localhost - Page 222 - Developer IT

Has anyone setup tomcat to run virtual hosts using mod_jk

- by Adam

I work in OSX primarily with mostly PHP. Normally I work locally using MAMP and virtual hosts setup in my httpd.conf so that I can point a browser to http://some-project and have as many projects as I need setup. We have a project coming up where we need to serve JSP pages and I would like to set up my local apache server to serve only JSP files to Tomcat and everything else to MAMP using the same virtual hosts setup in: ~/applications/MAMP/conf/apache/httpd.conf So far I have: Successfully installed Tomcat Placed mod_jd.so in ~/applications/MAMP/Library/modules/mod_jk.so Added the module by placing: LoadModule jk_module modules/mod_jk.so in ~/applications/MAMP/conf/apache/httpd.conf Created /Library/Tomcat/Home/conf/jk/workers.properties and added the following lines: workers.tomcat_home=/Library/Tomcat workers.java_home=/System/Library/Frameworks/JavaVM.framework/Versions/1.5.0/Home ps=/ worker.list=ajp12, ajp13 worker.ajp13.port=8009 worker.ajp13.host=localhost worker.ajp12.type=ajp13 worker.ajp13.mount=/*.jsp added the following lines: JkWorkersFile /Library/Tomcat/Home/conf/workers.properties JkLogFile /Library/Tomcat/Home/logs/mod_jk.log JkLogLevel debug to ~/applications/MAMP/conf/apache/httpd.conf I cannot start my MAMP however when these last two lines are present in my httpd.conf. Does anyone work like this? Any tips? Any clear ideas of what I'm doing wrong?

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PHP check http referer for form submitted by AJAX, secure?

- by Michael Mao

Hi all: This is the first time I am working for a front-end project that requires server-side authentication for AJAX requests. I've encountered problems like I cannot make a call of session_start as the beginning line of the "destination page", cuz that would get me a PHP Warning : Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\xampp\htdocs\comic\app\ajaxInsert Book.php:1) in C:\xampp\htdocs\comic\app\common.php on line 10 I reckon this means I have to figure out a way other than checking PHP session variables to authenticate the "caller" of this PHP script, and this is my approach : I have a "protected" PHP page, which must be used as the "container" of my javascript that posts the form through jQuery $.ajax(); method In my "receiver" PHP script, what I've got is: <?php define(BOOKS_TABLE, "books"); define(APPROOT, "/comic/"); define(CORRECT_REFERER, "/protected/staff/addBook.php"); function isRefererCorrect() { // the following line evaluates the relative path for the referer uri, // Say, $_SERVER['HTTP_REFERER'] returns "http://localhost/comic/protected/staff/addBook.php" // Then the part we concern is just this "/protected/staff/addBook.php" $referer = substr($_SERVER['HTTP_REFERER'], 6 + strrpos($_SERVER['HTTP_REFERER'], APPROOT)); return (strnatcmp(CORRECT_REFERER, $referer) == 0) ? true : false; } //http://stackoverflow.com/questions/267546/correct-http-header-for-json-file header('Content-type: application/json charset=UTF-8'); header('Cache-Control: no-cache, must-revalidate'); echo json_encode(array ( "feedback"=>"ok", "info"=>isRefererCorrect() )); ?> My code works, but I wonder is there any security risks in this approach? Can someone manipulate the post request so that he can pretend that the caller javascript is from the "protected" page? Many thanks to any hints or suggestions.

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Secure Copy File from remote server via scp and os module in Python

- by user1063572

I'm pretty new to Python and programming. I'm trying to copy a file between two computers via a python script. However the code os.system("ssh " + hostname + " scp " + filepath + " " + user + "@" + localhost + ":" cwd) won't work. I think it needs a password, as descriped in How do I copy a file to a remote server in python using scp or ssh?. I didn't get any error logs, the file just won't show in my current working directory. However every other command with os.system("ssh " + hostname + "command") or os.popen("ssh " + hostname + "command") does work. - command = e.g. ls When I try ssh hostname scp file user@local:directory in the commandline it works without entering a password. I tried to combine os.popen commands with getpass and pxssh module to establish a ssh connection to the remote server and use it to send commands directly (I only tested it for an easy command): import pxssh import getpass ssh = pxssh.pxssh() ssh.force_password = True hostname = raw_input("Hostname: ") user = raw_input("Username: ") password = getpass.getpass("Password: ") ssh.login(hostname, user, password) test = os.popen("hostname") print test But I'm not able to put commands through to the remote server (print test shows, that hostname = local and not the remote server), however I'm sure, the conection is established. I thought it would be easier to establish a connection than always use "ssh " + hostname in the bash commands. I also tried some of the workarounds in How do I copy a file to a remote server in python using scp or ssh?, but I must admit due to lack of expirience I didn't get them to work. Thanks a lot for helping me.

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Why does Rails screw up timezones when I am editing a resource?

- by DJTripleThreat

Steps to produce this: prompt>rails test_app prompt>cd test_app prompt>script/generate scaffold date_test my_date:datetime prompt>rake db:migrate now edit your app/views/date_tests/edit.html.erb: <h1>Editing date_test</h1> <% form_for(@date_test) do |f| %> <%= f.error_messages %> RIGHT! <%= text_field_tag @date_test, f.object.my_date %> WRONG! <%= f.text_field :my_date %> <%= f.submit 'Update' %> <% end %> <%= link_to 'Show', @date_test %> | <%= link_to 'Back', date_tests_path %> now edit your config/environment.rb: #add this config.time_zone = 'Central Time (US & Canada)' This recreates the problem I am having in my actual app. The problem with my app is that I'm storing a date in a hidden field and rendering a "user friendly" version. Creating a resource works fine but as soon as I try to edit it the time changes (it adds the difference between my current time zone configuration and UTC). go to http://localhost:3000/date_tests/new and save the time then go to reedit it and you will have two different representations of the date/time one which will save incorrectly and the other that will.

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How to establish a socket connection from iPhone to a Apache server and communicate via PHP?

- by candoyo

Hi, I am working on an iPhone game which is depended on a LAMP server. I want to create a "event" based system where the apache server sends an event to the iphone. For this, I am thinking of using "CFStreamCreatePairWithSocketToHost" to connect to port 80 of the apache server. I am able to successfully connect to the server and open a read and write stream via the iPhone, but I am not sure how to send data to the iphone using PHP running from the LAMP server to the iPhone. I think I can use fsockopen in php to open a socket connection and write data to that socket. I tired running this code $fp = fsockopen("tcp://localhost", 80, $errno, $errstr); if (!$fp) { echo "ERROR: $errno - $errstr \n"; } else { echo"writing to socket "; fwrite($fp, "wwqeqweqw eqwe qwe \n"); //echo fread($fp, 26); fclose($fp); echo "done"; } But, I dont see anything being read on the iphone.. Any idea what's going on, or how to accomplish this? Thanks!

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Website. AJAX and FIREFOX problems. I dont think Firefox likes ajax..?

- by DJDonaL3000

Working on an AJAX website (HTML,CSS,JavaScript, AJAX, PHP, MySQL). I have multiple javascript functions which take rows from mysql, wrap them in html tags, and embed them in the HTML (the usual usage of AJAX). THE PROBLEM: Everything is working perfect, except when I run the site with Firefox (for once its not InternetExplorer causing the trouble). The site is currently in the developmental stage, so its offline, but running on the localhost (WampServer, apache, Windows XP SP3,VISTA,7). All other cross-browser conflicts have been removed, and works perfectly on all major browsers including IE, Chrome, Opera and Safari, but I get absolutely nothing from the HTTPRequest (AJAX) if the browser is Firefox. All browsers have the latest versions. THE CODE: I have a series of javascript functions, all of which are structured as follows: function getDatay(){ var a = document.getElementById( 'item' ).innerHTML; var ajaxRequest; try{//Browser Support Code: // code for IE7+, Firefox, Chrome, Opera, Safari: ajaxRequest = new XMLHttpRequest(); } catch (e){ // code for IE6, IE5: try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser is not compatible - Browser Incompatibility Issue."); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState < 4){ document.getElementById( 'theDiv' ).innerHTML = 'LOADING...'; } if(ajaxRequest.readyState == 4){ document.getElementById( 'theDiv' ).innerHTML = ajaxRequest.responseText; } } //Post vars to PHP Script and wait for response: var url="01_retrieve_data_7.php"; url=url+"?a="+a; ajaxRequest.open("POST", url, false);//must be false here to wait for ajaxRequest to complete. ajaxRequest.send(null); } My money is on the final five lines of code being the cause of the problem. Any suggestions how to get Firefox and AJAX working together are most welcome...

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JQuery error in IE, works with FF. Maybe a problem with live.

- by olve

Hello. I have an ASP.net MVC2 application. In wich I'm using JQuery to alter all table rows so I can click anywhere in any row to trigger a click event on a link in the clicked row. The tables is created using MVC's built in partialview ajax. Here is my JQuery script. <script type="text/javascript"> $(document).ready(function () { $('table tr').live('click',function (event) { $('#asplink', this).trigger('click'); }) .live('mouseenter',function (event) { this.bgColor = 'lightblue'; }) .live('mouseleave', function (event) { this.bgColor = 'white'; }); }); </script> And this is the first part of the partial view code that creates the table. <% foreach (var item in Model.JobHeaderData) { %> <tr> <td> <a id="asplink" href="http://localhost/sagstyring/EditJob.asp?JobDataID=<%: item.JobDataId %>&JobNumId=<%: item.JobNumID%>&JobNum=<%: item.JobNumID%>&DepId=1&User_Id=<%:ViewData["UserId"]%>" onclick="window.open(this.href,'Rediger sag <%: item.JobNumID %> ', 'status=0, toolbar=0, location=0, menubar=0, directories=0, resizeable=0, scrollbars=0, width=900, height=700'); return false;">Rediger</a> </td> In firefox this works perfectly. In IE, JQuery crashes when I click on a row. If I debug the page in IE. I get this. Out of stack space In jquery-1.4.1.js line 1822 // Trigger the event, it is assumed that "handle" is a function var handle = jQuery.data( elem, "handle" ); if ( handle ) { handle.apply( elem, data ); } I'm no eagle at javascript, so I'm pretty much stuck.

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WCF REST adding data using POST or PUT 400 Bad Request

- by user55474

HI How do i add data using wcf rest architecture. I dont want to use the channelfactory to call my method. Something similar to the webrequest and webresponse used for GET. Something similar to the ajax WebServiceProxy restInvoke Or do i always have to use the Webchannelfactory implementation I am getting a 400 BAD request by using the following Dim url As String = "http://localhost:4475/Service.svc/Entity/Add" Dim req As WebRequest = WebRequest.Create(url) req.Method = "POST" req.ContentType = "application/xml; charset=utf-8" req.Timeout = 30000 req.Headers.Add("SOAPAction", url) Dim xEle As XElement xEle = <Entity xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <Name>Entity1</Name> </Entity> Dim sXML As String = xEle .Value req.ContentLength = sXML.Length Dim sw As New System.IO.StreamWriter(req.GetRequestStream()) sw.Write(sXML) sw.Close() Dim res as HttpWebResponse = req.GetResponse() Sercice Contract is as follows <OperationContract()> _ <WebInvoke(Method:="PUT", UriTemplate:="Entity/Add")> _ Function AddEntity(ByVal e1 As Entity) DataContract is as follows <Serializable()> _ <DataContract()> _ Public Class Entity private m_Name as String <DataMember()> _ Public Property Name() As String Get Return m_Name End Get Set(ByVal value As String) m_Name = value End Set End Property End Class thanks

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Apache ReWriteEngine throwing 500 Internal Server Error for too many internal redirects... why?!?!?!

- by Stephen G

I'm trying to implement a new ReWrite rule on my local dev machine. I have 13 rules set up already, and all work fine (even as of this writing). However, for some reason the newest one is throwing me 500 Internal Server Errors. The ReWrite rule is: RewriteRule stuff/public_html/vault/mystuff/view/(.*) /stuff/public_html/vault/mystuff/view/index.php?stuff=$1 RewriteRule stuff/public_html/vault/mystuff/view/(.*)/ /stuff/public_html/vault/mystuff/view/index.php?stuff=$1 Checked my apache logs and got this: [Thu Jan 13 22:07:43 2011] [error] [client ::1] mod_rewrite: maximum number of internal redirects reached. Assuming configuration error. Use 'RewriteOptions MaxRedirects' to increase the limit if neccessary., referer: http://localhost:8888/stuff/public_html/vault/mystuff/all/index.php?curr=7 On the script I am trying to redirect to view/index.php?stuff=$1, there is nothing that even remotely resembles a redirect of any kind. I do have a very, very basic session verifier being called at the top of the landing script, which is as follows: //Start session session_start(); //Check whether the session variable SESS_MEMBER_ID is present or not if(!isset($_SESSION['SESS_MEMBER_ID']) || (trim($_SESSION['SESS_MEMBER_ID']) == '')) { header("location: ".$root_http.""); exit(); } However, when I access the page directly, it acts as it should, and there is no redirect. All of my other ReWrite rules and their corresponding landing pages are set up the exact same way. This is blowing my mind. Any help, PLEASE!?

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mysql_real_escape_string() just makes an empty string?

- by James P

I am using a jQuery AJAX request to a page called like.php that connects to my database and inserts a row. This is the like.php code: <?php // Some config stuff define(DB_HOST, 'localhost'); define(DB_USER, 'root'); define(DB_PASS, ''); define(DB_NAME, 'quicklike'); $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die('ERROR: ' . mysql_error()); $sel = mysql_select_db(DB_NAME, $link) or die('ERROR: ' . mysql_error()); $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg'])); $timeStamp = time(); if(empty($likeMsg)) die('ERROR: Message is empty'); $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; $result = mysql_query($sql, $link) or die('ERROR: ' . mysql_error()); echo mysql_insert_id(); mysql_close($link); ?> The problematic line is $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg']));. It seems to just return an empty string, and in my database under the like_message column all I see is blank entries. If I remove mysql_real_escape_string() though, it works fine. Here's my jQuery code if it helps. $('#like').bind('keydown', function(e) { if(e.keyCode == 13) { var likeMessage = $('#changer p').html(); if(likeMessage) { $.ajax({ cache: false, url: 'like.php', type: 'POST', data: { likeMsg: likeMessage }, success: function(data) { $('#like').unbind(); writeLikeButton(data); } }); } else { $('#button_container').html(''); } } }); All this jQuery code works fine, I've tested it myself independently. Any help is greatly appreciated, thanks.

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Update graph in real time from server

- by user1869421

I'm trying to update a graph with received data, so that the height of the bars increase as more data is received from the server via a websocket. But my code doesn't render a graph in the browser and plot the data points. I cannot see anything wrong with the code. I really need some help here please. ws = new WebSocket("ws://localhost:8888/dh"); var useData = [] //var chart; var chart = d3.select("body") .append("svg:svg") .attr("class", "chart") .attr("width", 420) .attr("height", 200); ws.onmessage = function(evt) { var distances = JSON.parse(evt.data); data = distances.miles; console.log(data); if(useData.length <= 10){ useData.push(data) } else { var draw = function(data){ // Set the width relative to max data value var x = d3.scale.linear() .domain([0, d3.max(useData)]) .range([0, 420]); var y = d3.scale.ordinal() .domain(useData) .rangeBands([0, 120]); var rect = chart.selectAll("rect") .data(useData) // enter rect rect.enter().append("svg:rect") .attr("y", y) .attr("width", x) .attr("height", y.rangeBand()); // update rect rect .attr("y", y) .attr("width", x) .attr("height", y.rangeBand()); var text = chart.selectAll("text") .data(useData) // enter text text.enter().append("svg:text") .attr("x", x) .attr("y", function (d) { return y(d) + y.rangeBand() / 2; }) .attr("dx", -3) // padding-right .attr("dy", ".35em") // vertical-align: middle .attr("text-anchor", "end") // text-align: right .text(String); // update text text .data(useData) .attr("x", x) .text(String); } useData.length = 0; } } Thanks

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Flex : providing data with a PHP Class

- by Tristan

Hello, i'm a very new user to flex (never use flex, nor flashbuilder, nor action script before), but i want to learn this langage because of the beautiful RIA and chart it can do. I watched the video on adobe : 1 hour to build your first program but i'm stuck : On the video it says that we have to provide a PHP class for accessing data and i used the example that flash builder gave (with zend framework and mysqli). I never used those ones and it makes a lot to learn if i count zen + mysqli. My question is : can i use a PHP class like this one ? What does flash builder except in return ? i hear that was automatic. example it may be wrong, i'm not very familiar with classes when acessing to database : <?php class DBConnection { protected $server = "localhost"; protected $username = "root"; protected $password = "root"; protected $dbname = "something"; protected $connection; function __construct() { $this->connection = mysql_connect($this->server, $this->username, $this->password); mysql_select_db($this->dbname,$this->connection); mysql_query("SET NAMES 'utf8'", $this->connection); } function query($query) { $result = mysql_query($query, $this->connection); if (!$result) { echo 'request error ' . mysql_error($this->connection); exit; } return $result; } function getAll() { $req = "select * from servers"; $result = query($req) return $result } function num_rows() { return mysql_num_rows($result); } function end() { mysql_close($this->connection); } } ?> Thank you,

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java.io.StreamCorruptedException: invalid stream header: 7371007E

- by Alex

Hello, this is pprobably a simple question . I got a client Server application which communicate using objects. when I send only one object from the client to server all works well. when I attempt to send several objects one after another on the same stream I get StreamCorruptedException. can some one direct me to the cause of this error . Thanks client write method private SecMessage[] send(SecMessage[] msgs) { SecMessage result[]=new SecMessage[msgs.length]; Socket s=null; ObjectOutputStream objOut =null; ObjectInputStream objIn=null; try { s=new Socket("localhost",12345); objOut=new ObjectOutputStream( s.getOutputStream()); for (SecMessage msg : msgs) { objOut.writeObject(msg); } objOut.flush(); objIn=new ObjectInputStream(s.getInputStream()); for (int i=0;i<result.length;i++) result[i]=(SecMessage)objIn.readObject(); } catch(java.io.IOException e) { alert(IO_ERROR_MSG+"\n"+e.getMessage()); } catch (ClassNotFoundException e) { alert(INTERNAL_ERROR+"\n"+e.getMessage()); } finally { try {objIn.close();} catch (IOException e) {} try {objOut.close();} catch (IOException e) {} } return result; } server read method //in is an inputStream Defined in the server SecMessage rcvdMsgObj; rcvdMsgObj=(SecMessage)new ObjectInputStream(in).readObject(); return rcvdMsgObj; and the SecMessage Class is public class SecMessage implements java.io.Serializable { private static final long serialVersionUID = 3940341617988134707L; private String cmd; //... nothing interesting here , just a bunch of fields , getter and setters }

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Post complex types to WebApi Client

- by BumbleBee

I am new to WebAPI. I have a MVC project and webApi project both reside under the **same solution**. Also, BLL Class library and DAL class library reside under the same solution. Earlier, my MVC project will talk to the BLL now I am trying to create a WebAPi project which stands in between MVC and BLL. Here is what I have come up with so far : I'm using the HTTPClient to post to a WebApi project. My post method on my controller accepts a single parameter (a model). StatsCriteria criteria = new StatsCriteria(); ...... var client = new HttpClient(); var response = client.PostAsJsonAsync("http://localhost:52765/api/reports", criteria).Result; ....... Here's the signature for my controller in Webapi [HttpPost] public CMAReportVM Reports([FromBody] StatsCriteria criteria) { var cmaReport = Service3.GetCMAReport(criteria.Mlsnums); //Create Map to enable mapping business object to View Model Mapper.CreateMap<CMAReport, CMAReportVM>(); // Maps model to VM model class var cmaVM = Mapper.Map<CMAReport, CMAReportVM>(cmaReport); reutn cmaVM; } // and here's my routing: config.Routes.MapHttpRoute( name: "DefaultApi", routeTemplate: "api/{controller}/{id}", defaults: new { id = RouteParameter.Optional } I am getting the following 405 : Method not allowed. As the WebAPI and MVC project both reside under same sloution I am not sure where/how to host my webapi.

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How do I post a .wav file from CS5 Flash, AS3 to a Java servlet?

- by Muostar

Hi, I am trying to send a byteArray from my .fla to my running tomcat server integrated in Eclipse. From flash I am using the following code: var loader:URLLoader = new URLLoader(); var header:URLRequestHeader = new URLRequestHeader("audio/wav", "application/octet-stream"); var request:URLRequest = new URLRequest("http://localhost:8080/pdp/Server?wav=" + tableID); request.requestHeaders.push(header); request.method = URLRequestMethod.POST; request.data = file;//wav; loader.load(request); And my java servlet looks as follows: try{ int readBytes = -1; int lengthOfBuffer = request.getContentLength(); InputStream input = request.getInputStream(); byte[] buffer = new byte[lengthOfBuffer]; ByteArrayOutputStream output = new ByteArrayOutputStream(lengthOfBuffer); while((readBytes = input.read(buffer, 0, lengthOfBuffer)) != -1) { output.write(buffer, 0, readBytes); } byte[] finalOutput = output.toByteArray(); input.close(); FileOutputStream fos = new FileOutputStream(getServletContext().getRealPath(""+"/temp/"+wav+".wav")); fos.write(finalOutput); fos.close(); When i run the flash .swf file and send the bytearray to the server, I receive following in the server's console window:: (loads of loads of Chinese symbols) May 20, 2010 7:04:57 PM org.apache.tomcat.util.http.Parameters processParameters WARNING: Parameters: Character decoding failed. Parameter '? (loads of loads of Chinese symbols) and then looping this for a long time. It is like I recieve the bytes but not encoding/decoding them correctly. What can I do?

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PHP and MySQL echoing out a Table

- by user1631702

Okay, so I've done this before, and it worked. I am trying to echo out specific rows on my database in a table. Here is my code: <?php $connect = mysql_connect("localhost", "xxx", "xxx") or die ("Hey loser, check your server connection."); mysql_select_db("xxx"); $quey1="select * from `Ad Requests`"; $result=mysql_query($quey1) or die(mysql_error()); ?> <table border=1 style="background-color:#F0F8FF;" > <caption>Student Record</caption> <tr> <th>Student ID</th> <th>Student Name</th> <th>Class</th> </tr> <?php while($row=mysql_fetch_array($result)){ echo "</td><td>"; echo $row['id']; echo "</td><td>"; echo $row['twitter']; echo "</td><td>"; echo $row['why']; echo "</td></tr>"; } echo "</table>"; ?> It gives me no errors, but It just shows a blank table with none of these rows. My Question: How come this wont show any rows in the table, what am I doing wrong?

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jQuery .ajax method executing but not firing error (or success)

- by John Swaringen

I'm having a very strange situation. I have a .NET Web Service (.asmx) that I'm trying to call via jQuery ajax to populate some <select></select>'s. The service is running System.Web.Services like it's supposed to and should be returning a JSON list. At least that's the way I understand that it will in .NET 3.5/4.0. The main problem is that the .ajax() function (below) seems to execute but the internal callbacks aren't executing. I know it's executing because I can do something before and after the function and both execute, so JavaScript isn't blowing up. $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: 'http://localhost:59191/AFEDropDownService/Service.asmx/GetAVP', data: "{}", dataType: "jsonp", crossDomain: true, success: function(list) { console.log(list); console.log("success!!"); }, error: function(msg) { console.log("error: " + msg.text); } }); If you need more of the code let me know. Or if you know a better way as I'm trying to build cascading <select></select's.

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php not redirecting

- by NSchulze

I'm trying to write the logout of a website. When I do this I want the page to redirect to the login page. I think I'm doing it the correct way, but can't get the right result. Could you guys point me in the right direction? Relevant Code: <button onclick="logout()">Logout</button> function logout() { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.location=xmlhttp.responseText; } } xmlhttp.open("GET","logout.php",true); xmlhttp.send(); } <?php session_destroy(); header("Location:http://localhost:8888/loginns.html"); mysql_close($con); ?> Thanks!

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UTF-8 MySQL and Charset, pls help me understand this once and for all!

- by FFish

Can someone explain me when I set everything to UTF-8 I keep getting those damn ??? MySQL Server version: 5.1.44 MySQL charset: UTF-8 Unicode (utf8) I create a new database name: utf8test collation: utf8_general_ci MySQL connection collation: utf8_general_ci My SQL looks like this: SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; CREATE TABLE IF NOT EXISTS `test_table` ( `test_id` int(11) NOT NULL, `test_text` text NOT NULL, PRIMARY KEY (`test_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; INSERT INTO `test_table` (`test_id`, `test_text`) VALUES (1, 'hééélo'), (2, 'wööörld'); My PHP / HTML: <?php $db_conn = mysql_connect("localhost", "root", "") or die("Can't connect to db"); mysql_select_db("utf8test", $db_conn) or die("Can't select db"); // $result = mysql_query("set names 'utf8'"); // this works... why?? $query = "SELECT * FROM test_table"; $result = mysql_query($query); $output = ""; while($row = mysql_fetch_assoc($result)) { $output .= "id: " . $row['test_id'] . " - text: " . $row['test_text'] . " "; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html lang="it" xmlns="http://www.w3.org/1999/xhtml" xml:lang="it"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>UTF-8 test</title> </head> <body> <?php echo $output; ?> </body> </html>

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Sencha : how to pass parameter to php using Ext.data.HttpProxy?

- by Lauraire Jérémy

I have successfully completed this great tutorial : http://www.sencha.com/learn/ext-js-grids-with-php-and-sql/ I just can't use the baseParams field specified with the proxy... Here is my code that follows tutorial description : __ My Store : Communes.js ____ Ext.define('app.store.Communes', { extend: 'Ext.data.Store', id: 'communesstore', requires: ['app.model.Commune'], config: { model: 'app.model.Commune', departement:'var', // the proxy with POST method proxy: new Ext.data.HttpProxy({ url: 'app/php/communes.php', // File to connect to method: 'POST' }), // the parameter passed to the proxy baseParams:{ departement: "VAR" }, // the JSON parser reader: new Ext.data.JsonReader({ // we tell the datastore where to get his data from rootProperty: 'results' }, [ { name: 'IdCommune', type: 'integer' }, { name: 'NomCommune', type: 'string' } ]), autoLoad: true, sortInfo:{ field: 'IdCommune', direction: "ASC" } } }); _____ The php file : communes.php _____ <?php /** * CREATE THE CONNECTION */ mysql_connect("localhost", "root", "pwd") or die("Could not connect: " . mysql_error()); mysql_select_db("databasename"); /** * INITIATE THE POST */ $departement = 'null'; if ( isset($_POST['departement'])){ $departement = $_POST['departement']; // Get this from Ext } getListCommunes($departement); /** * */ function getListCommunes($departement) { [CODE HERE WORK FINE : just a connection and query but $departement is NULL] } ?> There is no parameter passed as POST method... Any idea?

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tomcat resource missing, servlet not running

- by user2837260

import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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I am unable to upload file to my local host folder in php.

- by Nauman khan

Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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gpg error - connection already closed?

- by OopsForgotMyOtherUserName

omg... hope someone can help me because I am so lost as to what to try next.... I don't know what is causing the error to happen, and I don't see how to figure it out... Keep going between the pgloader.conf examples and what I have, and I don't understand why I keep getting the 'connection already closed' error? The first few lines of my fr.conf is at the very end... I'd really appreciate / love some guidance here... Been trying to get this thing going all morning, and am even getting stuck just on this part... Running this command at the command line: /usr/bin/pgloader -c /var/mybin/pgconfs/fr.conf Yields this in the pgloader.log (with the process just hanging) more /tmp/pgloader.log 27-03-2010 12:22:53 pgloader INFO Logger initialized 27-03-2010 12:22:53 pgloader INFO Reformat path is ['/usr/share/python-support/pgloader/reformat'] 27-03-2010 12:22:53 pgloader INFO Will consider following sections: 27-03-2010 12:22:53 pgloader INFO fixed 27-03-2010 12:22:54 fixed INFO fixed processing 27-03-2010 12:22:54 pgloader INFO All threads are started, wait for them to terminate 27-03-2010 12:22:57 fixed ERROR connection already closed 27-03-2010 12:22:57 fixed INFO closing current database connection [pgsql] host = localhost port = 5432 base = frdb user = username pass = password [fixed] table = fr format = fixed filename = /var/www/fr.txt ...

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Selecting Date Range on a PHP form and displaying results from MySQL database

- by Sarah HSL

This may be something simple but I cant understand why this wouldn't work.. I have a php form where you can select a date range from drop downs. I've given the field names day, month year, and day1, month1, year1. When clicking submit it takes you to a second php form. Here is the code for second form: <?php $username="***"; $password="***"; $database="****"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td>Product Description</td> <td>Category</td> <td>Master Category</td> <td>Barcode</td> <td>Status</td> <td>TimeStamp</td> <td>New Own</td> <td>Serial No.</td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><?php echo $f1; ?></td> <td><?php echo $f2; ?></td> <td><?php echo $f3; ?></td> <td><?php echo $f4; ?></td> <td><?php echo $f5; ?></td> <td><?php echo $f6; ?></td> <td><?php echo $f7; ?></td> <td><?php echo $f8; ?></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> Is there any reason this wouldn't work? I'm not sure where I am going wrong. It displays results when there is another option as well as the date such as 'status' but when this is taken out and I just want to display all the results between the date range it doesn't work.. This works: <?php $username="+++"; $password="+++"; $database="+++"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $status = $_GET['status']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE status = '$status' AND curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td>Product Description</td> <td>Category</td> <td>Master Category</td> <td>Barcode</td> <td>Status</td> <td>TimeStamp</td> <td>New Own</td> <td>Serial No.</td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><?php echo $f1; ?></td> <td><?php echo $f2; ?></td> <td><?php echo $f3; ?></td> <td><?php echo $f4; ?></td> <td><?php echo $f5; ?></td> <td><?php echo $f6; ?></td> <td><?php echo $f7; ?></td> <td><?php echo $f8; ?></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> But when the 'status' field is taken out (and obviously the serial drop down in the first form) it stops working...

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How can I format Custom Data and display in autocomplete when source is an DB

- by Andres Scarpone

so I'm trying to get some info in the auto-complete widget like it's shown in the JQuery UI demo Demo, the only problem is they use a variable that they fill with the data they want to show, I instead want to access the data and the different description and stuff using a Data Base in MySQL, for this I have changed the source to use another php page that looks up the info. here is the code for the Auto-complete, I really don't understand the methods so I haven't changed it from the basic search. This is the JS: $(document).ready((function(){ $( "#completa" ).autocomplete({ source: "buscar.php", minLength: 1, focus: function (event, ui){ $("#completa").val(ui.item.val); return false; }; })); This is what I have in buscar.php: <?php $conec = mysql_connect(localhost, root, admin); if(!$conec) { die(mysql_error()); } else { $bd = mysql_select_db("ve_test",$conec ); if(!$bd) { die(mysql_error()); } } $termino = trim(strip_tags($_GET['term']));//Obtener el termino que envia el autocompletar $qstring = "SELECT name, descripcion FROM VE_table WHERE name LIKE '%".$termino."%'"; $result = mysql_query($qstring);//Solicitud a la Base de Datos while ($row = mysql_fetch_array($result,MYSQL_ASSOC))//Realizar un LOOP sobre los valores obtenidos { $row['value']=htmlentities(stripslashes($row['name'])); $row_set[] = $row;//build an array } echo json_encode($row_set);//Enviar los datos al autocompletar en codificacion JSON, Altamente Necesario. ?

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