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  • Java Port Socket Programming Error

    - by atrus-darkstone
    Hi- I have been working on a java client-server program using port sockets. The goal of this program is for the client to take a screenshot of the machine it is running on, break the RGB info of this image down into integers and arrays, then send this info over to the server, where it is reconstructed into a new image file. However, when I run the program I am experiencing the following two bugs: The first number recieved by the server, no matter what its value is according to the client, is always 49. The client only sends(or the server only receives?) the first value, then the program hangs forever. Any ideas as to why this is happening, and what I can do to fix it? The code for both client and server is below. Thanks! CLIENT: import java.awt.*; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.awt.image.BufferedImage; import java.io.*; import java.net.Socket; import java.text.SimpleDateFormat; import java.util.*; import javax.swing.*; import javax.swing.Timer; public class ViewerClient implements ActionListener{ private Socket vSocket; private BufferedReader in; private PrintWriter out; private Robot robot; // static BufferedReader orders = null; public ViewerClient() throws Exception{ vSocket = null; in = null; out = null; robot = null; } public void setVSocket(Socket vs) { vSocket = vs; } public void setInput(BufferedReader i) { in = i; } public void setOutput(PrintWriter o) { out = o; } public void setRobot(Robot r) { robot = r; } /*************************************************/ public Socket getVSocket() { return vSocket; } public BufferedReader getInput() { return in; } public PrintWriter getOutput() { return out; } public Robot getRobot() { return robot; } public void run() throws Exception{ int speed = 2500; int pause = 5000; Timer timer = new Timer(speed, this); timer.setInitialDelay(pause); // System.out.println("CLIENT: Set up timer."); try { setVSocket(new Socket("Alex-PC", 4444)); setInput(new BufferedReader(new InputStreamReader(getVSocket().getInputStream()))); setOutput(new PrintWriter(getVSocket().getOutputStream(), true)); setRobot(new Robot()); // System.out.println("CLIENT: Established connection and IO ports."); // timer.start(); captureScreen(nameImage()); }catch(Exception e) { System.err.println(e); } } public void captureScreen(String fileName) throws Exception{ Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize(); Rectangle screenRectangle = new Rectangle(screenSize); BufferedImage image = getRobot().createScreenCapture(screenRectangle); int width = image.getWidth(); int height = image.getHeight(); int[] pixelData = new int[(width * height)]; image.getRGB(0,0, width, height, pixelData, width, height); byte[] imageData = new byte[(width * height)]; String fromServer = null; if((fromServer = getInput().readLine()).equals("READY")) { sendWidth(width); sendHeight(height); sendArrayLength((width * height)); sendImageInfo(fileName); sendImageData(imageData); } /* System.out.println(imageData.length); String fromServer = null; for(int i = 0; i < pixelData.length; i++) { imageData[i] = ((byte)pixelData[i]); } System.out.println("CLIENT: Pixel data successfully converted to byte data."); System.out.println("CLIENT: Waiting for ready message..."); if((fromServer = getInput().readLine()).equals("READY")) { System.out.println("CLIENT: Ready message recieved."); getOutput().println("SENDING ARRAY LENGTH..."); System.out.println("CLIENT: Sending array length..."); System.out.println("CLIENT: " + imageData.length); getOutput().println(imageData.length); System.out.println("CLIENT: Array length sent."); getOutput().println("SENDING IMAGE..."); System.out.println("CLIENT: Sending image data..."); for(int i = 0; i < imageData.length; i++) { getOutput().println(imageData[i]); } System.out.println("CLIENT: Image data sent."); getOutput().println("SENDING IMAGE WIDTH..."); System.out.println("CLIENT: Sending image width..."); getOutput().println(width); System.out.println("CLIENT: Image width sent."); getOutput().println("SENDING IMAGE HEIGHT..."); System.out.println("CLIENT: Sending image height..."); getOutput().println(height); System.out.println("CLIENT: Image height sent..."); getOutput().println("SENDING IMAGE INFO..."); System.out.println("CLIENT: Sending image info..."); getOutput().println(fileName); System.out.println("CLIENT: Image info sent."); getOutput().println("FINISHED."); System.out.println("Image data sent successfully."); } if((fromServer = getInput().readLine()).equals("CLOSE DOWN")) { getOutput().close(); getInput().close(); getVSocket().close(); } */ } public String nameImage() throws Exception { String dateFormat = "yyyy-MM-dd HH-mm-ss"; Calendar cal = Calendar.getInstance(); SimpleDateFormat sdf = new SimpleDateFormat(dateFormat); String fileName = sdf.format(cal.getTime()); return fileName; } public void sendArrayLength(int length) throws Exception { getOutput().println("SENDING ARRAY LENGTH..."); getOutput().println(length); } public void sendWidth(int width) throws Exception { getOutput().println("SENDING IMAGE WIDTH..."); getOutput().println(width); } public void sendHeight(int height) throws Exception { getOutput().println("SENDING IMAGE HEIGHT..."); getOutput().println(height); } public void sendImageData(byte[] imageData) throws Exception { getOutput().println("SENDING IMAGE..."); for(int i = 0; i < imageData.length; i++) { getOutput().println(imageData[i]); } } public void sendImageInfo(String info) throws Exception { getOutput().println("SENDING IMAGE INFO..."); getOutput().println(info); } public void actionPerformed(ActionEvent a){ String message = null; try { if((message = getInput().readLine()).equals("PROCESSING...")) { if((message = getInput().readLine()).equals("IMAGE RECIEVED SUCCESSFULLY.")) { captureScreen(nameImage()); } } }catch(Exception e) { JOptionPane.showMessageDialog(null, "Problem: " + e); } } } SERVER: import java.awt.image.BufferedImage; import java.io.*; import java.net.*; import javax.imageio.ImageIO; /*IMPORTANT TODO: * 1. CLOSE ALL STREAMS AND SOCKETS WITHIN CLIENT AND SERVER! * 2. PLACE MAIN EXEC CODE IN A TIMED WHILE LOOP TO SEND FILE EVERY X SECONDS * */ public class ViewerServer { private ServerSocket vServer; private Socket vClient; private PrintWriter out; private BufferedReader in; private byte[] imageData; private int width; private int height; private String imageInfo; private int[] rgbData; private boolean active; public ViewerServer() throws Exception{ vServer = null; vClient = null; out = null; in = null; imageData = null; width = 0; height = 0; imageInfo = null; rgbData = null; active = true; } public void setVServer(ServerSocket vs) { vServer = vs; } public void setVClient(Socket vc) { vClient = vc; } public void setOutput(PrintWriter o) { out = o; } public void setInput(BufferedReader i) { in = i; } public void setImageData(byte[] imDat) { imageData = imDat; } public void setWidth(int w) { width = w; } public void setHeight(int h) { height = h; } public void setImageInfo(String im) { imageInfo = im; } public void setRGBData(int[] rd) { rgbData = rd; } public void setActive(boolean a) { active = a; } /***********************************************/ public ServerSocket getVServer() { return vServer; } public Socket getVClient() { return vClient; } public PrintWriter getOutput() { return out; } public BufferedReader getInput() { return in; } public byte[] getImageData() { return imageData; } public int getWidth() { return width; } public int getHeight() { return height; } public String getImageInfo() { return imageInfo; } public int[] getRGBData() { return rgbData; } public boolean getActive() { return active; } public void run() throws Exception{ connect(); setActive(true); while(getActive()) { recieve(); } close(); } public void recieve() throws Exception{ String clientStatus = null; int clientData = 0; // System.out.println("SERVER: Sending ready message..."); getOutput().println("READY"); // System.out.println("SERVER: Ready message sent."); if((clientStatus = getInput().readLine()).equals("SENDING IMAGE WIDTH...")) { setWidth(getInput().read()); System.out.println("Width: " + getWidth()); } if((clientStatus = getInput().readLine()).equals("SENDING IMAGE HEIGHT...")) { setHeight(getInput().read()); System.out.println("Height: " + getHeight()); } if((clientStatus = getInput().readLine()).equals("SENDING ARRAY LENGTH...")) { clientData = getInput().read(); setImageData(new byte[clientData]); System.out.println("Array length: " + clientData); } if((clientStatus = getInput().readLine()).equals("SENDING IMAGE INFO...")) { setImageInfo(getInput().readLine()); System.out.println("Image Info: " + getImageInfo()); } if((clientStatus = getInput().readLine()).equals("SENDING IMAGE...")) { for(int i = 0; i < getImageData().length; i++) { getImageData()[i] = ((byte)getInput().read()); } } if((clientStatus = getInput().readLine()).equals("FINISHED.")) { getOutput().println("PROCESSING..."); setRGBData(new int[getImageData().length]); for(int i = 0; i < getRGBData().length; i++) { getRGBData()[i] = getImageData()[i]; } BufferedImage image = null; image.setRGB(0, 0, getWidth(), getHeight(), getRGBData(), getWidth(), getHeight()); ImageIO.write(image, "png", new File(imageInfo + ".png")); //create an image file out of the screenshot getOutput().println("IMAGE RECIEVED SUCCESSFULLY."); } } public void connect() throws Exception { setVServer(new ServerSocket(4444)); //establish server connection // System.out.println("SERVER: Connection established."); setVClient(getVServer().accept()); //accept client connection request // System.out.println("SERVER: Accepted connection request."); setOutput(new PrintWriter(vClient.getOutputStream(), true)); //set up an output channel setInput(new BufferedReader(new InputStreamReader(vClient.getInputStream()))); //set up an input channel // System.out.println("SERVER: Created IO ports."); } public void close() throws Exception { getOutput().close(); getInput().close(); getVClient().close(); getVServer().close(); } }

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  • Smaller Chunks of Data

    - by Googler
    I am using a web service to fetch a large amount of data. While sending the request, i receive an error as: Error: ** Please request data in smaller chunks.** Is this a problem with the web services i am fetching the information or a normal rule for fetching the data through internet. May i know the cause of this problem and also how to send the data in smaller chunks to avoid this error.

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  • Cannot connect to Github?

    - by user2973438
    so I tried to push some updates onto my repo on github via terminal on Mac OSX 10.8.4 and it doesn't work. I've been getting the same error many times: Lillys-MacBook-Air:Yuewei Lilly$ git push origin master error: Failed connect to github.com:443; Operation timed out while accessing https://github.com/lillybeans/Yuewei.git/info/refs?service=git-receive-pack fatal: HTTP request failed Some background: I've pushed many projects onto github before using terminal (when I was in Canada). I am currently in Shanghai, China, could it be the GFW? But when I was in Beijing, I was able to push projects onto github still. when I do ping github.com: Lillys-MacBook-Air:Yuewei Lilly$ ping github.com PING github.com (192.30.252.131): 56 data bytes Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 ping: sendto: No route to host Request timeout for icmp_seq 2 ping: sendto: Host is down Request timeout for icmp_seq 3 ping: sendto: Host is down Request timeout for icmp_seq 4 ping: sendto: Host is down Request timeout for icmp_seq 5 ping: sendto: Host is down Request timeout for icmp_seq 6 ping: sendto: Host is down Request timeout for icmp_seq 7 ^C --- github.com ping statistics --- 9 packets transmitted, 0 packets received, 100.0% packet loss Lillys-MacBook-Air:Yuewei Lilly$ I have ShadowSocks (proxy) turned on. Without it I can't access github.com via browser, with it, I can. also when I do "git remote -v" I see both my pull and push remote repos correctly listed. Thank you in advance!

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  • UNC path to a folder on my local computer

    - by xt_20
    Hi all, What's the UNC path to a folder on my local computer, and how can I access it? I have tried: 1. Security for the folder -- set to Everyone Full Control (for now!) 2. Sharing permissions -- set to Everyone Full Control (for now!) I can see the folder in \, but can't go in ( is not accessible.) Error message: "You might not have permission to use this network resource. Contact the administrator of this server to find out if you have access pernmissions. The network location cannot be reached. For information about network troubleshooting, see Windows Help." My computer is not connected to a network.

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  • Ruby on Rails, PHP or C++ for web social network

    - by faya
    Hello, I have chosen diploma work in university. It's a mini social network. But now I am really stuck with which technology I should stick. I am average at C++ ISAPI web services development, below average PHP(had few projects with it) and new to Ruby and its framework RAILS. I have a deadline 1.5 month to develop it(about 5 hours every day after my full time job). Also I heard that its very easy to learn and develop with Ruby on Rails. Considering C++ I know that I have to do lots of coding and work by myself and PHP looks almost the same to me. So I am looking for you skilled developers advise what would you do in my position? Learn RoR, stick with C++ or PHP or maybe use something else?

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  • How to establish a socket connection from iPhone to a Apache server and communicate via PHP?

    - by candoyo
    Hi, I am working on an iPhone game which is depended on a LAMP server. I want to create a "event" based system where the apache server sends an event to the iphone. For this, I am thinking of using "CFStreamCreatePairWithSocketToHost" to connect to port 80 of the apache server. I am able to successfully connect to the server and open a read and write stream via the iPhone, but I am not sure how to send data to the iphone using PHP running from the LAMP server to the iPhone. I think I can use fsockopen in php to open a socket connection and write data to that socket. I tired running this code $fp = fsockopen("tcp://localhost", 80, $errno, $errstr); if (!$fp) { echo "ERROR: $errno - $errstr<br />\n"; } else { echo"writing to socket "; fwrite($fp, "wwqeqweqw eqwe qwe \n"); //echo fread($fp, 26); fclose($fp); echo "done"; } But, I dont see anything being read on the iphone.. Any idea what's going on, or how to accomplish this? Thanks!

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  • Analyzing Python Code: Modulus Operator

    - by Bhubhu Hbuhdbus
    I was looking at some code in Python (I know nothing about Python) and I came across this portion: def do_req(body): global host, req data = "" s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((host, 80)) s.sendall(req % (len(body), body)) tmpdata = s.recv(8192) while len(tmpdata) > 0: data += tmpdata tmpdata = s.recv(8192) s.close() return data This is then called later on with body of huge size, as in over 500,000 bytes. This is sent to an Apache server that has the max request size on the default 8190 bytes. My question is what is happening at the "s.sendall()" part? Obviously the entire body cannot be sent at once and I'm guessing it is reduced by way of the modulus operator. I don't know how it works in Python, though. Can anyone explain? Thanks.

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  • Host ::1 resolves to remote IP

    - by thebuckst0p
    /etc/hosts files usually have this line, ::1 localhost. I thought ::1 was the equivalent of 127.0.0.1/localhost, and from my reading it seems to be the IPv6 version. So I was using it in Apache for firewalling, "Allow from ::1" and it only allowed local. Then suddenly that stopped working, so I pinged ::1 and got a remote IP address. I tracerouted it and it went through my ISP, through some Microsoft server, then another half dozen steps of asterisks... I'm not sure why this would be (the remote IP), but it doesn't seem good. I grep'd my hard drive for the remote IP and it doesn't appear anywhere. Is this some indicator that I'm being hacked, or normal behavior? Maybe my IPv6 settings are wrong? (This is a brand new MacBookPro with Snow Leopard.) Any ideas about this would be great - what is ::1 supposed to be, why would it be remote, should I be worried, how do I get it back to localhost? Thank you!

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  • C automatically assign port

    - by Gary
    Hi, I just wanted to know how to use C to automatically assign a free port (and see what was used) if a specific port number is not provided. For example, i'm using this: struct sockaddr_in address; address->sin_family = AF_INET; address->sin_addr.s_addr = INADDR_ANY; address->sin_port = htons( port ); But how can I replace the sin_port assignment and let C automatically assign for me? Thanks!

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  • Should I close sockets from both ends?

    - by Roman
    I have the following problem. My client program monitor for availability of server in the local network (using Bonjour, but it does not rally mater). As soon as a server is "noticed" by the client application, the client tries to create a socket: Socket(serverIP,serverPort);. At some point the client can loose the server (Bonjour says that server is not visible in the network anymore). So, the client decide to close the socket, because it is not valid anymore. At some moment the server appears again. So, the client tries to create a new socket associated with this server. But! The server can refuse to create this socket since it (server) has already a socket associated with the client IP and client port. It happens because the socket was closed by the client, not by the server. Can it happen? And if it is the case, how this problem can be solved? Well, I understand that it is unlikely that the client will try to connect to the server from the same port (client port), since client selects its ports randomly. But it still can happen (just by chance). Right?

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  • Google Social Graph API, working as intended?

    - by pns
    Hey, I'm experiencing some problems with Google's social graph API. It seems that for some parameters passed to 'otherme' nothing is returned. I'll use Robert Scoble's profiles as an example (as he's a guy sure to be everywhere on the web). If I query: http://socialgraph.apis.google.com/otherme?q=http://twitter.com/scobleizer&pretty=1 I get results, as expected. However, if I query: http://socialgraph.apis.google.com/otherme?q=http://delicious.com/scobleizer&pretty=1 Nothing is returned, even though 'http://delicious.com/scobleizer' is listed in the previous results... Any thoughts? Thanks

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  • Neural Network Basics

    - by Stat Onetwothree
    I'm a computer science student and for this years project, I need to create and apply a Genetic Algorithm to something. I think Neural Networks would be a good thing to apply it to, but I'm having trouble understanding them. I fully understand the concepts but none of the websites out there really explain the following which is blocking my understanding: How the decision is made for how many nodes there are. What the nodes actually represent and do. What part the weights and bias actually play in classification. Could someone please shed some light on this for me? Also, I'd really appreciate it if you have any similar ideas for what I could apply a GA to. Thanks very much! :)

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  • Why do sockets not die when server dies? Why does a socket die when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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  • Javascript XMLHttpRequest Post method

    - by user535617
    Hey So I have a question about posting using an XMLHttpRequest. In theory, if I am to post a username and password to an https domain (which I have yet to get working, unfortunately) would the responseText then change to the next website, or should the text fields become filled in? What normally happens is you navigate to this page via browser, enter a username and password, and it uses a POST method when the submit button is clicked, doing some authentication under the hood and returning a different page. I feel like maybe the responseText should even stay exactly the same (which is what happens now), but I don't know as I have no experience with this kind of thing. this.requests[1].open("POST", "https://" + this.address, true); var query = "target=%2Fcgi-bin%2FStatusConfig.cgi%3FPage%3Dindex&userfile=&username=user&password=pass&log+in=Log+in"; this.requests[1].setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); this.requests[1].setRequestHeader("Content-length", query.length); this.requests[1].setRequestHeader("Keep-Alive", 115); this.requests[1].setRequestHeader("Connection", "keep-alive"); this.requests[1].setRequestHeader("Host", this.address); this.requests[1].send(query); this.requests[1].onreadystatechange = onReadyStateChange1; Then basically onReadyStateChange1 displays the responseText when ready. Any light that could be shed on what SHOULD be happening with the post and responseText would be very appreciated. As would any advice in getting the new, logged into page. For further clarification, what I'm trying to do is log in and then return the new page, because the login page displays only log in information/functionality and the page after logging in has a lot of relevant information. I'm not trying to check the credentials as much as I'm trying to get it (the script) to log in so it can access the next page. Granted, the credentials will have to be valid for that. Thanks all.

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  • Ubuntu problem not connecting to wireless or wired network

    - by ToughPal
    I recently installed openvpn and things were working. But I got a weird screen after a few hours and on restart my wired and wireless connections are not working. Can someone help? cat /etc/network/interfaces auto lo iface lo inet loopback cat /etc/resolv.conf #Generated by NetworkManager Is there anything missing? I tried both wired and wireless and both are not working. Usually if I ever have a problem with wireless, the wired always work! My /etc/network/interfaces is looking wrong. Can you please send me yours? I am using ubuntu 9.10 and the internet was working correctly until today! Please help

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  • Feature categories for a social network

    - by mafutrct
    Not sure if this question belongs on SO. Anyway, please let me try to clarify the issue. I'm currently planning a social program. It's basically a chat server with the major additional ability to play games. I'd like to create categories of features that are offered to users. My question is, are there any useful standard feature categories? Does not have to be specific to my case, I'm interested in the general case as well. Just to give you an idea of what I'm thinking: functional e.g. play games social e.g. chatting operational e.g. 24/7 service availability I'm entirely unsure if this is the right place to ask, if you know of any better site to ask please don't hesitate to add a comment.

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  • one two-directed tcp socket of two one-directed? (linux, high volume, low latency)

    - by osgx
    Hello I need to send (interchange) a high volume of data periodically with the lowest possible latency between 2 machines. The network is rather fast (e.g. 1Gbit or even 2G+). Os is linux. Is it be faster with using 1 tcp socket (for send and recv) or with using 2 uni-directed tcp sockets? The test for this task is very like NetPIPE network benchmark - measure latency and bandwidth for sizes from 2^1 up to 2^13 bytes, each size sent and received 3 times at least (in teal task the number of sends is greater. both processes will be sending and receiving, like ping-pong maybe). The benefit of 2 uni-directed connections come from linux: http://lxr.linux.no/linux+v2.6.18/net/ipv4/tcp_input.c#L3847 3847/* 3848 * TCP receive function for the ESTABLISHED state. 3849 * 3850 * It is split into a fast path and a slow path. The fast path is 3851 * disabled when: ... 3859 * - Data is sent in both directions. Fast path only supports pure senders 3860 * or pure receivers (this means either the sequence number or the ack 3861 * value must stay constant) ... 3863 * 3864 * When these conditions are not satisfied it drops into a standard 3865 * receive procedure patterned after RFC793 to handle all cases. 3866 * The first three cases are guaranteed by proper pred_flags setting, 3867 * the rest is checked inline. Fast processing is turned on in 3868 * tcp_data_queue when everything is OK. All other conditions for disabling fast path is false. And only not-unidirected socket stops kernel from fastpath in receive

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  • Facebook: Social Widgets versus Share

    - by just_wes
    Hello all, I am interested in people's thoughts on Facebook's new social widgets thing. Most notably the new "Like" button. The concept I am struggling with is the difference between "Like" and "Share". I have an existing Connect application. This application has its own fan page on Facebook. People can become "Fans" of the page and register to receive email updates and the like. The application is currently programmed to update its own fan page any time content is added to the site. Enter Social Widgets and "Like". People who visit our site can currently "share" our content on Facebook. With "Share" they can post a full item to their wall with a comment or send the content item as a message to another Facebook user. "Like" seems to do the same thing minus the message part. However "Like" automatically subscribes people to the fan page. My question is simply, should I add "Like" to my existing Connect site? Is "Like" different than what I already have? Are Social Widgets the future of Connect? Thanks!

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  • Basic Client-Server Design for persistent connections?

    - by cam
    Here's as far as I understand it: Client & Server make connection Client sends server data Server interprets data, sends client data So on, and so forth, until client sends disconnect signal. I'm just wondering about implementation. Step 2 and 3 are confusing to me, maybe I'm over-complicating it. Is there anymore to interpreting the data than a giant switch statement? Any good books on client/server design? Specifically talking about multithreaded servers, scalability, and message design (byte 1 = header info, byte 2 = blah blah, etc)? Specifically geared towards C++.

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  • Multiple HTTP requests using sockets in java

    - by codeomnitrix
    How could i send multiple http requests from my java program using sockets. actually i have tried as: import java.net.*; import java.io.*; class htmlPageFetch{ public static void main(String[] args){ try{ Socket s = new Socket("127.0.0.1", 80); DataInputStream dIn = new DataInputStream(s.getInputStream()); PrintWriter dOut = new PrintWriter(s.getOutputStream(), true); dOut.println("GET /mytesting/justCheck.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); boolean more_data = true; String str; int i = 0; while(more_data){ str = dIn.readLine(); if(str==null){ //Now server has stopped sending data //So now write again the inputs dOut.println("GET /mytesting/justCheck1.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); continue; } System.out.println(str); } }catch(IOException e){ } } } But when I send the request again it was not processed? Thank in advance.

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  • Can an application affect TCP retransmits

    - by sipwiz
    I'm troubleshooting some communications issues and in the network traces I am occasionally coming across TCP sequence errors. One example I've got is: Server to Client: Seq=3174, Len=50 Client to Server: Ack=3224 Server to Client: Seq=3224, Len=50 Client to Server: Ack=3224 Server to Client: Seq=3274, Len=10 Client to Server: Ack=3224, SLE=3274, SRE=3284 Packets 4 & 5 are recorded in the trace (which is from a router in between the client and server) at almost exactly the same time so they most likely crossed in transit. The TCP session has got out of sync with the client missing the last two transmissions from the server. Those two packets should have been retransmitted but they weren't, the next log in the trace is a RST packet from the Client 24 seconds after packet 6. My question is related to what could be responsible for the failure to retransmit the server data from packets 3 & 5? I would assume that the retransmit would be at the operating system level but is there anyway the application could influence it and stop it being sent? A thread blocking or put to sleep or something like that?

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