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  • Distinct rand() sequences yielding the same results in an expression

    - by suszterpatt
    Ok, this is a really weird one. I have an MPI program, where each process has to generate random numbers in a fixed range (the range is read from file). What happens is that even though I seed each process with a different value, and the numbers generated by rand() are different in each process, the expression to generate the random numbers still yields the same sequence between them. Here's all relevant code: // 'rank' will be unique for each process int rank; MPI_Comm_rank(MPI_COMM_WORLD, &rank); // seed the RNG with a different value for each process srand(time(NULL) + rank); // print some random numbers to see if we get a unique sequence in each process // 'log' is a uniquely named file, each process has its own log << rand() << " " << rand() << " " << rand() << std::endl; // do boring deterministic stuff while (true) { // waitTimeMin and waitTimeMax are integers, Max is always greater than Min waitSecs = waitTimeMin + rand() % (waitTimeMax - waitTimeMin); log << "waiting " << waitSecs << " seconds" << std::endl; sleep(waitSecs); // do more boring deterministic stuff } Here's the output of each process, with 3 processes generating numbers in the range [1,9]. process 1: 15190 28284 3149 waiting 6 seconds waiting 8 seconds waiting 9 seconds waiting 4 seconds process 2: 286 6264 3153 waiting 6 seconds waiting 8 seconds waiting 9 seconds waiting 4 seconds process 3: 18151 17013 3156 waiting 6 seconds waiting 8 seconds waiting 9 seconds waiting 4 seconds So while rand() clearly generates different numbers, the expression to calculate waitSecs still evaluates to the same sequence on all processes. What's even weirder: if I run the program with the same parameteres again, only the first 3 random numbers will change, the rest of the "random" sequence will be exactly the same in each run! Changing the range of numbers will obviously produce a different result from this one, but the same parameters always yield the same sequence, between processes and between executions: except for the first 3 numbers. Just what the hell is going on here?

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  • [MySQL/PHP] Avoid using RAND()

    - by Andrew Ellis
    So... I have never had a need to do a random SELECT on a MySQL DB until this project I'm working on. After researching it seems the general populous says that using RAND() is a bad idea. I found an article that explains how to do another type of random select. Basically, if I want to select 5 random elements, I should do the following (I'm using the Kohana framework here)? If not, what is a better solution? Thanks, Andrew <?php final class Offers extends Model { /** * Loads a random set of offers. * * @param integer $limit * @return array */ public function random_offers($limit = 5) { // Find the highest offer_id $sql = ' SELECT MAX(offer_id) AS max_offer_id FROM offers '; $max_offer_id = DB::query(Database::SELECT, $sql) ->execute($this->_db) ->get('max_offer_id'); // Check to make sure we're not trying to load more offers // than there really is... if ($max_offer_id < $limit) { $limit = $max_offer_id; } $used = array(); $ids = ''; for ($i = 0; $i < $limit; ) { $rand = mt_rand(1, $max_offer_id); if (!isset($used[$rand])) { // Flag the ID as used $used[$rand] = TRUE; // Set the ID if ($i > 0) $ids .= ','; $ids .= $rand; ++$i; } } $sql = ' SELECT offer_id, offer_name FROM offers WHERE offer_id IN(:ids) '; $offers = DB::query(Database::SELECT, $sql) ->param(':ids', $ids) ->as_object(); ->execute($this->_db); return $offers; } }

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  • Oracle's Australian Graduate Recruitment Program

    - by david.talamelli
    I have been with Oracle for 5 years now and one thing that I have found that there is never a shortage of here is - Variety. Over the last 5 years I have had the opportunity to work on projects across various countries, across various technologies and skill-sets and also across various level of seniority. No two days are the same. One of the projects I was fortunate to be involved in occurred last year and it is one of the ones that is closest to me. Last year I was able to take responsibility for our 2011 Graduate Recruitment drive in Australia. Two weeks ago I went to Sydney to meet our Graduates who started in February 2011 with us and it was great to see them come to the end (or beginning actually) of our journey together. I am excited at the potential of what our Graduates careers will develop into here with us. I remember at our interviewing last year trying to explain life in Oracle, it is great to see those same Graduates with us now learning and developing life and business skills that I hope they will take with them in their professional careers. I was talking to one of my colleagues this week who mentioned the excitement and energy that our new Graduates bring is infectious, and I agree it really is. Our Graduates have a big learning curve ahead of them and they are about to start going on rotations into some of our Business Groups - but I think it is a great experience to see how a global company operates and pulls together to achieve results together. Here is a picture we took the other week of this year's Oracle Graduates (if any of our Graduates are reading this blog - it was great seeing you in NSW and I do wish you all the success here at Oracle) Once again Oracle's Graduate Program will be running in 2011 in Australia (Graduates will start in Jan/Feb 2012). The Oracle Australia Graduate Development Program is a one-year program consisting of orientation, formal training, project rotations in one core line of business and finally job placement. The formal training is a combination of structured development programs on soft skills and functional competencies via various delivery formats. Graduates are also expected to work in a team environment and complete multiple projects addressing real business challenges and at the time gaining a broad business understanding. For our Australia program we are hiring in our North Ryde and Melbourne offices. Resume submissions are being accepted now. First Round interviews will take place in June 2011 with Final Round interviews in July 2011. The Australia Graduate Program is open to Australian Residents and Citizens who are either in the final year of their studies or have graduated the previous year. For more details on Oracle and our Graduate Program visit our Campus website To express your interest, mail your resume to [email protected]

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  • Interviews Gone Bad.....Now What Do I Do?

    - by david.talamelli
    We have all done it at some stage of our working careers - you know those times when you leave an interview and then you think to yourself "why didn't I ask that question" or "I can't believe I said that" or "how could I have forgotten to say that". It happens to everyone but how you handle things moving forwards could be critical in helping you land that dream job. There is nothing better than seeing that dream job with the dream company that you are looking to work for advertised (or in some cases getting called by the Recruiter to let you know about that job). The role may seem perfect and it could be just what you are looking for and it is with the right company as well. You have sent in your resume and have subsequently had one, two or maybe three interviews for the role. After each step of the process you get a little bit more excited about the role as you start to think about your work day in your new role/company. Then it happens, you get it: you get The Phone Call to inform you that you have not been successful in securing the position that you have invested so much time and effort into. It can be disappointing to hear this news but what you do next is important in potentially keeping that door open for future opportunities with that company. How you handle yourself in this situation is important: if any of you remember the Choose Your Own Adventure Books do you: Tell the Recruiter (maybe get aggressive) they are wrong in their assessment and that you are the right candidate for the role Switch off and say ok thanks and hang up without engaging in any further dialogue Thank the company for their time and enquire if there may be any other opportunities in the future to explore If you chose the first option - the company in question may consider whether or not to look at you for other opportunities. How you handle yourself in the recruitment process could be an indication of how you would deal with clients/colleagues in your role and the impression that you leave a potential employer may be what sticks in their mind when they think of you (eg: isn't that the person who couldn't handle it when we told him he wasn't right for our role). The second option potentially produces a similar outcome. If you rush to get off the phone, the company may come back to you to talk about other roles when they come up, but you also leave open the potential thought with the company you were only interested in that role and therefore not interested in any other opportunities. Why take the risk of the company thinking that and potentially not getting back to you in the future. By picking the third option, you actively engage with the company and keep the dialogue open for future discussions. Ok, so you didn't get the role you interviewed for - you don't know who else the company may have been interviewing - maybe they found someone who was a better fit, or maybe there were too many boxes you didn't tick to step straight into that specific role. Take a deep breath and keep the company engaged. You are fresh in their mind - take advantage of that fact and let them know that while you respect their decision, that you are still interested in the company and would like to be kept in mind for future roles. Ask if it is ok to keep in touch and when they would like to keep in touch, as long as you are interested let them know you are still interested. You do need to balance that though if you come across as too keen or start stalking people - it could equally damage your brand. Companies normally have more than one open role. New roles are created all the time, circumstances change and hiring people is not a static business, it changes course from everyone's best laid initial plans. If you didn't get that initial role you wanted, keep the door open with that company so that when those new roles do come up or when circumstances do change you have already laid the ground to step into those new positions.

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  • Your Job Search Should be More Than Just a New Year's Resolution

    - by david.talamelli
    I love the beginning of a new year, it is a great chance to refocus and either re-evaluate goals you are working to or even set new ones. I don't have any statistics to measure this but I am sure that one of the more popular new year's resolutions in the general workforce is to either get a new job or work to further develop one's career. I think this is a good idea, in today's competitive work force people should have a plan of what they want to do, what role they are after and how to get there. One common mistake I think many people make though is that a career plan shouldn't be a once a year thought. When people finish with the holiday season with their new year's resolution to find a new job fresh in their mind, you can see the enthusiasm and motivation a person has to make something happen. Emails are sent, calls are made, applications are made, networking is happening, etc..... Finding the right role that you are after however can be difficult, while it would be great if that dream role was available just at the time you happened to be looking for it - in reality this is not always the case. Job Seekers need to keep reminding themselves that while sometimes that dream job they are after is available at the same time they are looking, that also a Job search can be a difficult and long process. Many people who set out with the best of intentions in January to find a new job can soon lose interest in a job search if they do not immediately find a role. Just like the Christmas decorations are put away and the photos from New Year's are stored away - a Job Seeker's motivation may slowly decrease until that person finds themselves 12 months later in the same situation in same role and looking for that new opportunity again. Rather than just "going for it" and looking for a role in the month of January, a person's job search or career plan should be an ongoing activity and thought process that is constantly updated and evaluated over the course of the year. It can be hard to stay motivated over an extended period of time, especially when you are newly motivated and ready for that new role and the results are not immediate. Rather than letting your job search fall down the priority list and into the "too hard basket" a few ideas that may keep your enthusiasm fresh Update your resume every 6 months, even if you are not looking for a job - it is easy to forget what you have accomplished if you don't keep your details updated. Also it is good to be prepared and have a resume ready to go in case you do get an unexpected phone call for that 'dream job' you have been hoping for. Work out what you want out of your next role before you begin your job search - rather than aimlessly searching job ads or talking to people - think of the organisations or type of role you would like before you search. If you know what you are looking for it will be much easier to work out how to get there than if you do not know what you want. Don't expect immediate results once you decide to look for another job, things don't always fall into place. Timing and delivery can be important pieces of being selected for a role, companies don't hire every role in January. Have an open mind - people you meet or talk to may not result in immediate results for your job search but every connection may help you get a bit closer to what you are after . These actions will not guarantee a positive result, but in today's competitive work force every little of extra preparation and planning helps. All the best for 2011 and I hope your career plan whatever it may be is a success.

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  • Fill a table from a RAND based formula in Excel 2010

    - by Greg Reynolds
    I am trying to do a Monte Carlo simulation using Excel, but a lot of the tutorials I have found are either for older versions of the product, or are not quite what I am after. A simple example of the kind of think I am after is: Cell A1 contains the formula to simulate (for example int(6*rand())+1 to simulate rolling a dice). I have 10 rows of "Trials". What I want is to somehow point each row at a different calculation of the formula in A1. So I would end up with something like Trial Value 1 2 2 5 3 6 4 2 5 1 6 3 7 2 8 4 9 2 10 1 I have tried playing with some of the "What-if Analysis" tools, but I am a bit lost.

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  • Example about crypto/rand in Go

    - by nevalu
    Could put a little example about the use of crypto/rand [1]? The function Read has as parameter an array of bytes. Why? If it access to /dev/urandom to get the random data. func Read(b []byte) (n int, err os.Error) [1] http://golang.org/pkg/crypto/rand/

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  • is rand() is perdicatable in C++

    - by singh
    Hi When i run below program i always get same values each time..Is rand is not a true random function. int main() { while(1) { getch(); cout<<rand()<<endl; } } In each run i am getting below values. 41 18467 6334 26500 19169 15724 ......

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  • Is rand() predictable in C++

    - by singh
    When I run the below program I always get the same values each time. Is rand not a true random function? int main() { while(1) { getch(); cout<<rand()<<endl; } } In each run I am getting the below values. 41 18467 6334 26500 19169 15724 ......

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  • MySQL ORDER BY rand(), name ASC

    - by Josh K
    I would like to take a database of say, 1000 users and select 20 random ones (ORDER BY rand(),LIMIT 20) then order the resulting set by the names. I came up with the following query which is not working like I hoped. SELECT * FROM users WHERE 1 ORDER BY rand(), name ASC LIMIT 20

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  • Plotting points so that they do not overlap if they have the same co-ordinates

    - by betamax
    Hi everyone, I have a function that takes longitude and latitude and converts it to x and y to be plotted. The conversion to X and Y is working fine and that is not what I have the problem with. I want to ensure that two points are not plotted in the same place. In one set of results there are about 30 on top of each other (because they have the same latitude and longitude), this number could be a lot larger. At the moment I am trying to achieve this by moving points to the left, right, top or bottom of the point to make a square. Once a square made up of points has been drawn, then moving to the next row on and drawing another square of points around the previous square. The code is Javascript but it is very generic so I guess it's slightly irrelevant. My code is as follows: var prevLong, prevLat, rand = 1, line = 1, spread = 8, i = 0; function plot_points(long, lat){ // CODE HERE TO CONVERT long and lat into x and y // System to not overlap the points if((prevLat == lat) && (prevLong == long)) { if(rand==1) { x += spread*line; } else if(rand==2) { x -= spread*line; } else if(rand==3) { y += spread*line; } else if(rand==4) { y -= spread*line; } else if(rand==5) { x += spread*line; y += spread*line; } else if(rand==6) { x -= spread*line; y -= spread*line; } else if(rand==7) { x += spread*line; y -= spread*line; } else if(rand==8) { x -= spread*line; y += spread*line; // x = double } else if(rand==9) { x += spread*line; y += spread; } else if(rand==10) { x += spread; y += spread*line; } else if(rand==11) { x -= spread*line; y -= spread; } else if(rand==12) { x -= spread; y -= spread*line; } else if(rand==13) { x += spread*line; y -= spread; } else if(rand==14) { x += spread; y -= spread*line; } else if(rand==15) { x += spread*line; y -= spread; } else if(rand==16) { x += spread; y -= spread*line; } else if(rand==17) { x -= spread*line; y += spread; } else if(rand==18) { x -= spread; y += spread*line; } else if(rand==19) { x -= spread*line; y += spread; } else if(rand==20) { x -= spread; y += spread*line; } if(rand == 20) {rand = 1; line++; } else { rand++; } i++ } else { line = 1; i = 0; } prevLat = latitude; prevLong = longitude; return [x,y]; } This is the output: It isn't working correctly and I don't even know if I am approaching the problem in a correct way at all. Has anyone had to do this before? What method would you suggest?

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  • The 2010 JavaOne Java EE 6 Panel: Where We Are and Where We're Going

    - by janice.heiss(at)oracle.com
    An informative article, based on a 2010 JavaOne (San Francisco, California) panel session, surveys a variety of expert perspectives on Java EE 6.The panel, moderated by Oracle's Alexis Moussine-Pouchkine, consisted of:* Adam Bien, Consultant Author/ Speaker, adam-bien.com* Emmanuel Bernard, Principal Software Engineer, JBoss by Red Hat,* David Blevins, Senior Software Engineer, and co-founder of the OpenEJB project and a     founder of Apache Geronimo* Roberto Chinnici, Technical Staff Consulting Member, Oracle* Jim Knutson, Java EE Architect, IBM* Reza Rahman, Lead Engineer, Caucho Technology, Inc.,* Krasimir Semerdzhiev, Development Architect, SAP Labs BulgariaThe panel addressed such topics as Platform and API Adoption, Contexts and Dependency Injection (CDI), Java EE vs. Spring, the impact of Java EE 6 on tooling and testing, Java EE.next, along with a variety of audience questions. Read the entire article for the whole picture.

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  • migrate method Rand(int) Visual Fox Pro to C#.net

    - by ch2o
    I'm migrating a Visual Fox Pro code to C #. NET What makes the Visual Fox Pro: generates a string of 5 digits ("48963") based on a text string (captured in a textbox), if you always enter the same text string will get that string always 5 digits (no reverse), my code in C #. NET should generate the same string. I want to migrate the following code (Visual Fox Pro 6 to C#) gnLower = 1000 gnUpper = 100000 vcad = 1 For y=gnLower to gnUpper step 52 genClave = **Rand(vcad)** * y vRound = allt(str(int(genclave))) IF Len(vRound) = 3 vDec = Right(allt(str(genClave,10,2)), 2) finClave = vRound+vDec Thisform.txtPass.value = Rand(971); Exit Endif Next y outputs: vcad = 1 return: 99905 vcad = 2 return: 10077 vcad = thanks return: 17200 thks!

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  • Order By Rand by Time (HQL)

    - by Felipe
    Hi all, I'm developing a web application using asp.net Mvc 2 and NHibernate, and I'm paging data (products in a category) in my page, but this data are random, so, I'm using a HQL statement link this: string hql = "from Product p where p.Category.Id=:IdCategory order by rand()"; It's working fine, but when I page, sometimes the same product appears in the first, second, etc... pages because it's order by rand(). Is there any way to make a random order by fixed by period (time internal) ? Or any solution ? thanks Cheers

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  • NorthWest Arkansas TechFest

    - by dmccollough
    David Walker is taking Tulsa TechFest on the road to NorthWest Arkansas When Thursday, July 8th 2010 Where Center for Nonprofits @St. Mary’s 1200 West Walnut Street Rogers, Ar 72756 479-936-8218 Map it with Bing! What is NorthWest Arkansas TechFest ? It is a technical conference with a primary focus to provide training/teaching sessions that are immediately beneficial to the broadest range of IT professionals in their day-to-day jobs. We can accomplish this with numerous national and international speakers delivering 75 minute sessions. A charitable non-profit event organized by local area volunteers. Even though it its a free event, we ask that you support the community and PLEASE bring TWO CANS or TWO BUCKS. All canned food will be donated to the NWA Food Bank and all proceeds will be donated to the The Jones Center. Since our first event in the Tulsa area back in 1996, many other communities have been following our example by hosting their own TechFest events: Vancouver TechFest, Houston TechFest, Dallas TechFest, Alberta TechFest and Indy TechFest. We are very PROUD to now bring the event to NorthWest Arkansas! Who should Attend? Every IT Professional IT Job seekers and IT Recruiters and Hiring Managers Developers of all languages Graphic and Web Designers Infrastructure, IT and System Administrators eMarketing Professionals Project Managers Compliance Managers IT Directors and Mangers Chief Compliance Officers Chief Security Officers CIOs/CTOs CEOs/Executive Officers With this many hours of training, anyone in the or wanting to get into the IT Industry will definitely find interesting and instructional presentations by professional speakers. Want to keep informed? More information can be found here.

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  • Error trying to use rand from std library cstdlib with g++

    - by Matt
    I was trying to use the random function in Ubuntu compiling with g++ on a larger program and for some reason rand just gave weird compile errors. For testing purposes I made the simplest program I could and it still gives errors. Program: #include <iostream> using std::cout; using std::endl; #include <cstdlib> int main() { cout << "Random number " << rand(); return 0; } Error when compiling with the terminal sudo g++ chapter_3/tester.cpp ./test ./test: In function _start': /build/buildd/eglibc-2.10.1/csu/../sysdeps/i386/elf/start.S:65: multiple definition of_start' /usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/crt1.o:/build/buildd/eglibc-2.10.1/csu/../sysdeps/i386/elf/start.S:65: first defined here ./test:(.rodata+0x0): multiple definition of _fp_hw' /usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/crt1.o:(.rodata+0x0): first defined here ./test: In function_fini': (.fini+0x0): multiple definition of _fini' /usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/crti.o:(.fini+0x0): first defined here ./test:(.rodata+0x4): multiple definition of_IO_stdin_used' /usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/crt1.o:(.rodata.cst4+0x0): first defined here ./test: In function __data_start': (.data+0x0): multiple definition ofdata_start' /usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/crt1.o:(.data+0x0): first defined here ./test: In function __data_start': (.data+0x4): multiple definition of__dso_handle' /usr/lib/gcc/i486-linux-gnu/4.4.1/crtbegin.o:(.data+0x0): first defined here ./test: In function main': (.text+0xb4): multiple definition ofmain' /tmp/cceF0x0p.o:tester.cpp:(.text+0x0): first defined here ./test: In function _init': (.init+0x0): multiple definition ofinit' /usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/crti.o:(.init+0x0): first defined here /usr/lib/gcc/i486-linux-gnu/4.4.1/crtend.o:(.dtors+0x0): multiple definition of `_DTOR_END' ./test:(.dtors+0x4): first defined here /usr/bin/ld: error in ./test(.eh_frame); no .eh_frame_hdr table will be created. collect2: ld returned 1 exit status

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  • struct and rand()

    - by teoz
    I have a struct with an array of 100 int (b) and a variable of type int (a) I have a function that checks if the value of "a" is in the array and i have generated the array elements and the variable with random values. but it doesn't work can someone help me fix it? #include <stdio.h> #include <stdlib.h> #include <time.h> typedef struct { int a; int b[100]; } h; int func(h v){ int i; for (i=0;i<100;i++){ if(v.b[i]==v.a) return 1; else return 0; } } int main(int argc, char** argv) { h str; srand(time(0)); int i; for(i=0;0<100;i++){ str.b[i]=(rand() % 10) + 1; } str.a=(rand() % 10) + 1; str.a=1; printf("%d\n",func(str)); return 0; }

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  • Rand(); with exclusion to and already randomly generated number..?

    - by Stefan
    Hey, I have a function which calls a users associated users from a table. The function then uses the rand(); function to chose from the array 5 randomly selected userID's however!... In the case where a user doesnt have many associated users but above the min (if below the 5 it just returns the array as it is) then it gives bad results due to repeat rand numbers... How can overcome this or exclude a previously selected rand number from the next rand(); function call. Here is the section of code doing the work. Bare in mind this must be highly efficient as this script is used everywhere. $size = sizeof($users)-1; $nusers[0] = $users[rand(0,$size)]; $nusers[1] = $users[rand(0,$size)]; $nusers[2] = $users[rand(0,$size)]; $nusers[3] = $users[rand(0,$size)]; $nusers[4] = $users[rand(0,$size)]; return $nusers; Thanks in advance! Stefan

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  • How do I deselect grid row when grouping in David Poll's silverlight CollectionPrinter

    - by kpg
    I'm using David Poll's CollectionPrinter and modifications by Fama to perform grouping. I'm using the control to print a datagrid with grouping and it works well if not a little slow. Problem: When the grid is displayed the first row of the grid is selected and the first cell of the row is also selected. I want to either deselect the row or change the datagrid template to make selected rows/cells appear as not selected. I tried to specify a grid template to change the row/cell selection appearance but when I added the default template I got a COM error of all things - anyway I concluded that what I was doing was not compatible with the SLab libraries, or perhaps because the grid was specified in a datatemplate. In any case I abandoned that approach. Since I have the SLab source if I understood it more there may be a way to deselect the row after from that side of things - but I know the SLaB CommectionPrinter does not rely on the data template to be a grid, so I'm not sure how to modify the code to accomplish what I want. Question: How can I prevent the row from being selected or deselect it once it is or change the appearance of the selectd row when using the CollectionPrinter with grouping? Note that the row selection problem may occur without grouping as well, I don;t know, but it definatly does with grouping.

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  • Cheap and cheerful rand() replacement.

    - by Mick
    After profiling a large game playing program, I have found that the library function rand() is consuming a considerable fraction of the total processing time. My requirements for the random number generator are not very onerous - its not important that it pass a great battery of statistical tests of pure randomness. I just want something cheap and cheerful that is very fast. Any suggestions?

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  • =rand(100,60) - MSOffice Problem

    - by sagar
    Oho ! Have you tried this one ?? Very simple office utility question. The question is something like this. Open Microsoft word ( 2003 or 2007 ) whatever you use. ( Let me clarify that - I am not here for any kind of advertisement of Micro soft - I want to solution to my Query ) After opening the word. Let's have a new empty blank document. ( It's up to you to have it or not ) Press enter to go to a new line. now type "=rand(100,60)" in new line Now press enter After writing this - it will create 81 pages long story The question is Why ?? How ?? What exactly microsoft word is doing?? Thanks in advance for sharing your great knowledge. Sagar

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  • Linq to NHibernate, Order by Rand() ?

    - by Felipe
    Hi everybody, I'm using Linq To Nhibernate, and with a HQL statement I can do something like this: string hql = "from Entity e order by rand()"; Andi t will be ordered so random, and I'd link to know How can I do the same statement with Linq to Nhibernate ? I try this: var result = from e in Session.Linq<Entity> orderby new Random().Next(0,100) select e; but it throws a exception and doesn't work... is there any other way or solution? Thanks Cheers

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