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  • How do you manage web navigation info in your application?

    - by Dave
    I’m building an application where different users will have different menu items available to them depending on what they’ve paid for. There will also be multiple levels to the menu hierarchy. What’s the best approach to this problem? I’m assuming I need a database table that represents the menu hierarchy, including the parent-child relationships of the nodes in the navigation as well as the sorting of the items. Then another table which I use to manage whether a user is authorized to access a particular item in that table. When I render the view, I’d reference the menus, and the access rights of the user to output the menu, and I’d also need a function to check that same authorization from each controller in case a user manually types in a URL of a controller they’re not supposed to have access to. Is this the right approach? Any suggestions for caching this to prevent the constant look-ups of this type of info? I’m open to any suggestions on how you may have approached this type of requirement.

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  • Flex 4 itemRendererFunction problem.

    - by michael
    This is a Flex 4 application: I have created a list as the following: <s:List id="previewList" horizontalCenter="14" verticalCenter="-112" itemRendererFunction="listItemRendererFunction" click="controller.previewListClickHandler()"> </s:List> And I have the itemRendererFunction: public function listItemRendererFunction(item:Object):ClassFactory { var cla:Class = SimpleItemRenderer; if( item.save == true ) { cla = ColorItemRenderer; } else { cla = SimpleItemRenderer; } return new ClassFactory(cla); } The application works fine if the listItemRendererFunction is inside fx:Script. However, when I put the listItemRendererFunction into a class and change to the following: itemRendererFunction="controller.listItemRendererFunction" in the List component. If I run the application, I get the " Error #1009". Please advice how to fix it.

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  • Devise role based routing

    - by teknull
    I have an app with multiple users. Each user as a theoretical role (user, client, etc). I've designed a view/controller for each user type. I want to be able to login each type of user do a different root url and lock them to it. Originally I was going to add a column to Users in Devise called role and so I can differentiate the users. The problem I'm having is how to say in routes.rb if current_user.role == "client" root :to = 'controller#index' Once they are logged in to the page I also want to keep them from being able to visit any of my other paths ie: domain.com/calls domain.com/units I've been looking into cancan to run alongside Devise but I'm not sure if this is the answer.

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  • Show a modal right after signup?

    - by user1494756
    When a user signup at my page I want them to be redirected to the root_path(this I have figured out how to do in the user controller). But then I want a modal to show in front of this page(and this should only happen the first time the user see this root/home page(like a flash message). Here is my create method in the user controller: def create @user = User.new(params[:user]) if @user.save sign_in @user redirect_to root_path else render 'new' end end The modal is placed in app/views/layouts/_modal.html.erb. Does anybody know how to make this happen? (Jepp, I am a newbie :)

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  • asp.net mvc 2 multiple partial view

    - by 303
    Hey Guys, I have a contoller that renders 3 different views. But I also have a common part (div) for every view. I thought that I can create an UserControl with own controller and include that control on my views (New controller and view as controll). How should I use that UserControl? Should it be a partial view? Or different approach - can I have multiple partial views on one page? I've been searching the web for the last view days and haven't found working solution that suits me. Also I want to use Strongly Typed views/data. Cheers

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  • What are the differences between MVP, Presentation Model, MVVM and MVC?

    - by Nicholas
    I have a pretty good idea how each of these patterns work some of the minor differences between them, but are they really all that different from each other? It seems to me that the Presenter, Presentation Model, ViewModel and Controller are essentially the same concept. Why couldn't I classify all of these concepts as controllers? I feel like it might simplify the entire idea a great deal. Can anyone give a clear description of their differences? I want to clarify that I do understand how the patterns work, and have implemented most of them in one technology or another. What I am really looking for is someone's experience with one of these patterns, and why they would not consider their ViewModel a controller for instance.

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  • Confused about technique to use to submit form

    - by user281180
    I have created a view in which i`m using clientsidevalidation. The jquery has a textbox , a table and a submit button. The table is empty at the beginning. Using jquery I populate the table with 2 columns ID and Name. I send the values to the controller using the submit button. My question are as follows: How do I send the values of the texbox and the table to the controller? Any guide please.

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  • Rendering Views as String with Spring MVC and Apache Tiles

    - by lynxforest
    I am trying to reuse some of my tiles in a controller which is returning a json response to the client. I would like to return a json response similar to the following format: { 'success': <true or false>, 'response': <the contents of an apache tile> } In my controller I would like to perform logic similar to this pseudocode: boolean valid = validator.validate(modelObj) String response = "" if(valid){ response = successView.render() // im looking for a way to actually accomplish // this, where the successView is the apache tiles view. // I would also need to pass a model map to the view somehow. }else{ response = errorView.render() } writeJsonResponse(httpResponse, /* a Map whose json representation looks like the one I described above. */)

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  • Searching in Rails 3

    - by cbarton
    Here is the situation: I have the need to search for specifics or generals, much like expedia.com or your local library catalog search. In that there are fields that may or may not be filled out based on the individual need. It acts much like an "advanced search page". I have all of that code done for the models/controller and such and have it setup with a Searches controller along with matching model and views. The question that I have is there a way to cut down the amount of parameters posted to GET so that the url isn't search?search[:a]=""+search[:b]=""+search[:c]="x"... plus the unicode checkmark. I only want the filled out fields to be shown in the response link especially minus the checkmark. cbarton

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  • Play 2.0 javaToDo tutorial doesn't compile

    - by chsn
    I'm trying to follow the Play2.0 JavaToDO tutorial and for some reason it just doesn't want to work. Have looked through stackoverflow and other online resources, but haven't find an answer to this and it's driving me crazy. Attached code of the Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { static Form<Task> taskForm = form(Task.class); public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result newTask() { return TODO; } public static Result deleteTask(Long id) { return TODO; } } Attached code of the Task java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task { public Long id; @Required public String label; // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create task public static void create(Task task) { task.create(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } // create new task public static Result newTask() { Form<Task> filledForm = taskForm.bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.create(filledForm.get()); return redirect(routes.Application.tasks()); } } } I get a compile error on Task.java on the line static Form<Task> taskForm = form(Task.class); As I'm working on eclipse (the project is eclipsified before import), it's telling me that taskForm cannot be resolved and it also underlines every play 2 command e.g. "render(), redirect(), bindFromRequest()" asking me to create a method for it. Any ideas how to solve the compilations error and also how to get Eclipse to recognize the play2 commands? EDIT: updated Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { // create new task public static Result newTask() { Form<Task> filledForm = form(Task.class).bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.newTask(filledForm.get()); return redirect(routes.Application.tasks()); } } public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result deleteTask(Long id) { return TODO; } } Updated task.java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task extends Model { public Long id; @Required public String label; // Define a taskForm static Form<Task> taskForm = form(Task.class); // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create new task public static Result newTask(Task newTask) { save(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } }

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  • How to change the view if I am not present in the viewController class?

    - by wolverine
    I am doing an app with about 6-7 views and their corresponding controllers. I am in a view with a toolbar and button. When I click this button a popup view comes and my control is being moved to the popup view's Controller. But my view is still the same. From this popupview Controller's class, I want to change my original view. But since I am not in my original viewControllers class, I am not able to change it. How can I overcome this? Can anyone plz help me?

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  • Symfony2 same form, different entities NOT related

    - by user1381537
    I'm trying to write one form for submitting against MySQL DB, but I can't get it working, I've tried a lot of things (separate forms, create an ->add('foo', new foo()) to a field, and trying to parse plain SQL with a normal HTML form is my only solution, which is obviously not the best. This is my DB structure: As you can see I need to insert the comments textarea to ticketcomments among the user who wrote it, etc. On crmentity the description field. Then on ticketcf the fields that I need to submit from form, are this (because you wont know if I don't tell you because of the field names): tcf.cf594 AS Type, tcf.cf675 AS Suscription, tcf.cf770 AS ID_PRODUCT, tcf.cf746 AS NotificationDate, tcf.cf747 AS ResponseDate, tcf.cf748 AS ResolutionDate, And, of course, every table needs to have the same ticketid id for the submitted form, so we can retrieve it with one simple query. It will be easy to do with plain SQL instead of using DQL and Symfony2 forms, but is not a good way to do it. Also, here's my "Ticket list" query, if you need it to have it more clear... SELECT t.ticketNo AS Ticket, t.title AS Asunto, t.status AS Estado, t.updateLog AS LOG, t.hours AS Horas, t.solution AS Solucion, t.priority AS Prioridad, tcf.cf594 AS Tipo, tcf.cf675 AS Suscripcion, tcf.cf770 AS IDPROD, tcf.cf746 AS F_Noti, tcf.cf747 AS F_Resp, tcf.cf748 AS F_Reso, CONCAT (cd.firstname, cd.lastname) AS Contacto, crm.description AS Descripcion, crm.crmid AS id FROM WbsGoclientsBundle:VtigerTroubletickets t INNER JOIN WbsGoclientsBundle:VtigerTicketcf tcf WITH t.ticketid = tcf.ticketid INNER JOIN WbsGoclientsBundle:VtigerContactdetails cd WITH t.parentId = cd.contactid INNER JOIN WbsGoclientsBundle:VtigerCrmentity crm WITH t.ticketid = crm.crmid WHERE t.parentId IN ( SELECT cd1.contactid FROM WbsGoclientsBundle:VtigerContactdetails cd1 WHERE cd1.accountid = ( SELECT cd2.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd2 WHERE cd2.contactid = :contactid)) AND t.status <> \'Closed\' And also "Ticket details" query (which is not in DQL format yet, only SQL) is so simple, it only retrieve the comments field and createdtime from ticketcomments appended to this query so we have all the fields... Thank you. This is a test form, using troubletickets and ticketcomments, it's returning errores because I can't set a comments field because troubletickets doesn't has it, but I need that field to be submitted to ticketcomments ... VtigerTicketcommentsType <?php namespace WbsGo\clientsBundle\Form\Type; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class VtigerTicketcommentsType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('ticketid') ->add('comments') ->add('ownerid') ->add('ownertype') ->add('createdtype') ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTicketcomments' )); } public function getName() { return 'comments'; } } OpenTicketType.php <?php namespace WbsGo\clientsBundle\Form; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface ; use WbsGo\clientsBundle\Form\Type\VtigerTicketcommentsType; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class OpenTicketType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('title') ->add('priority') ->add('solution') ->add('comments', 'collection', array( 'type' => new VtigerTicketcommentsType() )) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTroubletickets' )); } public function getName() { return 'ticket'; } } TicketController.php <?php namespace WbsGo\clientsBundle\Controller; use Symfony\Bundle\FrameworkBundle\Controller\Controller; use WbsGo\clientsBundle\Entity\VtigerTroubletickets; use WbsGo\clientsBundle\Entity\VtigerTicketcomments; use WbsGo\clientsBundle\Form\OpenTicketType; use Symfony\Component\HttpFoundation\Request; class TicketController extends Controller { public function indexAction() { $em = $this->getDoctrine()->getManager(); $tickets = $em ->getRepository('WbsGoclientsBundle:VtigerTroubletickets') ->findAllOpenByCustomerId($this->getUser()->getId()); $userdata = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerContactdetails') ->findContact($this->getUser()->getId()); return $this ->render('WbsGoclientsBundle:Ticket:index.html.twig', array('tickets' => $tickets, 'userdata' => $userdata)); } public function addAction() { $assets = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerAssets') ->findAssetByAccountId($this->getUser()->getId()); $assetlist = array(); foreach ($assets as $key => $v) { $assetlist[$key] = $key; } $form = $this->createForm(new OpenTicketType(), new VtigerTroubletickets()); return $this ->render('WbsGoclientsBundle:Ticket:add.html.twig', array('form' => $form->createView(), 'assets' => $assets,)); } } This is the error Symfony2 is returning Neither the property "comments" nor one of the methods "getComments()", "isComments()", "hasComments()", "_get()" or "_call()" exist and have public access in class "WbsGo\clientsBundle\Entity\VtigerTroubletickets". EDIT 2 This code is actually rendering my forms, but I need help in order to submit each XXXType form to its corresponding table. public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('descripcion') ->add('prioridad') ->add('solucion') ->add('comment', new VtigerTicketcommentsType() ) ->add('contacto') ->add('suscripcion') ->add('producto', 'entity', array( 'class' => 'WbsGo\clientsBundle\Entity\VtigerAssets', 'property' => 'assetname', 'empty_value' => '--SELECT--', 'query_builder' => function(\WbsGo\clientsBundle\Entity\VtigerAssetsRepository $repository) { //return $repository->findAssetByAccountId($this->customerId); return $repository->createQueryBuilder('a') ->select('a') ->where('a.account = (SELECT cd.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd WHERE cd.contactid = ?1)') ->setParameter(1, $this->customerId); } ) ) ->add('hardware') ->add('backup') ->add('web') ->add('restore') ->add('customerId') ; } I also removed ->add('ticketid') from VtigerTicketcommentsType.php because it has relationship and is not needed. it's auto_incremental and must be generated once everything is submitted.

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  • Subprocess with variables & Command from different class

    - by Pastelinux
    source: http://pastebin.com/utL7Ebeq My thinking is that if i run from controller class "main" it will allow me to take the "data" from Class "model", def "filename". It doesn't seem to work. As you can see below what i mean class Controller: def __init__(self): self.model = Model() self.view = View() def main(self): data = self.model.filename() self.view.tcpdump(data) class View: def tcpdump(self, command): subprocess.call(command.split(), shell=False) When i run my code i get this error: subprocess.call(command.split(), shell=False) AttributeError: 'NoneType' object has no attribute 'split' My guess means that its not picking up command (look at source for reference) or that its not getting command with variables. But i know the error when variables are not being picked up so i don't think it is that. My question is, from what i have thus far, how do i from "class view" grab "command" for my subprocesses to run. Thanks~ John Riselvato

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  • why is link generated in YUI javascript failing to render in rails?

    - by pmneve
    Using YAHOO.widget.treeview to generate a table with three levels of data: module, submodule, and detail. If there is an image associated with a detail row the javascript generates a link: "<td><a href=\"/screenshot/show/" + rowData.id + "\">Screenshot</a></td>" that is appended to the html for the row. The url is generated correctly and the link appears. When clicked nothing happens except the word 'Done' appears in the browser status bar. Am calling the very same url from another page that does not use javascript and the screenshot page appears as expected. Here is the controller. class ScreenshotController < ApplicationController def show if @detail.screen_path.length 1 @imagePath = "#{RAILS_ROOT}" + "/private/#{Company.find(@detail.company_id).subdir}/" + "#{Project.find(@detail.project_id).subdir}/screenshot/" + "#{@detail.screen_path}" send_file ( @imagePath, :type = 'image/jpeg', :disposition = 'inline') end end end A sample url: http://localhost:3004/screenshot/show/20854 This code from show.html.erb belonging to the detail model works: <%= link_to 'View', :controller = 'screenshot', :id = @detail.id, :action = 'show' % Any ideas???

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  • How do you render a rails partial that is outside of a namespace in a view that is inside of a namespace?

    - by iand675
    I've got a 'static' controller and static views that are pages that don't utilize ruby in their views. For these pages, I have a sitemap partial that is generated programatically and used in the application layout file. Namespaced routes still use the application layout file but are taking the static routes and trying to namespace them too. Here's the relevant portion of the route file: namespace :admin do resources :verse_categories resources :verses resources :songs resources :flowers resources :visits, :except => [:new, :create] end match ':action' => 'static' root :to => 'static#home' Here's the error I'm getting: No route matches {:controller=>"admin/static", :action=>"about"} Note that about is one of the static pages that the sitemap partial uses. So, how can I resolve this routing issue so that it's not trying to find my static sites inside of the admin namespace? Any help would be appreciated!

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  • Namespace with index action in Rails

    - by yuval
    I have an admin controller located inside /controllers/admin/admin_controller.rb I also have a pages controller located inside /controllers/admin/pages_controller.rb In my routes.rb file, I have the following: map.namespace :admin do |admin| admin.resources :pages end When the user goes to localhost:3000/admin, I'd like the user to see a page with a link to /admin/pages (Pages CRUD) and to / (To go back home). Since I am using a namespace, I cannot have an index action for /admin. How would I get this done and still have my controllers located inside my /controllers/admin folder (rather than using admin as a map.resources component and a has_many association to pages). Please note I am only interested in the show action of admin. Thank you!

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  • PHP Shared Sessions across Domain

    - by bigstylee
    Hi, I have seen a few answers to this on SOO but most of these are concerned with the use of subdomains, of which none have worked for me. The common one being that the use of session.cookie_domain, which from my understanding will only work with subdomains. I am interested in a solution that deals with deals with entirely different domains (and includes the possibility of subdomains). Unfortunately project deadlines being what they are, time is not on my side, so I turn to SOO's expertise and experience. The current project brief is to be able to log into one site which currently only stores the user_id in the session and then be able to retrieve this value while on a different domain within the same server enviroment. Session data is being stored/retrieved from a database where the session id is the primary key. I am hoping to find a "light wieght" and "easy" to implement solution. The system is utlising an in-house Model View Controller design pattern, so all requests (including different domains) are run through a single bootstrap script. Using the domain name as a variable, this determines what context to display to the user. One option that did look like to have potential is the use of a hidden image and using the alt tag to set the user id. My first impressions suggest this immediately seems "too easy" (if possible) and riddled with security flaws. Disscuss? Another option which I considered is using the IP and User Agent for authentication but again I feel this not going to be a reliable option due to shared networks and changing IP addresses. My third option (and preferred) which I considered and as yet not seen discussed is using htaccess to fool the user into thinking that they are on a different domain when infact apache is redirecting; something like www.foo.com/index.php?domain=bar.com&controller=news/categoires/1 but displays to the user as www.bar.com/news/categories/1 foo.com represents the "main site domain" which all requests are run through and bar.com is what the user thinks they are accessing. The controller request dictates the page and view being requested. Is this possible? Are there other options? Pros/Cons? Thanks in advanced!!!

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  • Trouble using xib files in libraries

    - by flohei
    Hi there, I'm having some trouble working with libraries and included xib files. Let me explain my situation first. I've got a project that's running pretty good. Now I need a part of my project as a library for another customer who want's to use some of the functionality in his app. I've created a library with help of that highly recommended article. My customer should be able to initialize a main view controller like this: LibraryMainViewController *lmvc = [[LibraryMainViewController alloc] initWithNibName:@"LibraryMainViewController.xib" bundle:foo]; That for sure leads to an error when I try to present that view controller modally. I'm not sure what bundle I have to use here. I tried something like [NSBundle bundleForClass:[SomeClassInTheLibrary class]]; but that didn't solve the problem. I would be glad if someone could tell me how to actually use a xib file in that kind of situation. Thanks –f

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  • UITableViewCell select even doesn't work

    - by saimun
    I had a page control(UIPageControl) on a view (UIViewController) with table view (UITableView) on each page, each page have own table and can go to different view controller. i add the codes in "didSelectRowAtIndexPath" which can go to next level, is works perfect when i test it in a table view by itself, but it doesn't works when i have page controller with it. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { [tableView deselectRowAtIndexPath:indexPath animated:YES]; if (pageNumber == 0) { PicturesViewController *picturesView = [[PicturesViewController alloc] init]; [self.navigationController pushViewController:picturesView animated:YES]; [picturesView release]; } else if (pageNumber == 1) { PictureDetailViewController *pictureDetailView = [[PictureDetailViewController alloc] init]; [self.navigationController pushViewController:pictureDetailView animated:YES]; [pictureDetailView release]; } else if (pageNumber == 2) { MessagesViewController *messagesView = [[MessagesViewController alloc] init]; [self.navigationController pushViewController:messagesView animated:YES]; [messagesView release]; } } here is the code, if view directly to this table view this code is work, how can i make it work under the pagecontrol??

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  • Where do I put constants file for Codeigniter (PHP)?

    - by wag2639
    I have a list of constants (I'm using them as an enum), some are define statements, and some are just global variables. Where am I suppose to put them in the MVC framework so I can use them for both my model and my controller that needs to reference it? I'd rather not stick it into config/constants.php since they shouldn't be called except for by this model and the controllers that use it. Edit 1: Clarification To be more specific, I have my message_model model and it has a bunch of constants that I need that are stored in message_model_constants.php. Where should I put message_model_constants.php and is there a way to have it automatically included by the controller that loads message_model when message_model is not (and I don't want it to be) auto-loaded. Edit 2: I really don't want to have the constants auto-loaded except for when I use the model

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  • Teacher confused about MVC?

    - by Gideon
    I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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  • How can I fix Grails error: "No domain class found for name PrivacyOptions. Please try again and e

    - by ?????
    I'm just getting started with Groovy/Grails. I added a new domain controller to my project, and generate-controller doesn't like it. There are other indications something's wrong: If I run the app no table is actually created in the database for this. I've reduced the DomainController to one String field and no constraints, just to make sure there wasn't something wrong with my specification. I also tried renaming it, just in case there was something about the original name (Privacy) that conflicted with something. I'm sure I have the correct name, and that the file is called PrivacyOptions.groovy and inside the class is also called PrivacyOptions. Here's the error: Running script /opt/local/grails/scripts/GenerateController.groovy Environment set to development Domain class not found in grails-app/domain, trying hibernate mapped classes... No domain class found for name PrivacyOptions. Please try again and enter a valid domain class name

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  • [super init] and loading NIB / XIB files?

    - by fuzzygoat
    I am a little curious, I have a view controller class and an NIB/XIB (both are named "MapViewController") If I do the following it loads the NIB with the matching name. -(id)init { self = [super initWithNibName:@"MapViewController" bundle:nil]; if(self) { do things ... } return self; } if on the other hand I just specify [super init] does Xcode just look for a NIB that matches the name of the controller, is that how this is working? -(id)init { self = [super init]; if(self) { do things ... } return self; } cheers Gary.

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  • How do you submit a rails 3 form without refreshing the page?

    - by Anthony H
    I've seen this done using ajax & php, but not rails 3. I've tried using: <%= form_for(:technician, :url => {:controller => 'pos', :action => 'create_ticket'}, :remote => true) do |f| %> but the page still refreshes each time. I'm building a point of sale program, so I don't want the page to refresh. How do I send the form data to the controller to process and store in the database without refreshing?

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