Python

    - by PulpFiction
    Hi. I need to write XML files using lxml and Python. However, I can't figure out whether to use a class to do this or a function. The point being, this is the first time I am developing a proper software and deciding where and why to use a class still seems mysterious. I will illustrate my point. For example, consider the following function based code I wrote for adding a subelement to a etree root. from lxml import etree root = etree.Element('document') def createSubElement(text, tagText = ""): etree.SubElement(root, text) # How do I do this: element.text = tagText createSubElement('firstChild') createSubElement('SecondChild') As expected, the output of this is: <document> <firstChild/> <SecondChild/> </document> However as you can notice the comment, I have no idea how to do set the text variable using this approach. Is using a class the only way to solve this? And if yes, can you give me some pointers on how to achieve this?

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  • Java Node.cloneNode()

    - by Tom Brito
    Talking about the org.w3c.dom package; When I call Node.cloneNode() method from a Element(extends Node) object, which Document is used to create the new cloned Element? Example: import org.w3c.dom; class MyClass { public static void main(String[] args) throws Exception { DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document doc = builder.newDocument(); Element element = doc.createElement("myElement"); Element cloneElement = (Element) element.cloneNode(true); } } Which Document was used to create cloneElement?

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  • How to switch a view after i parse data?

    - by charles Graffeo
    OK my problem is this, i parse a document and after the document is parsed then i want to load to the next view sounds simple but ive been here for like 4 hours playing with code and id appreciete any help u can give me atm. k heres my parserDidEndDocumentCode - (void)parserDidEndDocument:(NSXMLParser *)parser{ IpadSlideShowViewController temp=(IpadSlideShowViewController)[[IpadSlideShowViewController alloc]init]; [temp performSelectorOnMainThread:@selector(switchViews) withObject:nil waitUntilDone:TRUE]; [temp release]; } now what i think should happen is my code will switch the view after it parses the documentation, n its not doing it idk why

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  • How to get node without children in xQuery?

    - by mbrevoort
    So I have two nodes of elements that I'm essentially trying to join. I want the top level node to stay the same but the child nodes to be replaced by those cross referenced. Given: <stuff> <item foo="foo" boo="1"/> <item foo="bar" boo="2" /> <item foo="baz" boo="3"/> <item foo="blah boo="4""/> </stuff> <list a="1" b="2"> <foo>bar</foo> <foo>baz</foo> </list> I want to loop through "list" and cross reference elements in "stuff" for this result: <list a="1" b="2"> <item foo="bar" boo="2" /> <item foo="baz" boo="3"/> </list> I want to do this without having to know about what attributes might be on "list". In other words I don't want to have to explicitly call them out like attribute a { $list/@a }, attribute b { $list/@b }

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  • Sorting based on existing elements in xslt

    - by Teelo
    Hi , I want to sort in xslt based on existing set of pattern . Let me explain with the code: <Types> <Type> <Names> <Name>Ryan</Name> </Names> <Address>2344</Address> </Type> <Type> <Names> </Name>Timber</Name> </Names> <Address>1234</Address> </Type> <Type> <Names> </Name>Bryan</Name> </Names> <Address>34</Address> </Type> </Types> Right now I m just calling it and getting it like (all hyperlinks) Ryan Timber Bryan Now I don't want sorting on name but I have existing pattern how I want it to get displayed.Like Timber Bryan Ryan (Also I don't want to lose the url attached to my names earlier while doing this) I was thinking of putting earlier value in some array and sort based on the other array where I will store my existing pattern. But I am not sure how to achieve that.. My xslt looks like this now(there can be duplicate names also) <xsl:for-each select="/Types/Type/Names/Name/text()[generate-id()=generate-id(key('Name',.)[1])]"> <xsl:call-template name="typename"> </xsl:call-template> </xsl:for-each> <xsl:template name="typename"> <li> <a href="somelogicforurl"> <xsl:value-of select="."/> </a> </li> </xsl:template> I am using xsl 1.0

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