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  • Retrieving data from MySQL in one SQL statement

    - by james.ingham
    Hi all, If I'm getting my data from Mysql like so: $result = $dbConnector->Query("SELECT * FROM branches, businesses WHERE branches.BusinessId = businesses.Id ORDER BY businesses.Name"); $resultNum = $dbConnector->GetNumRows($result); if($resultNum > 0) { for($i=0; $i < $resultNum; $i++) { $row = $dbConnector->FetchArray($result); // $row['businesses.Name']; // $row['branches.Name']; echo $row['Name']; } } Does anyone know how to print the field Name in businesses and how to print the name from branches? My only other alternative is to rename the fields or to call Mysql with two seperate queries. Thanks in advance

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  • Twitter Trends API weekly.json causing error "Cannot use object of type stdClass as array"

    - by tucson
    I have the following PHP code: $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$URL); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); $result = curl_exec($ch); curl_close($ch); $obj = json_decode($result); foreach ($obj[0]->trends as $trend) echo utf8_decode($trend->name); which works fine for URL #1 (into the variable $URL): http://api.twitter.com/1/trends/1.json?exclude=hashtags but causes an error "Cannot use object of type stdClass as array" for URL #2: http://api.twitter.com/1/trends/weekly.json?exclude=hashtags I have searched for a while, but can't figure out a code to fix this and handle both URLs. Any help would be much appreciated.

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  • PHP preg_replace() pattern, string sanitization.

    - by Otar
    I have a regex email pattern and would like to strip all but pattern-matched characters from the string, in a short I want to sanitize string... I'm not a regex guru, so what I'm missing in regex? <?php $pattern = "/^([\w\!\#$\%\&\'\*\+\-\/\=\?\^\`{\|\}\~]+\.)*[\w\!\#$\%\&\'\*\+\-\/\=\?\^\`{\|\}\~]+@((((([a-z0-9]{1}[a-z0-9\-]{0,62}[a-z0-9]{1})|[a-z])\.)+[a-z]{2,6})|(\d{1,3}\.){3}\d{1,3}(\:\d{1,5})?)$/i"; $email = 'contact<>@domain.com'; // wrong email $sanitized_email = preg_replace($pattern, NULL, $email); echo $sanitized_email; // Should be [email protected] ?> Pattern taken from: http://fightingforalostcause.net/misc/2006/compare-email-regex.php (the very first one...)

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  • PHP, MVC, 404 - How can I redirect to 404?

    - by Doug
    I'm trying to build my own MVC as a practice and learning experience. So far, this is what I have: <?php require "config.php"; $page = $_GET['page']; if( isset( $page ) ) { echo "isset is true"; if( file_exists( MVCROOT . "/$page.php" ) ) { include "$page.php"; } else { header("HTTP/1.0 404 Not Found"); } } ?> My problem here is, I can't use header to send to a 404 because the headers have been send already. Should I just redirect to a 404.html or is there a better way? Feel free to critique what I have so far (it's very little). I would love suggestions and ideas. Thanks!

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  • CSS Margin Top Issues

    - by Denoteone
    Not sure why I am having such a hard time with this. Trying to add a 10px top margin to a that is inside of a div. But that does not add the gutter I want and just pushes the containing div down 10px. Styles #item{width:738px; height:168px; background-image:url(../images/item_bg.png);margin:0px auto;} #description{width:314px; height:55px;} #description p{font:12px arial; color:#666666;margin:10px 0 0 30px;} HTML/PHP echo "<div id='item'> <div id='description'><p>{$row['description']}</p></div> </div>"; If I use padding it works fine but I want to know why margin-top isn't working?

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  • CakePHP Shell issue

    - by aboxy
    Hello, I am just getting started with Cakephp shell and running into issues. My cake core library is under path d:/libs/cake My app is setup under d:/servers/htdocs/myapp I wrote a test shell under d:/servers/htdocs/myapp/vendor/shells class ReportShell extends Shell { var $uses = array('Appt'); function main() { echo $this->Appt->find('first'); } } When I try to run this code from d:/servers/htdocs/myapp , It gives me an error Warning: include_once(d:/servers/htdocs/myapp/config/database.php): failed to open stream: No such file or directory in d:/libs/cake\libs\mode l\connection_manager.php on line 23 Warning: include_once(): Failed opening 'd:/servers/htdocs/myapp/config/database.php' for inclusion (include_path='.;D:\work\xampp\php\PEAR') in d:/libs/cake\libs\model\connection_manager.php on line 23 Fatal error: ConnectionManager::getDataSource - Non-existent data source default in d:/libs/cake\libs\model\connection_manager.php on line 102 Reason is that it is trying to find database.php under 'd:/servers/htdocs/myapp/config/' and the correct path is 'd:/servers/htdocs/myapp/app/config/database.php' What am I doing wrong here? thanks

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  • PHP: System Timezone Setting error

    - by marknt15
    Hi, I'm trying to use PHP in the terminal under MAMP but I got an error related to the system's timezone settings. How can I fix this error? $/Applications/MAMP/bin/php5/bin/php echo.php PHP Strict Standards: PHP Startup: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'Asia/Manila' for 'PHT/8.0/no DST' instead in Unknown on line 0 Thanks

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  • Better explanation of $this-> in this example please

    - by Doug
    Referring to this question: http://stackoverflow.com/questions/2035449/why-is-oop-hard-for-me class Form { protected $inputs = array(); public function makeInput($type, $name) { echo '<input type="'.$type.'" name="'.$name.'">'; } public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); } public function run() { foreach($this->inputs as $array) { $this->makeInput($array['type'], $array['name']; } } } $form = new form(); $this->addInput("text", "username"); $this->addInput("text", "password");** Can I get a better explanation of what the $this->input[] is doing in this part: public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); }

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  • Passing parameters to Javascript using PHP

    - by ayush
    I have the following line of code: <a href="javascript:;" onClick="tweeet('myid')">My Tweets!</a> Now while this is working perfectly fine the following line is not: <a href="javascript:;" onClick="tweeet(<?php echo 'myid'; ?>)">My Tweets!</a> Can anyone help me out why it is not working and suggest any changes? The variable I want to pass to the Javascript function is a PHP variable. I have tried the PHP with single quotes and double quotes but it is not working.

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  • Set two classes from array

    - by Thomas
    I want to change the classes on every third output from a query: <?php $style_classes = array('box','box','box no_right_margin'); $style_index = 0; ?> I set this on the div: <div <?php $k = $style_index%4; echo "class=$style_classes[$k]"; $style_index++; ?>> On the third div I want the class to look like this: <div class="box no_right_margin"> Right now it looks like: <div class="box" no_right_margin>

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  • INET_ATON() and INET_NTOA() in PHP?

    - by blerh
    I want to store IP addresses in my database, but I also need to use them throughout my application. I read about using INET_ATON() and INET_NTOA() in my MySQL queries to get a 32-bit unsigned integer out of an IP address, which is exactly what I want as it will make searching through the database faster than using char(15). The thing is, I can't find a function that does the same sort of thing in PHP. The only thing I came across is: http://php.net/manual/en/function.ip2long.php So I tested it: $ip = $_SERVER['REMOTE_ADDR']; echo ip2long($ip); And it outputs nothing. In the example they gave it seems to work, but then again I'm not exactly sure if ip2long() does the same thing as INET_ATON(). Does someone know a PHP function that will do this? Or even a completely new solution to storing an IP address in a database? Thanks.

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  • pass jQuery value to php

    - by andrew
    Hi, for example, i have got this value in my php file: <script type="text/javascript"> function altcat(id) { $ogzu = id; } </script> i want to use $ogzu value in php. is it possible? can i pass a value to php from jquery? i need to learn this answer. can anyone help me please? thanks and regards edit: thanks for your kindly replies. i wanted to use $ogzu value in php like that: <?php echo "<a href='".$ogzu."'>test link</a>"; ?> well, i know its wrong. its already not working. i want to learn if we are able to use jquery values in php? thanks again friends. regards

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  • Display data requested by an ajax.load() call once complete, not during the call.

    - by niczoom
    My jQuery code (using ajax) request's data from a php script (pgiproxy.php) using the following function: function grabPage($pageURL) { $homepage = file_get_contents($pageURL); echo $homepage; } I then extract the html code i need from the returned data using jQuery and insert it into a div called #BFX, as follows: $("#btnNewLoadMethod1").click(function(){ $('#temp1').load('pgiproxy.php', { data : $("#formdata").serialize(), mode : "graph"} , function() { $('#temp').html( $('#temp1').find('center').html() ); $('#BFX').html( $('#temp').html() ); }); }); This works fine. I get the html data (which is a gif image) i need displayed on screen in the correct div. The problem is i can see the html data loading into the div (dependant on network speed), but what I want is to insert the extracted html code into #BFX ONLY when the ajax request has fully completed.

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  • PHP MVC: How to implement an effective Controller/View Association like ZendFramework guys do!

    - by Navi
    Hi, I am making my own PHP-MVC framework. i have a question regarding Controller and View Association. I love the way Zend framework uses view within Controller as follow: $this->view->data = 'Data here'; so it can be used in view as follow: echo $this->data; I am wondering how can i implement this association. I want to remove codes between /** **/ and want to replace with some magic functions. My codes for controller as as follow: class UserController extends Controller{ /************************************/ public function __construct(){ $this->view = new View(); $this->view->setLayout( 'home' ); } function __destruct(){ $this->view->render(); } /************************************/ public function index(){ $this->redirect('user/login'); } public function login(){ } public function register(){ } public function forgotPassword(){ } } Thanks and best regards, -Navi

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  • Troubles with DateTime and PHP 5.2

    - by Nate Wagar
    I'm attempting to use the PHP DateTime class on a server with PHP 5.2.6, with a test server running PHP 5.3. Here is the code: <?php try { $dt = new DateTime('2009-10-08'); $dt->setDate(2009,10,8); print_r($dt); }catch (Exception $e) { echo $e->getMessage(); } On the test server, things work flawlessly, this is what prints: DateTime Object ( [date] => 2009-10-08 00:00:00 [timezone_type] => 3 [timezone] => America/New_York ) On the server I need to use it on, however, this is what prints: DateTime Object ( ) Removing the setDate makes no difference whatsoever. Any ideas why this might be happening? Thanks!

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  • php extract data from mysql

    - by florin
    I have this mysql table with the following rows: id_cont suma_lun month year -------------------------------------------- FL28 2133 March 2012 FL28 2144 April 2012 FL28 2155 May 2012 FL28 2166 June 2012 How can i extract suma_lun, month and year foreach id_cont? so that i get an output like this: ID: Month: Monthly Sum: Year: ---------------------------------------------- FL28 March 2133 2012 April 2144 2012 May 2155 2012 June 2166 2012 This is my current code: $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db(DB_DATABASE,$link); $sql="SELECT * FROM test WHERE id_cont = '$cur'"; $result=mysql_query($sql); while ($row=mysql_fetch_array($result)) { $a=$row["id_cont"]; $b=$row["suma_lun"]; $c=$row["month"]; $d=$row["year"]; } I echo the data in a table Thanks!

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  • Bash Scripting: I want to open a set of .php files, and add line before html tag

    - by Bashn00b
    Hi guys, I have a set of .php files in a folder, I want to add text just before these lines: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > What i want is to insert just before these lines in the html file. So just want to prepend that file before each docType declaration. However the DOCTYPE declaration is never on line 1, as there is loads of php lines before. I have this current script (where FE is the folder containing all the scripts i want to edit): for file in ${fe}*; do echo "$file" done Thanks,

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  • Can't get Javac to work on Mac OS X

    - by elguapo-85
    I am trying to compile with javac on Snow Leopard through the command line. I have Xcode installed. I am just using a simple Hello World file, it works in Eclipse but I can't get it to work using javac. javac -version returns javac 1.6.0_17 HelloWorld.java public class HelloWorld { public static void main(String[] args) { String message = "Welcome to Java!"; System.out.println(message); } } I type: javac HelloWorld.java and get the following error. HelloWorld.java:1: class, interface, or enum expected public class HelloWorld ^ 1 error and... javac -cp . HelloWorld.java returns the same. echo $CLASSPATH just returns blank. Thanks for the help.

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  • Loading var from PHP script using flash

    - by webnoob
    Hi All, I am trying to get a var from a PHP script running on my web server and from every forum post I have read, what I am doing should be working. I have the following: var lvContent = new LoadVars(); lvContent.load("http://{MY_DOMAIN}/Includes/getID.php"); trace("ID: " + lvContent.pageID); The problem is that ID in the trace is always undefined. I have tried the following in the php file: <?php echo "pageID=29"; ?> This is a small test to try and get it working but I cannot seem to. Am I doing something wrong? Thanks in advance for the help. I am using ActionScript 2.0

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  • PHP Serialization Will not work correctly.

    - by stevoo
    Hi, I am developing and doing all the testing on a local machine using PHP Version 5.3.3-1ubuntu9.1 version. The host machine is PHP Version 5.2.15. All the seriliaze arguments are identical. The problems is when i try to login the user on my test local machine i do the following : $user->getByUserId($results['id'],$db); $_SESSION['user'] = serialize($user); which retrieved me and serialize the user. and i just load it back when ever i detect that a session exists $user->LoadFromObject(unserialize($_SESSION['user'])); This works perfectly on my test machine. Just transfered the files on the host to see if i can get a beta version out but i keep on getting Warning: unserialize() expects parameter 1 to be string, object given in /home/gamerent/public_html/beta/includes/header.php on line 19 i have noticed that if i echo the $_SESSION['user'] in both system the test will indeed display me the serializated one but the main one will just show me the object and will not serialize the $user

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  • Why doesn't this piece of php code work?

    - by Sam Gabriel
    Hey guys, I have a mysql database which stores an id for each picture, as well as the picture's url and its thumbnail url. the thumbnail url is something like thumbs/pic.jpg and the page I'm creating has the folder thumbs in the same place it is created. But when I run this piece of code, nothing shows up: <?php ini_set('display_errors', 'On'); error_reporting(E_ALL | E_STRICT); mysql_connect("localhost", "***", "***") or die(mysql_error()); mysql_select_db("pics") or die(mysql_error()); $results = mysql_query("select id from classpics") or die(mysql_error()); $data=mysql_fetch_array($results); foreach($data as $uno) { echo '<td valign="middle" align="center"><a class="neutral" href="../images.php?id=' . $uno['id'] . '"><img src="'. $uno['thumbs'].'" border="0" /></a></td>'; } ?>

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  • how to solve the captcha problem

    - by magna
    ho i have writen this code for my captcha. i created my captcha for contact form everything works fine but what er the number i entered in captcha box it shows invalid captcha `` <?php if(isset($_POST['norobot'])) { if(md5($_POST['norobot']) == $_SESSION['randomnr2']) { echo "Validation Success"; $_SESSION['name'] = $name ; $_SESSION['phone_no'] = $phone; $_SESSION['mailid'] = $mailid; $_SESSION['msg'] = $msg; $_SESSION['category'] = $category; header("Location:thankyou.php"); } else { $Error = 'Invalid CAPTCHA'; } } } ?> can any one say the solution. thanks

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  • How to substr html entities properly?

    - by Emily
    Hi everyone. I have like this : $mytext="that&#039;s really &quot;confusing&quot; and &lt;absolutly&gt; silly"; echo substr($mytext,0,6); The output in this case will be : that&# instead of that's What i want is to count html entities as 1 character then substr, because i always end up with breaked html or some obscure characters at the end of text. Please don't suggest me to html decode it then substr then encode it, i want a clean method :) Thanks

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  • Korn Shell - Test with variable that may be not set

    - by C. Ross
    I have the following code in KornShell FAILURE=1 SUCCESS=0 isNumeric(){ if [ -n "$1" ]; then case $1 in *[!0-9]* | "") return $FAILURE; * ) return $SUCCESS; esac; else return $FAILURE; fi; } #... FILE_EXT=${FILE#*.} if [ isNumeric ${FILE_EXT} ]; then echo "Numbered file." fi #... In some cases the file name not have an extension, and this causes the FILE_EXT variable to be empty, which causes the following error: ./script[37]: test: 0403-004 Specify a parameter with this command. How should I be calling this function so that I do not get this error?

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  • PHP Connect to 4D Database

    - by Matt Reid
    Trying to connect to 4D Database. PHPINFO says PDO is installed etc etc... Testing on localhost MAMP system. However when I run my code I get: Fatal error: Uncaught exception 'PDOException' with message 'could not find driver' in /Applications/MAMP/htdocs/4d/index.php:12 Stack trace: #0 /Applications/MAMP/htdocs/4d/index.php(12): PDO->__construct('4D:host=127.0.0...', 'test', 'test') #1 {main} thrown in /Applications/MAMP/htdocs/4d/index.php on line 12 My code is: $dsn = '4D:host=127.0.0.1;charset=UTF-8'; $user = 'test'; $pass = 'test'; // Connection to the 4D SQL server $db = new PDO($dsn, $user, $pass); try { echo "OK"; } catch (PDOException $e) { die("Error 4D : " . $e->getMessage()); } Can't put my finger on the error, i'm using the settings under the PHP tab... Thank you.

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