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  • Using NULL in MySQL

    - by JPro
    The data in my dabatase comes from an external source and where ever there is no data passed, I keep NULL in those places. Can anyone tell me if there are any implications in using NULL to represent empty value? Should I follow some other convention like 'data_not_available'? or something like that? Can anyone suggest?

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  • Timestamps and Intervals: NUMTOYMINTERVAL SYSTDATE CALCULATION SQL QUERY

    - by MeachamRob
    I am working on a homework problem, I'm close but need some help with a data conversion I think. Or sysdate - start_date calculation The question is: Using the EX schema, write a SELECT statement that retrieves the date_id and start_date from the Date_Sample table (format below), followed by a column named Years_and_Months_Since_Start that uses an interval function to retrieve the number of years and months that have elapsed between the start_date and the sysdate. (Your values will vary based on the date you do this lab.) Display only the records with start dates having the month and day equal to Feb 28 (of any year). DATE_ID START_DATE YEARS_AND_MONTHS_SINCE_START 2 Sunday , February 28, 1999 13-8 4 Monday , February 28, 2005 7-8 5 Tuesday , February 28, 2006 6-8 Our EX schema that refers to this question is simply a Date_Sample Table with two columns: DATE_ID NUMBER NOT Null START_DATE DATE I Have written this code: SELECT date_id, TO_CHAR(start_date, 'Day, MONTH DD, YYYY') AS start_date , NUMTOYMINTERVAL((SYSDATE - start_date), 'YEAR') AS years_and_months_since_start FROM date_sample WHERE TO_CHAR(start_date, 'MM/DD') = '02/28'; But my Years and months since start column is not working properly. It's getting very high numbers for years and months when the date calculated is from 1999-ish. ie, it should be 13-8 and I'm getting 5027-2 so I know it's not correct. I used NUMTOYMINTERVAL, which should be correct, but don't think the sysdate-start_date is working. Data Type for start_date is simply date. I tried ROUND but maybe need some help to get it right. Something is wrong with my calculation and trying to figure out how to get the correct interval there. Not sure if I have provided enough information to everyone but I will let you know if I figure it out before you do. It's a question from Murach's Oracle and SQL/PL book, chapter 17 if anyone else is trying to learn that chapter. Page 559.

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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • Export a MYSQL column to a plain txt file with no headings

    - by Kohl Sharples
    So what I'm trying to do is write a script or CRON job (Linux- CentOS) to export the usernames listed in my wordpress database to a simple .txt file with just on username per line. So with the picture, I would like the .txt file to read like this: Sir_Fluffulus NunjaX007 (Except with all the username in the user_login column.) See screenshot at: http://i.stack.imgur.com/lZQai.png I have found how to export the entire table to a CVS file, but that contains about 10+ fields (Columns) that I DO NOT what to show up in this text file. Can anyone point me in the right direction on how to do this? If it helps, this is going to be for exporting users that have signed up on our website (Wordpress) to a whitelist.txt file for Minecraft. Thanks!

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  • MySQL Non Index Queries Analysis

    - by Markii
    I'm using the log queries not using index but it logs all that use indexes but just more advanced or using IFs. Is there a parser or a program out there that can analyze the log and give me a literal output of saying "table.column should be a index" Thanks

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  • Find and replace braced tags within a MySQL table

    - by Cy
    I have about 40000 records in that table that contains plain text and within the plain text, contains that kind of tags which its only characteristic is that they are braced between [ ] [caption id="attachment_2948" align="alignnone" width="480" caption="the caption goes here"] How could I remove those? (replace by nothing) I could also run a PHP program if necessary to do the cleanup.

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  • Mysql Query is not working, why?

    - by Furkan Kadioglu
    Im using this example: www.jtable.org Now i download to jtable php version. And i edited script. Jtable simple version is working but my edition is doesnt working. I can do list, but i cant do add a row; this codes having problem. But php doesnt giving any error. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } if you doesnt understand, please ask me question. Where is the problem?

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  • MySQL whats wrong with my foreign keys?

    - by Skiy
    Hello, what is wrong with the two foreign keys which I have marked with comments? create database db; use db; create table Flug( Flugbez varchar(20), FDatum Date, Ziel varchar(20), Flugzeit int, Entfernung int, Primary Key (Flugbez, FDatum)); create table Flugzeugtyp( Typ varchar(20), Hersteller varchar(20), SitzAnzahl int, Reisegeschw int, primary key (Typ) ); create table flugzeug( Typ varchar(20), SerienNr int, AnschDatum Date, FlugStd int, primary key(Typ,SerienNr), foreign key(Typ) references Flugzeugtyp(Typ)); create table Abflug( Flugbez varchar(20), FDatum Date, Typ varchar(20), Seriennr int, Kaptaen varchar(20), Primary key(Flugbez,FDatum,Typ,SerienNr), Foreign key(Flugbez) references Flug(Flugbez), -- Foreign key(FDatum) references Flug(FDatum), Foreign key(Typ) references Flugzeugtyp(Typ) -- ,Foreign key(SerienNr) references Flugzeug(SerienNr) ); When I uncomment these, I get: ERROR 1005 (HY000): Can't create table 'db.abflug' (errno: 150)

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  • Displaying name instead of ID PHP MySQL

    - by Derek
    Hi, I need something simple; I have page where a user clicks an author to see the books associated with that author. On my page displaying the list of books for the author, I want a simple HTML title saying: 'The books for: AUTHORNAME' I can get the page to display author ID but not the name. When the user clicks the link in the previous page of the author, it looks likes this: <a href="viewauthorbooks.php?author_id=<?php echo $row['author_id']?>"><?php echo $row['authorname']?></a> And then on the 'viewauthorbooks.php?author_id=23' I have declared this at the start: $author_id = $_GET['author_id']; $authorname = $_GET['authorname']; And finally, 'The books for: AUTHORNAME, where it says AUTHORNAME, I have this: echo $authorname (With PHP tags, buts its not letting me put them in!) And this doesnt show anything, however if I change it to author_id, it displays the correct author ID that has been clicked, but its not exactly user friendly!! Can anyone help me out!

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  • Fighing system in Php & MYSQL

    - by Gully
    I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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  • Find all those columns which have only null values, in a MySQL table

    - by Robin v. G.
    The situation is as follows: I have a substantial number of tables, with each a substantial number of columns. I need to deal with this old and to-be-deprecated database for a new system, and I'm looking for a way to eliminate all columns that have - apparently - never been in use. I wanna do this by filtering out all columns that have a value on any given row, leaving me with a set of columns where the value is NULL in all rows. Of course I could manually sort every column descending, but that'd take too long as I'm dealing with loads of tables and columns. I estimate it to be 400 tables with up to 50 (!) columns per table. Is there any way I can get this information from the information_schema? EDIT: Here's an example: column_a column_b column_c column_d NULL NULL NULL 1 NULL 1 NULL 1 NULL 1 NULL NULL NULL NULL NULL NULL The output should be 'column_a' and 'column_c', for being the only columns without any filled in values.

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  • How to change data structure in mysql using mysqldump without deleting files

    - by Don Quixote
    Essentially what I'm trying to do is sync a production server with a sandbox server, but only the table structures and stored procedures. The procedures aren't any problem since they can be overriden, but the problem is the tables. I want to sync and alter their structures on the production server using mysqldump (or any other way that you can propose) without altering any existing data. If it helps, I only want to add more columns, not remove any existing ones. Also, I am using mysqlyog. Is there any way to do this?

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  • mysql select update

    - by Tillebeck
    Hi I have read quite a few selcet+update questions in here but cannot understand how to do it. So will have to ask from the beginning. I would like to update a table based on data in another table. Setup is like this: - TABLE a ( int ; string ) ID WORD 1 banana 2 orange 3 apple - TABLE b ( "comma separated" string ; string ) WORDS TEXTAREA 0 banana -> 0,1 0 orange apple apple -> BEST:0,2,3 ELSE 0,2,3,3 0 banana orange apple -> 0,1,2,3 Now I would like to for each word in TABLE a append ",a.ID" to b.WORDS like: SELECT id, word FROM a (for each) -> UPDATE b SET words = CONCAT(words, ',', a.id) WHERE b.textarea like %a.word% Or even better: replace the word found in b.textarea with ",a.id" so it is the b.textarea that ends up beeing a comma separeted string of id's... But I do not know if that is possible.

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  • An array of MySQL results...

    - by Michael Falk
    What am I doing wrong here? I am attempting to return a json object and I can't seem to get past the array... I've built hundreds of regular array and returned them as a json object but I am having a hard time wrapping my head around this one. $rows = array(); $post_array = array(); $i = 0; $result = mysql_query(" SELECT * FROM forum_posts WHERE permalink = '$permalink' AND LOWER(raw_text) LIKE '%$str%' " ); while($row = mysql_fetch_assoc($result)) { $post_array[$i] = $rows[ "id" => htmlentities($row["id"]), "post_content" => htmlentities($row["content"]), "author" => $row["author"], "last_updated" => $row["last_updated"], "author_id" => $row["author_id"], "editing_author" => $row["editing_author"], "date" => $outputQuoteDate ]; $i++; }

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  • formatting mysql data for ouptut into a table

    - by bsandrabr
    Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

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  • SQL query: Last but one rank for user

    - by Derk
    My table structure looks like this: create table rankings ( id IDENTITY NOT NULL, user_id INT NOT NULL, game_poule_id INT NOT NULL, rank INT NOT NULL, insertDate DATETIME NOT NULL, FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE, FOREIGN KEY (game_poule_id) REFERENCES game_poules(id) ON DELETE CASCADE ); All old rankings of users per game are saved in this table. Now I want to have the last but one rank in the table for all users in a gamepoule. Has someone an idea how to achive this? Thanks

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  • Unserialize data and check it against an id in MySQL

    - by kylex
    I have a row of IDs in a database that has been serialized. What I'm trying to do is check those serialized IDs against a known ID to see if it should be excluded or not. for example: "SELECT * FROM mydb WHERE id = 4 AND checkID != 'an id in the serialized column' " What's the best way to go about this?

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  • MS Access query for time

    - by nisha
    following data and using MS Access with VB6 UserID UserName LogTime LogDate 1 S 9:00 21/5/2010 1 S 10:00 21/5/2010 1 S 11:00 21/5/2010 1 S 12:00 21/5/2010 1 S 14:00 21/5/2010 1 S 17:00 21/5/2010 Need Output as in below 6 columns:- 1 S 21/5/2010 9:00 21/5/2010 10:00 1 S 21/5/2010 11:00 21/5/2010 12:00 1 S 21/5/2010 14:00 21/5/2010 17:00

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  • PHP & MySQL checked checkbox problem

    - by BeepU
    I'm trying to check if the checkbox has been checked and display the check mark for the user to see when they check there account settings. I want to know how can I fix this problem using PHP so that the check mark is displayed every time the user views their account settings? Here is the HTML. <input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" />

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  • C#:checking existing record in database Mysql

    - by Meko
    HI.I searched this question inform and I found solution to change column property Unique Index.Now If I try to insert same record cmd.ExecuteNonQuery() gives error that record exist ,but how can use this exception to give user a message that record exist and must enter new one ? I am trying to make some thing like if(cmd.ExecuteNonQuery() !=true ) { MessageBox.Show("User Exists"); } But I dont know what returns cmd.ExecuteNonQuery() ? Or I must get records using reader in table and compare them with text in Textfiel?

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  • mySql Delete only removes the data not the entire entry

    - by Mick
    Hi all I have this line in my php code $insert = "DELETE FROM allocation_table WHERE job = '$jobnumber' " ; Mysql_query ($insert) ; The problem is it will remove all the values from the the one line in my table but not the entry itself. as you can see in the picture if I delete where job = 315 , it does not delete the line but does delete all the entries Yet in this code that preceeds it (a different table) . it works fine and the whole line is removed $insert = "DELETE FROM event WHERE jobnumber = '$jobnumber' " ; mysql_query ($insert) ;enter code here can anyone offer some advice please ??

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  • Help with PHP MySQL join

    - by kester martinez
    Please help me to understand proper join syntax. I have table named inventory which has: trans_id trans_items items -> item_id trans_user employees -> person_id trans_date trans_comment trans_inventory As you can see above, trans_items is a foreign key in items table, and trans_user is a foreign key in employees table. Now what I want to do is to display in HTML the inventory table, but instead of displaying the item id, I want the ITEM NAME to be displayed. Here is what I have done. Please note I'm using CodeIgniter. public function getData(array $inputs) { $this->db->select('trans_items, trans_user, trans_date, trans_inventory, trans_comment'); $this->db->from('inventory'); $this->db->order_by('trans_date desc'); return $this->db->get()->result_array(); }

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