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  • ANSI SQL question - how to insert or update a record if it already exists?

    - by morpheous
    Although I am using mySQL (for now), I dont want any DB specific SQL. I am trying to insert a record if it doesn't exist, and update a field if it does exist. I want to use ANSI SQL. The table looks something like this: create table test_table (id int, name varchar(16), weight double) ; //test data insert into test_table (id, name, weight) values(1,'homer', 900); insert into test_table (id, name, weight) values(2,'marge', 85); insert into test_table (id, name, weight) values(3,'bart', 25); insert into test_table (id, name, weight) values(4,'lisa', 15); If the record exists, I want to update the weight (increase by say 10)

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  • Selecting a radio button when a dropdown value changes

    - by Tim F.
    My setup is something like this: radiobutton1 - selection1 radiobutton2 - selection2 textinput1 I want radiobutton1 to be selected whenever selection1 is changed, and I want radiobutton2 to be selected whenever either selection2 or textinput1 is changed. There has to be a simple javascript solution here... I just can't find it. Here's my actual code ("$semopt" is a string holding the html code for the options on the first selection input): <input type='radio' name='semester' value='existing'/>Existing semester: <select name='sem_id'">$semopt </select><br/> <input type='radio' name='semester' value='new'/>New Semester: <select name='sem_name'"> <option value='Fall'>Fall</option> <option value='Spring'>Spring</option> </select> <input name='sem_year' value='$thisyear' size='5'"/><br/>

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  • Why the following upload if condition does not work?

    - by Ole Media
    So I have an upload script, and I want to check the file type that is being uploaded. I only want pdf, doc, docx and text files So I have: $goodExtensions = array('.doc','.docx','.txt','.pdf', '.PDF'); $name = $_FILES['uploadFile']['name']; $extension = substr($name, strpos($name,'.'), strlen($name)-1); if(!in_array($extension,$goodExtensions) || (($_FILES['uploadFile']['type'] != "applicatioin/msword") || ($_FILES['uploadFile']['type'] != "application/pdf"))){ $error['uploadFile'] = "File not allowed. Only .doc, .docx, .txt and pdf"; } Why I'm getting the error when testing and including correct documents?

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  • Data Modeling Help - Do I add another table, change existing table's usage, or something else?

    - by StackOverflowNewbie
    Assume I have the following tables and relationships: Person - Id (PK) - Name A Person can have 0 or more pets: Pet - Id (PK) - PersonId (FK) - Name A person can have 0 or more attributes (e.g. age, height, weight): PersonAttribute _ Id (PK) - PersonId (FK) - Name - Value PROBLEM: I need to represent pet attributes, too. As it turns out, these pet attributes are, in most cases, identical to the attributes of a person (e.g. a pet can have an age, height, and weight too). How do I represent pet attributes? Do I create a PetAttribute table? PetAttribute Id (PK) PetId (FK) Name Value Do I change PersonAttribute to GenericAttribute and have 2 foreign keys in it - one connecting to Person, the other connecting to Pet? GenericAttribute Id (PK) PersonId (FK) PetId (FK) Name Value NOTE: if PersonId is set, then PetId is not set. If PetId is set, PersonId is not set. Do something else?

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  • question on database query using hibernate in java with annotations

    - by molleman
    Hello, simple question regarding HQL(Hibernate query language) so i have user class , that can hold a list of Projects, how do i take this out of the database depending on a username, this is how i take out my user String username = "stephen"; YFUser user = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", name).uniqueResult(); but i want to take out the list of projects here is the projects list within the class YFUser(my user class); how would i query the database to get this list of projects @Entity @Table(name = "yf_user_table") public class YFUser implements Serializable,ILightEntity { ......... @OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY) @JoinTable(name = "YFUSER_JOIN_PROJECT", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = { @JoinColumn(name = "project_id") }) private List<Project> projects = new ArrayList<Project>();

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  • Why no ArgumentEmptyException in .NET ?

    - by Andrei Rinea
    I am beginning to think I am doing something wrong. I mean they did place System.String.IsNullOrWhitespace finally but no ArgumentEmptyException class. public FilterItem(string name, IEnumerable<string> extensions) { if (string.IsNullOrWhiteSpace(name)) { throw new ArgumentNullException("name"); } if (extensions == null) { throw new ArgumentNullException("extensions"); } if (extensions.Count() == 0) { throw new ArgumentOutOfRangeException("extensions"); } this.Name = name; this.Extensions = extensions; } throwing an ArgumentOutOfRangeException feels unnatural. Also an instance of ArgumentException is too general in my opinion. It's easy to me to create a new exception class call it this way and have it over with. What bugs me is that it's not in the BCL/FCL and I am beginning to think there's a good reason not to have it. Should there be one?

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  • jquery validate check at least one checkbox

    - by Omu
    I have something like this: <form> <input id='roles' name='roles' type='checkbox' value='1' /> <input id='roles' name='roles' type='checkbox' value='2' /> <input id='roles' name='roles' type='checkbox' value='3' /> <input id='roles' name='roles' type='checkbox' value='4' /> <input id='roles' name='roles' type='checkbox' value='5' /> <input type='submit' value='submit' /> <form> I would like to validate that at least one checkbox (roles) should be checked, is it possible with jquery.validate ?

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  • Kohana3 ORM save problem

    - by Bob0101
    Hi, Can anyone help me with Kohana ORM. I can take out name and value. I can give them new values and I try to save them back to base, but in phpmyadmin i can see still old values for these option attributes. What is wrong with this code (it works and echos right value but i can't see it in db): $option = ORM::factory('draft') ->where('user_id', '=', $user_id) ->find() ->draft_options ->where('name', '=', $_POST['name']) ->find(); $option->name = $_POST['name']; $option->value = $_POST['value']; $option->save(); if ($option->saved()) echo Kohana::debug($option->value);

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  • SQL query to return data from two separate rows in a table joined to a master table

    - by Ali
    I have a TWO tables of data with following fields table1=(ITTAG,ITCODE,ITDESC,SUPcode) table2=(ACCODE,ACNAME,ROUTE,SALMAN) This is my customer master table that contains my customer data such as customer code, customer name and so on... Every Route has a supervisor (table1=supcode) and I need to know the supervisor name in my table which both supervisor name and code exist in one table. table1 has contain all names separated by ITTAG. For example, supervisor's name has ITTAG='K'; also salesman's name has ITTAG='S'. ITTAG ITCODE ITDESC SUPCODE ------ ------ ------ ------- S JT JOHN TOMAS TF K WK VIKI KOO NULL Now this is the result which I want ACCODE ACNAME ROUTE SALEMANNAME SUPERVISORNAME ------- ------ ------ ------------ --------------- IMC1010 ABC HOTEL 01 JOHN TOMAS VIKI KOO I hope this this information is sufficient to get the query..

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  • jquery problem with simple code

    - by moustafa
    why this code is not working var name = $("#name").val(); var email = $("#email").val(); var web = $("#web").val(); var comment = $("#comment").val(); if(name.length < 5){ $("#name").css("border-color","red"); } elseif (email.length < 5) { $("#email").css("border-color","red"); } elseif (web.length < 5) { $("#web").css("border-color","red"); } elseif (comment.length < 10) { $("#comment").css("border-color","red"); }else{ alert('ok'); } and each val for one like this <input id="name" type="text" size="24" />

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  • Plural to Singular conversion trouble in Rails Migrations?

    - by Earlz
    Hi, I'm a beginner at Ruby On Rails and am trying to get a migration to work with the name Priorities So, here is the code I use in my migration: class Priorities < ActiveRecord::Migration def self.up create_table :priorities do |t| t.column :name, :string, :null => false, :limit => 32 end Priority.create :name => "Critical" Priority.create :name => "Major" Priority.create :name => "Minor" end def self.down drop_table :priorities end end This results in the following error though: NOTICE: CREATE TABLE will create implicit sequence "priorities_id_seq" for serial column "priorities.id" NOTICE: CREATE TABLE / PRIMARY KEY will create implicit index "priorities_pkey" for table "priorities" rake aborted! An error has occurred, this and all later migrations canceled: uninitialized constant Priorities::Priority Is this some problem with turning ies to y for converting something plural to singular?

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  • MySQL calling in Username to show instead of ID!

    - by Jess
    I have a users table, books table and authors table. An author can have many books, while a user can also have many books. (This is how my DB is currently setup). As I'm pretty new to So far my setup is like bookview.php?book_id=23 from accessing authors page, then seeing all books for the author. The single book's details are all displayed on this new page...I can get the output to display the user ID associated with the book, but not the user name, and this also applies for the author's name, I can the author ID to display, but not the name, so somewhere in the query below I am not calling in the correct values: SELECT users.user_id, authors.author_id, books.book_id, books.bookname, books.bookprice, books.bookplot FROM books INNER JOIN authors on books.book_id = authors.book_id INNER JOIN users ON books.book_id = users.user_id WHERE books.book_id=" . $book_id; Could someone help me correct this so I can display the author name and user name both associated with the book! Thanks for the help :)

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  • Populate properties decorated with an attribute

    - by PUT
    Are there any frameworks that assist me with this: (thinking that perhaps StructureMap can help me) Whenever I create a new instance of "MyClass" or any other class that inherits from IMyInterface I want all properties decorated with [MyPropertyAttribute] to be populated with values from a database or some other data storage using the property Name in the attribute. public class MyClass : IMyInterface { [MyPropertyAttribute("foo")] public string Foo { get; set; } } [AttributeUsage(AttributeTargets.Property)] public sealed class MyPropertyAttribute : System.Attribute { public string Name { get; private set; } public MyPropertyAttribute(string name) { Name = name; } }

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  • Setting instance names on keyframes quickly in AS3

    - by Boon
    Right now in Flash CS3 and up (using Actionscript 3) if you have the same instance that is used in multiple keyframes in a layer, and you decide to assign or change the instance name later, you would have to go to each keyframe and set the instance name. This is a big nuisance. Is there a quicker or better way to do this? NOTE: In AS2, you can set the name by using name property of the MovieClip in your code in the onLoad handler of the MovieClip class so it's done once and for all. Unfortunately in AS3, you are not allowed to set the name property anymore.

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  • Using a ICollection Value in sqlite SELECT parameterized statment

    - by case23
    Im trying to get all the entrys from a sqlite Database which have the same name as the keys in a Hashtable. My Statement looks like this. // the keys from the hashtable are names equivalent // to name entrys in the SomeTable Names Collumn Hashtable names; String query = "SELECT Id, Name FROM SomeTable WHERE Name LIKE (@Names)"; SQLiteCommand command = new SQLiteCommand(query, _databaseConnection); command.Parameters.AddWithValue("@Names", names.Keys); SQLiteDataReader reader = reader.ExecuteReader(); while(reader.Read()) { Console.WriteLine("Name: {0}, ID: {1}", reader[1].ToString(), reader[0].ToString()); } Im totally sure there are similar values in the Database, but i get nothing back and the reader does not execute. Is it impossible to add a ICollection as a Parameter Value so i need to start the reader only one time?

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  • Getting the first image elements id within an unordered list using JQuery

    - by Roland
    I'm trying to get the id of the first element of an unordered list using JQuery. Here's the list <ul class="list"> <li><img id="1" src="image1.jpg" name="image1" /></li> <li><img id="2" src="image2.jpg" name="image2" /></li> <li><img id="3" src="image3.jpg" name="image3" /></li> <li><img id="4" src="image4.jpg" name="image4" /></li> <li><img id="5" src="image5.jpg" name="image5" /></li> </ul> JQuery var id = $('.list li img'):first.attr('id');

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  • Setting minOccurs="0" (required) on web service parameters of type int

    - by Alex Angas
    I have an ASP.NET 2.0 web method with the following signature: [WebMethod] public QueryResult[] GetListData( string url, string list, string query, int noOfItems, string titleField) I'm running the disco.exe tool to generate .wsdl and .disco files from this web service for use in SharePoint. The following WSDL for the parameters is being generated: <s:element minOccurs="0" maxOccurs="1" name="url" type="s:string" /> <s:element minOccurs="0" maxOccurs="1" name="list" type="s:string" /> <s:element minOccurs="0" maxOccurs="1" name="query" type="s:string" /> <s:element minOccurs="1" maxOccurs="1" name="noOfItems" type="s:int" /> <s:element minOccurs="0" maxOccurs="1" name="titleField" type="s:string" /> Why does the int parameter have minOccurs set to 1 instead of 0 and how do I change it? I've tried using [XmlElementAttribute(IsNullable=false)] in the parameter declaration without success.

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  • Jpa subclass mapping

    - by Roy Chan
    I am making a POS like system. I wonder how to map subclass using JPA (this is for my DAO). Product class has product details and OrderProduct class has information about the Product and details about the order. @Entity @Table(name="products") public class Product implements Serializable{ @Id @Column(name="id") @GeneratedValue(strategy = GenerationType.AUTO public int getId(){ return id;} /** Other get/set methods */ } @Entity @Table(name="order_products") public class OrderProduct extends Product{ @Id @Column(name="id") @GeneratedValue(strategy = GenerationType.AUTO) public int getId(){ return id;} /** Other get/set methods */ } I got complain about duplicate @Id. But OrderProduct class really need another id than the product one. How should I map this? DB is something like this Table products id int name varchar(32) Table order_product id int quantity int productid int fk referencing product table Would @IdClass or @AttributeOverride help?

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  • modrewrite RewriteRule problem

    - by timpone
    I am using Apache 2.2 and mod_rewrite. I would like to take the following urls and map them to another url. The pattern is simple and like this: http://domain/test/ex1.html - http://domain/app/index.php/content/?name=ex1 I tried the following in an .htaccess file: RewriteEngine On RewriteBase /app/ RewriteRule (.*)\.html index.php/content/?name=$1 and RewriteEngine On RewriteRule (.*)\.html /app/index.php/content/?name=$1 I wasn't sure if the backreference was correct so set to $0 and $2 but never seemed to help. I also tried setting the RewriteLogLevel to 9. There is a step where it is almost there: rewrite 'ex1.html' - 'index.php/content/?name=ex1' The last line of the rewrite log is as follows: [perdir /var/www/domain/htdocs/test/] internal redirect with /app/index.php/content/ [INTERNAL REDIRECT] How can I get this to rewrite to /app/index.php/content/?name=ex1 ? thanks

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  • Parsing a dynamic value with Lift-JSON

    - by Surya Suravarapu
    Let me explain this question with an example. If I have a JSON like the following: {"person1":{"name": "Name One", "address": {"street": "Some Street","city": "Some City"}}, "person2":{"name": "Name Two", "address": {"street": "Some Other Street","city": "Some Other City"}}} [There is no restriction on the number of persons, the input JSON can have many more persons] I could extract this JSON to Persons object by doing var persons = parse(res).extract[T] Here are the related case classes: case class Address(street: String, city: String) case class Person(name: String, address: Address, children: List[Child]) case class Persons(person1: Person, person2: Person) Question: The above scenario works perfectly fine. However the need is that the keys are dynamic in the key/value pairs. So in the example JSON provided, person1 and person2 could be anything, I need to read them dynamically. What's the best possible structure for Persons class to account for that dynamic nature.

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  • MVC Razor Engine For Beginners Part 1

    - by Humprey Cogay, C|EH, E|CSA
    I. What is MVC? a. http://www.asp.net/mvc/tutorials/older-versions/overview/asp-net-mvc-overview II. Software Requirements for this tutorial a. Visual Studio 2010/2012. You can get your free copy here Microsoft Visual Studio 2012 b. MVC Framework Option 1 - Install using a standalone installer http://www.microsoft.com/en-us/download/details.aspx?id=30683 Option 2 - Install using Web Platform Installer http://www.microsoft.com/web/handlers/webpi.ashx?command=getinstallerredirect&appid=MVC4VS2010_Loc III. Creating your first MVC4 Application a. On the Visual Studio click file new solution link b. Click Other Project Type>Visual Studio Solutions and on the templates window select blank solution and let us name our solution MVCPrimer. c. Now Click File>New and select Project d. Select Visual C#>Web> and select ASP.NET MVC 4 Web Application and Enter MyWebSite as Name e. Select Empty, Razor as view engine and uncheck Create a Unit test project f. You can now view a basic MVC 4 Application Structure on your solution explorer g. Now we will add our first controller by right clicking on the controllers folder on your solution explorer and select Add>Controller h. Change the name of the controller to HomeController and under the scaffolding options select Empty MVC Controller. i. You will now see a basic controller with an Index method that returns an ActionResult j. We will now add a new View Folder for our Home Controller. Right click on the views folder on your solution explorer and select Add> New Folder> and name this folder Home k. Add a new View by right clicking on Views>Home Folder and select Add View. l. Name the view Index, and select Razor(CSHTML) as View Engine, All checkbox should be unchecked for now and click add. m. Relationship between our HomeController and Home Views Sub Folder n. Add new HTML Contents to our newly created Index View o. Press F5 to run our MVC Application p. We will create our new model, Right click on the models folder of our solution explorer and select Add> Class. q. Let us name our class Customer r. Edit the Customer class with the following code s. Open the HomeController by double clickin HomeController of our Controllers folder and edit the HomeControllerusing System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc;   namespace MyWebSite.Controllers {     public class HomeController : Controller     {         //         // GET: /Home/           public ActionResult Index()         {             return View();         }           public ActionResult ListCustomers()         {             List<Models.Customer> customers = new List<Models.Customer>();               //Add First Customer to Our Collection             customers.Add(new Models.Customer()                     {                         Id = 1,                         CompanyName = "Volvo",                         ContactNo = "123-0123-0001",                         ContactPerson = "Gustav Larson",                         Description = "Volvo Car Corporation, or Volvo Personvagnar AB, is a Scandinavian automobile manufacturer founded in 1927"                     });                 //Add Second Customer to Our Collection             customers.Add(new Models.Customer()                     {                         Id = 2,                         CompanyName = "BMW",                         ContactNo = "999-9876-9898",                         ContactPerson = "Franz Josef Popp",                         Description = "Bayerische Motoren Werke AG,  (BMW; English: Bavarian Motor Works) is a " +                                       "German automobile, motorcycle and engine manufacturing company founded in 1917. "                     });                 //Add Third Customer to Our Collection             customers.Add(new Models.Customer()             {                 Id = 3,                 CompanyName = "Audi",                 ContactNo = "983-2222-1212",                 ContactPerson = "Karl Benz",                 Description = " is a multinational division of the German manufacturer Daimler AG,"             });               return View(customers);         }     } } t. Let us now create a view for this Class, But before continuing Press Ctrl + Shift + B to rebuild the solution, this will make the previously created model on the Model class drop down of the Add View Menu. Right click on the views>Home folder and select Add>View u. Let us name our View as ListCustomers, Select Razor(CSHTML) as View Engine, Put a check mark on Create a strongly-typed view, and select Customer (MyWebSite.Models) as model class. Slect List on the Scaffold Template and Click OK. v. Run the MVC Application by pressing F5, and on the address bar insert Home/ListCustomers, We should now see a web page similar below.   x. You can edit ListCustomers.CSHTML to remove and add HTML codes @model IEnumerable<MyWebSite.Models.Customer>   @{     Layout = null; }   <!DOCTYPE html>   <html> <head>     <meta name="viewport" content="width=device-width" />     <title>ListCustomers</title> </head> <body>     <h2>List of Customers</h2>     <table border="1">         <tr>             <th>                 @Html.DisplayNameFor(model => model.CompanyName)             </th>             <th>                 @Html.DisplayNameFor(model => model.Description)             </th>             <th>                 @Html.DisplayNameFor(model => model.ContactPerson)             </th>             <th>                 @Html.DisplayNameFor(model => model.ContactNo)             </th>         </tr>         @foreach (var item in Model) {         <tr>             <td>                 @Html.DisplayFor(modelItem => item.CompanyName)             </td>             <td>                 @Html.DisplayFor(modelItem => item.Description)             </td>             <td>                 @Html.DisplayFor(modelItem => item.ContactPerson)             </td>             <td>                 @Html.DisplayFor(modelItem => item.ContactNo)             </td>                   </tr>     }         </table> </body> </html> y. Press F5 to run the MVC Application   z. You will notice some @HTML.DisplayFor codes. These are called HTML Helpers you can read more about HTML Helpers on this site http://www.w3schools.com/aspnet/mvc_htmlhelpers.asp   That’s all. You now have your first MVC4 Razor Engine Web Application . . .

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  • JavaOne Session Report: “50 Tips in 50 Minutes for GlassFish Fans”

    - by Janice J. Heiss
    At JavaOne 2012 on Monday, Oracle’s Engineer Chris Kasso, and Technology Evangelist Arun Gupta, presented a head-spinning session (CON4701) in which they offered 50 tips for GlassFish fans. Kasso and Gupta alternated back and forth with each presenting 10 tips at a time. An audience of about (appropriately) 50 attentive and appreciative developers was on hand in what has to be one of the most information-packed sessions ever at JavaOne!Aside: I experienced one of the quiet joys of JavaOne when, just before the session began, I spotted Java Champion and JavaOne Rock Star Adam Bien sitting nearby – Adam is someone I have been fortunate to know for many years.GlassFish is a freely available, commercially supported Java EE reference implementation. The session prioritized quantity of tips over depth of information and offered tips that are intended for both seasoned and new users, that are meant to increase the range of functional options available to GlassFish users. The focus was on lesser-known dimensions of GlassFish. Attendees were encouraged to pursue tips that contained new information for them. All 50 tips can be accessed here.Below are several examples of more elaborate tips and a final practical tip on how to get in touch with these folks. Tip #1: Using the login Command * To execute a remote command with asadmin you must provide the admin's user name and password.* The login command allows you to store the login credentials to be reused in subsequent commands.* Can be logged into multiple servers (distinguish by host and port). Example:     % asadmin --host ouch login     Enter admin user name [default: admin]>     Enter admin password>     Login information relevant to admin user name [admin]     for host [ouch] and admin port [4848] stored at     [/Users/ckasso/.asadminpass] successfully.     Make sure that this file remains protected.     Information stored in this file will be used by     asadmin commands to manage the associated domain.     Command login executed successfully.     % asadmin --host ouch list-clusters     c1 not running     Command list-clusters executed successfully.Tip #4: Using the AS_DEBUG Env Variable* Environment variable to control client side debug output* Exposes: command processing info URL used to access the command:                           http://localhost:4848/__asadmin/uptime Raw response from the server Example:   % export AS_DEBUG=true  % asadmin uptime  CLASSPATH= ./../glassfish/modules/admin-cli.jar  Commands: [uptime]  asadmin extension directory: /work/gf-3.1.2/glassfish3/glassfish/lib/asadm      ------- RAW RESPONSE  ---------   Signature-Version: 1.0   message: Up 7 mins 10 secs   milliseconds_value: 430194   keys: milliseconds   milliseconds_name: milliseconds   use-main-children-attribute: false   exit-code: SUCCESS  ------- RAW RESPONSE  ---------Tip #11: Using Password Aliases * Some resources require a password to access (e.g. DB, JMS, etc.).* The resource connector is defined in the domain.xml.Example:Suppose the DB resource you wish to access requires an entry like this in the domain.xml:     <property name="password" value="secretp@ssword"/>But company policies do not allow you to store the password in the clear.* Use password aliases to avoid storing the password in the domain.xml* Create a password alias:     % asadmin create-password-alias DB_pw_alias     Enter the alias password>     Enter the alias password again>     Command create-password-alias executed successfully.* The password is stored in domain's encrypted keystore.* Now update the password value in the domain.xml:     <property name="password" value="${ALIAS=DB_pw_alias}"/>Tip #21: How to Start GlassFish as a Service * Configuring a server to automatically start at boot can be tedious.* Each platform does it differently.* The create-service command makes this easy.   Windows: creates a Windows service Linux: /etc/init.d script Solaris: Service Management Facility (SMF) service * Must execute create-service with admin privileges.* Can be used for the DAS or instances* Try it first with the --dry-run option.* There is a (unsupported) _delete-serverExample:     # asadmin create-service domain1     The Service was created successfully. Here are the details:     Name of the service:application/GlassFish/domain1     Type of the service:Domain     Configuration location of the service:/work/gf-3.1.2.2/glassfish3/glassfish/domains     Manifest file location on the system:/var/svc/manifest/application/GlassFish/domain1_work_gf-3.1.2.2_glassfish3_glassfish_domains/Domain-service-smf.xml.     You have created the service but you need to start it yourself. Here are the most typical Solaris commands of interest:     * /usr/bin/svcs  -a | grep domain1  // status     * /usr/sbin/svcadm enable domain1 // start     * /usr/sbin/svcadm disable domain1 // stop     * /usr/sbin/svccfg delete domain1 // uninstallTip #34: Posting a Command via REST* Use wget/curl to execute commands on the DAS.Example:  Deploying an application   % curl -s -S \       -H 'Accept: application/json' -X POST \       -H 'X-Requested-By: anyvalue' \       -F id=@/path/to/application.war \       -F force=true http://localhost:4848/management/domain/applications/application* Use @ before a file name to tell curl to send the file's contents.* The force option tells GlassFish to force the deployment in case the application is already deployed.* Use wget/curl to execute commands on the DAS.Example:  Deploying an application   % curl -s -S \       -H 'Accept: application/json' -X POST \       -H 'X-Requested-By: anyvalue' \       -F id=@/path/to/application.war \       -F force=true http://localhost:4848/management/domain/applications/application* Use @ before a file name to tell curl to send the file's contents.* The force option tells GlassFish to force the deployment in case the application is already deployed.Tip #46: Upgrading to a Newer Version * Upgrade applications and configuration from an earlier version* Upgrade Tool: Side-by-side upgrade– GUI: asupgrade– CLI: asupgrade --c– What happens ?* Copies older source domain -> target domain directory* asadmin start-domain --upgrade* Update Tool and pkg: In-place upgrade– GUI: updatetool, install all Available Updates– CLI: pkg image-update– Upgrade the domain* asadmin start-domain --upgradeTip #50: How to reach us?* GlassFish Forum: http://www.java.net/forums/glassfish/glassfish* [email protected]* @glassfish* facebook.com/glassfish* youtube.com/GlassFishVideos* blogs.oracle.com/theaquariumArun Gupta acknowledged that their method of presentation was experimental and actively solicited feedback about the session. The best way to reach them is on the GlassFish user forum.In addition, check out Gupta’s new book Java EE 6 Pocket Guide.

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  • How to get the values from post method to the codehind file

    - by SmartestVEGA
    I have created a Webpage which will post as "post" method..not as "get" method. <html> <head> </head> <body> <FORM action="RetrieveData_Post.asp" id=form1 method=post name=form1> First Name: <br> <INPUT id="txtFirstName" name="txtFirstName" > <br> Last Name: <br> <INPUT id="txtLastName" name="txtLastName" > <br> <INPUT type="submit" value="Submit"> </FORM> </body> </html> i want to retieve the values in the textboxes in the code behind of another form. Please help me.

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  • How can i filter a list of objects using lamda expression?

    - by Colour Blend
    I know i shouldn't have id's with the same value. This is just fictitious, so overlook that. I have: List<Car> carList = new List<Car>(); carList.Add(new Car() { id = 1, name = "Honda" }); carList.Add(new Car() { id = 2, name = "Toyota" }); carList.Add(new Car() { id = 1, name = "Nissan" }); I want to use Lamda Expression to retreive all cars that have an id of 1. Anticipated Result: -- Id: 1, Name: Honda -- Id: 1, Name: Nissan The problem is more filtering an object list based on a foriegn key. Please help me.

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  • Accessing variables of an object of a particular class through a different class within the construc

    - by Haxed
    class Student { private String name; public Student(String name){ this.name = name; } public String getName(){ return name; } } class StudentServer { public StudentServer(){ Student[] s = new Student[30]; s[0] = new Student("Nick"); System.out.println(s[0]); // LINE 01:But this compiles, although prints junk System.out.println(s[0].getName()); // LINE 02:I get a error called cannot find symbol } public static void main(){ new StudentServer(); } } Hey, there are two lines, I want the reader to focus on, the first line prints junk as usual, but suprizingly the second one gives me an error. Do you know why ? Many Thanks

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