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  • Oracle Database 11g upgrade egy érdekes hozadéka

    - by Lajos Sárecz
    A napokban olvastam egy érdekes 11g upgrade hatást Tom Kyte blogjában. Mivel mostanában sok hazai ügyfél tervez 11g upgrade-et, úgy gondoltam beszámolok én is errol, hátha valakinek hasznos lehet, bár szerintem viszonylag kevesen futnak majd bele ebbe a problémába. Az érdekes jelenséget az Oracle Database 11g Release 2 verzióban bevezetett deferred segment creation okozza. Ez egy alapértelmezetten bekapcsolt képesség, ami arra való, hogy egy új tábla készítésekor az adatbázis-kezelo automatikusan nem foglal tárterületet, azaz nincs initial extent allokáció. Ennek az újításnak a célja az, hogy alkalmazások telepítésekor a létrejövo számtalan táblának ne legyen lefoglalva a tároló terület, amíg azokba nem kerül adat. Ez azért hasznos, mert sok dobozos alkalmazás számos olyan táblát létrehoz, amihez aztán végül nem is nyúl az adott környezetben (pl. nem használt alkalmazás funkció miatt). Összességében tehát sok feleslegesen lefoglalt diszk területet spórolhatunk ezzel, azonban ha egy táblatérre nincs kvótánk, akkor az eddig tapasztalt muködéssel szemben létre tudunk hozni táblákat, hiszen nem foglalunk le vele területet. Viszont az elso insert muveletnél kapunk egy "ORA-01950: no privileges on tablespace 'USERS'" hibát, ami nem volt megszokott insert muveletek esetén korábban. Hogy ez most bug, vagy feature, azt döntse el mindenki maga :-) Ha valakinek nem tetszik így, akkor persze kikapcsolhatja a deferred segment creation képességet akár az init/spfile szintjén, akár session szintjén ("alter session set deferred_segment_creation = false;"), de lehet a tábla létrehozásakor is szabályozni: "create table t ( x int ) segment creation immediate;"

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  • Issue getting camera emulation to work with Tom G's HttpCamera

    - by user591524
    I am trying to use the android emulator to preview video from webcam. I have used the tom gibara sample code, minus the webbroadcaster (i am instead using VLC streaming via http). So, I have modified the SDK's "CameraPreview" app to use the HttpCamera, but the stream never appears. Debugging through doesn't give me any clues either. I wonder if anything obvious is clear to others? The preview app launches and remains black. Notes: 1) I have updated the original CameraPreview class as described here: http://www.inter-fuser.com/2009/09/live-camera-preview-in-android-emulator.html, but referencing httpCamera instead of socketcamera. 2) I updated Tom's original example to reference "Camera" type instead of deprecated "CameraDevice" type. 3) Below is my CameraPreview.java. 4) THANK YOU package com.example.android.apis.graphics; import android.app.Activity; import android.content.Context; import android.hardware.Camera; import android.os.Bundle; import android.view.SurfaceHolder; import android.view.SurfaceView; import android.view.Window; import java.io.IOException; import android.graphics.Canvas; // ---------------------------------------------------------------------- public class CameraPreview extends Activity { private Preview mPreview; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); // Hide the window title. requestWindowFeature(Window.FEATURE_NO_TITLE); // Create our Preview view and set it as the content of our activity. mPreview = new Preview(this); setContentView(mPreview); } } // ---------------------------------------------------------------------- class Preview extends SurfaceView implements SurfaceHolder.Callback { SurfaceHolder mHolder; //Camera mCamera; HttpCamera mCamera;//changed Preview(Context context) { super(context); // Install a SurfaceHolder.Callback so we get notified when the // underlying surface is created and destroyed. mHolder = getHolder(); mHolder.addCallback(this); //mHolder.setType(SurfaceHolder.SURFACE_TYPE_PUSH_BUFFERS); mHolder.setType(SurfaceHolder.SURFACE_TYPE_NORMAL);//changed } public void surfaceCreated(SurfaceHolder holder) { // The Surface has been created, acquire the camera and tell it where // to draw. //mCamera = Camera.open(); this.StartCameraPreview(holder); } public void surfaceDestroyed(SurfaceHolder holder) { // Surface will be destroyed when we return, so stop the preview. // Because the CameraDevice object is not a shared resource, it's very // important to release it when the activity is paused. //mCamera.stopPreview();//changed mCamera = null; } public void surfaceChanged(SurfaceHolder holder, int format, int w, int h) { // Now that the size is known, set up the camera parameters and begin // the preview. //Camera.Parameters parameters = mCamera.getParameters(); //parameters.setPreviewSize(w, h); //mCamera.setParameters(parameters); //mCamera.startPreview(); this.StartCameraPreview(holder); } private void StartCameraPreview(SurfaceHolder sh) { mCamera = new HttpCamera("10.213.74.247:443", 640, 480, true);//changed try { //mCamera.setPreviewDisplay(holder); Canvas c = sh.lockCanvas(null); mCamera.capture(c); sh.unlockCanvasAndPost(c); } catch (Exception exception) { //mCamera.release(); mCamera = null; // TODO: add more exception handling logic here } } }

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  • Tom Kyte szeminárium Budapesten, 2010. ápr. 19-20.

    - by Fekete Zoltán
    Még lehet jelentkezni Tom Kyte 2010-es budapesti szemináriumára, az itt található linkeken keresztül: - 2010. április 19-20., Budapesten tantermi szeminárium keretében. Témák: The top 10 - no 11 - new features of Oracle; Database 11g; All about binding; Materialized Views, Caching; Effective Indexing; Storage Techniques; Reorganizing objects - when and how. ASK TOM!

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  • Do Eclipse's Refactoring Tools Violate The Java Language Specification?

    - by Tom Tresansky
    In Eclipse 3.5, say I have a package structure like this: tom.package1 tom.package1.packageA tom.package1.packageB if I right click on an the tom.package1 package and go to Refactor-Rename, an option "Rename subpackages" appears as a checkbox. If I select it, and then rename tom.package1 to tom.red my package structure ends up like this: tom.red tom.red.packageA tom.red.packageB Yet I hear that Java's packages are not hierarchical. The Java Tutorials back that up (see the section on Apparent Hierarchies of Packages). It certainly seems like Eclipse is treating packages as hierarchical in this case. I was curious why access specifiers couldn't allow/restrict access to "sub-packages" in a previous question because I KNEW I had seen "sub-packages" referenced somewhere before. So are Eclipse's refactoring tools intentionally misleading impressionable young minds by furthering the "sub-package" myth? Or am I misinterpreting something here?

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  • Tricky SQL - Select non-adjacent numbers

    - by Daniel
    Given this data on SQL Server 2005: SectionID Name 1 Dan 2 Dan 4 Dan 5 Dan 2 Tom 7 Tom 9 Tom 10 Tom How would I select records where the sectionID must be +-2 or more from another section for the same name. The result would be: 1 Dan 4 Dan 2 Tom 7 Tom 9 Tom Thanks for reading!

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  • Select and copy to MySQL table PHP

    - by Liju
    Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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  • Cyrus: In practical terms, how do end users administer their shared mailboxes?

    - by Nick
    Let's say we have four customer service reps: Billy, Bob, Joe, and Tom. Tom is the department manager. There's a shared Customer Service mailbox on the Cyrus server that they all have access to. Tom, as the manager also has administrative privileges for the shared mailbox. They decide they want to create sub-folders a certain way, and Tom creates them. They're all running Thunderbird, so Tom right-clicks the main folder and chooses "New Subfolder". Now Tom has the Subfolders he needs and the other sales reps have... nothing! Because Cyrus created the Subfolders giving Tom "Full Access" permissions, and everyone else gets no access. So how does Tom give the other reps in his department access to the new folders? As far as Cyrus is concerned, Tom has permission to grant others access to his new mailboxes- But as far as I can tell, there's no option in Thunderbird for granting mailbox permissions. An IT staff member should not have to receive a support request every time someone wants to add a Subfolder to a shared mailbox. That's why we make certain users into mailbox admins in the first place! But asking (non-technical) users to SSH into an IMAP server to run cyradm seems like a bad idea too. Certainly someone has found a solution for this dilemma. Perhaps a Thunderbird extension for setting Cyrus permissions? Or something like umask that forces subfolders to have identical permissions to their parents on creation? And related, what about Sieve configuration? Is there anyway that can be done from the client machine too? Thanks, Nick

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  • blacklist VGA compatible controller: Intel Corporation 82845G/GL[Brookdale-G]/GE

    - by Thomas Labensi
    I have an hp a310n pavillion I have installed an nvidia pci geforce card I want to blacklist the VGA compa[Brookdale-G]/GE Chipset Integrated Graphics Device (rev 03)integrated graphics what do I need to do?? [email protected]:~$ lspci | grep VGA 00:02.0 VGA compatible controller: Intel Corporation 82845G/GL[Brookdale-G]/GE Chipset Integrated Graphics Device (rev 03) 02:09.0 VGA compatible controller: NVIDIA Corporation NV11 [GeForce2 MX/MX 400] (rev b2) [email protected]:~$ I'm using the nvidia via neuvoux and I want to really make sure I'm using the nvidia card

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  • Primefaces, JavaScript, and JSF does not work well together or am I doing something wrong

    - by Harry Pham
    Here is something so simple <p:commandLink value="Tom" onclick="document.getElementById('tom').focus()"/><br/> <input id="tom"/> When u click on the Tom, the textbox get focus. Great, now try this <p:commandLink value="Tom" onclick="document.getElementById('tom').focus()"/><br/> <h:inputText id="tom"/> <br/> when I click nothing happen, I check firebug, I see document.getElementById("tom") is null When I try to use jQuery $('#tom').focus(), nothing happen, no error, but did not get focus either. This is the response (not sure if this is the response from the server) when I see from firebug <?xml version="1.0" encoding="utf-8"?> <partial-response> <changes> <update id="javax.faces.ViewState"><![CDATA[455334589763307998:-2971181471269134244]]></update> </changes> <extension primefacesCallbackParam="validationFailed">{"validationFailed":false}</extension> </partial-response>

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  • How to mutate rows of data frame - replacing one value with another

    - by rhh
    I'm having trouble with what I think is a basic R task. Here's my sample dataframe named 'b' Winner Color Size Tom Yellow Med Jerry Yellow Lar Jane Blue Med where items in the Winner column are factors. I'm trying to change "Tom" in the dataframe to "Tom LLC" and I can't get it done. Here's what I tried: Simple way: b$winner[b$winner=='Tom'] = as.factor('Tom LLC') but that failed with "invalid factor level, NAs generated" Next I tried a more advanced route: name_reset = function (x, y, z) { if (x$winner == y) {x$winner = z} } b = adply(b,1,name_reset,'Tom','Tom LLC') but that failed with "Error in list_to_dataframe(res, attr(.data, "split_labels")) : Results are not equal lengths" I feel I'm missing something basic. Can someone redirect me or offer suggestions on the code I wrote above? Thank you very much

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  • SQL query for select distinct with most recent timestamp first

    - by Josh
    I have a mysql table with three columns: username, location, timestamp. This is basically a log of user activity of what location they are in and the time that they were there. What I want to do is select a distinct username+location where only the most recent item (by timestamp) is provided. So say the table consists of: tom roomone 2011-3-25 10:45:00 tom roomtwo 2011-3-25 09:00:00 tom roomtwo 2011-3-25 08:30:00 pam roomone 3011-3-25 07:20:23 I would want only these to be selected: tom roomone 2011-3-25 10:45:00 tom roomtwo 2011-3-25 09:00:00

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  • Java MVC - How to divide a done text game into MVC?

    - by Zopyrus
    Been sitting here for hours now trying to figure this out, so a bit sympathy for this large question. :) The Goal: I simply want to divide my done code into MVC (Model View Controller) parts. I have the game logics done and text based - the code works fine. The Problem: Well, I want to implement this code into MVC, but where do explain for the MODEL that it should use text-based? Because the VIEW is only for the layout (graphically) correct? I am having a REALLY hard time figuring out where to begin at all. Any pointers would be so nice! Here is my game logics code: import mind.*; import javax.swing.*; import java.util.*; import java.lang.*; import java.awt.*; public class Drive { String[] mellan; boolean gameEnd, checkempty, checkempty2, enemy, enemy2; String gr,rd,tom; int digits; public Drive() { // Gamepieces in textform gr="G"; rd="R"; tom=" "; mellan = new String[7]; String[] begin = {gr,gr,gr,tom,rd,rd,rd}; String[] end = {rd,rd,rd,tom,gr,gr,gr}; //input Scanner in = new Scanner(System.in); mellan=begin; gameEnd=false; while (gameEnd == false) { for(int i=0; i<mellan.length; i++) { System.out.print(mellan[i]); } System.out.print(" Choose 0-6: "); digits = in.nextInt(); move(); checkWin(); } } void move() { //BOOLEAN for gameruls!!! checkempty = digits<6 && mellan[digits+1]==tom; checkempty2 = digits>0 && mellan[digits-1]==tom; enemy = (mellan[digits]==gr && mellan[digits+1]==rd && mellan[digits+2]==tom); enemy2 = (mellan[digits]==rd && mellan[digits-1]==gr && mellan[digits-2]==tom); if(checkempty) { mellan[digits+1]=mellan[digits]; mellan[digits]=tom; } else if (checkempty2) { mellan[digits-1]=mellan[digits]; mellan[digits]=tom; } else if (enemy) { mellan[digits+2]=mellan[digits]; mellan[digits]=tom; } else if (enemy2) { mellan[digits-2]=mellan[digits]; mellan[digits]=tom; } } void checkWin() { String[] end = {rd,rd,rd,tom,gr,gr,gr}; for (int i=0; i<mellan.length; i++){ } if (Arrays.equals(mellan,end)) { for (int j=0; j<mellan.length; j++) { System.out.print(mellan[j]); } displayWin(); } } void displayWin() { gameEnd = true; System.out.println("\nNicely Done!"); return; } // Kör Drive! public static void main(String args[]) { new Drive(); } } Here is how I defined my DriveView thus far: (just trying to make one button to work) import mind.*; import javax.swing.*; import java.util.*; import java.lang.*; import java.awt.*; import java.awt.event.*; public class DriveView extends JFrame { JButton ruta1 = new JButton("Green"); JButton ruta2 = new JButton("Green"); JButton rutatom = new JButton(""); JButton ruta6 = new JButton("Red"); private DriveModel m_model; public DriveView(DriveModel model) { m_model = model; //Layout for View JPanel myPanel = new JPanel(); myPanel.setLayout(new FlowLayout()); myPanel.add(ruta1); myPanel.add(ruta2); myPanel.add(rutatom); myPanel.add(ruta6); this.setContentPane(myPanel); this.pack(); this.setTitle("Drive"); this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); } void addMouseListener(ActionListener mol) { ruta2.addActionListener(mol); } } And DriveController which gives me error at compile import mind.*; import java.awt.*; import java.awt.event.*; import javax.swing.*; import java.lang.*; public class DriveController { private DriveModel m_model; private DriveView m_view; public DriveController(DriveModel model, DriveView view) { m_model = model; m_view = view; view.addMouseListener(new MouseListener()); } class MouseListener implements ActionListener { public void actionPerformed(ActionEvent e) { String mening; mening = e.getActionCommand(); if (mening.equals("Green")) { setForeground(Color.red); } } } }

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  • Why does Windows XP (during a rename operation) report file already exists when it doesn't?

    - by Hawk
    From the command-line: E:\menu\html\tom\val\.svn\tmp\text-base>ver Microsoft Windows [Version 5.2.3790] E:\menu\html\tom\val\.svn\tmp\text-base>dir Volume in drive E is DATA Volume Serial Number is F047-F44B Directory of E:\menu\html\tom\val\.svn\tmp\text-base 12/23/2010 04:36 PM <DIR> . 12/23/2010 04:36 PM <DIR> .. 12/23/2010 04:01 PM 0 wtf.com3.csv.svn-base 1 File(s) 0 bytes 2 Dir(s) 170,780,262,400 bytes free E:\menu\html\tom\val\.svn\tmp\text-base>rename wtf.com3.csv.svn-base com3.csv.svn-base A duplicate file name exists, or the file cannot be found. E:\menu\html\tom\val\.svn\tmp\text-base>dir Volume in drive E is DATA Volume Serial Number is F047-F44B Directory of E:\menu\html\tom\val\.svn\tmp\text-base 12/23/2010 04:36 PM <DIR> . 12/23/2010 04:36 PM <DIR> .. 12/23/2010 04:01 PM 0 wtf.com3.csv.svn-base 1 File(s) 0 bytes 2 Dir(s) 170,753,064,960 bytes free E:\menu\html\tom\val\.svn\tmp\text-base>` I don't know what to do about this, as there is no other file in this directory. Why does Windows XP report that there is already a file here named com3.csv.svn-base when there is clearly no other file here?

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  • LINQ-To-SQL and Many-To-Many Relationship Deletions

    - by Jake
    I have a many-to-many relationship between two tables, let's say Friends and Foods. If a friend likes a food I stick a row into the FriendsFoods table, like this: ID Friend Food 1 'Tom' 'Pizza' FriendsFoods has a Primary Key 'ID', and two non-null foreign keys 'Friend' and 'Food' to the 'Friends' and 'Foods' tables, respectively. Now suppose I have a Friend tom .NET object corresponding to 'Tom', and Tom no longer likes pizza (what is wrong with him?) FriendsFoods ff = tom.FriendsFoods.Where(x => x.Food.Name == 'Pizza').Single(); tom.FriendsFoods.Remove(ff); pizza.FriendsFoods.Remove(ff); If I try to SubmitChanges() on the DataContext, I get an exception because it attempts to insert a null into the Friend and Food columns in the FriendsFoods table. I'm sure I can put together some kind of convoluted logic to track changes to the FriendsFoods table, intercept SubmitChanges() calls, etc to try and get this to work the way I want, but is there a nice, clean way to remove a Many-To-Many relationship with LINQ-To-SQL?

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  • Finding duplicate values in a SQL table

    - by Alex
    It's easy to find duplicates with one field SELECT name, COUNT(email) FROM users GROUP BY email HAVING ( COUNT(email) > 1 ) So if we have a table ID NAME EMAIL 1 John [email protected] 2 Sam [email protected] 3 Tom [email protected] 4 Bob [email protected] 5 Tom [email protected] This query will give us John, Sam, Tom, Tom because they all have the same e-mails. But what I want, is to get duplicates with the same e-mails and names. I want to get Tom, Tom. I made a mistake, and allowed to insert duplicate name and e-mail values. Now I need to remove/change the duplicates. But I need to find them first.

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  • Finding duplicate values in a SQL table - ADVANCED

    - by Alex
    It's easy to find duplicates with one field SELECT name, COUNT(email) FROM users GROUP BY email HAVING ( COUNT(email) > 1 ) So if we have a table ID NAME EMAIL 1 John [email protected] 2 Sam [email protected] 3 Tom [email protected] 4 Bob [email protected] 5 Tom [email protected] This query will give us John, Sam, Tom, Tom because they all have the same e-mails. But what I want, is to get duplicates with the same e-mails and names. I want to get Tom, Tom. I made a mistake, and allowed to insert duplicate name and e-mail values. Now I need to remove/change the duplicates. But I need to find them first.

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  • Directory error when trying to create a new user

    - by Tom Brossman
    I added a second user 'shirley' in Settings - User Accounts, and set a password. The account type is Standard. In 11.04, this worked and I logged in and had a functioning desktop for this user. How is this done in 11.10? When I try to log in as this user I have this error: Nautilus could not create the required folder "/home/shirley/.config/nautilus". Before running Nautilus, please create the following folder, or set permissions such that Nautilus can create it. The only option then is to click OK, this dumps me out to full-screen Nautilus, like this: There is no launcher or visible way to start any programs. Print screen doesn't take a screengrab. The desktop is similar to this question but I get no terminal when I press CTRL+ALT+T. I have to press CTRL+ALT+F2 and restart from the terminal to get out of this. This answer is to install gnome-system-tools. Shouldn't I be able to add a second user with the default install? EDIT: I tried the deluser+adduser suggestion, there was no change after trying it. Here is what I got: [email protected]:~$ sudo deluser shirley [sudo] password for tom: Removing user `shirley' ... Warning: group `shirley' has no more members. Done [email protected]:~$ sudo adduser shirley Adding user `shirley' ... Adding new group `shirley' (1001) Adding new user shirley' (1001) with groupshirley' The home directory '/home/shirley' already exists. Not copying from `/etc/skel'. Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully Changing user information for shirley Enter the new value, or press ENTER for the default Full Name []: Room Number []: Work Phone []: Home Phone []: Other []: Is the information correct? [Y/n] y What has gone so wrong with simply adding a second user? Am I the only one having this problem? I'd reinstall if that fixed things, but this is a fresh install only a few days old.

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  • Uploading file from file object with PyCurl

    - by Tom
    I'm attempting to upload a file like this: import pycurl c = pycurl.Curl() values = [ ("name", "tom"), ("image", (pycurl.FORM_FILE, "tom.png")) ] c.setopt(c.URL, "http://upload.com/submit") c.setopt(c.HTTPPOST, values) c.perform() c.close() This works fine. However, this only works if the file is local. If I was to fetch the image such that: import urllib2 resp = urllib2.urlopen("http://upload.com/people/tom.png") How would I pass resp.fp as a file object instead of writing it to a file and passing the filename? Is this possible?

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  • Python file-io code listing current folder path instead of the specified

    - by Tom Brito
    I have the code: import os import sys fileList = os.listdir(sys.argv[1]) for file in fileList: if os.path.isfile(file): print "File >> " + os.path.abspath(file) else: print "Dir >> " + os.path.abspath(file) Located in my music folder ("/home/tom/Music") When I call it with: python test.py "/tmp" I expected it to list my "/tmp" files and folders with the full path. But it printed lines like: Dir >> /home/tom/Music/seahorse-gw2jNn Dir >> /home/tom/Music/FlashXX9kV847 Dir >> /home/tom/Music/pulse-DcIEoxW5h2gz This is, the correct file names, but the wrong path (and this files are not either in my Music folder).. What's wrong with this code?

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  • What could cause these "failed to authenticate" logs other than failed login attempts (OSX)?

    - by Tom
    I've found this in the Console logs: 10/03/10 3:53:58 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:53:58 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:00 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:00 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:03 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:03 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). There are about 11 of these "failed to authenticate" messages logged in quick succession. It looks to me like someone is sitting there trying to guess the password. However, when I tried to replicate this I get the same log messages except that this extra message appears after five attempts: 13/03/10 1:18:48 PM DirectoryService[11] Failed Authentication return is being delayed due to over five recent auth failures for username: tom. I don't want to accuse someone of trying to break into an account without being sure that they were actually trying to break in. My question is this: is it almost definitely someone guessing a password, or could the 11 "failed to authenticate" messages be caused by something else?

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  • What's the format of Real World Performance Day?

    - by william.hardie
    A question that has cropped a lot of late is "what's the format of Real World Performance Day?" Not an unreasonable question you might think. Sure enough, a quick check of the Independent Oracle User Group's website tells us a bit about the Real World Performance Day event, but no formal agenda? This was one of the questions I posed to Tom Kyte (one of the main presenters) in our recent podcast. Tom tells us that this isn't your traditional event where one speaker follows another with loads of slides. In fact, the Real World Performance Day features Tom and fellow Oracle performance experts - Andrew Holdsworth and Graham Wood - continuously on stage throughout the day. All three will be discussing database performance challenges and solutions from development, architectural design and management perspectives. There's going to be multi-terabyte demos on show, less of the traditional slides, and more interactive debate and discussion going on. Tune-in and hear what else Tom has to say about this fairly unique event!

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  • What could cause these "failed to authenticate" logs other than failed login attempts (OSX)?

    - by Tom
    I've found this in the Console logs: 10/03/10 3:53:58 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:53:58 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:00 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:00 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:03 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:03 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). There are about 11 of these "failed to authenticate" messages logged in quick succession. It looks to me like someone is sitting there trying to guess the password. However, when I tried to replicate this I get the same log messages except that this extra message appears after five attempts: 13/03/10 1:18:48 PM DirectoryService[11] Failed Authentication return is being delayed due to over five recent auth failures for username: tom. I don't want to accuse someone of trying to break into an account without being sure that they were actually trying to break in. My question is this: is it almost definitely someone guessing a password, or could the 11 "failed to authenticate" messages be caused by something else? EDIT: The actual user wasn't logged in, or using a computer at the time of the log in attempts.

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  • Using SQL to join spreadsheets in excel

    - by toms
    Based on the explenation here: How do I join two worksheets in Excel as I would in SQL? I tried to join to excel sheets from different files into the same sheet. However, I keep getting this error message when I try to refresh the table: [MICROSOFT][OBDC Excel Driver] Too few parameters. Expected 5. The SQL queries i've put in so far were: SELECT `Sheet1$`.ID, `Sheet1$`.Name, `Sheet1$`.`L Name` FROM `C:\Users\Tom\Book1.xlsx`.`Sheet1$` a LEFT JOIN `C:\Users\Tom\Book2.xlsx`.`Sheet1$` b ON a.col2= b.col2 and SELECT `Sheet1$`.ID, `Sheet1$`.Name, `Sheet1$`.`L Name` FROM `C:\Users\Tom\Book1.xlsx`.`Sheet1$` a LEFT JOIN `C:\Users\Tom\Book2.xlsx`.`Sheet1$` b ON a.`ID`= b.`ID` and SELECT * FROM `C:\Users\Tom\Book1.xlsx`.`Sheet1$` a LEFT JOIN `C:\Users\Tom\Book2.xlsx`.`Sheet1$` b ON a.`ID`= b.`ID` and a few combinations and alterations. I can't seem to find the solution. I've learned that it definitely doesn't like the SELECT *. But I can't fix it. Can anyone suggest any solution?

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