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  • codeigniter csrf protection with ajax

    - by Yarandi
    i have a small problem here which i cannot fix,This post goes through but the response returns a “500 internal server error” who to fix it? JS in view: function load(value) { var utype = value; if(utype>0) { new Ajax.Request('<?php echo base_url().'another/load';?>'+'/'+utype, { method:'post', onSuccess: function(transport){ var response = transport.responseText || "no response text"; if(response!="no response text") document.getElementById('prog_id').innerHTML = response; }, onFailure: function(){ alert('Something went wrong ...') } }); } error in firebug : An Error Was Encountered The action you have requested is not allowed. when i change CSRF protection to False in config file its work for me.but i want protect this request with CSRF enabled. after search in CI forum i found this this link codeigniter-csrf-protection-with-ajax but i cant solve by it.can any one help me?

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  • Outputting an HTML entity character from a helper function

    - by morpheous
    I am using Symfony 1.3.2 on Ubuntu. I have written a little helper function (statsfoo) that prints out summary statistics about an item. I am using the helper function in my template like this: // In StatsHelper.php <?php function statsfoo($some_param) { return "<div class=\"sfoo\">&9830; the stats number for item is 42</div>" } //In showStatsSuccess.php <?php use_helper(Stats); <?php echo statsfoo($foobar, ESC_ENTITIES); I tried both ESC_ENTITIES and ESC_RAW. In both instances, the raw number (&9830) was displayed in the page. I want to display the diamond instead. What am I doing wrong and how can I fix this?

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  • Wordpress: Not able to retrieve css for new plugin in admin mode

    - by Steven
    I'm creating a new plugin which will have it's own css file. The css file resides in the root folder of the plugin. In the plugin section of the admin interface, I have added a few text fields fields. But the CSS is not applied. I'm adding the CSS file using this code: // Register styling add_action('admin_init', 'event_styles'); function event_styles() { wp_register_style('event_cal', plugins_url('eventcall.css',__FILE__)); wp_enqueue_style('event_cal'); } The following code gives me the CSS path: echo plugins_url('eventcall.css',__FILE__); and outputs http://mysite.com/wp-content/plugins/wp-eventcal/eventcall.css If I try to enter this URL directly in the browser, it only shows me the front page. And if I look in the source code using Firebug, where the link to the CSS should be, I only find the entire HTML code for the front page. Am I using wrong code to use backend in admin interface? In my HOST file, I have added ``

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  • Korn Shell - Test with variable that may be not set

    - by C. Ross
    I have the following code in KornShell FAILURE=1 SUCCESS=0 isNumeric(){ if [ -n "$1" ]; then case $1 in *[!0-9]* | "") return $FAILURE; * ) return $SUCCESS; esac; else return $FAILURE; fi; } #... FILE_EXT=${FILE#*.} if [ isNumeric ${FILE_EXT} ]; then echo "Numbered file." fi #... In some cases the file name not have an extension, and this causes the FILE_EXT variable to be empty, which causes the following error: ./script[37]: test: 0403-004 Specify a parameter with this command. How should I be calling this function so that I do not get this error?

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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  • What's the best way to format long strings of HTML in PHP?

    - by dclowd9901
    I know it's really a subjective question, but for best-practices (and readability), I can't seem to get a fix on the best way to format long strings of HTML. I typically do it like this: echo ' <div> <p>Content Inside</p> <div class="subbox"> <ul> <li>etc.</li> <li>etc.</li> <li>etc.</li> <li>etc.</li> </ul> </div> </div> '; But I still don't like the outcome, especially if this appears in the middle of a large block of code. It just feels messy.

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  • Why I am getting type error undefined from my jquery from my php json?

    - by Brained Washed
    I don't know what is wrong is am I just missing something, all my expected data is successfully receive based on firebug' console tab the problem is displaying the data. Here's my jquery code: success: function(data){ var toAppend = ''; if(typeof data === "object"){ for(var i=0;i<data.length;i++){ toAppend += '<tr><td colspan="2">'+data[i]['main-asin'][0]+'</td></tr>'; toAppend += '<tr><td>'+data[i]['sub-asin'][0]+'</td><td></td></tr>'; } $('.data-results').append(toAppend); } } Here's my php code: foreach($xml->Items->Item as $item){ $items_from_amazon[] = array('main-asin'=>$item->ASIN); foreach($xml->Items->Item->Variations->Item as $item){ $items_from_amazon[] = array('sub-asin'=>$item->ASIN); } } echo json_encode($items_from_amazon); //return amazon products And here's the result from my firebug:

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  • Get only new RSS entries with PHP Script ?

    - by ArneRie
    What im trying to do: Fetch X numbers of RSS Feeds from my Blogs and echo only new entries. My Problem is, how to know wich items are already parsed? Solution so far: Fetch the Feed every 5 hours, store all titles inside an Database table or flat file. Next run check if the title is already in database if not print it and save it inside the database. But iam not sure if this is best practise to do this? If someone knows a fast way, it would be great. Sorry for my poor english.

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  • Unable to open a file for writing

    - by asdasdas
    I am trying to write to a file. I do a file_exists check on it before I do fopen and it returns true (the file does exist). However, the file fails this code and gives me the error every time: $handle = fopen($filename, 'w'); if($handle) { flock($handle, LOCK_EX); fwrite($handle, $contents); } else { echo 'ERROR: Unable to open the file for writing.',PHP_EOL; exit(); } flock($handle, LOCK_UN); fclose($handle); Is there a way I can get more specific error details as to why this file does not let me open it for writing? I know that the filename is legit, but for some reason it just wont let me write to it. I do have write permissions, I was able to write and write over another file.

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  • VBScript - copy files modified in last 24 hours

    - by Martin North
    Hi, I'm trying to copy files from a directory where the last modified date is within 24hours of the current date. I'm using a wildcard in the filepath as it changes every day I'm using; option explicit dim fileSystem, folder, file dim path path = "d:\x\logs" Set fileSystem = CreateObject("Scripting.FileSystemObject") Set folder = fileSystem.GetFolder(path) for each file in folder.Files If DateDiff("d", file.DateLastModified, Now) < 1 Then filesystem.CopyFile "d:\x\logs\apache_access_log-*", "d:\completed logs\" WScript.Echo file.Name & " last modified at " & file.DateLastModified end if next Unfortunately this seems to be copying all files, and not just the recently modified ones. Can anyone point me in the right direction? many thanks Martin.

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  • PHP math gets crazy, need explanation, my brain is melting

    - by derei
    I know that playing with php float can give strange results if you try to add "goats + apples", but please take a look to the following case: $val = 1232.81; $p1 = 1217.16; $p2 = 15.65; $sum = $p1 + $p2; $dif = $val - $sum; echo $dif; It will give you -2.2737367544323E-13 ... yeah, ALMOST zero, but then why it doesn't say 0 ? This freaks me out big time. Please, I need some valid explanation.

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  • Substring extraction using bash shell scripting and awk

    - by rohanbk
    So, I have a file called 'dummy' which contains the string: "There is 100% packet loss at node 1". I also have a small script that I want to use to grab the percentage from this file. The script is below. result=`grep 'packet loss' dummy` | awk '{ first=match($0,"[0-9]+%") last=match($0," packet loss") s=substr($0,first,last-first) print s}' echo $result I want the value of $result to basically be 100% in this case. But for some reason, it just prints out a blank string. Can anyone help me?

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  • Compare output of program to correct program using bash script, without using text files

    - by Doug
    I've been trying to compare the output of a program to known correct output by using a bash script without piping the output of the program to a file and then using diff on the output file and a correct output file. I've tried setting the variables to the output and correct output and I believe it's been successful but I can't get the string comparison to work correctly. I may be wrong about the variable setting so it could be that. What I've been writing: TEST=`./convert testdata.txt < somesampledata.txt` CORRECT="some correct output" if [ "$TEST"!="$CORRECT" ]; then echo "failed" fi

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  • Add links to specific words within span tag in PHP

    - by dazhall
    I have a list of words that I'd like to add a link to, I can do this fairly easily using preg_match_all and preg_replace: $str = "<span class=\"cz\">Dám si jedno pivo prosím.</span> = I'll have a beer please."; preg_match_all('/[a-ztúuýžácdéeínórš]+/i',$str,$matches); $matches = array_unique($matches[0]); foreach ($matches as $match) { if(!empty($words[$match])) { $str = preg_replace("/(^|[^\w]){1}(".preg_quote($match,"/").")($|[^\w]){1}/i", '\\1<a href="#">\\2</a>\\3', $str); } } echo $str; What I'd like to do is restrict the linking to only within the span tag. My brain is all regex-ed out, so any help would be appreciated! Thanks! Darren.

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  • How do I rewrite binary data in Java

    - by hayato
    I'm trying to figure out how to replace binary data using Java. below is a PHP example of replacing "foo" to "bar" from a swf file. <?php $fp = fopen("binary.swf","rb"); $size = filesize("binary.swf"); $search = bin2hex("foo"); $replace = bin2hex("bar"); $data = fread($fp, $size); $data16 = bin2hex($data); $data16 = str_replace($search, $replace, $data16); $data = pack('H*',$data16); header("Content-Type:application/x-shockwave-flash"); echo $data; ?> How do I do this in Java.

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  • How can I set the main theme-font dynamically, in WordPress

    - by windyjonas
    I have created a theme where I already have a custom options page where I let the user set text for footer, twitter user and some other things and that works well. Now i'd like to add the functionality of letting the user select which font that should be used for content on the site. How can i accomplish this? I can probably create a php file that outputs something like: <style type="text/css"> body{ font-family: <?php echo get_option('my-font');?>; } </style> and include that file in header.php, but that means that I have to hit php for every request for this css and I want to avoid that if posssible.

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  • PHP and Apache environment variables

    - by Simon
    Hello, I want to pass an environment variable in linux to apache on start up. export MYVAR=5 --I define my environment variable on the command line PassEnv MYVAR --set apache to import the variable in apache config file apachectl restart --when I restart apache I don't get an error message. However I have noticed that if I do not create the environment variable in my first step, I get a warning message, so must be working here echo $_SERVER['MYVAR'] --i try to access the environment variable within PHP but it is not defined I've observed that if I try to PassEnv an environment variable that already exits (one that I havn't created myself) it works fine. The SetEnv directive also works fine. I'd really like to pass an environment variable to apache on the fly without writing it in a file. Help much appreciated. I'm using CentOS, PHP5 and Apache2. Thanks.

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  • CakePHP - radio button not showing error message

    - by teepusink
    Hi, I'm unable to get the error message to show up when creating a radio form using the CakePHP form helper. This is what I have now. $options=array('active'=>'Active','inactive'=>'Inactive'); echo $form->input('Status', array( 'type' => 'radio', 'id' => 'EntryStatus', 'name' => 'data[Entry][status]', 'options' => $options )); What am I missing? I'm using CakePHP 1.2.7 and this is what I have in the validation 'status' = array( 'notempty' = array( 'rule' = 'notempty', 'required' = true, 'message' = 'yo' ) ) Tried the answer from http://stackoverflow.com/questions/1388823/form-helper-for-creating-radio-button-in-cakephp and it's giving me a select option form instead. Thanks, Tee

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  • Website including pages/pages to my site

    - by Azzyh
    Hello.. I have my site on index.html made in html+css., at my index.html i have this div id "content", where you put in main content to the page, and there's a link at the menubar that src to page2.php. When you press on the link it goes to the page2.php, but i want it to display inside the < div "content". In page2 i have Hello this is a test, in a echo.. I dont want to use frames.. should i split up my design on index.php, and then on page2.php include top & footer? or is there another way

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  • change last key name from array in php

    - by robertdd
    i want to be able to change the last key from array i try with this function i made: function getlastimage($newkey){ $arr = $_SESSION['files']; $oldkey = array_pop(array_keys($arr)); $arr[$newkey] = $arr[$oldkey]; unset($arr[$oldkey]); $results = end($arr); //echo json_encode($results); print_r($arr); } if i call the function getlastimage('newkey') it change the key!but after if i print the $_SESSION the key is not changed? why this?

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  • Bash script function return value problem

    - by Eedoh
    Hi to all. Can anyone help me return the correct value from a bash script function? Here's my function that should return first (and only) line of the file passed as an argument: LOG_FILE_CREATION_TIME() { return_value=`awk 'NR==1' $1` return return_value } And here's my call of that function in the other script: LOG_FILE_CREATION_TIME "logfile" timestamp=$? echo "Timestamp = $timestamp" I always get some random values with this code. If, for example, there's a value of 62772031 in the "logfile", I get Timestamp = 255 as an output. For some other values in the file, I get other random values as a return value, never the correct one. Any ideas?

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  • Display loading image while post with ajax

    - by DonJoe
    I know there are thousands of examples on the internet, but I want for the script I already have to display a loading gif image while the data is retrievedd. My java knowledge are poor, therefore I'm asking how to change the following: <script type="text/javascript"> $(document).ready(function(){ function getData(p){ var page=p; $.ajax({ url: "loadData.php?id=<? echo $id; ?>", type: "POST", cache: false, data: "&page="+ page, success : function(html){ $(".content").html(html); } }); } getData(1); $(".page").live("click", function(){ var id = $(this).attr("class"); getData(id.substr(8)); }); }); </script> And my div is here: <div class="content" id="data"></div> Thanks. John

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  • Using md5_file(); doesn't return the md5 sometimes?

    - by Rob
    <?php include_once('booter/login/includes/db.php'); $query="SELECT * FROM shells"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $hash = @md5_file($row['url']); echo $hash . "<br>"; } ?> The above is my code. Usually it works flawlessly on most urls, but every now and then it will just skip the md5 on a line, as if it doesn't retrieve it, even though the file is there. I can't figure out why. Any ideas?

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  • How do I move Zend Framework From Development to Production?

    - by dirtylogic
    I'm just wondering if anyone else has had problems moving the Zend Framework from development to production. I changed my docroot to the public folder, updated my library path, but it's still not working out for me. The IndexController is working just fine, but my ServiceController is giving me an internal server error. ServiceController <?php class ServiceController extends Zend_Controller_Action { public function amfAction() { require_once APPLICATION_PATH . '/models/MyClass.php'; $srv = new Zend_Amf_Server(); $srv->setClass('Model_MyClass', 'MyClass'); echo $srv->handle(); exit; } }

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  • Extract a sentence out of sentences separated by delimitors

    - by Laura
    Below is a sample line I have extracted from a website: below a satisfactory level; &quot;an off year for tennis&quot;; &quot;his performance was off&quot; The output displays as: below a satisfactory level; "an off year for tennis"; "his performance was off" I want to get only the first sentence "below a satisfactory level"; Here is the code I have tried after exploring many stackoverflow posts: $data=explode('; ',$str); echo $data[0]; But somehow it is not working. Thanks in advance.

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