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  • MySQL Count If using 4 tables or Perl

    - by user1726133
    Hi I have a relatively convoluted query that relies on 4 different tables, unfortunately I do not have control of this data, but I do have to query it. I ran this simpler query and it works using just table 1 and table 2 SELECT actor, receiver, count(IF(t2.group1 = "anxiety behavior", 1,0)) AS 'anxiety' FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code GROUP BY actor; Below are the 4 tables I need and the query I tried that didn't work Table 1 | Table 2 | Table 3 | Table 4 Actor | Behavior | Behavior | type of Behavior | subject | sex | subject |subject_code er frown | frown anxiety behavior | Eric M | Eric | er Here is the query that is failing SELECT actor, count(IF(t2.group1 = "anxiety behavior", 1,0) AND(t3.sex = "M", 1,0)) AS 'anxiety', FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code JOIN subject_code t3 on t1.actor = t3.behavior_code1 JOIN subjects t4 on t3.subject = t4.yerkes_code GROUP BY actor; Any help would be much appreciated!! Thanks :) P.S. if this is easier to do in Perl tips also much appreciated

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  • Aggregate functions in ANSI SQL

    - by morpheous
    I want to use multiple aggregate functions in a query. All the examples i have seem on aggregate functions however, are trivial. Typically, they are of the form: SELECT field1,agg_func1, agg_func2 GROUP BY SOME_COLUMNS HAVING agg_func1 OP SOME_SCALAR Where: OP: is a boolean operator (e.g. <, = etc) SOME_SCALAR: is a scalar (i.e. a constant number) What I want to know is if it is possible to write (IN ANSI SQL) queries like: SELECT field1,agg_func1, agg_func2, agg_func3 GROUP BY SOME_COLUMNS HAVING (agg_func1 OP1 agg_func2) OP2 (agg_func2 OP3 agg_func3) Where: OP[N] are boolean operators or ANSI SQL clause operators like 'BETWEEN', 'LIKE', 'IN' etc. Also, assuming this is possible (I have not seen any documentation saying otherwise) are there any efficiency/performance considerations (i.e. penalties) when the HAVING clause consists of a boolean expression combining the output of the aggregate functions - instead of the normal comparison of the output of the aggregate with a constant number (e.g. min('salary') 100 ) - which is often used in the most banal examples involving aggregate functions?

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  • SVN: authz directory identifiers not support

    - by ledy
    Without using the authz, all the svn users can login and use the repos without issues. However, I would like to limit the access to some directories - not to be readable or writeable for all users. svnserve --version = 1.6.6 I tried both, granting access to users and groups. I also tried it separate, only group or only user access. [groups] admingroup=i_can_access_anything limitedgroup=i_am_limited [/] #*= @admingroup=rw i_can_access_anything=rw [projectX] #i also tried [repository:/projectX] #*= @limitedgroup=rw i_am_limited=rw Trying to access the / or /projectX at the svn fails. = access denied Without the authz, it works properly, but also grants access to other projects that do not belong to the "limited" user group :-/ Do you see what's wrong there? Thx

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  • Combining 2 Linq queries into 1

    - by Mike Fielden
    Given the following information, how can I combine these 2 linq queries into 1. Having a bit of trouble with the join statement. 'projectDetails' is just a list of ProjectDetails ProjectDetails (1 to many) PCardAuthorizations ProjectDetails (1 to many) ExpenditureDetails Notice I am grouping by the same information and selecting the same type of information var pCardAccount = from c in PCardAuthorizations where projectDetails.Contains(c.ProjectDetail) && c.RequestStatusId == 2 group c by new { c.ProjectDetail, c.ProgramFund } into g select new { Key = g.Key, Sum = g.Sum(x => x.Amount) }; var expenditures = from d in ExpenditureDetails where projectDetails.Contains(d.ProjectDetails) && d.Expenditures.ExpenditureTypeEnum == 0 group d by new { d.ProjectDetails, d.ProgramFunds } into g select new { Key = g.Key, Sum = g.Sum(y => y.ExpenditureAmounts.FirstOrDefault(a => a.IsCurrent && !a.RequiresAudit).CommittedMonthlyRecords.ProjectedEac) };

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  • Optimize slow ranking query

    - by Juan Pablo Califano
    I need to optimize a query for a ranking that is taking forever (the query itself works, but I know it's awful and I've just tried it with a good number of records and it gives a timeout). I'll briefly explain the model. I have 3 tables: player, team and player_team. I have players, that can belong to a team. Obvious as it sounds, players are stored in the player table and teams in team. In my app, each player can switch teams at any time, and a log has to be mantained. However, a player is considered to belong to only one team at a given time. The current team of a player is the last one he's joined. The structure of player and team is not relevant, I think. I have an id column PK in each. In player_team I have: id (PK) player_id (FK -> player.id) team_id (FK -> team.id) Now, each team is assigned a point for each player that has joined. So, now, I want to get a ranking of the first N teams with the biggest number of players. My first idea was to get first the current players from player_team (that is one record top for each player; this record must be the player's current team). I failed to find a simple way to do it (tried GROUP BY player_team.player_id HAVING player_team.id = MAX(player_team.id), but that didn't cut it. I tried a number of querys that didn't work, but managed to get this working. SELECT COUNT(*) AS total, pt.team_id, p.facebook_uid AS owner_uid, t.color FROM player_team pt JOIN player p ON (p.id = pt.player_id) JOIN team t ON (t.id = pt.team_id) WHERE pt.id IN ( SELECT max(J.id) FROM player_team J GROUP BY J.player_id ) GROUP BY pt.team_id ORDER BY total DESC LIMIT 50 As I said, it works but looks very bad and performs worse, so I'm sure there must be a better way to go. Anyone has any ideas for optimizing this? I'm using mysql, by the way. Thanks in advance Adding the explain. (Sorry, not sure how to format it properly) id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY t ALL PRIMARY NULL NULL NULL 5000 Using temporary; Using filesort 1 PRIMARY pt ref FKplayer_pt77082,FKplayer_pt265938,new_index FKplayer_pt77082 4 t.id 30 Using where 1 PRIMARY p eq_ref PRIMARY PRIMARY 4 pt.player_id 1 2 DEPENDENT SUBQUERY J index NULL new_index 8 NULL 150000 Using index

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  • Apache security for multi-user development web server.

    - by mrmartinblue
    I've been searching and reading through documents all morning and understand that I need to use some combination of chown and probably 'jailing' to securely give programmers access to directories on my centos webserver. Here's the situation: I have an apache web server that has any number of virtual sites located in /var/www/site1 /var/www/site2 etc.. I have different developers that need full access both ssh and vsFTP to only the site they are working on. What is the best way to create and maintain security in this scenario. My thought would be to create a new user for each coder, jail that user to the website directory they are allowed to work in, add their user to a group and set the webroot's owner to that group. Any thoughts? Good, bad, ugly? Thanks!

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  • How should I join these 3 SQL queries in Oracle?

    - by Nazgulled
    I have these 3 queries: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url FROM movies m WHERE m.mid = 1; SELECT AVG(rating) FROM movie_ratings WHERE mid = 1; SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1; And I need to join them into a single query. I was able to do it like this: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url, AVG(rating) average, COUNT(rating) count FROM movies m INNER JOIN movie_ratings mr ON m.mid = mr.mid WHERE m.mid = 1 GROUP BY title, year, MovieGenres(m.mid), MovieDirectors(m.mid), MovieWriters(m.mid), synopsis, poster_url; But I don't really like that "huge" GROUP BY, is there a simpler way to do it?

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  • LINQ count query returns a 1 instead of a 0

    - by user335810
    I have the following view:- CREATE VIEW tbl_adjudicator_result_view AS SELECT a.adjudicator_id, sar.section_adjudicator_role_id, s.section_id, sdr.section_dance_role_id, d.dance_id, c.contact_id, ro.round_id, r.result_id, c.title, c.first_name, c.last_name, d.name, r.value, ro.type FROM tbl_adjudicator a INNER JOIN tbl_section_adjudicator_role sar on sar.section_adjudicator_role2adjudicator = a.adjudicator_id INNER JOIN tbl_section s on sar.section_adjudicator_role2section = s.section_id INNER JOIN tbl_section_dance_role sdr on sdr.section_dance_role2section = s.section_id INNER JOIN tbl_dance d on sdr.section_dance_role2dance = d.dance_id INNER JOIN tbl_contact c on a.adjudicator2contact = c.contact_id INNER JOIN tbl_round ro on ro.round2section = s.section_id LEFT OUTER JOIN tbl_result r on r.result2adjudicator = a.adjudicator_id AND r.result2dance = d.dance_id When I run the following query directly against the db I get 0 in the count column where there is no result select adjudicator_id, first_name, COUNT(result_id) from tbl_adjudicator_result_view arv where arv.round_id = 16 group by adjudicator_id, first_name However when I use LINQ query I always get 1 in the Count Column var query = from arv in db.AdjudicatorResultViews where arv.round_id == id group arv by new { arv.adjudicator_id, arv.first_name} into grp select new AdjudicatorResultViewGroupedByDance { AdjudicatorId = grp.Key.adjudicator_id, FirstName = grp.Key.first_name, Count = grp.Select(p => p.result_id).Distinct().Count() }; What do I need to change in the View / Linq query.

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  • best way to add route under resource in Laravel 4

    - by passingby
    I would like know if there is a better way to add additional route aside from the default of resource in Laravel 4. I have this code below which is no problem with regard to the functionality, it's just that it seems to be long: <?php Route::group(array('before' => 'auth'), function() { # API Route::group(array('prefix' => 'api'), function() { Route::resource('projects', 'ProjectsController'); Route::resource('projects.groups', 'GroupsController'); Route::post('/projects/{projects}/groups/{groups}/reorder', 'GroupsController@reorder'); }); }); If in Rails Rails.application.routes.draw do # API namespace :api, defaults: { format: 'json' } do scope module: :v1 do resources :projects do resources :groups do member do post :reorder end end end end end end

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  • Page not rewriting in ExpressionEngine

    - by Andrew
    I recently just launched an ExpressionEngine site and one of the last steps I take is removing index.php from the URL. In the case of this site, the default template group is called "site". Long story short, after removing index.php from the URL, all pages continue to work great with the exception of my contact page, which also lives in the "site" template group. Going to http://example.com/contact/ gives me a 404 while going to http://example.com/site/contact produces the desired result. In past ExpressionEngine site setups (including my own) this has never happened, so does anyone have thoughts on why this might not be working?

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  • CTE Join query issues

    - by Lee_McIntosh
    Hi everyone, this problem has me head going round in circles at the moment and i wondering if anyone could give any pointers as to where im going wrong. Im trying to produce a SPROC that produces a dataset to be called by SSRS for graphs spanning the last 6 months. The data for example purposes uses three tables (theres more but the it wont change the issue at hand) and are as follows: tbl_ReportList: Report Site ---------------- North abc North def East bbb East ccc East ddd South poa South pob South poc South pod West xyz tbl_TicketsRaisedThisMonth: Date Site Type NoOfTickets --------------------------------------------------------- 2010-07-01 00:00:00.000 abc Support 101 2010-07-01 00:00:00.000 abc Complaint 21 2010-07-01 00:00:00.000 def Support 6 ... 2010-12-01 00:00:00.000 abc Support 93 2010-12-01 00:00:00.000 xyz Support 5 tbl_FeedBackRequests: Date Site NoOfFeedBackR ---------------------------------------------------------------- 2010-07-01 00:00:00.000 abc 101 2010-07-01 00:00:00.000 def 11 ... 2010-12-01 00:00:00.000 abc 63 2010-12-01 00:00:00.000 xyz 4 I'm using CTE's to simplify the code, which is as follows: DECLARE @ReportName VarChar(200) SET @ReportName = 'North'; WITH TicketsRaisedThisMonth AS ( SELECT [Date], Site, SUM(NoOfTickets) AS NoOfTickets FROM tbl_TicketsRaisedThisMonth WHERE [Date] >= DATEADD(mm, DATEDIFF(m,0,GETDATE())-6,0) GROUP BY [Date], Site ), FeedBackRequests AS ( SELECT [Date], Site, SUM(NoOfFeedBackR) AS NoOfFeedBackR FROM tbl_FeedBackRequests WHERE [Date] >= DATEADD(mm, DATEDIFF(m,0,GETDATE())-6,0) GROUP BY [Date], Site ), SELECT trtm.[Date] SUM(trtm.NoOfTickets) AS NoOfTickets, SUM(fbr.NoOfFeedBackR) AS NoOfFeedBackR, FROM Reports rpts LEFT OUTER JOIN TotalIncidentsDuringMonth trtm ON rpts.Site = trtm.Site LEFT OUTER JOIN LoggedComplaints fbr ON rpts.Site = fbr.Site WHERE rpts.report = @ReportName GROUP BY trtm.[Date] And the output when the sproc is pass a parameter such as 'North' to be as follows: Date NoOfTickets NoOfFeedBackR ----------------------------------------------------------------------------------- 2010-07-01 00:00:00.000 128 112 2010-08-01 00:00:00.000 <data for that month> <data for that month> 2010-09-01 00:00:00.000 <data for that month> <data for that month> 2010-10-01 00:00:00.000 <data for that month> <data for that month> 2010-11-01 00:00:00.000 <data for that month> <data for that month> 2010-12-01 00:00:00.000 122 63 The issue I'm having is that when i execute the query I'm given a repeated list of values of each month, such as 128 will repeat 6 times then another value for the next months value repeated 6 times, etc. argh!

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  • ResultSet and aggregation

    - by kachanov
    Ok, I admit my situation is special There is a data system that supports SQL-92 and JDBC interface However the SQL requets are pretty expensive, and in my application I need to retreive the same data multiple times and aggregate it ("group by") on different fields to show different dimensions of the same data. For example on one screen I have three tables that show the same set or records but aggregated by City (1st grid), by Population (2nd grid), by number of babies (3rd grid) This amounts to 3 SQL queries (which is very slow), UNLESS anyone of you can suggest any idea any library from apache commons or from google code, so that I can select all records into ResultSet and get 3 arrays of data group by different fields from this single ResultSet. Am I'm missing some obvious and unexpected solution to this problem?

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  • Confusion in RegExp Reluctant quantifier? Java

    - by Dusk
    Hi, Could anyone please tell me the reason of getting an output as: ab for the following RegExp code using Relcutant quantifier? Pattern p = Pattern.compile("abc*?"); Matcher m = p.matcher("abcfoo"); while(m.find()) System.out.println(m.group()); // ab and getting empty indices for the following code? Pattern p = Pattern.compile(".*?"); Matcher m = p.matcher("abcfoo"); while(m.find()) System.out.println(m.group());

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  • Conflicting ip routes with local table on attaching a virtual network interface

    - by user1071840
    I have an EC2 instance with these ip rules: $ sudo ip rule show 0: from all lookup local 32766: from all lookup main 32767: from all lookup default I can attach an elastic network interface to it with a private IP. Say the IP of my machine is 10.1.3.12 and the IP of the interface is 10.1.1.190. As soon as I attach the interface to my machine a new entry is added to the routing policy and local routing table: sudo ip rule show 0: from all lookup local 32765: from 10.1.1.190 lookup 10003 32766: from all lookup main 32767: from all lookup default $ sudo ip route show table local broadcast 10.1.1.0 dev eth3 proto kernel scope link src 10.1.1.190 local 10.1.1.190 dev eth3 proto kernel scope host src 10.1.1.190 broadcast 10.1.1.255 dev eth3 proto kernel scope link src 10.1.1.190 broadcast 10.1.3.0 dev eth0 proto kernel scope link src 10.1.3.12 local 10.1.3.12 dev eth0 proto kernel scope host src 10.1.3.12 broadcast 10.1.3.255 dev eth0 proto kernel scope link src 10.1.3.12 broadcast 127.0.0.0 dev lo proto kernel scope link src 127.0.0.1 local 127.0.0.0/8 dev lo proto kernel scope host src 127.0.0.1 local 127.0.0.1 dev lo proto kernel scope host src 127.0.0.1 broadcast 127.255.255.255 dev lo proto kernel scope link src 127.0.0.1 I can send traffic to this ENI directly from a host that can have the same IP as the host the ENI is attached to. This is where the problem starts. I ran tcpdump on the port in question and saw multiple SYNs going to the ENI with src '10.1.3.12' and destination '10.1.1.190' but didn't see even a single ACK. In my understanding if ACKs were being sent from the ENI they'd have destination as 10.1.3.12 i.e. the same as the local machine's IP and such packets will now be routed as local packets matching local routing policy: local 10.1.3.12 dev eth0 proto kernel scope host src 10.1.3.12 I'd like to send all the packets originating from 10.1.1.190 (my ENI) to go back on the same interface i.e. eth3 in this case. Contents of the nee table 10003 are: $ sudo ip route show table 10003 default via 10.1.1.1 dev eth3 I think I can do the following: I don't know if its possible but probably decrease the priority of local table so the packets match the table 10003. Use iptables to mangle these packets and update the local table route to include the mark information But I'm not sure if these are the right approaches.

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  • Drupal email users

    - by msindle
    I'm using Drupal 6.16: When a user creates an account on my site I have them select a category (ie children, youth, adult, etc). This is done with the select list box using the content_profile module. I have a content type that posts an announcement. In this content type is a check box that says 'email group'. Right now it does nothing, but what I would like for it to do is e-mail all the users that are associated with the group they chose when signing up for their account. If this will require extra code please be specific as I am not a strong php programmer. Thanks for the help!! msindle

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • Nested attributes form for model which belongs_to few models

    - by ExiRe
    I have few models - User, Teacher and TeacherLeader. class User < ActiveRecord::Base attr_accessible ..., :teacher_attributes has_one :teacher has_one :teacher_leader accepts_nested_attributes_for :teacher_leader end class Teacher < ActiveRecord::Base belongs_to :user has_one :teacher_leader end class TeacherLeader < ActiveRecord::Base belongs_to :user belongs_to :teacher end I would like to fill TeacherLeader via nested attributes. So, i do such things in controller: class TeacherLeadersController < ApplicationController ... def new @user = User.new @teacher_leader = @user.build_teacher_leader @teachers_collection = Teacher.all.collect do |t| [ "#{t.teacher_last_name} #{t.teacher_first_name} #{t.teacher_middle_name}", t.id ] end @choosen_teacher = @teachers_collection.first.last unless @teachers_collection.empty? end end And also have such view (new.html.erb): <%= form_for @user, :url => teacher_leaders_url, :html => {:class => "form-horizontal"} do |f| %> <%= field_set_tag do %> <% f.fields_for :teacher_leader do |tl| %> <div class="control-group"> <%= tl.label :teacher_id, "Teacher names", :class => "control-label" %> <div class="controls"> <%= select_tag( :teacher_id, options_for_select( @teachers_collection, @choosen_teacher )) %> </div> </div> <% end %> <div class="control-group"> <%= f.label :user_login, "Login", :class => "control-label" %> <div class="controls"> <%= f.text_field :user_login, :placeholder => @everpresent_field_placeholder %> </div> </div> <div class="control-group"> <%= f.label :password, "Pass", :class => "control-label" %> <div class="controls"> <%= f.text_field :password, :placeholder => @everpresent_field_placeholder %> </div> </div> <% end %> <%= f.submit "Create", :class => "btn btn-large btn-success" %> <% end %> Problem is that select form here does NOT appear. Why? Do i do something wrong?

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  • A linq join combined with a regex

    - by Geert Beckx
    Is it possible to combine these 2 queries or would this make my code too complex? Also I think there should be a performance gain by combining these queries since I think in the near future my source table could be over 11000 records. This is what i came up with so far : Dim lit As LiteralControl ' check characters not in alphabet Dim r As New Regex("^[^a-zA-Z]+") Dim query = From o In source.ToTable _ Where r.IsMatch(o.Field(Of String)("nam")) lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", "0-9", query.Count)) plhAlpabetLinks.Controls.Add(lit) Dim q = From l In "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToLower.ToCharArray _ Group Join o In source.ToTable _ On l Equals o.Field(Of String)("nam").ToLowerInvariant(0) Into g = Group _ Select l, g.Count ' iterate the alphabet to generate all the links. For Each letter In q.AsEnumerable lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", letter.l, letter.Count)) plhAlpabetLinks.Controls.Add(lit) Next Kind regards, G.

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  • SPF blocking some emails. How to complete disable it?

    - by Rafael Colucci
    We have configured a SMTP server on IIS. We have not configured any SPF rule. Some emails are going straight to the badmail folder. Most of them have this error message: Address does not pass the Sender Policy Framework Is there any way to disable that? I know this is insecure and spammers could use it to send spam, but I really need it to be disabled for now until I have configured and tested the SPF correctly.

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  • PHP is_file returns false (incorrectly) for Windows share on Ubuntu

    - by M3Mania
    Ubuntu server, PHP 5.3, connected via Samba to Windows server share. I am using file_exists() to check for availability of file on Windows machine. It returns false, although the filepath does exist. Meanwhile, file_get_contents() on the exact same filepath works fine. I'm wondering if it's a permission issue, since I'm having trouble configuring permissions of the files on the Windows share (it says I don't have permission to change permissions on them). When I look at the permissions through Nautilus, it says the user and group are both root, with 755 rights. I'd like to change the group to www-data, but can't seem to do it.

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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  • Are there any solutions for translating measurement units on Rails?

    - by Leonid Shevtsov
    I'd like to implement measurement unit preferences in a Ruby on Rails app. For instance, the user should be able to select between displaying distances in miles or in kilometers. And, obviously, not only displaying, but entering values, too. I suppose all values should be stored in one global measurement system to simplify calculations. Are there any drop-in solutions for this? Or should I maybe write my own?

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