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  • Apache Rewrite Excluding Assets Directory

    - by Midiane
    Hi all I'm writing a mini-MVC application. App architecture: actions/ templates/ site/ app/ styles/ images/ scripts/ So far, I've got a controller working properly, taking in all requests. However, javascript files are not being rendered properly in the browser; I'm getting a 404 Not Found when I try to load the file in the browser. Here is my current Directory config in a vhost file: DirectoryIndex index.php RewriteEngine On RewriteBase /apps/ecatalogue RewriteRule ^scripts/(.*) - [NC,L] <--- Rule not working RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php [NC,L,QSA] I can confirm everything else works; I just need apache to ignore anything in scripts so the file can be loaded normally without being processed by the controller. Your help is appreciated.

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  • Persistence scheme & state data for low memory situations (iphone)

    - by Robin Jamieson
    What happens to state information held by a class's variable after coming back from a low memory situation? I know that views will get unloaded and then reloaded later but what about some ancillary classes & data held in them that's used by the controller that launched the view? Sample scenario in question: @interface MyCustomController: UIViewController { ServiceAuthenticator *authenticator; } -(id)initWithAuthenticator:(ServiceAuthenticator *)auth; // the user may press a button that will cause the authenticator // to post some data to the service. -(IBAction)doStuffButtonPressed:(id)sender; @end @interface ServiceAuthenticator { BOOL hasValidCredentials; // YES if user's credentials have been validated NSString *username; NSString *password; // password is not stored in plain text } -(id)initWithUserCredentials:(NSString *)username password:(NSString *)aPassword; -(void)postData:(NSString *)data; @end The app delegate creates the ServiceAuthenticator class with some user data (read from plist file) and the class logs the user with the remote service. inside MyAppDelegate's applicationDidFinishLaunching: - (void)applicationDidFinishLaunching:(UIApplication *)application { ServiceAuthenticator *auth = [[ServiceAuthenticator alloc] initWithUserCredentials:username password:userPassword]; MyCustomController *controller = [[MyCustomController alloc] initWithNibName:...]; controller.authenticator = auth; // Configure and show the window [window addSubview:..]; // make everything visible [window makeKeyAndVisible]; } Then whenever the user presses a certain button, 'MyCustomController's doStuffButtonPressed' is invoked. -(IBAction)doStuffButtonPressed:(id)sender { [authenticator postData:someDataFromSender]; } The authenticator in-turn checks to if the user is logged in (BOOL variable indicates login state) and if so, exchanges data with the remote service. The ServiceAuthenticator is the kind of class that validates the user's credentials only once and all subsequent calls to the object will be to postData. Once a low memory scenario occurs and the associated nib & MyCustomController will get unloaded -- when it's reloaded, what's the process for resetting up the 'ServiceAuthenticator' class & its former state? I'm periodically persisting all of the data in my actual model classes. Should I consider also persisting the state data in these utility style classes? Is that the pattern to follow?

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • Joomla forwarding code to the View...is this the correct way to do it?

    - by jax
    Here are some sample methods from my Controller class. Now when the user clicks the New button $task=add is sent to the Controller and the add() method is called. As you can see it does not really do anything, it just creates a url and forwards it off to the correct view. Is this the correct way of doing things in the MVC pattern? /** * New button was pressed */ function add() { $link = JRoute::_('index.php?option=com_myapp&c=apps&view=editapp&cid[]=', false); $this->setRedirect($link); } /** * Edit button was pressed - just use the first selection for editing */ function edit() { $cid = JRequest::getVar( 'cid', array(0), '', 'array' ); $id = $cid[0]; $link = JRoute::_("index.php?option=com_myapp&c=apps&view=editapp&cid[]=$id", false); $this->setRedirect($link); }

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  • How do you manage web navigation info in your application?

    - by Dave
    I’m building an application where different users will have different menu items available to them depending on what they’ve paid for. There will also be multiple levels to the menu hierarchy. What’s the best approach to this problem? I’m assuming I need a database table that represents the menu hierarchy, including the parent-child relationships of the nodes in the navigation as well as the sorting of the items. Then another table which I use to manage whether a user is authorized to access a particular item in that table. When I render the view, I’d reference the menus, and the access rights of the user to output the menu, and I’d also need a function to check that same authorization from each controller in case a user manually types in a URL of a controller they’re not supposed to have access to. Is this the right approach? Any suggestions for caching this to prevent the constant look-ups of this type of info? I’m open to any suggestions on how you may have approached this type of requirement.

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  • Does anybody have practice in programming PCMEF - architectures?

    - by Erkki
    PCMEF is an architecture style presented in the book Practical Software Engineering by Maciaszek and Liong. The layers are: P: Presentation C: Controller M: Mediator E: Entity F: Foundation. It is some kind of enchancement compared with MVC - architecture. I recommend it to interactice, data and communicating - oriented purposes. I have programmed it using Visual Prolog. Foundation in my applications is the data model (domains) for the application. PCMEF is like a simulated computer: Presentation is the display, Controller the user interface and event handling, Mediator the internal logic and data highway. Entity is the database or external interfaces and F defines the knowledge. This is a really nice small architecture. Does any other have experiance of it?

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  • why is link generated in YUI javascript failing to render in rails?

    - by pmneve
    Using YAHOO.widget.treeview to generate a table with three levels of data: module, submodule, and detail. If there is an image associated with a detail row the javascript generates a link: "<td><a href=\"/screenshot/show/" + rowData.id + "\">Screenshot</a></td>" that is appended to the html for the row. The url is generated correctly and the link appears. When clicked nothing happens except the word 'Done' appears in the browser status bar. Am calling the very same url from another page that does not use javascript and the screenshot page appears as expected. Here is the controller. class ScreenshotController < ApplicationController def show if @detail.screen_path.length 1 @imagePath = "#{RAILS_ROOT}" + "/private/#{Company.find(@detail.company_id).subdir}/" + "#{Project.find(@detail.project_id).subdir}/screenshot/" + "#{@detail.screen_path}" send_file ( @imagePath, :type = 'image/jpeg', :disposition = 'inline') end end end A sample url: http://localhost:3004/screenshot/show/20854 This code from show.html.erb belonging to the detail model works: <%= link_to 'View', :controller = 'screenshot', :id = @detail.id, :action = 'show' % Any ideas???

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  • Show a modal right after signup?

    - by user1494756
    When a user signup at my page I want them to be redirected to the root_path(this I have figured out how to do in the user controller). But then I want a modal to show in front of this page(and this should only happen the first time the user see this root/home page(like a flash message). Here is my create method in the user controller: def create @user = User.new(params[:user]) if @user.save sign_in @user redirect_to root_path else render 'new' end end The modal is placed in app/views/layouts/_modal.html.erb. Does anybody know how to make this happen? (Jepp, I am a newbie :)

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  • Teacher confused about MVC?

    - by Gideon
    I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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  • Confused about technique to use to submit form

    - by user281180
    I have created a view in which i`m using clientsidevalidation. The jquery has a textbox , a table and a submit button. The table is empty at the beginning. Using jquery I populate the table with 2 columns ID and Name. I send the values to the controller using the submit button. My question are as follows: How do I send the values of the texbox and the table to the controller? Any guide please.

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  • Searching in Rails 3

    - by cbarton
    Here is the situation: I have the need to search for specifics or generals, much like expedia.com or your local library catalog search. In that there are fields that may or may not be filled out based on the individual need. It acts much like an "advanced search page". I have all of that code done for the models/controller and such and have it setup with a Searches controller along with matching model and views. The question that I have is there a way to cut down the amount of parameters posted to GET so that the url isn't search?search[:a]=""+search[:b]=""+search[:c]="x"... plus the unicode checkmark. I only want the filled out fields to be shown in the response link especially minus the checkmark. cbarton

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  • How do you submit a rails 3 form without refreshing the page?

    - by Anthony H
    I've seen this done using ajax & php, but not rails 3. I've tried using: <%= form_for(:technician, :url => {:controller => 'pos', :action => 'create_ticket'}, :remote => true) do |f| %> but the page still refreshes each time. I'm building a point of sale program, so I don't want the page to refresh. How do I send the form data to the controller to process and store in the database without refreshing?

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  • What's a good place to unregister an observer from the notification center?

    - by mystify
    When I add an observer to the default notification center, where would I unregister that? Example: I have a UIView subclass which lives inside a view controller. That subclass is an observer for the FooBarNotification. If this notification is posted, that view will get it. But now, the view controller decides to throw away the view. Is the best place the -dealloc method of the view itself? Are there any rules like memory management rules? For example: Must I unregister an observer where I registered it? i.e. the view registers itself in it's init method, so it should unregister itself in it's -dealloc method? (not talking about push notifications, but NSNotificationCenter)

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  • How to update content of one ArrayController from the selected value of another ArrayController in Ember.js

    - by CodeHugger
    I have the following problem in ember.js. A child controller depends on a selected value in a parent controller in order to determine its content. In the database a child has a parent_id reference. App.parentsController = Em.ArrayController.create({ content: [], selected: null }); App.sonsController = Em.ArrayController.create({ // the value of content depends on the id of // the selected item in the parentsController content: [], selected: null }); App.daughtersController = Em.ArrayController.create({ // the value of content depends on the id of // the selected item in the parentsController content: [], selected: null }); I would prefer to solve this without the parentsController having to know anything about the other controllers. This should be possible with observers, bindings or even through calculations but I have no clue where to start. Any help would be well appreciated.

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  • Inconsistent Routing Results in MVC

    - by HapiDjus
    Seems I'm still missing something to the MVC routing concept. I have a route that follows nearly the same pattern as another route in an area but for what ever reason I get a 404 every time I attempt to run it. I've tried to use Phil Haack's Route Tester DLL and according to that it hits the correct route (matched route comes out to common/itemhistory/{contentid}). When I try to run it for real, it blows up. I'm trying to map a call to a JsonResult by passing a Guid. I've had success with other routes working fine (common is an area in my site). What could I be doing wrong? context.MapRoute( "ItemHistory", "common/itemhistory/{contentid}", new { controller = "common", action = "GetItemHistory" }, new { contentid = @"^(\{){0,1}[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}(\}){0,1}$" } ); context.MapRoute( "Common_default", "common/{action}", new { controller="common", action = "Index" } );

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  • User-customizable rails authorization

    - by neutrino
    Hello everyone, Seems there is an abundance of popular declarative-style authorization plugins, which allow you to somehow state in the code that, e.g., this controller action can be accessed by users with such-and-such roles. But what if I need a more dynamic scheme. I want to have an admin area, with a list of all authorizable actions and an ability to assign permissions on actions from the UI. I have ideas how to implement it from scratch, like to define a model corresponding to a controller and/or action and store the permissions via normal associations. Just wonder if there are any ready solutions to this. Thanks a lot

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  • Trouble using xib files in libraries

    - by flohei
    Hi there, I'm having some trouble working with libraries and included xib files. Let me explain my situation first. I've got a project that's running pretty good. Now I need a part of my project as a library for another customer who want's to use some of the functionality in his app. I've created a library with help of that highly recommended article. My customer should be able to initialize a main view controller like this: LibraryMainViewController *lmvc = [[LibraryMainViewController alloc] initWithNibName:@"LibraryMainViewController.xib" bundle:foo]; That for sure leads to an error when I try to present that view controller modally. I'm not sure what bundle I have to use here. I tried something like [NSBundle bundleForClass:[SomeClassInTheLibrary class]]; but that didn't solve the problem. I would be glad if someone could tell me how to actually use a xib file in that kind of situation. Thanks –f

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  • I am having trouble with my first project in ruby on rails

    - by Sebastian
    Here's my index action in the books controller: http://pastebin.com/XdtGRQKV Here's the view for the action i just mentioned: http://pastebin.com/nQFy400m Here's the result without being logged in: http://i.imgur.com/rQoiw.jpg Here's the result when i'm logged in with the user 'admin': http://i.imgur.com/E1CUr.jpg So the problem is that, in the view, before line 25 the 'user' variable seems to be empty ( or not loaded), and after line 25 the variable 'user' has the expected values. I have tried initializing a variable in the index method of the books controller but get exactly the same results. Thanks in advance! BTW had to make the links text because of stackoverflow limit.

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  • asp.net mvc 2 multiple partial view

    - by 303
    Hey Guys, I have a contoller that renders 3 different views. But I also have a common part (div) for every view. I thought that I can create an UserControl with own controller and include that control on my views (New controller and view as controll). How should I use that UserControl? Should it be a partial view? Or different approach - can I have multiple partial views on one page? I've been searching the web for the last view days and haven't found working solution that suits me. Also I want to use Strongly Typed views/data. Cheers

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  • How do you render a rails partial that is outside of a namespace in a view that is inside of a namespace?

    - by iand675
    I've got a 'static' controller and static views that are pages that don't utilize ruby in their views. For these pages, I have a sitemap partial that is generated programatically and used in the application layout file. Namespaced routes still use the application layout file but are taking the static routes and trying to namespace them too. Here's the relevant portion of the route file: namespace :admin do resources :verse_categories resources :verses resources :songs resources :flowers resources :visits, :except => [:new, :create] end match ':action' => 'static' root :to => 'static#home' Here's the error I'm getting: No route matches {:controller=>"admin/static", :action=>"about"} Note that about is one of the static pages that the sitemap partial uses. So, how can I resolve this routing issue so that it's not trying to find my static sites inside of the admin namespace? Any help would be appreciated!

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  • Rails 3 Routing help

    - by Rod Nelson
    OK i'm new to rails 3 and the new routing is driving me mad. I just a good example i was looking at the info on http://rizwanreza.com/2009/12/20/revamped-routes-in-rails-3 but it don't make sense to me. i need an example please! I have my root down that's not hard. I have Site as my controller and i have index help and about then i have a second controller users with index and register on the register page i have 3 text boxes and a submit when i hit submit i get Routing Error No route matches "/user/register" if you need me to i will post my routes file

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • Best Design Pattern to Implement while Mapping Actions in MVC

    - by FidEliO
    What could be the best practices of writing the following case: We have a controller which based on what paths users take, take different actions. For example: if user chooses the path /path1/hello it will say hello. If a user chooses /path1/bye?name="Philipp" it will invoke sayGoodBye() and etc. I have written a switch statement inside the controller which is simple, however IMO not efficient. What are the best way to implement this, considering that paths are generally String. private void takeAction() { switch (path[1]) { case "hello": //sayHello(); break; case "bye": //sayBye(); break; case "case3": //Blah(); break; ... } }

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  • Symfony2 same form, different entities NOT related

    - by user1381537
    I'm trying to write one form for submitting against MySQL DB, but I can't get it working, I've tried a lot of things (separate forms, create an ->add('foo', new foo()) to a field, and trying to parse plain SQL with a normal HTML form is my only solution, which is obviously not the best. This is my DB structure: As you can see I need to insert the comments textarea to ticketcomments among the user who wrote it, etc. On crmentity the description field. Then on ticketcf the fields that I need to submit from form, are this (because you wont know if I don't tell you because of the field names): tcf.cf594 AS Type, tcf.cf675 AS Suscription, tcf.cf770 AS ID_PRODUCT, tcf.cf746 AS NotificationDate, tcf.cf747 AS ResponseDate, tcf.cf748 AS ResolutionDate, And, of course, every table needs to have the same ticketid id for the submitted form, so we can retrieve it with one simple query. It will be easy to do with plain SQL instead of using DQL and Symfony2 forms, but is not a good way to do it. Also, here's my "Ticket list" query, if you need it to have it more clear... SELECT t.ticketNo AS Ticket, t.title AS Asunto, t.status AS Estado, t.updateLog AS LOG, t.hours AS Horas, t.solution AS Solucion, t.priority AS Prioridad, tcf.cf594 AS Tipo, tcf.cf675 AS Suscripcion, tcf.cf770 AS IDPROD, tcf.cf746 AS F_Noti, tcf.cf747 AS F_Resp, tcf.cf748 AS F_Reso, CONCAT (cd.firstname, cd.lastname) AS Contacto, crm.description AS Descripcion, crm.crmid AS id FROM WbsGoclientsBundle:VtigerTroubletickets t INNER JOIN WbsGoclientsBundle:VtigerTicketcf tcf WITH t.ticketid = tcf.ticketid INNER JOIN WbsGoclientsBundle:VtigerContactdetails cd WITH t.parentId = cd.contactid INNER JOIN WbsGoclientsBundle:VtigerCrmentity crm WITH t.ticketid = crm.crmid WHERE t.parentId IN ( SELECT cd1.contactid FROM WbsGoclientsBundle:VtigerContactdetails cd1 WHERE cd1.accountid = ( SELECT cd2.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd2 WHERE cd2.contactid = :contactid)) AND t.status <> \'Closed\' And also "Ticket details" query (which is not in DQL format yet, only SQL) is so simple, it only retrieve the comments field and createdtime from ticketcomments appended to this query so we have all the fields... Thank you. This is a test form, using troubletickets and ticketcomments, it's returning errores because I can't set a comments field because troubletickets doesn't has it, but I need that field to be submitted to ticketcomments ... VtigerTicketcommentsType <?php namespace WbsGo\clientsBundle\Form\Type; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class VtigerTicketcommentsType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('ticketid') ->add('comments') ->add('ownerid') ->add('ownertype') ->add('createdtype') ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTicketcomments' )); } public function getName() { return 'comments'; } } OpenTicketType.php <?php namespace WbsGo\clientsBundle\Form; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface ; use WbsGo\clientsBundle\Form\Type\VtigerTicketcommentsType; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class OpenTicketType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('title') ->add('priority') ->add('solution') ->add('comments', 'collection', array( 'type' => new VtigerTicketcommentsType() )) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTroubletickets' )); } public function getName() { return 'ticket'; } } TicketController.php <?php namespace WbsGo\clientsBundle\Controller; use Symfony\Bundle\FrameworkBundle\Controller\Controller; use WbsGo\clientsBundle\Entity\VtigerTroubletickets; use WbsGo\clientsBundle\Entity\VtigerTicketcomments; use WbsGo\clientsBundle\Form\OpenTicketType; use Symfony\Component\HttpFoundation\Request; class TicketController extends Controller { public function indexAction() { $em = $this->getDoctrine()->getManager(); $tickets = $em ->getRepository('WbsGoclientsBundle:VtigerTroubletickets') ->findAllOpenByCustomerId($this->getUser()->getId()); $userdata = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerContactdetails') ->findContact($this->getUser()->getId()); return $this ->render('WbsGoclientsBundle:Ticket:index.html.twig', array('tickets' => $tickets, 'userdata' => $userdata)); } public function addAction() { $assets = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerAssets') ->findAssetByAccountId($this->getUser()->getId()); $assetlist = array(); foreach ($assets as $key => $v) { $assetlist[$key] = $key; } $form = $this->createForm(new OpenTicketType(), new VtigerTroubletickets()); return $this ->render('WbsGoclientsBundle:Ticket:add.html.twig', array('form' => $form->createView(), 'assets' => $assets,)); } } This is the error Symfony2 is returning Neither the property "comments" nor one of the methods "getComments()", "isComments()", "hasComments()", "_get()" or "_call()" exist and have public access in class "WbsGo\clientsBundle\Entity\VtigerTroubletickets". EDIT 2 This code is actually rendering my forms, but I need help in order to submit each XXXType form to its corresponding table. public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('descripcion') ->add('prioridad') ->add('solucion') ->add('comment', new VtigerTicketcommentsType() ) ->add('contacto') ->add('suscripcion') ->add('producto', 'entity', array( 'class' => 'WbsGo\clientsBundle\Entity\VtigerAssets', 'property' => 'assetname', 'empty_value' => '--SELECT--', 'query_builder' => function(\WbsGo\clientsBundle\Entity\VtigerAssetsRepository $repository) { //return $repository->findAssetByAccountId($this->customerId); return $repository->createQueryBuilder('a') ->select('a') ->where('a.account = (SELECT cd.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd WHERE cd.contactid = ?1)') ->setParameter(1, $this->customerId); } ) ) ->add('hardware') ->add('backup') ->add('web') ->add('restore') ->add('customerId') ; } I also removed ->add('ticketid') from VtigerTicketcommentsType.php because it has relationship and is not needed. it's auto_incremental and must be generated once everything is submitted.

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  • How to change the view if I am not present in the viewController class?

    - by wolverine
    I am doing an app with about 6-7 views and their corresponding controllers. I am in a view with a toolbar and button. When I click this button a popup view comes and my control is being moved to the popup view's Controller. But my view is still the same. From this popupview Controller's class, I want to change my original view. But since I am not in my original viewControllers class, I am not able to change it. How can I overcome this? Can anyone plz help me?

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