I have a form that when you submit it, it sends the data for validation to another php script via ajax. Validation errors are echo'd back in a div in my form. A success message also is returned if validation passes.
The problem is that the form is still displayed after submit and successful validation. I want to hid the div after success.
So, I wrote this simple CSS method which works fine when called from the page the form is displayed on.
The problem is that I cannot seem to
call the hide script via returned code. I can return html like
echo "<p>Thanks, your form passed validation and is being sent</p>";
So I assumed I could simply echo another line after that
echo "window.onload=displayDiv()"; inside script tags (which I cannot get to display here)...
and that it would hide the form div.
It does not work. I am assuming that the problem is that the javascript is being returned incorrectly and not being interpreted by the browser...
How can I invoke my 'hide' script on the page via returned data from my validation script? I can echo back text but the script
call is ineffective.
Thanks!
This is the script on the page with the form...
I can
call it to show/hide with something like onclick="displayDiv()" while on the form but I don't want the user to invoke this... it has be called as the result of a successful validation when I write the results back to the div...
function displayDiv()
{
var divstyle = new String();
divstyle = document.getElementById("myForm").style.display;
if(divstyle.toLowerCase()=="block" || divstyle == "")
{
document.getElementById("myForm").style.display = "none";
}
else
{
document.getElementById("myForm").style.display = "block";
}
}
PS: I am using the mootools.js library for the form validation if this matters for the syntax..
