Search Results

Search found 12773 results on 511 pages for 'ide controller'.

Page 222/511 | < Previous Page | 218 219 220 221 222 223 224 225 226 227 228 229  | Next Page >

  • How do you submit a rails 3 form without refreshing the page?

    - by Anthony H
    I've seen this done using ajax & php, but not rails 3. I've tried using: <%= form_for(:technician, :url => {:controller => 'pos', :action => 'create_ticket'}, :remote => true) do |f| %> but the page still refreshes each time. I'm building a point of sale program, so I don't want the page to refresh. How do I send the form data to the controller to process and store in the database without refreshing?

    Read the article

  • Imitating Multiple Inheritance in PHP

    - by fabieno
    I am working on my own MVC framework and found myself stuck. I need the following construction: Controller -- Backend_Controller -- Backend_Crud_Controller -- Frontend_Controller -- Frontend_Crud_Controller Both 'Backend_Crud_Controller' and 'Frontend_Crud_Controller' have the same functionality and thus they should extend another class named 'Base_Crud_Controller', the only difference comes from the 'Backend/Frontend' Controllers which implement different mechanisms. Basically they should inherit both classes but my problem is that 'Backend/Frontend' controller doesn't necessarily extend 'Base_Crud_Controller'. I know multiple inheritance doesn't exist in PHP but I am looking for a solution, I choose to refrain Mixins (like in Symfony) as I don't consider that an elegant solution. Interfaces do not suit me as all of these end up as concrete classes that should implement methods.

    Read the article

  • Error handling in controllers with MVC

    - by twrn
    Does it make sense to do error handling and logging inside actions methods or handle the OnException method inside the controllers. One way means writing try/catches in all the action methods even when there is nothing to be done to recover from the error. Handling this at the controller level would allow logging and redirection to an error handler page without writing try/catches inside all the action methods. Which method makes the most sense? Here is example code of try/catches in an action method. [HttpPost] public ActionResult Delete(int id) { using (new Tracer("Project Controller")) { try { Logger.Write("Deleting project"); projService.DeleteProject(id); TempData["message"] = "Project Deleted successfully"; } catch (System.Exception ex) { HandleException(ex, "Project could not be deleted."); } return RedirectToAction("List"); } }

    Read the article

  • IPhone: Controllers, Delagates, DataSources, etc all in one class?

    - by MLS
    Hi All, I am learning iPhone programming. I am starting with a simple example of displaying recently used documents in a UITableView. What I am confused about is why do I need to have several classes and why cant I just use one? Example, My class is called RecentFileList. I need to implement controller, delegate and datasource as well as the actual table view. Can't I just do this all in my RecentFileList Class versus having to create a RecentFileListDelegate RecentFileListController, RecentFileListDataSource class, etc, etc. Related to this can one define a class like: @interface FileListView : NSObject <UITableViewDelegate> <UITableViewController> <UITableViewDataSource { // code } @end or would I just do the work to make my class a delegate and controller in init()?

    Read the article

  • Inconsistent Routing Results in MVC

    - by HapiDjus
    Seems I'm still missing something to the MVC routing concept. I have a route that follows nearly the same pattern as another route in an area but for what ever reason I get a 404 every time I attempt to run it. I've tried to use Phil Haack's Route Tester DLL and according to that it hits the correct route (matched route comes out to common/itemhistory/{contentid}). When I try to run it for real, it blows up. I'm trying to map a call to a JsonResult by passing a Guid. I've had success with other routes working fine (common is an area in my site). What could I be doing wrong? context.MapRoute( "ItemHistory", "common/itemhistory/{contentid}", new { controller = "common", action = "GetItemHistory" }, new { contentid = @"^(\{){0,1}[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}(\}){0,1}$" } ); context.MapRoute( "Common_default", "common/{action}", new { controller="common", action = "Index" } );

    Read the article

  • subviews show confused rotated state after a modal dialog is displayed

    - by deafgreatdane
    I've created a custom UIViewController that mimics the UISplitViewController. It manages two child view controllers that get displayed in the left & right body area while in landscape and hides the left to show in a popover when in portrait. It works fine, using the didRotateFromInterfaceOrientation: and willRotateToInterfaceOrientation: messages to reset the location and sizing of the child views. All the views and child controllers are loaded from a nib. This custom view controller is shown inside a UINavigationController. The trouble arises after one of the child view controllers uses presentModalViewController. If the device was rotated after the views were initialized (but before the modal controller is shown), after the modal dialog is dismissed, the left and/or body views will be re-rendered in a different rotation than they were before the modal dialog was changed. I'm wondering if folks have had a similar problem, and what the solution is. I'm sure sample code would be helpful, but it'll take a bunch of work to distill it into a runnable sample.

    Read the article

  • help with Zend dispatcher

    - by simple
    this is the Zend Controller Dispatcher Standart public function isDispatchable(Zend_Controller_Request_Abstract $request) { $className = $this->getControllerClass($request); echo 'is dispatchanble started'; var_dump($className); if (!$className) { return false; } var_dump(class_exists($className, false)); if (class_exists($className, false)) { return true; } $fileSpec = $this->classToFilename($className); $dispatchDir = $this->getDispatchDirectory(); $test = $dispatchDir . DIRECTORY_SEPARATOR . $fileSpec; return Zend_Loader::isReadable($test); } I need to set up custom modular structure and loading just using plugins (I need to setup the path where zend looks for controller), so I am stuck tracing down I came to the isDispatchable method that returns false and consequently the dispatching returns error . This method returns false because class_exists return false , it is surely has to do with auto loading ,but confused. help will be appreciated,though I got the feeling that I am looking at wrong place.

    Read the article

  • php: two objects from the same class work independent of each other

    - by user317563
    Good morning, I would like the code in my controller to look something like this: <?php $class = new sanitizeInput() $string1 = $class -> input($_POST[name]) -> mysql_escape(); $string2 = $class -> input($_POST[age]) -> mysql_escape(); print " String1: $string1 <br /> String2: $string2" ?> It seems with my sanitizeInput class, any change to $string2 is applied to $string1. What ways can I change this? I would preferably like to make the changes within the class to make my controller as easily read as possible. Thank you for your time. Kind regards, Marius

    Read the article

  • How to program a Sort feature

    - by Brian Roisentul
    I'm working on Ruby on rails 2.3.4 and I'm trying to develop a Sort feature on my website's search page(its url is /anuncios/buscar). What I tried is to create a "map" on routes file: map.search_filter_relevance "/anuncios/buscar", :controller => 'announcements', :action => 'search_filter_relevance' Then, I wrote this on the view: <%= link_to 'M&Aacute;S RELEVANTES', search_filter_relevance(@announcements) %> And finally, I created a method in the controller, as is specified on the routes' line: def search_filer_relevance raise params.inspect end First of all, as I'm sorting search results, I'd like to keep them in their public variable called @announcements. Please help me do this. An the other thing is that when I click the link I get an error due its trying to access the Show action instead of search_filter_relevance as specified in routes. Why is this happening?

    Read the article

  • How to send exceptions to exceptionController?

    - by ivar
    <bean class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver"> <property name="mappedHandlers"> <set> <ref bean="exceptionController" /> </set> </property> <property name="defaultErrorView" value="tiles/content/error" /> </bean> I'm trying to send exceptions to a controller so I can create a redirect. If I comment out the mappedHandlers part then the error tile is displayed but it is only a tile. The rest of the tiles load normally. I need to make a redirect in the controller so I can show an error page not just an error tile. I can't find enough information or an example how the exception invokes some method in exceptionController.

    Read the article

  • Rails 3 Routing help

    - by Rod Nelson
    OK i'm new to rails 3 and the new routing is driving me mad. I just a good example i was looking at the info on http://rizwanreza.com/2009/12/20/revamped-routes-in-rails-3 but it don't make sense to me. i need an example please! I have my root down that's not hard. I have Site as my controller and i have index help and about then i have a second controller users with index and register on the register page i have 3 text boxes and a submit when i hit submit i get Routing Error No route matches "/user/register" if you need me to i will post my routes file

    Read the article

  • Add params before submit form ROR

    - by Jorge Najera T
    It's possible to add some parameters before submit an form? My problem is that I need to send the ticket id to my payment controller. A possibility is to send it through an hidden input field, but there's any other secure way to achieve this? Any help will be appreciated. Thanks. The process of buying a ticket 0) Select the event 1) User select the kind of ticket he wants to buy. 2) User add his personal information 3) Finally the Checkout (payment controller)

    Read the article

  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

    Read the article

  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

    Read the article

  • What is the best way to log errors in Zend Framework in my project at this stage?

    - by Pasta
    We built an app in Zend Framework and have not worked a lot in setting up error reporting and logging. Is there any way we could get some level or error reporting without too much change in the code? Is there a ErrorHandler plugin available? The basic requirement is to log errors that happens within the controller, missing controllers, malformed URLs, etc. I also want to be able to log errors within my controllers. Will using error controller here, help me identify and log errors within my controllers? How best to do this with minimal changes?

    Read the article

  • Best Design Pattern to Implement while Mapping Actions in MVC

    - by FidEliO
    What could be the best practices of writing the following case: We have a controller which based on what paths users take, take different actions. For example: if user chooses the path /path1/hello it will say hello. If a user chooses /path1/bye?name="Philipp" it will invoke sayGoodBye() and etc. I have written a switch statement inside the controller which is simple, however IMO not efficient. What are the best way to implement this, considering that paths are generally String. private void takeAction() { switch (path[1]) { case "hello": //sayHello(); break; case "bye": //sayBye(); break; case "case3": //Blah(); break; ... } }

    Read the article

  • Widget_Controller for different types of data (MVC)

    - by steve-o
    Hello, I have a few widgets I need to show on a site - they are all relating to different types of data (e.g user, house). Each type of data and its relations is represented in specific models, but as far as a controller or helper is concerned, is it an ok plan to have a generic Widget controller/helper which generates the necessary widgets, even though each widget is dealing with distinct data? I don't really want to generate these widgets within the User and House controllers, as these controllers are dealing with different types of functionality. I'd imagine that the Widget_Controller could just contain static methods for generating these widgets, e.g: Widget_Controller::user_panel(); Does that make sense? Cheers!

    Read the article

  • Are these REST HTTP response codes right, and what about the Content-Type?

    - by talentedmrjones
    I'm writing a controller helper that sets the proper response headers for my REST controller action. It's pasted below and should be simplified enough for those who aren't familiar with Zend Framework to understand what I'm doing. My question is: Are these codes correct for their respective responses, and in the case of "access denied" do I use a 401 or 403? Also, in case of responding with an error, I understand I should be placing a message in the response body, but should I set the "Content-Type" to "text/plain"? <?php class App_Controller_Helper_RestResponse extends Zend_Controller_Action_Helper_Abstract { public function denied() { // 403 or 401? } public function notFound() { // 404 } public function created() { // 201 } public function deleted() { // 204 } public function redirect() { // 301 // new url } public function malformed() { // 400 } public function gone() { // 410 } }

    Read the article

  • MVC Pages that require the user to be logged in

    - by keithjgrant
    I'm working on a little MVC framework and I'm wondering what the "best way" is to structure things so secure pages/controllers always ensure the user is logged in (and thus automatically redirects to a login page--or elsewhere--if not). Obviously, there are a lot of ways to do it, but I'm wondering what solution(s) are the most common or are considered the best practice. Some ideas I had: Explicitly call user->isLoggedIn() at the beginning of your controller action method? (Seems far too easy to forget and leave an important page unsecure on accident) Make your controller extend a secureController that always checks for login in the constructor? Do this check in the model when secure information is requested? (Seems like redundant calls would be made) Something else entirely? Note: I'm working in PHP, though the question is not language-dependent.

    Read the article

  • Can someone explain Kohana 3's routing system?

    - by alex
    In bootstrap.php, where you set routes, I'm having a hard time getting them to work. I read some documentation a while ago that I can't seem to find again that explains them. Here is one of my examples Route::set('products', 'products/(type)', array('type' => '.+')) ->defaults(array( 'controller' => 'articles', 'action' => 'view_product', 'page' => 'shock-absorbers', )); I thought that would mean a request like products/something would load up the articles controller, and the action_view_product method. But I can't get it to work. Can someone please explain to me exactly how they work, and what all the method parameters are?

    Read the article

  • What would be the best approach for this?

    - by chobo
    I have a site which has an area that requires authentication. Right now I use the roles attribute on all the controllers in that area, and I run a query to retrieve that users ID, and all their settings. It seems like a code or design smell to me that I am retrieving the userid and settings each time a controller in that area loads up? I'm not sure if I should be using sessions, or if ASP.Net MVC 2.0 provides some unique way to handle this. Another concern is security. Overall, I don't really know which way to turn. Design wise I would like the userId and settings retrieved only once when the user logs into the area. Right now I grab the userId each time a controller loads up, and then if required, I query the database for their settings each time as well.

    Read the article

  • Error handling with Python + Pylons

    - by ensnare
    What is the proper way to handle errors with Python + Pylons? Say a user sets a password via a form that, when passed to a model class via the controller, throws an error because it's too short. How should that error be handled so that an error message gets displayed on the web page rather than the entire script terminating to an error page? Should there be any error handling in the controller itself? I hope I am explaining myself clearly. Thank you.

    Read the article

  • will_paginate route only works on page > 1

    - by Avishai
    I have the following routes defined: map.resources :categories, :has_many => :downloads map.resources :downloads, :member => {:go => :get}, :collection => {:tag => :get} map.connect '/downlods/page/:page', :controller => 'downloads', :action => 'index' map.connect '/categories/:category_id/downloads/page/:page', :controller => 'downloads', :action => 'index' For some reason, the first page that the will_paginate helper is called on causes links with ?page=2 to be rendered, while subsequent pages have links with /downloads/page/2. Do you know what might be causing this?

    Read the article

< Previous Page | 218 219 220 221 222 223 224 225 226 227 228 229  | Next Page >