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• Optimize MySQL query (ngrams, COUNT(), GROUP BY, ORDER BY)

  - by Gerardo

  I have a database with thousands of companies and their locations. I have implemented n-grams to optimize search. I am making one query to retrieve all the companies that match with the search query and another one to get a list with their locations and the number of companies in each location. The query I am trying to optimize is the latter. Maybe the problem is this: Every company ('anunciante') has a field ('estado') to make logical deletes. So, if 'estado' equals 1, the company should be retrieved. When I run the EXPLAIN command, it shows that it goes through almost 40k rows, when the actual result (the reality matching companies) are 80. How can I optimize this? This is my query (XXX represent the n-grams for the search query): SELECT provincias.provincia AS provincia, provincias.id, COUNT(*) AS cantidad FROM anunciantes JOIN anunciante_invertido AS a_i0 ON anunciantes.id = a_i0.id_anunciante JOIN indice_invertido AS indice0 ON a_i0.id_invertido = indice0.id LEFT OUTER JOIN domicilios ON anunciantes.id = domicilios.id_anunciante LEFT OUTER JOIN localidades ON domicilios.id_localidad = localidades.id LEFT OUTER JOIN provincias ON provincias.id = localidades.id_provincia WHERE anunciantes.estado = 1 AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') GROUP BY provincias.id ORDER BY cantidad DESC And this is the query explained (hope it can be read in this format): id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY anunciantes ref PRIMARY,estado estado 1 const 36669 Using index; Using temporary; Using filesort 1 PRIMARY domicilios ref id_anunciante id_anunciante 4 db84771_viaempresas.anunciantes.id 1 1 PRIMARY localidades eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.domicilios.id_localidad 1 1 PRIMARY provincias eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.localidades.id_provincia 1 1 PRIMARY a_i0 ref PRIMARY,id_anunciante,id_invertido PRIMARY 4 db84771_viaempresas.anunciantes.id 1 Using where; Using index 1 PRIMARY indice0 eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.a_i0.id_invertido 1 Using index 6 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 6 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 5 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 5 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 4 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 4 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 3 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 3 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 2 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 2 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index

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• mysql how to see most common queries

  - by Nikos

  I have a server and many websites, i want to see the most common queries so that to optimize them. Do you know any tool or any way to collect some statistics ? Thank you

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• I DISTINCTly hate MySQL (help building a query)

  - by Alex Mcp

  This is staight forward I believe: I have a table with 30,000 rows. When I SELECT DISTINCT 'location' FROM myTable it returns 21,000 rows, about what I'd expect, but it only returns that one column. What I want is to move those to a new table, but the whole row for each match. My best guess is something like SELECT * from (SELECT DISTINCT 'location' FROM myTable) or something like that, but it says I have a vague syntax error. Is there a good way to grab the rest of each DISTINCT row and move it to a new table all in one go?

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• mysql display each day in a month

  - by Jason

  during a month, display the infor each date, order by date, but this infor is empty in some day. how can i still display each day as a row? Product date ----------------- 20 2008-01-01 10 2008-01-02 20 2008-01-03 10 2008-01-05 09 2008-01-08 30 2008-01-09 result: Product date ----------------- 20 2008-01-01 10 2008-01-02 20 2008-01-03 0 2008-01-04 10 2008-01-05 0 2008-01-06 0 2008-01-07 09 2008-01-08 30 2008-01-09

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• rewritten mysql query returning unexpected results, trying to figure out why

  - by dq

  I created a messy query in a hurry a while ago to get a list of product codes. I am now trying to clean up my tables and my code. I recently tried to rewrite the query in order for it to be easier to use and understand. The original query works great, but it requires multiple search strings in order to do one search because it uses UNIONS, and it has a few other issues. My newly modified query is easier to understand, and only requires one search string, but is returning different results. Basically the new query is leaving records out, and I would like to understand why, and how to fix it. Here are the two queries (search strings are all null): Original Query: $query = 'SELECT product_code FROM bus_warehouse_lots WHERE status=\'2\''.$search_string_1 .' UNION SELECT product_code FROM bus_po WHERE status=\'0\''.$search_string_2 .' UNION SELECT bus_warehouse_entries.new_product_code AS product_code FROM (bus_warehouse_entries LEFT JOIN bus_warehouse_transfers ON bus_warehouse_entries.picking_ticket_num=bus_warehouse_transfers.pt_number) LEFT JOIN bus_warehouse_lots ON bus_warehouse_entries.ebooks_lot_id=bus_warehouse_lots.id WHERE bus_warehouse_entries.type=\'6\' AND bus_warehouse_transfers.status=\'0\''.$search_string_3 .' UNION SELECT bus_contracts.main_product AS product_code FROM bus_contracts LEFT JOIN bus_warehouse_lots ON bus_contracts.main_product=bus_warehouse_lots.product_code WHERE bus_contracts.status=\'0\''.$search_string_4 .' UNION SELECT prod_id AS product_code FROM bus_products WHERE last_usage > \''.date('Y-m-d', strtotime('-12 months')).'\''.$search_string_5 .' ORDER BY product_code'; New Query: $query = 'SELECT bus_products.prod_id FROM bus_products' .' LEFT JOIN (bus_warehouse_lots, bus_po, bus_warehouse_entries, bus_contracts) ON (' .'bus_products.prod_id = bus_warehouse_lots.product_code' .' AND bus_products.prod_id = bus_po.product_code' .' AND bus_products.prod_id = bus_warehouse_entries.new_product_code' .' AND bus_products.prod_id = bus_contracts.main_product)' .' LEFT JOIN bus_warehouse_transfers ON' .' bus_warehouse_entries.picking_ticket_num = bus_warehouse_transfers.pt_number' .' WHERE (bus_products.last_usage > \''.date('Y-m-d', strtotime('-12 months')).'\'' .' OR bus_warehouse_lots.status = \'2\'' .' OR bus_po.status = \'0\'' .' OR (bus_warehouse_entries.type = \'6\' AND bus_warehouse_transfers.status = \'0\')' .' OR bus_contracts.status = \'0\')' .$search_string_6 .' GROUP BY bus_products.prod_id' .' ORDER BY bus_products.prod_id';

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• Mysql show create constraint?

  - by pvgoddijn

  Hi, Is there a easy way to query a table for its constraints(foreignkeys specificaly) like show create table, but for the constraints only? thanks, pvgoddijn

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• Optimize a MySQL count each duplicate Query

  - by Onema

  I have the following query That gets the city name, city id, the region name, and a count of duplicate names for that record: SELECT Country_CA.City AS currentCity, Country_CA.CityID, globe_region.region_name, ( SELECT count(Country_CA.City) FROM Country_CA WHERE City LIKE currentCity ) as counter FROM Country_CA LEFT JOIN globe_region ON globe_region.region_id = Country_CA.RegionID AND globe_region.country_code = Country_CA.CountryCode ORDER BY City This example is for Canada, and the cities will be displayed on a dropdown list. There are a few towns in Canada, and in other countries, that have the same names. Therefore I want to know if there is more than one town with the same name region name will be appended to the town name. Region names are found in the globe_region table. Country_CA and globe_region look similar to this (I have changed a few things for visualization purposes) CREATE TABLE IF NOT EXISTS `Country_CA` ( `City` varchar(75) NOT NULL DEFAULT '', `RegionID` varchar(10) NOT NULL DEFAULT '', `CountryCode` varchar(10) NOT NULL DEFAULT '', `CityID` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`City`,`RegionID`), KEY `CityID` (`CityID`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; AND CREATE TABLE IF NOT EXISTS `globe_region` ( `country_code` char(2) COLLATE utf8_unicode_ci NOT NULL, `region_code` char(2) COLLATE utf8_unicode_ci NOT NULL, `region_name` varchar(50) COLLATE utf8_unicode_ci NOT NULL, PRIMARY KEY (`country_code`,`region_code`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; The query on the top does exactly what I want it to do, but It takes way too long to generate a list for 5000 records. I would like to know if there is a way to optimize the sub-query in order to obtain the same results faster. the results should look like this City CityID region_name counter sheraton 2349269 British Columbia 1 sherbrooke 2349270 Quebec 2 sherbrooke 2349271 Nova Scotia 2 shere 2349273 British Columbia 1 sherridon 2349274 Manitoba 1

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• how i group do this mysql query

  - by moustafa

  i want to make charts system and i think it must be like that 1 jan 2009 = 10 post 2 jan 2009 = 2 post 4 jan 2009 = 10 post 6 jan 2009 = 60 post and i have posts table that has id,user_id,date how i can select from posts to show it like that

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• mysql statement with inner SELECT - how to improve performance

  - by ernie

  This statement appears inefficient because only one one out of 10 records are selected and only a of 100 entries contain comments. What can I do to improve it ? $query = "SELECT A,B,C, (SELECT COUNT(*) FROM comments WHERE comments.nid = header_file.nid) as my_comment_count FROM header_file Where A = 'admin' "

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• Creating a [materialised]view from generic data in Oracle/Mysql

  - by Andrew White

  I have a generic datamodel with 3 tables CREATE TABLE Properties ( propertyId int(11) NOT NULL AUTO_INCREMENT, name varchar(80) NOT NULL ) CREATE TABLE Customers ( customerId int(11) NOT NULL AUTO_INCREMENT, customerName varchar(80) NOT NULL ) CREATE TABLE PropertyValues ( propertyId int(11) NOT NULL, customerId int(11) NOT NULL, value varchar(80) NOT NULL ) INSERT INTO Properties VALUES (1, 'Age'); INSERT INTO Properties VALUES (2, 'Weight'); INSERT INTO Customers VALUES (1, 'Bob'); INSERT INTO Customers VALUES (2, 'Tom'); INSERT INTO PropertyValues VALUES (1, 1, '34'); INSERT INTO PropertyValues VALUES (2, 1, '80KG'); INSERT INTO PropertyValues VALUES (1, 2, '24'); INSERT INTO PropertyValues VALUES (2, 2, '53KG'); What I would like to do is create a view that has as columns all the ROWS in Properties and has as rows the entries in Customers. The column values are populated from PropertyValues. e.g. customerId Age Weight 1 34 80KG 2 24 53KG I'm thinking I need a stored procedure to do this and perhaps a materialised view (the entries in the table "Properties" change rarely). Any tips?

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• MySQL Dynamicly determine the tabel to use with inner join

  - by user366990

  He guys, I'm stuck with a problem and I hope someone can help me out. I have a date. For example 2009-10-1. This date is used to check in which season I am working. This could be summer or winter. If whe are in the summer the table to use for my inner join whould be 'summer09_rooms'. If winter 'winter09_rooms'. So I basicly whant to do a CASE WHEN in my INNER JOIN. How to accomplish this. The query would look like this: SELECT name, arrival_date, departure_date FROM holliday a INNER JOIN ( CASE when arrival_date BETWEEN 2009-10-1 AND 2009-4-1 THEN summer09_rooms b ELSE winter09_rooms b END ) ON a.dossier=b.dossier Of course this query isn't working but now I hope you'l see what I want to accomplish. Kind regards, Digital Human

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• mysql subquery strangely slow

  - by aviv

  I have a query to select from another sub-query select. While the two queries look almost the same the second query (in this sample) runs much slower: SELECT user.id ,user.first_name -- user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); This query takes 1.2s Explain on this query results: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user index first_name 152 141192 Using where; Using index 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where The second query: SELECT -- user.id -- user.first_name user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); Takes 45sec to run, with explain: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user ALL 141192 Using where 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where Why is it slower if i query only by index fields? Why both queries scans the full length of the user table? Any ideas how to improve? Thanks.

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• Procedure in converting int to decimal data type?

  - by Fedor

  I have an int(11) column which is used to store money. I read some of the answers on SO and it seems I just need to update it to be a decimal (19,4) data type. Are there any gotchas I should know about before I actually do the converting? My application is in PHP/Zend and I'm not using an ORM so I doubt I would need to update any sort of class to consistently identify the data type.

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• Mysql syntax using IN help!

  - by Axel

  Hi, i have a pictures table : pictures(articleid,pictureurl) And an articles table : articles(id,title,category) So, briefly, every article has a picture, and i link pictures with article using articleid column. now i want to select 5 pictures of articles in politic category. i think that can be done using IN but i can't figure out how to do it. Note: Please only one query, because i can do it by selecting articles firstly then getting the pictures. Thanks

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• Mysql partition error?

  - by drake

  I have a kinda table like this: CREATE TABLE test ( id MEDIUMINT NOT NULL AUTO_INCREMENT, user VARCHAR(30), time VARCHAR(30), status VARCHAR(30), origin VARCHAR(30), PRIMARY KEY (id) ) ENGINE=MyISAM; PARTITION BY RANGE(id) ( PARTITION p0 VALUES LESS THAN (500000), PARTITION p1 VALUES LESS THAN (1000000), PARTITION p2 VALUES LESS THAN (1500000), PARTITION p3 VALUES LESS THAN (2000000), PARTITION p4 VALUES LESS THAN (2500000) ) I have Three questions: 1) I have here an #1064 error; 2) How can i set split test.user as alphabetic range in partition; 3) How can i check that the partition was successful;

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• Access 2nd MySQL db in PHP without mysql_select_db()

  - by Brian

  If I select a db db1 with mysql_select_db() is it possible to access another db db2 in a query? I am looking for something like SELECT * FROMdb2.sometableWHERE 1

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• Syntax for "RETURNING" clause in Mysql PDO

  - by dmontain

  I'm trying to add a record, and at the same time return the id of that record added. I read it's possible to do it with a RETURNING clause. $stmt->prepare("INSERT INTO tablename (field1, field2) VALUES (:value1, :value2) RETURNING id"); but the insertion fails when I add RETURNING. There is an auto-incremented field called id in the table being added to. Can someone see anything wrong with my syntax? or maybe PDO does not support RETURNING?

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• Help with a MySQL SELECT WHERE Clause

  - by Dr. DOT

  A column in my table contains email addresses. I have a text string that contains the a few usernames of email addresses separated by commas. I can make text sting into an array if necessary to get my SELECT WHERE clause to work correctly. Text string search argument is 'bob,sally,steve' I want to produce a WHERE clause that only returns rows where the username portion of the email address in the table matches one of the usernames in my text string search argument. Thus a row with [email protected] would not be returned but [email protected] would be. Does anyone have a WHERE clause sample that produces this result? Thanks.

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• How does PostgreSQL's JDBC drivers compare to MySQL?

  - by Bytecode Ninja

  Especially regarding completeness and compliance with the JDBC 3 and JDBC 4 specs?

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• mysql: how to change column to be PK NU and Auto_Increment

  - by every_answer_gets_a_point

  is there a single select statement that will do all three of those: primary key, not unique, and auto_increment and not null i guess?

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• Membership with Mysql, EF 1 and ASP.NET 3.5

  - by sanfra1983

  Hi, I created a web application with asp.net 3.5 and ado.net entity framework WebForms 1, but have not yet succeeded in creating a memebrship and roles. When I go on ASP.NET Configuration and click the Security Tab I get the following error: Keyword not supported. Parameter name: metadata Someone has already created an application with these same features to help me understand where is the problem? P.S.: I'm going crazy Thanks to all

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• Problem with DBDesigner

  - by Renato Bezerra

  Hi everyone. The DBDesigner can synchronize only with MySQL? I tried with SQL Server but don't works. DBDesigner Ver: 4.0.5.6 Tks.

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• Can primary index be a CHAR in MySQL?

  - by FFish

  My primary indexes are unique reference numbers like 002345 and 000023. If I format them as integers I loose my zero's. They need to be 6 digits. Can I use CHAR? I don't need any auto increments.

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• Syntax for combining joins in mysql

  - by UltraVi01

  I seem to remember reading somewhere that there is a way to combine LEFT JOIN statements into a more simple query. I have the following query and was hoping someone could kindly take a look at it. SET @userId = 8; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug, user u, profile p LEFT JOIN user_block ub ON @userId = ub.blocked_id LEFT JOIN user_block ub2 ON @userId = ub2.blocker_id LEFT JOIN user_user uu ON @userId = uu.user_id LEFT JOIN friend_request fr ON @userId = fr.user_id WHERE ug.user_id = u.id AND u.profile_id = p.id AND (ub.blocker_id IS NULL OR ub.blocker_id != ug.user_id) AND (ub2.blocked_id IS NULL OR ub2.blocked_id != ug.user_id) AND (uu.user_friends_id IS NULL OR uu.user_friends_id != ug.user_id) AND (fr.to_user_id IS NULL OR (fr.to_user_id != ug.user_id)) AND ug.user_id!=@userId AND p.suggestible AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4

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• MySQL: Calculate depth in a parent-child model?

  - by Ivarska

  As title says: How do I calculate a node's depth in a parent-child model? I'll need the depth to, among other things, create the indent in my list (coded with PHP). Thank you in advance.

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