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  • How can I recursively read out directories in Perl?

    - by Przemek
    Hi, I want to read out a directory recursively to print the data-structure in an HTML-Page with Template::Toolkit. But I'm hanging in how to save the Paths and Files in a form that can be read our easy. My idea started like this sub list_dirs{ my ($rootPath) = @_; my (@paths); $rootPath .= '/' if($rootPath !~ /\/$/); for my $eachFile (glob($path.'*')) { if(-d $eachFile) { push (@paths, $eachFile); $paths[$i] = &list_dirs($eachFile); } else { push (@files, $eachFile); } } return @paths; } How could I solve this problem?

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  • How to input test data using the DecisionTree module in python?

    - by lifera1n
    On the Python DescisionTree module homepage (DecisionTree-1.6.1), they give a piece of example code. Here it is: dt = DecisionTree( training_datafile = "training.dat", debug1 = 1 ) dt.get_training_data() dt.show_training_data() root_node = dt.construct_decision_tree_classifier() root_node.display_decision_tree(" ") test_sample = ['exercising=>never', 'smoking=>heavy', 'fatIntake=>heavy', 'videoAddiction=>heavy'] classification = dt.classify(root_node, test_sample) print "Classification: ", classification My question is: How can I specify sample data (test_sample here) from variables? On the project homepage, it says: "You classify new data by first constructing a new data vector:" I have searched around but have been unable to find out what a data vector is or the answer to my question. Any help would be appreciated!

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  • What is an efficient way to erase substrings?

    - by Legend
    I have a long string and a set of <end-index, string> list like the following: long_sentence = "This is a long long long long sentence" indices = [[6, "is"], [8, "is a"], [18, "long"], [23, "long"]] An element 6, "is" indicates that 6 is the end index of the word "is" in the string. I want to get the following string in the end: >> print long_sentence This .... long ......... long sentence" I tried an approach like this: temp = long_sentence for i in indices: temp = temp[:int(i[0]) - len(i[1])] + '.'*(len(i[1])+1) + temp[i[0]+1:] While this seems to be working, it is taking exceptionally long time (more than 6 hours on 5000 strings inside a 300 MB file). Is there a way to speed this up?

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  • Resources for learning how to better read code

    - by rsteckly
    Hi, I recently inherited a large codebase and am having to read it. The thing is, I've usually been the dev starting a project. As a result, I don't have a lot of experience reading code. My reaction to having to read a lot of code is, well, umm to rewrite it. But I need to bring myself up to speed quickly and build on top of an existing system. Do other people have techniques they've learned to absorb a code base? At this point, I'm just reading through the code. I've tried generating UML diagrams using UModel. They're so big they won't print cleanly and when I zoom in, I really do lose the perspective of seeing all the relationships. How have other people dealt with this problem?

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  • dropping user to IRB after reading from pipe

    - by aurelian
    I have this script that drops the user to an IRB session when executed. All good, but when I use *nix pipes to get the input (e.g. with cat), the IRB session ends immediately. I could reduce the script (let's call it myscript.rb) to the following: require 'irb' if $stdin.stat.size 0 @text = $stdin.read else @text= "nothing" end ARGV.clear IRB.start When executed like: ruby myscript.rb, I end up in the IRB session (as expected). But (assuming foo.txt exists in the cwd): cat foo.txt | ruby myscript.rb will just print the IRB prompt and then the IRB session is closed (I'm being dropped to $bash). Any known workarounds or ideas? BTW: it has the same behavior on ruby 1.8.7 as well as on 1.9.2.

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  • Referenced vector does not pass through functions

    - by kylepayne
    The referenced vector to functions does not hold the information in memory. Do I have to use pointers? Thanks. #include <iostream> #include <cstdlib> #include <vector> #include <string> using namespace std; void menu(); void addvector(vector<string>& vec); void subvector(vector<string>& vec); void vectorsize(const vector<string>& vec); void printvec(const vector<string>& vec); void printvec_bw(const vector<string>& vec); int main() { vector<string> svector; menu(); return 0; } //functions definitions void menu() { vector<string> svector; int choice = 0; cout << "Thanks for using this program! \n" << "Enter 1 to add a string to the vector \n" << "Enter 2 to remove the last string from the vector \n" << "Enter 3 to print the vector size \n" << "Enter 4 to print the contents of the vector \n" << "Enter 5 ----------------------------------- backwards \n" << "Enter 6 to end the program \n"; cin >> choice; switch(choice) { case 1: addvector(svector); menu(); break; case 2: subvector(svector); menu(); break; case 3: vectorsize(svector); menu(); break; case 4: printvec(svector); menu(); break; case 5: printvec_bw(svector); menu(); break; case 6: exit(1); default: cout << "not a valid choice \n"; // menu is structured so that all other functions are called from it. } } void addvector(vector<string>& vec) { //string line; //int i = 0; //cin.ignore(1, '\n'); //cout << "Enter the string please \n"; //getline(cin, line); vec.push_back("the police man's beard is half-constructed"); } void subvector(vector<string>& vec) { vec.pop_back(); return; } void vectorsize(const vector<string>& vec) { if (vec.empty()) { cout << "vector is empty"; } else { cout << vec.size() << endl; } return; } void printvec(const vector<string>& vec) { for(int i = 0; i < vec.size(); i++) { cout << vec[i] << endl; } return; } void printvec_bw(const vector<string>& vec) { for(int i = vec.size(); i > 0; i--) { cout << vec[i] << endl; } return; }

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  • Python instances and attributes: is this a bug or i got it totally wrong?

    - by Mirko Rossini
    Suppose you have something like this: class intlist: def __init__(self,l = []): self.l = l def add(self,a): self.l.append(a) def appender(a): obj = intlist() obj.add(a) print obj.l if __name__ == "__main__": for i in range(5): appender(i) A function creates an instance of intlist and calls on this fresh instance the method append on the instance attribute l. How comes the output of this code is: [0] [0, 1] [0, 1, 2] [0, 1, 2, 3] [0, 1, 2, 3, 4] ? If i switch obj = intlist() with obj = intlist(l=[]) I get the desired output [0] [1] [2] [3] [4] Why this happens? Thanks

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  • Add the "selected" attribute to a drop down option with jQuery

    - by gaoshan88
    How do I add the attribute "selected" to a drop down menu option based on that option matching some variable? Here is how the dropdown is populated... loginOptions = ["First", "Second", "Third]; var Login = $( '#Login' ); for ( var i = 0; i < loginOptions.length; i++ ) { Login.append('<option value="'+ loginOptions[i] +'">'+ loginOptions[i] +'</option>'); } I want to mark one option as "selected" based on whether or not its value matches another variable. so if loginOption[i] is equal to var existingLoginValue then set that option to 'selected' Something that would do if(loginOptions[i] === existingLoginValue){ print 'selected'; }; Thanks!

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  • Why doesn't Perl threading work when I call readdir beforehand?

    - by Kevin
    Whenever I call readdir before I create a thread, I get an error that looks like this: perl(2820,0x7fff70c33ca0) malloc: * error for object 0x10082e600: pointer being freed was not allocated * set a breakpoint in malloc_error_break to debug Abort trap What's strange is that it happens when I call readdir before I create a thread (i.e. readdir is not called in any concurrent code). I don't even use the results from readdir, just making the call to it seems to screw things up. When I get rid of it, things seem to work fine. Some example code is below: opendir(DIR, $someDir); my @allFiles = readdir(DIR); close(DIR); my $thread = threads-create(\&sub1); $thread-join(); sub sub1 { print "in thread\n" }

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  • How to read the whole istream correctly?

    - by L.Lawliet
    Here is a simple code to print all characters of a txt file on screen: #include <iostream> #include <fstream> #include <string> using namespace std; int main() { int **i; int j,k; char a; ifstream test("test.txt", ios::binary); while((a=test.get())!=-1)//if I use "while(!test.eof())" here, how to avoid the output of the last character(-1) to std::cout, or any ostream objects? { putchar(a);//also change this to putchar(test.get()); } getchar(); } As I noted in the code, if I use "test.eof()" to judge the end of test.txt, I'll always get an extra blank at the end of the output. How to avoid it?

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  • filter results quarterly

    - by user339067
    I am writing a simple C# application that is handling bank savings. I want to be able to show the results on either, yearly, monthly or quarterly basic how can this be done? How can I loop through a set of results and only show every third post (if I am using quarterly) for example. In Python I can use range(1,31,3) but how is it done in C#? UPDATE 1 I want to loop 12 times (annually) and calculate the interest each loop but I only want to print the results every third loop (quarterly). How can I achieve this?

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  • 2 Select or 1 Join query ?

    - by xRobot
    I have 2 tables: book ( id, title, age ) ---- 100 milions of rows author ( id, book_id, name, born ) ---- 10 millions of rows Now, supposing I have a generic id of a book. I need to print this page: Title: mybook authors: Tom, Graham, Luis, Clarke, George So... what is the best way to do this ? 1) Simple join like this: Select book.title, author.name From book, author WHERE ( author.book_id = book.id ) AND ( book.id = 342 ) 2) For avoid the join, I could make 2 simple query: Select title FROM book WHERE id = 342 Select name FROM author WHERE book_id = 342 What is the most efficient way ?

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  • paintComponent method is not displaying anything on the panel

    - by Captain Gh0st
    I have been trying to debug this for hours. The program is supposed to be a grapher that graphs coordinates, but i cannot get anything to display not even a random line, but if i put a print statement there it works. It is a problem with the paintComponent Method. When I out print statement before g.drawLine then it prints, but it doesn't draw any lines even if i put a random line with coordinates (1,3), (2,4). import java.awt.*; import java.util.*; import javax.swing.*; public abstract class XYGrapher { abstract public Coordinate xyStart(); abstract public double xRange(); abstract public double yRange(); abstract public Coordinate getPoint(int pointNum); public class Paint extends JPanel { public void paintGraph(Graphics g, int xPixel1, int yPixel1, int xPixel2, int yPixel2) { super.paintComponent(g); g.setColor(Color.black); g.drawLine(xPixel1, yPixel1, xPixel2, yPixel2); } public void paintXAxis(Graphics g, int xPixel, int pixelsWide, int pixelsHigh) { super.paintComponent(g); g.setColor(Color.green); g.drawLine(xPixel, 0, xPixel, pixelsHigh); } public void paintYAxis(Graphics g, int yPixel, int pixelsWide, int pixelsHigh) { super.paintComponent(g); g.setColor(Color.green); g.drawLine(0, yPixel, pixelsWide, yPixel); } } public void drawGraph(int xPixelStart, int yPixelStart, int pixelsWide, int pixelsHigh) { JFrame frame = new JFrame(); Paint panel = new Paint(); panel.setPreferredSize(new Dimension(pixelsWide, pixelsHigh)); panel.setMinimumSize(new Dimension(pixelsWide, pixelsHigh)); panel.setMaximumSize(new Dimension(pixelsWide, pixelsHigh)); frame.setLocation(frame.getToolkit().getScreenSize().width / 2 - pixelsWide / 2, frame.getToolkit().getScreenSize().height / 2 - pixelsHigh / 2); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setResizable(false); frame.add(panel); frame.pack(); frame.setVisible(true); double xRange = xRange(); double yRange = yRange(); Coordinate xyStart = xyStart(); int xPixel = xPixelStart - (int) (xyStart.getX() * (pixelsWide / xRange)); int yPixel = yPixelStart + (int) ((xyStart.getY() + yRange) * (pixelsHigh / yRange)); System.out.println(xPixel + " " + yPixel); if(yPixel > 0 && (yPixel < pixelsHigh)) { System.out.println("y"); panel.paintYAxis(panel.getGraphics(), yPixel, pixelsWide, pixelsHigh); } if(xPixel > 0 && (xPixel < pixelsHigh)) { System.out.println("x"); panel.paintXAxis(panel.getGraphics(), xPixel, pixelsWide, pixelsHigh); } for(int i = 0; i>=0; i++) { Coordinate point1 = getPoint(i); Coordinate point2 = getPoint(i+1); if(point2 == null) { break; } else { if(point1.drawFrom() && point2.drawTo()) { int xPixel1 = (int) (xPixelStart + (point1.getX() - xyStart.getX()) * (pixelsWide / xRange)); int yPixel1 = (int) (yPixelStart + (xyStart.getY() + yRange-point1.getY()) * (pixelsHigh / yRange)); int xPixel2 = (int) (xPixelStart + (point2.getX() - xyStart.getX()) * (pixelsWide / xRange)); int yPixel2 = (int) (yPixelStart + (xyStart.getY() + yRange - point2.getY()) * (pixelsHigh / yRange)); panel.paintGraph(panel.getGraphics(), xPixel1, yPixel1, xPixel2, yPixel2); } } } frame.pack(); } } This is how i am testing it is supposed to be a square, but nothing shows up. public class GrapherTester extends XYGrapher { public Coordinate xyStart() { return new Coordinate(-2,2); } public double xRange() { return 4; } public double yRange() { return 4; } public Coordinate getPoint(int pointNum) { switch(pointNum) { case 0: return new Coordinate(-1,-1); case 1: return new Coordinate(1,-1); case 2: return new Coordinate(1,1); case 3: return new Coordinate(-1,1); case 4: return new Coordinate(-1,-1); } return null; } public static void main(String[] args) { new GrapherTester().drawGraph(100, 100, 500, 500); } } Coordinate class so if any of you want to run and try it out. That is all you would need. public class Coordinate { float x; float y; boolean drawTo; boolean drawFrom; Coordinate(double x, double y) { this.x = (float) x; this.y = (float) y; drawFrom = true; drawTo = true; } Coordinate(double x, double y, boolean drawFrom, boolean drawTo) { this.x = (float) x; this.y = (float) y; this.drawFrom = drawFrom; this.drawTo = drawTo; } public double getX() { return x; } public double getY() { return y; } public boolean drawTo() { return drawTo; } public boolean drawFrom() { return drawFrom; } }

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  • Calling software modules (Java, Perl, etc.) from R

    - by harshsinghal
    I've recently started using R for Natural Language Processing tasks and find that a lot of applications are available in Java and Perl (for my purposes). For example: A few perl modules are available to find distance measures between words by querying Wordnet. I am aware of the R Wordnet package, but it does not perform the tasks that these CPAN modules do. Many Java packages for NLP are out there, which I'd like to use from within R. I know of rJava, RSPerl, the simple system command amongst others, but I'd like more examples of how I could make calls to Java and Perl applications from R. Recently I tried capturing console output from a perl script. cat( 'print "Hello World\n";',file="hello.pl" ) system(command="c:\Perl64\bin\perl hello.pl") system(command=paste(Sys.getenv("COMSPEC"),"/c","C:\Perl64\bin\perl hello.pl")) None of the above system commands showed 'Hello World' on the R console. I've used "system" before to run perl scripts to perform tasks without wanting to capture console output. Any hints and redirection to other more extensive sources of information would be highly appreciated. Thank you

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  • European signs in img src problem

    - by Rakoon
    Hey. I recently encountered a strange problem on my website. Images with æ ø and å in them (Western European signs) Won't display. The character encoding on all sites is "Iso-8859-1" I can print æ ø and å on the page without problems. If I right click the "broken image" and choose properties, it displays the filename with the european signs. (/admin/content/galleri/å.jpg) the code for img looks like this <img name='bilde' src='content/{$_SESSION["linkname"]}/{$row["img"]}' class='topmargin_ss leftmargin_ms rightmargin_s' width='80' height='80'> (Wasn't allowed to post images so the code is without starting and ending brackets) Made 4 files: z.jpg æ.jpg ø.jpg å.jpg Only z.jpg shows up, they are the exact same jpg. The images are uploaded using php code, which works, uploads to the right directory and has no problem with the european signs. Does anybody know what could be causing this?

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  • <thead> and <tfoot> in Safari

    - by AJ
    I trying to print a page with multiple tables. The problem is that any of these tables may break and carry over to the next page. Have been trying to get the table header to repeat on the second page. Am currently using thead and setting the display property to table-header-group. This works just as expected in IE and firefox but the header will not repeat in Safari. Since we are using software that converts our page to a pdf document for printing...and the 3rd party software uses a Safari engine, we are stuck with this problem. Does anyone know a way / workaround to make headers repeat if the table spans multiple pages in Safari?

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  • Using the JNotify library, how can you tell if a deleted file was a file or a directory?

    - by Moeri
    For those unfamiliar with JNotify, this is a library which provides an easy way to monitor events in a directory. For instance, when a file gets deleted in the selected folder, the method "fileDeleted" gets called, along with a few parameters. Here's an example of the fileDeleted method: public void fileDeleted(int wd, String rootPath, String name) { print("deleted " + rootPath + " : " + name); } Now, I would like to know if the deleted file was a file or directory. My usual approach is to create a new File object with the given path, and use the methods isFile() and isDirectory() However, since this file is already deleted, these methods always return false. So here's my concrete question: I have the path to a deleted file or directory, how can I tell wether it was a file or a directory? Is there a workaround to this? What's the best practice to do here? Thank you in advance.

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  • Ajax / GroovyGrails Post data coming over with unexpected leading character. Who is encoding/decod

    - by ?????
    I'm having an encoding issue, and I'm not sure where to look for the problem. I have this Ajax.Request function (prototype library) sending data to a Groovy/Grails encoder var myAjax = new Ajax.Request(url, {method:'post', encoding:'UTF-8', contentType:'application/x-www-form-urlencoded', parameters:{'content':new_content}, onSuccess:success, onFailure:failure}); The data is coming in with an unexpected %A0 at the beginning: I have this simple controller that just echos the content back: def titlechange = { def content = URLDecoder.decode(params['content']) printf("Content: %s; DecodedContent = %s\n", params['content'], content) response.characterEncoding='UTF-8' render content } the debug print statement shows: Content: %A0Hello%2C%20world%21; DecodedContent = †Hello, world! Where is that %A0 coming from? My grails configuration has this: // The default codec used to encode data with ${} grails.views.default.codec="none" // none, html, base64 grails.views.gsp.encoding="UTF-8" grails.converters.encoding="UTF-8 Is the issue on the grails side or on the JavaScript side?

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  • Python extension building with boost

    - by user1544053
    Hey guys I'm fairly new to boost c/c++ library. I downloaded boost library and build the library. I created a very simple python library in c++ using boost interface (actually it is example code given in the documentation). I built it into a dll file. In the documentation it reads that this dll is exposed to python and they just show the import function in python and include the created library. I don't understand how to expose that dll to python and load the library inside in tradition ('import') manner. In case if you wanna look at the code then here it is: #include <boost/python.hpp> char const* greet() { return "hello, world"; } BOOST_PYTHON_MODULE(hello_ext) { using namespace boost::python; def("greet", greet); } Please help I really want to build applications with c/c++ and python. I simply want to use hello_ext as: >>>import hello_ext >>>print hello_ext.greet() Thank you.

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  • Semicolon in object variable name

    - by milkfilk
    There's a common LDAP attribute called userCertificate;binary. It actually has a semi-colon in the attribute name. In ruby, I turn an LDAP entry into a OpenStruct object called 'struct'. struct.class = OpenStruct But of course ruby thinks it's an end-of-line character. ? struct.userCertificate;binary NameError: undefined local variable or method `binary' for main:Object from (irb):52 from :0 IRB knows that the local variable is there, because it gives me struct.userCertificate;binary from the tab auto-completion. I can also see the class variable when calling struct.methods on it. struct.methods = ... "send", "methods", "userCertificate;binary=", "hash", ... It's definitely there, I can see the contents if I print the whole variable to_s(). But how can I access the local variable when it has a semicolon in it? I have workarounds for this but I thought it was an interesting problem to post.

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  • How do I reference members of a single object passed to the View?

    - by Juxtaposed
    I'm new to MVC2 in ASP.NET/C#, so please forgive me if I misunderstand something. I have code similar to this in my Controller: var singleInstance = new Person("John"); ViewData["myInstance"] = singleInstance; return View(); So in my view, Index.aspx, I want to be able to reference members in that object. For example, Person has a member called Name, which is set in the constructor. In the view I want to get Person.Name from what is stored in the ViewData object. Ex.: <%= ViewData["myInstance"].name %> That doesn't work. The only real workaround I've found is to do something like this: <% var thePerson = ViewData["myInstance"]; print (or whatever the method is) thePerson.Name; %> Any help would be much appreciated... This was so much easier in PHP/Zend Framework... sigh

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  • Programming error in Java Socket

    - by Akhil K Nambiar
    Can you tell me what is the error in this code? Socket socket = new Socket(hostname, port); PrintWriter out = new PrintWriter(socket.getOutputStream(), true); //DataInputStream is = new DataInputStream(socket.getInputStream()); out.println("hi"); System.out.print(in.readLine()); The Server Socket program is written in .Net and it echoes back the data. The data is sent successfully but could not be retrieved properly. I tried the same by using the linux command nc 192.168.1.6 8425 (enter) Hi (Sent data) Hi (recieved data) When I checked the code the data is found to have sent as byteStream in .Net. Is that a problem. In that case what modification should I make.

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  • What is the standard way to add an icon to a link with CSS?

    - by ewernli
    I'm used to use padding + background-image to place an icon next to a link. There are many example of this approach. Here is one from here: <a class="external" href="http://www.othersite.com/">link</a> a.external { padding-right: 15px; background: transparent url(images/external-link-icon.gif) no-repeat top right; } But most browser don't print background image, which is annoying. What is the standard to place icon next to links which is semantically correct and works in all cases? (I couldn't find an exact similar question. If there is one, just close this one as duplicate)

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  • PHP MySQL New Lines / Whitespaces from textarea

    - by rob_robsen
    I've a problem about whitespaces and new lines at the beginning of a textarea. I send a json string with ajax to the php script. Then I decode the string into an php array (with json_decode). So I have a string in this array with two line breaks at the beginning. If a print the text from the array, the line breaks are there, but if I store the text into the mysql database, the line breaks are gone... Only at the beginning of the string, the line breaks gone... At the rest of the string, the line breaks are ok. Thanks for your answers! rob

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  • Unix - "xargs" - output "in the middle" (not at the end!)

    - by Petike
    Hello, example use of "xargs" application in Unix can be something like this: ls | xargs echo which is the same as (let's say I have "someFile" and "someDir/" in the working dir): echo someFile someDir so "xargs" take its "input" and place it "at the end" of the next command (here at the end of echo). But sometimes I want xargs to place its input somewhere "in the middle" of next command. For example: find . -type f -name "*.cpp" -print | xargs g++ -o outputFile so if I had in the current directory files "a.cpp" "b.cpp" "c.cpp" the output would be the same as with the command: g++ -o outputFile a.cpp b.cpp c.cpp but I want to have something like this: g++ a.cpp b.cpp c.cpp -o outputFile Is there a way to do it? P.S.: I need it in some cases, because e.g.: i586-mingw32msvc-g++ -o outputFile `pkg-config --cflags --libs gtkmm-2.4` a.cpp b.cpp c.cpp doesn't work but this one works fine: i586-mingw32msvc-g++ a.cpp b.cpp c.cpp -o outputFile `pkg-config --cflags --libs gtkmm-2.4` Thanks. Petike

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